The equivalent capacitance of these capacitors as they are arranged in series and parallel will be 0.093 μF and 71.1 μF.
What is a capacitor?A capacitor is a device that can store electrical energy. It is a two-conductor configuration separated by an insulating medium that carries charges of equal size and opposite sign.
If the capacitor is connected in the series the equivalent capacitance is found as;
[tex]\rm \frac{1}{c_{eq}} = \frac{1}{c_1} +\frac{1}{c_2} +\frac{1}{c_3} +\frac{1}{c_4} +\frac{1}{c_5} \\\\\ \rm \frac{1}{c_{eq}} = \frac{1}{10} +\frac{1}{50} +\frac{1}{9} +\frac{1}{2} +\frac{1}{0.1} \\\\\ \frac{1}{c_{eq}} = 0.1+0.02+0.11+0.5+10 \\\\ \frac{1}{c_{eq}} = 10.7 \\\\ c_{eq} = 0.093 \ \mu F[/tex]
If the capacitor is connected in parallel the equivalent capacitance,cₐ is found as;
cₐ= c₁+c₂+c₃+c₄+c₅
cₐ = 10+50+9+2+0.1 μF
cₐ =71.1 μF
Hence, the equivalent capacitance of these capacitors as they are arranged in series and parallel will be 0.093 μF and 71.1 μF.
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Two particles P and Q each moves towards ther along Straight Line (M)(N), 51m long. P starts from M with velocity 5m/s and constant acceleration Of 1m/s². Q Starts from N at the Same time with velocity 6m/s and at a Constant acceleration of 3m/s². find the time when the
a) Particles are 30m apart, 13
b) Particles meet
c) velocity of P is ¾ of the velocity of Q
The time required by the particles are as follows:
a. t = 1.5 seconds
b. t = 3 seconds
c. t = 0.4 seconds
What is the time required?The time required for the particles to be at several distances apart is calculated using the equation of motion given below:
[tex]S = ut + \frac{1}{2}at^{2}[/tex]
a) Time required to be 30 m apart:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51 - 30
S1 + S2 = 21
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 21
2t^2 + 11t - 21 = 0
Solving for time, t by factorization, t = 1.5 seconds
b) Time required to meet:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 51
2t^2 + 11t - 51 = 0
Solving for time, t by factorization, t = 3 seconds
c) Time required for velocity of P is ¾ of the velocity of Q:
Using the equation of motion: V = u + at
Vp = 3/4 Vq
4Vp= 3Vq
Substituting the values:
4(5 + t) = 3(6 + 3t)
5t = 2
t = 0.4 seconds
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Which has more mass - a 5-kg bag of feathers or a 5-kg
cannon ball?
Answer:equal mass
Explanation:the mass of both is 5kg
A 545 N sled is pulled a distance of 385 m. The task is done by pulling on a rope with a force of 1225 N at an angle of 19° with the horizontal. How much work is done in pulling the sled? What is the acceleration in the x direction, assuming that friction is negligible? Assuming the sled started at rest, how long does it take to pull the sled 185 m?
The work done in pulling the sled is 445,930.2 Joules.
The acceleration in the x direction, assuming that friction is negligible, is 20.85 m/s².
Time taken to pull the sled 185 m is 4.21s.
What is work done?Work done is equal to product of force applied and distance moved.
Given is a 545 N sled is pulled a distance of 385 m. The task is done by pulling on a rope with a force of 1225 N at an angle of 19° with the horizontal.
Work = Force x Distance x cos(angle)
W= 1225 x 385 x cos 19°
W = 445,930.2 Joules
Thus, the work done in pulling the sled is 445,930.2 Joules
From the Newton's second law of motion, we have'
F = ma
acceleration, a = 1225cos19° / ( 545 /9.81)
a = 20.85 m/s²
Thus, the acceleration in the x direction is 20.85 m/s²
Using the second equation of motion, we get
s = ut+ 1/2 at²
Substitute the values, we have
185 m = 0 +1/2 x 20.85 x t²
t = 4.21 s
Thus, the time taken to pull the sled 185 is 4.21s.
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Which scientific method could I use to test this hypothesis? "If the mass and the volume of an object are known, then its density can be calculated dividing the object's mass by its volume."
Answer:
Multiple so you can test multiple hypothesis at once
Explanation:
because
Answer:
To test the hypothesis, we need to make an observation or perform an experiment associated with the prediction. For instance, in this case, we would plug the toaster into a different outlet and see if it toasts.
inspired by answer up there
sorry i couldn't add details because think its bad
Hypothesis testing is a formal procedure for investigating our ideas about the world using statistics. It is most often used by scientists to test specific predictions, called hypotheses, that arise from theories.
which one of the following is true about Tesite stress
It is defined as the stress that results in the elongation of the material
An electric field is described by the vector e=yj -xi. what is the electric flux through a rectangular box in the x-z plane that is bounded by x between 0 and 1, and z between 0 and 1? (You need to identify dA to do this problem.)
The flux of [tex]\vec E = -x\,\vec\imath + y\,\vec\jmath[/tex] is given by the surface integral
[tex]\displaystyle \iint_S \vec E \cdot d\vec\sigma[/tex]
where [tex]S[/tex] is the given square region, which we can parameterize by
[tex]\vec s(x, z) = x\,\vec\imath + z\,\vec k[/tex]
with [tex]0\le x\le 1[/tex] and [tex]0\le z\le 1[/tex]. The area element is
[tex]d\vec\sigma = \vec n \, dx\,dz[/tex]
where [tex]\vec n[/tex] is the normal vector to [tex]S[/tex]. Depending on the orientation of [tex]S[/tex], this vector could be
[tex]\vec n = \dfrac{\partial\vec s}{\partial x} \times \dfrac{\partial\vec s}{\partial z} = -\vec\jmath[/tex]
or [tex]-\vec n = \vec \jmath[/tex]; either way, the integral reduces to
[tex]\displaystyle \iint_S \vec E \cdot d\,\vec\sigma = \int_0^1 \int_0^1 (-x\,\vec\imath + z\,\vec k) \cdot (\pm\vec\jmath) \, dx\,dz = \boxed{0}[/tex]
Jon and Jim push a dead car forward to the gas station. Jon pushes with 90N while Jim pushes 80 N.
The resultant of the two forces is about 170 N.
What is the resultant force?The term resultant force has to do with the single force that has the same magnitude and direction as two or more forces acting together.
In this case, the both forces are acting in the forward direction. This implies that the resultant force is 90 N + 80 N = 170 N.
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Proofread the following text and correct the 3 subject-verb disagreements.
Astronomers are telling people to be especially watchful this evening, as a rare event could be making a very special appearance. The release of energised particles from the sun , coupled with particularly helpful overnight conditions , are predicted to make the "Northern Lights" visible much further south than normal.
Interviewed earlier today, Derwent University's Professor Andrew Higgins said, 'Everybody are talking about it. It's a once-in-a-decade opportunity that people really shouldn't miss.'
He added: 'The forecasts given out by the weather office enables us to know when the skies will be clear. Either 11pm or 3am will be best, and I'll be over the moon if we get some good photos.'
(a) From the first sentence, particularly goes with condition.
(b) From the second sentence, everybody goes with is.
(c) From the third sentence, forecasts goes with enable.
What is subject verb agreement?In subject- verb agreement, if a subject is singular, its verb must also be singular and if a subject is plural, its verb must also be plural.
From the first sentence, the correct subject-verb agreement is;
The release of energised particles from the sun , coupled with particularly helpful overnight condition, are predicted to make the "Northern Lights" visible much further south than normal.
From the second sentence, the correct subject-verb agreement is;
'Everybody is talking about it. It's a once-in-a-decade opportunity that people really shouldn't miss.'
From the third sentence, the correct subject-verb agreement is;
'The forecasts given out by the weather office enable us to know when the skies will be clear.
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What is the energy of a photon of blue light with a frequency of 6.53 × 10¹4 Hz?
Answer:
V = 6.53 × 10^14
h = 6.626 × 10^-34
E = hV
E = (6.626 × 10^-34) (6.53 × 10^14)
E = 4.33 × 10^-19
a 2.50 cm tall object is 36.0 cm from a concave mirror with f=12.0 cm. find the image height.
The height of the image is -6 cm.
The reflecting surface of a concave mirror is curled inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.
Given that, an object placed 36 cm from a concave mirror having the focal length of 12 cm and height of image is 2.50 cm
We have to find height of the Image
Using Mirror Formula:
1/f = 1/v + 1/u
Where,
f = focal length
v = Image distance from the mirror
u = object distance from the mirror (concave)
Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.
1/(-12) = 1/v + 1/(-36)
1/(-12) = 1/v - (1/36)
1/v = -0.055
v = -18 cm
Therefore, Image distance the from the concave mirror is -18 cm.
Now,
m = -v/u = hi/h
Substitute the values,
-(-18)/(-36) = hi/12
-0.5 = hi/12
-6 = hi
Therefore, the height of the image is -6 cm.
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n Step 5, you will calculate H+/OH– ratios for more extreme pH solutions. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide for a solution at a pH = 2. Then divide the H+ concentration by the OH– concentration. Record these concentrations and ratio in Table C.
What is the concentration of H+ ions at a pH = 2?
mol/L
What is the concentration of OH– ions at a pH = 2?
mol/L
What is the ratio of H+ ions to OH– ions at a pH = 2?
: 1
At pH = 2 the ratio of the concentration of the hydrogen to the hydroxide ion is 10¹⁰. The hydrogen ion concentration at pH, 2 is 10⁻² and the hydroxide ion is 10⁻¹².
What is pH?The parameter of measuring the concentration of the hydroxide and the hydrogen ion in the solution in order to determine the basic and the acidic nature is known as pH.
The concentration of H⁺ ions is calculated as:
pH = -log [H⁺]
2 = -log [H⁺]
[H⁺] = 10⁻²
The concentration of OH⁻ ions is calculated as:
pH + pOH = 14
pOH = 14 - 2
pOH = 12
Solving further:
pOH = -log [OH⁻]
12 =-log [OH⁻]
[OH⁻] = 10⁻¹²
At a pH = 2, the ratio of hydrogen ions to hydroxide ions:
10⁻² ÷ 10⁻¹² = 10¹⁰
Therefore, at pH = 2 the ratio is 10¹⁰.
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Two charged particles are near each other – the charge magnitudes are +3 uC and +7 uC, respectively. The electrostatic force between these charges is 25 N. A charged particle of -1 uC is added to both of the original two charges. What is the electrostatic force between the two charged particles after the -1 uC charge is added?
Answer:
Approximately [tex]14\; {\rm N}[/tex].
Explanation:
By Coulomb's Law, the magnitude of the electrostatic force between two charges is proportional to the product of the magnitudes of the two charges.
For example, consider charges of magnitude [tex]q_{1}[/tex] and [tex]q_{2}[/tex] that are apart from one another by a distance of [tex]r[/tex] in between. Let [tex]k[/tex] denote Coulomb's constant. By Coulomb's Law, the magnitude of electrostatic force between the two charges would be:
[tex]\displaystyle F = \frac{k\, q_{1}\, q_{2}}{r^{2}}[/tex].
In this question, the product of the magnitude of the two charges was originally [tex]3\; {\rm \mu C} \times 7\; {\rm \mu C} = 21\; {\rm (\mu C)^{2}}[/tex]. After [tex](-1\; {\rm \mu C})[/tex] is added to each charge, product of the magnitude of the two charges would become [tex](3 - 1)\; {\rm \mu C} \times (7 - 1)\; {\rm \mu C} = 12\; {\rm (\mu C)^{2}}[/tex].
Thus, the product of the magnitude of the two charges has been scaled to [tex]12\; {\rm \mu C}[/tex] from [tex]21\; {\rm \mu C}[/tex] . The magnitude of the electrostatic force between the two charges would be scaled from [tex]25\; {\rm N}[/tex] to [tex]25\; {\rm N} \times (12 / 21) \approx 14\; {\rm N}[/tex].
A person who falls between introversion and extroversion is
Answer:
the answer is ambivert have a good fourth of July
Answer:
i believe the answer is ambivert
Can i use a 1000mAh battery instead of 600mAh Battery?
please tell me quickly
To deliver more power or voltage in the circuit use a battery with more current rating which is 1000 mAh.
Power generated in a circuitThe power generated in a circuit is directly proportional to the current flowing in the circuit.
P = IV
where;
I is currentV is voltageVoltage in the circuit also increases with increase in the current flowing in the circuit.
Thus, to deliver more power or voltage in the circuit use a battery with more current rating which is 1000 mAh.
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The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?
Answer:
it is double the temperature change of iron
Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more than 10.0 centimeters, however, it no longer follows that simple linear rule. What force will result in stretching the spring 10.0 centimeters?
The force result in stretching the spring 10.0 centimeters is 2.5N.
What is Hooke's law?If a spring is stretched from its equilibrium position, then a force with magnitude proportional to the increase in length from the equilibrium length is pulling each end.
F = kx
where k is the proportionality constant called the spring constant or force constant.
Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more than 10.0 centimeters, however, it no longer follows that simple linear rule.
Let the spring constant be very low 0.04N/m
The force applied is
F = 10 cm / 0.04
F = 0.1 m / 0.04
F = 2.5 N
Thus, the force result in stretching the spring 10cm is 2.5 N.
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Answer: 2.5 newtons
source- trust me bro
What quantity is represented by a unit called a newton (N)?
A. Inertia
B. Acceleration
C. Force
D. Mass
[tex]\textsf {C. Force}[/tex]
[tex]\textsf {The quantity which is represented by a unit called Newton (N)}\\\textsf {is Force.}[/tex]
An object is released from an aeroplane which is diving at an angle of 30° from the horizontal with a speed of 50m/s. If the plane is at a height of
4000m from the ground when the object is released, find
(a) the velocity of the object when it hits the ground.
(b) the time taken for the object to reach the ground.
please I need the solution urgently.
a)The velocity of the object when it hits the ground will be 1.12 × 10⁵ m/sec
b) The time taken for the object to reach the ground will be 11.4 × 10³ sec.
What is projectile motion?The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.
The velocity in the x-direction;
[tex]\rm v_x = (vcos \theta)^2 +2gh \\\\ v_x = (50 cos 30)^2+ 2 \times 9.81 \times 4000 \\\\ v_x = 80355 m/sec[/tex]
Velocity in y-direction;
[tex]\rm v_ y = (vsin \theta)^2 + 2gh \\\\ v_ y = (25)^2+2 \times 9.81 \times 4000 \\\\ v_y =79105 \ m/sec[/tex]
The resultant velocity is found as 1.12 × 10⁵ m/sec.
The time taken to reach the ground is found as;
[tex]\rm v = u+gt \\\\ 1.12 \times 10^5 \ m/sec = 50 \ m/sec + 9.81 \times t \\\\ t = 11.4 \times 10^3 \ sec[/tex]
Hence, the velocity of the object when it hits the ground will be 1.12 × 10⁵ m/sec, and the time taken for the object to reach the ground will be 11.4 × 10³ sec.
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Why is a valve placed before the rotameter?
a.To measure the flow of liquid entering the extraction bed
b.To regulate the flow of fluid leaving the extraction bed
c.To regulate the flow of liquid entering the extraction bed
d.None of the above.
A valve placed is before the rotameter to regulate the flow of liquid entering the extraction bed. The correct option is c.
What is control valve?Control valves are generally used to maintain a flow as close as possible to the desired value.
Valves positioned before the rotameter for throttling purposes. A control valve will regulates the rate of fluid flow. Control valves control typically flow rate, pressure, and temperature.
Thus, the correct option is c.
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One mole of a substance contains 6.02 × 1023 protons and an equal number of electrons. If the protons could somehow be separated from the electrons and placed in very small, individual containers separated by a million meters, what would be the magnitude of the electrostatic force exerted by one box on the other?
Explanation:
it is almost zero .this is because the distance and the electrostatic force are inversely proportional
Answer pleaseeeee
Question 2 of 10
Which is directly proportional to your weight on a planet's surface?
OA. The distance from the surface to the center of the planet
B. Only the mass of the planet
OC. Only your mass
OD. Your mass and the mass of the planet
Answer:
from my side the will be b only the mass of the planet thank you
Answer:
D
Explanation:
W=mg
g=GM/r²(G=Gravitational constant, M=mass of earth, r=Radius of earth)
>>W=m(GM/r²)
W is directly proportional to mass of earth and mass of your body
A trolley is moving at constant speed in a friction compensated track. Some plasticine is dropped on the trolley and sticks on it. State with a reason what is observed about the motion of the trolley.
Answer:
Since the momentum of the body remains constant ( conserved) the trolley slows down (its velocity reduces) since its mass increases.
Can anyone solve? Thank you
Answer:
The rod is stretched because there is a larger gravitational force on the mass closest to mass M.
F = G M m / r^2 - G M m / (r + l)^2 the difference of the forces on m's
F = G M m [1 / r^2 - 1 / (r + l)^2]
[1 / r^2 - 1 / (r + l)^2] = (r^2 + 2 r l + l^2 - r^2 / [r^2 (r + l)^2]
= (2 r l + l^2) / [r^2 (r + l)^2]
if l is small compared to r = (2 r l ) / [r^2 (r + l)^2]
= (2 r l ) / [r^4 + 2 r^3 l ]
How many significant digits should the answer to the following problem have? (2.49303 g) * (2.59 g) / (7.492 g) =
The number of significant digits to the answer of the following problem is four.
What are the significant digits?The number of digits rounded to the approximate integer values are called the significant digits.
The following problem is
(2.49303 g) * (2.59 g) / (7.492 g) =
On solving we get
= 0.86184566204
The answer is approximated to 0.86185
Thus, the significant digits must be four.
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How to put a new command in the command prompt
Typing in the commands and instructions and pressing enter will put a new command in the command prompt.
What is a Command?This refers to a words or phrase which causes the computer to execute certain tasks or functions.
Typing the exact instruction and entering it will ensure that the chosen tasks are found in the command prompt.
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The velocity of the water jet discharging from the orifice can be obtained from v=\12ih, where h = 2 m is the depth of the orifice from the water surface. Determine the time for a particle of water leaving the orifice to reach point B and the horizontal distance x where it hits from surface.
(a) The time for a particle of water leaving the orifice to reach point B is 0.63 s.
(b) The horizontal distance x where it hits from surface is 3.94 m.
Time for the water to reach the surface
The time of the water to reach the surface is calculated as follows;
h = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
where;
t is time of motionh is height of the orificet = √( (2 x 2)/(9.8) )
t = 0.63 s
Horizontal distanceThe horizontal distance is calculated as follows;
X = vt
where;
v is the velocity of the water = √2ghX = (√2gh)t
X = (√2 x 9.8 x 2) x 0.63
X = 3.94 m
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(correct answers only)
A sailfish is swimming after a herring in a straight line at 11.8 m/s and begins to accelerate at 6.39 m/s². How long does it take for the sailfish to reach the herring if it is 55.0 m away?
(unit=s)
The time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.
Time of motion of the star fishThe time taken for the star fish to travel the given distance is calculated as follows;
s = ut + ¹/₂at²
55 = 11.8t + (0.5)(6.39)t²
55 = 11.8t + 3.195t²
3.195t² + 11.8t - 55 = 0
solve the quadratic equation using formula method,
where;
a = 3.195, b = 11.8, c = -55
t = 2.7 s
Thus, the time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.
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Erbium-165 has a half-life of 10.4 hours. If you start with 1,000 grams of
erbium-165, how much time will it take to have 125 grams of erbium-165 left
in the sample?
A. 41.6 hours
OB. 20.8 hours
C. 31.2 hours
D. 10.4 hours
The amount of time it will take to have 125 grams of erbium-165 left
in the sample is; C: 31.2 hours
How to calculate decay time?The formula for amount of substance after decay is;
N(t) = N₀(¹/₂)^(t/t_¹/₂)
We are given;
Half life; t_¹/₂ = 10.4 hours
Initial amount; N₀ = 1000 g
Amount left; N(t) = 125 g
Thus;
125 = 1000 * (¹/₂)^(t/10.4)
125/1000 = (¹/₂)^(t/10.4)
In 0.125 = (t/10.4) In 0.5
-2.08 = -0.693(t/10.4)
t/10.4 = -2.08/-0.693
t = 10.4 * 3
t = 31.2 hours
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_____ is a force which is applied to an object by another object or a person. __________ is a force that always opposes the motion of an object and is frequently ignored. a. Tensional force, friction c. Applied force, air resistance b. Friction, applied force d. None of the above. Please select the best answer from the choices provided A B C D
Answer:
Fritional force
Explanation:
Fritional force is a force that always opposes the motion of an object and is frequently ignored
C
Explanation:
Applied force, air resistance
A rocket is fired with an initial VELOCITY OF 100m/s at an angle of 55° above the horizontal, It explodes On the mountain Side 12s after its Firing What is X - and y-coordinates of the rocket relative to its Firing Point?
Answer
688.32m and 277.44m
Explanation :
⠀
[tex] \large{\maltese{\textsf{\underline{To find :-}}}} [/tex]
The X and Y coordinates of the rocket relative of firing
⠀
⠀
[tex] \large{\maltese{\textsf{\underline{Given :-}}}} \\ \\ \sf velocity (v_i) = 100m{s}^{-1} \\ \sf angle ({\theta}_{1}) = 55.0{\degree} \\ \sf time (t) = 12s [/tex]
⠀
⠀
[tex] \Large{\maltese{\textsf{\underline{\underline{Step by Step Solution:-}}}}} [/tex]
⠀
⠀
The horizontal range of projectile at x.
⠀
[tex] \sf \large{x = v_{xi}} \times t \\ \\ \sf \large{x = v_i \times \cos {\theta}_{i} \times t} [/tex]
⠀
⠀
[tex] \large\textsf{\underline{Now substituting the required values}} [/tex]
⠀
⠀
[tex] \sf x = 300 \times \cos 55{\degree} \times 12 \\ \\ \sf x = 100 \times 0.5756 \times 12 \\ \\ {\underline{\boxed{\bold{ x = 688.32m}}}} [/tex]
⠀
⠀
The vertical position of projectile at y.
⠀
⠀
[tex]\sf \large y = v_{yi} \times t - (\frac{1}{2} \times g \times {t}^{2}) \\ \\ \sf \large y = v_i \times \cos \theta \times t - \frac{1}{2} g {t}^{2} [/tex]
⠀
⠀
[tex]\textsf{ \large {\underline{Now substituting the required values}} } [/tex]
⠀
⠀
[tex] \sf y = 100 \times \cos55{ \degree} \times 12 - \frac{1}{2} \times 9.80 \times {12}^{2} \\ \\ \sf y = 100 \times 0.8192 \times 12 - 0.5 \times 9.8 \times 144 \\ \\ \sf y = 983.04 - 705.6 \\ \\ \underline{ \boxed{ \bold{y = 277.44m}}} [/tex]
⠀
⠀
⠀
Henceforth, the distance at horizon is 688.32m and at vertical is 277.44m.