b) A vapor compression refrigerator uses methyl chloride and works in the pressure range of 1.19 bar and 5.67 bar. At the beginning of compression, the refrigerant is 0.96 dry and the end of isentropic compression its temperature is 55 °c. The refrigerant liquid leaving the condenser is saturated.

If the mass flow of refrigerant is 1.8 kg/min.​

The calculation of the coefficient of performance, the rise in temperature of condenser cooling water, and the ice produced in the evaporator can be done using the energy balance equations for the refrigeration cycle.

(i) Co-efficient of Performance (COP):

COP is defined as the ratio of the cooling capacity to the power required for refrigeration.

COP = Cooling capacity / Power required for refrigeration

The cooling capacity can be determined using the energy balance on the evaporator, which states that the heat absorbed by the refrigerant in the evaporator is equal to the heat rejected by the condenser.

Cooling capacity = m_ref * (h2 - h1)

where

m_ref = 1.8 kg/min, mass flow rate of refrigerant

h2 = enthalpy of refrigerant at the end of isentropic compression, 55°C

h1 = enthalpy of refrigerant at the beginning of the compression, 0.96 dry

The power required for refrigeration can be calculated as the work done on the refrigerant during the isentropic compression process.

Power required for refrigeration = m_ref * (h2 - h1)

Now we can calculate the COP using the above equations.

(ii) Rise in temperature of condenser cooling water:

The rise in temperature of condenser cooling water can be calculated using the energy balance on the condenser. The heat rejected by the refrigerant in the condenser is equal to the heat absorbed by the condenser cooling water.

Q_rejected = m_cw * Cp * (T_out - T_in)

where

m_cw = 16 kg/min, mass flow rate of condenser cooling water

Cp = 4.187 kJ/kg, specific heat of water

T_out = Final temperature of cooling water

T_in = Initial temperature of cooling water

We can solve for the rise in temperature (T_out - T_in) using the above equation.

(iii) Ice produced in the evaporator:

The ice produced in the evaporator can be calculated using the energy balance on the evaporator and the latent heat of fusion of ice.

Q_absorbed = m_ice * hf

where

m_ice = Mass of ice produced

hf = 336 kJ/kg, specific enthalpy of fusion of ice

We can solve for the mass of ice produced (m_ice) using the above equation.

Note: The above calculations require the enthalpies of the refrigerant at various states, which can be obtained from thermodynamic tables.

learn more about enthalpies: https://brainly.com/question/14047927

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The complete question goes thus:

A vapour compression refrigerator uses methyl chloride and works in the pressure range of 1.19 bar and

5.67 bar. At the beginning of the compression, the refrigerant is 0.96 dry and at the end of isentropic

compression, it has a temperature of 55°C. The refrigerant liquid leaving the condenser is saturated. If the

mass flow of refrigerant is 1.8 kg/min. Determine :

(i) Co-efficient of performance.

(ii) The rise in temperature of condenser cooling water if the water flow rate is 16 kg/min.

(iii) The ice produced in the evaporator in kg/hour from water at 15°C and ice at 0°C. Take : Specific enthalpy of fusion of ice = 336 kJ/kg

Specific heat of water = 4.187 kJ/kg.

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