Can someone please help me with this question

mg reacts with the acid and produce visible bubbles of hydrogen gas. they will produce audible pops as the hydrogen ignites. ... Hydrochloric acid is a corrosive liquid. Hydrogen gas is explosive.

Answer:

nucleus

Explanation:

The nucleus holds all the other things, keeping them safe and confined.

Answer:

Nucleus

Explanation:

It contains DNA which contains a GENE which contains a CHROMOSOME so its NUCLEUS

Answer:

base

Explanation:

carbonic acid - H2CO3 - is a weak acid. Therefore, HCO3 itself is its conjugate base. The Na(sodium) ion is neutral.

This means that NaHCO3 is a base. (a weak one)

Answer: 11 Electrons

Explanation:

We know that the atomic number of sodium is 11. This tells us that sodium has 11 protons and because it is neutral it has 11 electrons.

Answer:

The sodium atom is left with a full outermost electron shell with eight electrons, and the outermost shell of the other atom is full as well.

Explanation:

The sodium atom now has a positive electrical charge of plus 1, and the other atom has a negative charge of minus 1. The two opposite charges attract, and the two atoms now form the molecule of a compound.

Answer:

For the last few decades fires started by any type of smoking material has been the number one leading cause for household fire fatalities. It could just be that people luckily escape in time with cooking equipment fires, and smoking related fires just result in more deaths.

Answer:

336.1 g of PbS precipitate

Explanation:

The equation of the reaction is given as;

Na2S(aq) + Pb(NO3)2(aq) ----> 2NaNO3(aq) + PbS(s)

Ionically;

Pb^2+(aq) + S^2-(aq) -----> PbS(s)

Number of moles of sodium sulphide= concentration of sodium sulphide × volume of sodium sulphide

Number of moles of sodium sulphide= 0.780 × 1.5 = 1.17 moles

Number of moles of lead II nitrate= concentration of lead II nitrate × volume of lead II nitrate

Number of moles of lead II nitrate= 3.31× 1.00= 3.31 moles

Then we determine the limiting reactant. The limiting reactant yields the least amount of product.

Since 1 moles of sodium sulphide yields 1 mole of lead II sulphide

1.17 moles of sodium sulphide also yields 1.17 moles of lead II sulphide

Hence sodium sulphide is the limiting reactant.

Thus mass of precipitate formed= amount of lead II sulphide × molar mass of sodium sulphide

Molar mass of lead II sulphide= 287.26 g/mol

Mass of lead II sulphide = 1.17 moles × 287.26 g/mol

Mass of lead II sulphide= 336.1 g of PbS precipitate

Answer:

Explanation:

NH3 + H2O ⇌ NH4  + OH-

0.35                              0.35

-log[OH-] = -log0.35 = 0.46 = pOH

14 - 0.46 = 13.54 = pH

Answer:

In the oxide form, uranium can be disposed of as low-level radioactive waste at an approved disposal facility. Approximately 350,000 tons of anhydrous HF are used annually in the United States.

Explanation:

Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]HCl[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is LiOH.

We are given:

[tex]n_1=1\\M_1=0.10mol/L\\V_1=?mL\\n_2=1\\M_2=0.15mol/L\\V_2=10mL[/tex]

Putting values in above equation, we get:

[tex]1\times 0.10\times V_1=1\times 0.15\times 10\\\\V_1=15mL[/tex]

Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

Answer: SI prefixes are used to form decimal multiples and submultiples of SI units. They should be used to avoid very large or very small numeric values.

Explanation: ^^^

Answer:

An endothermic reaction takes in heat, but feels cold to the touch. An exothermic reaction gives off heat and feels warm to the touch because it is heating the outside objects.

Answer: Thus [tex]CH_3CH(OH)CH_3[/tex] is a secondary alkanol.

Explanation:

Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.

Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example: [tex]CH_3CH_2CH_2OH[/tex] and [tex]CH_3CH_2CH_2CH_2OH[/tex]

Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example: [tex]CH_3CH(OH)CH_3[/tex]

Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example: [tex]C(CH_3)_3OH[/tex]

Thus [tex]CH_3CH(OH)CH_3[/tex] is a secondary alkanol.

Answer:

It would have to be D, a bent shape

Explanation:

I just took the quiz

Answer:

potassium is likely to be harder

Explanation:

because whenan atom loss electron they can form particle ion acquare stable a arrangement that loos electron can transfer to another which that also to acquaire stable

If the water vapor content remains the same and the temperature decreases, the relative humidity rises.

If the water vapor content remains the same and the temperature increases, the relative humidity falls.

This is because colder air doesn’t need as much moisture to become saturated as warmer air.

Hope this helps

Answer:

The empirical formula is same as the molecular formula = C6H10S2O

Explanation:

we start by dividing the percentage of each of the elements by their atomic mass

Carbon = 44.4/12 = 3.7

Hydrogen = 6.21/1 = 6.21

Sulphur = 39.5/32 = 1.234375

oxygen = 9.89/16 = 0.618125

That of oxygen is smallest so we divide all by that of oxygen

C = 3.7 / 0.618125 = 6

H = 6.21/ 0.618125 = 10

S = 1.234375/ 0.618125 = 2

Automatically, oxygen is 1

So the empirical formula is;

C6H10S2O

Let’s get its molecular formula. We multiply each of the subscript by the number;

(72 + 10 + 64 + 16)n= 162

162n = 162

n = 1

So the molecular formula is same as the empirical formula

B is the answer ,ammonium accepts a proton and becomes ammonium ion