Alex Souza's potential profit represented by the combined retail value of the seven remaining animals is $13.20.
What is profit?Profit is the excess of revenue over costs.
Profit represents the additional revenue a business generates from its activities after subtracting all costs.
Data and Calculations:Hamsters Parakeets Total
Ratio 2 : 1
Cost price $2 $1
Profit margin $0.20 $0.10 (10%)
Retail price $2.20 $1.10
Ending inventory 5 2 7
Profit value $11 $2.20 $13.20
Thus, Alex Souza's potential profit represented by the combined retail value of the seven remaining animals is $13.20.
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Enter an inequality that represents the graph in the box.
Graph of a linear inequality on a coordinate plane. The horizontal x-axis ranges from negative 8 to 8 in increments of 2. The vertical y-axis ranges from negative 8 to 8 in increments of 2. A solid line passes through begin ordered pair 0 comma negative 6 end ordered pair and begin ordered pair 2 comma 2 end ordered pair. The region above the solid line is shaded.
The linear inequality represented by the given graph in the attached image is y > -3x + 6.
What is inequality?Inequality is the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.
The graph of the linear inequality. Let's pick two points from the graph to frame the linear equation
The slope-intercept form of the equation is Where m is the slope and b is the y-intercept is (0,6) from the graph so b=6.
Find out slope m by using the general formula. Pick two points (0,6) and (2,0).
Slope = ( y₂ - y₁) / ( x₂ - x₁ )
Slope = ( 0 - 6 ) / ( 2 - 6 )
Slope = -3
m = -3
So the equation is y = -3x + 6
Now we check the inequality sign by testing any point on the shaded area let's pick (4,0). let's plug in 4 for x and 0 for y
y= -3x + 6
0 = -3(4) + 6
0 > -6
Inequality: y > -3x + 6.
Therefore, the inequality represented by the given graph is y > -3x + 6.
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Answer: y≥4x−6
Step-by-step explanation: I took the test and this was the right answer for me.
please help
please hurry
Answer:
-22 I arrived as fast as I could
Solve for [x]. Each figure is a trapezoid.
*
Question 1
Opposite sides of a trapezoid are parallel. So, by the same-side interior angles theorem,
[tex]-16x+10x+86=180 \\ \\ 10x+70=180 \\ \\ 10x=110 \\ \\ x=11[/tex]
Question 2
Opposite sides of a trapezoid are parallel. So, by the same-side interior angles theorem,
[tex]9x+30+7x-10=180 \\ \\ 16x+20=180 \\ \\ 16x=160 \\ \\ x=10[/tex]
Aubrey has 64 m of fencingEli has 44 m of fencing to build a four-sided fence around a rectangular plot of land. The area of the land is 120 square meters. Solve for the dimensions (length and width) of the field. to build a four-sided fence around a rectangular plot of land. The area of the land is 255 square meters. Solve for the dimensions (length and width) of the field.
The dimensions of the rectangular field with area 120 square meters is 10 meters by 12 meters.
The measurement that expresses the size of a region on a plane or curved surface is called area. Surface area refers to the area of an open surface or the boundary of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a form or planar lamina.
Given perimeter of the rectangular plot is 44 meters.
let the length is x , and width = y
Therefore perimeter = 2 (x + y)
or, 2 (x + y) = 44
or, x + y = 22
or, y = 22 - x
Now the area of the field is given as 120 square meters.
Area of the fields in terms of x is given by:
x ( 22 - x ) = 22 x - x²
Therefore 22 x - x² = 120
or, x² -22x +120 = 0
or, x² - 10x - 12x + 120 = 0
or, x (x -10) -12(x-10)=0
or, (x-10)(x-12) = 0
Now either the value of x is 10m or the value of x is 12m
Therefore the dimensions of the rectangular field is 10 meters by 12 meters.
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Please help ASAP! Help greatly appreciated with step by step solutions
The nth terms of the arithmetic sequences;
I. Tn = 3 + √2 + ( n - 1) √2
ii. Tn = 2/ √3 + ( n - 1) 1/ √3
How to determine the nth termThe formula for the nth term of an arithmetic sequence is expressed as;
Tn = a + ( n - 1)d
Where;
Tn is the nth terma is the first term n is the number of termsd is the common differencei. a = 3 + √2
d = √2
Substitute the values, we have;
Tn = 3 + √2 + ( n - 1) √2
ii. a = 2/ √3
d = 1/ √3
Substitute the value, we have;
Tn = 2/ √3 + ( n - 1) 1/ √3
Thus, the nth terms of the arithmetic sequences are Tn = 3 + √2 + ( n - 1) √2 and Tn = 2/ √3 + ( n - 1) 1/ √3 respectively
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Part C
Which investment would you choose if you were Sam or Julia?
In two to three sentences, state your choice of investment and the reasoning for your decision using concepts you've
learned in this lesson.
Answer:
i would choose investment A
Step-by-step explanation:
A is simply the best anwser choice
Answer:
If I were Sam, I would buy the bond with a 3% interest rate since selling at any time is not a priority. The bond would provide a steady income from the investment, which is what he his needing.If I were Julia, I would invest in the stock, which has long-term growth potential. This would allow her to sell the investment at any time in the future.
Step-by-step explanation:
SAMPLE ANSWER!!!
18 acres of land is for sale at $11001.
What is the cost per acre?
Answer in units of dollars/acre.
Answer:
$611.17 per acre
Step-by-step explanation:
11001 ÷ 18 = 611.16666...
So, the answer is an infinite decimal, so we round it to the nearest hundredth.
Solve the following system of equations using either Gaussian elimination or a matrix. Write your answer as a point and explain how you would check your work:
By using Matrix method it denotes that the equations are consistent and have a single solution.
Matrix method, we will use the formula, [tex]X=A^{-1} B[/tex] where,
[tex]\[{\rm{X}} = \left[ {\begin{array}{*{20}{l}}x\\y\\z\end{array}} \right]\][/tex]
[tex]\[{A^{ - 1}} = \frac{{adjA}}{{|A|}}\][/tex]
[tex]\[{\rm{B}} = \left[ {\begin{array}{*{20}{c}}{33}\\{ - 26}\\{23}\end{array}} \right]\][/tex]
So, we will have to find [tex]A^{-1}[/tex], for that, we will first find the determinant of matrix A, that is |A|, then we will find the cofactors of matrix A, take its transpose, and that will be Adj A.
Therefore, we will be able to get the inverse of matrix A using
[tex]A^{-1}[/tex] =Adj A|A|
and hence We then substitute all the obtained values of [tex]A^{-1}[/tex] and B in the main formula and do necessary calculations to get the value of x, y and z accordingly.
Complete step-by-step answer:
It is given in the question that, we have to solve the system of equations,
2x-y+4z=33
X+2y-3z=−26
-5x−3y+5z=23
Applying the matrix approach.
Therefore, the first step is to convert the supplied equations into matrix form. Thus, it can be expressed as follows.
[tex]\[\left[ {\begin{array}{*{20}{c}}2&{ - 1}&4\\1&2&{ - 3}\\{ - 5}&{ - 3}&5\end{array}} \right]\left[ {\begin{array}{*{20}{l}}x\\y\\z\end{array}} \right]\]\[[/tex][tex]= \left[ {\begin{array}{*{20}{c}}{33}\\{ - 26}\\{23}\end{array}} \right][/tex]
[tex]\[|{\rm{A}}| = \left[ {\begin{array}{*{20}{c}}2&{ - 1}&4\\1&2&{ - 3}\\{ - 5}&{ - 3}&5\end{array}} \right]\][/tex]
= 2(10+9) + 1(5-15) + 4(-3+10)
= 38-10+28
=56
Since we have |A|≠0.
Hence, it denotes that the equations are consistent and have a single solution.
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Gruman Company purchased a machine for $198,000 on January 2, 2017. It made the following estimates:
Service life 5 years or 10,000 hours
Production 180,000 units
Residual value $18,000
In 2016, Gruman uses the machine for 1,700 hours and produces 40,000 units. In 2017, Gruman uses the machine for 1,200 hours and produces 34,000 units. If required, round your final answers to the nearest dollar.
Required:
Compute the depreciation for 2016 and 2017 under each of the following methods:
a. Straight-line method
b. Sum-of-the-years'-digits method
c. Double-declining-balance method
d. Activity method based on hours worked
e. Activity method based on units of output
a. Straight-line method: $36,000 $36,000
b. Sum-of-the-years'-digits method: $60,000 $48,000
c. Double-declining-balance method: $79,200, $47,520
d. Activity method based on hours worked: $30,600, $21,600
e. Activity method based on units of output $40,000 $34,000
Straight-line methodb. Straight line method
Depreciation expense = (Cost of asset - Salvage value) / Useful life
Depreciation expense=( $198,000 - $18,000 ) / 5
Depreciation expense = $36,000
b. Sum-of-the-years'-digits method
Sum-of-the-year digits = (Remaining useful life / Sum of the years ) x (Cost of asset - Salvage value)
Sum of the years = (1 +2 +3 +4 + 5 )
Sum of the years = 15
Year 1 Depreciation expense = (5/15) × ( $198,000 - $18,000 )
Year 1 Depreciation expense = $60,000
Year 2 Depreciation expense = (4/15) x ( $198,000 - $18,000 )
Year 2 Depreciation expense = $48,000
c. Double-declining-balance method
Depreciation factor = 2 x (1/Useful life)
Depreciation factor =2 x(1/5)
Depreciation factor = 0.4
Year 1 Depreciation expense = 0.4 x $198,000
Year 1 Depreciation expense= $79,200
Year 1 Book value = $198,000 - $79,200
Year 1 Book value= $118,800
Year 2 Depreciation expense= 0.4 x $118,800
Year 2 Depreciation expense= $47,520
d. Activity method based on hours worked
Activity method = (Hours worked / Total machine hours) x (Cost of asset - Salvage value)
Year 1 Depreciation expense = (1,700 / 10,000) x ( $198,000 - $18,000 )
Year 1 Depreciation expense = $30,600
Year 2 Depreciation expense = (1,200 / 10,000) x ( $198,000 - $18,000 )
Year 2 Depreciation expense = $21,600
e. Activity method based on units of output
Activity method = (Output produced / Total machine output capacity) x (Cost of asset - Salvage value)
Year 1 Depreciation expense = ( 40,000 / 180,000) x ( $198,000 - $18,000 )
Year 1 Depreciation expense = $40,000
Year 2 Depreciation expense= ( 34,000 / 180,000) x ( $198,000 - $18,000 )
Year 2 Depreciation expense = $34,000
Therefore the Straight-line method is $36,000 $36,000.
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Triangle PQR has vertices P (3,8), Q (-5, 7), and R (0, 2). What are the coordinates of the vertices of the image after a reflection in the y-axis?
A) P' (3,-8)
B) P (-3,8)
□C) Q' (5,7)
□D) Q' (5-7)
□E) R¹ (-2,0)
OF) R¹ (0,2)
After the picture is reflected along the y-axis, its vertices will have the coordinates P'Q'R.:
[tex]P' = (-3,8)\\Q' = (5,7)\\R'=(0,2)[/tex]
What is coordinates of the vertices?
The triangle's vertices' coordinates are [tex](x_{1} ,y_{1} )[/tex], [tex](x_{2},y_{2})[/tex], and [tex](x_{3},y_{3} )[/tex]. The line that connects the first two is split in the ratio l:k, and the line that runs from the division point to the opposing angular point is divided in the ratio m:k+l.
Given:
Triangle PQR and vertices of triangle are
[tex]P=(3,8)\\Q=(-5,7)\\R=(0,2)[/tex]
The following rule results in a reflection about the y-axis:
[tex](x, y) ---- > (-x, y)[/tex]
Using the rule on each of our vertices, we have:
[tex](3, 8) ---- > (-3, 8)\\(-5, 7) ---- > (5, 7)\\(0, 2) ---- > (0, 2)[/tex]
Therefore,
After the picture is reflected along the y-axis, its vertices will have the coordinates P'Q'R.
[tex]P' = (-3,8)\\Q' = (5,7)\\R'=(0,2)[/tex]
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13 square kilometers to square mile? Round to nearest tenth as needed
Answer:
5 square mile
Step-by-step explanation:
1 square km = 0.3 square mile
13 square km = 5.01 square mile
5.01 rounded equals 5
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how many terms are in the sequence given of the following d=5,a1=-9 and an=141
The number of terms in the sequence with d=5 , a₁ = -9 and aₙ=141 is 31 terms.
Arithmetic Sequence
The nth term of the sequence { a , a+d , a+2d , ... , a+(n-1)d } is given by
aₙ=a+(n-1)d ...(i)
where , a = first term ,
d = common difference ,
n = number of terms ,
aₙ = nth term of the sequence .
It is given in the question that
first term (a) = -9
common difference (d) = 5
and nth term (aₙ) = 141
Substituting the values in equation (i) we get ,
141 = -9 + (n-1)5
simplifying further we get
141+9=(n-1)5
150 = 5n - 5
150+5 = 5n
155 = 5n
n=155/5
n=31.
Therefore , There are 31 terms in the sequence with d=5 , a1 = -9 and aₙ=141 .
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Input
0
1
6
Output = Input x Itself + (-5) Output
95
59
76
We are given a table for input and output values and the relation between them.
Consider the table,
Input Output = Input × itself + (-5) Output
0
1
6
95
59
76
For Input = 0 :
Output = Input × itself + (-5)
Output = 0 × 0 - 5
Output = -5
Now, for Input = 1,
Output = Input x Itself + (-5)
Output = (1) × 1 + (-5)
Output = 1 - 5
Output = - 4
For Input = 6,
Output = Input x Itself + (-5)
Output = (6) × 6 + (-5)
Output = 36 - 5
Output = 31
For Output = 95,
Output = Input x Itself + (-5)
95 = (Input)²+ (-5)
95 + 5 = (Input)²
(Input)² = 100
Input = √100
Input = 10
For Output = 59,
Output = Input x Itself + (-5)
59 = (Input)²+ (-5)
59 + 5 = (Input)²
(Input)² = 64
Input = √64
Input = 8
For Output = 76,
Output = Input x Itself + (-5)
76 = (Input)²+ (-5)
76 + 5 = (Input)²
(Input)² = 81
Input = √81
Input = 9
Therefore the complete table will be:
Input Output = Input × itself + (-5) Output
0 Output = 0 × 0 + (-5) -5
1 Output = 1 × 1 + (-5) -4
6 Output = 6 × 6 + (-5) 31
10 95 = Input × itself + (-5) 95
8 59 = Input x Itself + (-5) 59
9 76 = Input x Itself + (-5) 76
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3x^2+7-6+1+3+7 add , sub, mult, what is the answer
Answer:
If just combining like terms: 3x^2 + 12
If solving for x: 2i, -2i
Step-by-step explanation: Combine like terms, so 3x^2 + 12 = 0; move the 12 to the other side by subtracting (3x^2 = -12), then divide both sides by 3, which gives x^2 = -4. Then get the square root of both sides to cancel out the power on the x. Since -4 is negative, use imaginary numbers, which makes x = 2i and x = -2i
In ΔXYZ, ∠Y=90° and ∠X=60°. ∠ZWY=83° and XW=1.5. Find the length of ZY to the nearest 100th.
Applying the law of sines, the length of ZY to the nearest hundredth is: 3.30 units.
How to Apply the Law of Sines?sin X/x = sin W/w = sin Z/z [according to the law of sines].
Given:
Measure of angle X = 60°
Measure of angle Z (∠XZW) = 180 - 60 - (180 - 83) = 23°
x = WZ = ?
z = XW = 1.5
Plug in the values into sin X/x = sin Z/z
sin 60/WZ = sin 23/1.5
WZ = (sin 60 × 1.5)/sin 23
WZ = 3.32
Find ZY using the sine ratio;
sin ∅ = opp/hyp = ZY/WZ
sin 83 = ZY/3.32
ZY = (sin 83)(3.32)
ZY = 3.30
Therefore, applying the law of sines, the length of ZY to the nearest hundredth is: 3.30 units.
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A used car dealership reduced the price of a used compact car by 10%. If the price of the car before
discount was $18,500, find the discount and the new price.
The discount in price is $
Hint: Discount = Original Price x Percentage
Answer:1/1850
Step-by-step explanation: Davide 10% from 18500
Monique has $48, then the following events happen, in order: • She earns $20 babysitting. • She spends $32. • She doubles her money doing chores.
Answer:
72
Step-by-step explanation:
$48 + $20 = $68
$68 - $32 = $36
$36 × 2 = $72
100000000000000000000000000000000000000000000 x 22222222222222 =
Scientific e Notation: 2.2222222e+57
Scientific Notation: 2.2222222 x 10^57
Answer:
I am pretty sure the answer is 2.2222222e+57.
The following trial balance of Reese Corp. at December 31, 2014 has been properly adjusted except for the income tax expense adjustment. Reese Corp. Trial Balance December 31, 2014 Dr. Cr. Cash $ 775,000 Accounts receivable (net) 2,695,000 Inventory 2,085,000 Property, plant, and equipment (net) 7,566,000 Accounts payable and accrued liabilities $ 1,701,000 Income taxes payable 654,000 Deferred income tax liability 85,000 Common stock 2,350,000 Additional paid-in capital 3,680,000 Retained earnings, 1/1/14 3,450,000 Net sales and other revenues 13,560,000 Costs and expenses 11,180,000 Income tax expenses 1,179,000 $25,480,000 $25,480,000 07. The current assets total is: A. $6,080,000 C. $5,405,000 B. $5,555,000 D. $4,955,000
Based on the balances in Reese Corp's trial balance, the current assets total can be found to be B. $5,555,000
What is the total current assets?The total of the current assets can be found by the formula:
= Inventory + Accounts Receivable + Cash
Solving then gives:
= 775,000 + 2,695,000 + 2,085,000
= $5,555,000
In conclusion, the current assets for Reese Corp is $5,555,000 .
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(3x^-4)6/9x^-12 can you please solve? I’ll give brainly
The answer to this given simplification (3x^-4)6/9x^-12 is 2 x^8.
What are exponents?
The exponent of a number indicates how many times a number has been multiplied by itself. For instance, 34 indicates that we have multiplied 3 four times. Its full form is 3 3 3 3. Exponent is another name for a number's power. It could be an integer, a fraction, a negative integer, or a decimal. In this essay, let's study more about exponents.
given:
(3x^-4)6/9x^-12
=x^-4 . 3 . 6 / 9 . x^-12
= 2. x^-4 / x^-12
=2 x^8
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Macy jogs 27 miles a month.
Part A
Explain how to use compensation to find how many miles Macy jogs in 6 months.
Please help! Brainliest to whoever correct first!!! THANK YOU!
An equivalent expression for 4d⁻³/22d⁹ is: B. 2d⁻³/11d⁻⁹
What is an expression?An expression can be defined as a mathematical equation which is used to show the relationship existing between two or more variables and numerical quantities.
What is an exponent?An exponent can be defined as a mathematical operation that is used to raise a quantity to the power of another and it is generally written as bⁿ.
Next, we would write the equation as a quotient:
Expression = 4d⁻³/22d⁹
Expression = 2d⁻³/11d⁹
By applying the law of indices, we have:
Expression = 2 × 1/11d(⁹ ⁻ ⁽⁻³⁾)
Expression = 2/11d¹²
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For the season, a basketball player made 279 free throws out of 313 attempts. What percent is this?
Answer:
89.14%
Step-by-step explanation:
279 Out of 313 is 89.14%. Follow the below steps to calculate what percent is 279 out of 313 or how to write 279/313 as a percentage.
Step 1: Percentage Formula = Number 1/Number 2 x 100
Step 2: plugin the 279 and 313 to the percentage formula and we get 279/313 x 100 = 89.14%
BD bisects AC at point E. if AE is 2x²- 8 and AC is 5x^2-25
find the length of EC
The length of EC will be 154 units.
We have the data that:
BD is the bisector of AC at point E.
This means that AE = EC
Also, AE + EC = AC
AE + AE = AC
2 AE = AC
Now,
AE = 2x² - 8 and AC is 5x² - 25
Substituting the values, we get that:
2 (2x² - 8) = 5x² - 25
4x² - 16 = 5x² - 25
5 x² - 4 x² = 25 - 16
x² = 9
x = 3 ( as length cannot be negative)
AE = EC = 2x² - 8
EC = 2 (9)² - 8
EC = 162 - 8
EC = 154 units.
Therefore, we get that, the length of EC will be 154 units.
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Multiply the numbers.
Answer:
[tex] \: \: \: \: \: { \rm{2 \: \: \: 3 \: \: \: 4}} \\ { \underline{ \times \: \: 0. \: \: 3 \: \: 5}} \\ { \rm{ 1 \: \: 1 \: \: 7\: \: 0}} \\ { \underline{ + 7\: \: 0\: \: 2 \: \: 0 }} \\ { \underline{ \: \boxed{ 8\: \: 1 \: .\: \: 9 \: \: 0}}}[/tex]
Answer: 81.9
Louisa made a purchase at her local convenience store for $6.65. She wanted to use up her change so she used
quarters and dimes to pay the clerk. If she used a total of 29 coins, how many fewer dimes than quarters did she
use?
Louisa used Number
fewer dimes.
Answer:
25 quarters and 4 dimes. Louisa used 21 more quarters than she did dimes.
Step-by-step explanation:
q=number of quarters
d=number of dimes
6.65=.25q+.10d 6.65 (the total) is equivalent to the amount of quarters times .25 (the value of a quarter) plus the amount of dimes times .10 (the value of a dime)
Now divide 6.65 by .25.
26 quarters can be used.
26 times .25 = 6.50
26 quarters is $6.50
29-26=3
3 times .10 = .30
.30+6.50=6.80
This is too much. Let's try taking off one quarter.
Now we have 25 quarters. .25 times 25 = 6.25
29-25=4 (This means there will be 4 dimes if she used 25 quarters, but let's see)
4 times .10 = .40
.40 + 6.25=6.65
6.65 is the total amount she had to pay, so we did it. Solving this showed us that she used 25 quarters and 4 dimes. This equals $6.65, the amount she paid, uses only quarters and dimes, and uses a total of 29 coins.
I hope this helps you! Please mark as Brainliest answer! I worked really hard to type all of this out for you.
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The admission fee at an amusement park is $ 3.00 for children and $ 7.00 for adults. On a certain day, 297 people entered the park, and the admission fees collected totaled $ 1551 . How many children and how many adults were admitted?
There were _________________ children admitted.
There were _________________ adults admitted
Answer:
There were 132 children admitted.
There were 165 adults admitted.
Step-by-step explanation:
Given information:
Child admission fee = $3.00Adult admission fee = $7.00Total admissions = 297 peopleTotal admission fees collected = $1,551Define the variables:
Let x = number of children admitted to the park.Let y = number of adults admitted to the park.Create two equations from the given information and defined variables:
[tex]\textsf{Equation 1}: \quad x+y=297[/tex]
[tex]\textsf{Equation 2}: \quad 3x+7y=1551[/tex]
Solve the first equation for y:
[tex]\implies x+y=297[/tex]
[tex]\implies x+y-x=297-x[/tex]
[tex]\implies y=297-x[/tex]
Substitute the found expression for x into the second equation and solve for y:
[tex]\implies 3x+7y=1551[/tex]
[tex]\implies 3x+7(297-x)=1551[/tex]
[tex]\implies 3x+2079-7x=1551[/tex]
[tex]\implies 2079-4x=1551[/tex]
[tex]\implies 2079-1551-4x=1551-1551[/tex]
[tex]\implies 528-4x=0[/tex]
[tex]\implies 528-4x+4x=0 + 4x[/tex]
[tex]\implies 528= 4x[/tex]
[tex]\implies \dfrac{528}{4}= \dfrac{4x}{4}[/tex]
[tex]\implies x=132[/tex]
Substitute the found value of x into the expression for y and solve for y:
[tex]\implies y=297-x[/tex]
[tex]\implies y=297-132[/tex]
[tex]\implies y=165[/tex]
Therefore:
There were 132 children admitted.There were 165 adults admitted.find the measures of the labeled angles :)
3x =
second answer =
simplified =
please help im struggling !! this is my last question :) ill mark brainliest
Answer: 54
Step-by-step explanation:
3x=72-x ==> 3x and 72-x are both congruent angles, so they're equal
3x+x=72-x+x
4x=72
x=18
3x=
3(18)=54 degrees
Each marble bag sold by bill marble company contains 8 purple marbles for every 5 yellow marbles. If a bag has 64 purple marbles how many yellow marbles does it contain
Answer:
40 yellow marbles
Step-by-step explanation:
1. Divide 64 by 8 (Determine how many sets there are)
64/8 = 8
2. Multiply 8 by 5 (Because for every 8 purple marbles there are 5 yellow ones)
8*5 = 40
Y= |x-1|-5 find points and graph
Step-by-step explanation:
(-4,0)
(0, -4)
(1, -5)
(6, 0)