Area codes are the first three digits of a 10-digit telephone number. The first digit of an area code cannot be 0 or 1.

a. How many area codes can be created if digits are allowed to be repeated?

b. How many area codes can be created if digits are not allowed to be repeated?

Answer:

..D).... x = 8..

Step-by-step explanation:

..x = 8..

Hi there!

[tex]\large\boxed{log_b3b = 1.8397}[/tex]

Keep in mind the following log property:

logₓab = logₓa + logₓb

Thus:

[tex]log_{b}3b = log_{b}3 + log_{b}b\\\\[/tex]

We know the value of log_b3, and a log with the same values for the base equals 1. Thus:

[tex]log_b3b = 0.8397 + 1 = 1.8397[/tex]

Answer:

y = 30

Step-by-step explanation:

Substitute x = 5 into the equation and solve for y

4(5) - y = - 10

20 - y = - 10 ( subtract 20 from both sides )

- y = - 30 ( multiply both sides by - 1 )

y = 30

Then (5, 30 ) is a solution of the equation

Answer:

0.92 to nearest 100th.

Step-by-step explanation:

cos T  = adjacent side / hypotenuse

= 12/13

= 0.9231

Answer:

19 is the answer i think.

Answer:

-9.705

Step-by-step explanation:

f-g+(-2)

Let  f = -3.005 and g = 4.7

-3.005 -4.7 -2

-9.705

Answer:

a) 3.5 cm / month

b y = 3.5(x-1) + 4, x >= 1

Step-by-step explanation:

the plant grew 32-4 = 28 cm in 9-1 = 8 months.

so, the growth rate is 28 cm / 8 months = 7 cm / 2 months, or (to norm it to a typical 1 unit denominator) 3.5 cm per month.

x = months of growth

y = height of plant

so, considering the "start" of 4 cm after one month, the equation is

y = 3.5(x-1) + 4, x >= 1

since we don't know anything about anything that happened before the first month was over, we cannot validate this equation for anything x<1.

Answer: x = 52

Step-by-step explanation:

You'd first deal with the 4 outside the parentheses, multiplying 10x-20 by 4. This would result in 40x - 80 = 200.

You'd then further isolate x, adding 80 on both sides, resulting in 40x = 2080. Divide by 40 on both sides and You'd get your answer of x = 52.

Answer:

q = -4   q=2

Step-by-step explanation:

q²+2q-8=0​

Factor

What 2 numbers multiply to -8 and add to 2

4*-2 = -8

4-2 = 2

(q+4)(q-2) =0

Using the zero product property

q+4 = 0  q-2 =0

q = -4   q=2

Answer:

192

Step-by-step explanation:

According to Euclidian theorem

x^2 = 144*(400-144)

x^2 = 144*256

x^2 = 36864 find the root of both

x = 192

Respuesta:

A.) BA = 12 m

Explicación paso a paso:

Usando triángulos similares:

BA / AC = DE / EC

BA = x; AC = 20; DE = 3; EC = 5

POR ESO ; TENEMOS :

x / 20 = 3/5

Multiplicar en cruz:

5 * x = 20 * 3

5 veces = 60

5x / 5 = 60/5

x = 12

Answer:

answer to that is A 1.75 per pint

Step-by-step explanation:

Against the wind, the wind works against the speed. With the wind, the wind aids the speed.

4(p - w) = 2416

4(p + w) = 2896

p - w = 604

p + w = 724

2p = 1328

p = 664 mph

664 + w = 724

w = 60 mph

Answer:

[tex]a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}[/tex]

By expanding the expression, we get;

[tex]\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}[/tex]

Collecting like terms gives;

[tex]\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

(b) The given expression is presented as follows;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4[/tex]

Therefore, we get;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}[/tex]

Collecting like terms gives;

[tex]x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )[/tex]

[tex]x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Answer:

2688 cm³

Step-by-step explanation:

2058×704/539 = 2688 cm³

Answer:

you would receive 12.5% of the discount

Step-by-step explanation:

20% off of 62.50 is 50; so you would pay $50

The sides of the image and pre-image are congruent

Each point has moved the same number of units

Answer:

50.24

Step-by-step explanation:

A = Area

Radius = 4 (The radius is half of the diameter

Diameter = 8

Pie = 3.14

A = (pie)r^2

A = (3.14)4^2

A = (3.14)16

A = 50.24

Answer:

.

.

.❥︎ᴀᴀɴᴋʜ ᴜᴛʜɪ ᴍᴏʜᴀʙʙᴀᴛ ɴᴇ ᴀɴɢᴅᴀɪ ʟɪ ,

.ᴅɪʟ ᴋᴀ sᴀᴜᴅᴀ ʜᴜᴀ ᴄʜᴀɴᴅɴɪ ʀᴀᴀᴛ ᴍᴇ ❣︎

.

.

Answer:

b the answer

Step-by-step explanation:

Answer/Step-by-step explanation:

✔️Volume of right cylinder = πr²h

Where,

π = 3.14

radius (r) = 4 cm

height (h) = 3 cm

Plug in the values into the formula

Volume of cylinder = 3.14*4²*3

= 150.72 cu cm

✔️Volume of cone = ⅓πr²h

Where,

π = 3.14

radius (r) = 5 cm

height (h) = 12 cm

Plug in the values into the formula

Volume of cylinder = ⅓*3.14*5²*12

= 314 cu cm

✔️Volume of pyramid = ⅓*Bh

Where,

Base area (B) = 16 cm²

height (h) = 30 cm

Substitute

Volume of pyramid = ⅓*16*30

= 160 cu cm

✔️Volume of square pyramid = ⅓*s²*h

Where,

Length of square base (s) = 3 cm

Height (h) = 16 cm

Substitute

Volume of square pyramid = ⅓*3²*16

= 48 cu cm

Answer:

X=

Step-by-step explanation:

x-1= 4x+3x+x-8

x-1 = 8x-8

shift places

8-1= 8x-x

7x = 7

X=7/7

X=1

I think so

please mark this answer as brainlist

Answer:

4 TOPPING WITH 5 CENTS LEFT

Step-by-step explanation:

A AND B ARE CORRECT ok so $6.50 to spend take out $3 for the cost of a plain hamburger which would leave you with $3.50 to spend on toppings alone so

3.5-0.75=2.75 (1 topping

2.75-0.75=2 (2 topping

2-0.75=1.25 (3 topping

1.25-0.75=0.5 (4 topping

there for you can get 4 toppings with 5 cents left over

Answer:

37degrees

Step-by-step explanation:

In order to get the required angle, we will use the SOH, CAH, TOA identity.

Let;

Adjacent = 60m

Opposite = 45m

According to TOA:

tan theta = opp/adj

tan theta = 45/60

tan theta = 0.75

theta = arctan 0.75

theta =  36.86

Hence the  angle, to the  nearest degree, between her path and the longest side of the playground is 37degrees

Answer:

C

Step-by-step explanation:

We are given that:

[tex]\displaystyle \sin y^\circ = \frac{s}{8}\text{ and } \tan y^\circ = \frac{s}{t}[/tex]

And we want to find the value of:

[tex]\displaystyle \sec y^\circ[/tex]

Recall that tan(θ) = sin(θ) / cos(θ). Since sec(θ) = 1 / cos(θ), tan(θ) = sin(θ)sec(θ). Substitute:

[tex]\displaystyle \sin y^\circ \sec y^\circ = \frac{s}{t}[/tex]

Substitute:

[tex]\displaystyle \frac{s}{8}\sec y^\circ =\frac{s}{t}[/tex]

Solve for secant:

[tex]\displaystyle \sec y^\circ = \frac{8}{t}[/tex]

Hence, our answer is C.

Answer:

c. sec y° = 8/t

Step-by-step explanation:

I took the test

Answer:

12 lemons

Step-by-step explanation:

CP of 15 lemon = ₹ 1

Profit = 25 %

SP of 15 lemons = [tex]\frac{100+profit}{100}*CP[/tex]

    [tex]= \frac{125}{100}*1\\\\= \frac{5}{4}[/tex]

SP of 15 lemons =  ₹  [tex]\frac{5}{4}[/tex]

Number of lemon for  ₹  [tex]\frac{5}{4}[/tex]  = 15

Number of lemons for  ₹  1 = 15 ÷ [tex]\frac{5}{4}[/tex]

                                            [tex]= 15 *\frac{4}{5}\\\\= 3*4\\\\= 12[/tex]