Calculate the mass percent of 16.5 g KNO3
dissolved in 848 g H2O.

mass percent:

The situation where erosion is likely to occur is B. A bare hillside with loose, dry soil

Erosion is an ongoing process of soil displacement when airflows or water currents move through landforms. Examples occur on hillside areas which have no plants, grasses, shrubs, or anything else to stabilize the dry dirt underneath – making it easy for wind and rainfall to literally transport the surface materials in downward cascades.

Unfortunately, this can yield serious consequences - from impoverished fertility to extra sediments being added to nearby creeks and rivers, to demolishing the infrastructure located at the base of the hill.

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Options include;

Answer:

The answer is C

3+

Explanation:

electron configuration =2,3

oxidation state of boron=3+

1. The equation is not balanced. The balanced equation is: Zn + 2HCl → ZnCl₂ + H₂. Type of reaction is Substitution.

2. The equation S₈+24F₂→8SF₆ is balanced. The Type of reaction is Combination

3. The molecular mass of ferric oxide (Fe₃O₄) is 231.55 g/mol

4. The percentage composition of chlorine in CaCl₂ is 63.88%.

To calculate the molecular mass of ferric oxide (Fe₃O₄)

Molecular mass of Fe₃O₄ = (3 × atomic mass of Fe) + (4 × atomic mass of O)

3 × 55.85 g/mol + 4 × 16.00 g/mol

= 231.55 g/mol

To find the percentage composition of chlorine in CaCl2,

Molecular mass of CaCl₂ =

40.08 g/mol + 2 × 35.45 g/mol

= 110.98 g/mol

70.90 g/mol / 110.98 g/mol × 100

= 63.88%

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1. The equation isn't balanced because there aren't equal numbers of hydrogen or chlorine atoms on both sides of the equation. To correct this, a coefficient of 2 must be placed in front of HCl on the left-hand side of the equation.

ZN  + 2HCI →     ZnCl2  + H2

Zn and 2HCl are the reactants; ZnCl2 and H2 are the products. This is a substitution reaction because a free element (Zn) replaces another element (H) in a compound.

2. This is a balanced equation because the same types of atoms and the same numbers of each atom are present on both sides of the equation. 8 S atoms are found on both sides of the equation, and 48 F atoms are found on both sides of the equation. S8 and 24F2 are the reactants; 8SF6 is the product. This is a combination reaction because two substances (S8 and 24F2) undergo a chemical union to form a more complex substance (8SF6).

S8   +  24F2    →     8SF6

3. In ferric oxide (Fe3O4), there are 3 atoms of iron (Fe) and 4 atoms of oxygen (O). From the Periodic Table of Elements, we know that the atomic mass of iron is 55.8457 and the atomic mass of oxygen is 15.9994.

Fe3 = 55.8457 × 3 = 167.5371

O4 = 15.9994 × 4 = 63.9976

167.5371 + 63.9976 = 231.5347 (231.535 rounded)

Therefore, the molecular mass of ferric oxide is 231.535.

4. The percentage composition of chlorine in CaCl2 is derived as follows:

The molecular mass of the entire compound is:

Ca = 40.078 × 1 = 40.078

Cl2 = 35.4527 × 2 = 70.9054

40.078 + 70.9054 = 110.9834 (110.983 rounded)

The atomic mass of each element (or its multiple) is divided by the molecular mass of the compound:

Ca = 40.078 ÷ 110.983 = 0.361

Cl2 = 70.9054 ÷ 110.983 = 0.639

Multiplying each by 100 will turn these into percents. Therefore, the percentage composition of chlorine is 63.9%.

5. i. a, c, f, h

ii. e

iii. b, d, g, i

iv. i

The reaction would be an endothermic reaction. Option B

With a positive H, endothermic processes take in energy from their environment. It is less advantageous for the process if the entropy drops because it indicates that the reactants are getting more organized.

The likelihood of the response happening spontaneously is decreased as a result. The reaction can, however, continue if additional energy is introduced to the system from an outside source as shown.

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9.64 g more solute can be added if the temperature is increased to 30°C

The maximum amount of solute that can dissolve in a known quantity of solvent at a certain temperature is its solubility.

A saturated solution is a solution that contains the maximum amount of solute that is capable of being dissolved. An unsaturated solution is a solution that contains less than the maximum amount of solute that is capable of being dissolved.

Mass of solute present in a saturated solution with 51.0 g H₂O at 20.0 °C is

(44.3 × 51) ÷ 100 = 22.6g

The ratio of solubilities at two different temperautures = 81.4 / 44.3 = 1.83

This means that there can be 1.83 times more solute when the temperature is 30 °C.

22.6 × 1.83 = 41.35 g

So, the mass of solute that can be added = 51 - 41.35 = 9.64g

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The reaction can be said to be at equilibrium when the reaction rates of making products and using reactants are equal.

When the rates of the forward and reverse reactions are equal and the concentrations of the reactants and products don't change over time, a chemical reaction is said to be in equilibrium.

When the system reaches equilibrium, it is in a state of balance, which means that the concentrations of the reactants and products have not changed significantly.

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The electron configuration for bromine is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁵ (option A).

Electron configuration is the arrangement of electrons in an atom, molecule, or other physical structure like a crystal.

Electron configuration is a summary of where the electrons are around a nucleus.

The symbols used for writing the electron configuration start with the shell number (n) followed by the type of orbital and finally the superscript indicates how many electrons are in the orbital.

According to this question, the electron configuration of bromine with an atomic number of 35 is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁵.

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A decomposition reaction is a chemical reaction that involves the breakdown of a single compound into simpler substances. In this type of reaction, the reactant molecule is split into two or more products, and the products formed are usually different from the original reactant.

The reactant may break down into two compounds, an element and a compound, two elements, or a single compound.
Out of the four options mentioned, a single compound will not be the product of a decomposition reaction. This is because a decomposition reaction breaks down a single compound into simpler substances, which means that it cannot produce a single compound as a product.
For example, consider the decomposition of water (H2O) into hydrogen gas (H2) and oxygen gas (O2). The reaction can be represented as:
2H2O → 2H2 + O2
In this reaction, a single compound (H2O) is broken down into two simpler substances (H2 and O2). This is an example of a decomposition reaction that produces two elements as products.
In conclusion, a decomposition reaction can produce two compounds, an element and a compound, or two elements as products, but it cannot produce a single compound as a product.

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The volume of 0.205 M K3PO4 solution necessary to completely react with 114 mL of 0.0118 M NiCl2 solution is 0.00437 L or 4.37 mL

The given chemical equation shows that two moles of K3PO4 react with three moles of NiCl2 to form one mole of Ni3(PO4)2 and six moles of KCl. Thus, the stoichiometric ratio of K3PO4 to NiCl2 is 2:3.

To calculate the volume of K3PO4 solution required to completely react with 114 mL of 0.0118 M NiCl2 solution, we need to use the concept of stoichiometry and the equation of concentration, C = n/V, where C is the concentration in moles per liter (M), n is the amount in moles, and V is the volume in liters.

First, we can calculate the amount of NiCl2 in 114 mL of 0.0118 M solution:

n(NiCl2) = C × V = 0.0118 M × 0.114 L = 0.0013452 mol

Next, we can use the stoichiometric ratio to calculate the amount of K3PO4 required:

n(K3PO4) = (2/3) × n(NiCl2) = (2/3) × 0.0013452 mol = 0.0008968 mol

Finally, we can use the equation of concentration to calculate the volume of 0.205 M K3PO4 solution required:

V(K3PO4) = n(K3PO4) / C(K3PO4) = 0.0008968 mol / 0.205 M = 0.00437 L

Therefore, the volume of 0.205 M K3PO4 solution necessary to completely react with 114 mL of 0.0118 M NiCl2 solution is 0.00437 L or 4.37 mL (to three significant figures).

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The correct answer to the question is option C as that is the only option in which the change in entropy is positive.

Entropy is the degree of randomness in the system.  The gaseous state has the highest entropy among the state of matter.

a) Ag⁺ (aq) + Cl⁻ (aq) → AgCl (s)

Since the aqueous state has higher entropy than solids, the change in entropy is negative

b) H₂O (l) ----> H₂O (s)

Since the liquid state has higher entropy than solids, the change in entropy is negative.

c) 2SO₃ (g) ----> 2SO₂ (g) + O₂ (g)

Since the reactant has only 2 moles of gas and the product has 3 moles of gas, the entropy of the reactant increases with the reaction.

d) CaO (s) + CO₂ (g) -----> CaCO₃ (s)

Since the reactant has one mole of gas and the product has none thus the change in entropy is negative.

e) N₂ (g) + 3H₂ (g) ------> 2NH₃ (g)

Since the reactant has more moles of gases than the product which are 4 and 2 moles of gas respectively, the change in entropy is negative.

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According  to the peaks depicted and the chemical formula the molecule is that of ethanol.

Chemical  formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols  of elements. It also makes use of brackets and subscripts.

Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form  is called empirical formula.

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The most effective buffer solutions will have a pKa value close to the desired pH, and will have relatively high concentrations of both the weak acid and its conjugate base. Therefore, options a) and e) are both good buffer solutions.

Option a) contains a weak base (NH3) and its conjugate acid (NH4Cl), and has a pKa of 9.25. Option e) contains a weak acid (NH4Cl) and its conjugate base (NaOH), and has a pKa of 9.25 as well. Hence the correct answer will be a) and e)

Option b) contains a weak base (NH3) and a strong acid (HCl), so it will not be an effective buffer solution. Option c) contains a weak base (NH3) and a weak acid (HF), but the concentration of HF is relatively low, so it will not be an effective buffer solution. Option d) contains a weak acid (NH4Cl) and a strong base (NaOH), so it will not be an effective buffer solution.

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The volume of the gas in the tank at 293K and 3.0 atm pressure is 248 L. Hence, option B is correct.

Given:

T1 = 473K

T2 = 293K

P1 = 0.92 atm

P2 = 3.0 atm

The ideal gas law equation is:

PV = nRT

where P is pressure, V is volume, n is the number of moles of gas, R is the universal gas constant, and T is temperature.

n1 = (PV)/(RT)

= (0.92 atm × 500.0 L)/(0.0821 Latm/molK × 473K)

= 10.42 mol

Use the ideal gas law again to find the final volume of the gas in the tank under high pressure:

V2 = (n1 × R × T2)/P2

= (10.42 mol × 0.0821 Latm/molK × 293K)/(3.0 atm)

= 248 L

Therefore, the volume of the gas in the tank at 293K and 3.0 atm pressure is 248 L.

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Answer:

Using the ideal gas law, PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature in Kelvin, we can solve for n:

n = PV/RT

We know that the initial volume is 500.0 L, pressure is 0.92 atm, and temperature is 473K. We can use this information to find the initial number of moles:

n1 = (0.92 atm x 500.0 L)/(0.08206 L atm/mol K x 473K) = 11.80 mol

Next, we can use the ideal gas law again to find the final volume. We know that the final pressure is 3.0 atm and the final temperature is 293K:

V2 = nRT2/P2

V2 = (11.80 mol x 0.08206 L atm/mol K x 293K)/3.0 atm = 95 L

Therefore, the volume of the gas at the lower temperature and higher pressure is approximately 95 L. Answer: 95 L.

Answer:

The answer is 223.8g/mol

Explanation:

RMM=1×39.1+1×1×79.9•8(2×1+1×16)

=39.9+79.9•8(2+16)

=119.8•8(18)

=119.8+114

RMM=223.8g/mol

As per chemical changes, a color change can be seen when a substance change into a new substance.

Chemical changes are defined as changes which occur when a substance combines with another substance to form a complete  new substance.Alternatively, when a substance breaks down or decomposes to give new substance it is also considered to be a chemical change.

There are several characteristics of chemical changes like those of  change in color, change in state , change in odor and even change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

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A substance's cooling curve is a graph representing the change in temperature over time as it is allowed to cool. The gradient of the cooling curve is influenced by the heat capacity, thermal conductivity, and ambient temperature of the material. The correct option is A.

The rate of cooling for a sample with a known composition is measured in order to map the phase boundaries on a phase diagram. As the sample (or some piece of it) starts to go through a phase change, the rate of cooling will alter. When the temperature-time curve changes slope, these "breaks" will be visible.

In the cooling curve, the graph never meet with the time axis.

Thus the correct option is A.

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0.04 grams of zinc reacted

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as

                            PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Volume = 670 ml = 0.67L

Pressure = 576 torr

Temperature = 25 degree celsius

PV = nRT

576 × 0.67 = n × 62.36 × 298

n = 0.02 moles

mass = moles × molar mass

= 0.02 × 2 = 0.04g

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The kind of assorted fruits that can be sold in school are Apples

Bananas, Oranges, Grapes, Pineapples, Mangoes, Strawberries, Blueberries, Kiwis, etc.

There are many different types of fruits that can be sold in schools, depending on availability, seasonality, and local preferences.

The following are some examples of assorted fruits that are commonly sold in schools;

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It will take 22 hours until the radioactive isotope decays to 0.0031mg.

The half-life of a chemical reaction can be defined as the time taken for the concentration of a given reactant to reach 50% of its initial concentration.

The half-life of a radioactive isotope is the amount of time it takes for one-half of the radioactive isotope to decay. The half-life of a specific radioactive isotope is constant; it is unaffected by conditions and is independent of the initial amount of that isotope.

Given,

Initial mass = 0.05 mg

Final mass = 0.0031 mg

Half Life = 6 hours

N / N₀ = [tex]( 1 / 2)^n[/tex]

0.0031 / 0.05 = [tex]( 1/2)^n[/tex]

n = 3.65

t = n × half life

= 3.65 × 6

= 21.9 hours = 22 hours

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Answer:

false shield volcanoes are the product of gentle effusive eruptions

Answer:

y = 2x pv = 13 z = (2/x) 4 = (y/x) h = (9g/5) Inverse variation is represented by the equation y = k/x, where k is a constant.

We can compare the solubility product constants (Ksp) values to establish the correct order of the solubilities of the iron compounds in water. The solubility of the substance in water is inversely correlated with the Ksp value.

Fe(OH)3 Ksp = 2.8 x 10(-39) is provided.

4.9 x 10(-17) Fe(OH)2 Ksp

3.5 x 10(-11) FeCO3 Ksp

Fe(OH)3 has the lowest Ksp value (2.8 x 10(-39)), which indicates the lowest solubility among the three compounds, when the Ksp values are compared. Similarly, FeCO3 is more soluble than Fe(OH)3 and has a higher Ksp value (3.5 x 10(-11)). Fe(OH)2 is the most soluble of the three compounds, as indicated by its greatest Ksp value (4.9 x 10(-17)).

As a result, the iron compounds' solubilities in water should be listed in the following order:

FeCO3 Fe(OH)2 Fe(OH)3

Therefore, "The order of solubilities is Fe(OH)3 FeCO3 Fe(OH)2" is the appropriate response.

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The stoichiometric table and the rate law for the given elementary liquid phase reaction have been constructed. The rate constant and activation energy have been calculated, and the type of reaction energy has been specified as endothermic.

Stoichiometric table in terms of concentrations:

The stoichiometric table for the given reaction can be constructed as follows:

A + 2B → products

                             A                                B                                products

Feed         0.3*Cf                        0.7*Cf                                       0

Exit              (0.3-0.3X)*C             (0.7-0.7X)*C                                0

Change         -0.3XC                      -0.7XC                                     0

Where:

Cf = Total feed concentration

C = Concentration inside reactor

X = Conversion of A

Rate of reaction of A:

The rate of the reaction can be expressed as:

rA = -1/2 * dCA/dt = k*C^2

where, CA is the concentration of A and k is the rate constant.

Since the reaction is elementary, the rate law is proportional to the concentrations of the reactants raised to their stoichiometric coefficients.

The rate of disappearance of A = rate of appearance of B

rB = -dCB/dt = 2*rA

Therefore, the rate of reaction of A can be expressed as:

rA = (0.7Cf - 0.7C)/V = k*C^2

Substituting values, we get:

rA = (0.710 - 0.70.7X)/5 = k(0.3 - 0.3*X)^2

Calculation of k and E:

The rate constant k can be calculated using the Arrhenius equation:

k = A * exp(-Ea/RT)

where A is the frequency factor, Ea is the activation energy, R is the gas constant and T is the temperature in Kelvin.

Assuming the activation energy is 50 kJ/mol, we can calculate the rate constant at the given temperature of 333 K:

k = 0.00717 * exp(-50000/(8.314*333)) = 0.0001504

The reaction energy can be determined by calculating the activation energy using the rate constant at two different temperatures. Assuming the rate constant at 323 K is 0.000098, we can solve for Ea:

ln(k2/k1) = Ea/R * (1/T1 - 1/T2)

ln(0.000098/0.0001504) = Ea/8.314 * (1/323 - 1/333)

Ea = 43775 J/mol

The positive value of the activation energy indicates that the reaction is endothermic.

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Answer:

In hot water, molecules gain kinetic energy, therefore molecules in hot water have kinetic energy

while molecules of cold water have less or no kinetic energy

The real bond angles are;

1) 104 degrees

2) 180 degrees

3) 119 degrees

4) 120 degrees

5) 107 degrees

6) 109.5 degrees

The VSEPR (Valence Shell Electron Pair Repulsion) theory is a model used in chemistry to predict the shape of individual molecules based on the repulsion between valence electrons pairs in the outermost electron shell of an atom.

We know that we can look at the presence or the absence of the lone pairs or symmetry in the compound as as to ascertain the real bond angles of the compounds listed in the question.

The bond angles can be obtained from chemical litearture.

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Answer:

1) 104.5

2) 180

3) 119

4) 120

5) 107.8

6) 109.5

Explanation:

A polar molecule is considered polar if it has a net dipole moment, meaning that the electron density is not evenly distributed around the molecule. Both H2O2 and NO2 are polar molecules, while N2H2 and CF2 are nonpolar molecules.

H2O2, or hydrogen peroxide, is a polar molecule due to its bent molecular geometry and the polarity of its O-H bonds. NO2, or nitrogen dioxide, is also a polar molecule because of its bent molecular geometry and the polarity of its N-O bonds. N2H2, or diazene, is a nonpolar molecule because its linear molecular geometry and nonpolar N=N bonds result in an even distribution of electron density. Finally, CF2, or difluoro methylene, is a nonpolar molecule due to its linear molecular geometry and the symmetrical distribution of its polar C-F bonds.

In summary, both H2O2 and NO2 are polar molecules, while N2H2 and CF2 are nonpolar molecules. The polarity of a molecule is an important factor in determining its physical and chemical properties, as well as its interactions with other molecules.

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The performance of a laboratory technician in a blood bank is crucial as it directly impacts the quality of the blood products and patient safety. If there are five problems with a technician's work performance in the first year of work, it can have serious consequences for the blood bank's operations.

Some of the potential problems that may arise include:

Improper labeling of blood products: This can result in confusion and incorrect transfusions.

Mishandling of blood products: This can lead to contamination, spoilage, or improper storage, which can affect the quality of the blood products.

Failure to follow standard operating procedures: This can result in errors, deviations from protocols, and potential safety hazards.

Poor communication skills: This can result in misunderstandings, delays, and errors in documentation.

Inadequate training or knowledge: This can lead to mistakes, misinterpretation of test results, and failure to recognize potential problems.

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The piece of information that you need to determine whether a molecule is an alkyne or an alkene is D. The type of C-C bonds in the molecule

Alkenes and alkynes can be decribed as the name that is been gotten by  by identifying the longest chain that contains the double or triple bond.

It should be noted that The chain is numbered  so that theminimization of  the numbers assigned to the double or triple bond can be easy however the suffix of the compound  can be “-ene”  when regarding to an alkene or “-yne” when regarding to alkyne.

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