The outward force on the sidewall of the tire due to the air pressure of 38.50 psi is 23,523.74 pounds.
What is pressure?Pressure is the amount of force applied over a given area. It is typically measured in units of Pascals (Pa) or pounds per square inch (psi). Pressure can be caused by a variety of factors, including the weight of the atmosphere, the weight of liquids, and the weight of objects. Pressure is important in many physical phenomena, including the flow of liquids, the transfer of energy, and the propagation of sound. In general, when pressure increases, the volume of the material decreases.
The outward force on the sidewall due to the air pressure of 38.50 psi is calculated by multiplying the gauge pressure by the total area of the sidewall. The formula for this calculation is F = P x A, where F is the outward force (in pounds) on the sidewall, P is the gauge pressure (in psi) and A is the total area of the sidewall (in square inches).
Therefore, the outward force on the sidewall of the tire due to the air pressure of 38.50 psi is 23,523.74 pounds. This value can be found by multiplying 38.50 by 606.47, the total area of the sidewall.
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The outward force (in pounds) on the sidewall due to air pressure is 1,945.18 pounds.
What do you mean by force?In physics, force is a push or pull exerted on an object to change its motion. It is a vector quantity, meaning it has both magnitude and direction. The standard unit of force in the International System of Units (SI) is the newton (N).
Forces can be classified into two types: contact forces and non-contact forces. Contact forces, such as friction and tension, require physical contact between the two objects. Non-contact forces, such as gravity and magnetism, can act on an object without physical contact.
Forces can also be categorized as balanced or unbalanced. Balanced forces are those that cancel each other out, resulting in no net force acting on an object. Unbalanced forces, on the other hand, produce a net force that causes an object to accelerate.
The outward force on the sidewall of the tire due to air pressure can be calculated using the formula:
F = P × A
where F is the force, P is the pressure and A is the area.
In this case, the gauge pressure is 38.50 psi, the area of one sidewall of the tire is 606.47 square inches. So,
F = P × A = 38.50 psi × 606.47 in² = 23,342.20 in-lbs
To convert in-lbs to pounds, we divide by 12
F = [tex]\frac{23,342.20 in-lbs }{12}[/tex] = 1,945.18 pounds
So the outward force on the sidewall of the tire due to air pressure is approximately 1,945.18 pounds.
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The illumination lights in an operating room use a converging mirror to focus an image of a bright lamp onto the surgical site. One such light has a mirror with a focal length of 15 cm. If the patient is 1.0m from the mirror, where should the lamp be placed relative to the mirror?
According to the question: The lamp should be placed 11 cm from the mirror.
What is mirror?Mirror is an object which reflects light in such a way that images of nearby objects are visible. It is a surface which can reflect light in an exact way. Mirrors are used for various purposes like for making up, for decorating a room, for security purposes, and also for various scientific experiments. Mirrors are usually made up of two pieces of glass which are either flat or curved with a reflective coating on one side.
This coating is usually made up of metal, such as silver, and is highly reflective. Mirrors can also be made up of other materials such as plastic and other metals. By reflecting light, mirrors can help to create illusions and also create an optical illusion.
This is because the distance between the mirror and the lamp should be equal to the sum of the focal length of the mirror (15 cm) and the distance between the patient and the mirror (1.0 m). Therefore, the distance between the mirror and the lamp should be 1.0 + 15/100 = 2.15 m.
Use the thin lens equation to solve this
(1/s)+(1/s prime)=(1/f)
You are looking for the s value, which is the lamps distance from the mirror. s prime is the distance to the patient, and f is 10 cm.
(1/s)+(1/1.1)= (1/0.1)
= 11.000001 cm
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sound travels at 343m/s in the air. what distance from the student, in meters, is the lightning strike?
In order to determine the distance from the student that the lightning strike occurred, you would need additional information, such as the time it took for the sound of the strike to reach the student. Without that information, it is not possible to calculate the distance of the lightning strike.
This can be calculated by dividing the distance (speed of sound x time) by the speed of sound, which is 343m/s. Once the time is known, the distance can be calculated by multiplying the time by the speed of the sound. It is not possible to determine the distance from the student to the lightning strike.
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what did you observe about the motion of objects during and after collisions? 2. based on the velocity change of each object, what did you infer about the direction of forces during a collision?
When two objects of different masses are subjected to a force of the same strength, the one with less mass will experience a higher change in velocity.
What occurs when two items hit each other?Each object pulls the other when two objects come into contact. Imagine using a bat to strike a softball. The ball is pushed away by the bat when it collides with it. The bat experiences force from the ball as well.
What happens when two moving objects slam into each other?Even if two colliding objects have masses that are very different from one another, they will nevertheless exert equal forces on one another. An object always experiences an impetus and a shift in momentum during a collision. The impulse that an object encounters during a collision is equal to its variation in speed.
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As an orange falls vertically downward, its momentum changes by 2. 4 kg x m/s per second.
a) What is the weight of the orange?
b) How much time does it take for the orange's momentum to change by 6. 1 kg x m/s?
A) The weight of the orange is 2.4N and B) It takes 1.542s for the orange's momentum to change by 6. 1 kg·m/s.
What is weight?Weight is the measure of the force of gravity on an object. It is a measure of the amount of matter present in an object and is measured in units such as kilograms, pounds, or ounces. Weight is the same no matter where an object is located, as gravity is a universal force. Weight is different than mass, which is the amount of matter in an object regardless of gravity. Mass is measured in kilograms, grams, or other metric units. Weight can be calculated by multiplying an object's mass by the acceleration due to gravity.
(a)
The rate of change of the momentum of any object is equal to the force acting on the object.
The orange is free falling so the force acting on the orange will be equal to to weight of the orange.
Then, the weight of the orange is 2.4N.
(b)
Given the initial momentum is 2.4 kg·m/s2
Calculate the time required for the oranges momentum to change by 6.1 kg·m/s,
W × t
= final momentum - initial momentum
= 6.1 - 2.4(t)
= 1.542s
Thus, The weight of the orange is 2.4N and It takes 1.542s for the orange's momentum to change by 6. 1 kg·m/s.
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4. A box rests on a horizontal, frictionless surface. A girl pushes on the box with a force of 18 N to the right and a boy pushes on the box with a force of 12 N to the left.The box moves 4.0 m to the right. Find the work done by (a) the girl, (b) the boy, and (c) the net force
A box rests on a horizontal, frictionless surface. A girl pushes on the box with a force of 18 N to the right and a boy pushes on the box with a force of 12 N to the left. The box moves 4.0 m to the right. Find the work done by (a) the girl, (b) the boy, and (c) the net force.
Explanation:
Find the work done by (a) the girl, (b) the boy, and (c) the net force.
a-b=c
18 N - 12 N = Net Force 6
The answer to Net Force of 6 to the right
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a ball starts from rest and rolls down a hill with uniform acceleration, traveling 200 m during the second 5.0 s of its motion. how far did it roll during the first 5.0 s of motion?
An object moving at a constant pace travels 5 meters in the first second; thus, it travels 45 meters in the third second.
In simple terms, what can the acceleration mean?The measurement of such a change in the speed called acceleration. Acceleration frequently, though not always, denotes a shift in speed. A thing that moves in a circle at a constant speed has still been moving forward since the direction of the motion is changing.
Calculation
the object starts from rest i.e. initial velocity, u = 0
and have uniform acceleration.
S = 5m and t = 1s
According to the formula of distance,
S = ut + 1/2 at²
5 = 0×1 + 1/2 a×1²
5 = 1/2a
a = 10m/s²
again, t = 3s
now, v = u + at
v = 0 + 10×3
v= 30m/s
Now, 2aS = v²-u²
2aS = 30²-0
2×10×S = 900
S= 900/20 = 90/2
S = 45m
Thus, the distance traveled by the body in 3rd second is 45m .
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A marble is launched at a speed of 9 m/s at an angle of 25° above the horizontal. If the experiment is done on a level floor, then how far away will the marble land if friction is neglected? SHOW WORK.
A. 1.58 m
B. 3.16 m
C. 6.33 m
D. 6.98 m
If a marble is launched at a speed of 9 m/s at an angle of 25° above the horizontal. If the experiment is done on a level floor, then The distance that the marble will land if friction is neglected is: C. 6.33 m.
How to find the distance the marble will land if friction is neglected?Given data:
Speed = 9m/s
Angle = 25°
Now let find the distance the marble will land if friction is neglected
Range = v² sin(25 × 2)/g
Range = (9 m/s)² × sin 50 / g
Range =(81 m/s² × 0.766044) / 9.8 m/s²
Range = 62.049564 m/s² / 9.8 m/s²
Range = 6.3315m
Range = 6.332 m (Approximately)
Therefore we can conclude that the correct option is C.
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a merry-go-round with a moment of inertia equal to and a radius of 2.5 m rotates with negligible friction at 1.70 rad/s. a child initially standing still next to the merry-go-round jumps onto the edge of the platform straight toward the axis of rotation, causing the platform to slow to 1.35 rad/s. what is her mass?
In order to cause the platform to rotate around her mass, m=54.51 kg, a youngster initially standing stationary next to the merry-go-round jumps onto the edge of the platform straight toward the axis of rotation.
Simply put, what is moment of inertia?The moment of inertia gauges an object's resistance to variations in rotational motion. A body's resistance to changes in rotation is measured by the moment of inertia of its cross-section.
What is the purpose of moment of inertia?One of the numerous mass qualities that describes an object's stability and the forces required to change its motion is the moment of inertia (MOI). Stability is a key component in the design and manufacture of air and spacecraft in aeronautical engineering.
Iω₁+0= (I + mR²)ω₂
1230×1.72+0= (1230+m×(2.7)²×1.30)
m= 54.51 kg
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what is the ball’s mass? use rho = 1.2 kg/m3 for the density of air at room temperature.
The ball's mass with a terminal velocity of 28 m/s is found to be 2.54Kg.
What is the terminal velocity?An object falling through a fluid at its greatest speed is said to have reached its terminal velocity. When the combined drag and buoyancy forces are equal to the force of gravity pulling the object downward, it is observed. Since there is no net force exerted on the object, there is no acceleration of the object.
Terminal velocity v = Sqrt(2mg/ρAC)
drag co-effiecient of sphere (ball) C = 0.47
=> Ball's mass m= v2 x ρAC/2g
=> 28^2 x 1.2 x 4 π (6.5 x 10^-2)^2/ 2 x 9.8
=> 2.54Kg
How does drag coefficient work?A dimensionless quantity called the Drag Coefficient (Cd) is used to measure an object's resistance to movement through a fluid. It enables aerodynamics to simulate how shape, inclination, and flow characteristics affect aerodynamic drag
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A 6.5-cm-diameter ball has a terminal speed of 28 m/s. What is the ball's mass? Use ρ=1.2 kg/m3 for the density of air at room temperature.
A container of volume 0.4 m3 contains 3 mol of argon gas at 300C. Assuming argon behaves as an ideal gas, find the total internal energy of the gas?
11223.9J or 11.2239 kJ is the total internal energy of the gas.
What is internal energy?Internal energy, which results from the motion of matter at the molecular level, is a type of energy that exists in all systems. For internal energy, the letter U is used, and the joule is the unit of measurement (J).
As a substance changes from one state or phase to another—from solid to liquid to gas—its internal energy also rises. It is possible to imagine planetary bodies as a fusion of heat engines and heat reservoirs.
The heat engines transform some of the thermal energy stored in the heat reservoirs into different forms of mechanical, electrical, and chemical energy.
The formula for total internal energy of gas is
(3/2)nRT
where n = amount of substance
R = Ideal gas constant
T = temperature
Put the value in the equation
(3/2)nRT
= (3/2)(3)( 8.314)(300)
= 11223.9J
Thus, 11223.9J or 11.2239 kJ is the total total internal energy of the gas.
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a satellite is currently orbiting earth in a circular orbit of radius r; its kinetic energy is k1. if the satellite is moved and enters a new circular orbit of radius 2r, what will be its kinetic energy?
The kinetic energy of the satellite when it has been moved and it enters a new circular orbit of radius 2r is K₁/2.
Centripetal force is equal to mass times velocity squared over radius (Fc = mv²/r). Gravity is equal to gravitational constant times the product of masses of two objects over distance squared (Fg = GMm/r²). The centripetal force on the satellite is provided by the gravitational pull by the earth, so Fc = Fg.
Kinetic energy, the energy acquired by a moving object, is equal to one half of a mass times velocity squared (K = mv²/2).
Fc = Fg gives the equation mv²/2 = GMm/2r. As you can see, the kinetic energy K of the satellite is inversely proportional to radius or distance r. Therefore, K decreases by a factor of 2 when r increases by a factor of 2, and K₁/2 = 2r.
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A woman and her motorbike together have a mass of 220 kg. The bike accelerates at 5 m/s². What is the force from the motorbike's engine?
The force from the motorbike's engine is equal to the mass multiplied by the acceleration, or 220 kg x 5 m/s² = 1,100 N.
What is mass ?
Mass is the amount of matter or material in an object. It is measured in kilograms (kg) or pounds (lbs). Mass is different from weight, which is the measure of the force of gravity on an object. Mass is a property of an object that is independent of its location in space, whereas weight is a measure of the force of gravity on an object and therefore is dependent on its location.
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The acceleration due to gravity on the Moon is gM. Suppose an astronaut on the Moon drops an object from a height of H. The time it would take the object to reach the Moon’s surface would be TM. The same object is dropped from the same height on Earth, where the acceleration due to gravity is gE. The time it takes the object to reach the Earth’s surface is TE. Which of the following is a correct mathematical relationship for the two times?A. TE = √gE/gM . TM B. TE = √gM/gE . TMC. TE = gE/gM . TM D. TE = gM/gE . TM E. TE = TM
The correct mathematical relationship for the two times is Option B: TE = √gM/gE . TM.
What is gravity?Gravity is a natural phenomenon that causes objects with mass to be attracted to one another. It is one of the four fundamental forces in nature and is responsible for the formation and structure of galaxies, stars, and planets. Gravity is experienced as a force pulling objects towards each other. The strength of gravity depends on the distance between two objects, as well as their masses.
This is because the acceleration due to gravity is inversely proportional to the time taken for an object to fall. The equation for this is:
Time = √2*Distance/Acceleration.
Therefore, if we substitute the values for the Moon and Earth in this equation, we get:
TE = √gM/gE . TM
where gM and gE are the accelerations due to gravity on the Moon and Earth, respectively, and TM and TE are the times taken for the object to reach the Moon's and Earth's surfaces, respectively.
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the gravity of the moon is about 1/6 that of the earth. for example, an astronaut weighing 180 pounds on the earth would weigh about 30 pounds on the moon. if you were to double the distance between the earth and the moon, how much would our 180 pound astronaut weigh on the moon?
The Moon's gravity is roughly 1/6 that of the Earth's. An astronaut who weighs 180 pounds on Earth would weigh roughly 30 pounds on the Moon, for instance.
What would the astronaut's acceleration be as a result of Earth's gravity?For instance, the astronauts on the International Space Station are located around 400 kilometers (250 miles) above the Earth's surface. The acceleration caused by Earth's gravity is just slightly less at their elevation than it is at the surface of the planet: 8.7 m/s2 as opposed to 9.8 m/s2, a decrease of only around 12%.
Why is it that an astronaut in a space station 300 kilometers above the earth's surface is weightless?(B) An astronaut in space does experience weightlessness because the force of gravity cannot be resisted by a ground or normal force. The astronaut is thus falling. The astronaut, however, falls continually around the Planet rather than colliding with it since they are both going extremely quickly.
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the speed of individual particle diffusion is influenced by temperature and particle size, not by concentration. the speed of individual particle diffusion is influenced by temperature and particle size, not by concentration. true false
True, the speed of individual particle diffusion is influenced by temperature and particle size, not by concentration.
Prolixity is the tendency of motes to spread out in order to enthrall an available space. feasts and motes in a liquid have a tendency to diffuse from a more concentrated terrain to a lower concentrated terrain. Passive transport is the prolixity of substances across a membrane. This is a robotic process and cellular energy isn't expended. motes will move from where a substance is more concentrated to where it's less concentrated. The rate of prolixity for different substances is affected by membrane permeability.
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a person accumulates a net charge of -42 microcoulombs. how many excess electrons does she get, and by how much does her mass increase?
The excess electrons does she get is 2.625 10^ 14 and her mass increase is 2.388 x 10^-16 Kg.
How does accumulated charge work?A new experimental method called accumulated charge measurement (ACM) uses a metal-insulator-semiconductor-metal (MISM) capacitor to assess the charge injection barrier at the semiconductor-metal interface.
Number electron => charge / charge of electron
=> -42 mc/-1.6 x 10^-19
=> 2.625 10^ 14 excess electron
Mass of her = mass of 1 electron x excess electron
9.1 x 10^-31 kg x 2.625 x 10^14
=> 2.388 x 10^-16 Kg
My body is tremendously energised, why?For instance, if there are too many electrons in our bodies, they will escape as soon as we come into contact with a positively charged object, trapping us. We are so electrically charged during this process that breaking down air molecules even when we are only an inch away results in a violent shock.
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give an example of something we think of as work in everyday circumstances that is not work in the scientific sense. is energy transferred or changed in form in your example? if so, explain how this is accomplished without doing work.
To raise my grade in mathematics, I am working diligently, although this is not research in the traditional sense. In this illustration, the person is expending mental energy to study arithmetic, but no practical labor
What energy has the greatest strength?Unquestionably, nuclear energy seems to have the largest nameplate capacity compared to any other source of energy.
What energizes you?According to biology, the food we consume gives our bodies energy. Carbohydrates, lipids, & proteins are the three fuel types from which this energy is derived. Your body metabolizes the food you consume and absorbs this into your blood so that your cells may use it as fuel.
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An object of mass M = 1.00 kg is attached to a spring with spring constant k = 99.0 N/m whose unstretched length is L = 0.140 m , and whose far end is fixed to a shaft that is rotating with an angular speed of ω = 3.00 radians/s . Neglect gravity and assume that the mass also rotates with an angular speed of 3.00 radians/s as shown. (Figure 1) When solving this problem use an inertial coordinate system, as drawn here. (Figure 2)
Assume that, at a certain angular speed ω2, the radius R becomes twice L. Find ω2.
Express your answer in radians per second.
The equation that relates the angular speed ω2 to the spring constant k, the mass M, and the unscratched length L is given by:
ω2 = sqrt(k/M)*2L
What is spring constant ?
The spring constant, also known as the rate or stiffness of the spring, is a measure of the force required to compress or extend a spring by a certain distance. It is defined as the change in force per unit change in length of the spring. The spring constant is usually denoted by the letter k and has units of force per unit length (such as N/m or lbf/in). A spring with a large spring constant will require more force to compress or extend it than one with a smaller spring constant.
Therefore, the angular speed ω2 at which the radius R becomes twice L can be calculated as follows:
ω2 = sqrt(99 N/m / 1.00 kg) * 2 * 0.140 m
ω2 = 19.67 radians/s
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a 300 kg mass is moving to the right at a velocity of 20 m/s. all of a sudden (for no explicable reason) the mass of the object triples. what happens to the velocity?
If mass of an object become three times of its initial mass then velocity of the object reduced and has value 11.547 m/s in order to conserve kinetic energy.
What is kinetic energy?Kinetic energy is a type of energy that is present in a particle or object in motion. When work, which includes the transfer of energy was done on an object by applying a net force, that object acquired kinetic energy.
Case 1 -
Mass of object (m1) = 300
velocity of object (v1) = 20 m/s
Kinetic energy = 1/2 m × v²
Kinetic energy = 1/2 × 300 × 20²
Kinetic energy = 60000 J
Case 2 -
Mass of object (m2) = 3 × 300
= 900 m/s
velocity of object (v2) = v2 m/s
Kinetic energy = 1/2 m × v²
60000 = 1/2 × 900 × v²
133.33 = v²
v = 11.547 m/s
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in a coulomb force experiment, a student determines that the force between two equally charged spheres is 300 nn when the centers are separated by 20 mm. what is the:
The charge is equal to the Q= 1.3×10^-4 c. Electric charge is the property of matter that causes it to experience a force when subjected to an electromagnetic field.
A force is what?In science, "force" refers to a certain concept. At this point, describing a force as a push or a draw is quite acceptable. It's incorrect to say that a thing "has in it" or "contains" the force. A force is experienced by one thing from another. The concept of a force makes no distinction between living creatures and inanimate objects.
Coulomb's law is what kind of force?Coulomb's inverse-square law, also referred to as Coulomb's law, is an experimental scientific concept that calculates the force between two stationary electrically charged particles. The electric force that exists between two charged objects at rest is known by the terms electrostatic force and Coulomb force.
F = (k ×Q1× Q2)/r^2
F = 300 N
r = 20 m
k = 8.987× 10^8 Nm^2/c^2
given Q1 =Q2 = Q
300= (8.987× 10^8× 2Q)/400
Q= 1.3×10^-4 c
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A proton and an alpha particle are momentarily at
rest at a distance y from each other. They then
begin to move apart. Find the speed of the proton
by the time the distance between the proton and
the alpha particle doubles.
Both particles are positively charged. The charge
and the mass of the proton are, respectively, e and
m. The charge and the mass of the alpha particle
are, respectively, 2e and 4m.
Find the speed of the proton (Ur )p by the time the distance between the particles doubles. Express your answer in terms of some or all of the quantities e, m, r, and ε
A proton and an alpha particle are momentarily at
rest at a distance y from each other. They then
begin to move ap
the speed of the proton (Ur )p by the time the distance between the particles doubles is (e / (m * y)) * √(2/πε)
The speed of the proton can be found by using the conservation of mechanical energy. The initial potential energy between the proton and the alpha particle is given by: Ui = (1/4πε) * (2e * e)/y. As the distance between the particles doubles, the final potential energy is given by: Uf = (1/4πε) * (2e * e)/(2y) Using the conservation of mechanical energy, we can write:Ui + Ki = Uf + Kf Where Ki is the initial kinetic energy and Kf is the final kinetic energy. Since the particles are momentarily at rest, Ki = 0. Also, Kf = (1/2) * m * Ur^2. where Ur is the speed of the proton. We can substitute these values into the equation for the conservation of mechanical energy:(1/4πε) * (2e * e)/y = (1/2) * m * Ur^2 + (1/4πε) * (2e * e)/(2y) Solving for Ur, we get: Ur = (e / (m * y)) * √(2/πε). This is the final velocity of the proton when the distance between the proton and the alpha particle doubles.
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12 kg of mercury is poured into a glass u-tube with inner diameter of 1.0 cm the mercury can flow without friction within the tube the density of mercury is 13.6 find the period of small oscilatins
The period of small oscillation 12 kg of mercury that poured into a glass tube u with an inside diameter of 1.0 cm mercury can flow without friction in the tube. (The density of mercury is 13.6 x 10³ kg/m³) = 4.61 s
The mercury column's unbalanced weight of 2x is what provides the restoring force when the mercury is moved x meters from its equilibrium location in the right arm.
Weight = v x ρ x g
= (2πr²) x (13.6 x 10³) x (12 x 10⁻⁶ m³)
= 1.13 x 10³ kg/m³
Since Hooke's rule is true and the restoring force = - (2r2 g) x, we can see that the system's effective spring constant is:
k = (2πr²) (ρ) (g)
= 2π (0.005)² (13.6 x 10³) (9.8)
= 20.92 N/m
So, the period:
T = 2π[tex]\sqrt{\frac{m}{k} }[/tex]
= 2π [tex]\sqrt{\frac{1.13(10^{3} )}{20.92} }[/tex]
= 4.61 s
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A)Find the net electric flux passing through the surface S1.
B) Find the net electric flux passing through the surface S2.
C) Find the net electric flux passing through the surface S3.
D) Find the net electric flux passing through the surface S4.
E) Find the net electric flux passing through the surface S5.
gh the surface S1.
B) Find the net electric flux passing through the surface S2.
C) Find the net electric flux passing through the surface S3.
D) Find the net el
Using Gauss Law, the flux through a surface, \phi = charge enclosed inside the surface/ \epsilono. So, for surface S2 net electric flux is 2.25*10^5 Wb.
for surface s2 - phi = (q1 + q2 - q5)/(8.854*10^-12) = (4.6+10 - 8)*10^-6/(8.854*10^-12) = 7.45*10^5 Wbc). flux = (q2+q3 -q6)/(8.854*10^-12) = ( 10 + 1 - 9)*10^-6/(8.854*10^-12) = 2.25*10^5 Wb
d)flux = (q4-q5)/(8.854*10^-12) = (8-8)/(8.854*10^-12) = 0
e) flux = (q1+q2+q3+q4 - q5 - q6)/(8.854*10^-12) = (4.6 + 10 + 1 + 8 - 8 - 9)*10^-6/(8.854*10^-12) = 7.45*10^5 Wb. Gauss's Law is a fundamental principle in physics, particularly in the study of electromagnetism. It states that the total electric flux through a closed surface is equal to the electric charge enclosed within the surface, divided by the permittivity of free space. Mathematically, it can be written as: Φ = ∫ E . dA = Q/ε. Where Φ is the electric flux, E is the electric field, dA is an infinitesimal surface element, Q is the total electric charge enclosed within the surface, and ε is the permittivity of free space.
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an adult helping her child learn to ride a bike, applies a net force of 6.17 newtons to the child on the bike for 4.00 seconds. how much momentum does the child and his bike gain after being pushed by the adult in kilogram-meters per second? round your final answer to two decimal places.
After being pushed by an adult, the child and his bike develop momentum at a rate of 24.68 Kg-m/s.
Describe momentum.momentum is the result of a particle's mass and velocity. Being a vector field, momentum includes both magnitude and the direction. As per Isaac Newton's second equation of motion, the force applied on the a particle is equal to the time change in momentum.
the solution is
given Net force F= 6.17 N
time t= 4.00 s
from Formula
Momentum = force × time
Momentum = 6.17 × 4 Kg-m/s
Momentum= 24.68 Kg-m/s
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if you double the force on an object but the distance remains the same, how much work is done on that object?
If you apply twice as much force to an item while keeping the distance the same, the quantity of effort is allegedly doubled.
What in science is a force?In science, the word "force" has a particular definition. Considering a forces a pull or just a pull is perfectly suitable at this level. Charges are not components that an object "would have in it" or "contains." A force is applied to one item by another.
Why do forces happen?Forces are generated by contacts between two or more objects. There is an equal and conflicting force acting on each individual on the other. External forces are what cause the item to move. This force has really no impact on the object's overall motion.
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what is the speed of the waves on the string what is the longest possible wavelength for a standing wave give the frequency of that wave
The wave speed on the string is 82.0m/s. The maximum wavelength for a standing wave is 16.8 m. That wave's frequency is 4.88Hz.
(a) V=[tex]\sqrt{\frac{T}{\mu} } =\sqrt{\frac{96}{\frac{0.12}{8.4} } }[/tex] = 82 m/sec
(b) for the lowest possible wavelength,
λ/2=l
λ=2l=2×8.4=16.8m
(c) V=fλ=v/λ=82/16.8=4.38Hz
the separation between the corresponding points of two successive waves is known as the wavelength. Two points or particles that are "corresponding points" are those that have finished the same fractions of their periodic motion and are in the same phase. Ordinarily, the wavelength of transverse waves—those with points vibrating perpendicular to the direction of their advance—is calculated from crest to crest or from trough to trough; for longitudinal waves—those with points vibrating parallel to the direction of their advance—the wavelength is calculated from compression to compression or from rarefaction to rarefaction. The Greek letter lambda () is commonly used to represent a wave's length. Wavelength is defined as the product of the speed (v) and frequency (f) of a wave train in a given medium.
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what is the maximum displacement after one time constant has elapsed in terms of the initial amplitude,
The highest deviation of the item from equilibrium, measured either in the positive or negative x-direction, is called the oscillation's amplitude, or A.
When the velocity reaches zero, the maximum displacement happens. (Why? You have the option of thinking physically or mathematically.) Additionally, the derivative of the velocity with respect to time is the acceleration. x(t) equals A cos(t + a).
The highest deviation of the item from equilibrium, measured either in the positive or negative x-direction, is called the oscillation's amplitude, or A. Repetitive harmonic motion is simple. The length of time (period T) required for an object to complete one oscillation and return to its initial position
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When a science teacher talks about a machine’s efficiency, what is she comparing?
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A. the useful energy put out by the machine and the energy put into the machine
B. the non-useful energy put out by the machine and the energy put into the machine
C. the thermal energy put out by the machine and the energy put into the machine
D. the non-useful energy put out by the machine and the useful energy put out by the machine
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Mechanics use a pulley to lift an engine out of a car. How could they make the pulley more efficient?
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A. clean and oil the pulley’s axle
B. use a longer rope or cable
C. raise the pulley’s wheel
D. lower the pulley’s wheel
(1) When a science teacher talks about a machine’s efficiency, she is comparing the useful energy put out by the machine and the energy put into the machine. (option A ).
(2) The pulley could be made more efficient by using a longer rope or cable. ( option B ).
What is efficiency of a machine?
The efficiency of a machine is defined as the ratio of output work to input work. Efficiency of a machine describes how a machine converts input energy or force into useful work or energy.
Mathematically, the formula for the efficiency of a machine is given as;
Eff = ( output force / input force ) x 100%
Eff = ( effort x distance moved by effort ) / ( load x distance moved by load ) x 100%
Thus, by increasing the distance travelled by the effort, the efficiency of the pulley or machine will be increased.
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based on the velocity change of each object, what did you infer about the direction of forces during a collision?
The direction of forces during a collision can be inferred grounded on the haste change of each object. The forces acting on the objects are equal in magnitude and contrary in direction in elastic collision. But on the other hand, the forces acting on the objects aren't equal in magnitude in inelastic collision and the direction of the forces is also towards the centre of mass.
What do you mean by collision?Collision means two objects coming into touch with each other for a veritably short period. It's a repaying commerce between two millions for a veritably short interval wherein the instigation and energy of the colliding millions change.
What's the difference between elastic andnon-elastic collision?A impeccably elastic collision is defined as a collision in which there's no loss of kinetic energy. An inelastic collision is one in which kinetic energy is changed to some other form of energy in the collision.
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Mg^12 O^8
-write down the electron structure
-Draw the atom
-write the molecule formula of the compound and give its name!
Answer:
Writing Electron Configurations. When writing an electron configuration, first write the energy level (the period), then the subshell to be filled and the superscript, which is the number of electrons in that subshell. The total number of electrons is the atomic number, Z