In order for the camera to follow the motion of the athlete, it must rotate at an angular velocity of approximately 1.74 rad/s.
We assume that the athlete has a non-zero size, then we can estimate the radius of the athlete's body as follows. Let's say the athlete has a height of 1.8 meters and a width of 0.5 meters. Then, we can estimate the radius of the athlete's body as the average of the height and width, or:
r = (1.8 m + 0.5 m) / 2 = 1.15 m
Using this value of r, we can calculate the angular velocity of the camera as:
ω = v / r
= 2 m/s / 1.15 m
≈ 1.74 rad/s
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What's the frequency of AC ( alternating current ) ?
The frequency of alternating current (AC) is the number of times the current changes direction per second. It is measured in hertz (Hz).
In most parts of the world, the frequency of alternating current (AC) is 50 Hz, meaning that the current changes direction 50 times per second. However, in some parts of the world, such as the United States and Canada, the frequency of AC is 60 Hz. This means that the current changes direction 60 times per second. It is important to note that the frequency of AC is determined by the power source, and cannot be changed by the user.
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. (3 points) the analog cathode ray oscilloscope described in the lab manual is related to the digital oscilloscope used in the lab in the same way that a 1950s era television is related to what device?
The analog cathode ray oscilloscope in the lab manual is related to the digital oscilloscope used in the lab in the same way that 1950s era television is related to modern flat-screen television.
What is meant by a cathode ray oscilloscope?Analog cathode ray oscilloscope and the 1950s era television are older technologies that use cathode ray tube (CRT) to display images or waveforms.
They operate by deflecting an electron beam on a phosphorescent screen to create visual display. And, in contrast, digital oscilloscope and modern flat-screen televisions use digital processing and display technologies to provide more precise and flexible visual representations.
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A balloon is inflated with helium at a constant pressure that is 4.3 × 105 Pa in excess of atmospheric pressure. If the balloon inflates from a volume of 1.8 × 10−4 m3 to 9.5 × 10−4 m3, how much work is done on the surrounding air by the helium-filled balloon during this expansion?
Answer: W = 331.1 J
Explanation:
W = pdv
= (4.3 x 10^5 Pa) (9.5 × 10−4 m3 - 1.8 × 10−4 m3)
W = 331.1 J or 3.3 x 10^2 J
The work done on the surrounding air by the helium-filled balloon during this expansion is 331.1 J.
What is meant by pressure-volume work?Pressure-volume work is defined as the work that a fluid does when it is compressed or expanded by an external force factor.
Here,
Pressure of the helium gas, P = 4.3 x 10⁵Pa
Initial volume of the helium gas, V₁ = 1.8 x 10⁻⁴m³
Final volume of the helium gas, V₂ = 9.5 x 10⁻⁴m³
The expression for the pressure-volume work is given by,
Work done, W = PΔV
where ΔV is the change in volume of the helium gas.
Therefore,
W = P(V₂ - V₁)
W = 4.3 x 10⁵(9.5 x 10⁻⁴- 1.8 x 10⁻⁴)
W = 4.3 x 10⁵x 7.7 x 10⁻⁴
W = 331.1 J
Hence,
The work done on the surrounding air by the helium-filled balloon during this expansion is 331.1 J.
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What is the change of GPE for a 8.0 kg object which is lowered from an initial height of 10 m above the floor to a final height of 4.0 m above the floor?
The change in gravitational potential energy, GPE for the 8 Kg object which is lowered from a height of 10 m to 4 m is -470.4 J
How do I determine the change in potential energy of the object?We'll begin by obtaining the initial potential energy. Details below:
Mass of object (m) = 8 KgInitial height (h₁) = 10 mAcceleration due to gravity (g) = 9.8 m/s² Initial potential energy (PE₁) = ?PE₁ = mgh₁
PE = 8 × 9.8 × 10
PE = 784 J
Next, we shall determine the final potential energy. Details below:
Mass of object (m) = 8 KgInitial height (h₂) = 4 mAcceleration due to gravity (g) = 9.8 m/s² Final potential energy (PE₂) = ?PE₂ = mgh₂
PE = 8 × 9.8 × 4
PE = 313.6 J
Finally, we shall determine the change in the potential energy. This is shown below:
Initial potential energy (PE₁) = 784 JFinal potential energy (PE₂) = 313.6 JChange in potential energy (ΔPE) =?ΔPE = PE₂ - PE₁
ΔPE = 784 - 313.6
ΔPE = -470.4 J
Thus, the change in potential energy is -470.4 J
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comets tend to be ________ than asteroids, and it is estimated that there are far ___________ large comets than large asteroids.A. Crust and MantleB. Faster and MoreC. Hydrogen and HeliumD. Change in climate and core
"Comets tend to be faster than asteroids, and it is estimated that there are far more large comets than large asteroids." Correct option is B.
As comets typically originate from farther out than asteroids do, they move at faster speeds when they cross Earth's orbit: An asteroid would need to be larger than 10 kilometres in diameter, whereas a comet would only need to be about 7 kilometres in diameter to hit Earth with enough energy to form Chicxulub crater.
Two factors that differentiate a comet from an asteroid are shape of the orbit and chemical composition.
There are asteroids that are spherical, curved, and even have satellites. A comet circles the Sun similarly to an asteroid, but unlike an asteroid, it is made of ice and dust. Therefore, a comet's ice and dust composition begin to vaporise as it approaches the Sun. Consequently, a comet looks fuzzy and/or has a tail when viewed through a telescope.
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1. A student measures the mass of a solution before and after a chemical reaction takes place. In both cases the student measures the mass to be 50.25 g on an electronic balance with an uncertainty of 0.05 g. The student realizes that the ranges of uncertainty for each measurement overlap exactly. Which claim can the student make?(a) The mass definitely stayed the same because the ranges of uncertainty overlap exactly.(b) We can't know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainity overlap.(c) The mass definitely stayed the same because the measurement of 50.25 g was obtained each time.2. In the previous question you learned that a measurement system can be accurate but not precise, precise but not accurate, neither, or both. If an equipment contains a systematic error, then increasing the sample size will in general:(a) improve both accuracy and precision.(b) have no effect on either accuracy and precision.(c) improve accuracy but will not increase precision.(d) increase precision but will not improve accuracy.3. The cloth tape measure that you use to measure the length of an object had been stretched out from years of use. As a result, all of your length measurements were too small. How could you compensate for the incorrect results of using the stretched out tape measure?(a) There is no way to compensate for the incorrect result.(b) This is due to systematic error. Assuming that a new tape is more accurate, compare the stretched tape to a new tape to see how much the measurements are off. This difference will tell you how much to correct each original length measurement causing the systematic error to be minimized.(c) This is due to random error. Take more measurements until you get enough data to average and reduce the error.(d) This stretch is due to random error, so it can be ignored.
a) The claim student can make is - We can't know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainity overlap.
b) increasing the sample size will in general - increase precision but will not improve accuracy.
c) incorrect results of using the stretched out tape measure- This is due to systematic error. Assuming that a new tape is more accurate, compare the stretched tape to a new tape to see how much the measurements are off. This difference will tell you how much to correct each original length measurement causing the systematic error to be minimized.
a) Since the pupil used the same electronic balance with an query of0.05 g to weigh the mass of the result ahead and later, we can say that the millions are the same within the query of the balance.
b) Precision is the degree to which unborn measures yield the same results. delicacy, on the other hand, is a measure of how nearly the results agree with a true value. By adding the sample size the standard error is dropped meaning that unborn measures will probably fall near to the average. However, also taking further measures won't address this error and ameliorate delicacy as each dimension will be" off" by the same quantum from the true value, If methodical error is present. rather the methodical error needs to be removed, if possible, and this will ameliorate delicacy.
c) The stretching of the tape recording measure introduces a methodical error which could be corrected by comparing the tape recording with a different tape recording( essence or new). Once the pupil knows how important each dimension is out, the pupil can acclimate the original measures consequently. Performing further measures simply reduces the arbitrary error caused by the person reading the scale and won't affect the delicacy of the dimension.
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An object 0.1 m tall is placed 0.4 m from a convex mirror with a focal length of 0.3 m. What is the height of the image?
Answer: no exact answer
=
Explanation:
vision is blurred if the head is vibrated at 29 hz because the vibrations are resonant with the natural frequency of the eyeball held by the musculature in its socket.
There is some scientific evidence to suggest that vibration at certain frequencies can affect visual perception, but the claim that vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball held by the musculature in its socket is not entirely accurate.
What is Eyeball resonance and vision?According to the concept of "eyeball resonance," the eyeball can vibrate at specific frequencies as a result of the tension in the muscles around it, and these vibrations can affect vision. Generally speaking, the natural frequency of the eyeball is thought to be around 20 Hz, however this frequency can change based on a number of variables, including the eyeball's flexibility and the tension of the optic nerve.
There is some evidence to support the idea that being exposed to vibration at particular frequencies can alter vision. For instance, some researchers have discovered that participants who are exposed to 25 Hz vibration may have a reduction in visual acuity, while other studies have found that those who are exposed to 10 Hz vibration may experience an increase in improve visual perception in some people.
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Read the list of sentences from the article.
1 In a physical change, the material involved is structurally the same
before and after the change.
2 A piece of metal may be heated in a fire until it glows, but the metal is
the same material before heating and after cooling.
3 Chemical changes require the breaking and forming of chemical bonds
during a chemical reaction.
4 The creation of a new, solid substance from two liquid substances
indicates that a reaction has taken place that has altered the original
substances.
Which two sentences, taken together, provide the BEST evidence to support the idea
that both physical and chemical changes can significantly change the appearance of a
substance?
(A) 1 and 3
(B) 1 and 4
(C) 2 and 3
(D) 2 and 4
The best evidence that a substance's appearance can be significantly altered by both chemical and physical changes is the combination of examples 1 and 3.
Option A is correct.
What exactly is a change in the body?A substance undergoes a change in its physical characteristics when it undergoes a physical change. Most of the time, a physical change can be reversed. In the course of such a transformation, no chemical substance is produced.
What are two examples of physical and chemical changes?Chemical changes include processes like burning, frying, rusting, and rotting. The processes of melting, freezing, shredding, and boiling are all examples of physical modifications. The majority of physical symptoms can be reversed with enough energy.
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Two large, charged plates with charge density ±30µC/m^2 face each other with a separation of 5.0 mm. The negative plate is grounded, and defined as 0 potential. Find the electric potential at a location 8.0mm from the negative plate, 3.0mm from the positive plate!
V=3.39×10⁶ ×d for 0≤d≤0.005 m, 7.73x10⁷ m/s is the electric potential at a location 8.0mm from the negative plate, 3.0mm from the positive plate
a. Identify the unknown:
The potential everywhere
List the Knowns:
Charge density of the two plates: σ = ±30×10⁻⁶ C/m²
Distance between the two plates: d=5×10⁻³ m
Permittivity of free space: ε₀=8.85×10⁻¹² C²/N⋅m²
Set Up the Problem:
Since the σ are equal and opposite, this means that in the region outside of the two plates, the electric fields cancel each other out to zero: E = 0 The electric field between the plates is this strong:
E = σ/ε₀ = 30×10⁻⁶/8.85×10⁻¹² = 3.39x10⁶N/C
Possible variations between the positive plate and the negative plate include:
ΔV=Ed=3.39×10⁶ ×0.005=1.7×10⁴ V
Assuming the negatively charged plate is at the origin (d=0) and has no potential, the electric field is directed away from the positively charged plate and towards the negatively charged plate, the positive plate is at (d=+0.005 m) and have 1.7×10⁴ V
Solve the Problem:
V=0 for d<0
V=3.39×10⁶×d for 0≤d≤0.005 m
V=1.7×10⁴ V for d>0.005m
b. Identify the unknown:
when an electron leaves a state of rest at the negative plate and strikes the positive plate, how quickly it moves
List the Knowns:
Electron charge: e=1.6×10⁻¹⁹ C
Electron mass: m=9.11×10⁻³¹ kg
Set Up the Problem:
Potential and electric potential energy have the following relationships: = U/q
U=qV
To move the drop, this potential energy is converted to kinetic energy:
1/2mv²=qV
v = √2qV/m
Solve the Problem:
v = √(2×1.6×10⁻¹⁹×1.7×10⁴/9.11×10⁻³¹) = 7.73x10⁷ m/s
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Which statement best describes wavelengths of sunlight that are longer than 700 nanometers? These wavelengths form the infrared part of the spectrum. These wavelengths form the ultraviolet light of the spectrum. These wavelengths are shorter than the wavelengths of visible light These wavelengths are part of the visible light spectrum
Answer:
The statement "These wavelengths form the infrared part of the spectrum." best describes wavelengths of sunlight that are longer than 700 nanometers. Infrared light is a type of electromagnetic radiation with longer wavelengths than visible light, but shorter wavelengths than radio waves. It is typically defined as having wavelengths between 700 nanometers and 1 millimeter.
g if the other charges are fixed in place and charge 2q is allowed to move, what will be the kinetic energy k2q of charge 2q when it is very far from the other charges?
A particle with a mass of m/2 and a charge of 2q has kinetic energy of 2K when it is propelled from rest by the same potential difference.
Due to the fact that mass has no impact on kinetic energy, W = K = QV. where,
charge = Q, q
V = potential difference
k = kinetic energy
m = mass
The kinetic energy of a particle with a 2q charge and a v potential difference is given by the equation K = Q V,
where,
K₁ = Q₁V₁
K¹ = 2Q¹ x V¹ = 2(QV).
Due to K = QV, K1 = 2K is obtained by substituting K = QV into 2(QV).
Applying the equation E = (k)(q/r²), If q becomes 2q and r becomes 2r, When an electric charge is present in a specific region of space, its properties are altered and an electric field is generated. The term electric field refers to the physical field that surrounds electrically charged particles and acts to either attract or repel other charged particles in the field.
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Is the rate-limiting step the slowest?
It is not important to the rate-limiting step in a chemical reaction how much energy is released or used. Instead, the slowest step among all the steps that take place in a specific chemical reaction is referred to as the rate-limiting step.
What is the rate-limiting step?One of the fundamental steps in a multistep reaction mechanism moves along much more slowly than the others. The slowest step is the one that limits or determines rate.
This is because the phase that moves slowly needs more time to complete because it may entail numerous other processes.
As an illustration, a reactant would need to diffuse or migrate to a certain reaction site before another reaction can occur, which then immediately creates a product.
Therefore, A reaction can only move through its slowest phase; as a result, the rate-determining step restricts the rate of the entire reaction.
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What is the velocity of a skater who is 10 kg, and has a Kinetic energy of 10000 Joules?
Answer:
44.7 meter per second
Explanation:
The formula to find velocity is
V = (2 · KE / m)^1/2
V = velocity
KE = Kinetic energy
m = mass
Let's calculate
(2 · 10000 / 10) ^1/2 = 44.7 meter per second
the energy loss over a ball valve (1/3 closed) has been calculated as 240 j/kg. what is the volumetric average fluid velocity (m/s) through the valve?
The volumetric average fluid velocity (m/s) through the valve of ball valve having energy loss as 240 j/kg is 15.5 m/s.
When energy is converted from one form to another, or moved from one place to another, or from one system to another there's energy loss. This means that when energy is converted to a different form, some of the input energy is turned into a largely disordered form of energy, like heat.
Flow rate is the volume of fluid per unit time flowing past a point through the area A. Then the shadowed cylinder of fluid flows once point P in a invariant pipe in time t. The volume of the cylinder is announcement and the average haste is v =d / t so that the inflow rate is Q = announcement/ t = Av.
Energy loss is given as 240 J/kg
So to find the volumetric average velocity we have,
Energy loss = 1/2 V² J/kg
240 = 1/2 V² J/kg
V = [tex]\sqrt{240}[/tex]
V = 15.49 ≈ 15.5 m/s
Therefore, the volumetric average fluid velocity is V = 15.49 ≈ 15.5 m/s.
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at the instant the traffic light turns green, an automobile starts with a constant acceleration of 2.70 m/s2. at the same instant a truck, traveling with a constant speed of 11.30 m/s, overtakes and passes the automobile. (a) how far beyond the traffic signal will the automobile overtake the truck?
The traffic signal will the automobile overtake the truck far away beyond the traffic signal is 2.7 m.
The difference between haste and relative haste is that haste is measured with respect to a reference point which is relative to a different point. While relative haste is measured in a frame where an object is either at rest or moving with respect to the absolute frame.
The relative haste is defined as the haste of an object with respect to another bystander.
It's the time rate of change of relative position of one object with respect to another object.
W.r.t automobile,
u = ut - ua at t=0
= 11.3 - 0
= 11.3 m/s
d = dt - da
= 0 - 2.7 = -2.7m/s²
So, s = ut + 1/2at²
= 11.3(t) - 2.7/2 at²
0 = 11.3t - 2.7/2 t²
= 11.3t - 1.35 t²
11.3t = 1.35t²
t = 11.3/1.35
t = 8.37 sec
They will overtake again at 8.37 s
v = 11.3 m/s and st = vx1 = 11.3 m
both truck and car would travelled 11.3 m
Speed of automobile,
v = u + at
= 0 + 2.7(1)
= 2.7 m/s
Speed of the automobile is : 2.7 m/s
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If you apply is 400 N pushing 20 - KG sled what is the acceleration ? solve the following problems
If you apply is 400 N pushing 20 - KG sled. The acceleration is 20 m/s².
What is acceleration?Acceleration is a vehicle's capacity to gain speed within a short time. The acceleration of an object is equal to the net force exerted on it divided by its mass, or a = F m, in accordance with Newton's second rule of motion.
When an item's mass and the net force acting on it are known, the acceleration of that object can be calculated using this equation for acceleration.
Acceleration = force/mass
Force = 400 N
Mass = 20 kg
400 / 20 = 20 m/s²
Therefore, the acceleration is 20 m/s².
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determine the vertical rise h of the load w during 10 seconds if the hoisting drum draws in cable at the constant rate of 180 mm/s.
The vertical rise of the load during 10 seconds is approximately 490.5 meters.
What is uniformly accelerated motion?Uniformly accelerated motion is a type of motion in which an object moves along a straight line with a constant acceleration. This means that the object's velocity changes at a constant rate over time, with equal changes in velocity occurring during equal time intervals.
We can use the kinematic equation for uniformly accelerated motion to determine the vertical rise of the load:
h = vit + (1/2)at²
where:
h is the vertical rise of the load (in meters)
vi is the initial vertical velocity of the load (in meters per second)
a is the vertical acceleration of the load (in meters per second squared)
t is the time interval (in seconds)
Since the load is being hoisted upward, its initial vertical velocity is zero, so vi = 0. The vertical acceleration of the load is equal to the acceleration due to gravity, which is approximately 9.81 m/s².
To use this equation, we need to convert the constant rate of cable draw, 180 mm/s, to meters per second:
180 mm/s = 0.18 m/s
Now we can plug in the values:
h = (0 m/s)(10 s) + (1/2)(9.81 m/s²)(10 s)²
h = 490.5 meters
Therefore, the vertical rise of the load during 10 seconds is approximately 490.5 meters.
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If a meteor with a 20 m in diameter impacts Earth on land, approximately how big will the crater be?A. 200-400 m in diameterB. 300-500 m in diameterC. 400-600 m in diameterD. 500-700 m in diameter
If a meteor with a 20 m in diameter impacts Earth on land, approximately the crater will be 200-400m in diameter long.
The size of the crater created by a meteorite impact depends on several factors, such as the composition of the meteorite and the density of the material it impacts. Generally speaking, a 20 m in diameter meteorite would create a crater with a diameter between 200 and 400m. A few meters to several hundred meters can make up the crater's depth. A crater will most likely be created at the point of impact when a meteor impacts a planet. The size of the crater will increase as the object moves faster and becomes larger or heavier. The biggest predictors of impact crater size are the meteor's mass and velocity.
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four different pairs of transverse wave pulses are shown below. in each case the pulses are moving towards each other. at some point in time the pulses meet and interact (interfere) with each other. for which pair will the height of the combined (resultant) pulse be greatest at the center of the combined pulses, at the point where the centers of the pulses coincide?
The resultant pulse's amplitude is the sum of the amplitudes of the two original pulses. This might be two crests or two troughs colliding.
When two waves superimpose in opposite phase, the amplitude of the consequent is equal to the difference in amplitude of the component waves, resulting in the least amount of light intensity; this is known as destructive interference.
When two pulses travelling in opposite directions along a stretched string collide. Because both pulses cause the string to move higher as they travel, the net displacement of the string at that location is equal to the total of the pulse amplitudes. Because the two waves are travelling through the same medium, they have the same speed. The superposition total wave travels in the same direction and at the same speed as the two component waves, but its local amplitude is determined by whether the two individual waves have the same or opposite phase.
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Student 1: The speed of the block at its maximum height is zero because the kinetic energy is a minimum at the top of the trajectory. Student 2: Only the vertical component of the velocity is zero at the maximum height, because the vertical component of the acceleration is zero at the top of the trajectory.
It is true that the maximum speed of a block in a trajectory occurs at its maximum height, where the vertical component of the velocity is zero. This is due to the fact that at that point, the kinetic energy is minimized and the acceleration is zero. At this point, the block is at its highest point, and the velocity of the block is at its lowest. Therefore, the speed is zero at the top of the trajectory.
However, the horizontal component of the velocity is not zero at the maximum height. This is because the block is constantly subject to horizontal acceleration by gravity, even at its highest point. This means that the block has a nonzero velocity in the horizontal direction, even if it is at its maximum height. Therefore, the block is not at rest at the highest point; it is just moving horizontally at a constant speed.
How many of the chemicals created when tobacco burns are known to cause cancer?
A. About 30 B. About 50 C. About 70 D. About 90
Answer:
I think about 70.
Explanation:
I hope I helped
a given copper wire is 7.5m long and has a circular cross-section of diameter 0.5mm. calculate the resistance of this wire. calculate the resistance of a similar wire made of aluminum
The resistance of a similar wire made of aluminum is higher than the resistance of the copper wire. This is because aluminum has a higher resistivity than copper.
The resistance of a wire depends on its length, cross-sectional area, and the resistivity of the material it's made of. The resistivity of copper is [tex]1.68 x 10^-8 Ωm[/tex] , while the resistivity of aluminum is [tex]2.65 x 10^-8 Ωm.[/tex]
To calculate the resistance of the copper wire, we first need to calculate its cross-sectional area. The diameter of the wire is 0.5mm, so its radius is 0.25mm (or 0.00025m). The cross-sectional area of the wire is therefore:
[tex]A = πr^2 = π(0.00025)^2 = 1.96 x 10^-7 m^2[/tex]
The length of the wire is 7.5m. Therefore, the resistance of the copper wire is:
[tex]R = ρL/A = (1.68 x 10^-8 Ωm)(7.5m)/(1.96 x 10^-7 m^2) = 0.644 Ω[/tex]
To calculate the resistance of a similar wire made of aluminum, we can use the same formula but with the resistivity of aluminum. The diameter of the wire is the same, so its cross-sectional area is also the same. The length of the wire is also the same, so the resistance of the aluminum wire is:
[tex]R = ρL/A = (2.65 x 10^-8 Ωm)(7.5m)/(1.96 x 10^-7 m^2) = 0.819 Ω[/tex]
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a light-rail commuter train accelerates at a rate of 1.45 m/s2. how long (in s) does it take to reach its top speed of 80.0 km/h, starting from rest?
The time taken to reach the top speed of the 80 lm/ hours, starting from the rest is 55.17 seconds.
We have rate = 1.45 and final velocity is 80
The formula to find the acceleration is,
a = v - u/t
t = v-u/a
Where, u = initial velocity
v = final velocity
a = acceleration
t = time taken
so,
t = 80 - 0/1.45
= 80/1.45
= 55.17 seconds
Then v is the final haste, u is the original haste, a is the acceleration and t is the time interval during which a body is under acceleration.
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a 2 kg mass has 40 j of potential energy with respect to the ground. approximately how high is it above the ground?
The ground is chosen as a base for potential gravitational energy for the same reason. Compared to the gravitational potential at the center of the planet, the truth is that you even have gravitational potential energy.
What potential energy with respect to the ground?Ep = mgh. An object has the same amount of stored gravitational potential energy as the work required to raise it. The gravitational potential energy (PEg) that is added to or obtained by the object-Earth system is how we describe this.
The force acting on the two objects affects the formula for potential energy. P.E. = mgh is the formula for gravitational force, where m is mass in kilograms, g is acceleration due to gravity (9.8 m/s2 at the earth's surface), and h is height in meters.
M= 2kg
P.E = 40j
g=10N
H=?
Using formula [tex]P.E. = mgh[/tex]
40 = 2 * 10* H
Therefore, approximately 2 meters it is above the ground.
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which of the following actions does not affect the value of the capacitance of a parallel plate capacitor? multiple select question. halving the distance between the plates and sliding one plate such that the overlap between the plates is halved doubling the voltage difference between the plates and doubling the distance between them doubling the area of each plate and doubling the distance between them doubling the area of one of the plates while keeping the distance between them the same doubling the charge on each of the plates
The actions which does not affect the value of the capacitance of a parallel plate capacitor is doubling the voltage difference between the plates and doubling the distance between them.
A capacitor is a two-terminal electrical device that can store energy in the form of an electric charge. It consists of two electrical operators that are separated by a distance. The space between the operators may be filled by vacuum or with an separating material known as a dielectric. The capability of the capacitor to store charges is known as capacitance.
Capacitors store energy by holding piecemeal dyads of contrary charges. The simplest design for a capacitor is a resemblant plate, which consists of two essence plates with a gap between them. But, different types of capacitors are manufactured in numerous forms, styles, lengths, circumferences, and accoutrements .
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How does an object's speed affect its kinetic energy?
Answer: Object's speed affects the Kinetic Energy Quadratically.
Explanation: we have to know that Kinetic Energy is a scalar quantity, that is it doesn't have direction. Kinetic Energy of a moving body is totally dependent upon the body's mass and velocity of it.
The Kinetic Energy of a moving body having mass M and velocity V, then at a certain instant, the body's having Kinetic Energy is equal to:
Kinetic Energy (K.E.) = (MV²)/2
where:
M⇒ Body's mass
V ⇒Velocity of a moving body
It is so Clear that K.E. directly proportional to square of the body's velocity.
Therefore, Object's speed affects the Kinetic Energy Quadratically.
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23) if two equal charges, each of 1 c, were separated in air by a distance of 1 km, what would be the force between them?
So the force between the two charges would be 8.99 x 10^3 newtons.
define force ?
Force is a physical quantity that describes the interaction between objects or systems, causing a change in motion or deformation. It is typically measured in newtons (N) and is represented as a vector quantity with both magnitude and direction.
The force between two charges can be calculated using Coulomb's law:
F = kq1q2 / r^2
where k is Coulomb's constant (k = 8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges of the two objects, and r is the distance between them.
In this case, q1 = q2 = 1 C, and r = 1 km = 1000 m. Plugging these values into the equation, we get:
F = (8.99 x 10^9 N m^2/C^2) * (1 C) * (1 C) / (1000 m)^2
= 8.99 x 10^3 N
So the force between the two charges would be 8.99 x 10^3 newtons.
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ta student does an experiment to check the mass of a cart. the student sends a 1.0-kg cart with a spring attached at the front end into a collision with a cart of unknown mass. after the collision, the student notes that the 1.0-kg cart moves forward with reduced speed, and the unknown cart moves forward at a faster speed than the 1.0-kg cart. what does this experiment show about the mass of the unknown cart?
The experiment shows about the mass of the unknown cart is The unknown cart is less than 1 kg.
A change in velocity with respect to time is called acceleration. The speed of the cart and the amount of time it needs to accelerate down the plane are two crucial factors.
Keep in mind that the acceleration increases as the height of the slanted plane increases. This demonstrates how crucial it is to understand the inclined plane's height.
The necessity of the timer is based on the fact that we also need to know how long it takes the body to decelerate from the aircraft.
In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.
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A student conducts an investigation on a bar magnet with unlabeled poles. To determine which side of the magnet is north (N) or south (S), what steps can the student take?
A. The student can cut the bar magnet in half and observe the direction of the magnetic field on each individual piece.
B. The student can place the bar magnet near a nonmetal surface and observe the direction of the magnetic field on the surface.
C. The student can place the bar magnet near a metallic surface and observe the direction of the magnetic field on the surface.
D. The student can place the bar magnet near the known pole of a second magnet and observe the interaction between the poles.
The student can place the bar magnet near the known pole of a second magnet and observe the interaction between the poles.
option D.
How can the student determine the poles of the magnet?When two magnets are brought near each other, the direction of the magnetic field lines can be used to determine the orientation of the poles.
If the two magnets are brought near each other with the same poles facing each other (north-north or south-south), they will experience a repulsive force and will push away from each other.
On the other hand, if the magnets are brought near each other with opposite poles facing each other (north-south), they will experience an attractive force and will move towards each other.
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