Analyze the effects on a passenger riding in a car traveling at
50 km/h that collides head-on with a solid object.

Answer: greater than

Explanation:

The ideal gas equation and the pressure in barometer allows us to find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:

Pressure is defined by the relationship between force and area.

       P = F / A

The ideal gas equation establishes a relationship between pressure, volume, and temperature of an ideal gas.

          PV = nR T

Where P is pressure, V is volume, and T is temperature.

Let's write this equation for two points assuming that the temperature has not changed.

          P₀ V₀ = P₁ V₁

          V₁ = [tex]\frac{P_o}{P_1} \ V_o[/tex]                 (1)

The subscript "o" is used for the start point and the subscript "1" for the end point.

The pressure in a barometer is:

         P = ρ g y

They indicate the initial height of the barometer y₀=75 cm, the distance from empty space y'₀ = 9 cm and the final height of the barometer y₁ = 59 cm.

The volume of the cylinder is

         V = π r² y

Let's calculate the initial volume.

         V₀ = π 1 9

         V₀ = 28.27 cm³

We substitute in equation 1.

         V₁ = [tex]\frac{\rho \ g \ y_o}{\rho \ g \ y_1} \ V_o[/tex]  

         V₁ = [tex]\frac{y_o}{y_1} \ V_o[/tex]  

Let's calculate.

        V₁ = [tex]\frac{75}{59} \ 27.27[/tex]  

        V₁ = 35.94 cm³

The volume to be incremented is

         ΔV = V₁ - V₀

         ΔV = 35.94 - 28.27

         ΔV = 7.67 cm³

Using the ideal gas equation and the pressure in barometer we can find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:

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The tension in the string pulling the box is most nearly 17 N.

The given parameters;

The tension on the string is calculated by applying Newton's second law of motion as follows.

[tex]\Sigma F = ma[/tex]

at constant speed, acceleration, a, = 0

[tex]\Sigma F = 0\\\\T_x - \mu F_n = 0\\\\Tcos(\theta) - \mu F_n = 0\\\\Tcos(\theta)= \mu F_n\\\\T = \frac{\mu F_n}{cos(\theta)} \\\\T = \frac{0.3 \times 5 \times 9.8}{cos(30)} \\\\T = 16.97 \ N\\\\T \approx 17 \ N[/tex]

Thus, the tension in the string pulling the box is most nearly 17 N.

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The distance between the mirror and your face is 39.5 cm

Using the mirror formula 2/r = 1/u + 1/v where r = radius of curvature = - 48.2 cm, u = distance between mirror and your face = object distance and v = distance between image and your face = - 61.8 cm. The distances are negative since the image is in front of the mirror and distances to the left of the mirror are negative.

So, making u subject of the formula, we have

2/r = 1/u + 1/v

1/u = 2/r - 1/v

1/u = (2v - r)/rv

u = rv/(2v - r)

Substituting the values of the variables into the equation, wse have

u = -48.2 cm × -61.8 cm/(2 × -61.8 cm - (-48.2 cm))

u = 2978.76 cm²/(-123.6 cm + 48.2 cm)

u = 2978.76 cm²/-75.4 cm

u = -39.51 cm

u ≅ -39.5 cm (The distance is negative since it is in front of the mirror)

So, the distance between the mirror and your face is 39.5 cm

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Answer:

we use : photometer to measure light intensity

:Anemometer to measure wind intensity

:Hygrometer to measure relative humidity

Answer:

Drums, harps, recorders, and bagpipes.

Explanation:

The velocity at the bottom of the swing is [tex]\mathbf{v= \sqrt{2gh -2gd}}[/tex]. The time it took the child to reach the river is 0.62 seconds.

The objective of this question is to determine:

At the bottom of the swing, there is an equal change in both the Kinetic energy as well as the potential energy and the expression can be computed as:

[tex]\mathbf{\dfrac{1}{2}mv^2 = mg (h -d)}[/tex]

[tex]\mathbf{\dfrac{v^2}{2}= g (h -d)}[/tex]

[tex]\mathbf{v^2= 2gh -2gd}[/tex]

[tex]\mathbf{v= \sqrt{2gh -2gd}}[/tex]

According to the second equation of motion;

[tex]\mathbf{S = ut +\dfrac{1}{2}at^2}[/tex]

where;

∴

[tex]\mathbf{1.9 = 0(t) +\dfrac{1}{2}(9.8) t^2}[/tex]

[tex]\mathbf{1.9 = \dfrac{1}{2}(9.8) t^2}[/tex]

[tex]\mathbf{t^2 =\dfrac{1.9\times 2}{9.8} }}[/tex]

[tex]\mathbf{t = \sqrt{\dfrac{1.9\times2}{9.8}}}[/tex]

[tex]\mathbf{t =0.62 \ s}[/tex]

Therefore, we can conclude that the velocity at the bottom of the swing is [tex]\mathbf{v= \sqrt{2gh -2gd}}[/tex]. The time it took the child to reach the river is 0.62 seconds.

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The first resonant position below the open end of the resonance tube is; one-quarter of the wavelength

In the event of the first resonant position in a resonance tube, there will be a maximum air displacement which is only one antinode right at the open end where the motion is constrained.

However, there will be no displacement at the closed end which means another one node right at the closed end where air is halted.

This means that the standing wave will have one-quarter of the wavelength in the test tube.

Thus;

L = ¼λ

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Given,

Force = 10,000 N

Distance = 30 m

Time = 40 s

Work done = force × distance

Work = 10,000 × 30

Work = 300,000 J

______

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

The work done on the object is equal to the power it experiences which is equal to 735 watts.

Work done is defined as the product of force applied and the distance over which the force is applied on the object. Work is done on an object when a force is applied to an object and the object is moved through a particular distance.

The time rate of doing work is called as power, which is designated by the symbol P. It is measured in the units of watts, where one watt is equal to one joule energy applied per second time.

Work done on an object is equal to the force (F) multiplied by the distance d in the direction of the force. Where, time interval is Δt.

P = W/Δt = F × d/Δt = m × g × h/Δt = 100 × 9.8 × 30 / 40

Power = 735 watts

The power of the object is 735 watts.

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The vectors point along the axis of rotation with a direction determined by an arrow.

There are two types of physical quantity one is a scaler and another one is a vector.

The quantity that requires only megnitude to define is known as the scalar quantity. While the vector quantities need both megnitude and the direction to define.

The vector quantity is represented by an arrow. The vectors point along the axis of rotation with a direction determined by an arrow.

The angular quantities L, omega, and alpha are vector quantities.

Hence arrow is the correct answer for the blank.

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The direction of the vectors of angular momentum and L, angular velocity omega and the mass alpha is determined using the right hand rule.

Righthand rule in physics states that, when we curl our right hand fingers, the direction of the angular momentum and velocity will be in the direction of thumb and curl of fingers determine the axis of rotation.

Angular momentum is a vector quantity defined as the product of moment of inertia and angular velocity where, the angular velocity ω is the rotational analogue of linear velocity i.e.. product of the linear velocity and radius of rotational path.

Therefore, the angular quantities L, angular velocity ω along the axis of rotation can be determined using the right hand rule. Where direction of thump represents the direction of vector components.

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Hi there!

We can use impulse for this situation:

I = Δp = mΔv

Impulse = Force × time, so:

I = 63.9(24) = 1533.6 Ns

Find force by dividing by time:

I/t = 1533.6/1.2 = 1278 N

Answer:How did family life under Prince Shotoku’s rule reflect Confucian ideals?

Women had rights and were equal to their husbands.

Children were taught to value individualism over community.

People were expected to give up worldly concerns and turn to nature.

Households were structured to maintain order, with the husband as head.

Explanation:

Given what we know about the Kepler space program, we know that the astronomers discovered that Earth-sized planets are more common than we imagined.

Kepler was launched with the intention of getting a closer look at other planets outside of our solar system using enhanced photometrics.

The idea behind this launch was to discover more Earth-sized planets, preferably within the habitable zone of their central star.

What this mission showed astronomers, is that Earth-sized planets are more common than we could have imagined, Kepler proved this by finding over 2,662 planets to date.

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Answer:

Explanation:

lThe mass of an object given only it's force and acceleration can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question

f = 195 N

a = 2.1 m/s

We have

[tex]m = \frac{195}{2.1 } = 92.857142... \\ [/tex]

We have the final answer as

Hope this helps you

Yes.

Because the mass would be measured in kilograms ( given units) 2 is two times greater than 1, so it would have twice the mass

Answer:

yes the 2 kg rock would be twice the size as a 1 kg rock

we can observe its gravitational influence on visible matter.

Dark matter is a term used in astrophysics to refer to matter that corresponds to approximately 80% of the matter in the universe.

Dark matter is related to the motion of galaxies because visible matter makes up only a small part of the cluster and the galaxies show signs of being composed mainly of a halo of dark matter concentrated in their center.

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Answer:

willie tower

Explanation:

mataas kasi

Answer:  When we use an analogy that represents the expanding universe with the surface of an expanding balloon, what does the inside of the balloon represent? The inside of the balloon does not represent any part of our universe.

Answer:

480

Explanation:

resistance equals to potential difference divide by electric current

120÷0.25

=480

Answer:

[tex]\mathsf {480 \Omega}[/tex]

Explanation:

[tex]\textsf {Formula used for calculating resistance :}[/tex]

[tex]\mathsf {Resistance = \frac{Voltage}{Current} }[/tex]

[tex]\textsf {This is otherwise known as Ohm's Law, hence the unit of resistance.}\\[/tex]

[tex]\textsf {Solving :}[/tex]

[tex]\implies \mathsf {R = \frac{120}{0.25}}[/tex]

[tex]\implies \mathsf {R = 480\Omega}[/tex]

[tex]\textsf{If the fan uses higher current at higher speeds, then}\\\textsf{the resistance would decrease as it is inversely}\\\textsf {proportional to the current.}[/tex]

Answer:

5m/s ez

Explanation:

plz make me brainliest

Answer:

time

Explanation:

power = work done ÷ time

The sag in the tensioned cable depends on the weight of the cable and

the applied tension.

Reasons:

The given parameters are;

Height of the towers are; h₁ = 40 m and h₂ = 30 m

Horizontal distance between the towers, l = 300 m

The tension in the conductor, T = 1,590 kg

Weight of the conductor, w = 0.8 kg/m

Required:

The clearance space of the conductor mid-way between the support

Solution:

The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;

[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]

Where;

h = h₂ - h₁ = 40 m - 30 m = 10 m

Which gives;

[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]

The sag at the lowest point is give by the formula;

[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]

Therefore;

[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]

The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m

The distance of the midpoint from the lowest point, x, is therefore;

[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]

Which gives;

[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]

The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34

The clearance midway between the support ≈ 29.34 m

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When light reflects from a surface, there is a change in its intensity. Thus, the correct option is C.

Light intensity is also known as luminous intensity. It is the amount of light which is falling on a surface over any given square foot or square meter in size. Light intensity can be measured in terms of lumens per square foot (foot candles) or lumens per square meter (lux).

Light intensity is affected by various factors such as surface on which the light rays strike, the medium, reflection, and the refraction of light.

When a ray of light reflects from a surface, there is a change in the intensity of light and also the speed of light in that medium.

Therefore, the correct option is C.

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Your question is incomplete, most probably the complete question is:

When light reflects from a surface, there is a change in its:

a. frequency

b. velocity

c. intensity

d. phase

Answer:

it is It will maintain its state of motion. because of newtons law states that any object in morion will stay in motion unless acted upon another force pushing against it

Explanation:

Answer:

It will maintain its state of motion.

Explanation:

Answer:

157.5

Explanation:

X=vi *t + 0.5*a*t^2

vi=12, t=7, a=3

x= 12*7 + 0.5*3*7^2

= 84+ 73.5= 157.5 m

An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.

An escalator used to lift people up from one floor to another, exerts a work (w) of 1.2 MJ in 1 minute (t).

In physics, power (P) is the amount of energy (w) transferred or converted per unit time (t).

[tex]P = \frac{w}{t} = \frac{1.2 \times 10^{6} J }{1min} = 1.2 \times 10^{6} W[/tex]

We can convert 1.2 × 10⁶ W to kW using the conversion factor 1 kW = 1000 W.

[tex]1.2 \times 10^{6} W \times \frac{1kW}{1000W} = 1200kW[/tex]

An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.

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Answer:

no

Explanation:

because the heaver an object the harder it is to move s the force will not be able to move it

Answer:

i dont know this one

Explanation:

sorry i wish i could help but if u look closley on that qyestion you will understand it mor