The coefficient of kinetic friction between the chair and the waxed floor, does she just reach the glass without knocking it over is,
[tex]\mu_k[/tex]= Coefficient of kinetic friction = 0.102
What is kinetic friction?The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing motion between the two surfaces.
Greek letter mu (μ) is typically used to represent it. In mathematics, is equal to F/N, where F is the frictional force and N is the normal force.
The coefficient of friction is dimensionless because both F and N are expressed in units of force (such as newtons or pounds).
For both static and kinetic friction, the coefficient of friction has different values. When an object experiences static friction, the frictional force resists any applied force, and the object stays at rest until the static frictional force is removed.
Using Energy conservation:
KEi + PEi + Wf = KEf + PEf
KEi = 0, since initially Albertine was at rest
KEf = 0, since finally Albertine need to be at rest to just reach the glass
PEi = (1/2)*k*x^2 = Initial Potential energy due to compression of spring
PEf = 0 (since at final position compression in spring is zero)
Wf = Work-done by friction = Ff×d = -μκ*m*g*d
So,
0 + (1/2)*k*x^2 -[tex]\mu_k[/tex]*m*g*d = 0 + 0
[tex]\mu_k[/tex]= k*x^2/(2*m*g*d)
Using given values:
[tex]\mu_k[/tex] = 95.0*5.00^2/(2*60.0*9.80*19.8)
[tex]\mu_k[/tex]= Coefficient of kinetic friction = 0.102
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A wire of resistance R connected in series with 1.5V cell is found to be carrying a current of 0.05A. If the wire is now connected i parallel with an identical wire, find the new current in the circuit
Answer:Assuming, The new circuit is like the circuit attached below, the current in the new circuit will be 0.1 Ampere.
Explanation: Given, We have Potential Difference of 1.5V, Current of 0.05A.
Now, we know V = I x R ,where V is potential difference, I is current and R is resistance in the circuit.
∴ Putting the values ⇒ 1.5V = 0.05A x R
⇒R = 1.5/0.05
∴R = 30 Ω
Now, It is said that A same identical wire is connected in parallel with the previous wire.
∴ New R will be ⇒ [tex]\frac{1}{R(new)}[/tex] = [tex]\frac{1}{r} + \frac{1}{r}[/tex]
=[1/30] + [1/30]
=1/15
∴ 1/R(new) = 15 Ω
Now, New Current in the circuit will be:
⇒ V= IR
⇒1.5V = I x 15
⇒I = 0.1 A
Therefore, Answer will be 0.1 ampere.
1. Helium gas is cooled from 20 °C to 10 °C by expanding from 40 atm to 1 atm. If there is 1.4 mol of helium,
(a) What is the final volume of helium?
(b) What is the change in internal energy?
By expanding from 40 atm to 1 atm, helium gas is cooled from 20 °C to 10 °C. If there is 1.4 mol of helium;(a) The final volume of helium is 28.7 L.(b) The change in internal energy is -453.8 kJ.
What is the volume?Volume is a measure of the amount of three-dimensional space an object takes up. It is measured in units of cubic units, such as cubic meters, cubic centimeters, or cubic inches. Volume is often used to measure the size of liquids, solids, and other substances. It is also used to calculate the amount of space an object occupies, such as a room, box, or container. Volume is a useful tool to calculate the amount of an ingredient in a recipe or mixture, or to measure the capacity of a storage container.
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during which time interval(s) (AB,BC,CD,DE,EF,FG) WAS THE CART AT REST
The time intervals in which the cart is at rest are AB, CD and EF.
What is rest in motion of a cart?
During the motion of a cart, the cart is said to be at rest when the change in the position of the cart with time is zero.
It can also be defined as the points in which the cart is at a constant position during a given time interval or zero speed.
Mathematically, the motion of a cart is determined by applying the following formula as shown below;
v = Δx / Δt
v = ( x₂ - x₁ ) / ( t₂ - t₁ )
where;
x₂ is the final position of the cartx₁ is the initial position of the cartt₂ is the final time of motiont₁ is the initial time of motionThe speed of the cart at point A and B;
v = ( - 5 - ( - 5 ) / ( 5 - 0 ) = 0
The speed of the cart at point C and D;
v = ( - 2 - ( - 2 ) / ( 20 - 11 ) = 0
The speed of the cart at point E and F;
v = ( 8 - 8 ) / ( 40 - 30 ) = 0
Thus, the cart is said to at rest if the speed of the cart is zero.
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A pilot light is typically wired in series with a/an____ to indicate whether the fan is moving air
A. auxiliary contact
B. thermostat
C. flow switch
D. thermal overload
to indicate whether the fan is moving air.
A pilot light is typically wired in series with a thermostat to indicate whether the fan is moving air
Who is a pilot?We know that the pilot is such a person that have been trained so as to be able to fly the air plane. This is the individual that can be able to control a plane and there are tools that the pilot would have to use to do his job.
Now we know that the pilot light is one of the tools that the pilot can use to be able to use in the discharge of his job when he is flying the air craft that is moving and it has to be in series with the thermostat.
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A tumbleweed is bouncing through the desert with a speed of 11 m/s. If the tumbleweed has 199.65 J of kinetic energy, what is the mass of the tumbleweed?
____kg
The speed of a moving bullet can be determined by allowing the bullet to pass through
two rotating paper disks mounted a distance
97 cm apart on the same axle. From the
angular displacement 12.9◦
of the two bullet holes in the disks and the rotational speed
1319 rev/min of the disks, we can determine
the speed of the bullet.
What is the speed of the bullet?
Answer in units of m/s.
Answer:
f = 1219/min = 1219 / 60 / sec = 20.32 / sec
T = 1/f = 1 / 20.32 = .04922 sec period of 1 revolution
t = 12.9 / 360 * .04922 = .001764 sec time to pass between disks
V = S / t = .97 m / .001764 = 550 m/sec
Dr. Burke performs an experiment to determine how plants grow in a variety of temperature and moisture conditions. He runs five trials with five different groups of the same species of plant. The table below shows the results from his experiment. Plant Group Temperature Moisture Average Plant Growth Group 1 high high 2 in Group 2 moderate moderate 6 in Group 3 low low 0 in Group 4 high moderate 3 in Group 5 moderate high 4 in After finishing the experiment, Dr. Burke explains that heat and moisture have no effect on plant growth. Based on the evidence shown in the table, is his explanation valid?
No, his explanation is not valid. The data from the experiment shows that both temperature and moisture do have an effect on plant growth.
What is the temperature?
An object's temperature serves as a gauge for its heat or coldness. Temperature is usually measured in degrees on the Celsius or Fahrenheit scales. At a temperature of 0 degrees Celsius (or 32 degrees Fahrenheit), water freezes. At 100 degrees Celsius (or 212 degrees Fahrenheit), water boils. Temperature can affect how quickly things happen, such as the speed at which a chemical reaction takes place. Temperature also affects how people and other living things feel and behave.
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A small toy car of mass 3.00kg runs into another toy car of mass 2.00kg at rest. They stick together and slide 2.0 meters along the rough floor m = 0.25. how fast was the first car going when it hit the ground car? Is this collision elastic or inelastic?
Answer:
Explanation:To determine the speed of the first car when it hit the second car, we can use the conservation of momentum. The momentum of the first car before the collision is equal to its mass multiplied by its velocity, and the momentum of the two cars after the collision is also equal to their combined mass multiplied by their combined velocity.
The momentum of the first car before the collision is 3.00kg * v1 = m1 * v1
The momentum of the two cars after the collision is (3.00kg + 2.00kg) * v2 = (m1 + m2) * v2
From the conservation of momentum, we can set these two equations equal to each other and solve for v1:
m1 * v1 = (m1 + m2) * v2
v1 = (m1 + m2) * v2 / m1
v1 = (3.00kg + 2.00kg) * v2 / 3.00kg
v1 = 5.00kg * v2 / 3.00kg
v1 = (5/3) * v2
The combined velocity of the two cars after collision is v2 = 2.0m / (2.0s) = 1.0m/s
Therefore, the first car was going at (5/3) * 1.0m/s = 1.67m/s.
To determine if this collision is elastic or inelastic, we need to calculate the coefficient of restitution (e).
e = (initial velocity of first car - final velocity of first car) / (initial velocity of first car)
The initial velocity of the first car was 1.67m/s and final velocity of the first car is 0 m/s (since it stops after the collision).
e = (1.67m/s - 0m/s ) / (1.67m/s)
e = 1.0
The coefficient of restitution is 1.0, which means the collision is perfectly elastic. This means that the kinetic energy is conserved in the collision.
a small, 250 g cart is moving at 1.60 m/s on a frictionless track when it collides with a larger, 3.00 kg cart at rest. after the collision, the small cart recoils at 0.840 m/s .
what is the speed of the large cart after the collision?1
m(small cart) = 250 g = 0.25 Kg
vi(small cart) = 1.60 m/s
m(large cart) = 3.00 kg
vi(large cart) = 0 m/s
vf(large cart) = ?
The speed of the larger cart after the collision is 0.084 m/s.
The principle of conservation of momentum states that the total momentum of an isolated system remains constant if no external forces act on the system. In this case, the momentum of the two carts before the collision is equal to the momentum of the two carts after the collision. We can use this principle to find the speed of the larger cart after the collision.
Let's call the speed of the larger cart after the collision "v".
Before the collision:
momentum = m1 * v1 = (250 g) * (1.60 m/s) = 0.25 kg * 1.60 m/s
After the collision:
momentum = (0.25 kg * 0.840 m/s) + (3.00 kg * v) = 0.25 kg * 0.840 m/s + 3.00 kg * v
Setting the before and after momenta equal:
0.25 kg * 1.60 m/s = 0.25 kg * 0.840 m/s + 3.00 kg * v
Solving for v:
v = (0.25 kg * 1.60 m/s - 0.25 kg * 0.840 m/s) / 3.00 kg
v = (0.25 kg * 0.760 m/s) / 3.00 kg
v = 0.25 kg / 3.00 kg * 0.760 m/s
v = 0.084 m/s
So the speed of the larger cart after the collision is 0.084 m/s.
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A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a stretched position. The position of the mass at any time is described by x = (8.8 cm)cos[2t/(4.18 s)]. Determine the following.
(a) period of the motion
(b) frequency of the oscillations
Hz
(c) first time the mass is at the position
x = 0
(d) first time the mass is at the site of maximum compression of the spring
A. The period of the motion is 4.18 s
B. The frequency of the oscillations
Hz is 0.2393 Hz
C. The first time the mass is at the position
x = 0 is 2.09 s
D. The first time the mass is at the site of maximum compression of the spring is 6.27s
How do we determine the values?a) The period of motion is given by the time it takes for the mass to complete one full oscillation. From the equation given, x = (8.8 cm)cos[2t/(4.18 s)], we can see that the function is in the form x = A cos(ωt + φ). The period of the motion T is given by the reciprocal of the angular frequency ω, which is T = 2π/ω.
In this case, the angular frequency is given by the coefficient of t in the argument of the cosine function, 2t/(4.18 s). So,
T = 2π/(2/(4.18 s)) = 4.18 s
b) The frequency of oscillations, f, is given by the reciprocal of the period, so
f = 1/T = 1/4.18 s^-1 = 0.2393 Hz
c) To find the first time the mass is at the position x = 0, we need to find the value of t when the cosine function is equal to 1.
x = (8.8 cm)cos[2t/(4.18 s)] = 8.8cm * 1 = 8.8cm
so,
cos[2t/(4.18 s)] = 1
t = (4.18 s)/2 = 2.09 s
d) To find the first time the mass is at the site of maximum compression of the spring, we need to find the value of t when the cosine function is equal to -1.
x = (8.8 cm)cos[2t/(4.18 s)] = 8.8cm * (-1) = -8.8cm
so,
cos[2t/(4.18 s)] = -1
t = (4.18 s) + (2.09 s) = 6.27s
It should be noted that the mass will be at the site of maximum compression at t = 6.27s and t = 2.09s + 4.18s = 6.27s + 4.18s = 10.45s and so on.
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2. A student attempts to fire a small steel sphere (mass= 250 g) into a cup from a spring-loaded cannon affixed to a table.
The cup is located 74.7 cm from the table's edge. If compressing the spring by 2.2 cm results in the sphere travelling
82.2 cm, by what distance should the spring be compressed to project the sphere into the cup?
From conservation of energy, the distance the spring should be compressed is 2 cm
What is Work ?The work done on an object is the product of force and distance in the direction of the force.
Given that a student attempts to fire a small steel sphere (mass = 250 g) into a cup from a spring-loaded cannon affixed to a table.
The cup is located 74.7 cm from the table's edge.
If compressing the spring by 2.2 cm results in the sphere travelling 82.2 cm, then,
the elastic potential energy = work done on the object
1/2ke² = Fs
Where F = mg = 0.25 × 9.8
F = 2.45 N
1/2 × k × (2.2/100)² = 2.45 × 82.2/100
0.000242K = 2.0139
k = 2.0139/0.000242
k = 8321.9 N/m
The distance the spring should be compressed in order to project the sphere into the cup can be known by using the same formula since k is the same elastic constant.
1/2ke² = Fs
1/2 × 8321.9 × (e)² = 2.45 × 74.7/100
4161e² = 1.83015
e² = 1.83015/4161
e² = 0.00044
e = √0.00044
e = 0.02 m
e = 2 cm
Therefore, the spring should be compressed by 2 cm in order to project the sphere into the cup.
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How do you get part (c)?
Part (a) Which statement best describes the numbers of protons and electrons in the penny when it is charged as indicated?
Electrons were added, and the number of electrons exceeds the
number of protons. ✔ Correct!
Part (b) How many electrons were transferred in order to create the charge on the penny?
Ne = 6.88 * 109
Ne = 6.880×109electrons ✔ Correct!
Part (c) By what percentage do the transferred electrons change the mass of the penny? (Express your result as a positive percentage for an increase, negative for a decrease.)
The percentage at which the transferred electrons change the mass of the penny is 0 %.
What percentage is the mass of the penny changed?
The percentage at which the transferred electrons change the mass of the penny is calculated by applying the following formula as shown below.
Mathematically, the formula for percentage change is given as;
percentage change = ( New mass - old mass ) / ( old mass ) x 100%
The original mass of the copper penny is given as 2.5 g and when converted to kilogram, the mass becomes 0.0025 kg.
The mass of 1 electron = 9.11 x 10⁻³¹ kg
then, the mass of 6.88 x 10⁹ electrons = ?
= ( 6.88 x 10⁹ ) x ( 9.11 x 10⁻³¹ kg )
= 6.27 x 10⁻²¹ kg
new mass of the penny = 0.0025 kg + 6.27 x 10⁻²¹ kg = 0.0025 kg
The percentage change in the mass of the penny is calculated as follows;
percentage change = ( New mass - old mass ) / ( old mass ) x 100%
percentage change = ( 0.0025 kg - 0.0025 kg ) / ( 0.0025 kg ) x 100%
percentage change = 0 %
Thus, the transferred electron has no effect on the mass of the penny because the mass an electron is almost insignificant.
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A tuning fork is vibrating the air around it. What best describes the waves produced by the tuning fork?
The waves produced by a vibrating tuning fork are longitudinal waves, also known as compression waves.
What are Longitudinal Waves?Longitudinal waves are waves that oscillate along the direction of propagation, meaning they create alternating regions of compression and rarefaction in the medium through which they travel.
In the case of a vibrating tuning fork, the tines of the fork move back and forth, causing the surrounding air to alternately compress and expand. These pressure changes propagate through the air as longitudinal waves.
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You weigh 610 n. what would you weigh if the earth were six times as massive as it is and its radius were three times its present value? answer in units of n.
Answer:
F1 = G M1 M2 R^2 force between objects M1 and M2
F2 = G M1 * 6 M2 / (3 * R)^2
F2 = 6 / 9 * F1
F2 = 2/3 * 610 n = 407 n
A particular calculation requires you to multiply kg x m/s² x m.
What are the CORRECT units of the answer? Select ALL that apply.
Elimination Tool
Select all that apply
A J
B N²
C kg/s
D Nm
Answer:Step-1: The first step is to multiply or divide both the linear equations with a non-zero number to get a common coefficient of any one of the variables in both equations. Step-2: Add or subtract both the equations such that the same terms will get eliminated.
12 This question is about a parachutist.
(a) A parachutist leaves a helicopter that is hovering above the ground.
The parachutist is initially at rest and falls vertically downwards.
Calculate the speed of the parachutist after they have fallen through a distance
of 1300m.
Ignore the effect of air resistance.
Answer:
159.6 m/s²
Explanation:
The third equation of motion is
v² = u² + 2gs
where v = final velocity
u = initial velocity or 0 ( body is initially at rest)
g = acceleration due to gravity = 9.8 m/s²
s = 1300 m
v² = 2gs
v² = 2600 x 9.8
v = √(2600 x 9.8
v is approximately 159.6 m/s^2
WHICH IS A LOT.
Two masses m1 = 15 kg and m2 = 25 kg are joined by connecting a rod of length 0.8 m. Determine the distance of the CM of the system from the m1 if: (a) the connecting rod is massless, and (b) the connecting rod is a uniform rod of mass 15 kg.
Answer:
a) When the connecting rod is massless, the center of mass (CM) of the system is located at the point where the two masses are joined. Therefore, the distance of the CM from m1 is 0.8 m.
b) When the connecting rod is a uniform rod of mass 15 kg, the position of the CM of the system can be found using the parallel axis theorem. The formula for the parallel axis theorem is:
CM = (m1d1 + m2d2 + m3*d3)/(m1 + m2 + m3)
where m1, m2, and m3 are the masses of the two masses and connecting rod, respectively, and d1, d2, and d3 are the distances of their respective CM from the reference point.
In this case, m1 = 15 kg, m2 = 25 kg, m3 = 15 kg, d1 = 0, d2 = 0.8 m, and d3 = 0.4 m (half of the length of the connecting rod).
Substituting these values into the formula, we get:
CM = (150 + 250.8 + 15*0.4)/(15 + 25 + 15) = 0.48 m
So the distance of the CM of the system from m1 is 0.48 m.
A car of mass 800 kg initially at rest is accelerated at the rate of 4ms^-2. The kinetic energy of the car after 5 seconds is ?
Answer:
Explanation:
velocity after 5 seconds is 4 x 5 = 20 m/s
KE formula = 0.5mv²
= 0.5 x 800 x 400
= 400²
= 160000 J
or, 160kJ
A floral clock in Japan has a radius of 15.5 m. If you ride a bike around
the clock, making 16 revolutions in 4.5 min, what is your average angular speed?
The average angular speed will be the ratio of total distance to total time which is 5.77 rad/s
What is Angular Speed ?Angular speed can be defined as the total angle turned per total time taken. It is measured in rad/s
Given that a floral clock in Japan has a radius of 15.5 m. If you ride a bike around the clock, making 16 revolutions in 4.5 min, what is your average angular speed ?
The circumference C of the circle = distance covered by the bike.
C = 2πr where r = 15.5 m
C = 2 × π × 15.5
C = 97.4 m
Total distance covered = 16 revolution × 97.4
Total distance covered = 1558.23 m
Total time taken = 4.5 × 60 = 270 s
Average angular speed = 1558.23 / 270
Angular speed = 5.77 rad/s
Therefore, your average angular speed is 5.77 rad/s
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A new planet is observed to orbit a 6.1x1030kg star. If astronomers calculate the planet to have a mass of 4.8x107 kg and an average distance of 1.3x1012meters from it's star, what is the gravitational force between the star and the new planet? (G=6.673x10−11 )
The force that is acting on the bodies is obtained as 1.15 * 10^- 48 N.
What is the force?Let us have it at the back of our minds that the force that is acting between the star and the planet has to be an attractive force since it is the force of gravity. Now we know that;
F = Gm1m2/r^2
F = force of gravity
m1 and m2 are the masses of the objects
r = The distance between the objects
Then;
F = 6.673x10^−11 * 6.1x10^30 * 4.8x10^7/(1.3x10^12)^2
F = 1.95 * 10^-24/1.69 * 10^24
F = 1.15 * 10^- 48 N
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the product of an object's instantaneous momentum and acceleration is what quantity?
Explanation:
In differential form, this is Newton's second law; the rate of change of the momentum of a particle is equal to the instantaneous force F acting on it, hence the net force is equal to the mass of the particle times its acceleration.
A 75,000-watt radio station transmits at 88 MHz. Calculate the energy of a single photon at the transmitted frequency.
5.0x 10 -29 J/photon
5.8 x 10 -32 J/photon
5.8 x 10 -26 J/photon
The energy of the photon is obtained as 5.8 x 10 -26 J/photon. Option C
What is the energy of the photon?We have to know that the energy of the photon can be obtained from the frequency. We can define the frequency as the number of cycles that is completed per second so the time that is taken is 1 s.
Energy = hf
h = Plank's constant
f = frequency
Then;
E = 6.6 * 10^-34 * 88 * 10^6
E = 5.8 x 10 -26 J/photon
The photon that we can see is going to have a total energy of 5.8 x 10 -26 J/photon.
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How many centimeters are in a kilometer? Step by step explanation
100,000 centimeters or 10⁵ centimeters are in a kilometer.
What is unit of length?Any arbitrarily selected and widely used reference standard for length measurement is referred to as a unit of length. The metric system, which is adopted by every nation on earth, is the most widely utilized in modern times.
We know that:
1 kilometer = 1000 meters.
And 1 meter = 100 centimeters.
So, 1 kilometer = 1000 meters
1 kilometer = 1000 × 100 centimeters
1 kilometer = 100,000 centimeters
1 kilometer = 10⁵ centimeters.
Hence, 100,000 centimeters or 10⁵ centimeters are in a kilometer.
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Tidal effects in the Earth-Moon system are causing the Moon’s orbital period to increase
at a current rate of about 35 ms per century. Assuming the Moon’s orbit around the Earth
is circular, to what rate of change in the Earth-Moon distance does this correspond? Hint :
Differentiate Kepler’s third law.
The rate of change in the Earth-Moon distance does this correspond to 1.1977e-9 m/s.
What is the difference between Kepler's laws?
The difference between Kepler and Newton laws is that Kepler law describes planetary motion around the Sun, whereas Newton laws describe an object's motion and its relationship to the force acting on it.
T= sqrt ((4 × pie^2 × r^3)/GM)
= 2 × 3.1416 × (r^3/GM)^0.5
T = 2 × 3.1416 × (r^3)^0.5 (1/(6.67e-11 × 5.97e24))^0.5
T = 3.1487e-7 (r^3)^0.5
dT/dr = 3.1487e-7 × (0.5) × (3 r^2) × (r^3)^-0.5
dT/dr = 3.1487e-7 × (0.5) × (3) × (r)^0.5
dT/dr = 3.1487e-7 × (0.5) × (3) × (384400e3)^0.5
dT/dr = 0.009260069 s/m
dr = 35e-3/0.009260069
dr = 3.77967 meters per century
v = dr/t
= 3.779669/(100 × 365.25 × 24 × 60 × 60)
= 1.1977e-9 m/s
Thus, The rate of change in the Earth-Moon distance does this correspond to 1.1977e-9 m/s.
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A refrigerator is pushed across across a horizontal floor with a force of 125 N. If the refrigerator moves 4 meters, then how much work is done to move it?
The work done to move the refrigerator is 500 J.
What do you mean by work?Work is defined as force multiplied by distance, in the direction of the force.
The work done to move the refrigerator can be calculated using the formula:
work = force x distance
Given that:
force = 125 N
distance = 4 m
We can substitute these values into the formula and solve for work:
work = 125 N x 4 m
work = 500 J (Joules)
So, the amount of work done to move the refrigerator is 500 Joules.
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4.og of nacl is heated with mno2 in excess concentrated h2so4 the chlorine gas liberated is then passed through KI solution to liberate iodin. Calculate the mass of mno2
The mass of MnO₂ required by 4 g of NaCl in the chemical reaction is 1.487 g.
What is the balanced chemical reaction of NaCl, MnO₂ and H₂SO₄?
The balanced chemical reaction of NaCl, MnO₂ and H₂SO₄ is given as follows;
4NaCl + MnO₂ + 4H₂SO₄ → MnCl₂ + 4NaHSO₄ + Cl₂ + 2H₂O
From the chemical equation given above, we can calculate the mass of 4NaCl and MnO₂ as follows;
where;
Na is sodium, mass = 23 g/molCl is chlorine, mass = 35.5 g/molMn is manganese, mass = 55 g/molO is oxygen = 16 g/mol4NaCl = 4 ( 23 + 35.5 ) = 234 g
MnO₂ = ( 55 + 32 ) = 87 g
The mass of MnO₂ required by 4 g of NaCl in the chemical reaction is calculated as;
4NaCl + MnO₂ + 4H₂SO₄ → MnCl₂ + 4NaHSO₄ + Cl₂ + 2H₂O
in this equation, 234 g of NaCl ---------> 87 g of MnO₂
4 g of NaCl -------------> ? MnO₂
= ( 4 x 87 ) / ( 234 )
= 1.487 g
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Here is a example of the classical conditioning process. A kid was drinking a Sprite soda. When he wasn’t looking, a bee crawled into the can. He took another drink and was stung by a bee on the inside of his cheek. He was startled and in pain! For years afterward, Sprite soda made him feel anxious.
Identify from this example the unconditioned stimulus, unconditioned response, conditioned stimulus, and conditioned response.
Answer:
The unconditioned stimulus (UCS) in this illustration of classical conditioning is a bee sting. The child's discomfort and startle response are examples of the unconditioned response (UCR).
The Sprite drink is the conditioned stimulus (CS). The Sprite soda did not initially elicit any specific reactions (it was neutral). However, since the child had a bee sting while drinking soda, the discomfort and bee sting are now connected to the beverage, specifically Sprite.
The child's fear of the Sprite soda is the conditioned reaction (CR). The child now has anxiety whenever he sees or consumes sprite soda as a result of the link between the bee sting and the soda.
Explanation:
see above
The first practical car to use a gasoline engine was built in London in 1826. The power generated by the engine was just 2984 W. How long would this engine have to run to produce 3.60 × 10^4 J of work?
To find out how long the engine would have to run to produce 3.60 x 10^4 J of work, we first need to determine the power output of the engine. The power generated by the engine is given as 2984 W.
To calculate the time it would take for the engine to produce 3.60 x 10^4 J of work, we can use the formula:
time = work / power
where work is measured in joules and power is measured in watts.
So, we can substitute in the values we know:
time = 3.60 x 10^4 J / 2984 W
If we perform the calculation we will get:
time = 12 seconds
So, the engine would have to run for 12 seconds to produce 3.60 x 10^4 J of work.
I hope this helps :)
A wave with a frequency of 17 Hz has a wavelength of 5 meters. At what speed will this wave travel?
Answer:
85
Explanation:
soln
given that;
frequency=17Hz
wavelength=5m
speed?
formula for wavelength is;
wavelength= speed/frequency
then ; making v the subject formula
we have that v=wavelength*frequency
v=17*5=>85ms
Analyzing Gravitational Data Quick Check
Which of the following statements about gravitational mass is true? (1 point)
O Gravitational acceleration is irrespective of mass.
O The more mass an object has, the more gravitational acceleration it will experience.
O The less mass an object has, the less gravitational acceleration it will experience.
Gravitational acceleration is always equal to mass.
The true statement about gravitational mass is the more mass an object has, the more gravitational acceleration it will experience.
option B.
What is gravitational acceleration?
The gravitational acceleration of an object is the acceleration an object with mass experiences due to impact of force of gravity on the object.
g = ( GM ) / ( R² )
where;
G is the universal gravitation constantM is the mass of the objectR is the radius of the objectFrom the equation given above, the acceleration of an object increases with increase in the mass of the object and decrease in the radius of the object.
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