An object weighs 15 N in air and 13 N when submerged in mineral spirits, which has a density of 788 kg/m3. Determine the density of the object

Answer: talking about others

Answer:

unfortunately we have not received a reply to the park yet but

Explanation:

mohamedz and he had killed him

Answer:

no

Explanation:

because the heaver an object the harder it is to move s the force will not be able to move it

The work that is required to increase the speed to 16 knots is 14,176.47 Joules

If a catamaran with a mass of 5.44×10^3 kg is moving at 12 knots, hence;

5.44×10^3 kg = 12 knots

For an increased speed to 16knots, we will have:

x = 16knots

Divide both expressions

[tex]\frac{5.44 \times 10^3}{x} = \frac{12}{16}\\12x = 16 \times 5.44 \times 10^3\\x = 7.23\times 10^3kg\\[/tex]

To get the required work done, we will divide the mass by the speed of one knot to have:

[tex]w=\frac{7230}{0.51}\\w= 14,176.47Joules[/tex]

Hence the work that is required to increase the speed to 16 knots is 14,176.47 Joules

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Answer:  When we use an analogy that represents the expanding universe with the surface of an expanding balloon, what does the inside of the balloon represent? The inside of the balloon does not represent any part of our universe.

The conservation of momentum, Newton's second law and kinematics allows to find the result for the initial speed of the car is:

Given parameters

To find

The momentum is defined by the product of the mass and the velocity of the body, so it is a vector quantity. In the case of an isolated system the momentum is conserved.

In the attachment we see a diagram of the vehicle crash, let's write the moment for each axis.

y-axis

Initial instant. Before the shock.

          [tex]p_{oy}[/tex]  = M v₀₁

Final moment. After the crash

          [tex]p_{fy}[/tex] = (M + m) [tex]v_{fy}[/tex]

The system is formed by the two vehicles for which during the crash it is isolated and the momentum is conserved.

          [tex]p_{oy} = p_{fy} \\\\M v_{o1} = (M+m) v_{fy} \\v_{fy} = \frac{M}{M+m} \ v_{o1}[/tex]          

Calculate us

           [tex]v_{fy} = \frac{1200}{1200+750} \ 15[/tex]  

           vfx = 9.23 m / s

x-axis

Initial instant. Before the crash.

           p₀ₓ = m v₀₂

Final moment. After the crash.

           [tex]p_{fx}[/tex] = ​​(M + m) [tex]v_{fx}[/tex]  

The momentum is preserved.

          [tex]p_{ox}= p_{fx} \\m v_{o2) = (M+m) \ v_{fx}[/tex]  

Let's find the velocity just after the collision, let's use Newton's second law,

y-axis

        N-W = 0

        N = W = (M + m) g

x-axis

       fr = (M + m) a

The friction force is the macroscopic manifestation of the interactions between the two bodies.

       fr = μ N

We substitute.

       μ  g = a

Now we can use kinematics.

        v² = v₀² - 2a d

When the vehicles stop their speed is zero.

        v₀² = 2 a x

        v₀ = [tex]\sqrt{2\ \mu \ g \ d}[/tex]

Let's calculate.

       v₀ = [tex]\sqrt{2 \ 0.40 \ 9.8 25 }[/tex]  

       v₀ = 14 m / s

This is the speed of the two vehicles just after the collision, that is, let's use trigonometry to find their components.

          cos 25 = [tex]\frac{v_{ox}}{v_o}[/tex]  

          v₀ₓ = v₀ cos 25

          v₀ₓ = 14 cos 25

          v₀ₓ = 12.69 m / s

We substitute in the expression of the conservation of the momentum in the x-axis.

           m v₀₂ = (M + m) [tex]v_{fx}[/tex]  

           [tex]v_{o2} = \frac{M+m}{m} v_{fx}[/tex]  

Let's calculate.

           [tex]v_{o2} = \frac{1200+750}{750} \ 12.69[/tex]  

           vfy = 32.99 m / s = 40 m / s

In conclusion using the conservation of momentum, Newton's second law and kinematics we can find the result for the initial speed of the car is:

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Answer:

Explanation:

lThe mass of an object given only it's force and acceleration can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question

f = 195 N

a = 2.1 m/s

We have

[tex]m = \frac{195}{2.1 } = 92.857142... \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

we use : photometer to measure light intensity

:Anemometer to measure wind intensity

:Hygrometer to measure relative humidity

Answer:

157.5

Explanation:

X=vi *t + 0.5*a*t^2

vi=12, t=7, a=3

x= 12*7 + 0.5*3*7^2

= 84+ 73.5= 157.5 m

The distance between the mirror and your face is 39.5 cm

Using the mirror formula 2/r = 1/u + 1/v where r = radius of curvature = - 48.2 cm, u = distance between mirror and your face = object distance and v = distance between image and your face = - 61.8 cm. The distances are negative since the image is in front of the mirror and distances to the left of the mirror are negative.

So, making u subject of the formula, we have

2/r = 1/u + 1/v

1/u = 2/r - 1/v

1/u = (2v - r)/rv

u = rv/(2v - r)

Substituting the values of the variables into the equation, wse have

u = -48.2 cm × -61.8 cm/(2 × -61.8 cm - (-48.2 cm))

u = 2978.76 cm²/(-123.6 cm + 48.2 cm)

u = 2978.76 cm²/-75.4 cm

u = -39.51 cm

u ≅ -39.5 cm (The distance is negative since it is in front of the mirror)

So, the distance between the mirror and your face is 39.5 cm

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Answer:

A centripetal force

Explanation:

The type of force in the given scenario is tension. The correct option is c.

Tension is defined in physics as the pulling force conveyed axially by a string, cable, loop, or similar material, or by every end of a rod, truss member, or similar three-dimensional object.

Tension can also be defined as the action-reaction pair of forces acting at each end of said elements.

Newton's second law states that the tension in the rope must equal the weight of the backed mass.

Tension, the normal force, and friction are all examples of contact forces.

Since the weight is not moving, the acceleration is zero. Even if the acceleration is not zero, this equals zero.

Thus, the correct option is c.

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Your question seems incomplete, the missing options are:

The sag in the tensioned cable depends on the weight of the cable and

the applied tension.

Reasons:

The given parameters are;

Height of the towers are; h₁ = 40 m and h₂ = 30 m

Horizontal distance between the towers, l = 300 m

The tension in the conductor, T = 1,590 kg

Weight of the conductor, w = 0.8 kg/m

Required:

The clearance space of the conductor mid-way between the support

Solution:

The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;

[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]

Where;

h = h₂ - h₁ = 40 m - 30 m = 10 m

Which gives;

[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]

The sag at the lowest point is give by the formula;

[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]

Therefore;

[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]

The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m

The distance of the midpoint from the lowest point, x, is therefore;

[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]

Which gives;

[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]

The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34

The clearance midway between the support ≈ 29.34 m

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Answer:

time

Explanation:

power = work done ÷ time

Answer:

4.3 m/s^2

Explanation:

a = vf - vi / t

26 - 20 / 1.4

= 4.28 ( round your numbers)

Given,

Force = 10,000 N

Distance = 30 m

Time = 40 s

Work done = force × distance

Work = 10,000 × 30

Work = 300,000 J

______

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

The work done on the object is equal to the power it experiences which is equal to 735 watts.

Work done is defined as the product of force applied and the distance over which the force is applied on the object. Work is done on an object when a force is applied to an object and the object is moved through a particular distance.

The time rate of doing work is called as power, which is designated by the symbol P. It is measured in the units of watts, where one watt is equal to one joule energy applied per second time.

Work done on an object is equal to the force (F) multiplied by the distance d in the direction of the force. Where, time interval is Δt.

P = W/Δt = F × d/Δt = m × g × h/Δt = 100 × 9.8 × 30 / 40

Power = 735 watts

The power of the object is 735 watts.

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Answer: It was on between 7 and 7.30 and also between 8 and 8.30 (when the line on the graph goes up only). So it was on for an hour or 60 minutes

Hi there!

We can use impulse for this situation:

I = Δp = mΔv

Impulse = Force × time, so:

I = 63.9(24) = 1533.6 Ns

Find force by dividing by time:

I/t = 1533.6/1.2 = 1278 N

Answer:

i dont know this one

Explanation:

sorry i wish i could help but if u look closley on that qyestion you will understand it mor

Answer:

im half new how does this work

Explanation:

Answer:Werner Heisenberg was born on 5th December, 1901, at Wurzburg. He was the son of Dr. August Heisenberg and his wife Annie Wecklein. His father later became Professor of the Middle and Modern Greek languages in the University of Munich. It was probably due to his influence that Heisenberg remarked, when the Japanese physicist Yukawa discovered the particle now known as the meson and the term “mesotron” was proposed for it, that the Greek word “mesos” has no “tr” in it, with the result that the name “mesotron” was changed to “meson”.Heisenberg went to the Maximilian school at Munich until 1920, when he went to the University of Munich to study physics under Sommerfeld, Wien, Pringsheim, and Rosenthal. During the winter of 1922-1923 he went to Göttingen to study physics under Max Born, Franck, and Hilbert. In 1923 he took his Ph.D. at the University of Munich and then became Assistant to Max Born at the University of Göttingen, and in 1924 he gained the venia legendi at that University.From 1924 until 1925 he worked, with a Rockefeller Grant, with Nlels Bohr, at the University of Copenhagen, returning for the summer of 1925 to Göttingen.In 1926 he was appointed Lecturer in Theoretical Physics at the University of Copenhagen under Nlels Bohr and in 1927, when he was only 26, he was appointed Professor of Theoretical Physics at the University of Leipzig.In 1929 he went on a lecture tour to the United States, Japan, and India.In 1941 he was appointed Professor of Physics at the University of Berlin and Director of the Kaiser Wilhelm Institute for Physics there.At the end of the Second World War he, and other German physicists, were taken prisoner by American troops and sent to England, but in 1946 he returned to Germany and reorganized, with his colleagues, the Institute for Physics at Göttingen. This Institute was, in 1948, renamed the Max Planck Institute for Physics.In 1948 Heisenberg stayed for some months in Cambridge, England, to give lectures, and in 1950 and 1954 he was invited to lecture in the United States. In the winter of 1955-1956 he gave the Gifford Lectures at the University of St. Andrews, Scotland, these lectures being subsequently published as a book.During 1955 Heisenberg was occupied with preparations for the removal of the Max Planck Institute for Physics to Munich. Still Director of this Institute, he went with it to Munich and in 1958 he was appointed Professor of Physics in the University of Munich. His Institute was then renamed the Max Planck Institute for Physics and Astrophysics.

Answer:

5m/s ez

Explanation:

plz make me brainliest

The change in position of an object is known as motion. Force is external that causes a body to change its position

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Answer:

In short terms. the 1N block at rest will stay still and the 1N block with 2N applied will move forward.

The minimum force required to start this block moving is 370 N.

The given parameters;

The minimum force required to start this block moving is calculated as follows;

[tex]F= \mu_s F_n[/tex]

where;

[tex]F_n[/tex] is the normal force on the block which is equal to the weight of the block

[tex]F= \mu_s F_n \\\\F= \mu_s W\\\\F = 0.74 \times 500 \\\\F= 370 \ N[/tex]

Thus, the minimum force required to start this block moving is 370 N.

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Answer:

it is It will maintain its state of motion. because of newtons law states that any object in morion will stay in motion unless acted upon another force pushing against it

Explanation:

Answer:

It will maintain its state of motion.

Explanation:

Answer:

willie tower

Explanation:

mataas kasi

Answer:

5.25MJ

Explanation:

Considering the weight of the skydiver constant over the descent -ie, the acceleration of gravity not decreasing as you go up the earth surfice, the work is simply the product of the two:

[tex]w= \vec F\cdot \vec x = Fx = 1050\times 5000 = 5,250,000 = 5.25MJ[/tex]