An airplane is preparing to land at an airport. It is 45,600 feet above the ground and is descending at the rate of 3,200 feet per minute. At the same​ airport, another airplane is taking off and will ascend at the rate of 2,500 feet per minute. When will the two airplanes be at the same altitude and what will that altitude​ be?

Answer:

5 notepads

Step-by-step explanation:

We know

Kristin spent $25 on a magazine and some notepads

1 magazine = $5

1 notepad = $4

$25 - $5 = $20

How many notepads did she buy?

We take

$20 divided by $4 = 5 notepads

So, she bought 5 notepads

Answer:

5 notepads

Step-by-step explanation:

25=4x+5

subract 5 from 25 and cancel out old 5

20=4x

divide by 4

20/4 = 5

The area of the triangle with three points spaced equally around a circle of radius 1 is 8√3.

The area of the triangle can be calculated using Heron's formula:

Area = √(s(s-a)(s-b)(s-c))

where s is the semiperimeter of the triangle and a, b, c are the side lengths.

The semiperimeter can be calculated as follows:

s = (a + b + c)/2

For this triangle, the side lengths are:

2, 2√2, and 2

Therefore, the semiperimeter is

s = (2 + 2√2 + 2)/2 = 4√2

The area of the triangle is then:

Area = √(4√2(4√2-2)(4√2-2√2)(4√2-2))

    = √(4√2*2√2*2*2)

    = 8√3

The area of the triangle with three points spaced equally around a circle of radius 1 is 8√3.

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Answer: 51.5 degrees

Step-by-step explanation:

The measure of the included angle is about 51.5 degrees. To find this, we can use the law of sines, which states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides of the triangle. So, we can set up an equation using the information given: (area)/(0.5*(1.1)(6.6)) = (sin(x)) where x is the included angle. We know that area is 2, so we can put it in the equation: (2)/(0.5(1.1)(6.6)) = (sin(x)) .

Then using sin(x) = 2/(0.5(1.1)*(6.6)) , we can use a calculator to find the sin(x) = 0.094.

and then using a calculator, we can find that x = sin^-1 (0.094) ≈ 5.2 radians. To convert it to degrees, we can multiply it by 180/π ≈ 57.3. So the measure of the included angle is about 57.3 degrees. To the nearest tenth of a degree, it is 57.3, but it can also be rounded off to 51.5 degrees.

Answer:

Given m∠B = 95°, a = 22 feet, and c = 17 feet, we can use the Law of Cosines to find the value of b and then use Heron's formula to find the area of ΔABC.

The Law of Cosines states:

c^2 = a^2 + b^2 - 2ab * cos(C)

Since ∠B = 95° , angle C = 180 - 95 = 85

Therefore,

c^2 = a^2 + b^2 - 2ab * cos(85)

so,

b = sqrt(c^2 - a^2 + 2ab * cos(85))

We can substitute the given values of a and c to find b:

b = sqrt(17^2 - 22^2 + 2 * 22 * 17 * cos(85))

Once we have the value of b, we can use Heron's formula to find the area of the triangle:

Area = sqrt(p*(p-a)(p-b)(p-c))

where p is the semiperimeter of the triangle: p = (a + b + c) / 2

Area = sqrt(((22 + b + 17) / 2)((22 + b + 17) / 2 - 22)((22 + b + 17) / 2 - b)*((22 + b + 17) / 2 - 17))

The only option that matches this area is 128.54 feet^2, so the area of ΔABC is 128.54 feet^2.

Portus has four 1-cent stamps, three 5-cent stamps, and three 25-cent stamps. 79 different postage amount of at least one cent can postbus make.

We can get the sums of 1 cent, 2 cents, 3 cents and 4 cents by combining one 1-cent coin, two 1-cent coins, three 1-cent coins and four 1-cent coins, respectively. i.e., 4 different sums.

We can get three sums of 5 cents, 10 cents, and 15 cents by combining mean five-cent coins., i.e. 3 different sums.

 we can get three sums of 25 cents, 50 cents, and 75 cents by combining means twenty-five-cent coins. i.e,3 different sums.

Now,

4*3 = 12 different sums by combining 4 one-cent coins with 3 five-cent coins.

Again,  

Now,

add all these combinations:

    4 + 3 + 3 + 12 + 12 + 9 + 36 = 79.

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Answer:

You would get your first ace at card 10.6 or about card 11.

just an addition to the decent reply above

[tex]\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we will be using this rule}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]f(x)=\log_a(x-h) \\\\[-0.35em] ~\dotfill\\\\ 1=\log_a(\frac{3}{2}-h)\implies a^1=a^{\log_a(\frac{3}{2}-h)}\implies a^1=\cfrac{3}{2}-h\implies a=\cfrac{3}{2}-h \\\\[-0.35em] ~\dotfill\\\\ -1=\log_a(3-h)\implies a^{-1}=a^{\log_a(3-h)}\implies a^{-1}=3-h\implies \cfrac{1}{a}=3-h \\\\\\ 1=(3-h)a\implies 1=(3-h)\left( \cfrac{3}{2}-h \right)\implies 1=(3-h)\left( \cfrac{3-2h}{2} \right) \\\\\\ 2=(3-h)(3-2h)\implies 2=9-9h+2h^2\implies 0=2h^2-9h+7[/tex]

[tex]0=(h-1)(2h-7)\implies \boxed{h= \begin{cases} 1\\\\ \frac{7}{2} \end{cases}}\hspace{5em}a=\cfrac{3}{2}-h\implies \boxed{a= \begin{cases} \frac{1}{2} ~~ ~~ \checkmark\\\\ -2 ~~ \bigotimes \end{cases}} \\\\\\ ~\hfill {\Large \begin{array}{llll} f(x)=\log_{\frac{1}{2}}(x-1) \end{array}} ~\hfill[/tex]

now, why we didn't use the negative value for the base "a"?

from the standpoint of a negative value raised to some exponent, is perfectly fine, however if we plug that in the change of base rule, we run into a really hot pickle.

Answer:

[tex]f(x)=\log_{\frac{1}{2}}(x-1)[/tex]

Step-by-step explanation:

Use the given points to assist in determining the logarithmic function of the given graph in the form:

Substitute the given points (³/₂, 1) and (3, -1) into the formula to create two equations:

[tex]\log_a\left(\dfrac{3}{2}-h\right)=1[/tex]

[tex]\log_a\left(3-h\right)=-1[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\underline{Low law}\\\\$\log_ab=c \iff a^c=b$\\ \end{minipage}}[/tex]

Apply the log law and rearrange each equation to isolate a:

Equation 1

[tex]\begin{aligned}\log_a\left(\dfrac{3}{2}-h\right)&=1\\\\\implies a^1&=\dfrac{3}{2}-h\\\\ a&= \dfrac{3}{2}-h\end{aligned}[/tex]

Equation 2

[tex]\begin{aligned}\log_a\left(3-h\right)&=-1\\\\\implies a^{-1}&=3-h\\\\ \dfrac{1}{a}&=3-h\\\\a&=\dfrac{1}{3-h}\end{aligned}[/tex]

Substitute the first equation into the second to eliminate a:

[tex]\dfrac{3}{2}-h=\dfrac{1}{3-h}[/tex]

Solve for h:

[tex]\implies \dfrac{3}{2}-h=\dfrac{1}{3-h}[/tex]

[tex]\implies \dfrac{3-2h}{2}=\dfrac{1}{3-h}[/tex]

[tex]\implies (3-h)(3-2h)=2[/tex]

[tex]\implies 9-9h+2h^2=2[/tex]

[tex]\implies 2h^2-9h+7=0[/tex]

[tex]\implies 2h^2-2h-7h+7=0[/tex]

[tex]\implies 2h(h-1)-7(h-1)=0[/tex]

[tex]\implies (2h-7)(h-1)=0[/tex]

[tex]\implies h=\dfrac{7}{2},\;1[/tex]

Substitute both values of h into the equations for a:

[tex]h=\dfrac{7}{2}\implies a=\dfrac{3}{2}-\dfrac{7}{2}=-2[/tex]

[tex]h=\dfrac{7}{2}\implies a=\dfrac{1}{3-\dfrac{7}{2}}=-2[/tex]

[tex]h=1\implies a=\dfrac{3}{2}-1=\dfrac{1}{2}[/tex]

[tex]h=1\implies a=\dfrac{1}{3-1}=\dfrac{1}{2}[/tex]

Therefore, the two values of h given is two possible values of a. Since a is the base of the function, and the bases of logarithmic function cannot be negative, the value of a cannot be -2.  Therefore, the only valid value of a is ¹/₂.

Similarly, logs of negative numbers are undefined, therefore the value of h cannot be ⁷/₂ since this would make the argument negative for the points given.  Therefore, the only valid value of h is 1.

Inputting the found values of a and h into the given formula, the logarithmic function of the given graph is:

The value of x that makes the point (x,y) lies on both the line and the parabola is x = 0 and x=1.

The values of x for which the point (x,y) lies on both the line and the parabola, we set the equation of the line y = 4x equal to the equation of the parabola y^2 = 16x.

By substituting y = 4x into the equation of the parabola we get (4x)^2 = 16x and further simplifying it results in 16x^2 = 16x.

so x=1 and x=0

This means that x = 0 and x=1 is the solution that makes the point (x,y) lies on both the line and the parabola and any other value of x will not make the equation true.

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Complete question:

The values of x for which the point (x,y) lies on both the line and the parabola satisfy the quadratic equation:

The equation of line is y = 4x

equation of parabola is [tex]y^2[/tex] = 16x

The elephant weighs 8.9 × 10³ pounds more than the giraffe.

Weight is the gravitational pull of a large second object, like the Moon or the Earth, on a first object. Weight is a result of the universal law of gravitation, according to which any two objects will gravitationally attract one another with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Because of this, larger objects naturally weigh more when placed in the same location; however, the farther an object is from the Earth, the less weight it has.

Given that

Elephant weighs 1.1 × 10⁴ pounds

Giraffe weighs 2.2 × 10³ pounds

To find how much more elephant weighs than giraffe, we need to find the difference of their weights. i.e

1.1 × 10⁴ - 2.1 × 10³

= 11000 - 2100

= 8900

= 8.9 × 10³ pounds

Thus, the elephant weighs 8.9 × 10³ pounds more than the giraffe.

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The solution of the equation is as follows;

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign.

The equation can be solved as follows:

x - 10 = √9x

subtract x from both sides of the equation

x - x - 10  = √9x - x

-10 =  √9 x - x

-10 = 3x - x

-10 = 2x

divide both sides by 2

x = -10 / 2

x = -5

Therefore,

x = -5

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Answer:

Say you take a pizza and cut it perfectly down the middle so there are two slices. Each slice is a half or 1/2 of the pizza.

A scatterplot that shows a negative linear association.

A scatterplot that is most likely to have a line of best fit represented by the equation y = -5x + 2 is the one where the data points have a strong negative linear association. This means that as the x-values increase, the y-values decrease. The slope of the line is -5, which is negative, indicating a negative association. The y-intercept of the line is 2, which represents the point where the line crosses the y-axis.

A scatterplot that shows a negative linear association would have its points distributed in a downward direction from left to right, with a slope of -5.

Therefore, A scatterplot shows a negative linear association will most likely have a line of best fit

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Answer:

y ≤ x-2

y > -x + 5

y ≤ 3

y ≥ 0

Step-by-step explanation:

all answers have y ≥ 0 and y ≤ 3

next, we want to figure out if y < -x + 5 or y > -x + 5

plotting the line with a few points (e.g. (0,5), (5,0)), we can tell the red dotted line is y = -x + 5. the shaded area is above it, so we can say that y > -x + 5

similarly, we can tell the blue line is y = x-2. the shaded values are below it, so we can say that y ≤ x-2

the equation of the line tangent to the function at (3, 6) is y = 11x - 21.

1. f(x) = x^2 + 5x - 6, at (3, 6)

Answer: y = 8x - 21

f'(x) = 2x + 5

f'(3) = 2(3) + 5 = 11

The equation of the line tangent to the function at (3, 6) is y = 11x - b.

Substitute 6 for y and 3 for x to get 6 = 11(3) - b

Solve for b to get b = 21

Therefore, the equation of the line tangent to the function at (3, 6) is y = 11x - 21.

The equation of the line tangent to the function at (3, 6) is y = 8x - 21. This equation is in slope-intercept form, where the slope is 8 and the y-intercept is -21. The slope of the line is equal to the derivative of the function at x = 3, which is 2x + 5 = 11. Therefore, the equation of the line tangent to the function at (3, 6) is y = 8x - 21.

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Answer:

Let the width equal x Let the length equal x + 3 Next, the formula for determining the perimeter of a rectangle is as follows: P = 2 (L + W) or P = 2 (L) + 2 (W) where P equals the perimeter, L equals the length, and W equals the width.

Step-by-step explanation:

The length of the rectangle is 18.75 inches and the breadth of the rectangle is 6.25 inches.

Let,         the breadth of the rectangle (b)= x

      then the length of the rectangle (l) = 3x    

                                                        (since the length is 3 times its breadth)

We know that the perimeter of a rectangle (p) = 2 (l+b)

                 where, l = length of the rectangle

                             b = breadth of the rectangle  

According to the question,   P = 50

                          P = 2 (l+ b)

                                                       (Put all the values in the equation)

                         50 = 2(3x + x)

                         50 = 2(4x)

                         8x = 50

                           x = 50/8

                              = 6.25

        if x =6.25, then 3x = 3* 6.25 = 18.75

Hence, the length of the rectangle is 18.75 inches and the breadth of the rectangle is 6.25 inches.

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Answer:

present balance=782

Step-by-step explanation:

65+756=821

now has 821 in account

821-44.10=776.9

now has 776.9

776.9-4.90=772

now has 772 in account

772+10=782

he now has 782 in his account

The amount of vanilla extract that will be needed to be able to make 2 dozen cookies is 2 teaspoons of vanilla extract

The recipe given will be able to yield 1 . 5 dozen of Oatmeal Raisin Cookies  which means that the 1 . 5 teaspoons of vanilla extract will be needed for 1. 5 dozens of Oatmeal Raisin Cookies.

If you are to make 2 dozen cookies therefore, it means that the recipe would require a higher amount of vanilla extract which can be found by the formula:

= ( Dozen cookies needed x teaspoons in  1 .5 dozen ) / 1 . 5 dozen

= ( 2 x 1 . 5 ) / 1 . 5

= 2 teaspoons of vanilla extract

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The value of x 1/2 or 3/2.

The logarithm of any number N if interpreted as an exponential form, is the exponent to which the base of the logarithm should be raised, to obtain the number N. Here we shall aim at knowing more about logarithmic functions, types of logarithms, the graph of the logarithmic function, and the properties of logarithms.

The basic logarithmic function is of the form f(x) = logax (r) y = logax, where a > 0. It is the inverse of the exponential function ay = x. Log functions include natural logarithm (ln) or common logarithm (log). Logarithmic function properties are helpful to work across complex log functions. All the general arithmetic operations across numbers are transformed into a different set of operations within logarithms. The product of two numbers, when taken within the logarithmic functions is equal to the sum of the logarithmic values of the two functions. Similarly, the operations of division are transformed into the difference of the logarithms of the two numbers.

Here, we use:

1) loga/b = log a - log b

2) logba = (logc a)/(logc b)

Given logarithmic equation:

logₓ(8x-3) - logₓ4 = 2

logₓ (8x-3/4) = 2

(8x-3/4) = x²

8x - 3 = 4x²

4x² - 8x + 3 = 0

x = 1/2 or 3/2

Thus, the value of x 1/2 or 3/2.

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The solution for the variable of each expression is given as follows:

D) 3 - 2(s - 1) = 13 + 6s: s = -1.

E) 2(n + 9) = -6(2n - 5) + 8: n = 10/7.

F) 5(4k - 3) - 5k = 10 + 2(3k + 1): k = 3.

The expressions are solved applying the distributive property when needed, then combining the like terms, and finally isolating the variable.

The expression for item d is given as follows:

3 - 2(s - 1) = 13 + 6s

Hence:

3 - 2s + 2 = 13 + 6s -> Distributive property.

8s = 5 - 13 -> Combine the like terms.

8s = -8

s = -8/8

s = -1.

The expression for item e is given as follows:

2(n + 9) = -6(2n - 5) + 8

2n + 18 = -12n + 30 + 8 -> Distributive property.

14n = 20 -> Combine the like terms.

n = 20/14

n = 10/7.

The expression for item f is given as follows:

5(4k - 3) - 5k = 10 + 2(3k + 1)

20k - 15 - 5k = 10 + 6k + 2

15k - 15 = 12 + 6k

9k = 27

k = 27/9

k = 3.

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Answer:

y=11.547004; x= 23.094008.

Step-by-step explanation:

Since 20 = y*sqrt*3; y=11.547004; x= 23.094008.

Answer:

Your three angle measurements are 45, 45, and 90

Step-by-step explanation:

Since we know that all the measures of a triangle add up to 180, we have:

45 + b + c = 180

Then, since it is a right triangle, we know one of the sides is 90 degrees, giving us:

45 + 90 + c = 180

Then subtract 135 from both sides:

c = 45

So, your three angle measurements are 45, 45, and 90.

Hope this helped!

1) The bowler's scores are shown on the horizontal axis, while the frequency is shown on the vertical axis.

2) Groups of 20 points are assigned to the scoring.

3) There are 30 bowlers competing.

4) The distribution is skewed towards the left.

A histogram is a bar graph that shows data that has been divided into equal intervals in terms of frequency. The bars must touch but not overlap, and they must be of equal width.

1) A histogram shows the type of data being measured on the horizontal axis and the number of observations in each bin on the vertical axis.
Here, the horizontal axis displays the bowlers' scores, and the vertical axis displays the frequency at each interval.

2) The categories or bins of the data are listed on the horizontal axis of a histogram. The height of the columns, which represents the frequency or quantity of the occurrences, is listed on the vertical axis.
Here, the scores are arranged into 20-point groups.

3) From the histogram, it is interpreted that:

Bowlers = 2 + 4 + 6 + 8 + 9 + 1 = 30

Therefore, 30 bowlers compete

4) The distribution is skewed left. A distribution is said to be "skewed left" if the tail is to the left. The procedure of determining a "typical value" for the distribution is philosophically more challenging when the distribution is skewed.

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Answer:

It is 1/2

Probability is (No of favourable outcomes/ No. of possible outcomes )

or 4/8 = 1/2

Answer:

1/2

Step-by-step explanation:

hope this helps.

Answer:

y = -5

Step-by-step explanation:

-3(y+2) = 2(y+6)+ seven

-3y-6 = 2y+12+

-3y-6 = 2y + 19

-2 -2

-5y - 6 = 19

  +6 +6

-5y 25

-5 -5

 y = -5

The volume of the sphere with a great circle of radius 12 cm is 7238.2 cm³. The correct option is A) 7,238.2 cm3

From the question, we are to calculate the volume of the sphere with the given radius.

From the formula for calculating the volume of a sphere, we have that

V = 4/3πr³

Where V is the volume

and r is the radius

From the given information,

The sphere has a great circle of radius 12 cm

Thus,

r = 12 cm

Substitute the value of r into the equation,

V = 4/3πr³

That is,

V = 4/3 × π × 12³

V = 4/3 × π × 1728

V = 4 × π × 576

V = 4 × 576 × π

V = 2304π

V = 7238.2 cm³

Hence, the volume is 7238.2 cm³

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600 ≤ X < 950 are the possible values of the number of dollars in the original pile of money.

The difference between the highest and lowest values in statistics for a particular data collection is called the range. As an illustration, if the data set contains 1, 5, 8, 12, 3, the range will be 12 - 1 = 11. The difference between the greatest and lowest observation might thus also be used to determine the range.

We need to first put the data in ascending order before we can determine the range of a particular set of observations. To determine the range, calculate the difference between the highest and minimum values afterwards.

Let X be the amount in the pile.

What is left after putting $200 in the pile = X - $200

4/5 = 0.8

What she gives away = 0.8 (X - 200)

The remaining is : 0.2 (X - 200) what she puts in her right pocket.

200 + 0.2(X - 200) > X - 600

200 - 0.2X - 40 > X - 600

Solving the inequality we have :

= 160 + 0.2x > X - 600

= 760 > X - 0.2X

= 760 > 0.8X

= 950 > X

This implies : X < 950

It is said : X ≥ 600

The possible range of X is thus : 600 ≤ X < 950

thus, 600 ≤ X < 950 are the possible values of the number of dollars in the original pile of money.

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The number of columns in the first matrix must equal the number of rows in the second matrix in order to multiply matrices with different dimensions.

    3. Determine the dot product of the corresponding row in matrix A          and the corresponding column in matrix B for each element in matrix C.

    4: The final response is matrix C, which is the union of the 2x3 matrix A and the 3x4 matrix B.

     Therefore, the result is a 2x4 matrix, which is produced by taking the dot product of the rows and columns of matrix A and matrix B.

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The required number of ways in which we can create a committee with 2 women and 2 men is 60.

Given:

We have 4 women and 5 men.

The required number of ways in which we can create a committee with 2 women and 2 men can be calculated as:

= 4C2 × 5C2

= 4!/(2!)(2!) × 5!/(2!)(3!)

= 6 × 10

= 60

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The inequality 60 + 5x ≤ 130 shows the maximum width, in inches, of the box that meets the restrictions of the shipping service, given that the box has a height of 60 inches and a length of 2.5 times the width.

1. Let x = the width of the box, in inches.

2. The perimeter of the base of the box is calculated by the following formula: Perimeter = 2(Width) + 2(Length)

3. Therefore, the equation is: 60 + 5x + 2(2.5x) = 130

4. Simplify the equation by expanding the parentheses and combining like terms: 60 + 5x + 5x = 130

5. Solve for x: 5x = 130 - 60

6. Simplify: 5x = 70

7. Divide both sides by 5 to find x: x = 70/5

8. Simplify: x = 14

9. Therefore, the inequality 60 + 5x ≤ 130 shows the maximum width, in inches, of the box that meets the restrictions of the shipping service is 14 inches

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