Brittany removed half of the total number of marbles from her bag, and gave one fourth of the remaining marbles to her friend. What fraction of the total number of marbles is left in the bag? A) 1/4, B) 3/8, C) 1/2, D) 7/8​

Answer:

3 gallons

Step-by-step explanation:

For every value of green ( 'x') ....white is 3 times as much

  for 1 gallon green     ====> 3 gallons white

Answer:

Blank 1 = SAS

Blank 2 = HL

Black 3 = ASA

Blank 4 = SSS

Answer:

The relationship between the scale factor and perimeter of an image and its pre-image is a, b = perimeter = 2a + 2b. the relationship between the scale factor and area of an image and its pre-image is k∧2 (ab).

Step-by-step explanation:

Relationship between the scale factor and perimeter of an image and its pre-image.

Scale factor = k

Pre-image lengths: a, b = perimeter = 2a + 2b

Image lengths: ka, kb = perimeter = 2ka + 2 kb = k (2a + 2b) = 2 * preimage perimeter.

She has to say that the perimeter of the image is the perimeter of the preimage times the same scale factor.

What should she say about the relationship between the scale factor and area of an image and its pre-image?

area of the pre-image = ab

are of the image = (ka)(kb) = k^2 (ab)

The area of the image is the area of the preimage times the square of the scale factor.

Support her statements using scale factors of 5 and 6.

Scale factor 5

length of the pre-image = 3 x 4 = perimeter = 2 (3 + 4) = 2(7) = 14

length of the image = 3*5 x 4*5 = 15 x 20 = perimeter = 2 (15 + 20) = 2 (35) = 70

14 * 5 = 70 which shows the prediction

area of the pre-image = 3 * 4 = 12

area of the image = 15 * 20 = 300

12 * (5^2) = 12*25 = 300 which is the value predicted.

Now you can do the same using scale factor 6.

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Answer:

My guess would be D

Step-by-step explanation:

The probability of 6 years or more, so we want the complement,

1 - 0.98533 = 0.01467                        1.467% chance, not very likely.

A z score is a type of statistical measurement that gives an idea of how far a raw score is from the mean of a distribution. A z score is used in a z test for hypothesis testing.

Here, Because you are looking for the mean of a group of 7.8, the standard deviation will shrink by a factor of √6

Old standard deviation = 0.7,

new standard deviation = 0.7/√6 = 0.64254

You need to find a z-score and then convert your z-score to a probability.

z-score = (your score - average)/ std dev

z-score = (7.8 - 6)/0.64254

z-score = 2.1789

To convert a z-score either look it up on a table or use a calculator.

But z-tables are designed to shade to the left, which means this is the probability that the mean life is 6 years or less. We want the probability of 6 years or more, so we want the complement, 1 - 0.98533 = 0.01467

1.467% chance, not very likely.

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The value of e:g is 2:7.

A ratio indicates how many times one number contains another.

Given:

e:f=3:7

f:g=2:3

Now take LCM of 2 and 7 i.e., 14.

e/f= 3/7= 3*2/7*2= 6/14

and, f/g= 2/3= 2*7/3*7= 14/21

So,

e/g= e/f *f /g

     = 6/14*14/21

     = 6/21

e:g = 2:7

Hence, the value of e:g is 2:7.

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The length of the rectangle is 100cm.

The breadth of the rectangle is 4cm.

The square encloses more area than the rectangle.

The first step is to determine the area of the square.

Area of a square = length² = 50² = 2500 cm²

Area of a rectangle = length x width

length = area / width

2500 / 25 = 100cm

The first step is to determine the perimeter of the square.

Perimeter = 4 x length

4 x 5 = 20cm

Perimeter of a rectangle = 2(length + width)

breadth = (perimeter / 2) - length

(20 / 2) - 6

10 - 6 = 4cm

Area of the square = 5 x 5 = 25

Area of the rectangle = 6 x 4 = 24

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The parabola has roots at x=3 and x=-1, so its vertex is halfway between those points, at x=1, and so the y-coordinate of the vertex is -(1-3)(1+1)=4.

Another point that lies on the parabola is (-1, 0).

When reflected over ry-axis (x, y) (-x, y) , rx-axis (x, y) (x,-y) , Option A and D is the correct answer.

The rule for reflection is when an object or a coordinate point is reflected over x axis then the coordinate of the x axis remains the same while the y coordinate changes to be additive inverse.

Vice Versa happens when reflected over y axis.

So,

rx-axis (x, y) - (-x, y) --> (x,-y)

ry-axis (x, y) (-x, y)

Therefore Option A and D is the correct answer.

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Answer: its A not A & D

Step-by-step explanation:

The standard deviation of the data to the nearest hundredth is 173.01.

Standard deviation is used to determine how the values in a group differs from the mean of the values in the group. It is a measure of variation.

In order to determine the standard deviation, take the following steps:

Determine the mean of the observation: 185

Determine the difference between each value and the mean and then square the result:

Determine the mean of the sum of the squared differences and then find the square root of the mean:

Following these steps, the standard deviation is 173.01

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Answer:

445

Step-by-step explanation:

I think it is 445 because each term is +1 and time is the number of terms you want to find.

So

(2+1) time 2 = 6

(6+1) time 3 = 7

(88+1)  time 5 = 445

Answer:

The account has $18,795.02.

Step-by-step explanation:

The account has $18,795.02.

3 years * $535 = $1,605

$1,605 * .0034 = $5.481

$5.481 * 36 (months) = $197.146

$18,795.02 = $1,605 + $197.146

Answer:

C

Step-by-step explanation:

A and B are wrong because 37 is prime. 31 is prime and 33 is divisible by 11 and 3 so C

Answer:

A = 13 degrees

B = 65.3 degrees

C = 180 - (13 + 65.3) = 101.7 degrees

Side a = 35 km

Side b = 141.4 km

Side c = 152.4 km

The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

P(A and B) = P(A) . P(B|A)

When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

[tex]\mathrm{P(B|A)=\frac{P(A~and~B)}{P(A)}}[/tex]

Hence the correct match are -

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[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

Answer:

Area of smaller square = [tex]\tt\underline{5cm}[/tex][tex]\tt{\times 5cm = }[/tex][tex]\tt\underline\green{25}[/tex] [tex]\tt{sq.cm}[/tex]

Area of bigger square = [tex]\tt{15cm \times}[/tex][tex]\tt\underline{ 15cm }[/tex][tex]\tt{=}[/tex] [tex]\tt\underline\green{225}[/tex] [tex]\tt{sq.cm}[/tex]

Total Area = [tex]\tt\underline\green{25sq.cm}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{225sq.cm}[/tex] [tex]\tt{=}[/tex] [tex]\normalsize \underline{\boxed{\tt \red{250}}}[/tex] [tex]\tt\underline{sq.cm}[/tex]

[tex]\\[/tex]

Area of square A = [tex]\tt\underline{7m}[/tex][tex]\tt{\times}[/tex][tex]\tt\underline{7m}[/tex][tex]\tt{=}[/tex][tex]\tt\green{49}[/tex] [tex]\tt{sq.m}[/tex]

Area of square B = [tex]\tt{7m}[/tex][tex]\tt{\times}[/tex][tex]\tt{7m}[/tex][tex]\tt{=}[/tex][tex]\tt\underline\green{49}[/tex] [tex]\tt{sq.m}[/tex]

Area of square B = [tex]\tt{14m}[/tex][tex]\tt{\times}[/tex][tex]\tt\underline{14m}[/tex][tex]\tt{=}[/tex][tex]\tt\green{196}[/tex] [tex]\tt{sq.m}[/tex]

Total Area = [tex]\tt\underline\green{49m}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{49m}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{196}[/tex] [tex]\tt{=}[/tex][tex] \normalsize \underline{\boxed{\tt \red{294}}}[/tex][tex]\tt{sq.m}[/tex]

====================================

To find the area of square use this formula [tex]\large\tt{A = s \times s}[/tex]. Means side of the square multiply to the same side of the square

[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

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૮₍´˶• . • ⑅ ₎ა

Answer

T-axis of his graph should go from 0 to at least 720, and the h-axis of his graph should go from 0 to at least 40.

Explanation

We know form our problem that  is the total pay,  is the number of hours, and $18 is the rate per hour, so putting it all into an equation we get:

We also know that James works between 25 and 40 hours each week, so we can replace the number of hours in our equation to get how much he can make per week:

- For

- For

Now we know that he can make between $450 and $720 working between 25 and 40 hours per week. So, to best show this information the T-axis should go from 0 to at least 720; otherwise, we won't be able to show values between $450 and $720. Similarly, the h-axis should go form 0 to at least 40; otherwise, we wont be able to show values between 25 and 40 hours.

Answer:

height = 8m

radius = 6m

Surface area of the cylinder = 2 Pie r h

= 2* 3.14 * 6 * 8

= 6.28 * 48

= 301.4 sq meters

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:sin(\theta) = \cfrac{2}{3} [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: \cos {}^{2} ( \theta) + \sin {}^{2} ( \theta) = 1[/tex]

[tex]\qquad \tt \rightarrow \: {\bigg( \cfrac{ \sqrt{5}}{3} \bigg) }^{2} + \sin {}^{2} ( \theta) = 1[/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{5}{9} + \sin {}^{2} ( \theta) = 1[/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{2} ( \theta) = 1 - \cfrac{5}{9} [/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{2} ( \theta) = \cfrac{9 - 5}{9} [/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{2} ( \theta) = \cfrac{4}{9} [/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{} ( \theta) = \sqrt \cfrac{4}{9} [/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{} ( \theta) = \pm \cfrac{2}{3} [/tex]

Generally, only positive value is taken :

[tex]\qquad \tt \rightarrow \: \sin {}^{} ( \theta) = \cfrac{2}{3} [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The complete question is :

Question: What is the coefficient in the expression 10x²-7?

The coefficient in the expression [tex]10x^{2} -7[/tex] is 10

A numerical or constant quantity placed before and multiplying the variable in an algebraic expression.

According to the question,

The expression given is [tex]10x^{2} -7[/tex]

The variable given is x

We need to find the coefficient in the expression.

In the given expression x is the variable and the number before the x is coefficient which is 10 .

Hence the coefficient in the expression is 10.

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Answer:

Solution:

Here,

[tex]\begin{array}{ | c| c c | } \hline\ \ \text{length \: of \: iron \: rod}& \text{weight} \\ \hline 13 \rm{m}& \rm{23.4kg} \\ \hline \rm{6m}&?\\ \hline\end{array}[/tex]

Weight of 13 m of rod=23.4 kg

Weight of 1 m of rod=23.4/13 kg

[less length,less weight]

Weight of 6 m of rod=23.4/13 ×6 kg=10.8 kg

[more length,more weight]

Thus,the weight of 6 m of rod is 10.8 kg.

Alternative method:

Let,the required weight be x kg.

Then,

[tex]\begin{array}{ | c| c c | } \hline\ \ \text{length \: of \: iron \: rod}& \text{weight} \\ \hline \rm{13m}& \rm{23.4 \: kg }\\ \hline \rm{6m}& \rm{x =? } \\ \hline\end{array}[/tex]

We know that,

More length of iron rod([tex]\red{\uparrow}[/tex]) will have the more weight([tex]\red{\uparrow}[/tex]).

So,using the rule of direct proportion;

i.e. Ratio of length=Ratio of weight

[tex] \displaystyle{ \frac{13}{6} = \rm\frac{23.4}{x} }[/tex]

[tex] \rm{13x = 6 \times 23.4}[/tex]

[tex] \rm{x = \displaystyle{ \frac{6 \times 23.4}{13} }}[/tex]

[tex] \therefore{x = 10.8}[/tex]

Thus,the weight of 6 m long iron rod is 10.8 kg.

I presume you meant [tex]y=-2\sqrt{x-3}+2[/tex].

The graph is shown in the attached image.

Answer:

y-4=-1/2(x-4)

Step-by-step explanation:

point slope form: y-y1=m(x-x1)

every time x increases by 8, y decreases by 4. slope can be found by rise/run. the slope is -4/8 which is -1/2, which means m=-1/2. in the given equation, it said y-4. It plugged in 4 for y1, meaning it was talking about the second given point, which was (4,4). plug in 4 for x and you get y-4=-1/2(x-4)

Answer:

Your answer would be A.

Step-by-step explanation:

okay so, with a best fit line, it needs to match up with your points. unless your points go up evenly. its not going to connect to all your points.

There are 540 fuses in total and the original price of the internet is $55.91

a) We know that 5% of the fuses are faulty, and there are 27 faulty fusses, then we can write:

5% = 27

100% = x

We want to find x, to do that, we can write:

x = 27*(100%/5%) = 27*20 = 540

There are 540 fuses in total.

b) Now we know that the original price is P, and when we decrease it by 7%, then new price is $52.00

Then we can write:

$52.00 = P*(1 - 7%/100%)

$52.00 = P*(0.93)

$52.00/0.93 = P = $55.91

The original price is $55.91

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The answer to the question on Parallelograms being rectangles is that; No; the diagonals may not be congruent

1) We cannot conclude that the parallelogram is a rectangle but we can say that all rectangles are parallelograms.

2) The explanation for number 1 above is that the parallelogram's diagonals may not be equal or congruent but in rectangles diagonals are always equal and bisect each other.

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Answer:

.wfhytrsssssssssd

Step-by-step explanation:

dddddddddddddddddd

Your question translates to computing [tex]3^{2020} \pmod {13}[/tex].

Recall Euler's theorem: if [tex]\gcd(a,n)=1[/tex] (that is, [tex]a[/tex] and [tex]n[/tex] are relatively prime), then [tex]a^{\varphi(n)}\equiv1\pmod n[/tex], where [tex]\varphi(n)[/tex] denotes Euler's totient function, which counts the number of positive integers relatively prime to [tex]n[/tex].

Since 13 is prime, we have [tex]\phi(13)=12[/tex]. Then by Euler's theorem,

[tex]3^{12} \equiv 1 \pmod{13}[/tex]

Now, observe that 2020 = 168×12 + 4, so that

[tex]3^{2020} \equiv 3^{168\times12+4} \equiv \left(3^{12}\right)^{168} \times 3^4 \equiv 1^{168} \times 3^4 \equiv 3^4 \pmod{13}[/tex]

and since 3⁴ = 81 = 6×13 + 3, we end up with

[tex]3^{2020} \equiv 81 \equiv 3 \pmod{13}[/tex]

so the remainder upon dividing 3²⁰²⁰ by 13 is 3.