46.2648
Explanation:Atomic mass describes the number of protons and neutrons in an atom.
Percent Abundance
Percent abundance is the percentage of atoms within a sample that have a specific mass number. The reason that different atoms within a sample would have different mass numbers is that they are different isotopes. For example, if the isotope Cl-35 has a percent abundance of 75%, then 75% of all Chlorine atoms within a sample will have a mass number of 35. Percent abundance refers to the likelihood of an isotope occurring in a natural sample. Percent abundance does not take into account artificial samples of elements.
Finding Atomic Mass
The atomic mass of an element is found through the mass of isotopes and their percent abundances. The formula for atomic mass is:
m₁*p₁ + m₂*p₂In this formula, the m is the mass of the isotope and p is the percent abundance. The percent abundance should be expressed as a decimal for all calculations. Now, plug in the values and solve.
(44.8776 * 0.3288) + (46.9443 * 0.6712)Rounded to 4 decimal places, this equals 46.2648. This means that the atomic mass of element "X" is 46.2648 amu.
Calcium hydroxide and hydrogen gas are produced by reaction of calcium hydride and water
Answer:
The reaction between calcium hydride (CaH2) and water (H2O) can be described by the following equation:
CaH2 + 2H2O → Ca(OH)2 + 2H2
This reaction produces calcium hydroxide (Ca(OH)2) and hydrogen gas (H2). The number of fluorine atoms is not specified in this equation.
Explanation:
Who knows and who doesn't know and who knows and who doesn't know and who knows because I thought that no one would even be happy to answer you
Determine the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of oxygen.
the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of oxygen is C3H8O2.
To determine the empirical formula of the compound, we need to find the ratios of the different elements present in the compound.
The first step is to convert the masses of each element to moles using their respective molar masses:
Carbon: 47.37 g / 12.01 g/mol = 3.94 mol
Hydrogen: 10.59 g / 1.01 g/mol = 10.48 mol
Oxygen: 42.04 g / 16.00 g/mol = 2.63 mol
Next, we divide each of the mole values by the smallest of the three, which is 2.63 mol:
Carbon: 3.94 mol / 2.63 mol = 1.50
Hydrogen: 10.48 mol / 2.63 mol = 3.98
Oxygen: 2.63 mol / 2.63 mol = 1.00
Now we need to convert these ratios to whole numbers by multiplying each by a common factor. The smallest ratio is 1.00, so we will multiply all the ratios by 2 to get:
Carbon: 1.50 x 2 = 3
Hydrogen: 3.98 x 2 = 8
Oxygen: 1.00 x 2 = 2
Therefore, the empirical formula of the compound is C3H8O2.
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How much energy, in joules per mole (J/mol), does a photon in the microwave region of the EM spectrum, contain? Assume the microwave has a frequency of 5.25 x 1010 s-1. Your answer should have 3 significant figures.
The energy, in joules per mole (J/mol), of a photon in the microwave region of the EM spectrum is 5.81 x 10-3 J/mol (3 significant figures).
What is energy?Energy is the capacity for doing work. It can take many forms, including kinetic energy (the energy of moving objects), potential energy (stored energy in an object due to its position or composition), thermal energy (heat), light, and electrical energy.
The energy carried by a single photon is equal to the product of Planck's constant (h) and the frequency (f) of the photon.
Therefore, the energy carried by a single photon in the microwave region of the EM spectrum, with a frequency of 5.25 x 1010 s-1, is:
E = h x f
= (6.63 x 10-34 J.s) x (5.25 x 1010 s-1)
= 3.48 x 10-23 J
The energy per mole of photons is then equal to:
E/mol = (3.48 x 10-23 J) / (6.02 x 1023 photons/mol)
= 5.81 x 10-3 J/mol
Therefore, the energy, in joules per mole (J/mol), of a photon in the microwave region of the EM spectrum is 5.81 x 10-3 J/mol (3 significant figures).
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Add electrons and the charge for the resulting radical
cationic intermediate, and add curved arrows for the
a-cleavage mechanism en route to m/z 43.
Electrons are negatively charged subatomic particles that orbit the nucleus of an atom. They are essential for chemical reactions, as they participate in the formation and breaking of chemical bonds. The appropriate diagram relating to the question is attached.
How to convey the informationA radical is a molecule or atom that contains one or more unpaired electrons. Radicals are highly reactive and can participate in a wide range of chemical reactions, such as combustion, polymerization, and oxidation.
A cationic intermediate is a positively charged species that forms during a chemical reaction. It is an intermediate state between the starting materials and the final products, and it is typically short-lived. Cationic intermediates can be formed by the loss of an electron or by the addition of a proton or other positively charged species.
Check the attachment.
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how (as per the Le Chateliers principle) an equilibrium is re-established when a change is imposed in terms of concentration, volume, pressure, and temperature
Select the correct answer from each drop-down menu. Complete the definitions. A rotation is a transformation where an object. A translation is a transformation where an object.
A rotation is a hard transformation that revolves an item around a central point. The direction of the form is different, but it still maintains its orientation. In a translation, the object's points are all moved in the same direction in a straight line.
Motion in which a moving body's points travel uniformly in one direction. We can observe that there is no change in the object's orientation if it is moving in a translatory manner. Motion that is translated is sometimes referred to as translational motion.
Although an object's position, size, or orientation can change during a transformation, its shape is not altered. Transformations can be non-rigid or rigid or isometric, where the size of the image remains constant.
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Defend the argument that creep feeding is beneficial to newborns.
Answer:
Creep feeding can help them make the transition without such a setback, and it can also help them begin to produce the enzymes needed to digest nonmilk proteins.
Explanation:
FeO (s) + O2(g) ->Fe₂O3(s)
O Combustion
O Double Replacement
O Decomposition
O Acid/Base Neutralization
O Single Replacement
O Synthesis
Answer: Synthesis
Explanation:
This is Synthesis because the reactants combine to form the products.
How many moles of Phosphorous are
needed to completely react with 3.25
moles of Calcium?
2 P + 3 Ca --> Ca3P2
A) 4.88 moles P
B) 2.17 moles P
C) 3.25 moles P
Answer: B) 2.17 moles P
Explanation:
To determine the number of moles of Phosphorous needed to completely react with 3.25 moles of Calcium, we need to look at the balanced chemical equation for the reaction:
2 P + 3 Ca → Ca3P2
From the equation, we see that two moles of Phosphorous are needed for every three moles of Calcium. To calculate the number of moles of Phosphorous needed for 3.25 moles of Calcium, we divide the number of moles of Calcium by 3 and multiply by 2:
3.25 moles Ca / 3 moles Ca/2 moles P * 2 moles P/1 mole Ca = 2.17 moles P
So, 2.17 moles of Phosphorous are needed to completely react with 3.25 moles of Calcium.
which of the following has a larger mass (2 mole of water) or (2 mole of carbon dioxide) or( 2 mole of ozone )
Answer:
The mass of 2 moles of water is greater than the mass of 2 moles of carbon dioxide, which is greater than the mass of 2 moles of ozone.
2 moles of water has a mass of approximately 36 grams, whereas 2 moles of carbon dioxide has a mass of approximately 44 grams, and 2 moles of ozone has a mass of approximately 48 grams.
ALLEN
A key advantage of PDF is that it has excellent tools for creating and editing images.
Group of answer choices
True
False
A key advantage of PDF is that it has excellent tools for creating and editing images. It is true.
What is a PDF?
PDF stypestands for Portable Document Format, which is a file format developed by Adobe in the 1990s. PDF files are used to present and exchange documents reliably and consistently across different platforms and devices, regardless of the software or hardware used to create or view the file.PDFs can contain various types of content, including text, images, graphics, and interactive elements such as hyperlinks and form fields. They can be created using a variety of tools and software, including Adobe Acrobat and many other third-party applications.PDF files can be viewed and edited using a variety of software, including Adobe Reader, Acrobat, and many other free and paid applicationsTo know more about PDFs, click the link given below:
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Given the following equation: 2N₂+502 → 2N₂O5
How many moles of N₂O5 are produced by reacting 10 moles of O₂?
We can form mole ratios by using a balanced chemical equation.
Solving the Question[tex]2N_2+5O_2\rightarrow 2N_2O_5[/tex]
2 moles of [tex]N_2O_5[/tex] can be formed with 5 moles of [tex]O_2[/tex]:[tex]\dfrac{n_{N_2O_5}}{2}=\dfrac{n_{O_2}}{5}[/tex]
We're given that we have 10 moles of [tex]O_2[/tex]:[tex]\dfrac{n_{N_2O_5}}{2}=\dfrac{10}{5}[/tex]
[tex]n_{N_2O_5}=4[/tex]
Answer4 moles of N2O4 are produced by reacting 10 moles of O2.
As per the balanced equation of the reaction, 5 moles of oxygen molecule gives 2 moles of the product N₂O₅ . Hence, 10 moles of oxygen will give 4 moles of nitrogen pentoxide.
What is mole ratio ?The balanced chemical equation of a reaction represents the perfect stoichiometry of the reactants and products. Hence, the number of atoms of each element in the reactant side must be equal to their number of atoms in the product side.
The stochiometric ratio of number of moles of one reactant to the other or the product is called its mole ratio.
From the given reaction, it is clear that 5 moles of oxygen molecules reacts with nitrogen gas to give 2 moles of dinitrogen pentoxide.
Hence, the number of moles of dinitrogen pentoxide produced by 10 moles of oxygen gas is calculated as follows:
(10× 2)/5 = 4
Therefore, the number of moles of the product formed from 10 moles of oxygen gas is 4 moles.
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The acid ionization constant, Ka, for propanoic acid, C2H5COOH, is 1.3x10-5.(a) Calculate the hydrogen ion concentration, [H+], in a 0.20-molar solution of propanoic acid.(b) Calculate the percentage of propanoic acid molecules that are ionized in the solution in (a).(c) What is the ratio of the concentration of propanoate ion, C2H5COO-, to that of propanoic acid in a buffer solution with a pH of 5.20?(d) In a 100.-milliliter sample of a different buffer solution, the propanoic acid concentration is0.35-molar and the sodium propanoate concentration is 0.50-molar. To this buffer solution,0.0040 mole of solid NaOH is added. Calculate the pH of the resulting solution
(a) The hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M. (b) 0.57%. (c) The ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.
(a) The balanced equation for the ionization of propanoic acid is:
C2H5COOH + H2O ⇌ C2H5COO- + H3O+
The equilibrium expression for this reaction is:
Ka = [C2H5COO-][H3O+] / [C2H5COOH]
At equilibrium, the concentration of propanoic acid that has ionized to form propanoate ion and hydronium ion is equal to the concentration of propanoic acid that has not ionized, so we can assume that [C2H5COO-] ≈ [H3O+]. Let x be the concentration of hydronium ion in the solution. Then the equilibrium expression becomes:
Ka = x^2 / (0.20 - x)
Solving for x, we get:
x = sqrt(Ka * (0.20 - x)) = sqrt(1.3x10^-5 * 0.20) = 1.14x10^-3 M
Therefore, the hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M.
(b) The percentage of propanoic acid molecules that are ionized in the solution is given by:
% ionization = [H3O+] / [C2H5COOH] x 100%
% ionization = (1.14x10^-3 / 0.20) x 100% = 0.57%
(c) The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:
pH = pKa + log([C2H5COO-] / [C2H5COOH])
At pH 5.20, the hydronium ion concentration is 10^-5.20
= 6.31x10^-6 M.
Using the equilibrium expression for propanoic acid and the fact that [C2H5COO-] + [C2H5COOH] = total buffer concentration,
we can solve for the ratio of the concentrations of propanoate ion to propanoic acid:
Ka = [C2H5COO-][H3O+] / [C2H5COOH]
[C2H5COO-] = Ka[C2H5COOH] / [H3O+]
[C2H5COO-] = (1.3x10^-5)([C2H5COOH]) / (6.31x10^-6)
[C2H5COO-] / [C2H5COOH]
= 2.68
Therefore, the ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.
(d) When solid NaOH is added to the buffer solution, it reacts with the propanoic acid to form propanoate ion and water:
C2H5COOH + NaOH → C2H5COO- + H2O + Na+
The number of moles of propanoic acid that react with NaOH is equal to the number of moles of NaOH that were added. The new concentration of propanoic acid is:
0.35 M - (0.0040 mol / 0.100 L) = 0.346 M
The new concentration of propanoate ion is:
0.50 M + (0.0040 mol / 0.100 L) = 0.54 M
The new concentration of hydronium ion can be calculated using the equilibrium expression.
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A sample of trifluoroacetid acid C2HF3O2 contains 83.3 g of oxygen calculate the mass
The mass of trifluoroacetic acid that contains 83.3 g of oxygen is approximately 482.6 g.
How to calculate the mass of trifluoroacetic acid (C2HF3O2) containing 83.3 g of oxygenFirst we need to use the molar mass and stoichiometry of the compound.
The molar mass of trifluoroacetic acid is:
(2 x 12.01 g/mol) + (1 x 19.00 g/mol) + (3 x 19.00 g/mol) + (2 x 16.00 g/mol) = 114.02 g/mol
The molar mass of oxygen is 16.00 g/mol.
From the chemical formula of trifluoroacetic acid (C2HF3O2),
we can see that each mole of the compound contains 2 moles of carbon, 1 mole of hydrogen, 3 moles of fluorine, and 2 moles of oxygen.
Using this information, we can set up a proportion to find the mass of trifluoroacetic acid that contains 83.3 g of oxygen:
(83.3 g O2) x (1 mol O2/16.00 g O2) x (1 mol C2HF3O2/2 mol O2) x (114.02 g C2HF3O2/1 mol C2HF3O2) = 482.6 g
Therefore, the mass of trifluoroacetic acid that contains 83.3 g of oxygen is approximately 482.6 g.
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Which characteristic is not a periodic trend?
A. Atomic radius
B. Electron affinity
C. Ionization energies
D. Number of elements in a group
Answer:
Explanation:
D
