Answer:
A nonmetal is a chemical element that generally lacks a predominance of metallic properties. Non-metals are mostly found in groups 5, 6 and 7. These non-metals will have 5, 6 or 7 electrons in the outer shell.
The outer shell of a non-metal is, therefore, more than half full of electrons.
Question 26 of 30
For a reaction, AH = -75 kJ/mol and SO = -0.081 kJ/(K.mol). At what
A
temperatures is this reaction spontaneous?
O A. T<930 K
OB. At all temperatures
C. T< 100 K
OD. T> 930 K
Answer: B
Explanation:
A group of students is comparing the graphs of strong acid-strong base and weak acid-strong base titration curves, where the base is the titrant. Which statement inaccurately describes a difference between the two curves?
A. The initial pH for the weak acid-strong base curve is higher than the initial pH for the strong acid-strong base curve.
B. At the equivalence points, the pH of the weak acid-strong base is greater than the pH of the strong acid-strong base.
C. At the half-equivalence points, the pH of the weak acid-strong base is greater than the pH of the strong acid- strong base.
D. The steep-rise interval in the weak acid-strong base curve is more pronounced than in the strong acid-strong base curve.
The initial pH for the weak acid-strong base curve is higher than the initial pH for the strong acid-strong base curve. Hence, option A is correct.
What is a weak acid?Weak acids are acids that don't completely dissociate in solution.
A weak acid is an acetic acid. It has a of 1.8⋅[tex]10^{-5}[/tex]. Calculate how much it will dissociate in water. Since acetic acid is a weak acid so large part will not dissociate completely.
[tex]k_a=\frac{[CH_3COO^-]H^+]}{[CH_3COOH]}[/tex]
B is not true, it shows the titration curve for weak/strong acid titrated with a strong base. When choosing an indicator for colourimetric titration select one so that the pH jump at the equivalence point contains the interval p±1. Phenolphthalein has a p≈9, so to decide if it is a suitable indicator check if the pH jumps from 8 to 10 at the equivalence point.
C is not true either because of the very slow reaction.
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Diffrentiate the reactivity of metals and Non-metals with air / oxygen.
Answer:
Both metals and non-metals when burnt in oxygen form their oxides. Oxides of metals are basic in nature and oxides of non-metals are acidic in nature.
What mass in grams of iron metal can be formed by the reaction of 2.14 gAI metal with excess Fe₂O₃, according to the thermite reaction: 2Al(s) + Fe₂O₃ → 2Fe(s) + Al₂O₃(s)
Answer:
4.43 g Fe
Explanation:
To find the mass of iron, you need to (1) convert grams Al to moles Al (via molar mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs because the given value (2.14) has 3 sig figs.
Molar Mass (Al): 26.982 g/mol
2 Al(s) + Fe₂O₃ ---> 2 Fe(s) + Al₂O₃(s)
Molar Mass (Fe): 55.845 g/mol
2.14 g Al 1 mole 2 moles Fe 55.845 g
---------------- x ----------------- x -------------------- x ------------------ = 4.43 g Fe
26.982 g 2 moles Al 1 mole
Aluminum reacts with ferric oxide to produce iron by the thermite reaction. The mass of the iron metal that will be formed by the chemical reaction is 4.43 g Fe.
What is a limiting reagent?Limiting reagent has been described as reactions that are present in lesser amounts than the other reactant in the reaction that determines the amount of formation of the products and are never left in a reaction.
The balanced thermite reaction is given as:
2 Al(s) + Fe₂O₃ → 2 Fe(s) + Al₂O₃(s)
Molar mass of aluminium = 26.982 g/mol
Molar Mass of iron= 55.845 g/mol
Mass of aluminium (Al) = 2.14 grams
Here, according to the reaction 2 moles of Aluminum are needed to produce 2 moles of iron (Fe).
Moles of aluminum is calculated as:
Moles = mass ÷ molar mass
n = 2.14 ÷ 26.982
= 0.079 mol
As aluminum is the limiting reagent, it determines the formation of iron as:
2 mol Al = 2 mol Fe
0.079 mol Al = 0.079 mol Fe
Mass of iron is calculated as:
Mass = moles × molar mass
mass = 0.079 × 55.845 g/mol
= 4.411 grams
Therefore, 4.43 g Fe will be produced from 2.14 gm Al.
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HELP! ASAP!
3. Describe the process of copper-plating. What occurs at the molecular level? Is this considered a physical change or a chemical change? Explain your reasoning.
Copper-plating is a chemical change in which copper ions become neutral copper atoms by accepting electrons which then are deposited on the material to be coated.
What is copper-plating?copper-plating?Copper-plating is the process by which a layer of copper is used to coat another material using the process of electrolysis.
At the molecular level, copper ions in solution accept electrons to become neutral copper atoms which then are deposited on the material, thereby coating.
This is an example of a chemical change since it us not easily reversible and new products are formed.
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Determine the number of protons, neutrons, and electrons in the following:
40
. . X
18
Ignore the dots im just trying to place the element over between the numbers
The ⁴⁰₁₈X is the symbol for ⁴⁰₁₈Ar - atom and it has 18 protons, 18 electrons, and 22 neutrons.
What is Mass number ?Mass number is the sum of the numbers of protons and neutrons present in the nucleus of an atom.
In the given element, ⁴⁰₁₈X, Subscript 18 is the number of proton and is also equal to the number of electron. While supercript 40 is the atomic mass.
The number of neutrons is given by subtracting the proton number from the mass number.
Therefore,
Number of Neutron = Mass Number - Atomic Number
= 40 - 18
= 22 Neutrons
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Felicity lists the factors that affect the shape of Florida.
Which does not belong in this list?
Answer:
if the Florida inters into the land se hokar gar ke bill Tak jane ke process Florida kahte hai aur bur ka bal se doodh chusne Tak wo Florida s
Humidity, thermometer, and rainfall factors affect the shape of Florida, making the shape different.
What is the shape of Florida?In general, a molecule's electron pairs will take on a structure that maximizes theirs from one another.
Even charges repel one another, whereas dissimilar charges attract H₂O, for instance, containing two pairs of lone electrons but taking on an angular form.
Sand ridges, like the Lake Wales Ridge, were created during dry times from sediments that had been transported by ocean currents and deposited to form islands.
Latitude, land and water distribution, dominant winds, hurricanes, pressure systems, and ocean currents are the main variables that influence Florida's climate.
Therefore, as glaciers retreated throughout cooling cycles, sea levels dropped and Florida occasionally doubled in size.
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7. How can it be said that two water molecules represent more entropy than two hydrogen molecules plus
an oxygen molecule?
The reason for this is that water is a polar molecule and one water molecule is attracted to the other by a hydrogen bond.
What is entropy?The term entropy refers to the degree of disorder in a molecule. The more disorderly a molecule is, the higher its entropy.
The fact that water is a polar molecule and one water molecule is attracted to the other by a hydrogen bond thus, two water molecules represent more entropy than two hydrogen molecules plus an oxygen molecule.
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Use the drop-down menus to determine the changes of
state that are missing from the triangle.
Answer:
can you post a photo? to help y with the question
Explanation:
A doctor prescribed a tablet to a patient suffering from iron deficiency. The tablet does not look like iron. Explain.
Answer:
Tablets are made from salts of iron hence it does not look like iron.
Explanation:
The table shows the total number of electrons in Atom A and Atom B.
Atom Number of Electrons
10
B
12
Which statement is correct? (5 points)
O A will give up two electrons to form bonds.
• B will give up two electrons to form bonds.
• Both A and B will be chemically unreactive.
• Both A and A B will gain electrons to become stable.
Answer:
The answer is "B will give up two electrons to form bonds".
Explanation:
To first solve this multiple choice question, we need to identify the Atoms, A and B.
We can do this by looking at their amount of electrons.
For instance,
A = Neon = 10 Electrons
B = Magnesium = 12 Electrons
With this information we can then look at both elements charges to see what they need to form a bond.
In this case Neon doesn't want to form a bond, since they're in a complete octet, however Magnesium does not have a complete octet. So, it wants to give up two electrons to form a bond (2+ charge shows us that).
This then shows us that Option 2, "B will give up two electrons to form bonds" is correct.
Answer:
B will give up two electrons to form bonds
Explanation:
what is the structure of alcohol?
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6. A sample of a gas at 77°C and 1.33 atm occupies a volume of 50.3 L. How many moles of the gas are present? (Hint: Since moles have been asked, which equation has the moles listed in the equation. Use that to solve this problem).
The number of moles of the gas at 77°C and 1.33 atm occupies a volume of 50.3 L is 2.35 moles. It can found with the help of Ideal gas equation.
What is Ideal Gas equation ?The ideal gas equation is formulated as : PV = nRT.
In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.
Given ;
Pressure = 1.33 atmVolume = 50.3 ltrTemperature = 77 (+273 k) = 350KWe know ;
Gas constant (R) = 0.081 L atm/mol KFormula used ;
n = PV / RT
n = 1.33 x 50.3 / 0.081 x 350k
= 2.35 moles.
Hence, The number of moles of the gas at 77°C and 1.33 atm occupies a volume of 50.3 L is 2.35 moles
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PLEASE HELPPPPPPPPPPPPP
Cyclopropane is a compound of carbon and hydrogen that is used as a general anaesthetic. When 1 g of this substance was burned completely in oxygen, 3.14 g of carbon dioxide and 1.29 g of water were produced. What is the empirical formula of the compound? The molar mass of cyclopropane is about 42 g/mol. What is the molecular formula?
Empirical formula of the Cyclopropane = C[tex]H_{2}[/tex]
Molecular formula of the Cyclopropane = [tex]C_{3} H_{6}[/tex]
Cyclopropane is a cyclic compound having 3 carbon atoms in a ring.
As we know carbon is having 4 valency, that means it can form 4 bonds with other atoms.
In case of cyclopropane each carbon atom is attached with 2 carbon atoms in a ring, so 2 valency of each carbon atom is used in a ring formation.
The remaining 2 valency are satisfied by hydrogen atoms.
Here, 3 carbons are there so 6 hydrogens are used to satisfy their valency.
An empirical formula is a simple representation of ratio of the atoms present, while a molecular formula is a detailed representation of the total number of atom.
So here, carbon and hydrogen ratio is 1:2 , from this the Empirical formula of the Cyclopropane became C[tex]H_{2}[/tex]
And the molecular formula of the Cyclopropane is [tex]C_{3} H_{6}[/tex].
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Can you help me with this with a solution
The complete table is inserted.
A table is given,
Formulas used:
pH= -log(H⁺)
pOH= -log(OH⁻)
pH+ pOH=14
Calculations:
For A: (H⁺)=2×10⁻⁸M
Using the pH formula:
pH= -log(H⁺)=-log(2×10⁻⁸)=7.69
pOH=14 - 7.69=6.3
Calculating OH concentration,
pOH= -log(OH⁻)
6.3= -log(OH⁻)
(OH⁻)=5.011×10⁻⁷M
Hence, the nature of A is basic.
Similarily,
For B,
(OH⁻)=1×10⁻⁷
Using the pH formula:
pOH= -log(OH⁻)= -log(1×10⁻⁷)=7
pH=14-7=7
Calculating H concentration,
pH= -log(H⁺)
7= -log(H⁺)
(H⁺)=1×10⁻⁷M
Hence, the nature of B is neutral.
Similarily,
For C,
pH=12.3
Using the pH formula:
pOH=14-12.3=1.7
Calculating H concentration,
pH= -log(H⁺)
12.3= -log(H⁺)
(H⁺)=5.011×10⁻¹³M
Calculating OH concentration,
pOH= -log(OH⁻)
1.7= -log(OH⁻)
(OH⁻)=1.99×10⁻²M
Hence, the nature of C is Basic.
Similarily,
For D,
pOH=6.8
Using the pH formula:
pH=14-6.8=7.2
Calculating H concentration,
pH= -log(H⁺)
7.2= -log(H⁺)
(H⁺)=6.309×10⁻⁸M
Calculating OH concentration,
pOH= -log(OH⁻)
6.8= -log(OH⁻)
(OH⁻)=1.58×10⁻⁷M
Hence, the nature of D is basic.
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What is the percent yield for the reaction below when
705.0 g SO2 and 80.0 g 0₂ produce 586.0 g SO3?
2SO2(g) + O₂(g) → 2SO3(g)
The percent yield for the chemical reaction producing sulfur trioxide is 66.51%.
What is percent yield?Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.
In cases where percent yield is over 100% it indicates that more sample is recovered than the predicted amount.
For the given reaction, theoretical yield is calculated as,
128.132 g of sulfur dioxide gives 160.12 g of sulfur trioxide
∴705 g of sulfur dioxide gives 705×160.12/128.132= 881 g
Percent yield is, 586/881×100=66.51%
Therefore, the percent yield for the chemical reaction is 66.51%.
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Which row about a change of state is correct?
Answer:
c
Explanation:
because heat is taken in in sublimation.
Sublimation is the straight transition from a solid state of materials to a vapor state upon heating (without becoming liquid). The row about a change of state which is correct is C.
Sublimation is the transition of a substance from its solid to its gaseous state without passing through a liquid phase. Sublimation is the term most frequently used to describe the process by which snow and ice turn into water vapor (gas) in the atmosphere without first melting into a liquid for those of us who are interested in the water cycle.
The best illustration of sublimation is dry ice, which is carbon dioxide that has been frozen. Dry ice directly transforms from its solid state to a gaseous state, which is visible as fog, when it is exposed to air. The gaseous state of frozen carbon dioxide is more stable than the solid state.
Thus the correct option is C.
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Please help me make analysis scheme flow chart for the detection of cation present in my unknown salt mixture of Ag+, Pb2+, or Ca2+ cations based on their solubility in the given reagents.
I can only use these reagents: Na2CO3, NaCl, & Na2SO4
The suspected cations in the unknown cation mixture are: Ag+, Pb2+, or Ca2+.
I used 0.5 M solution of all these reagents.
My test results are:
Na2CO3: 20 drops of sodium carbonate were used and silver blue precipitate was produced.
NaCl: 20 drops of sodium chloride were used and no precipitate was formed.
Na2SO4: 20 drops of sodium sulfate were used yellow precipitate was produced.
Please please help me make analysis flow chart based on this information and also tell me in what sequence these reagents will be added to unknown salt mixture.
I suspect that the cation may be Ca2+ based on solubility rules. But I'm not sure.
The possible action your solution might contain is amongst [tex]Ag^+[/tex], [tex]Pb^{2+}[/tex], or [tex]Ca^{2+}[/tex].
What are the solutions?A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.
NaCl: 20 drops of NaCl were used and no precipitate was formed.
No precipitation formed means the [tex]Cl^-[/tex] cation is soluble in water. From your chart, you might see the halide of [tex]Ag^+[/tex] and [tex]Pb^{2+}[/tex] is insoluble in water, which means they should have formed precipitation but you didn't. This means there's less possibility it contains [tex]Ag^+[/tex] or [tex]Pb^{2+}[/tex], so we are left with only [tex]Ca^{2+}[/tex]. Let's confirm it with the rest.
[tex]Na_2SO_4[/tex] : 20 drops of [tex]Na_2SO_4[/tex] were used yellow precipitate was produced.
Even though all other sulfates form precipitation ( Insoluble in water)
[tex]Na_2CO_3[/tex] : 20 drops of sodium carbonate were used and the silver-blue precipitate was produced.
It seems all of their Carbonate is insoluble in nature. ( which is our case too ).
From the above result, only the reaction with NaCl was deemed to be decisive and it indeed contains [tex]Ca^{2+}[/tex] ions. Means you are correct.
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In the reaction below, 1.000 × 103 g LiOH is combined with 8.80 × 102 g CO2. The reaction produces 3.25 × 102 g H2O in an experiment.
CO2 + 2LiOH → Li2CO3 + H2O
theoretical yield
Answer:
CO2
Explanation:
100% CORRECT ON EDGE
The mass of water produced when 1.000 × 10³ g of LiOH is combined with 8.80 × 10² g CO₂ is 3.25 × 10² g H₂O.
What is mass?Mass is defined as a dimensionless number used to describe the mass of a particle or item. The kilogram is the International System's (SI) preferred unit of mass (kg). Atoms make up everyday matter. A majority of an atom's mass is contained in its nucleus.
It is a neutralization process when lithium hydroxide and carbon dioxide combine to form water and lithium carbonate.
The reaction is [tex]\rm CO_2 + 2LiOH \rightarrow Li_2CO_3 + H_2O[/tex]
Neutralization reaction is defined as an acid and base reaction that produces an ionic molecule and potentially water.
Thus, the mass of water produced when 1.000 × 10³ g of LiOH is combined with 8.80 × 10² g CO₂ is 3.25 × 10² g H₂O.
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Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p.
The force exerted between S and q is ___4 times____ the force exerted between S and p.
What is Coulomb's law ?Coulomb's law states that , the electrostatic force of attraction or repulsion between two charged bodies is directly proportional to the product of the charges and is inversely proportional to the square of the distance between them
It is given by
[tex]\rm F = k_e \dfrac{q_1 q_2}{r^2}[/tex]
r is the distance between two bodies
It is given that
Charge q is 1 unit of distance away from the source charge S
Charge p is two times further away from the source charge S
force exerted between S and q
distance between the charges is 1 unit
[tex]\rm F_{qs} = k_e \dfrac{q_q q_s}{1^2}\\\\\rm F_{ps} = k_e \dfrac{q_p q_s}{2^2}\\[/tex]
The force exerted between S and q is _______ the force exerted between S and p.
[tex]\rm F_{qs} = k_e \dfrac{q_q q_s}{1^2} = F_{ps} = k_e \dfrac{q_p q_s}{2^2}\\\\[/tex]
Assuming the charges to be q units
Then
[tex]\rm F_{qs} = k_e \dfrac{q_q q_s}{1^2} = F_{ps} = k_e \dfrac{q_p q_s}{2^2}\\\\\\\\\dfrac {F_{qs}}{F_{ps}} = \dfrac{2^2}{1^2} = 4 \\\\\\{F_{qs}} = 4{F_{ps}}[/tex]
Therefore ,
The force exerted between S and q is ___4 times____ the force exerted between S and p.
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someone people help me with this chemistry question
Answer:
6 moles
Explanation:
From the equation you can see that twice as many HCL moles are used as H2 produced
2 x 3 = 6 moles of HCL required
When 50.5 g iron(III) oxide reacts with carbon monoxide, 32.2 g iron is produced. What is the percent yield of the reaction?
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
Taking into account definition of percent yield, the percent yield for the reaction is 91.17%.
Reaction stoichiometryIn first place, the balanced reaction is:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Fe₂O₃: 1 mole CO: 3 moles Fe: 2 moles CO₂: 3 molesThe molar mass of the compounds is:
Fe₂O₃: 159.7 g/moleCO: 28 g/moleFe: 55.85 g/moleCO₂: 44 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Fe₂O₃: 1 mole ×159.7 g/mole= 159.7 grams CO: 3 moles ×28 g/mole= 84 gramsFe: 2 moles ×55.85 g/mole= 111.7 gramsCO₂: 3 moles ×44 g/mole= 132 gramsMass of Fe formedThe following rule of three can be applied: if by reaction stoichiometry 159.7 grams of Fe₂O₃ form 111.7 grams of Fe, 50.5 grams of Fe₂O₃ form how much mass of Fe?
[tex]mass of Fe=\frac{50.5 grams of Fe_{2} O_{3} x111.7 grams of Fe}{159.7 grams of Fe_{2} O_{3}}[/tex]
mass of Fe= 35.32 grams
Then, 35.32 grams of Fe can be produced from 50.5 g iron(III) oxide.
Percent yieldThe percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
[tex]percent yield=\frac{actual yield}{theorical yield}x100[/tex]
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
Percent yield for the reaction in this caseIn this case, you know:
actual yield= 32.2 gramstheorical yield= 35.32 gramsReplacing in the definition of percent yields:
[tex]percent yield=\frac{32.2grams}{35.32grams}x100[/tex]
Solving:
percent yield= 91.17%
Finally, the percent yield for the reaction is 91.17%.
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Need answer ASAP!! The specific heat capacity of metal A is twice that of metal B. Based on
this information, which of the following statements is true?
The melting point of metal A is higher than that of metal B
The heat of fusion of metal A is twice that of metal B
If the same amount of heat is absorbed by equal masses of metal A and metal B,
the temperature change of metal A will be twice that of metal B
If the same amount of heat is absorbed by equal masses of metal A and metal B,
the temperature change of metal A will be half that of metal B
Answer:
last choice
Explanation:
Specific heat of a metal is j/kg-c
It says nothing about melting point or heat of fusion
A = twice B = 2 * j/kg-c B = j/kg-c
if j is constant and mass is the same we can write this more like
A = 2 /C and B = 1/C
or A ~ C/2 and B~ C
now you can see that the temp change in A will be 1/2 that of B
What is the number of moles in 4.20 kg of carbon dioxide
Answer:
95.45 moles
Explanation:
CO2 has mole weight 12 + 2 *16 = 44 gm/mole
4200 gm / 44 gm/mole = 95.45 moles
3A. The following skeletal oxidation-reduction reaction occurs under basic conditions. Write the balanced REDUCTION half reaction.
Cl- + SiO32- Cl2 + Si
Reactants Products
3B.
The following skeletal oxidation-reduction reaction occurs under basic conditions. Write the balanced OXIDATION half reaction.
Bi + HPO32-Bi(OH)3 + H2PO2-
Reactants Products
4A. The following skeletal oxidation-reduction reaction occurs under acidic conditions. Write the balanced REDUCTION half reaction.
Cd + SO42- Cd2+ + H2SO3
Reactants Products
4B. The following skeletal oxidation-reduction reaction occurs under acidic conditions. Write the balanced OXIDATION half reaction.
Mn2+ + NiO2MnO4- + Ni2+
Reactants Products
The balanced redox equations of the reactions are:
[tex]SiO_{3}^{2-} + 3\:H_{2}O + 4\:e^{-} \rightarrow Si + 6\:OH^{-}[/tex][tex]2\:Bi + 6\:OH^{-} \rightarrow 2\:Bi(OH)_{3} + 6\:e^{-}[/tex] [tex]SO_{4}^{2-} + 4\:H^{+} + 2\:e^{-} \rightarrow H_{2}SO_{3} + H_{2}O[/tex][tex]Mn^{2+} + 4\:H_{2}O \rightarrow MnO_{4}^{-} +8\:H^{+} + 5\:e^{-}[/tex]What are balanced redox equations?Balanced redox equations are those in which the atoms and electrons transferred are equal on both sides of the equation.
The balanced redox equations of the reactions are given below:
(3a) Balanced REDUCTION half reaction of the equation under basic conditions:
[tex]SiO_{3}^{2-} + 3\:H_{2}O + 4\:e^{-} \rightarrow Si + 6\:OH^{-}[/tex](3b)Balanced OXIDATION half reaction of the equation under basic conditions:
[tex]2\:Bi + 6\:OH^{-} \rightarrow 2\:Bi(OH)_{3} + 6\:e^{-}[/tex](4a) Balanced REDUCTION half reaction of the equation under acidic conditions:
[tex]SO_{4}^{2-} + 4\:H^{+} + 2\:e^{-} \rightarrow H_{2}SO_{3} + H_{2}O[/tex](4b) Balanced OXIDATION half reaction of the equation under acidic conditions:
[tex]Mn^{2+} + 4\:H_{2}O \rightarrow MnO_{4}^{-} +8\:H^{+} + 5\:e^{-}[/tex]Therefore, the balanced oxidation and reduction half reactions are balanced by adding the numerical coefficients to the reacting species as well hydrogen ions, hydroxide ions, water molecules and electrons to the appropriate side of the reactions.
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A laser emits light at a wavelength of 678 nm. How many photons are required to emit 1 joule of energy?
0.342 x [tex]10^(^1^6^)[/tex]) photons are required to emit 1 joule of energy.
What is a photon?A photon is a particle of light defined as a discrete bundle (or quantum) of electromagnetic (or light) energy.
We need to find the number of photons emitted per second.
So we have E = hc ÷ λ
= (6.6 x [tex]10^-(^3^4^)[/tex]x 3 x [tex]10^8[/tex] m/s) ÷ 6.78 x [tex]10^(^-^7^)[/tex]nm
= 2.92 x [tex]10^(^-^1^9^)[/tex]Joules
Now number of photons per second = I / E (I = intensity)
= 1 x [tex]10^(^-^3^)[/tex] joule / sec ÷ 2.92 x [tex]10^(^-^1^9^)[/tex]joule
= 0.342 x[tex]10^(^1^6^)[/tex]
Hence, 0.342 x [tex]10^(^1^6^)[/tex]) photons are required to emit 1 joule of energy.
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A group of students measure the length of a pencil using a metric ruler. The pencil has a known length of 14.2 cm. They record the following measurements: 13.7 cm, 13.6 cm, and 13.7 cm. What is the best way to describe their data?
a. Accurate, but not precise
c. BOTH accurate and precise
b. Precise, but not accurate
d. NEITHER accurate nor precise
Answer:
Neither accurate not precise
2 upper N upper O subscript 2 (g) right arrow 2 upper N upper o (g) plus upper O subscript 2 (g). Second: 2 upper N upper O (g) right arrow upper N subscript 2 (g) plus upper O subscript 2 (g). Third: upper N subscript 2 (g) plus 2 upper O subscript 2 (g) right arrow upper N subscript 2 upper O subscript 4 (g). What is the equation for the overall reaction obtained by adding these equations?
The equation for the overall reaction obtained by adding these equations is; 2NO₂(g) ⇒ N₂O₄(g)
How to simplify chemical equations?We are given equations;
2NO₂(g) ----> 2NO(g) + O₂(g) ---(1)
2NO(g) -----> N₂(g) + O₂(g) -----(2)
N₂(g) + 2O₂(g) ----> N₂O₄(g) -----(3)
Add eq 1 and eq 2 to get;
2NO₂(g) + 2NO(g) ⇒ 2NO(g) + O₂(g) + N₂(g) + O₂(g)
2NO will cancel out to get;
2NO₂(g) ⇒ N₂(g) + 2O₂(g) -----(4)
Add eq 3 to eq 4 to get;
N₂(g) + 2O₂(g) + 2NO₂(g) ⇒ N₂O₄(g) + N₂(g) + 2O₂(g)
This will reduce to;
2NO₂(g) ⇒ N₂O₄(g)
The correct question is;
Consider the chemical equations shown here.
2NO₂(g) ----> 2NO(g) + O₂(g)
2NO(g) -----> N₂(g) + O₂(g)
N₂(g) + 2O(g) ----> N₂O₄(g)
What is the equation for the overall reaction obtained by adding these equations?
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Answer:
A &D
Explanation:
I took it
A balloon is inflated to 7.0 L of volume. How many moles of gas does it contain at
STP?
0.31 moles
15 moles
3.2 moles
0.70 moles
The number of moles of gas, a balloon inflated to 7 L of volume at STP will be 0.31 moles.
What is the Molar volume ?The molar volume of a gas is the volume of one mole of a gas at STP.
At STP, one mole (6.02×10²³ particles) of any gas occupies a volume of 22.4 L
Therefore,
If 1 mole of any gas occupies 22.4 L of volume at STP
Then, X mole of gas occupies 7 L of Volume at STP
Now,
Let's equate both the above conditions ;
X / 7 L = 1 / 22.4 L
X = 1/ 22.4 L x 7 L
X = 0.31 moles
Hence, the number of moles of gas, a balloon inflated to 7 L of volume at STP will be 0.31 moles.
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1) Consider this row in the periodic table. What changes can you predict based on what information is provided by the boxes for each element?
A) The elements change from solids to gases and the valence electrons decrease in number.
B) As you move across the row, the number of electrons increases and reactivity also increases.
C) They have different atomic numbers and mass numbers; they have the same number of valence electrons.
D) Both the atomic numbers and the mass numbers increase; the least reactive element is in the last box.
USA test prep question
Answer:
B) As you move across the row, the number of electrons increases and reactivity also increases.
Explanation:
The periodic table is arranged in a way that if you go across a period, the number of protons, neutrons, and electrons in an element increases. In terms of reactivity, the most reactive elements are the ones which have a high electronegativity. The electronegativity of the elements increases as you travel to the right and upwards on the periodic table.
