A student rubbed a plastic rod with a doth

The rod became negatively charged and the cloth became positively charged

explain why the cloth became positively charged

The time the athlete takes to reach the maximum speed will be 0.93 seconds

acceleration = change in speed / time

initial speed = 0

final speed = 30 km / h = 8.33 m/s

acceleration = 9 [tex]m/s^{2}[/tex]

acceleration = change in speed / time

time =  change in speed  / acceleration  = 8.33 / 9 = 0.93 seconds

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Answer:

Explanation:

Given:

n = 8

t = 4 s

______

f - ?

T - ?

Frequency:

f = n /t = 8 / 4 = 2 Hz

Period:

T = 1 / f = 1 / 2 = 0.5 s

Impact ice is formed either from water present in the atmosphere as snow, sleet, or from exposure of liquid water to a temperature below 32°F.

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According to the given information self gravity two forces keep stars in equilibrium.

The correct option is B.

The push or pull on a mass-containing item alters its velocity. An external force is an agent that has the power to alter the rest or flowing condition of a body. It has a direction and a magnitude. Like we discovered in a previous session, forces are significant because they create motion changes.

An object can change its dimensions or shape, begin moving, stop moving, accelerate, or decelerate as a consequence of the a force acting on it. When two things contact, they exert pressures on each other that are identical in size but directed in the opposite direction.

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Time period  and frequency of the pendulum are respectively 3.17 second and 0.315  second⁻¹. The velocity of its bob at the equilibrium is

140 cm/s.

Given parameters:

Length of the pendulum, L = 2.5 m = 250 cm.

Mass of the bob, m = 75 g

And,  bob is pulled 10 cm above equilibrium and then released.

acceleration due to gravity, g = 9.8 m/s².

Hence, time period of the pendulum is, T = 2π√(l/g)

= 2π√( 250/980) second.

= 3.17 second.

Frequency of the pendulum , n = 1/T = 1/3.17 second⁻¹ = 0.315  second⁻¹.

Let v be the velocity of the bob at equilibrium,

Kinetic energy at equilibrium = potential energy at the highest point

⇒ 1/2 × 75 × v² = 75 × 980 × 10

⇒ v = √(2×980×10)

= 140 cm/s.

So, the velocity at equilibrium after its bob is pulled 10 cm above equilibrium and then released is 140 cm/s.

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Social dynamics behind lower -class drug use is homelessness, criminal behaviors, association with gangs and unemployment whereas social dynamics behind middle -class drug use is peer relationships, extramarital relations and distortion of interpersonal family relationships.

Social factors that increase the risk for adolescent drug use can include popularity, bullying, peer relationships, and association with gangs.

Other possible factors can be social and familial influences. This can result in financial hardships due to job loss. It may also lead to certain behavior that can put family at risk and can also cause domestic violence within relationships.

Other social problems linked with SUDs can be housing instability, homelessness and unemployment.

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Answer:

a)  -9  [tex]m/s^2[/tex]

b)  112.5 meters

Explanation:

Here is a formula for acceleration.

[tex]a=\frac{V_{f} -V_{o} }{t}[/tex]

We are given

[tex]V_o=45[/tex] m/s

[tex]V_f=0[/tex] m/s

[tex]t=5[/tex] s

Lets solve for [tex]a[/tex].

[tex]a=\frac{0-45}{5}[/tex]

[tex]a=\frac{-45}{5}[/tex]

[tex]a=-9[/tex] [tex]m/s^2[/tex]

Here is a formula for displacment.

[tex]x=V_o t+\frac{at^2}{2}[/tex]

[tex]V_o=45[/tex] m/s

[tex]t=5[/tex] s

[tex]a=-9[/tex] [tex]m/s^2[/tex]

Lets solve for [tex]x[/tex].

[tex]x=45*5+\frac{-9*5^2}{2}[/tex]

[tex]x=225+\frac{-9*25}{2}[/tex]

[tex]x=225+\frac{-225}{2}[/tex]

[tex]x=225+-112.5[/tex]

[tex]x=225-112.5[/tex]

[tex]x=112.5[/tex]

Answer:

I think the answer is the option h

hope this helps you

If relativistic effects are to be less than 6%, then must be less than 1.06. Hence, at a relative velocity (v) of 0.33c, gamma is = 1.06. This problem is solved using the Lorentz Factor.

The Lorentz factor is a correction parameter used to calculate relativity. Without this component, relativistic motion calculations simply fail, and we can obtain speeds that surpass the speed of light, which cannot be.

The calculation to the above solution is given as follows

Given:

γ = 1/ √1-(v²/c²)

It is logical to simplify by squaring both sides

⇒ γ² = 1/ 1-(v²/c²)

Taking the reciprocal of both sides, we have

1-(v²/c²) = 1/γ²

Transposing we have

v²/c² = 1 - 1/γ²

Since we are looking at v, lets us isolate it:

v = √[1 - (1/γ²) · c]

Inserting the Lorentz factor which is

γ = 1.06, we have

v = √[1 - (1/1.06²) · c]

Hence,

v = 0.33c

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Full Question:

If relativistic effects are to be less than 6% then gamma must be less than 1.06. At what relative velocity is gamma = 1.06?

a. The force should be applied 5 m from the fulcrum

b. The issue is that deformation of the rod will occur.

In order to avoid this deformation, with the help of friends, the distance from the can be reduced and more force applied.

The principle of moments states that for a system in equilibrium, the sum of the clockwise moments about a point of rotation is equal to the sum of the anticlockwise moments about that point.

Mathematically;

The moment of a force is the product of the force and the perpendicular distance from its point of action.

From the data provided:

Let the woolly mammoth move in a clockwise direction and the applied force in an anticlockwise direction.

Let d be the perpendicular distance of the applied force from the fulcrum

5000 * 2 m = 2000 * d

d = 5 m

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Answer:

The Earth's major plates are the African plate, the Antarctic plate, the Eurasian plate, the North American plate, the South American plate, and the Pacific plate.

Explanation:

The dog’s linear speed will be 1.88 m/s

The angular speed of the merry-go- round will be  0.85  rad/sec

centripetal acceleration = [tex]v^{2} / r[/tex]

given

r = 2.2 m

linear speed = ?

centripetal acceleration  = 1.6 [tex]m/s^{2}[/tex]

centripetal acceleration C(a) = [tex]v^{2} / r[/tex]

             linear speed = [tex]\sqrt{C(a) * r}[/tex]

                                   = [tex]\sqrt{1.6 * 2.2 }[/tex] = [tex]\sqrt{3.52}[/tex]  = 1.88 m/s

The dog’s linear speed will be 1.88 m/s

angular speed = linear speed / radius

                        = 1.88 / 2.2 = 0.85  rad/sec

The angular speed of the merry-go- round will be  0.85  rad/sec

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Answer:

Approximately [tex](-6)\; {\rm J}[/tex], assuming that [tex]g = 9.81\; {\rm m \cdot s^{-2}}[/tex].

Explanation:

Let [tex]m[/tex] denote the mass of this box.

Decompose the weight [tex]m\, g[/tex] of the box into two components: perpendicular to the slope [tex](-m\, g)\, \cos(15^{\circ})[/tex] and parallel to the slope [tex](-m\, g)\, \sin(15^{\circ})[/tex]. The perpendicular component is balanced with the normal force of the slope on the box. In contrast, since there is no friction between the box and the slope, the parallel component isn't balanced and will be equal to the net force on the box:

[tex]F_{\text{net}} = (-m\, g) \sin(15^{\circ}})[/tex].

Note that [tex]F_{\text{net}}[/tex] is constant during this [tex]t = 1\; {\rm s}[/tex].

The acceleration [tex]a[/tex] of this box will be:

[tex]\begin{aligned}a &= \frac{F_{\text{net}}}{m}\\ &= \frac{(-m\, g) \sin(15^{\circ})}{m} \\ &= (-g)\, \sin(15^{\circ})\end{aligned}[/tex].

Let [tex]u[/tex] denote the initial velocity of this box. Since after the [tex]t = 1\; {\rm s}[/tex] of acceleration at [tex]a = (-g)\, \sin(15^{\circ}})[/tex] the velocity of the box is [tex]v = 0\; {\rm m\cdot s^{-1}}[/tex], the initial velocity of this box will be:

[tex]\begin{aligned} u &= v - a\, t \\ &= 0 - (-g)\, \sin(15^{\circ})\, t \\ &= g\, t\, \sin(15^{\circ}})\end{aligned}[/tex].

Initial kinetic energy of this box would be:

[tex]\begin{aligned} (\text{KE}) &= \frac{1}{2}\, m\, u^{2} \\ &= \frac{1}{2}\, m\, (g\, t\, \sin(15)^{\circ}})^{2}\end{aligned}[/tex].

The kinetic energy of this box is [tex]0[/tex] when the box is at rest. The change in kinetic energy was [tex](1/2)\, m\, (g\, t\, \sin(16^{\circ}))^{2}[/tex]. That energy change should be the opposite of the work the external force weight did on this box.

Substitute in [tex]m = 2\; {\rm kg}[/tex], [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], [tex]t = 1\; {\rm m\cdot s^{-1}}[/tex] to find the change in kinetic energy and hence the work that the net force did on the box:

[tex]\begin{aligned} (\text{Work Done}) &= -(\text{Kinetic energy change}) \\ &= -\frac{1}{2}\, m\, (g\, t\, \sin(15)^{\circ}})^{2} \\ &= -\frac{1}{2}\times 2\; {\rm kg} \times (9.81\; {\rm m\cdot s^{-2}} \times 1\; {\rm s} \times \sin(15^{\circ})^{\circ} \\ &\approx (-6)\; {\rm J}\end{aligned}[/tex].

Distance travelled by insects A and B is respectively 50√26 unit and 300 unit.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Uniform velocity of insect A: [tex]\bold{v_A}[/tex] =  i+4j+3k unit.

Uniform velocity of insect B: [tex]\bold{v_B}[/tex] =  4i+2j-4k unit.

Now dot product of two velocity vector is:

[tex]\bold{v_A}[/tex]·[tex]\bold{v_B}[/tex] = 50 (i+4j+3k)·50( 4i+2j-4k).

= 2500(4 + 4×2 + 3×(-4))

= 0.

Hence, the velocity vectors of two insects are perpendicular to each other. So, the insect fly at right angles to each other.

After time t = 50 unit, Position of insect A: [tex]\bold{X_A}[/tex] = time* velocity

= 50 (i+4j+3k) unit.

After time t = 50 unit, Position of insect B: [tex]\bold{X_B}[/tex] = time* velocity

= 50( 4i+2j-4k).

So, After time t = 50 unit, insect A travels a distance = 50 ×√(1²+4²+3²) = 50√26 unit.

After time t = 50 unit, insect B travels a distance = 50 ×√(4²+2²+(-4)²) = 300 unit.

Hence, distance travelled by insects A and B is respectively 50√26 unit and 300 unit.

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The magnitude and direction of the acceleration of the air balloon, with a mass of 3100 kg and a force of 30000 N acting on it is  9.68 m/s² upward.

Acceleration can be defined as the rate of change of velocity.

To calculate the magnitude and direction of the acceleration, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the magnitude and the acceleration of the air balloon is  9.68 m/s²  upward.

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A)  The reading on the scale is 250 N.

B)  The reading on the scale is 122.45 N.

C)  The reading on the scale is 0 N.

Given parameters:

Weight of the box is : W = 250 N.

As the acceleration due to gravity is 9.8 m/s², the mass of the box be: m = W/g = 250/9.8 kg = 25.51 kg

A) When the elevator is moving upward at constant speed,  there has no acceleration. the reading on the scale remains same and it be 250 N.

B) When the elevator is accelerating downward at 5 meters per second squared, the apparent weight of the box be, W₁ = W  -ma = 250 -25.51×5 N = 122.45 N. So,  the reading on the scale is 122.45 N.

C) If the elevator cables broke and the elevator fell freely,  the elevator is accelerating downward at the same magnitude of acceleration due to gravity, so the apparent weight of the box be, W₁ = W  -mg = 0. So,  the reading on the scale is 0 N.

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Answer:

Speed of light in glass V = 2·10⁸ m/s

Explanation:

Given:

c = 3·10⁸ m/s - The speed of light in vacuum

n = 1.5 - Refractive index of glass

__________

V - ?

Speed of light in glass:

V = c / n

V = 3·10⁸ / 1.5 = 2·10⁸ m/s

Answer:

candle and hand torch

Explanation:

we can find a light energy and heat energy from the candle but only light energy for hand torch

The speed at the edge of a disc of radius 8.5 cm that rotates at the rate of 2.5 rev/s will be 21.25 m/s

Angular velocity is the rate of change of angular displacement  

Mathematically it can also be calculated as linear speed divided by radius

linear speed = omega * radius

                     = 2.5 * 8.5

                     = 21.25 m/s

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Answer:

here, if you have an iron which has 28 protons and 26 electrons, and we have to find the charge on the iron, the element and the symbol of the iron. So For 28 protons charge is 28 e. And for 26 electrons, charge will be -26 E. So total charges 28 E minus 26 E. Equal to two E. On I N S, plus two. No, we have to find the element. So atomic number is equal to Number of protons, which is 28, and this is atomic number four nickels. So the element is nickel and we have to find the symbol of iron. So the iron has to positive child. So the symbol will be and I took place So this completes the solution. Thank you.

Explanation:

If you stand in front of a flat mirror. The one-half of your height will be seen yourself entirely. Option C is the correct answer.

Take a look at your room's four walls. The height of a wall is measured from the ground to the ceiling. Remember how your class is organized in the school assembly, with the tiniest child in the front and the tallest youngster at the back.

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Answer:

[tex]v=3.4081\frac{m}{s}[/tex]

Explanation:

[tex]F=ma\\F=12.4N\\m=7.9kg\\a=\frac{12.4N}{7.9kg}\\a=1.5696\frac{m}{s^2}[/tex]

[tex]v^2=v_0^2+2a\Delta x\\v_0=0\frac{m}{s}\\a=1.5696\frac{m}{s^2}\\\Delta x=3.7m\\v^2=(0\frac{m}{s})^2+2(1.5696\frac{m}{s^2})(3.7m)\\v^2=11.6152\frac{m^2}{s^2}\\v=\sqrt(11.6152\frac{m^2}{s^2})\\v=3.4081\frac{m}{s}[/tex]

Answer:

Explanation:

L₁ =80 dB

S₁ = 2 m

S₂ = 40 m

__________

L₂ - ?

The intensity of the site is nearby:

ΔL = 10·lg(S₂/S₁)²

ΔL = 10·lg(40/2)² = 10·2·lg(20) = 20·1.3 = 26 dB

L₂ = L₁ - ΔL = 80 - 26 = 54 dB

Yes, if two bodies have the same momentum, the velocities of the two objects needs to be equal to be moving in the same direction.

Momentum is the product of mass and velocity of a body in motion. It is a vector quantity.

Two bodies of equal momentum can only move in the same direction if their velocities are equal. This is because both the velocity and the momentum are vector quantities. Momentum is the product of mass, which is a scalar quantity and the velocity, which is a vector.

In conclusion, for two objects to have the same momentum and for their directions to be the same, they need to have the same velocity.

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Yes,  two bodies of equal momentum must be moving in the same direction.

We know that momentum is the product of the mass and the velocity of the object, In fact, momentum is a vector quantity and it should be clearly stated here that the direction of the momentum vector have to be the direction of the velocity vector.

With this said, when we say that two object have the same momentum we are essentially saying that the velocity vector of the two bodies have to pointing in the same direction. Once the direction is not the same, the momentum of the objects can not ever be the same!

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τ=Fd

In this instance, it will

τ=Fballdball+Farmdcenter of mass

τ = 4*9.81*.7 + 4*9.81*.35 = 41.2

and both of our forces have a magnitude of 4g*cos(55), but they are located in different places.

τ = 4g*cos(55)*(.35+.7) = 23.6

The term "magnitude" refers to an object's greatest size and direction. Scalar and vector quantities both use magnitude as a common factor.

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The magnet affected the block of material next to it because it exerts an attractive or repulsive force on other objects.

Magnets do the retinue things: Attract certain materials, such as iron, nickel, cobalt, certain steels, and other alloys. apply an attractive or repulsive force on other magnets (opposite poles attract, like poles repel).  

Magnetic forces are oblivious forces; they pull or push on objects without touching them. Magnets are only attracted to a few 'magnetic' metals and not all matter. Magnets are attracted to and repel other magnets.

So we can conclude that Materials with a magnetic field can attract other materials with such a field. Materials that are not magnets do not have a net outer magnetic field.

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40,000 kg m/s will be the momentum if the truck at a truck mass of 4500kg and velocity of 10 m/s.

Given mass of a truck = 4000 kg

truck mass = 4 grams

velocity = 10 m/s

The formula of momentum will be:

p = mv

where, p = momentum

           m = truck mass

           v = velocity

substituting the values, we get:

momentum = 4000 × 10

momentum = 40000 kg m/s

Thus the momentum of the truck is 40,000 kg m/s

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If the average distance from Venus to the Sun is given to be 0.7AU, its time period is 208.49 days.

Kepler's laws of planetary motion :

According to this law, the semi-major axes of the planets' orbits are directly proportional to the squares of the planets' orbital periods.

radius of the venus = 0.7AU

radius of the earth = 1 AU

orbital period of the earth = 365 days

According to the Kepler's 3rd law of planetary motion :

T² ∝ R³

T² = k R³

k = T²/ R³

[tex]k = \frac{T^2_v}{R^3_v} = \frac{T^2_e}{R^3_e}[/tex]

T² /(0.7)³ = (365)² /(1)³

T = [tex](0.7/1)^{\frac{3}{2}}[/tex] X 365

T = 208.49 days

If the average distance from Venus to the Sun is given to be 0.7AU, its time period is 208.49 days.

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