A triangle is shown with its exterior angles. The interior angles of the triangle are angles 2, 3, 5. The exterior angle at angle 2 is angle 1. The exterior angle at angle 3 is angle 4. The exterior angle at angle 5 is angle 6.
Which statements are always true regarding the diagram? Select three options.
m∠5 + m∠3 = m∠4
m∠3 + m∠4 + m∠5 = 180°
m∠5 + m∠6 =180°
m∠2 + m∠3 = m∠6
m∠2 + m∠3 + m∠5 = 180°
Answers
Answer:
m∠5 + m∠6 =180°m∠2 + m∠3 = m∠6m∠2 + m∠3 + m∠5 = 180°Step-by-step explanation:
m∠5 + m∠6 = 180° - This is true because the exterior angle and interior angle form a linear pair, and are thus supplementary.
m∠2 + m∠3 = m∠6 - This is true by the exterior angle theorem.
m∠2 + m∠3 + m∠5 = 180° - This is true because the interior angles of a triangle add to 180 degrees.
The three right options are:
m∠5 ₊ m∠6 = 180° which represents a linear pair.
∠2 ₊ ∠3 = ∠6 showing the exterior angle property of triangle.
m∠2 m∠3 m∠5 = 180° as the sum-triangle
sum-triangleproperty.
Given,
the interior angles of the triangle are 2,3,5
the exterior angle at ∠2 is ∠1.
the exterior angle at ∠3 is ∠4.
the exterior angle at ∠5 is ∠6.
Now, take into account a triangle with external angles as ∠1 , ∠4 and ∠6.
Apply the exterior angle property of a triangle.
The sum of the opposing internal angles determines the outer angle of a triangle.
For exterior ∠1 we get
∠1 = ∠5 ₊ ∠3
Similarly, for exterior ∠4 we get
∠4 = ∠5 ₊ ∠2
Then for exterior ∠6 we get
∠6 = ∠2 ₊ ∠3
∴ through the exterior angle property we get the correct option as
m∠6 = m∠2 ₊ m∠3
Now we know the sum-triangle property that sum of the angles in triangle is equal to 180°
∴ m∠2 ₊ m∠3 ₊ m∠5 = 180°
We know the linear pair property i.e, If the angles follow the point where the two lines cross, they are considered to be linear. A linear pair's angles add up to 180° in every case.,
∴ m∠5 ₊ m∠6 = 180°
Hence we get the statements which match the diagram are:
m∠5 ₊ m∠6 = 180°
m∠2 ₊ m∠3 ₊ m∠5 = 180°
m∠6 = m∠2 ₊ m∠3
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Related Questions
Hey guys- need help here. Topic- exponents.
Answers
A projector was sold after allowing 10% discount on the marked price and levying 13% VAT .If the selling price of the projector after discount is Rs 5,850 , less than its selling price with VAT, find the marked price of the projector.
Answers
The marked price of the projector is $50,000.
What is the marked price?The price of the projector after the discount can be represented with:
(100 - 10%)x - 90%x = 0.90x
Where x is the marked price
The price of the projector after the VAT is : (1.13) x 0.90x = 1.02x
Difference in price = 1.02x - 0.90x = 5850
0.12x = 5850
x = 5850 / 0.12
x = $50,000
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Emma is designing a playground for her neighborhood
park. Her drawing has a scale of 1 cm: 3 feet. The length
of her drawing is 15 cm. What will be the actual lenght of
the playground in feet?
Answers
Answer: 45 feet
Answer:
45 feet
Step-by-step explanation:
if 1 cm = 3 ft, we can scale up the drawing from there.
We are multiplying each cm by 3, and considering that length to be 3 feet.
If we had 2 cm, (multiply both by 3) we would have 6 feet.
So, if we had 15 cm, we also need to convert this scale length into actual length. We do this by multiplying
15 × 3 = 45
So, we know that the actual length of the playground in feet is 45 feet.
A stadium has a a central rectangular area 125m long by 80m wide.there are two semi circular ends.a running track goes all the way round. a) what is the total inside length of the curved ends of the track? b) what is the total distance round the inside of the track? c) what is the area inside of the track? (take pi=3.14, give answer to 1 decimal place).
Answers
a)The total inside length of the curved ends of the track will be 25.13 meters
b)The total distance around the inside of the track will be 275.13 meters
c)The area inside the track is 10050 square meters.
What is an area?The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.
Given that:-
A stadium has a central rectangular area 125m long by 80m wide. there are two semi-circular ends. a running track goes all the way around.
a) what is the total inside length of the curved ends of the track?
The length of the curved track means it is a perimeter of the circle so the radius of the semicircle will be 4 meters.
So the length will be = π r + πr = 2 πr
= 2 x π x 4 = 25.13
b) what is the total distance around the inside of the track?
The total distance of the track will be the sum of the length of the two semicircles and the longer side of the rectangle.
Total length = 125 + 125 + 25.13
= 275.13 meters
c) what is the area inside of the track?
The area will be equal to the area of the two semicircular tracks and the rectangular track.
Total Area = Area of semicircle + Area of semicircle + Area of rectangle
= ( π/2 ) r² + (π/2) r² + ( L x W )
= π r² + ( L x W)
= π ( 4 )² + ( 125 x 8 )
= 10050.26 square meters.
Therefore the total inside length of the curved ends of the track will be 25.13 meters. The total distance around the inside of the track will be 275.13 meters. The area inside the track is 10050 square meters.
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find the value of x in the given figure
Answers
To solve this problem, you will first use the Angle Sum Property to determine the value of x after creating an algebraic equation, combining like terms, and subtracting from both sides of an equation.
Use the Angle Sum PropertyThe Angle Sum Property states that all interior angles of a triangle will summate to 180º.
An equation can be created to find this when you are given two angles and missing a third. That third angle can be referred to as x in this scenario.
Adding the two known angles and the unknown angle will result in a sum of 180º. This means that our unknown is x and can therefore be placed in an equation:
[tex]65+42+x=180[/tex]
Combine Like TermsCombine the like terms by combining the constants on the left side of the equation using addition:
[tex]65+42+x=180[/tex]
[tex]107+x=180[/tex]
SubtractAfter combining like terms, subtract 107 from both sides of the equation:
[tex]107 - 107 +x = 180-107[/tex]
[tex]\boxed{x=73}[/tex]
The final answer is x = 73 degrees.
Express (x-8x)^2 as a trinomial in standard form
Answers
Answer:
(x - 8x)²
(x - 8x) (x - 8x).
using the identity
( a - b) ² = a² + b² - 2ab
a = x
b = 8x
x² + 64x - 16x²
Which of the following values can be found by using the formula √1+cos^2 0?
Answers
Let's check
Remove root over and simplify 1+cot²Ø
1+cos²theta/sin²thetasin²Ø+cos²Ø/sin²Ø1/sin²Øcosec²ØPutting root over
cscØSin can be found also along with csc
0.345 recurring as a fraction please - the 3 and 5 are recurring
Answers
Answer:
The decimal 0.345 expressed as a fraction is 69200 .
a. Write an expression for the value of the account at the end of three years in terms of the growth factor x
Answers
find the missing value. 2 + blank = -13
Answers
Answer:
-15
Step-by-step explanation:
-13-2= -15
(to check:2+ -15= -13)
[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{2 + [blank] = -13}[/tex]
[tex]\large\textbf{CONVERT TO: }[/tex]
[tex]\mathsf{2 + b = -13}[/tex]
[tex]\mathsf{b + 2 = -13}[/tex]
[tex]\large\textbf{SUBTRACT 2 to BOTH SIDES: }[/tex]
[tex]\mathsf{b + 2 - 2 = -13 - 2}[/tex]
[tex]\large\textbf{SIMPLIFY IT!}[/tex]
[tex]\mathsf{b = -13 - 2}[/tex]
[tex]\mathsf{b = -15}[/tex]
[tex]\huge\text{Therefore, the mystery number is: \boxed{\mathsf{-15}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
6.11.4 Test(TST): Circles Without Coordinates). The questions are in the document.
Answers
The value of AOB and BOC based in the information given in the circle will be 53°.
How to calculate the values in the circle?From the information given, the central angle is the angle that the vertex is at the center of the circle.
It was stated that OB bisects AOC. Therefore, since AOB is 53°, BOC is also 53°.
The value of AOC will now be:
= AOB + BOC
= 53° + 53°
= 106°
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find the measure of arc DB in P
please hurry if you can
Answers
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex] \qquad \tt \rightarrow \: m \overbrace{DB} + m \overbrace{TB} = 180 \degree[/tex]
[ linear pair ]
[tex] \qquad \tt \rightarrow \: m \overbrace{DB} + 90 \degree = 180 \degree[/tex]
[tex] \qquad \tt \rightarrow \: m \overbrace{DB} = 180 \degree - 90 \degree[/tex]
[tex] \qquad \tt \rightarrow \: m \overbrace{DB} = 90 \degree[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
a Each exterior angle of a regular polygon measures 20° How many sides
does the polygon have?
Answers
Answer:
18
Step-by-step explanation:
The exterior angles of any regular polygon add to 360°, so the answer is 360/20 = 18
The formula for the area of a rhombus is A = a equals StartFraction one-half EndFraction d 1 d 2.d1d2, where d1 and d2 are the lengths of the diagonals.
Which are equivalent equations? Select two correct answers.
Answers
The two equivalent equations are d₁= 2a/d₂ and d₂= 2a/d₁ , Option 2 and 5 is the right answer.
What is a Rhombus ?Rhombus is a quadrilateral with all the sides equal to each other.
It is given that d₁ and d₂ are the lengths of the diagonals.
and Area = a
a = (1/2) d₁ * d₂
2a = d₁ * d₂d₁ * d₂ = 2a
It can be written as
d₁= 2a/d₂
a = (1/2) d₁ * d₂
d₁ * d₂ = 2ad₂= 2a/d₁
Therefore Option 2 and 5 are the correct answer.
The options of this question are:
1. d₁=2Ad₂
2. d₁= 2A/d₂
3. d₂= d₁/2A
4. d₁= 2A/d₂
5. d₂= 2A/d₁
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11. rewrite the function in the form y=a (1+r)*
or y=a (1-r) ² then state the growth or decay
rate. y = a (6) t/a
Please help!!
Answers
Problem 10
The two functions are inverses of each other. Why? Because we can think of f(x) = (x-7)/(-2) as y = (x-7)/(-2).
Swap x and y to get x = (y-7)/(-2). Solving for y leads to y = -2x+7 showing that g(x) = -2x+7 is the inverse of f(x) = (x-7)/(-2). This process can be done in reverse to get the same result.
===================================================
Problem 11
y = a(6)^(t/2)
y = a( 6^(1/2) )^t
y = a(2.4494897)^t
y = a( b )^t
where b = 6^(1/2) = 2.4494897 approximately
Set b equal to 1+r and solve for r
1+r = 2.4494897
r = 2.4494897-1
r = 1.4494897
This rounds to about r = 1.45
The r value is the decimal form of the percentage, which means we move the decimal point over two spots to the right to get 145% approximately
Answers:
The equation is roughly y = a(1 + 1.4494897)^t
The growth rate is approximately 145%
===================================================
Problem 12
You have the correct answer. Nice work.
===================================================
Problem 13
You are very close to the correct answer. However, you're missing the base of the log.
The answer should be [tex]\log_{49}(343) = \frac{3}{2}[/tex]. So you'll need to write in a small "49" under the log.
The general rule is that exponential equations in the form [tex]b^x = y[/tex] are equivalent to the log version of [tex]\log_{b}(y) = x[/tex]. For each equation, b is the base. The idea of logs is to isolate the exponent.
Please help 2 sorry for last one it didnt go through
Answers
Answer:
No, it's not.
Use the drawing tools to sketch the graph of a rational function with a domain of { x | x ∈ R , x ≠ - 5 , 4 } . Include one removable discontinuity and one nonremovable discontinuity. Label each discontinuity using the text tool.
Answers
If [tex]f(x)[/tex] has a removable discontinuity at [tex]x=a[/tex], then the limit
[tex]\displaystyle \lim_{x\to a} \frac{f(x)}{x-a}[/tex]
exists and is finite.
A non-removable discontinuity at [tex]x=b[/tex] would entail a non-finite limit,
[tex]\displaystyle \lim_{x\to b} \frac{f(x)}{x-b} = \pm\infty[/tex]
or the limit does not exist (which could be due to the limits from either side of [tex]x=b[/tex] not matching or existing).
For a rational function, we want
[tex]f(x) = \dfrac{p(x)}{q(x)}[/tex]
where [tex]p[/tex] and [tex]q[/tex] are polynomials in [tex]x[/tex]. To get a removable discontinuity at [tex]x=a[/tex], both [tex]p[/tex] and [tex]q[/tex] must be divisible by [tex]x-a[/tex], and the limit of their quotient after removing these factors still exists. That is,
[tex]\displaystyle \lim_{x\to a} f(x) = \lim_{x\to a} \frac{p(x)}{q(x)} = \lim_{x\to a} \frac{(x-a)p^*(x)}{(x-a)q^*(x)} = \lim_{x\to a} \frac{p^*(x)}{q^*(x)} = \frac{p^*(a)}{q^*(a)}[/tex]
On the flip side, we get a non-removable discontinuity [tex]x=b[/tex] if [tex]p[/tex] is not divisible by [tex]x-b[/tex], in which case
[tex]\displaystyle \lim_{x\to b} f(x) = \lim_{x\to b} \frac{p(x)}{q(x)} = \lim_{x\to b} \frac{p(x)}{(x-b)q^*(x)} = \frac{p(b)}{0\times q^*(b)}[/tex]
and this is undefined.
Suppose [tex]f(x)[/tex] has a non-removable discontinuity at [tex]x=-5[/tex] and a removable one at [tex]x=4[/tex]. Then one such function could be
[tex]f(x) = \dfrac{x-4}{(x-4)(x+5)} = \dfrac{x-4}{x^2+x-20}[/tex]
Please help me with this thanks!!
Answers
Step-by-Step Explanation:
In a Triangle the Sum of all the Angles equal to 180° (Angle Sum Property)
Therefore,
x + 78 + 55 = 180
x + 133 = 180
x = 180 - 133
=> x = 47
Hence, ∠x = 47°
Answer:
x° = 47°
Step-by-step explanation:
The sum of the measurements of three interior Angles in a triangle is 180°.This is known as angle sum property.Same case is here.
78°,55° and x° are interior angles here.
So,
[tex] 78{}^{ \circ} + 55 {}^{ \circ} + x {}^{ \circ} = 180 {}^{ \circ} [/tex]Solving for x°,
[tex]133 {}^{ \circ} + x {}^{ \circ} = 180 {}^{ \circ} [/tex][tex]x {}^{ \circ} = 180 {}^{ \circ} - 133 {}^{ \circ} [/tex][tex]x {}^{ \circ} = \boxed{47 {}^{ \circ} }[/tex]Hence,the value of x° is 47°.
1. What are you going to make? (6 points) (Note: The maximum
build size is 25 cm by 16 cm by 15 cm - about the size of a small
shoe box.)
Answers
Answer: You have already given the answer in the question! You can make a small shoe box.
Find the accumulated amount of an account if the principal amount was 5000 at 16% interest at the end of 3 years
Answers
Answer:
2400
Step-by-step explanation:
Find the accumulated amount of an account if the principal amount was 5000 at 16% interest at the end of 3 years
Solution
The formula for simple interest
S.I = P *R* T/100
Where P = Principal = 5000
R = Rate = 16%
T = Time = 3 years
5000 * 16 * 3/100
50 * 16 * 3
= 2400.
Three teachers shared 4/5 of a flat paper that was donated to the school. what fraction of the flat paper did each teacher receive
Answers
Question 12 of 25
Which of the following values are in the range of the function graphed below?
Check all that apply.
A. -5
B. 3
C. 2
☐D. O
E. 1
F. -3
5
Answers
1 is the values are in the range of the function graphed below. Option E is corect.
What is the difference between domain and range?The domain denotes all potential x values, while the range denotes the domain's possible y values.
The domain is the value of x which lies between the -2 ≤ x ≤ 1.While the range shows the value of y which is equal to 1.
Hence, option E is correct
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A cylinder has a diameter of 14 cm and height of 20cm . find the curved surface area
Answers
Answer:
879.6452 cm
Step-by-step explanation:
The curved surface area of a cylinder is calculated using the formula, curved surface area of cylinder = 2πrh, where 'r' is the radius and 'h' is the height of the cylinder.
diameter = 2r
14=2(r)
7=r
2(π)(7)(20) cm
2(3.14159)(7)(20)
879.6452
Really could use help here.
Answers
Answer:
[tex]\mathsf {y =\frac{15}{7}x }[/tex] < [tex]\mathsf {y=\frac{13}{6}x }[/tex] < [tex]\mathsf {y=\frac{11}{5}x }[/tex] < [tex]\mathsf {y=\frac{21}{9}x }[/tex] < [tex]\mathsf {y= \frac{19}{8}x}[/tex]
Step-by-step explanation:
Finding the unit rate of the graph :
Take 2 points and find the slope⇒ (0,0) and (12, 25)⇒ m = 25 - 0 / 12 - 0⇒ m = 25/12The equation is : y = 25/12xNow, the equations with greater unit rates (in increasing order) are :
[tex]\mathsf {y =\frac{15}{7}x }[/tex] < [tex]\mathsf {y=\frac{13}{6}x }[/tex] < [tex]\mathsf {y=\frac{11}{5}x }[/tex] < [tex]\mathsf {y=\frac{21}{9}x }[/tex] < [tex]\mathsf {y= \frac{19}{8}x}[/tex]find the area of the shaded shape
Answers
Answer:
69 meters squared
Step-by-step explanation:
You can split the shape into two small rectangles by drawing a vertical line. Then, you can solve for the areas of the two rectangles separately and then add them together.
The larger rectangle would have an area of 5 * 12, or 60 m^2.
The smaller rectangle would have an area of 3 * 3, or 9 m^2.
Simply add those together and the total area would be 69 m^2.
Answer:
Area is 69 m
Step-by-step explanation:
please help
Find the sum or type
“impossible”
Answers
Answer:
finished this question is from matric it is very easy
Devonte used the change of base formula to approximate log Subscript 8 Baseline 25. Which expression did Devonte use?
Answers
[tex]\frac{log 25}{log 8}[/tex] is the expression Devonte used the change of base formula to approximate log Subscript 8 Baseline 25.
Given that, Devonte used the change of base formula to approximate log Subscript 8 Baseline 25.
We need to determine the expression did Devonte use.
What is the formula of change of base formula?The change of base formula says [tex]log_{a} b=\frac{log_{c}b }{log_{c}a}[/tex]. It means to change the base of a logarithm logb b a, we just use division [tex]\frac{log a}{log b}[/tex] where these logarithms can have any positive number as a base.
Now, log Subscript 8 Baseline 25 [tex]=log_{8}25[/tex]
[tex]=\frac{log_{10}25 }{log_{10}8}=\frac{log 25}{log 8}[/tex]
Therefore, [tex]\frac{log 25}{log 8}[/tex] is the expression Devonte used the change of base formula to approximate log Subscript 8 Baseline 25.
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Answer:
D
Step-by-step explanation:
\frac { 6 ^ { n + 2 } - 6 ^ { n } } { 6 ^ { n + 1 } + 6 ^ { n } }
Solve this ...
this is the question of laws of indices(exponent)
Answers
Answer:
5
Step-by-step explanation:
Given expression:
[tex]\dfrac{6^{n+2}-6^n}{6^{n+1}+6^n}[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c[/tex]
[tex]\implies \dfrac{6^n6^2-6^n}{6^n6^1+6^n}[/tex]
Factor:
[tex]\implies \dfrac{6^n(6^2-1)}{6^n(6^1+1)}[/tex]
Cancel [tex]6^n[/tex] :
[tex]\implies \dfrac{(6^2-1)}{(6^1+1)}[/tex]
Simplify:
[tex]\implies \dfrac{36-1}{6+1}[/tex]
[tex]\implies \dfrac{35}{7}[/tex]
[tex]\implies 5[/tex]
Insert two pairs of brackets to make this statement true:
-3+-2x5divided by-4+-1=5
Answers
Answer:
-3 + -2x5 / -4 + -1 = 5
(-3 + -2)* 5/ (-4-1) = 5.
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2, 5)? y 5 = x 2 y − 2 = x − 5 y − 5 = −(x − 2) y 2 = −(x 5)
Answers
The equation of the line in point-slope form is: C. y − 5 = −(x − 2).
What is the Point-Slope Equation of a Line?A line with a slope (m) and a point (a, b) is represented in point-slope form as, y - b = m(x - a).
Slopes of perpendicular lines are negative reciprocals of each other. Find the slope of the line in the graph given as follows:
Slope (m) = rise/run = 3 units/3 units = 1
Negative reciprocal of 1 is -1.
The slope of the line would be m = -1.
Substitute m = -1 and (a, b) = (2, 5) into y - b = m(x - a) to wrote the equation:
y - 5 = -1(x - 2)
y − 5 = −(x − 2)
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