Answer:
a) puck is subjected to both the forces of the hockey sticks in a horizontal direction,
b)the puck does not move since the sum of the forces is zero
c) changing the magnitude or direction of its applied force
Explanation:
a) The puck is subjected to both the forces of the hockey sticks in a horizontal direction, these forces are of equal magnitude and opposite direction since the puck is at rest.
In the direction of the y-axis (perpendicular to the ice) you have the weight of the disk and the normal to this weight that are also in equilibrium.
b) the puck does not move since the sum of the forces is zero, which implies that the forces of the hockey sticks are of equal magnitude and opposite direction.
c) the player has several ways to make the puck move
* slightly changing the angle of the club and therefore the direction of the force, in this case the disc comes out in the direction of this component
* inclined the stick slightly so that the force has a vertical component and the puck jumps in this direction
* Increasing the magnitude of the force so that the puck comes out in the opposite direction to the player
* The worst case, decreasing its force to zero and the disk comes out in its direction by the other force that had the same magnitude.
Find the power of a force F~ = (8 N)ˆı + (−4 N) ˆ if the velocity ~v = (−7 m/s)ˆı + (1 m/s) ˆ. Answer in units of W
Answer:
[tex]P=-60W[/tex]
Explanation:
From the question we are told that
Force of power [tex]F=8Ni+-4Nj[/tex]
Velocity of power [tex]V=-7m/si+1m/sj[/tex]
Generally the equation for power is mathematically represented as
[tex]Power=Force *Velocity[/tex]
[tex]P=F *V[/tex]
Generally the dot product of F and V is mathematically given as
[tex]P=[/tex] [tex]\begin{vmatrix}8 & -4\end{vmatrix} .[/tex][tex]\begin{vmatrix}-7 & 1\end{vmatrix}[/tex] [tex]=-56-4[/tex]
[tex]P=-60W[/tex]
Do this for alot of points
1. A complete fitness and exercise program should incorporate three basic components: Endurance (Aerobic), Flexibility, and Strength. Each of these components has specific guidelines, which govern their effectiveness
How many significant figures are in 20,000?
Answer:
4
Explanation:
a 4.0x 10^3 watt motor applies a force of 8.0 x 10^2 newtons to move a boat at constant speed. ow far does the boat move in 16 seconds
Answer:
80 m
Explanation:
From the question,
Power(P) = Force(F) × Velocity (V)
P = FV..................... Equation 1
V = P/F.................... Equation 2
Given: P = 4.0×10³ W, F = 8.0×10² N.
Substitute into equation 2
V = 4.0×10³/(8.0×10²)
V = 5 m/s.
Applying,
S = Vt............................ Equation 3
Where S = distance move by the boat, t = time.
Given: t = 16 s, V = 5 m/s
Substitute into equation 3
s = 16(5)
s = 80 m.
Hence the distance moved by the boat is 80 m
Abunai Hana is standing atop a hill and fires her crossbow perfectly horizontally. If the crossbow bolt begins
moving with a speed of 35 m/s, then at what height does the bolt land if it hits the ground 150 m horizontally
away from her?
Answer:
h = 90.09 m
Explanation:
First, we consider the horizontal motion of the crossbow. Considering air friction to be negligible we can use the following equation:
[tex]X = V_{x}t[/tex]
where,
X = horizontal distance covered = 150 m
Vₓ = Horizontal component of velocity = 35 m/s
t = time taken during the motion = ?
Therefore,
[tex]150\ m = (35\ m/s)t\\\\t = \frac{150\ m}{35\ m/s}\\\\t = 4.28\ s[/tex]
Now, we consider the vertical motion of the crossbow. Using second equation of motion:
[tex]h = V_{i}t + \frac{1}{2}gt^{2}\\\\[/tex]
where,
h = the height the bolt fell = ?
Vi = Vertical component of initial velocity = 0 m/s (since the crossbow was fired horizontally)
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]h = (0\ m/s)(4.28\ s) + \frac{1}{2}(9.81\ m/s^2)(4.28\ s)^{2}\\[/tex]
h = 90.09 m
What distance does a plate with an average speed of 1.95 cm/year move in 1000 years? help pls
Answer:
1950cm
Explanation:
You should multiply 1.95 cm by 1000. This will result in the answer.
At a certain location, wind is blowing steadily at 10 m/s. Determine the mechanical energy of air per unit mass and the power generation potential of a wind turbine with 90-m-diameter (D) blades at that location. Take the air density to be 1.25 kg/m3. The mechanical energy of air per unit mass is .05 Numeric ResponseEdit Unavailable. .05 correct.kJ/kg. The power generation potential of the wind turbine is
Answer:
[tex]X=3976.078202kW \approx 3976kW[/tex]
Explanation:
From the question we are told that
Wind speed[tex]V_w=10m/s[/tex]
Turbine blade diameter [tex]D=90m[/tex]
Air density [tex]\tau=1.25kg/m^3[/tex]
Mechanical energy [tex]K.E =0.05kJ/kg[/tex]
Generally the power generation potential of the wind turbine X is mathematically given as
[tex]X=m'*K.E[/tex]
Where
[tex]m'=\tau *\pi*D^2/4*V[/tex]
[tex]m'=1.25 *\pi*90^2/4*10[/tex]
[tex]m'=79521.56404kg/s \approx 79521.5kg/s[/tex]
Therefore
[tex]X=m'*K.E[/tex]
[tex]X=79521.56404*0.05[/tex]
[tex]X=3976.078202kW \approx 3976kW[/tex]
[tex]X=4.0MW[/tex]
PLEASE ANSWER 50 points
A car manufacturer wants to change its car’s design to increase the car’s acceleration. Which changes should the engineers consider making to the design?
O increase the force that the engine provides
O decrease the force that the engine provides
O increase the mass of the car
O decrease the mass of the car
O increase the top velocity the car can travel
O decrease the top velocity the car can travel
Which type of electromagnetic radiation is useful in communications
technology?
ANSWER : RADIO WAVES
Explanation:
radio wave: Electromagnetic radiation having a wavelength between about.5 centimeters and 30,000 meters; used for the broadcasting of radio and television signals.
Help!!
A stationary hockey puck has a mass of 0.18 kg. A hockey player uses her stick to apply a 11 N force over a distance of 0.56 m.
How much work does this force do on the puck?
A 20j
B 0.10j
C 2.0j
D 6.2j
E 34j
Answer:
6.2j
Explanation:
work done=force × displacement
wd=11N×0.56m
wd=6.16N/m~6.2j
6. What is the complete spectrum of all forms of light?
a. galaxy
b. electromagnetic spectrum
C. energy
d. system
Answer:
b. the electromagnetic spectrum
Explanation:
the electromagnetic spectrum contains all the forms of light, including gamma rays, x-rays, ultraviolet radiation, visible light, infrared, radio waves, microwaves, etc
electric heater carries a current of 18.0 A when operating at a voltage of 120 V. What is the resistance of the heater
Answer:
R = 6.67 ohms
Explanation:
Given that,
The current carried in the heater, I = 18 A
Voltage, V = 120 V
We need to find the resistance of the heater. Let the resistance be R.
We can use Ohm's law to find R.
V = IR
[tex]R=\dfrac{V}{I}\\\\R=\dfrac{120}{18}\\\\R=6.67\ \Omega[/tex]
So, the resistance of the heater is 6.67 ohms.
Blue ran 100 m south then 50 m north
all togather becomes 150 m
or 150 ×100cm = 15000cm
a railway train 100m long passes over a bridge 400m long at 20ms.1 how long will it take to pass over the bridge
Total length to be covered=400+100=500mts
time =distance/speed
=500/20
=25 sec
What is a push or pull that one object excerpts on another object?
Answer:
Force
Explanation:
a bag of cement is pulled along a horizontal plane by a constant force of 15n calculate the work done in moving the bag through a distance of 20m
Answer:
300J
Explanation:
Given parameters:
Constant force = 15N
Distance = 20m
Unknown:
Work done = ?
Solution:
Work done is the force applied to move a body through a particular distance.
Work done = Force x distance
So;
Work done = 15 x 20 = 300J
A student performs an experiment in which a 4kg object travels across a horizontal surface with an initial speed velocity of 6m/s and a 2kg object travels across a horizontal surface with an initial speed velocity of −3m/s. The objects travel toward each other and collide. Data collected from the experiment were used to create the velocity versus time graph shown that contains information about both objects before and after the collision. The positive direction is considered to be to the right. Which of the following statements are true regarding the data from the experiment?
A- Both objects always travel in the positive direction during the experiment.
B- Kinetic energy is conserved during the experiment.
C- The position of the center of mass of the system remains constant during the experiment.
D- The velocity of the center of mass of the two-object system remains constant during the experiment.
The position of the center of mass of the system remains constant during the experiment.
Conservation of linear momentumThe principle of conservation of linear momentum states that the total momentum of the system before after collision is always conserved for both elastic and inelastic collision.
[tex]m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\ \ (elastic)\\\\m_1 u_1 + m_2 u_2 = v(m_1 + m_2 ) \ (inelastic)[/tex]
Conservation of kinetic energyThe total kinetic energy of the system is conserved for perfectly elastic collision BUT not conserved for inelastic collision.
The center mass of the system
The center mass of the system is always constant.
Thus, the position of the center of mass of the system remains constant during the experiment.
Learn more about elastic and inelastic collision here: https://brainly.com/question/7694106
Which type of electromagnetic radiation is useful in communications
technology?
Answer:
radio waves
Explanation:
Radio waves are used for communication such as television and radio. Radio waves are transmitted easily through air. They do not cause damage if absorbed by the human body, and they can be reflected to change their direction. These properties make them ideal for communications.
Answer:
The answer is radio waves.
Explanation:
I took AP EX quiz.
1.
Which of the following best explains the
relationship between molecules and atoms?
A
Atoms are molecules that have a charge.
B
Atoms have smaller parts, called
molecules.
С
Molecules are made up of two or more
atoms.
D
Molecules are atoms that have no mass.
Answer:
С . Molecules are made up of two or more atoms.
Explanation:
The relationship between molecules and atoms is that molecules are made up of two or more atoms.
Molecules are made up of atoms.
A molecule is the smallest particle of a substance element or compound capable of independent existence.
A molecule could be monoatomic, diatomic or polyatomic.
Monoatomic molecules are made up of one atom
Diatomic are made up of two different atoms
Polyatomic substances are made up of more than two kinds of atoms.
An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 34.5 m/s . It then flies a further distance of 46100 m , and afterwards, its velocity is 40.7 m/s . Find the airplane's acceleration.
Answer:
the acceleration of the airplane is 5.06 x 10⁻³ m/s²
Explanation:
Given;
initial velocity of the airplane. u = 34.5 m/s
distance traveled by the airplane, s = 46,100 m
final velocity of the airplane, v = 40.7 m/s
The acceleration of the airplane is calculated from the following kinematic equation;
v² = u² + 2as
[tex]2as= v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{(40.7)^2 -(34.5)^2}{2 \times 46,100} \\\\a = 5.06 \ \times \ 10^{-3} \ m/s^2[/tex]
Therefore, the acceleration of the airplane is 5.06 x 10⁻³ m/s²
The current in a coil with a self inductance of 1.5 mH increases from 0 to 1.0 A in a tenth of a second. What is the induced emf in the coil
Answer:
the induced emf in the coil is 15 mV.
Explanation:
Given;
self inductance, L = 1.5 mH = 1.5 x 10⁻³ H
change in current = dI = 1.0 A
change in time, dt = 1/10 = 0.1
The induced emf is calculated as;
[tex]Induced \ EMF = L (\frac{dI}{dt} )\\\\Induced \ EMF = 1.5 \times 10^{-3}\ (\frac{1}{0.1} )\\\\Induced \ EMF = 1.5 \times 10^{-3} \ \times \ 10\\\\Induced \ EMF = 15 \times 10^{-3} \ V\\\\Induced \ EMF = 15 \ mV[/tex]
Therefore, the induced emf in the coil is 15 mV.
If the pressure in a gas is doubled while its volume is held constant, by what factor do vrms change
Answer is given below
Explanation:
given data
pressure = double
volume = constant
solution
As we know that an Average velocity and rms velocity is directly proportional to square root of PV ..................1
so if we take P is doubled while keeping V constant
than Velocity increases by a factor [tex]\sqrt{2}[/tex]
so that Factor = 1.414 for both the cases
What is the relationship among the potential drops across each resistor when the resistors are in series
Answer:
V = V₁ + V₂ + V₃ + ... + Vₙ
Explanation:
When the resistors are connected end to end such that there is only one path for the current to follow, it is called a series arrangement of resistors. In the series arrangement of the resistors, the current across each resistor is the same as the current applied across the circuit.
The potential difference across each resistor is different in the series arrangement of the resistors. But the sum of potential differences across each of the resistors in the series arrangement of resistors is equal to the total potential difference applied by the battery or source. Therefore, if n number of resistors are connected in a series arrangement with a source of potential V, the:
V = V₁ + V₂ + V₃ + ... + Vₙ
Please help if giving 20 points and brainliest
You have designed a prototype of a new, lighter material. What should be the
next step in your process?
O A. Figure out what problems people want to solve.
B. Update your initial design for the new type of material.
O c. Test to see whether your material is strong and works well.
D. Brainstorm new ways to design materials.
Answer:
O
Explanation:
Because your product will not work well so people will not buy it and it could be a defect and explode
Answer:
c
Explanation:
Suppose that the voltage is reduced by 10 percent (to 90 V). By what percentage is the power reduced
Answer:
percent decrease in power = 20 % .
Explanation:
Power P = v² / R where v is voltage and R is resistance which is constant .
taking log on both sides
log P = 2 log v - log R
differentiating on both sides
dP/P = 2 dv/v
-dP/P x 100 = 2 x -dv/v x 100
percent decrease in power = 2 x percent decrease in v ( voltage )
percent decrease in power = 2 x 10 = 20 %
4.Jessica Diggins a US world champion cross country skier is participating in the winter Olympic games. Over a 200m stretch in her race she increases her speed with a constant acceleration from 5.1 m/s to 6.2 m/s over a period of 25 seconds. What is her acceleration
Answer:
[tex]a=0.044\ m/s^2[/tex]
Explanation:
Given that,
Initial speed, u = 5.1 m/s
Final speed, v = 6.2 m/s
Time, t = 25 s
We need to find acceleration. We know that,
acceleration = rate of change of velocity
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{6.2-5.1}{25}\\\\a=0.044\ m/s^2[/tex]
So, her acceleration is [tex]0.044\ m/s^2[/tex].
What happens to plankton during the spring bloom?Which organisms are consumers? (Select all that apply.) coyote, snail ,green algae, or bacteria
Answer:
See explanation
Explanation:
Plankton refers to the small and microscopic organisms drifting or floating in the sea or fresh water, consisting chiefly of diatoms, protozoans, small crustaceans, and the eggs and larval stages of larger animals(Oxford dictionary).
The spring bloom is a sudden growth or increase in plankton abundance. It begins around the early spring and continues until late in the spring or sometimes even early in the summer.
One organism that is a consumer of plankton are the snails. One of the commonest snails that eat plankton are the Nerite Snails.
What is the electrical consumption in KVA of a motor powered by a 3-phase, 60 Hz, 460 VAC supply that continuously draws 17 A
Answer:
15.34 kVA
Explanation:
A motor is a device that converts electrical energy into mechanical energy. It takes in electrical energy at the input and produce torque (motion) at the output.
The power consumption for a three phase motor is the product of voltage and current and √3. The √3 is because it is a three phase supply.
Hence Power (P) =√3 × voltage (V) × current (I)
P = √3 × V × I
Given that voltage (V) = 460 V, current (I) = 17 A. Hence:
P = √3 × V × I = √3 × 460 × 17 = 13544.64 VA
But 1000 VA = 1 kVA. Hence:
[tex]P=13544.64\ VA*\frac{1\ kVA}{1000\ VA}=13.54\ kVA[/tex]
A water bug is suspended on the surface of a pond by surface tension (water does not wet the legs). The bug has six leg, and each leg is in contact with the water over a length of 5 mm. What is the maximum mass (in grams) of the bug if it is to avoid sinking
Answer:
m = 2.2 x 10⁻⁴ kg = 0.22 g
Explanation:
The surface tension of water is 0.072 N/m. So in order for the bug to avoid sinking, its weight per unit length of contact must be no more than the surface tension of water. Therefore,
[tex]Weight\ of bug\ per\ unit\ length = Surface\ Tension\ of\ Water\\\frac{mg}{L} = Surface\ Tension\ of Water\\m = \frac{(Surface\ Tension\ of\ Water)(L)}{g}[/tex]
where,
m = mass of bug = ?
g = acceleration due to gravity = 9.81 m/s²
L = Contact length = (contact length of each leg)(No. of Legs) = (5 mm)(6)
L = 30 mm = 0.03 m
Therefore,
[tex]m = \frac{(0.072\ N/m)(0.03\ m)}{9.81\ m/s^{2}} \\[/tex]
m = 2.2 x 10⁻⁴ kg = 0.22 g
Light with a wavelength of 560.0 nm is incident on a pair of slits with a separation of 0.380 mm. (a) Find the angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe
Answer:
Angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe are;
∅₁ = 0.8439°
∅₂ = 0.1688°
∅₃ = 0.2533°
Explanation:
Given that;
wavelength λ = 560 nm = 560 × 10⁻⁹
Separation between slits d = 0.380 mm = 0.00038
n = first three orders = 1st order, 2nd order and 3rd oder.
we know that for constructive interference;
λn = dsin∅
sin∅ = λn/d
∅ = sin⁻¹ ( λn/d )
where λ is wavelength, ∅ is the angle, d is the distance between slits, n is the order of constructive interference.
now;
-First order; n = 1
∅₁ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(1) /0.00038 )
∅₁ = sin⁻¹( 0.001473) = 0.8439°
-2nd order; n = 2
∅₂ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(2) /0.00038 ) =
∅₂ = sin⁻¹( 0.002947) = 0.1688°
-3rd order; n = 3
∅₃ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(3) /0.00038 ) =
∅₃ = sin⁻¹( 0.004421) = 0.2533°
Therefore, angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe are;
∅₁ = 0.8439°
∅₂ = 0.1688°
∅₃ = 0.2533°
