An indoor running track is 200 meters in length. During a 3,000-meter race, runners must complete 15 laps of the track. An electronic timing device records the amount of time it takes each runner to complete a lap for every lap in the race. These are called lap times. The histograms below display the lap times for both Stefano and Alex, runners in the 3,000-meter race.

2 histograms. A histogram titled Alex apostrophe s 3,000 meter race lap times has lap times (seconds) on the x-axis, and frequency on the y-axis. 35 to 36, 1; 36 to 37, 5; 37 to 38, 4; 38 to 39, 4; 39 to 40, 1. A histogram titled Stefano apostrophe s 3,000 meter race lap times has lap times (seconds) on the x-axis, and frequency on the y-axis. 32 to 33, 1; 34 to 35, 1; 36 to 37, 1; 37 to 38, 4; 38 to 39, 5; 39 to 40, 1; 40 to 41, 2.

Using the histograms, which of the following is a correct comparison?

Neither runner had a lap time between 35 and 36 seconds.
Alex’s lap times show less variability than Stefano’s lap times.
The median lap time for both runners is in the 38–39 interval.
Both runners’ highest number of lap times in the 37–38 interval.

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Answer:  [tex]\textsf{x}^2\textsf{ - 14x + 24}[/tex]

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Given:  [tex]\textsf{x = 12 and x = 2}[/tex]

Find: [tex]\textsf{Determine the quadratic equation}[/tex]

Solution:  In order to determine the quadratic equation we need to move the integers onto the side where x is and then distribute.

Move the integers

Create and expression and distribute

Therefore, after completing the steps we were able to determine that the quadratic equation that will have solutions of x = 12 and x = 2 is x^2 - 14x + 24.

Answer:

75 mm

Step-by-step explanation:

 To find the hypotenuse, use Pythagorean theorem

Hypotenuse² = base² + altitude²

                  c² = 21² + 72²

                      = 441 + 5184

                      = 5625

                 [tex]\sf c = \sqrt{5625}[/tex]

                    [tex]= \sqrt{75*75}\\\\\boxed{\bf c = 75 \ mm}[/tex]

Answer:

[tex]\sf C) \ x = -1\dfrac{2}{5} , \ y = \ 1\dfrac{3}{5}[/tex]

Given equations:

Make x the subject in equation 1:

Substitute this into equation 2:

2(y - 3) - 7y = -14

2y - 7y = -14 + 6

-5y = -8

  y = -8/-5

  y = 1.6

Then x = y - 3

           = 1.6 - 3

           = -1.4

Solution: (x, y) ⇒ (-1.4, 1.6)

The distributive property of multiplication over addition for rational numbers is (a) -3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

Which of the following is an example of distributive property of multiplication over addition for rational numbers

(a) -3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

(b) -3/4 × {2/3 + (-5/6)} = [3/4 × 2/3] - (-5/6)

(c) -3/4 × {2/3 + (-5/6)} = 2/3 + (-3/4) × -5/6

(d) -3/4 × {2/3 + (-5/6)} = {2/3 + (-5/6)} - 3/4

The distributive property of multiplication states that:

a * (b + c) = (a * b) + (a * c)

From the given question, we have:

-3/4 × {2/3 + (-5/6)}

This means that:

a = -3/4

b = 2/3

c = -5/6

Recall that a * (b + c) = (a * b) + (a * c)

So, we have:

-3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

Hence, the distributive property of multiplication over addition for rational numbers is (a) -3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

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when you subtract a negative number from any platitude number the equation changes to addition so you would add the value of the negative number to 1.

To subtract a negative number from one you will need to set it up like this

1- (-x) x equals the negative number you're talking about

so we use the method KCC (keep change change)

So we KEEP the positive one, CHANGE the subtraction sign in to a plus sign "+" then CHANGE the negative number to a positive

lets say the negative number is 2

1-(-2)

1+ (+2)

1+2 = 3

(a) The fraction of books that are fiction is 2/3.

(b) The fraction of books that are non-fiction is 1/3.

To find the fraction of fiction and non-fiction books on a bookshelf:

Given: A bookshelf has 96 books. 64 of the books are fiction and the rest are non-fiction books. (a)Fraction of fiction books =?

(b)Fraction of non-fiction books =?

Now,

As given, we have,

The total number of books on a bookshelf = 96

Out of 96, the total number of fiction books = 64

So,

The remaining number of books = non-fiction books = 96-64 = 32

(a) Fraction of fiction books = fiction books/total books

= 64/96

On simplification,

= 2/3

(b) Fraction of non-fiction books = non-fiction books/total books

= 32/96

= 1/3

Therefore, the fraction of fiction and non-fiction books is 2/3 and 1/3 respectively.

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Answer:

HI i no  answer of this quetion but what grade are in school

Answer:

Step-by-step explanation:

Answer:

b = 2

Step-by-step explanation:

using the tangent ratio in the right triangle and the exact value

tan30° = [tex]\frac{1}{\sqrt{3} }[/tex] , then

tan30° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{b}{a}[/tex] = [tex]\frac{b}{2\sqrt{3} }[/tex] = [tex]\frac{1}{\sqrt{3} }[/tex] ( cross- multiply )

b × [tex]\sqrt{3}[/tex] = 2[tex]\sqrt{3}[/tex] ( divide both sides by [tex]\sqrt{3}[/tex] )

b = 2

Answer:

Given that a = 2√3.

Let's find value of b...

[tex]\textsf {21 cm}[/tex]

[tex]\textsf {If it is correct to the nearest centimeter, then the least side length}\\\textsf {would be 8 - 1 = 7 cm. }[/tex]

[tex]\textsf {Then, the least possible perimeter would be :}[/tex]

[tex]\mathsf {7 \times 3}[/tex]

[tex]\textsf {21 cm}[/tex]

1.  m³

2. cm³

3. s³

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

1. Volume is measure in m³

2.  volume of a rectangular pencil case in cm³

3. V = s x s x s or s³

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Answer:

534

Step-by-step explanation:

The solution is in the image

Answer:15

Step-by-step explanation:

Start off using Java. As u progress you cant move over to C and the then transfer to python.

An expression is defined as a set of numbers, variables, and mathematical operations. The correct option is C.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Juanita’s salary once she completes 10 years, her salary will be increased to 3 times what she makes now plus $2,000. Now, if her salary is represented by s, then the expression that would represent her salary after 10 years is,

Salary after 10 years = 3s + 2000

Hence, the correct option is C.

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Answer:

C

Step-by-step explanation:

Answer:

{-3, 2, -5, 1, 6}

Step-by-step explanation:

The domain is the set of input values.

A function assigns the value of each element of one set to the other specific element of another set. The zeroes of the functions are -2, 1, and 3.

A function assigns the value of each element of one set to the other specific element of another set.

Given f(x) = (x - 1)(x + 2)(x − 3), therefore, the zeroes of the functions are -2, 1, and 3. The end behavior of the function is that if x approaches ∞ then f(x) approaches ∞, while if x approaches -∞ then f(x) approaches -∞, as can be observed from the given graph.

Hence, the zeroes of the functions are -2, 1, and 3.

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Answer:

−1, 2, −3; continues downward to the left and upward to the right

Step-by-step explanation:

Answer:

Hey there : y= 3x - 3

Answer:

y = [tex]\frac{3}{2}[/tex] x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line

m = [tex]\frac{3-0}{0-(-2)}[/tex] = [tex]\frac{3}{0+2}[/tex] = [tex]\frac{3}{2}[/tex]

the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = [tex]\frac{3}{2}[/tex] x + 3 ← equation of line

Answer:

x = ± [tex]\sqrt{2}[/tex] , x = ± i

Step-by-step explanation:

f(x) = [tex]x^{4}[/tex] - x² - 2

to find the zeros , equate f(x) to zero , that is

[tex]x^{4}[/tex] - x² - 2 = 0

using the substitution u = x² , then

u² - u - 2 = 0 ← in standard form

(u - 2)(u + 1) = 0 ← in factored form

equate each factor to zero and solve for u

u - 2 = 0 ⇒ u = 2

u + 1 = 0 ⇒ u = - 1

convert u back into terms of x

x² = 2 ( take square root of both sides )

x = ± [tex]\sqrt{2}[/tex]

x² = - 1 ( take square root of both sides )

x = ± [tex]\sqrt{-1}[/tex] = ± i

Answer: Positive or negative square root of 2, ±i

Proof o fvalidity is shown below.

Answer:

(-6)

Step-by-step explanation:

Integer subtraction:

If two numbers have different sign, subtract and the result will have the sign of the bigger number.

 8 - 14 = (-6)

Subtract 8 from 14 and the bigger number is 14 and sign of 14 is (-).

So, the answer is  (-6)

The table is a function and the relation f(x) = 5x + 14 has a greater value when x = 9

The table of values is given as:

Input (x) 2 5 9 12

Output (y) 20 15 12 8

In the above table of values, each x value have a unique y value.

This means that the table is a one-to-one relation

A one-to-one relation is a function

Hence, the table is a function.

The function is given as:

f(x) = 5x + 14

This gives

f(9) = 5 * 9 + 14

Evaluate

f(9) = 59

From the table, we have:

y = 12 when x = 9

Hence, the relation f(x) = 5x + 14 has a greater value when x = 9

We have

f(x) = 5x + 14

This gives

5x + 14 = 64

Subtract 14 from both sides

5x = 50

Divide by 5

x = 10

Hence, the value of x when f(x) = 64 is 10

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A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.

"If the 2 is quantity use multiply it again"

NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).

"Problem has been solve"

(ノ^_^)ノ

[tex]\large\bold{SOLUTION} \\ [/tex]

GIVEN :-

FIND :-

By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .

[tex] \bold{Formula:}[/tex]

[tex] \qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}[/tex]

Now let's start solving :-

[tex] \quad \sf \implies{Area = Length \times Width} \\ [/tex]

[tex] \quad \sf \implies{Area = 12ft \times 4.2ft} \\ [/tex]

[tex] \quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}} \\ [/tex]

[tex] \quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}} \\ [/tex]

Therefore, the area of the space that needs to be covered is 100.80ft² .

[tex] \underline{ \rule{185pt}{3pt}}[/tex]

By defining and solving systems of equations, we will see that:

a) the fraction is 40/56

d) the fraction is 15/21.

We have the fraction 5/7 and we want to write it in different ways.

a) First we want to find a number a/b such that:

a/b = 5/7

a + b = 96

This is a little system of equations, to solve this, first we can rewrite the first equation as:

7a = 5b

Now we can isolate a on the second equation:

a = 96 - b

And replace that on the other equation:

7*(96 - b) = 5b

And now we can solve this for b.

672 - 7b = 5b

672 = 5b + 7b = 12b

672/12 = b = 56

And we know that:

a = 96 - b = 96 - 56 = 40

Then the fraction is 40/56

d) This time we want the denominator to be 9 less than twice the numerator.

in a/b, a is the numerator and b is the denominator.

So this time we have:

a/b = 5/7

b = 2a - 9

We can rewrite the first equation again:

7a = 5b

And then replace the other equation in the right side:

7a = 5*(2a - 9)

And now solve this for a.

7a = 10a - 45

45 = 10a - 7a = 3a

45/3 = a = 15.

And:

b = 2a - 9 = 2*15 - 9 = 21

Then the fraction is 15/21.

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Answer:

9,000 minutes (150 hours)

Step-by-step explanation:

You have 3,600 points total; you need to divide it by 2 points.
3,600 ÷ 2 = 1,800

So, now you need to multiply the 1,800 points by 5 minutes.

1,800 × 5 = 9,000

Another way:

You can figure out how long it takes to get 1 point. If 2 points takes 5 minutes, divide 5 by 2.

5 ÷ 2 = 2.5

Now you need to figure out how long it would take to get 3,600 points. If each point takes 2.5 minutes, just multiply.

3,600 × 2.5 = 9,000

It would take 9,000 minutes (which is equivalent to 150 hours) to get to 3,600 points.

One complete period of a non-transformed cotangent function is π.

The period of the function is defined as the interval after which the function value repeats itself.

For example, f(T+x)=f(x)

where T is the period of the function.

Here given that there is a non-transformed function cotangent function.

We have to find the period of the function in which interval the value of the function will repeat.

So for the function y=f(x)=cot x

the period of the function is π. means after π the value of the cotangent repeats.

cot(π+x)=cot x

Then one cycle of the cotangent graph lies between 0 and π.

Therefore One complete period of a non-transformed cotangent function is π.

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Step-by-step explanation:

1. let n=2, then, n+2= 2+2=4 so 2^2= 4 and 4^2=16 then 16-4=12 which is an even number

2. let n=4, the. n+3=4+3=7, and 4^2=16 and 7^2=49 then 49-16 =33 which is an odd number

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the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

To do this, we can think on the situation as a right triangle, where the hypotenuse is 4 miles, the angle that we look at measures 10.5°, and the change in elevation (let's call it x) will be the opposite cathetus to that angle.

Then we can use the relation:

Sin(a) = (opposite cathetus)/(hypotenuse)

Replacing what we know, we get:

sin(10.5°) = x/4mi

x = sin(10.5°)*4mi = 0.73mi

So the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

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Answer:  [tex]\textsf{y = -1/4x - 4}[/tex]

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Given: [tex]\textsf{Slope = -1/4, Point through = (4, -5)}[/tex]

Find:  [tex]\textsf{Equation for the line that passes through the given point}[/tex]

Solution: In order to get the equation, we need to first use the point-slope form to help us sort out our information and then we solve for y.

Plug in the values

Simplify and solve for y

Therefore, the final answer would be that the equation that has a slope of -1/4 and passes through (4, -5) is y = -1/4x - 4.