assume that y varies inversely with x. If y= 1.6 when x= 0.5, find x when y= 3.2

The function g(x) = ∛(x -3) is positive at the interval x > 3

Given g(x) = ∛(x -3), on what interval is the function positive?

The function is given as:

g(x) = ∛(x -3)

Set the radicand to positive

x - 3 > 0

Add 3 to both sides

x > 3

Hence, the function is positive at the interval x > 3

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Answer:

is it 1 ques or 4 different questions?

Answer:

175000 km

Step-by-step explanation:

the 1:25000 essentially means that every centimeter represents 25000 kilometers. so the answer is 175000 by multiplying 7 and 25000

An equation is formed of two equal expressions. The given equation is not true.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The complete question is: Check whether the given equation is true or not?cos2pi/7+cos4pi/7+cos8pi/7=1/8.

To know if the given equation, [tex]cos\dfrac{2\pi}{7}+cos\dfrac{4\pi}{7}+cos\dfrac{8\pi}{7}=\dfrac18[/tex] is true or not, both the sides of the equation are needed to be solved separately.

The value of [tex]cos\dfrac{2\pi}{7}+cos\dfrac{4\pi}{7}+cos\dfrac{8\pi}{7}[/tex] when simplified is equal to -0.5, or the value can be written as -(1/2).

Since the right side of the equation is equal to -1/2, while the right side of the equation is 1/8. Thus, the given equation is not true.

Hence, the given equation is not true.

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Step-by-step explanation:

please mark me as brainlest

Answer:

-92/35

Step-by-step explanation:

-3 + 4/7 - 1/5 =

-21/7 + 4/7 - 1/5 =

-(21*5) / (7*5) + (4*5)/(7*5) - (1*7)/(5*7) =

-105/35 + 20/35 - 7/35 =

-105+20-7 / 35 = -92/35

The midpoint of the class interval 80-89 is 84.5.

The mid point of a class interval is also called the class mark of the class interval.

The midpoint is defined as the average of the upper and lower class limits.

Therefore, the midpoint of the class interval 80-89 can be calculated as follows:

mid point = 80 + 89 / 2

mid point = 169 / 2

mid point = 84.5

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Answer:

You have not added a picture soi can not help answer this question.

Step-by-step explanation:

Add the picture by either taking a photo or screenshot of the question then upload it.

Answer:

search it up ok that's all you can do

∠ROQ and ∠TOS are vertically opposite angles, so must be equal, which means they are 122°

Answer:

14 will be the answer...

Step-by-step explanation:

6 13/28 = 6

8 3/32 = 8

6 + 8 = 14

The coordinates for the center and length of the radius of this circle are equal to (½, 1), 2 units.

Mathematically, the standard form of the equation of a circle is given by;

(x - h)² + (y - k)² = r²

Where:

In order to determine the coordinates for the center and the length of the radius of this circle, we would use completing the square method:

x² + y² - x - 2y - 11/4 = 0

x² - x + ¼ + y² - 2y = 11/4 + ¼

(x - ½)² + y² - 2y + 1 = 12/4 + 1

(x - ½)² + (y - 1)² = 4

Comparing with the standard form, we have:

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Complete Question:

A circle is defined by the equation given below.

x^2 + y^2 − x − 2y − 11/4 = 0

What are the coordinates for the center of the circle and the length of the radius?

========================================================

Work Shown:

x = number of quarters

3x = number of dimes

0.25x = value of just the quarters, in dollars

0.10(3x) = 0.30x = value of just the dimes, in dollars

0.25x+0.30x = 0.55x = total value in dollars

0.55x = 9.35

x = (9.35)/(0.55)

x = 17

Alison has 17 quarters and 3x = 3*17 = 51 dimes

17 quarters = 17*0.25 = $4.25

51 dimes = 51*0.10 = $5.10

17 quarters + 51 dimes = $4.25 + $5.10 = $9.35

The answers are confirmed.

The true statement is Peter walks at a rate of 13 over 4 miles per hour.

Direct variation is when two variables move in the same direction. If one variable increases, the other variable increases. When the hour Peter walks increases, the distance he walks also increases.

Here are the options:

Peter walks at a rate of StartFraction 4 over 13 EndFraction miles per hour.

Peter walks at a rate of 4 miles per hour.

Peter walks at a rate of StartFraction 13 over 4 EndFraction miles per hour.

Peter walks at a rate of 13 miles per hour.

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Answer:

I think it's C. transitive property of equality

We need to prove

[tex]\frac{\tan A+\sin A}{\tan A-\sin A}=\frac{\sec A+1}{\sec A-1}[/tex]

[tex]\text{LHS}=\frac{\tan A+\sin A}{\tan A-\sin A}\\\\=\frac{\frac{\sin A}{\cos A}+\sin A}{\frac{\sin A}{\cos A}-\sin A}\\\\=\frac{\sin A+\sin A \cos A}{\sin A-\sin A \cos A}\\\\=\frac{\sin A(1+\cos A)}{\sin A(1-\cos A)}\\\\=\frac{1+\cos A}{1-\cos A}\\\\=\frac{1+\frac{1}{\sec A}}{1-\frac{1}{\sec A}}\\\\=\frac{\sec A+1}{\sec A-1}\\\\ =\text{RHS}[/tex]

Answer: Coordinates: (1,3) length RS: 3 length RT: 2 ST: 3.6

Step-by-step explanation:

a^2+b^2=c^2

3^2+2^2=c^2

9+4=c^2

13=c^2

3.6=c

Answer:

the angles of a triangle always equal 180 so

34+x-5+4y=180

simplify

29+x+4y=180

-29

x+4y=151

-4y

x=-4y+151

then put this into the original equation

29-4y+151+4y=180

simplify

29+151=180

so this proves that this works

-1/4x-151=y

Hope This Helps!!!

Answer:

Should have ended with "at most -15, not "at least -15."

Step-by-step explanation:

[tex]\leq[/tex] -15 means less than or equal to -15

So it can be -15, but also anything less than -15.  The phrase "at most -15, not "at least -15" says exactly that.

Answer:

x<2 or x ≥ 15/2

Step-by-step explanation:

The inequality which represents the situation is; |x - 7| < 20 and the solution is; 27 > x > -13.

Since the number is less than 20 units away from.the number 7 on the number line, it follows.from interpretation that the inequality is;

|x - 7| < 20

Hence; x-7 < 20; x < 27

Or

-x + 7 < 20

-x < 13

x > -13

Hence, the solution of the inequality is; 27 > x > -13.

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Answer:

B. (4,2)

Step-by-step explanation:

The answer is where the lines intersect.

Hope this helps!

If not, I am sorry.

Answer:

(4,2)

Step-by-step explanation:

the solution is where both lines intersect. We would write the point as (x,y). That’s why the answer is (4,2) not (2,4)

Answer: 35.675

Step-by-step explanation:

10.465−(−25.21)

The opposite of −25.21 is 25.21.

10.465+25.21

Add 10.465 and 25.21 to get 35.675.

35.675

Answer:

c is the answer.

Answer:

[tex]\log_8{(3)} + \log_8{(7)}[/tex]

Step-by-step explanation:

Product Rule for Logarithms

[tex]\log_b{(mn)} = \log_b{(m)} + \log_b{(n)}[/tex]

Instead of 21 you can write 3 · 7, because 21 = 3 · 7.

[tex]\log_8{(21)} = \\= \log_8{(3 \cdot 7)} =\\= \log_8{(3)} + \log_8{(7)}[/tex]

Answer:

Domain & Range are both all real numbers.

Step-by-step explanation:

i

If this was a traditional parabola, the range would be y<=4. However, the arrow on the left going back up means eventually y will go to both positive & negative infinity.

Answer:

opotion has not correct answer

answer is 15.

Answer:

[tex]3^\frac{7}{10}[/tex]    or      [tex]\sqrt[10]{3^7}[/tex]

Step-by-step explanation:

[tex]\left(\sqrt{3}\right)\left(\sqrt[5]{3}\right)=\sqrt[10]{3^7}\quad[/tex]

(√3)([tex]\sqrt[5]{3}[/tex]) = √3 · [tex]\sqrt[5]{3}[/tex]

{√3 = [tex]3^{\frac{1}{2}}[/tex]}                 {radical rule: [tex]\sqrt{x}=x^1^/^2[/tex]}

[tex]\sqrt3[/tex][tex]\sqrt[5]{3}[/tex] =  [tex]3^{\frac{1}{2}}[/tex] · [tex]\sqrt[5]{3}[/tex]

{[tex]\sqrt[5]{3}[/tex] = [tex]3^{\frac{1}{5}}[/tex]}                  {radical rule: [tex]\sqrt[n]{x} = x^1^/^n[/tex]}

 [tex]3^{\frac{1}{2}}[/tex] · [tex]\sqrt[5]{3}[/tex] =   [tex]3^{\frac{1}{2}}[/tex] · [tex]3^{\frac{1}{5}}[/tex]     {exponent rule:  [tex]a^x*a^y=a^x^+^y[/tex]}

                (1/2 + 1/5 = 5/10 + 2/10 = 7/10)

              [tex]=3^\frac{7}{10}[/tex]        {opposite of radical rule: [tex]\sqrt[n]{x} = x^1^/^n[/tex] ;  [tex]x^\frac{a}{b}=\sqrt[b]{x^a}[/tex]}

             = [tex]\sqrt[10]{3^7}[/tex]

so, the simplified version of this equation can either be written as:

[tex]3^\frac{7}{10}[/tex]    or      [tex]\sqrt[10]{3^7}[/tex]

hope this helps!!

(I can't clearly see the last option, but if it's either of these, then it's correct)

Step-by-step explanation:

well you can distribute the sqrt(15x) to the (√3x + √5) and then combine the radicals using the product property of radicals: [tex]\sqrt[n]{a} * \sqrt[n]{b} = \sqrt[n]{ab}[/tex].

[tex](\sqrt{3x} + \sqrt{5})\sqrt{15x} + 2\sqrt{30}\\(\sqrt{3x} * \sqrt{15x}) + (\sqrt{5} * \sqrt{15x}) + 2\sqrt{30}\\\sqrt{45x^2} + \sqrt{75x} + 2\sqrt{30}\\[/tex]

Now we can simplify the radicals using the same property we used to combine them but instead of combining into one radical we'll separate them into two radicals where one of the radicals simplifies into a number without a radical

[tex](\sqrt{9} * \sqrt{x^2} * \sqrt{5}) + (\sqrt{25} * \sqrt{3x}) + 2\sqrt{30}\\3x\sqrt{5} + 5\sqrt{3x} + 2\sqrt{30}[/tex]