A surveyor wants to know the length of a tunnel built through a mountain according to his equipment he is located 340 m from the entrance of the tunnel at an angle of 58° to the perpendicular also according to his equipment he is 193 m from the other entrance of the tunnel other angle of 21° to the perpendicular based on these measurements find the length of the entire tunnel

Answers

Answer 1

Answer:

Length of the tunnel is 357.50 meters

Step-by-step explanation:

We are given that,

The surveyor is located 340 meters from one entrance at an angle of 58°.

The surveyor is located 193 meters from one entrance at an angle of 21°.

Let the length of the tunnel = x meters

Using the Law of Cosines,

[tex]x^{2} =(340)^{2}+(193)^{2}-(2)(340)(193)cos(21+58)\\x^{2} =115600+37249-131240cos(79)\\x^{2} =115600+37249-25041.77255\\x^{2} =127807.2274\\x=\sqrt{127807.2274} \\x=357.50 meters\\[/tex]

Hence, the length of the tunnel is 357.50 meters

Related Questions

Solve the differential equation by variation of parameters. y" + y = CSC X y(x) =sin(x)ln(|sin(x)|) + C2cos(x) + C1sin(x) + xcos(x)

Answers

To solve the differential equation y" + y = csc(x) using variation of parameters, we first need to find a particular solution.

Since the non-homogeneous term is csc(x), we can try a particular solution of the form yp = u(x) csc(x), where u(x) is a function to be determined.

Substituting yp into the differential equation:

u''(x)csc(x) + u(x)csc(x) = csc(x)

To find u(x), we can multiply both sides by csc(x) and integrate with respect to x:

∫u''(x)csc(x) dx + ∫u(x)csc^2(x) dx = ∫csc(x) dx

Integrating the first term by parts:

u'(x) = ∫csc(x) dx = ln|cot(x/2)| + C1

Integrating the second term by parts:

u(x) = -∫csc(x)cot(x) dx = -ln|sin(x)| + C2

So, the particular solution for yp is:

yp = u(x)csc(x) = -ln|sin(x)|csc(x) + C1csc(x) + C2

Now we need to find the general solution y = yc + yp

where yc is the general solution for the complementary homogeneous equation y" + y = 0

yc = C1cos(x) + C2sin(x)

Now we can use the method of variation of parameters to find the general solution for the non-homogeneous equation

By this method, we need to find two functions v1(x) and v2(x) such that W(yc, yp) = v1(x)cos(x) + v2(x)sin(x)

W(yc, yp) = (yc * yp') - (yp * yc')

W(yc, yp) = (C1cos(x) + C2sin(x)) * (-cot(x)csc(x) + C1) - (-ln|sin(x)|csc(x) + C1csc(x) + C2) * (-sin(x)cos(x) + cos(x)sin(x))

W(yc, yp) = -C1cot(x)csc(x) + C1^2 + C2csc(x)

As W(yc, yp) is not identically zero, we can proceed to find v1(x) and v2(x)

v1'(x) = -cot(x)csc(x) + C1

v2'(x) = csc(x)

Integrating both sides by parts:

v1(x) = ln|cot(x/2)| - cot(x) + C3

v2(x) = -cot(x) + C4

The general solution for the non-homogeneous equation y" + y = csc(x) is:

y = yc + yp = (C1cos(x) + C2sin(x)) + (sin(x)ln|sin(x)|

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D) 3-2 (s-1) = 13+6s
Answer: -1
E) 2 (n+9) = -6 (2n-5) +8
Answer: 10/7
F) 5 (4k-3) -5k = 10+2 (3k+1)
Answer: 3

Answers

The solution for the variable of each expression is given as follows:

D) 3 - 2(s - 1) = 13 + 6s: s = -1.

E) 2(n + 9) = -6(2n - 5) + 8: n = 10/7.

F) 5(4k - 3) - 5k = 10 + 2(3k + 1): k = 3.

How to solve the expressions?

The expressions are solved applying the distributive property when needed, then combining the like terms, and finally isolating the variable.

The expression for item d is given as follows:

3 - 2(s - 1) = 13 + 6s

Hence:

3 - 2s + 2 = 13 + 6s -> Distributive property.

8s = 5 - 13 -> Combine the like terms.

8s = -8

s = -8/8

s = -1.

The expression for item e is given as follows:

2(n + 9) = -6(2n - 5) + 8

2n + 18 = -12n + 30 + 8 -> Distributive property.

14n = 20 -> Combine the like terms.

n = 20/14

n = 10/7.

The expression for item f is given as follows:

5(4k - 3) - 5k = 10 + 2(3k + 1)

20k - 15 - 5k = 10 + 6k + 2

15k - 15 = 12 + 6k

9k = 27

k = 27/9

k = 3.

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Determine the volume of a sphere with a great circle of radius 12 cm. Question 7 options:A) 7,238.2 cm3 B) 3,216.9 cm3 C) 1,024 cm3 D) 21,714.7 cm3

Answers

The volume of the sphere with a great circle of radius 12 cm is 7238.2 cm³. The correct option is A) 7,238.2 cm3

Calculating the volume of a sphere

From the question, we are to calculate the volume of the sphere with the given radius.

From the formula for calculating the volume of a sphere, we have that

V = 4/3πr³

Where V is the volume

and r is the radius

From the given information,

The sphere has a great circle of radius 12 cm

Thus,

r = 12 cm

Substitute the value of r into the equation,

V = 4/3πr³

That is,

V = 4/3 × π × 12³

V = 4/3 × π × 1728

V = 4 × π × 576

V = 4 × 576 × π

V = 2304π

V = 7238.2 cm³

Hence, the volume is 7238.2 cm³

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a) Two workers laid 250 bricks. If Ram had laid twice as many as he did and Shyam had laid half as many as Ram did, there would have been 50 bricks left over. How many bricks did each lay?​

Answers

Step-by-step explanation:

Let x be the number of bricks Ram laid.

Shyam laid x/2 bricks.

Therefore, x + x/2 + 250 = x(3/2) + 250 = x(3/2) = 300

x = (2*300)/3 = 200

Ram laid 200 bricks.

Shyam laid 200/2 = 100 bricks.

Find the measures of the angles of a right triangle with one angle measuring 45 . I need three measures

Answers

Answer:

Your three angle measurements are 45, 45, and 90

Step-by-step explanation:

Since we know that all the measures of a triangle add up to 180, we have:

45 + b + c = 180

Then, since it is a right triangle, we know one of the sides is 90 degrees, giving us:

45 + 90 + c = 180

Then subtract 135 from both sides:

c = 45

So, your three angle measurements are 45, 45, and 90.

Hope this helped!

An elephant weighs 1.1 * 10 to the 4th power pounds a giraffe weighs 2.1 * 10 to the third power pounds how much more does the elephant weigh than the giraffe

Answers

The elephant weighs 8.9 × 10³ pounds more than the giraffe.

What is weight?

Weight is the gravitational pull of a large second object, like the Moon or the Earth, on a first object. Weight is a result of the universal law of gravitation, according to which any two objects will gravitationally attract one another with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Because of this, larger objects naturally weigh more when placed in the same location; however, the farther an object is from the Earth, the less weight it has.

Given that

Elephant weighs 1.1 × 10⁴ pounds

Giraffe weighs 2.2 × 10³ pounds

To find how much more elephant weighs than giraffe, we need to find the difference of their weights. i.e

1.1 × 10⁴ - 2.1 × 10³

= 11000 - 2100

= 8900

= 8.9 × 10³ pounds

Thus, the elephant weighs 8.9 × 10³ pounds more than the giraffe.

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Steadman Bailey's bank account shows a previous balance of $65.00. He
made $756.00 in deposits. He wrote $44.10 in checks. He had a service
charge of $4.90 and earned $10.00 in interest. What is his present
balance?
VEGHER
PEREKONNAN
FRECEN
CAFETERA
FREETING

Answers

Answer:

present balance=782

Step-by-step explanation:

65+756=821

now has 821 in account

821-44.10=776.9

now has 776.9

776.9-4.90=772

now has 772 in account

772+10=782

he now has 782 in his account

x - 10 = √9x show steps

Answers

The solution of the equation is as follows;

x = -5

How to solve equation?

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign.

The equation can be solved as follows:

x - 10 = √9x

subtract x from both sides of the equation

x - x - 10  = √9x - x

-10 =  √9 x - x

-10 = 3x - x

-10 = 2x

divide both sides by 2

x = -10 / 2

x = -5

Therefore,

x = -5

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WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!
What is the area of ΔABC given m∠B = 95°, a = 22 feet, and c = 17 feet?

34.23 feet2
128.54 feet2
188.29 feet2
34680.46 feet2

Answers

Answer:

Given m∠B = 95°, a = 22 feet, and c = 17 feet, we can use the Law of Cosines to find the value of b and then use Heron's formula to find the area of ΔABC.

The Law of Cosines states:

c^2 = a^2 + b^2 - 2ab * cos(C)

Since ∠B = 95° , angle C = 180 - 95 = 85

Therefore,

c^2 = a^2 + b^2 - 2ab * cos(85)

so,

b = sqrt(c^2 - a^2 + 2ab * cos(85))

We can substitute the given values of a and c to find b:

b = sqrt(17^2 - 22^2 + 2 * 22 * 17 * cos(85))

Once we have the value of b, we can use Heron's formula to find the area of the triangle:

Area = sqrt(p*(p-a)(p-b)(p-c))

where p is the semiperimeter of the triangle: p = (a + b + c) / 2

Area = sqrt(((22 + b + 17) / 2)((22 + b + 17) / 2 - 22)((22 + b + 17) / 2 - b)*((22 + b + 17) / 2 - 17))

The only option that matches this area is 128.54 feet^2, so the area of ΔABC is 128.54 feet^2.

Which of the following scatterplots is most likely to have a line of best fit represented by the equation below?y = -5x + 2

Answers

A scatterplot that shows a negative linear association.

A scatterplot that is most likely to have a line of best fit represented by the equation y = -5x + 2 is the one where the data points have a strong negative linear association. This means that as the x-values increase, the y-values decrease. The slope of the line is -5, which is negative, indicating a negative association. The y-intercept of the line is 2, which represents the point where the line crosses the y-axis.

A scatterplot that shows a negative linear association would have its points distributed in a downward direction from left to right, with a slope of -5.

Therefore, A scatterplot shows a negative linear association will most likely have a line of best fit

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The angles of a quadrilateral are $x$, $5x + 15^\circ $, $3x - 25^\circ$, and $4x - 20^\circ $. Find the measure of the largest angle of the angle

Answers

The measure of the largest angle of the quadrilateral is 88 degrees.

The sum of the angles of a quadrilateral is 360 Degrees. This is derived from the property named Angle Sum property of quadrilateral. We can use this fact to set up an equation using the given information:

x + (5x + 15) + (3x - 25) + (4x - 20) = 360

Simplifying this equation:

13x = 350

x = 27^

Now we can substitute this value of x back into the equation for any of the four angles to find the largest angle:

4x - 20 = 4(27) - 20 = 108 - 20 = 88

Therefore, the measure of the largest angle of the quadrilateral is 88 degrees.

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in the geometric sequence with a first term of $6$ and a second term of $-6$, what is the $205^{th}$ term?

Answers

The 205th term of the given geometric sequence is given by 6

What is a Geometric Sequence?

A geometric sequence is a special type of sequence where the ratio of every two successive terms is a constant. This ratio is known as a common ratio of the geometric sequence.

Given here: The first term of a given geometric sequence as 6 and second term -6.

Thus clearly we can deduce that the common ratio of the sequence is given by -1

Therefore the geometric sequence has two elements that are alternating sequence of the form 6,-6,6,-6,6.........

Therefore the 205th term of the sequence will be given by

T₂₀₅=6×-1²⁰⁵⁻¹

       =6×1

        =6

Hence, The 205th term of the given geometric sequence is given by 6

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a fair die is rolled three times. what’s the probability that it will land on a 2 on the first roll, a 3 on the second roll, and a 4 on the third roll?

1/216

1/6

1/18

1/24

Answers

The probability of having a 2 on first roll, 3 on second roll and 4 on third roll is 1 / 216

What is probability of a fair dice

A fair dice is a dice that is equally likely to land on any of its faces, meaning that each face has the same probability of facing up after a roll. The probability of getting a specific face on a fair dice is represented by the number of ways that face can appear divided by the total number of possible outcomes.

For a standard six-sided fair dice, the total number of possible outcomes is 6, since there are six faces on the dice. The probability of getting a specific face (for example, the number 4) is 1/6, because there is only one way to get that number out of the six possible outcomes.

The probability of landing 2 on first roll, 3 on second roll and 4 on third roll is given as;

P = (1/6 * 1/6 * 1/6)

P = 1 / 216

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Type the correct answer in each box. Write your answers as fractions, using / as the fraction bar, and write the greater value first.if log3 (8x-3)-log 4 = 2, the value of x is

Answers

The value of x 1/2 or 3/2.

The logarithm of any number N if interpreted as an exponential form, is the exponent to which the base of the logarithm should be raised, to obtain the number N. Here we shall aim at knowing more about logarithmic functions, types of logarithms, the graph of the logarithmic function, and the properties of logarithms.

The basic logarithmic function is of the form f(x) = logax (r) y = logax, where a > 0. It is the inverse of the exponential function ay = x. Log functions include natural logarithm (ln) or common logarithm (log). Logarithmic function properties are helpful to work across complex log functions. All the general arithmetic operations across numbers are transformed into a different set of operations within logarithms. The product of two numbers, when taken within the logarithmic functions is equal to the sum of the logarithmic values of the two functions. Similarly, the operations of division are transformed into the difference of the logarithms of the two numbers.

Here, we use:

1) loga/b = log a - log b

2) logba = (logc a)/(logc b)

Given logarithmic equation:

logₓ(8x-3) - logₓ4 = 2

logₓ (8x-3/4) = 2

(8x-3/4) = x²

8x - 3 = 4x²

4x² - 8x + 3 = 0

x = 1/2 or 3/2

Thus, the value of x 1/2 or 3/2.

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Find The Range of y-x=3

Answers

The answer will be(-3,0)

Find the logarithmic function f(x)=log a (x-h) that describes each graph.
PLEASE HELP 100 POINTS+BRAINLIEST

Answers

just an addition to the decent reply above

[tex]\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we will be using this rule}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]f(x)=\log_a(x-h) \\\\[-0.35em] ~\dotfill\\\\ 1=\log_a(\frac{3}{2}-h)\implies a^1=a^{\log_a(\frac{3}{2}-h)}\implies a^1=\cfrac{3}{2}-h\implies a=\cfrac{3}{2}-h \\\\[-0.35em] ~\dotfill\\\\ -1=\log_a(3-h)\implies a^{-1}=a^{\log_a(3-h)}\implies a^{-1}=3-h\implies \cfrac{1}{a}=3-h \\\\\\ 1=(3-h)a\implies 1=(3-h)\left( \cfrac{3}{2}-h \right)\implies 1=(3-h)\left( \cfrac{3-2h}{2} \right) \\\\\\ 2=(3-h)(3-2h)\implies 2=9-9h+2h^2\implies 0=2h^2-9h+7[/tex]

[tex]0=(h-1)(2h-7)\implies \boxed{h= \begin{cases} 1\\\\ \frac{7}{2} \end{cases}}\hspace{5em}a=\cfrac{3}{2}-h\implies \boxed{a= \begin{cases} \frac{1}{2} ~~ ~~ \checkmark\\\\ -2 ~~ \bigotimes \end{cases}} \\\\\\ ~\hfill {\Large \begin{array}{llll} f(x)=\log_{\frac{1}{2}}(x-1) \end{array}} ~\hfill[/tex]

now, why we didn't use the negative value for the base "a"?

from the standpoint of a negative value raised to some exponent, is perfectly fine, however if we plug that in the change of base rule, we run into a really hot pickle.

Answer:

[tex]f(x)=\log_{\frac{1}{2}}(x-1)[/tex]

Step-by-step explanation:

Use the given points to assist in determining the logarithmic function of the given graph in the form:

[tex]f(x)=\log_a(x-h)[/tex]

Substitute the given points (³/₂, 1) and (3, -1) into the formula to create two equations:

[tex]\log_a\left(\dfrac{3}{2}-h\right)=1[/tex]

[tex]\log_a\left(3-h\right)=-1[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\underline{Low law}\\\\$\log_ab=c \iff a^c=b$\\ \end{minipage}}[/tex]

Apply the log law and rearrange each equation to isolate a:

Equation 1

[tex]\begin{aligned}\log_a\left(\dfrac{3}{2}-h\right)&=1\\\\\implies a^1&=\dfrac{3}{2}-h\\\\ a&= \dfrac{3}{2}-h\end{aligned}[/tex]

Equation 2

[tex]\begin{aligned}\log_a\left(3-h\right)&=-1\\\\\implies a^{-1}&=3-h\\\\ \dfrac{1}{a}&=3-h\\\\a&=\dfrac{1}{3-h}\end{aligned}[/tex]

Substitute the first equation into the second to eliminate a:

[tex]\dfrac{3}{2}-h=\dfrac{1}{3-h}[/tex]

Solve for h:

[tex]\implies \dfrac{3}{2}-h=\dfrac{1}{3-h}[/tex]

[tex]\implies \dfrac{3-2h}{2}=\dfrac{1}{3-h}[/tex]

[tex]\implies (3-h)(3-2h)=2[/tex]

[tex]\implies 9-9h+2h^2=2[/tex]

[tex]\implies 2h^2-9h+7=0[/tex]

[tex]\implies 2h^2-2h-7h+7=0[/tex]

[tex]\implies 2h(h-1)-7(h-1)=0[/tex]

[tex]\implies (2h-7)(h-1)=0[/tex]

[tex]\implies h=\dfrac{7}{2},\;1[/tex]

Substitute both values of h into the equations for a:

[tex]h=\dfrac{7}{2}\implies a=\dfrac{3}{2}-\dfrac{7}{2}=-2[/tex]

[tex]h=\dfrac{7}{2}\implies a=\dfrac{1}{3-\dfrac{7}{2}}=-2[/tex]

[tex]h=1\implies a=\dfrac{3}{2}-1=\dfrac{1}{2}[/tex]

[tex]h=1\implies a=\dfrac{1}{3-1}=\dfrac{1}{2}[/tex]

Therefore, the two values of h given is two possible values of a. Since a is the base of the function, and the bases of logarithmic function cannot be negative, the value of a cannot be -2.  Therefore, the only valid value of a is ¹/₂.

Similarly, logs of negative numbers are undefined, therefore the value of h cannot be ⁷/₂ since this would make the argument negative for the points given.  Therefore, the only valid value of h is 1.

Inputting the found values of a and h into the given formula, the logarithmic function of the given graph is:

[tex]f(x)=\log_{\frac{1}{2}}(x-1)[/tex]

Solve the system. {4x^2+4y^2=36 {2x+3y=6

Answers

Substitute 2x+3y=6 into the first equation:

4x^2+4y^2=(2x+3y)^2

4x^2+4y^2=4x^2+12xy+9y^2

0=12xy+5y^2

Divide both sides by 5:

0=2.4xy+y^2

Subtract 2.4xy from both sides:

-2.4xy=y^2

Take the square root of both sides:

y=±√-2.4xy

Substitute y=±√-2.4xy into the equation 2x+3y=6:

2x+3(±√-2.4xy)=6

2x±3√-2.4xy=6

Add 2x to both sides:

4x±3√-2.4xy=6+2x

Subtract 4x from both sides:

±3√-2.4xy=6-4x

Divide both sides by 3:

±√-2.4xy=2-4/3x

Square both sides:

-2.4xy=(2-4/3x)^2

-2.4xy=4-16/3x+8/9x^2

8/9x^2-16/3x+4+2.4xy=0

Use the quadratic equation to solve for x:

x= (16 ± √(256+192y^2))/18

Substitute this back into the equation 2x+3y=6 to solve for y:

2(16 ± √(256+192y^2))/18 + 3y = 6

3y = 6 - 32 ± √(256+192y^2))/9

3y = -26 ± √(256+192y^2))/9

y = (-26 ± √(256+192y^2))/27

Therefore, the solution is:

x = (16 ± √(256+192y^2))/18

y = (-26 ± √(256+192y^2))/27

Hunter is 1. 75 meters tall. At 12 noon, he measures the length of a tree's shadow to be 30. 85 meters. He stands 26. 8 meters away from the tree, so that the tip of his shadow meets the tip of the tree's shadow. Find the height of the tree to the nearest hundredth of a meter

Answers

The height of the tree to the nearest hundredth of a meter is 29.1m.

We can use the concept of similar triangles to find the height of the tree. The ratio of the height of the tree to the length of its shadow is the same as the ratio of Hunter's height to the length of his shadow.

Let h be the height of the tree.

Hunter's height : h = 1.75m : x (where x is the height of the tree)

Hunter's shadow : Tree's shadow = 1.75m : 30.85m

We know that Hunter is 26.8 meters away from the tree, and the tip of his shadow meets the tip of the tree's shadow.

Hunter's shadow = Hunter's height + Tree's shadow

1.75 + x = 30.85

x = 29.1m

Therefore, the height of the tree to the nearest hundredth of a meter is 29.1m.

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How do i do this? I forgot

Answers

Scientific notation 295000 is 295×10³ and standard notation of  7.3×10⁻⁴ is 0.00073 and From least to greatest is 1, 3/2, π/2, √3, 9 and E is the best estimate of √3

What is Number system?

A number system is defined as a system of writing to express numbers.

Scientific notation is a way of expressing numbers that are too large or too small to be conveniently written in decimal form.

295000 is 295×10³

Now let us write 7.3×10⁻⁴ is standard notation

7.3/10000=0.00073

We have to arrange from least to greatest

1, 9, 3/2, √3, π/2

1, 9, 1.5, 1.732, 1.57

From least to greatest is 1, 3/2, π/2, √3, 9

E is the best estimate of √3

Hence, scientific notation 295000 is 295×10³ and standard notation of  7.3×10⁻⁴ is 0.00073 and From least to greatest is 1, 3/2, π/2, √3, 9

E is the best estimate of √3

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a shipping service restricts the dimensions of the boxes it will ship for a certain type of service. the restriction states that for boxes shaped like rectangular prisms, the sum of the perimeter of the base of the box and the height of the box cannot exceed 130130130 inches. the perimeter of the base is determined using the width and length of the box. if a box has a height of 606060 inches and its length is 2.52.52, point, 5 times the width, which inequality shows the allowable width xxx, in inches, of the box?

Answers

The inequality 60 + 5x ≤ 130 shows the maximum width, in inches, of the box that meets the restrictions of the shipping service, given that the box has a height of 60 inches and a length of 2.5 times the width.

1. Let x = the width of the box, in inches.

2. The perimeter of the base of the box is calculated by the following formula: Perimeter = 2(Width) + 2(Length)

3. Therefore, the equation is: 60 + 5x + 2(2.5x) = 130

4. Simplify the equation by expanding the parentheses and combining like terms: 60 + 5x + 5x = 130

5. Solve for x: 5x = 130 - 60

6. Simplify: 5x = 70

7. Divide both sides by 5 to find x: x = 70/5

8. Simplify: x = 14

9. Therefore, the inequality 60 + 5x ≤ 130 shows the maximum width, in inches, of the box that meets the restrictions of the shipping service is 14 inches

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A teacher would like to estimate the true mean amount of time her students spend completing a particular homework assignment. The day the homework is due, the teacher selects a random sample of 30 of her 75 students and records the amount of time that each of them spent completing the assignment. Are the conditions for constructing a t confidence interval met

Answers

The conditions for constructing a t-confidence interval are met.

In order to construct a t-confidence interval for the mean amount of time the students spend completing the homework assignment, the following conditions must be met:

The data must be a random sample from the population of interest
The sample size must be sufficiently large (typically, n > 30)
The data should be approximately normally distributed
The population standard deviation or variance must be unknown
From the information provided it can be inferred that the data is a random sample (30 students out of 75 students) and that the population standard deviation or variance is unknown. If the sample size is greater than 30, and the data is approximately normal or the sample size is large, then the conditions for constructing a t-confidence interval are met.

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-3(y + 2) = 2(y + 6) + 7

Answers

Y=-5 because you move the parentheses distribute -3 then distribute 2 add the numbers move the variable to the left hand side and change its sign

Answer:

y = -5

Step-by-step explanation:

-3(y+2) = 2(y+6)+ seven

-3y-6 = 2y+12+

-3y-6 = 2y + 19

-2 -2

-5y - 6 = 19

  +6 +6

-5y 25

-5 -5

 y = -5

18. in a bag containing only red apples and green apples, the number of red apples is 3 4of the number of green apples. what fraction of the apples in the bag is red? express your answer as a common fraction.

Answers

The fraction of red apples in the bag is 3/ (4+x).

Let there be "x" number of green apples and "y" number of red apples in the bag.

According to the given information,

3/4 * x = y

Therefore, y = 3/4 * x

Since the fraction of red apples is y/ (x+y)

Therefore, fraction of red apples = 3/4 * x / (x+3/4 * x)

Simplifying,

Fraction of red apples = 3/ (4+x)

Therefore, the fraction of red apples in the bag is 3/ (4+x).

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Please help ASAP i will give brainliest if they answer all the questions "100 points"
Thank you Have a good day :)!

Answers

they are the same answer no?

How much Vanilla extract Will be needed to make 2 dozen cookies?

As you answer the following questions, write explanations for why your current answer is correct

Answers

The amount of vanilla extract that will be needed to be able to make 2 dozen cookies is 2 teaspoons of vanilla extract

How to find the amount of vanilla extract ?

The recipe given will be able to yield 1 . 5 dozen of Oatmeal Raisin Cookies  which means that the 1 . 5 teaspoons of vanilla extract will be needed for 1. 5 dozens of Oatmeal Raisin Cookies.

If you are to make 2 dozen cookies therefore, it means that the recipe would require a higher amount of vanilla extract which can be found by the formula:

= ( Dozen cookies needed x teaspoons in  1 .5 dozen ) / 1 . 5 dozen

= ( 2 x 1 . 5 ) / 1 . 5

= 2 teaspoons of vanilla extract

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Solve this 30-60-90 Triangles
Draw the triangle if necessary​

Answers

Answer:

y=11.547004; x= 23.094008.

Step-by-step explanation:

Since 20 = y*sqrt*3; y=11.547004; x= 23.094008.

What is the type of a triangle with sides measuring 5 cm 6 cm and 4 cm?

Answers

Answer:

scalene

Step-by-step explanation:

It is a scalene triangle, meaning all sides are different lengths.  It is NOT a right triangle because the 6 cm side is "too short" to be a hypotenuse.  

[amazon - medium] how many cards would you expect to draw from a standard deck before seeing the first ace?

Answers

Answer:

You would get your first ace at card 10.6 or about card 11.

teri finds a pile of money with at least $\$600$. if she puts $\$200$ of the pile in her left pocket, gives away $\frac45$ of the rest of the pile, and then puts the rest in her right pocket, she'll have more money than if she instead gave away $\$600$ of the original pile and kept the rest. what are the possible values of the number of dollars in the original pile of money? (give your answer as an interval.)

Answers

600 ≤ X < 950 are the possible values of the number of dollars in the original pile of money.

What is range?

The difference between the highest and lowest values in statistics for a particular data collection is called the range. As an illustration, if the data set contains 1, 5, 8, 12, 3, the range will be 12 - 1 = 11. The difference between the greatest and lowest observation might thus also be used to determine the range.

We need to first put the data in ascending order before we can determine the range of a particular set of observations. To determine the range, calculate the difference between the highest and minimum values afterwards.

Let X be the amount in the pile.

What is left after putting $200 in the pile = X - $200

4/5 = 0.8

What she gives away = 0.8 (X - 200)

The remaining is : 0.2 (X - 200) what she puts in her right pocket.

200 + 0.2(X - 200) > X - 600

200 - 0.2X - 40 > X - 600

Solving the inequality we have :

= 160 + 0.2x > X - 600

= 760 > X - 0.2X

= 760 > 0.8X

= 950 > X

This implies : X < 950

It is said : X ≥ 600

The possible range of X is thus : 600 ≤ X < 950

thus, 600 ≤ X < 950 are the possible values of the number of dollars in the original pile of money.

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Kristin spent $25 on a magazine and some notepads. If the magazine cost $5 and each notepad cost $4, then how many notepads did she buy?

Answers

Answer:

5 notepads

Step-by-step explanation:

We know

Kristin spent $25 on a magazine and some notepads

1 magazine = $5

1 notepad = $4

$25 - $5 = $20

How many notepads did she buy?

We take

$20 divided by $4 = 5 notepads

So, she bought 5 notepads

Answer:

5 notepads

Step-by-step explanation:

25=4x+5

subract 5 from 25 and cancel out old 5

20=4x

divide by 4

20/4 = 5

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