A tuning fork of frequency 254 Hz and an open orang pipe of slightly lower frequency are at 15oC. When
sounded together, they produce 4 beats per second. On altering the temperature of the air in the pipes,
it is observed that the number of beats per second first diminishes to zero and then increases again to 4.
By how much has the temperature of the air in the pipe been altered?

Answers

Answer 1

The temperature of the air in the open orang pipe has been altered by 18.73° C

The frequency of an open orang pipe is estimated by using the formula:

[tex]\mathbf{f = \dfrac{v}{2L}}[/tex]

Then, the combination of the frequency of the tuning fork and the open orang pipe is:

[tex]\mathbf{254 - \dfrac{v}{2L} }[/tex]

These combinations of frequency produce 4 beats per sound.

i.e.

[tex]\mathbf{254 - \dfrac{v}{2L} =4}[/tex]

[tex]\mathbf{ \dfrac{v}{2L} = 254-4 }[/tex]

[tex]\mathbf{ \dfrac{v}{2L} = 250 ----(1)}[/tex]

When it is altered, the beats first diminish and increase again by 4.

i.e.

[tex]\mathbf{ \dfrac{v'}{2L} = 254+4 }[/tex]

[tex]\mathbf{ \dfrac{v'}{2L} = 258 --- (2) }[/tex]

If we equate both equations (1) and (2) together, we have:

[tex]\mathbf{\dfrac{v'}{v}= \dfrac{258}{250}}[/tex]

However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.

Hence;

when the temperature of the pipe  = unknown ???the temperature of the open orang pipe = 15

[tex]\implies \mathbf{\sqrt{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \dfrac{258}{250}}[/tex]

By squaring both sides, we have:

[tex]\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \Big (\dfrac{258}{250}\Big )^2}[/tex]

[tex]\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)= \Big (\dfrac{66564}{62500}\Big )}[/tex]

[tex]\implies \mathbf{\Big(\dfrac{273 + T}{288}\Big)= \Big (1.065024\Big )}[/tex]

[tex]\implies \mathbf{273 +T =306.726912 }[/tex]

T = 306.726912 - 273

T ≅ 33.73 ° C

The change in temperature ΔT = 33.73° C - 15° C

The change in temperature ΔT = 18.73° C

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Related Questions

A motorcycle moves according to the velocity-time graph
shown in Figure 3.28. Find the average acceleration of
the motorcycle during each of the following segments of
the motion: (a) A, (b) B, and (c) C.

Answers

Answer:

a) 1 m/s²

b) -1 m/s²

c) 0 m/s² (constant speed, not accelerating)

Explanation:

A

delta speed = 10 - 0

delta time = 10 - 0

delta speed / delta time = 10/10

delta speed / delta time = 1

B

ds = 5 - 10

dt = 15 - 10

ds / dt = -5 / 5

ds / dt = -1

C

ds = 5 - 5

dt = 25 - 15

ds / dt = 0 / 10

ds / dt = 0

The average acceleration of A, B, and C will be 1 m/s², -1 m/s², and 0 m/s².

What is acceleration?

An object is considered to have been accelerated if its velocity changes. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. These examples demonstrate how acceleration occurs whenever a moving object modifies its direction, speed, or both.

There are different types of acceleration :

Uniform accelerationNon-Uniform AccelerationAverage acceleration

Average acceleration is defined as the average change in velocity with respect to the average change in time.

SI unit is m/and it is vector quantity.

According to the question,

For A, Acceleration= (v₁-v₀)/(t₁-t₀)

⇒10-0/10-0

= 1 m/s².

For B, Acceleration= (v₃-v₂)/(t₃-t₂)

⇒5-10/15-10

= -1 m/s²

For C, Acceleration will be constant because change in velocity is constant, this is the case of uniform motion, so its acceleration is also going to be constant (as per the definition of acceleration change in velocity ratio change in time).

For more information about acceleration :

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As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air acts as an ideal gas, calculate the work done per mol of the air.
A. -80.35 J
B. 80.35 J
C. -811.93 J
D. 811.93 J

(please show calculation)
can use this formula W=nRT ln(p1/p2)​

Answers

Answer:

B.-80.35 J

i dont know the calculation



A person of mass 70 kg stands 0.5 m from one end of a 2 m long uniform plank (of negligible mass) that is
being held in equilibrium by two vertical ropes attached to the ends of the plank. What is the tension in the
rope closer to the person?
Help

Answers

Hi there!

We can begin by using a summation of torques, with the fulcrum being at the rope farthest from the person (the other end).

Thus:

F1 = weight of person

R1 = distance of person to fulcrum (farther end)

F2 = Tension of rope closest to person

R2 = distance of rope to fulcrum

∑τ = 0 = R2F2 - R1F1

R2F2 = R1F1

Plug in values:

2F2 = 1.5(700N)

2F2 = 1050 N

F2 = 525 N = Tension of closest rope

)Suppose you have two insulated buckets containing the same amount of water at room temperature. You also happen to have two blocks of metal of the same mass, both at the same temperature, warmer than the water in the buckets. One block is made of aluminum and one is made of copper. You put the aluminum block into one bucket of water, and the copper block into the other. After waiting a while you measure the temperature of the water in both buckets. Which is warmer

Answers

The water in the bucket containing the aluminium block is warmer than the bucket containing the copper block.

The specific heat is the amount of heat needed or required to elevate the temperature of 1 gram of a substance by 1° C.

At standard conditions;

the specific heat of aluminium = 0.215 cal/gm/° Cthe specific heat of copper = 0.0923  cal/gm/° C

We know that:

Heat loss by the metal block = Heat gained by the water bucket

Therefore, since the specific heat of aluminium is higher than that of copper, the water bucket containing aluminium block will be warmer than the bucket containing the copper block.  

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A racecar can be slowed with a constant acceleration of -14 m/s2. If the car is going 75 m/s, how many meters will take to stop?​

Answers

Answer:

Explanation:

v² = u² + 2as

s = (v² - u²)/2a

s = (0² - 75²) / (2(-14))

s = 200.8928

s = 200 m

Answer:

Identification

Explanation:

:-;..........

. If the frequency of a system undergoing simple harmonic motion doubles, by what factor does the maximum value of acceleration change

Answers

Answer:

a1 = -w^2 A sin w t        where w is the angular frequency

a2 =  - (2 w)^2 A sin 2 w t       where w2 = 2 w1

a2 / a1 = 4 sin 2 w t / sin  w t

Since sin 2 w t / sin w t = 2     sin w t will change twice as fast

a2 / a1 = 8      the max acceleration must change 8 tims as fast

Work is required to lift a barbell. How many times more work is required to lift the barbell 2 times as high?

Answers

Answer:

2 times more work

Explanation:

Work is a force times distance

W = Fd

The barbell does not change mass so its weight (force) is constant.

That means work is directly proportional to the distance traveled.

twice the distance means twice the work.

What is the volume of 150g of a substance that has a density of 150g of a substance that has a density of 11.3g/cm3

Answers

Answer:

25.0 cm3

Explanation:

The volume is 25.0 cm3 .

The less dense areas created as a sound wave propagates are called
A. rarefactions✅
B. troughs
C. crests
D. compressions

Answers

Answer:

C. crests

don't trust me though

Answer:

The less dense areas created as a sound wave propagates are called rarefactions.

Explanation:

Hoped this helped.

¿Por qué el origen de ciertos metales se relaciona con la dinámica terrestre?

Answers

Yo no hablo espanol

10. What is Newton's 3rd Law?
O A. For every action there is an equal and opposite reaction.
B. Acceleration depends on two variables, the mass of the object and the amount of
force.
C. An object at rest will stay at rest, an object in motion will stay in motion, unless an
unbalanced force acts upon it.
D. The amount of matter in an object.
7. What is Newton's 2nd Law? *

Answers

Answer:

A. For every action there is an equal and opposite reaction.

Newton’s 3rd law is A. For every action there is an equal and opposite reaction.

Newton’s 2nd law is B. Acceleration depends on two variables, the mass of the object and the amount of force. (Acceleration = force/mass)

name two examples where the cohesive force dominates over the adhesive force and vice versa​

Answers

Attractive forces between molecules of the same type are called cohesive forces. ... Attractive forces between molecules of different types are called adhesive forces. Such forces cause liquid drops to cling to window panes, for example.

Cohesive forces are the forces that draw molecules of the same type together. Adhesive forces are those that draw molecules of various types together.

What is the difference between cohesive force and adhesive force?

Cohesive forces are the forces that draw molecules of the same type together. Adhesive forces are those that draw molecules of various types together.

The force that draws molecules of the same substance together is called the cohesive force. The force that holds molecules of various substances together is known as the adhesive force.

Between molecules of the same substance, there are cohesive forces. There is a natural tendency to resist separation due to these intermolecular forces between like elements. Conversely, adhesive forces draw disparate molecules together.

In physics, cohesion refers to the intermolecular attraction that exists between two adjacent parts of a substance, especially one that is solid or liquid. A piece of matter is held together by this force. Adhesion is a term for the intermolecular forces that act when two dissimilar substances come into contact.

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At a distance of 1 cm from the source, the flux from the isotropic source is one hundred times brighter. Which source is brighter fifty centimeters away

Answers

Answer:

op

Explanation:

At a distance of 1 cm from the source, the flux from the isotropic source is one hundred times brighter. Which source is brighter fifty centimeters away

2) A ray of light in air is approaching the boundary with water at an
angle of 52 degrees. Determine the angle of refraction of the light
ray. (Refractive index of air = 1, water = 1.33)
=

Answers

Answer:

Explanation:

ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface

          n₁sinθ₁ = n₂sinθ₂

          1 sin52 = 1.33sinθ₂

                  θ₂ = arcsin(sin52 / 1.33)

                  θ₂ = 36°

as measured from the perpendicular to the surface

Is acceleration included in a force diagram? Why?

Answers

Answer:

No

Explanation:

Acceleration is not a "Force"

The only things added on a force diagrams are forces that are acting on the object. Force causes acceleration to change but it is not a force itself and is not included on a force diagram.

6. A 15.53 kg bag of soil falls 5.50 m at a construction site. If all the energy is retained by the soil in the bag, how much will its temperature increase

Answers

The increase in the temperature of the soil when bag fall from the given height is 0.065 ⁰C.

The given parameters:

mass of the bag, m = 15.53 kgheight of fall, h = 5.5 mspecific heat capacity of soil, C = 0.200 kcal/kg ⁰C

Apply the principle of conservation of energy as follows;

[tex]mgh = mC \Delta T\\\\gh = C \Delta T\\\\\Delta T= \frac{gh}{C}[/tex]

Convert the value of C in kcal/kg ⁰C  to  J/kg ⁰C

1 kcal = 4180 J

[tex]0.200 \ kcal/kg ^0 C= 0.2 \times 4180 (J/kg ^0C) = 836 \ J/kg^0 C[/tex]

The increase in the temperature of the soil is calculated as follows;

[tex]\Delta T= \frac{gh}{C}\\\\\Delta T= \frac{9.8 \times 5.5}{836} \\\\\Delta T= 0.065 \ ^0C[/tex]

Learn more about conservation of energy here: https://brainly.com/question/166559

The coefficient of kinetic friction for a 22 kg bobsled on a track is 0.10. What force is required to push it down a 5.0 degree incline and achieve a speed of 62 km/h at the end of 75 m

Answers

Hi there!

We must begin by converting km/h to m/s using dimensional analysis:

[tex]\frac{62km}{1hr} * \frac{1hr}{3600sec}*\frac{1000m}{1km} = 17.22 m/s[/tex]

Now, we can use the kinematic equation below to find the required acceleration:

vf² = vi² + 2ad

We can assume the object starts from rest, so:

vf² = 2ad

(17.22)²/(2 · 75) = a

a = 1.978 m/s²

Now, we can begin looking at forces.

For an object moving down a ramp experiencing friction and an applied force, we have the forces:

Fκ  = μMgcosθ  = Force due to kinetic friction

Mgsinθ = Force due to gravity

A = Applied Force

We can write out the summation. Let down the incline be positive.

ΣF = A + Mgsinθ - μMgcosθ

Or:

ma = A + Mgsinθ - μMgcosθ

We can plug in the given values:

22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))

A = 46.203 N

If it takes 50.0 seconds to lift 10.0 Newtons of books to a height of 7.0
meters, calculate the power required to lift it?

Answers

Work of the force = 10 N

Time required for the work = 50 sec

Height = 7 m

We are given with the value of work and time in the question.

Substitute the values in the formula of power and then you'll get the power required.

We know that,

w = Work

p = Power

t = Time

By the formula,

Given that,
Work (w) = 7 m = 70 Joules
Time (t) = 50 sec
Substituting their values,

p = 70/50

p = 1.4 watts

Therefore, the power required is 1.4 watts.

Hope it helps!

I need to choose a theme for my physics assignment My experiment is finding g

Answers

Question:

How to find g (acceleration due to gravity)

Solution:

We know,

Acceleration due to gravity (g)

[tex] = \frac{GM}{ {R}^{2} } [/tex]

where, G = Gravitational constant

[tex] = 6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \\ [/tex]

M = Mass of the earth

[tex] = 6 \times {10}^{24} \: kg[/tex]

R = Radius of the earth

[tex] = 6.4 \times {10}^{6} m[/tex]

Putting these values of G, M and R in the above formula, we get

[tex]g \: = \: \frac{6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \times \: 6 \times {10}^{24} \: kg }{(6.4 \times {10}^{6}m {)}^{2} } \\ = 9.8m/ {s}^{2} [/tex]

So, the value of acceleration due to gravity is

[tex]9.8m/s ^{2} [/tex]

Hope it helps.

Do comment if you have any query.

There is a uniform magnetic field of magnitude B, pervading all space, perpendicular to the plane of rod and rails. The rod is released from rest, and it is observed that it accelerates to the left. In what direction does the magnetic field point?

Answers

The right hand rule to find the direction of the magnetic field for a falling bar is:

The charge is positive the magnetic field is outgoing, horizontally and towards us. The charge of the bar is negative, the magnetic field is incoming, that is horizontal away from us.

The magnetic force is given by the vector product of the velocity and the magnetic field.

        F = q v x B

Where the bolds indicate vectors, F is the force, q the charge on the particle, v the velocity and B the magnetic field.

In the vector product, the vectors are perpendicular, which is why the right-hand rule has been established, see attached:

The thumb points in the direction of speed. Fingers extended in the direction of the magnetic field. The palm is in the direction of the force if the charge is positive and in the opposite direction if the charge is negative.

They indicate that the bar is dropped, therefore its speed is vertical and downwards, it moves to the left therefore this is the direction of the force, we use the right hand rule, the magnetic field must be horizontal, we have two possibilities:

If the charge is positive the magnetic field is outgoing, horizontally and towards us. If the charge of the bar is negative, the magnetic field is incoming, that is, horizontal away from us

In conclusion using the right hand rule we can find the direction of the magnetic field for a falling bar is:

The charge of the bar is negative, the magnetic field is incoming, that is horizontal away from us.The charge is positive the magnetic field is outgoing, horizontally and towards us.

Learn more about the right hand rule here:  brainly.com/question/12847190

why is cooking faster with a pressure cooker. plz help me I beg​

Answers

Explanation:

The same thing happened in pressure cooker but the temperature inside is most higher.

hope you like my answer

thank you

Because cooking reactions speed up at a higher temperature also the boiling temperature of water increases and hence, the food cooks faster.

source:

https://www.vedantu.com/question-answer/a-pressure-cooker-reduces-cooking-time-for-food-class-9-chemistry-cbse-5feaba32e9fb3d3419e4a61a


I will mark brainlist

If a wave’s amplitude is 2cm, then its height is equal to:



5 cm.



0 cm



4 cm.



2 cm

Answers

Answer:

4 cm

Explanation:

Amplitude is the measure from the MIDLINE to the peak of the wave....so the wave HEIGHT is twice the ampltude

2 x 2 cm = 4 cm

2. An auditorium has 58 seats in the first row, 62 seats in the second row, 66 seats in the third row, and so
on.
a)Find the explicit formula of this arithmetic sequence.

B) find the number of seats in the twentieth row.

Answers

The answer is (a) hope it helped!<3






Help please..
Kepler’s third law states that:
A. the orbits of the planets are elliptical.
B. the planets move slower when they are closer to the Sun and faster when they are farther from the Sun.
C. the square of the ratio of the periods of any two planets revolving around the Sun is equal to the cube of the ratio of their average distance from the Sun.
D. objects attract other objects with a force that is directly proportional to the product of their masses, and inversely proportional to the square of the distance between them.

Answers

Answer:

c

Explanation:


E5. A ball is thrown downward with an initial velocity of 12 m/s.
Using the approximate value of g 10 m/s2, what is the
velocity of the ball 1.0 seconds after it is released?

Answers

Hi there!

We know the following kinematic equation:

vf = vi + at

Where:

vf = final velocity

vi = initial velocity

a = acceleration

t = time

In this instance, the ball is experiencing a constant acceleration of that of gravity, thus:

vf = 12 + 10(1) = 22 m/s (if downward is considered positive in this instance)

Kinesha and her friend were watching a solar eclipse. Kinesha explains to her friend that a solar eclipse means that Earth is located between the Sun and the Moon. Her friend tells Kinesha that her explanation is incorrect. Why?

Answers

this is where the sun and moon line up where you asleep only a tiny bit of the sun it's pretty cool to see

Explanation:

a solar eclipse means when the moon goes infront of the sun and the earth turns dark

HELPP

When two forces are in opposite directions, and they are the exact same magnitude, the forces will _______.

a. subtract from each other
b. cancel out
c. go on infinitely
d. eventually reach equilibrium

Answers

Answer:

i think the correct answer is B. cancel out

What will be the speed of these waves (in terms of V) if we increase M by a factor of 18.0, which stretches the wire to double its original length

Answers

The speed of the chord wave allows finding a new speed when the mass is increased and the chord length is:

The velocity is: v = [tex]\frac{v_o}{3}[/tex]  

A wave is a periodic movement of the particles that carries energy, but not matter, the speed of the waves is related to the properties of the medium by the relationship.

           [tex]v = \sqrt{\frac{T}{\mu } }[/tex]  

Where v is the speed of the wave, T the force and μ is the linear density.

Indicates that the applied mass increases by a factor of 18.0 and the length of the head is increased to twice the original.

The linear density of the cable is

          [tex]\mu = \frac{m}{l}[/tex]

Where m is the mass of the cable and l is the length.

Let's use the subscript "o" for the initial conditions.

          M = 18.0 m₀

          l = 2 l₀

We look for the density.

         [tex]\mu = \frac{18.0 m_o}{2.0 l_o}[/tex]mu = 18.0 mo / 2 lo

         [tex]\mu = 9.0 \mu_o[/tex]  

We substitute in the expression for the velocity assuming that the tension is kept constant.

        [tex]v= \sqrt{\frac{T}{9.0 \mu} }[/tex]  

        [tex]v= \frac{v_o}{3}[/tex]  

In conclusion, using the speed of the chord wave we can find a new speed when the mass is increased and the chord length is:

The velocity is: v = [tex]\frac{v_o}{3}[/tex]

Learn more about wave speed here:  brainly.com/question/16824509

i mark u brainliest answer please answer me​

Answers

Answer:

bathing and wear clean clothes 2 pollute 3throwing waste in land air water pollution

An electromagnet does not attract a piece of iron.Is it true ? Give reason

Answers

Answer:

False..

Explanation:

An electoMagnets attract iron due to the influence of their magnetic field upon the iron. ...

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