When a ball is thrown up by doing work, the velocity of the ball will be 2.6 m/s.
What is Work energy theorem?It states that the Work done in moving a body is equal to the change in kinetic energy of the body
Kinetic energy = 1/2 mv²
Given is a ball of mass m = 0.750 kg and the work done on ball W = 2.50 J
The ball is initially at rest. So, initial velocity is zero. Then, change in kinetic energy will be
W= ΔK.E = K.Ef - K.Ei
According to work energy theorem, work done is
W = 2.5J = 1/2 x 0.750 x (v)² -0
v =2.6 m/s
Thus, the velocity of the ball is 2.6 m/s
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the 3kg object in figure is released from rest at height of 5m on curved frictionless ramp.at the foot of the ramp is a spring of force constant 400N/m.the object slide down the ramp and into the spring, compressing it a distance x before coming momentarily to rest. a) find x
b)describe the motion of the object (if any) after the block momentarily comes to rest?
The value of x given the data from the question is 0.86 m
How to determine the energyFrom the data given above, we can s determine the energy as follow:
Mass (m) = 3 KgHeight (h) = 5 mAcceleration due to gravity (g) = 9.8 m/s² Energy (E) = ?E = mgh
E = 3 × 9.8 × 5
E = 147 J
How to determine the value of xSpring constant (K) = 400 N/mEnergy (E) = 147 JExtention (e) = x = ?E = ½Ke²
147 = ½ × 400 × x²
147 = 200 × x²
Divide both side by 200
x² = 147 / 200
Take the square root of both sides
x = √( 147 / 200)
x = 0.86 m
Since the block came to rest, there is no motion
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5.00 μF, 10.0 μF, and 50.0 μF capacitors are connected in series across a 12.0-V battery.
(a) How much charge is stored in the 5.00-μF capacitor?
(b) What is the potential difference across the 10.0-μF capacitor?
(a) The charge stored in the 5.00-μF capacitor is 37.2 μC.
(b) The potential difference across the 10.0-μF capacitor is 3.72 V.
What is capacitor?The capacitance of a capacitor is defined as the ratio of the charge stored and the potential difference between the capacitor.
The capacitance of a capacitor is denoted by C and expressed as
C = Q/V
Given, 5.00 μF, 10.0 μF, and 50.0 μF capacitors are connected in series across a 12.0-V battery.
(a) The equivalent capacitance is
1 / Ceq = 1 / C₁ +1 / C₂ + 1/ C₃
Substitute the values, we get
Ceq = 3.1 μF
The charge stored in 5.00-μF capacitor is
Q = Ceq x V
Q = 3.1 μF x 12 V
Q = 37.2 μC
Thus, the charge stored in the 5.00-μF capacitor is 37.2 μC
(b) The potential difference across the 10.0-μF capacitor is given by
V = Q/C₂
Put the values, we get
V = 37.2 / 10
V = 3.72 V
Thus, the potential difference across the 10.0-μF capacitor is 3.72 V.
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During a NASCAR race a car goes 58 m/s around a curved section of track that has a radius of 260 m. What is the car's acceleration?
Answer:
12.9m/s^2
Explanation:
As, a=(v^2)/r
=(58^3)/260
=12.9
During a diversity management session, a manager suggests that stereotypes are a necessary part of working with others. “I have to make assumptions about what’s in the other person’s head, and stereotypes help me do that,” she explains. “It’s better to rely on stereotypes than to enter a working relationship with someone from another culture without any idea of what they believe in!” Discuss the merits of and problems with the manager’s statement.
The merits of and problems with the manager’s statement are explained below.
What is stereo typing in organizations?Extension of the social identity of the individual in groups such as working in company or studying in college is called as the stereotyping in organizations.
Merits of Stereotypes in organizations:
It relies on categorical thinkingHelps understand outside world easily'unique characteristics are difficult to recall every time.groups are identified easilyhelps filling the gaps while talking of some new culture.helps enhancing self perception and social identity.Demerits of Stereotypes:
difficulty in understanding behavior of other individual in organizations.an individual may be sometimes under or over estimated.discourages social group while entering a profession.discriminatory behavior.not helps in describing with their talent.Thus, the merits and demerits of stereotypes in organizations are explained above.
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A uniform plate of height 1.870 m is cut in the form of a parabolic section.
The lower boundary of the plate is defined by: y = 0.500[tex]x^{2}[/tex]. Find the distance from the rounded tip of the plate to the center of mass.
The distance from the rounded tip of the plate to the center of mass is 1.87 m.
What is center of mass?The center of mass is a point inside or outside the mass where all of the mass is concentrated.
The y-coordinate of the centroid is given by the ratio of two definite integrals;
Yc = ∫ydm/∫dm,
where dm is a density function
For the uniform plate, δ does not change with position in the plate.
Yc = ∫yδdA/∫δdA
Yc = ∫ydA/∫dA.
dA is a horizontal slice of the plate with dimensions xdy.
Solving the parabola for x,
y = 0.5x²
x = ± √(y/0.50), where the negative value corresponds to the left half of the parabola and the positive to the right half.
dA = (√(y/0.50)
= √(y/0.50))dy
= 2(√(y/0.50))dy
The limits of integration are from zero to 1.870, the top of the plate.
∫ydA = ∫2y√(y/0.50)dy = 7.232 m³
∫dA = ∫2√(y/0.50)dy = 3.868 m²
∫ydA/∫dA = 7.232 m³/3.868 m²
∫ydA/∫dA = 1.869700 m
∫ydA/∫dA = 1.87 m
Thus, the distance from the rounded tip of the plate to the center of mass is 1.87 m.
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If a 100 N block is resting on a steel table with a coefficient of
static friction μs = 0.68, then what minimum force is required to
move the block?
Answer:
6800
Explanation:
100 x 0.68=6800
Answer: 68
Explanation:
2. Two small (green) objects, each of mass m, are separated by a solid, massless rod of length L. They are located so that one of the objects is located at a distance of r away from the center of a uniform spherical planet with mass M (see figure). M r m L m Assume that m is very small so that you can ignore the gravitational force between the two small (green) objects. Is the rod being compressed, stretched, or neither? If compressed/stretched, calculate the magnitude of this deformation force on the rod. If neither, explain clearly why.
The rod is stretched due to the force of gravitational attraction.
The magnitude of the deformation force on the rod is -GMm×((1/r² + 1/(L+r)²)
What is gravity?The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.
The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.
F = GMm/R²
Given are two small (green) objects, each of mass m, are separated by a solid, massless rod of length L. They are located so that one of the objects is located at a distance of r away from the center of a uniform spherical planet with mass M. Assume that m is very small so that you can ignore the gravitational force between the two small (green) objects.
Let the mass closer to the planet is A and the other is B
FA = Force on planet A = -GMm/r²
FB = Force on planet B = -GMm/(L+r)²
Net Force on the rod is given by the addition of the individual forces.
Fnet= FA + FB = -GMm/r² -GMm/(L+r)²
Fnet = -GMm×((1/r² + 1/(L+r)²)
Thus, the magnitude of the deformation force on the rod is derived above.
A experience more force than B, so A will stretch out from B. Hence the force is stretching the rod.
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Consider the baby being weighed in Figure 4.25.
Figure 4.25
(a) What is the mass of the child and basket if a scale reading of 104 N is observed?
kg
(b) What is the tension T in the cord attaching the child to the scale?
N
(c) What is the tension T' in the cord attaching the scale to the ceiling, if the scale has a mass of 0.500 kg?
N
(d) Draw a sketch of the situation indicating the system of interest used to solve each part. The masses of the cords are negligible. (Do this on paper. Your instructor may ask you to turn in this work.)
The mass and tension due to the system are as follows:
The mass of the child and scale = 10.6 kgThe tension T, in the cord attaching the child to the scale = 104N The tension T', in the cord attaching the scale to the ceiling T' = 108.9 NWhat is tension?Tension is a type of pulling force due transmitted by means of a string or cable.
Force = mass * acceleration due to gravitya) The mass of the child and scale = 104/9.81 = 10.6 kg
b) The tension T, in the cord attaching the child to the scale = scale reading = 104N
c) The tension T', in the cord attaching the scale to the ceiling = scale reading + weight of scale
T' = 104 + (0.5 * 9.81)
T' = 108.9 N
d) The sketch is attached in the picture
In conclusion, the tension is force exerted on the cord due to the weight of the scale and the baby.
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Which of the following measurement is most significant?
A. 66.000cm
B. 0.00066cm
C. 6.600cm
D. 6.6cm
Option C. The measurement with the most significant number is 6.600 cm.
What is significant number?
Significant numbers are numbers that have significance or meaning and give more precise details about the value of the entire numbers.
66.000 cm ------> 2 significant numbers0.00066 cm -------> 2 significant numbers6.600 cm ----------> 4 significant numbers6.6 cm ---------------> 2 significant numbersThus, the measurement with the most significant number is 6.600 cm.
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Taking the density of air to be 1.29 kg/m3, what is the magnitude of the angular momentum (in kg · m2/s) of a cubic meter of air moving with a wind speed of 73.0 mi/h in a hurricane? Assume the air is 51.2 km from the center of the hurricane "eye."
The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.
Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h
We have to find the magnitude of the angular momentum
Let,
ρ = Density of air = 1.29 kg/m^3
v = Speed of wind = 73.0 mi/h = 0.032 km/s
M = angular momentum of air
Let the volume of air be 1 m^3
Mass = Volume x ρ = 1 x 1.29 = 1.29 kg
Momentum = M = mass x velocity
Momentum = 1.29 x 0.0032
Momentum = 4.128 x 10^(-3) kg·m^2/s
Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
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Jose was out drinking with his friends for nearly the whole night. The next morning he was confused and vomiting, and had a low body temperature.
Answer:
He has a hangover.
Explanation:
Just something I know.
Psychology is a combination of the Greek words psyche, which means “soul” or “mind,” and logos, which means “the study of.”
Please select the best answer from the choices provided
T
F
Greek terms psyche, which means "soul" or "mind," and logos, which means "the study of," are combined to form the english word psychology. The assertion is true.
What is Psychology?Psychology is the name given to the scientific study of the mind and behavior. Psychologists are actively interested in researching and comprehending how the mind, the brain, and behavior work.
Psychology is a combination of the Greek words psyche, which means “soul” or “mind,” and logos, which means “the study of.”The given statement is corect.
Hence the best answer from the choices provided will be true.
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Mark is diving to the bottom of a pool to pick up a penny. Which of the
following describes the fluid pressure on his ears as he dives?
A. The fluid pressure increases as he dives.
B. After he dives, the fluid pressure increases and then decreases as
he dives deeper.
C. The fluid pressure on his ears doesn't change as he dives.
D. The fluid pressure decreases as he dives.
Answer:
A
Explanation:
As you go deeper, the pressure increases because the water is going farther away from the air and atmosphere
There are several ways to model a compound one type of model is shown ?what is the chemical formula for the molecule modeled?
The is organic compound with the correct chemical formula C4H9O2.
What is a model?A model is a representation of reality. A model serves the purpose of prediction as well as explanation.
Looking at the model of the molecule we can see that it is the organic compound with the correct chemical formula C4H9O2. The molecule is shown in the image attached to this answer.
Missing parts:
There are several ways to model a compound. One type of model is shown.
What is the chemical formula for the molecule represented by the model?
CHO
C4H9O2
C4H8O
C3H8O2
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If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
Pleas help this is Flvs comprehensive science class
6.01 please please help
So, the complete sentence is If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.
When the mass of the sun is larger, Earth moves around the sun at a faster pace and When the mass of the sun is smaller, Earth moves around the sun at a slower pace.
When Earth is closer to the sun, its orbit becomes faster and When Earth is farther from the sun, its orbit becomes slower.
When Earth is closer to the sun, there will be a hotter climate. A little movement that takes one closer to the sun could lead to a huge impact, as the sun is very hot.
So, it can be concluded that If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.
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Suppose the ski patrol lowers a rescue sled carrying an injured skier, with a combined mass of 97.5 kg, down a 60.0-degree slope at a constant speed, as shown in the Figure. The coefficient of kinetic friction between the sled and snow is 0.100.
a) How much work, in joules, is done by friction as the sled moved 28 m along the hill?
b) How much work, in joules, is done by the rope on the sled this distance?
c) What is the work, in joules done by the gravitational force on the sled?
d) What is the net work done on the sled, in joules?
a. 1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.
b.21,835 J work, in joules, is done by the rope on the sled this distance.
c. 23,170 J the work, in joules done by the gravitational force on the sled d. The net work done on the sled, in joules is 43,670 J.
What is friction work?
The work done by friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement
a. How much work is done by friction as the sled moves 28m along the hill?
ans. We use the formula:
friction work = -µ.mg.dcosθ
= -0.100 * 97.5 kg * 9.8 m/s² * 28 m * cos 60
= -1337.3 J
-1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.
b. How much work is done by the rope on the sled in this distance?
We use the formula:
Rope work = -m.g.d(sinθ - µcosθ)
rope work = - 97.5 kg * 9.8 m/s² * 28 m (sin 60 – 0.100 * cos 60)
= 26,754 (0.816)
= 21,835 J
21,835 J work, in joules, is done by the rope on the sled this distance.
c. What is the work done by the gravitational force on the sled?
By using the formula:
Gravity work = mgdsinθ
= 97.5 kg * 9.8 m/s² * 28 m * sin 60
= 23,170 J
23,170 J the work, in joules done by the gravitational force on the sled .
D. What is the total work done?
By adding all the values
work done = -1337.3 + 21,835 + 23,170
= 43,670 J
The net work done on the sled, in joules is 43,670 J.
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A ball of mass 500g is dropped from a height 1.5m . It rebounds the floor and reached the height 1.2m. Calculate the impulse given to the bàll by the floor
The impulse given to the ball by the floor is 0.2865 kg.m/s.
What is impulse?The change in momentum is equal to the product of impact force applied while colliding and time for that impact.
Impulse F. t = m (Vf -Vi)
where, Vf is the final velocity and Vi is the initial velocity.
A ball of mass 500g is dropped from a height 1.5m . It rebounds the floor and reached the height 1.2m.
The initial velocity u = √2x 9.81 x 1.5 = 5.425 m/s
The final velocity v = √2x 9.81 x 1.2 = 4.852 m/s
Substitute the values into the expression, we get
Impulse = m(v- u)
Impulse=0.5 x (4.852- 5.425 )
Impulse = - 0.2865 kg.m/s
Thus, the magnitude of impulse given to the ball by the floor is 0.2865 kg.m/s.
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Q3, A ball of mass 5.0 kg moving with a Velocity of 10.0 ms collides
with a 15.0 kg ball moves with a Velocity of 4 ms! If both balls
Stick together after Collision, Calculate their Common Velocity after Impact if they initially moves in The Same direction, and Opposite direction.
Answer:
Their common velocity after the collision will be 5.5m/s
Explanation:
look at the attachment above ☝️
which has more KE, a 2 g bee flying at 1 m/s, or a 1 g wasp flying at 2 m/s
Answer:
the 1 gram wasp
Explanation:
To start off with this problem, write down every piece of information and do neccessary conversions.
mass of bee = 2 grams = 0.002 kg
speed of bee = 1 m/s
mass of wasp = 1 gram = 0.001 kg
speed of wasp = 2 m/s
now, we will use the kinetic energy formula and compare the answers
KE BEE = 0.5 (0.002 kg)(1 m/s)^2 = 0.001 Joules
KE WASP = 0.5(0.001 kg)(2 m/s)^2 = 0.002 Joules
0.002 J > 0.001 J
The road from city A to city B is described by a car with Vm 40 km / h. When the car turns (from B to A) the average speed is 60 km / h. Find the average round trip speed.
Answer:
i think the answer is 20.......
143°C = _____
416 K
-130 K
0 K
143 K
an object is 27.0 cm from a concave mirror of focal length 15.0 cm. find the image distance.
The distance of the Image will be -33.75 cm
A concave mirror has an inward-curving reflecting surface that faces away from the light source. Unlike convex mirrors, a concave mirror's image forms a variety of images based on the object's proximity to the mirror.
Given that, an object placed 27 cm from a concave mirror having the focal length of 15 cm
We have to find distance of the Image
Using Mirror Formula:
1/f = 1/v + 1/u
Where,
f = focal length
v = Image distance from the mirror
u = object distance from the mirror (concave)
Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.
1/(-15) = 1/v + 1/(-27)
1/(-15) = 1/v - (1/27)
1/v = -0.029
v = -33.75 cm
Therefore the distance of the Image will be -33.75 cm
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When compared to wave II, wave I represents a wave with...
Select one:
a. a higher frequency.
b. a lower frequency.
c. an equal frequency.
d. a greater amplitude.
Wave I stands for a wave with an equal frequency as wave II. Option c is correct.
What is the frequency?Frequency is defined as the number of repititions of a wave occurring waves in 1 second. Its unit is Hz.
Frequency is given by the formula as,
[tex]\rm f = \frac{1}{t}[/tex]
Where,
f is the frequency
t is the period of the wave
From the digrame it is observed that both the wave has the same period. So that they will have the same frequency.
Hence option c is correct.
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which items can be classified as matter? check all that apply?
-pencil
-oxygen
-idea
-horse
-dream
Answer:horse
Explanation:
please help me in this questions
Answer:
Rainy daywindy daysunny daycloudy daysorry I don't know the answer of question 8.sunglassesumbrella:-(:-):-):-(day ☀️night day ☀️night Day ☀️Day ☀️night nightExplanation:
Hope I give all correct answer please mark as brainlest answer
A hollow cast-iron cylinder 4m long, 300mm outer diameter, and thickness of metal 50mm is subjected to a central load on the top when standing straight. The stress produced is 75000kN/m2. Assume Young's modulus for cast iron as 1.5x 108 kN/m^2 and find (i) magnitude of the load, (ii) longitudinal strain produced, and (iii) total decrease in length.
Here, the calculated Magnitude of the load P is 2945.2 kN, the Longitudinal strain produced is 0.0005 and the decrease in length is 2 mm.
Given,
Length, L = 4 m
Outer diameter, D = 300mm, D= 0.3 m
Thickness, t = 50 mm, t = 0.05 m
Stress produced, σ = 75000 kN/m²
Young's modulus for cast iron, E = 1.5 x 10⁸ kN/m²
Calculating the diameter of the cylinder,
Diameter of cylinder, d = (D) – (2t) = 0.3 –( 2 × 0.05)
d= 0.2 m
(i) Magnitude of the load P:
Using the relation, σ =P/A
P = σ × A = 75000 × π /4 (D² – d² )
P= 75000 × π/4 (0.3² – 0.2²)
P= 75000 × π/4 (0.09 – 0.04)
P = 2945.2 kN
Hence, Magnitude of the load P is 2945.2 kN.
(ii) Longitudinal strain produced, e :
Using the relation, Strain, (e) = stress/E
e= 75000/(1.5 x 10⁸)= 0.0005
Hence, the Longitudinal strain produced is 0.0005.
(iii)Total decrease in length, dL:
The total decrease in length can be calculated using the strain as the ratio of change in length to the original length is known as Strain.
Strain = change in length/original length
e= dL/L
0.0005 = dL/4
dL = 0.0005 × 4m = 0.002m=2mm
Hence,the decrease in length is 2 mm.
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A 808 kg automobile is sliding on an icy street. It collides with a parked car which has a mass of 632 kg. The two cars lock up and slide together with a speed of 15.0 km/h. What was the speed of the first car just before the collision?
The speed of the first car just before the collision is 26.73 km/h.
What is conservation of momentum principle?When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.
The external force is not acting here, so the initial momentum is equal to the final momentum. For inelastic collision, final velocity is the common velocity for both the bodies.
m₁u₁ +m₂u₂ =(m₁ +m₂) v
Given a 808 kg automobile is sliding on an icy street. It collides with a parked car which has a mass of 632 kg. The two cars lock up and slide together with a speed of 15.0 km/h.
Second car is parked, so its velocity will be zero.
808 x u +632 x 0 = (808 +632 ) x 15
u = 26.73 km/h
Thus, the speed of the first car just before the collision is 26.73 km/h
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A resistor has a resistance of 8.2 kΩ. If a voltage of 15.9 V were placed across it, what would be the current, in mA? Give the answer to two decimal places; don't worry if the computer adds zeroes.
The value of the electric current for the given conditions willl be 1939.02 A.
What is ohm’s law?Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
Ohm's law claims that the voltage across a conductor is direct to the current flowing through it. This current-voltage connection may be expressed mathematically as,
V=IR
15.9 V = I × 8.2 × 10³ Ω
I = 1939.02 A
Hence, the value of the electric current for the given conditions willl be 1939.02 A.
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28. An electron with a speed of 4.0 x 10° m/s enters a uniform magnetic field of magnitude 0.040 T at an angle of 35 degrees to the magnetic field lines. The electron will follow a helical path. a) Determine the radius of the helical path. b) How far forward will the electron have moved after completing one circle?
Answer:
r= 1.09×10^-4
Explanation:
Given
V=speed=4.0×10^5 m/s
B= magnetic field= 0.040 T
©=angle= 35°
m= mass of electron= 9.11×10^-31
q= charge of electron= 1.60×10^-19
solution
qv×B= mv²/r
qvBsin©=mv²/r
qBsin©=mv/r
r=mv/qBsin©
r=9.11×10^-31× 4.0×10^5/1.064×10^-19×0.04T(sin35°)
r= 1.09×10^-4 m
a) r = 1.09 * [tex]10^{-4}[/tex] m
b) Distance travelled : 6.845 * [tex]10^{-4}[/tex] m
What is an electron ?
An electron is a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.
given
charge of electron : 1.6 * [tex]10^{-19}[/tex] C
mass of electron = 9.11 * [tex]10^{-31}[/tex] kg
v = 4.0 x 10 m/s
B = 0.040 T
theta = 35 degrees
since ,
force in magnetic field on electron = centripetal force
a) q(v*B) = m [tex]v^{2}[/tex] / r
q v B sin(theta) = m [tex]v^{2}[/tex] / r
r =m v /q B sin(theta)
r = 9.11 * [tex]10^{-31}[/tex] * 4.0 x [tex]10^{5}[/tex]/ 1.6 * [tex]10^{-19}[/tex] sin (35)
r = 1.09 * [tex]10^{-4}[/tex] m
b) far forward will the electron have moved after completing one circle will be equal to circumference of the circle = 2πr
= 2 * 3.14 * 1.09 * [tex]10^{-4}[/tex] m = 6.845 * [tex]10^{-4}[/tex] m
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A plane leaves with an acceleration of 6.34 m/s squared and takes 1.5 hours to stop. What is the speed of the plane? What was the distance it traveled?
The answer to this question is Initial velocity of plane will be 34236 m/s and 92437.2 Km is the distance travelled by it.
Three equation of motion are:-
v = u + ats = ut + (1/2)at²v² - u² = 2asWhere v is final velocity, u in initial velocity, s is the displacement by the object, a is the acceleration and t denotes the time.
In question we have given deceleration as 6.34 m/s² and time as 1.5 hour which is equal to 5400 seconds.
Applying equation 1 to find the initial speed of plane
v = u + at
0 = u + (-6.34 × 5400) {v=0 as plane will stop after 5400 sec}
u = 6.34 × 5400
u = 34236 m/s
Initial velocity of plane is 34236 m/s
Applying equation 2 to find the displacement of plane in that time period
s = ut + (1/2)at²
s = ( 34236 × 5400 ) - ( (1/2) × 6.34 × 5400² )
s = 5400 × ( 34236 - ((1/2) × 6.34 × 5400) )
s = 5400 × ( 34236 - 17118 )
s = 5400 × 17118 metres
s = 5.4 × 17118 Km
s = 92437.2 Km
Distance travelled by plane is 92437.2 Km
So, the initial velocity of plane will be 34236 m/s and the displacement of plane in that time period will be 92437.2 Km.
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