Which is the graph of the system x + 3y > –3 and y < One-halfx + 1?

Answers

Answer 1

Step-by-step explanation:

hope it helps you understand

Which Is The Graph Of The System X + 3y &gt; 3 And Y &lt; One-halfx + 1?

Related Questions

solve for y in 1/8^2-3y=2^y-2

Answers

The value of y is 2.33924.

What is equation?

An equation in math is an equality relationship between two expressions written on both sides of the equal to sign.

Given:

(1/8)²-3y = [tex]2^{y}[/tex]-2

1/64 - 3y =  [tex]2^{y}[/tex]-2

1/64+ 2 =  [tex]2^{y}[/tex]+3y

129/2 =  [tex]2^{y}[/tex]+3y

Taking log on both side

log 129 - log 2 = y log 2 + 3 log y

2.11 - 0.301 = 0.301 y + 3 log y

1.809 = 0.301 y + 3 log y

1.809/3= 0.1 y + log y

0.603 = 0.1 y + log y

y = [tex]10^{\frac{603-100y}{1000}}[/tex]

y= 2.33924

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What are the zeros of the quadratic function f(x) = 2x² + 16x - 9?
7
O x = -4 -
-√7
and x = -4 +
+√√2/2
O x=-4- 25
and x = 4 +
-
2
21
0 x = -4-√²/²
and x = -4 +
2
41
Ox=-4-
and x = -4 +
2
|~~
25
2
21
2
41
2

Answers

The zeros of the quadratic function f(x) = 2x² + 16x - 9 are given as follows:

[tex]x = -4 + \sqrt{\frac{41}{2}}, x = -4 - \sqrt{\frac{41}{2}}[/tex]

What is a quadratic function?

A quadratic function is given according to the following rule:

[tex]y = ax^2 + bx + c[/tex]

The solutions are:

[tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a}[/tex]

[tex]x_2 = \frac{-b - \sqrt{\Delta}}{2a}[/tex]

In which:

[tex]\Delta = b^2 - 4ac[/tex]

In this problem, the equation is given by:

f(x) = 2x² + 16x - 9.

The coefficients are a = 2, b = 16, c = -9, hence:

[tex]\Delta = 16^2 - 4(2)(-9) = 328[/tex]

Then:

[tex]x_1 = \frac{-16 + \sqrt{328}}{2(2)} = -4 + \sqrt{\frac{41}{2}}[/tex]

[tex]x_2 = \frac{-16 - \sqrt{328}}{2(2)} = -4 - \sqrt{\frac{41}{2}}[/tex]

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r=
help me please thank u​

Answers

Answer:

[tex]\fbox {r = 34}[/tex]

Step-by-step explanation:

Finding IQ and RJ by tangent rule :

⇒ IQ = QK = 10

⇒ KR = RJ = 8

Finding PJ :

⇒ PJ = 32 - 8

⇒ PJ = 24

∴ But PJ = PI (by tangent rule)

⇒ PI = 24

Finding r :

⇒ PI + IQ

⇒ 24 + 10

r = 34

9^2 times 9^-6 exponential form

Answers

The result of the expression in exponential form is 9^-4

Product of exponents

Given the expression below

[tex]9^2 \times 9^{-6}[/tex]

According the product law, since the base are equal, we will add the exponent to have:

[tex]9^2 \times 9^{-6}=9^{-6+2}\\9^2 \times 9^{-6} = 9^{-4}[/tex]

Hence the result of the expression in exponential form is 9^-4

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Eugenia rolls a six-sided number cube. What is the probability that she gets a number greater than 4? A. 1/6 B. 1/3 C. 2/3 D. 5/6

Answers

The probability that she gets a number greater than 4 is 1/3

How to determine the probability?

A six-sided number cube has the following properties:

Faces = 6

Numbers greater than 4 = 2

The probability that she gets a number greater than 4 is calculated as:

P = 2/6

Simplify

P =1/3

Hence, the probability that she gets a number greater than 4 is 1/3

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What is the inverse of the function f(x) = 2x +1?

Answers

Answer:

y=0.5(x−1)

Step-by-step explanation:

Explanation: To find the inverse of a function, you have to substitute y for x in the equation and simplify to get a normal equation again. In this case, f(x) is y.

y=2x+1

x=2y+1

2y+1=x

2y=x−1

y=0.5(x−1)

Answer

[tex]y=\frac{x-1}{2}[/tex]

Step-by-step explanation:

To find the inverse of a function  [tex]f(x)=2x+1[/tex] , we substitute x and y for each other and then solve for y to get a new function.

We rewrite the original function as:

[tex]x=2y+1[/tex]

And then we solve for y:

[tex]x-1=2y[/tex]

[tex]y=\frac{x-1}{2}[/tex]

This is our answer.

Gene has a gasoline budget of $300 per month. He uses an average of $6 of gasoline each day he drives. Which of the following equations represents how much money is left in his gasoline budget after x days of driving?

Answers

Answer:

300-6x

Step-by-step explanation:

Trust me

Find the equation of the parabola that has zeros of x = - 6 and x = 6 and a yintercept of (0, 4) .

Answers

Since the zeros are symmetrical to the y axis, the equation can be written as
y=a(x-b)(x+b), where a is a scale factor and b is x intercept. By plugging in the zeros, you get y=A(x-6)(x+6). Now we can plug in the (0,4) and solve for a to get the scale factor.

4=A(0-6)(0+6)
4=A(-36)
-36A=4
A=-1/9

Therefore the equation is Y=-1/9(x-6)(x+6), or Y=-1/9(x^2-36)

Hope this helps!


(a - b)(2x-3)+(6x+7)(a+b)
Factorise

Answers

Answer:

2(4ax+2bx+2a+5b)

Step-by-step explanation:

If an employer reduces the working week from 40 hours to 35 hours, with no
loss of weedy pay, calculate the percentage increase in the hourly rate of pay.

Answers

Answer:

14.285714285714 %

Step-by-step explanation:

suppose the weekly payment is of x dollars

Then

Previous payment : $(x/40) per hour

New payment : $(x/35) per hour

Then

The percentage increase in the hourly rate of pay is :

[tex]=\frac{\frac{x}{35} -\frac{x}{40} }{\frac{x}{40} } \times100[/tex]

[tex]=\frac{\frac{5x}{1400} }{\frac{x}{40} } \times100[/tex]

[tex]=\frac{5x}{1400} \times \frac{40}{x} \times100[/tex]

[tex]=\frac{200}{1400} \times100[/tex]

[tex]=\frac{1}{7} \times100[/tex]

[tex]=14.285714285714[/tex]

Examine the following dot plot.


A dot plot with 1 dot above 5, 1 dot above 10, 1 dot above 20, 2 dots above 30, 5 dots above 40, and 6 dots above 50.


© 2018 StrongMind. Created using GeoGebra.



Which answer correctly describes the shape of the data in the dot plot?


right-skewed


left-skewed


symmetrical


uniform

Answers

The data in the plot is Right skewed.

Therefore , Option A is the right answer

What is a Right skewed ?

A right skewed distribution means most of the data lies to the right side of the graph's peak.

A dot plot is given and observing the data it can be seen that peak is towards the right side of the graph.

Thus the data in the plot is Right skewed.

Therefore , Option A is the right answer.

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Jack goes to a restaurant in a state with a 7.25% sales tax. He buys a
meal and tips 20% before tax. Select the meal cost that would allow his
total bill, including tip and tax, to have a total cost equal to $15.

Answers

The meal cost spent by Jack at the restaurant if he spent $15 including tip and bill is $11.79.

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the meal cost, hence:

Total cost = x + 0.2x + 0.0725x

15 = 1.2725x

x = 11.79

The meal cost spent by Jack at the restaurant if he spent $15 including tip and bill is $11.79.

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Find the values of a and b 3 * 2 = a + b if​

Answers

value of a = 3

value of b = 2

a + b = 3 + 2 = 5 .

If two angles have the same angle measure, then they are said to be____.

A. Complementary
B.adjacent
C.congruent

Answers

Answer:

C

Step-by-step explanation:

2 equal angles are said to be congruent

Congruent angles have the same measure is answer is C

the population of blackbirds in a park is counted every year.
the population decreases by 24% to 323
what was the original population?

Answers

Answer:

the original population was 425

Step-by-step explanation:

Answer:

425

Step-by-step explanation:

Let the original population of blackbirds be x.

Original population              decreases by                   New population

          100                                     24                                       76

            x                                        24                                     323

Now we can make an expression like this.

100  ⇒  76

x     ⇒   323

And now let us use cross multiplication and solve for x.

Let us solve it now.

323 × 100 = 76x

32300 = 76x

425=  x

write the equation of the line that contains (-4, -3) and is parallel to the line x+2y=-10

Answers

Introduction

Hello! I hope you are having a nice day. My name is Galaxy and I will be helping you with this problem. We can solve this problem in 2 steps, respectively Theory and Solving.

I'll go ahead and start with the Theory.

Theory

Before we attempt to solve the problem mathematically, we must first figure out how we're going to solve this problem.  

We know that we have a line and a point, we can start by graphing the equation and point that we've received.

Solving

Now that we have our points plotted and our equations graphed, we can start to see that something odd is happening, the given point is on the line itself.

We can check this by inputting the points into our equation:

[tex](-4)+2(-3)=-10?\\(-4)+(-6)=-10?\\-10=-10[/tex]

This proves that our point is on the line that we were given.

According to the basic rules of Euclidean Geometry, we know that parallel lines can never intersect each other and due to this there cannot be any solution to this problem.

Any other line using this point would intersect the given line, and due to this, this problem has no real solutions.

* The only line that can use these points and graph is the line provided, and that cannot work due to the lines intersecting at an infinite number of points.

Cheers,
Galaxy.

What is the equation of the line that passes through (-3, 4) and (3, -2)?

y = - x - 1
y = x + 7
y = x - 1
y = - x + 1

Answers

Answer:

y = -x +1

Step-by-step explanation:

p1 (-3,4)

p2 ( 3, -2)

line equation y = mx + b

The slope m equals

[tex] \frac{y2 - 21}{x2 - x1} [/tex]

[tex] \frac{ - 2 - 4}{3 - - 3} = \frac{ - 6}{6} = - 1[/tex]

y = - x + b

from any point

-2 = -3 + b

b = 1

line equation = y = -x +1

Just plugging the points into the equations, both fit y=-x+1

Hope this helps

Please help!!
Construct the circle that circumscribes image DEF.

Answers

Answer:

See below

Step-by-step explanation:

General outlineConstruct the perpendicular bisectors of DE, EF, and DF.Identify the circumcenter. Draw the circumcircle.

Circles & Circumcircles

To construct a circle, one must know the center point of the circle, and the circle's radius.
The circle that circumscribes a triangle (called a circumcircle), has a circumcenter (center point) that is the point of concurrency (a point where more than two lines intersect at the same point) of all three perpendicular bisectors (perpendicular lines that happen to cut a given line segment exactly in half) of the sides of the triangle.

Construct the circle with a center at the circumcenter, and a radius out to any one of the vertices of the triangle.  The circumcenter is equidistant from all three vertices, so the circle draw will contain all three vertices.

Constructing perpendicular bisectors

To construct perpendicular a bisector, recall that a perpendicular bisector is a line containing all points that are equidistant the end points of a line segment (each point on the line is the same distance from both segment endpoints simultaneously).

So, if we can find two points that are the equidistant from the two segment endpoints, we'll have two points on the line, and to draw any line, one only needs two distinct points, and the straightedge.

Finding a point that is equidistant from two given points

Set the compass to any radius that is larger than half the distance between the two endpoints.  If uncertain of a "good" choice, one can simply choose the length of the line segment itself as a radius.

Setting the center of the compass circle on one endpoint, draw an arc such that the arc will pass through the perpendicular line we're trying to construct twice.  If uncertain, draw the entire circle.  Keeping the radius saved.

With the same radius, setting the center of the compass circle to the second endpoint, draw and arc such that the arc intersects the first circle two times.  If it doesn't intersect two times, the radius chosen at the beginning was too small.  Start the entire process over with a larger radius.

These two points of intersection are equidistant from the two endpoints of the line segment, and thus, they are on the perpendicular bisector of the line segment.

Using those two points, and a straightedge, draw the line containing those two points, and extend it generously in both directions.

Process

Steps 1-5 in pink; steps 6-10 in green; steps 11-15 in blue (see diagram):

Set compass radius to length DEDraw circle, centered at D, through E.  Keep radius set.Draw circle, centered at E, through D.Identify points of intersection of the circles from steps 2 & 3, M & NDraw line  MNSet compass radius to length EFDraw circle, centered at E, through F.  Keep radius set.Draw circle, centered at F, through E.Identify points of intersection of the circles from steps 7 & 8, Q & RDraw line  QRSet compass radius to length DFDraw circle, centered at D, through F.  Keep radius set.Draw circle, centered at F, through D.Identify points of intersection of the circles from steps 12 & 13, S & TDraw line  STIdentify point of concurrency of line MN, line QR, and line ST;  label it point PSet compass radius to length DP (or EP, or FP)Draw circle, centered at P, through points D, E, and F.

Note:  Since all three perpendicular bisectors intersect at the same point, it is only necessary to find two of three, not all three.  So, one could skip constructing one of those three perpendicular bisectors (either steps 1-5, 6-10, or 11-15), and still be able to construct the circumcircle correctly.

Solve by elimination
show your work
y = 3x + 10
y = 2x - 8
​im giving brainlyest

Answers

Answer:

[tex]x=-18, y=-44[/tex]

Step-by-step explanation:

[tex]y=3x+10\\y=2x-8\\\\3x+10=y\\2x-8=y\\3x-y=-10\\2x-y=8\\\\-2(3x-y=-10)\\3(2x-y=8)\\\\-6x+2y=20\\6x-3y=24\\-y=44\\y=-44\\-44=3x+10\\-54=3x\\x=\frac{-54}{3} \\x=-18\\\\x=-18, y=-44\\[/tex]

CHECK

[tex]-44=3(-18)+10\\-44=-54+10\\-44=-44\\\\-44=2(-18)-8\\-44=-36-8\\-44=-44[/tex]

Logarithm of x to the root 2 + logarithm (x-1) to the root 2 = 1

Answers

By the application of algebraic procedures and logarithm properties, the roots of the logarithmic equation [tex]\log \sqrt{x} + \log \sqrt{x-1} = 1[/tex] are x = 2 and x = -1.

How to solve a logarithmic functions

In this question we need to solve a logarithmic equation by means of algebraic procedures and logarithm properties:

[tex]\log \sqrt{x} + \log \sqrt{x-1} = 1[/tex]

[tex]\log \sqrt{x\cdot (x-1)} = 1[/tex]

[tex]\log \sqrt{x^{2}-x} = 1[/tex]

[tex]\frac{1}{2}\cdot \log (x^{2}-x) = 1[/tex]

[tex]\log (x^{2}-x) = 2[/tex]

[tex]x^{2}-x = 2[/tex]

[tex]x \cdot (x-1) = 2[/tex]

[tex]x - 1 = \frac{2}{x}[/tex]

[tex]x - \frac{2}{x} = 1[/tex]

[tex]\frac{x^{2}-2}{x} = 1[/tex]

[tex]x^{2} - 2 = x[/tex]

[tex]x^{2}-x-2 = 0[/tex]

[tex](x-2)\cdot (x + 1) = 0[/tex]

[tex]x = 2 \,\lor \,x= -1[/tex]

By the application of algebraic procedures and logarithm properties, the roots of the logarithmic equation [tex]\log \sqrt{x} + \log \sqrt{x-1} = 1[/tex] are x = 2 and x = -1.

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Find the values of the variables indicated below

M=

K=

Answers

Answer:

m=120

k=60

Step-by-step explanation:

a trapezoid has 360 degrees. subtract 120 degrees to get 240 degrees. we know that m=2k. 240=2k+2k which is 4k. 240 is 4k. k=60. m=2k, so mulitply 60 by 2 to get m=120

Use finite differences to identify the degree of the polynomial that best describes the data. 9 10 11 12 13 14

Answers

The forward differences for this data is 1, 1, 1, 1, 1, 1 (since 10 - 9 = 1, 11 - 10 = 1, etc). Since we only need one iteration of differences, a linear polynomial will fit the data exactly.

It Sami anual Compound interest is applied interest, what instead of anual compound will be the profit of an investor It Sami anual Compound interest is applied interest , what instead of anual compound will be the profit of an investor.​

Answers

Answer:

it's helps with learning the difference of thr compound

Write an equation for a polynomial with all the following features:
a. The degree is 5. b. The polynomial has 4 terms.
c. The graph of the polynomial crosses the vertical axis at y = 12.
2. Identify the approximate input values of any relative maximums and minimums of
this 5th degree polynomial.

Answers

The answer is 72 using the theorem postulate formula

Solve this system of equations by
using the elimination method.
2x - 3y = 25
5x + 3y = 10
The ordered pair of solutions
is written in the format (x, y).
([?], [])
Enter

Answers

Answer:

(5,-5)

x=5

y=-5

Step-by-step explanation:

How to solve using elimination method.

First, add the two equations.

   2x - 3y = 25

+  5x + 3y = 10

7x=35

The y values got eliminated.

Next, divide 7 from both sides.

7x/7=35/7

x=5

Next, plug-in x=5 into one of the equations.

2(5) - 3y = 25

10-3y=25

Subtract 10 from both sides.

-3y=15

Divide -3 from both sides.

y=-5

Remember a positive divided by a negative is a negative.

Hope this helps!

If not, I am sorry.

Question Progress
Find the following, giving your answers
to 1 decimal place.
10 cm/
Homework Progress
17/21 Marks
6 cm
8 cm
a) The volume of the cone.
b) The curved surface area of the cone.
Vol = ²
Curved
surface area

Answers

Answer:

[tex]\pi \times radius \times hieght[/tex]

180 is equivalent to π/2 radians

true
false

Answers

Answer:

[tex]\fbox {False}[/tex]

Step-by-step explanation:

To convert a degree measure to radian measure, multiply with π/180.

⇒ 180 × π/180

⇒ π radians

false is the answers

please mark me as brainlest

please please help ME!!!

Answers

Answer:

720 Course Schedules

Step-by-step explanation:

When you choose the first course, there are 6 to choose from. When you scoose the second, there are only 5. This keeps going until the 6th course where there is only 1 choice.

You multiply these choices together. You should get 6×5×4×3×2×1

6×5=30

30×4=120

120×3=360

360×2=720

720×1=720

You then end up with 720 course schedules.

2 inches tall on week 4 3 inches tall on week 6 4 inches tall on
week 8

Answers

The linear relation of the height as a function of the number of weeks is:

y = 0.5*x

How to find the linear relation?

A general linear relation is written as:

y = a*x + b

Where a is the slope.

If we know that the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope is:

[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

In this case, we have the points of the form (week, height).

(4, 2)

(6, 3)

(8, 4)

If we use any two of these we can get the slope, so using the first two:

a = (3 - 2)(6 - 4) = 1/2 = 0.5

y = 0.5*x + b

To get the value of b, we can use the first point, it says that when x = 4, we have y = 2, then:

2 = 0.5*4 + b

2 = 2 + b

0 = b

Then the linear relation of the height as a function of the number of weeks is:

y = 0.5*x

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-3(2x-5)<5(2-x)
Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.

x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Answers

The correct option is an open circle at 5 and a bold line starts at 5 and is pointing to the right.

The given inequality is -3(2x-5)<5(2-x).

What is inequality?

Inequality is a declaration of an order relationship between two numbers or algebraic expressions, such as greater than, greater than or equal to, less than, or less than or equal to.

At first simplify each side

LHS of inequality -3(2x - 5) = -3(2x) + -3(-5) [∵(-)(-) = (+)]

⇒ -3(2x - 5) = - 6x + 15

Now, RHS of the inequality 5(2 - x) = 5(2) + 5(-x) [∵(+)(-) = (-)]

⇒ 5(2 - x) = 10 - 5x

Now, - 6x + 15 < 10 - 5x

Subtract 15 from both sides

That is, - 6x < -5 - 5x

Add 5x to both sides

That is, - x < - 5

Remember the coefficient of x is negative, and then when you divide both sides by it you must reverse the sign of inequality.

Now, the coefficient of x is -1

So, divide both sides by -1

Then, x > 5.

Hence, the correct option is an open circle at 5 and a bold line starts at 5 and is pointing to the right.

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