What is the equation of the blue line?

Answer:

65.4

Step-by-step explanation:

5 × 6 = 30 square meter

30 × 2.18 = 65.4

Answer:

A = 50x^2+3

B = 75

C = 55

Step-by-step explanation:

[tex]f(x)=2x^2+3\\g(x)=5x[/tex]

A. f(g(x))

[tex]2(5x)^2+3\\2(25x^2)+3\\=50x^2+3[/tex]

B. g(g(3))

[tex]5(5(3))\\5(15)\\=75[/tex]

C. g(f(-2))

[tex]g(2(-2)^2+3)\\g(8+3)\\g(11)\\5(11)\\=55[/tex]

This is a geometric progression

So

The general formUla is

[tex]\\ \rm\Rrightarrow a(n)=ar^{n-1}[/tex]

[tex]\\ \rm\Rrightarrow a(n)=\dfrac{1}{4}\left(\dfrac{1}{4}\right)^{n-1}[/tex]

Answer:

[tex]\displaystyle \lim_{n \to \infty} \dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]

Step-by-step explanation:

Series: the sum of the elements of a sequence.

Therefore, as the numbers have been defined as a series and we need to find [tex]S_n[/tex]:

[tex]\dfrac{1}{4}+\dfrac{1}{16}+\dfrac{1}{64}+\dfrac{1}{256}+...[/tex]

First determine if the sequence is arithmetic or geometric.

If it is an arithmetic sequence, there will be a common difference between consecutive terms.

if it is a geometric sequence, there will be a common ratio between consecutive terms.

From inspection of the terms, we can see that there is a common ratio of 1/4, as each term is the previous term multiplied by 1/4, so it is a geometric series.

Sum of the first n terms of a geometric series:

[tex]S_n=\dfrac{a(1-r^n)}{1-r}[/tex]

Given:

[tex]a=\dfrac{1}{4}[/tex]

[tex]r=\dfrac{1}{4}[/tex]

Substitute the values of a and r into the formula:

[tex]\implies S_n=\dfrac{\frac{1}{4}\left(1-\left(\frac{1}{4}\right)^n\right)}{1-\frac{1}{4}}[/tex]

[tex]\implies S_n=\dfrac{\frac{1}{4}\left(1-\left(\frac{1}{4}\right)^n\right)}{\frac{3}{4}}[/tex]

[tex]\implies S_n=\dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]

Therefore:

[tex]\displaystyle \lim_{n \to \infty} \dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]

The activity series is an arrangement of species in order of reactivity.

The activity series is an arrangement of species in order of reactivity. The position of a specie in the series determines the possibility of certain reactions.

The following are the fates of these reactions;

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Answer:

Step-by-step explanation:

Answer:

The answer is figure A, B, C, D.

Step-by-step explanation:

Because, polygon means a shape with more then 1 side, and in your pic all of the figures have more than one side, so that's the answer.

Answer:

(x+y)

Step-by-step explanation:

[tex] {x}^{2} - {y}^{2} = (x + y)(x - y)[/tex]

Thus, the HCF is (x+y).

Answer:

(x + y)

Step-by-step explanation:

Factorizing both terms :

The HCF of the terms is (x + y).

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

[tex]\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)[/tex]

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

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Answer:

Graph C

Step-by-step explanation:

Rearrange the terms so the equation is in slope-intercept form:
4x + y = 7
y = -4x + 7
The slope is -4, and the only graph that has a slope of -4 is graph C.

Answer:

3.2

The value of C when B is 5 is 3.2

Step-by-step explanation:

Answer:

It's the third one

Step-by-step explanation:

The cube root of 1/1000 is 1/10.

The cube root of c^9 is c^3.

The cube root of d^12 id d^4.

When you are doing to roots of variables, just divide :)

9/3 = 3

12/3 = 4

The numerical length of GH is 20.

Given, FH=4x+8, FG=x and GH=5x.

We need to determine the numerical length of GH.

In geometry, a line segment is a part of a line that is bounded by two distinct end points and contains every point on the line that is between its endpoints.

Given Point G is on the line segment FH, then FG + GH = FH.

Now, substitute the given values into the formula as shown:

x + 5x = 4x + 8

6x = 4x + 8

6x - 4x = 8

2x = 8

x=4

To get the length of GH substitute x=4 for 5x

That is, GH = 5(4)= 20

Hence, the numerical length of GH is 20.

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The value of pi determined is same when used the circumference formula and the formula of area.

A circle is a round shaped figure , whose all the point lie on same plane.

It is given that

The value of pi is about 3.14, and it is the same when using both the area and circumference.

The circumference is found by

Circumference = π * diameter

For circle A:

25.12 = π * 8

π = 3.14

For circle B:

9.42 = π * 3

π = 3.14

The area is given by

Area = π * diameter² / 4

For circle A:

50.24 = π * (8²)/4

π = 3.14

For circle B:

7.065 = π * (3²)/4

π = 3.14

The value of pi is about 3.14,

The value of pi determined is same when used the circumference formula and the formula of area.

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Answer:

a) The mass of a box of bolts is greater.

b) 3/20 kg

Step-by-step explanation:

a) Firstly, you have to make the denominators of the two fractions the same (by finding the LCM of the denominators).

The LCM of 4 and 5 is 20.

Converting 3/4 into denominator 20:

[tex]\frac{3 * 5}{4 * 5}[/tex]

= 15/20

Converting 3/5 into denominator 20:

[tex]\frac{3 * 4}{5 * 4}[/tex]

= 12/20

Now comparing the numerators:

15 > 12

Hence,

3/4 > 3/5

b) Difference of the boxes can be done by subtracting the numbers with the same denominator:

15/20 - 12/20

= 3/20 kg

Hope this helps and feel free to give me brainliest! :)

Step-by-step explanation:

4.500 mm³ → cm³

1 cm³ = 1.000 mm³

= 4.500 ÷ 1.000

= 4,5 cm³ IS THE ANSWER

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = -3 [/tex]

[tex]\qquad \tt \rightarrow \: f(2) = 1[/tex]

[tex]\qquad \tt \rightarrow \: f(4) = 1 [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

F(x) represents the value of y on curve for given value of x

[tex] \textsf{\large First -} [/tex]

[tex]\qquad \tt \rightarrow \: f(0) =( 0) {}^{2} - 3[/tex]

[ since 0 < 2 ]

[tex]\qquad \tt \rightarrow \: f(0) = 0 {}^{} - 3[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = - 3[/tex]

[tex] \textsf{\large Second} [/tex]

[tex]\qquad \tt \rightarrow \: f(2) = (2) {}^{2} - 3[/tex]

[ since 2 = 2 ]

[tex]\qquad \tt \rightarrow \: f(2) = 4{}^{} - 3[/tex]

[tex]\qquad \tt \rightarrow \: f(2) = 1[/tex]

[tex] \textsf{\large Third -} [/tex]

[tex]\qquad \tt \rightarrow \: f(4) = - 4 + 5[/tex]

[ since 4 > 2 ]

[tex]\qquad \tt \rightarrow \: f(4) = 1[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

9

Step-by-step explanation:

Answer:

1 (2/3) or 1.66666667

Step-by-step explanation:

The slope of a line is found by using the equation :

y2 - y 1 / x2 - x1

So all we have to do is plug in our values given.

To find which belongs with which variable (such as x2 or y1), we do the following:

We know that the coordinates of a point are represented by (x, y). So we must assign a number to each points number.

(2, 8) will be x1 and y1.

(5, 13) will be x2 and y2

Plug in the values :

13 - 8 = 5

5 - 2 = 3

5 / 3 = 1 (2/3)

So, the slope of the line is 1.66666667 or 1 and (2/3)s

Answer:

34.3 square unit.

Step-by-step explanation:

[tex]calculate \: df \: using \: pythagoras \\ theorem \\ df {}^{2} = 8 {}^{2} + 6 {}^{2} \\ df {}^{2} = 64 + 36 \\ df {}^{2} = 100 \\ df = \sqrt{100} \\ df = 10 \\ calculating \: for \: the \: area \: of \: \\ angle \: \: dfg \\ using \: heros \: formular \\ \\ area = \sqrt{s(s - a)(s - b)(s - c)} \\ s = \frac{a + b + c}{2} \\ s = \frac{10 + 11 + 7}{2} = \frac{28}{2} = 14 \\ area = \sqrt{14(14 - 10)(14 - 11)14(14 - 7)} \\ area = \sqrt{14(4)(3)(7)} = \sqrt{14 \times 84} \\ area = \sqrt{1176} = 34.2928564 \\ to \: the \: nearest \: tenth \: = 34.3[/tex]

Here it is stated that, side DE = 8 units, side EF = 6 units, side FG = 7 units and side GD = 11 units. We have to find area of ∆DFG, here we will use heron's formula which is given by:

Area of ∆ = √[s(s – a) (s – b) (s – c)]

Here a, b, and c are sides of ∆. We have;

So firstly lets calculate a i.e DF by using Pythagoras theorem on ∆DEF:

➸ DF² = 8² + 6²

➸ DF² = (8 × 8) + (6 × 6)

➸ DF² = 64 + 36

➸ DF² = 100

➸ DF = √(100)

➸ DF = √(10 × 10)

➸ DF = 10 units

Now, lets calculate s i.e semi - perimeter:

Now, using heron's formula on ∆DFG to calculate its area:

➸ Area(∆DFG) = √[14(14 – 10) (14 – 7) (14 – 11)]

➸ Area(∆DFG) = √[14(4) (7) (3)

➸ Area(∆DFG) = √(14 × 4 × 7 × 3)

We can write it as;

➸ Area(∆DFG) = √(2 × 2 × 2 × 7 × 7 × 3)

➸ Area(∆DFG) = 2 × 7√(2 × 3)

➸ Area(∆DFG) = 14√(6)

➸ Area(∆DFG) = 14 × 2.449

➸ Area(∆DFG) = 34.28

➸ Area(∆DFG) = 34.3 square units (approx)

By looking at the graph of the piecewise function, we can see that:

On the graph, we have a piecewise function, which we want to evaluate in some different values.

First we have x  = -0.0001

This value belongs to the interval (-5, 0), and by looking at the graph, you can see that the function on that interval is equal to -9, then:

G(-0.0001) = -9

x = 0

x = 0 belongs to the interval [0, 9). On that interval the function values -1. (x = 0 belongs to that interval because we have a closed dot). Then we conclude

G(0) = -1

x = 0.0001

This value also belongs to the interval  [0, 9)

Then G(0.0001) = -1

Finally, x = 9.

If you look at the domain of the function, you can see that there is an open dot at x = 9.

This means that x = 9 does not belong to that domain, so:

G(9) is not defined.

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Answer:

The only methods allowed are

-  "Subtract equation 2 from equation 1,"  and "Multiply equation 1 by 2. Then add the new equation to equation 2"

-

Step-by-step explanation:

Subtract Eq 2 from Eq 1:

3x-2y=7

-3x-4y=-17

-6y = -10

y = (5/3)

Use y =(5/3) to solve for x in both equations.

x=(31/9)

Subtract the left side of equation 2 from the left side of equation  No, this is not a legal operation.  

Multiply equation 1 by 2. Then add the new equation to equation 2  Yes, this works.  Instead of solving for y first, this method solves for x, which can then be used to find y:

2(3x-2y=7)

  6x-4y=14

  3x+4y=17    

   9x = 31    (y is eliminated)

x = (31/9)

Now use this to find y in either equation:

3x-2y=7

3x-2(31/9)=7

y = (5/3)

Answer:

A. (6x + 7)(6x - 7)

Step-by-step explanation:

use difference of squares, which says a^2 - b^2 =(a+b)(a-b)

take the square roots of the two numbers, 6x and 7, and use them as a and b

Answer:

-69

Step-by-step explanation:

inches:-69

-5 9/12 (-5 3/4 clearer) feet

Explanation in detail:

Write the equation down and distribute it.

3x - 1 = 2(x + 34)

3x - 1 = 2x + 68

Remove the variable on one side first (it makes solving the equation less complicated.)

3x - 1 = 2x + 68

-3x -3x

-1 = -x + 68

On all sides, subtract 68.

-1 = -x + 68

-68 -68

-69 = x

I'm guessing the answer in feet and inches is...

inches:-69

-5 9/12 (-5 3/4 simplified) feet

The complete question is

"What is the component form of the vector represented by 2a when a =⟨−2,3⟩?"

The Component form of the vector represented by 2a is (-4,6)

The component form of a vector is represented by (x, y) that has gone x units left to the origin and y units up from the origin.

Given, a=(-2,3)

By using scalar multiplication,

2a = (2(-2), 2(3))

2a = (-4,6).

Therefore the component form of 2a=(-4,6)

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Answer:

the LCM of 18 25 40 80 81 and 72 is 226800

i hope this helps you

Step-by-step explanation:

by which method

prime factorization , division or defination method

Answer:

c

Step-by-step explanation:

Answer:

330.6

Step-by-step explanation:

You have to enter 290 for x.

T(290) = 290 + 0.14(290)

T(290) = 290 + 40.6

T(290) = 330.6

Triangles FGH and ABC are congruent because of the: AAS congruence theorem.

The AAS congruence theorem states that when two angles and one non-included side in one triangle are congruent to corresponding two angles and one non-included side in another triangle, then both triangles are congruent.

In the proof given, it is established that both triangles have two corresponding congruent angles, and also, BC ≅ GH which are non-included sides.

Therefore, both triangles are congruent because of the AAS congruence theorem.

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