A projectile's horizontal velocity is constant (a never changing in value), Gravity causes a downward vertical acceleration with a magnitude of 9.8 m/s/s. A projectile's vertical velocity fluctuates by 9.8 m/s per second, A projectile's vertical motion is unrelated to its horizontal motion.
For relatively small displacements, the force of gravity has little effect on an object's horizontal motion. This indicates that while the vertical velocity is accelerating, the horizontal velocity is remaining constant. The cause is that perpendicular vectors behave differently from one another. A projectile's vertical velocity is zero at its maximum height. There is now only the horizontal velocity.
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This huge rocket was as tall as a football field is long. Its mass is 3,038,500 kg. If this rocket accelerated from rest at 5 g’s, How much force was used to lift it off the ground?
The force used to lift the huge rocket off the ground is 148,886,500 N.
Force used to lift the huge rocket off the ground
The force used to lift the huge rocket off the ground is calculated as follows;
F = ma
where;
m is mass of the rocketa is the acceleration of the rocketa = 5g
F = m(5g)
F = ( 3,038,500 kg) x (5 x 9.8 m/s²)
F = 148,886,500 N
Thus, the force used to lift the huge rocket off the ground is 148,886,500 N.
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3. What would happen if two black holes were to
collide?
Answer:
What would happen is that once the two collide they will make a bigger black hole.
Explanation:
Why are the noble gases the least reactive elements?
A 20 km long, 8 m wide, two-lane highway is to be paved with a 4 cm thick
layer of asphalt. A fleet of three dump trucks is to be employed, each with
an empty mass of 20 metric tons and a carrying capacity of 20 m3 asphalt
with a density of 0.72 g/cm3 will be used. Determine the following:
a. the total volume of asphalt needed
b. the number of dump truck loads required
c. the gross mass of each truck
(a) The volume of asphalt needed is 6400 m³.
(b) The number of dump truck loads required is 320.
(c) The gross mass of each truck is 34400 kg.
The dimension of the two-lane highway 20 km long, 8 m wide, and 4 cm thick.
The mass of a dump truck is 20 metric tons, and carrying capacity is 20 m³ and the density is 0.72 g/cm³.
The two-lane highway:
length, l = 20 km = 20 × 10³ m
breadth, b = 8 m
Thickness, h = 4 cm = 4 × 10⁻² m
(a) The volume of the asphalt will be:
V = l × b × h
V = 20 × 10³ × 8 × 4 × 10⁻² m³
V = 64 × 10² m³
V = 6400 m³
V = 6400 × 10⁶ cm³
(b) The carrying capacity of 20 m³ asphalt.
Therefore, the number of truckloads required will be:
= 6400 m³ / 20 m³
= 320
(c) Now,
Density, d = 0.72 g/cm³ = 720 kg/m³
The empty mass is 20 metric tons which is equal to 20 ×10³ kg.
Therefore, the gross mass of each truck will be
m = 20 ×10³ kg + 720 kg/m³ × 20 m³
m = 20000 kg + 14400 kg
m = 34400 kg
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What is the weight of a 12.5kg mass?
What is the mass of a 2.5N weight?
200N are weighed. What is the mass?
What will a scale read for a 4kg mass?
1. The weight of a 12.5 kg mass is 122.625 N
2. The mass of a 2.5 N weight is 0.255 kg
3. The mass of a 200 N weight is 20.4 kg
4. The scale read for a 4 kg mass is 39.2 N
What is the relationship between weight and mass?The mass of a substance is the quantity of matter present in that substance.
The quantity of matter or mass of a substance is constant and is measured using a weighing balance.
The weight of a substance is the product of the mass of a substance and the acceleration due to gravity.
The weight of a substance varies and is measured using a spring balance and the unit is N.
Weight = m * g
where;
m is mass in kg
g = 9.81 m/s²
Considering the given substances:
1. The weight of a 12.5 kg mass = 12.5 * 9.81
The weight of a 12.5 kg mass = 122.625 N
2. The mass of a 2.5 N weight = 2.5/9.81
The mass of a 2.5 N weight = 0.255 kg
3. The mass of a 200 N weight = 200/9.81
The mass of a 200 N weight = 20.4 kg
4. The scale read for a 4 kg mass = 4 * 9.81
The scale read for a 4 kg mass = 39.2 N
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An apple is hanging at rest on a tree when its stem breaks. It takes 1.4 seconds for the apple to fall halfway to the ground. How long does it take for the apple to fall the entire distance to the ground?
The apple takes 2.05 seconds to fall due to gravity.
Newton's Second Law of Motion and Newton's Law of Universal Gravitation serve as the foundation for the formula for the acceleration caused by gravity. The most practical formula for estimating the acceleration caused by gravity is given by these two laws: g = G*M/R2, where g is the acceleration caused by gravity, G is the universal gravitational constant, M is mass, and R is distance.
Everything has a gravitational pull on every other object, according to Newton's Law of Universal Gravitation. The force is inversely proportional to the square of the distance between the centers of both objects and directly proportional to the masses of both objects. This is determined mathematically by the formula F = G*(m1*m2/d2), where F is the force and G is the gravitational constant of the universe.
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A car with an initial speed of 22.1 km/h accelerates at a uniform rate of 0.84 m/s2 for 4.4 s. Find the final speed of the car. Answer in units of m/s. Find the displacement of the car after that time. Answer in units of km.
(Desperately need help with Part 2)
Answer:
Final speed of car = 9.834 m/s
Displacement = 0.035 km
Explanation:
Part 1
Final velocity, v of an object moving with an acceleration a m/s² for t seconds and an initial velocity u m/s is given by the formula
v = u + at m/s
[tex]\textrm{Initial velocity } u = 22.1 km/h\\\\\textrm{Convert this to m/s:}\\\\\textrm{1 km/h = 1000m/3600 s}\\\\ 22.1 km/h = 22.1 x 1000/3600 = 6.139 m/s\\\\\boxed{\textrm{Final velocity } v = u + at = 6.138 + 0.84 x 4.4 = 9.834 m/s}[/tex]
Displacement s in m for a constant acceleration of a m/s² for a time t seconds is given by the formula:
[tex]x = ut+\dfrac{1}{2}at^2[/tex]
where u is initial velocity
Plugging in the values we get
[tex]s = 6.139\cdot 4.4 + \dfrac{1}{2}\cdot0.84\cdot (4.4)^2 = 35.143 \;\mathrm {meters}[/tex]
35.143 meters = 35.143/1000 = 0.035 km
Answer:
1) 9.83 m/s (2 d.p.)
2) 0.04 km (2 d.p.)
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Part 1Given:
u = 22.1 km/ha = 0.84 m/s²t = 4.4 sConvert km/h into m/s by dividing by 3.6:
[tex]\implies \sf 22.1\;km/h=\dfrac{22.1}{3.6}\;m/s[/tex]
Substitute the given values into the formula and solve for v:
[tex]\begin{aligned}v&=u+at\\\implies v & = \dfrac{22.1}{3.6}+0.84(4.4)\\v & = 6.1388...+3.696\\v & = 9.834888...\\v & = 9.83 \sf \;m/s\;(2\:d.p.)\end{aligned}[/tex]
Therefore, the final speed of the car was 9.83 m/s (2 d.p.).
Part 2Substitute the given values into the formula and solve for s, remembering to use the initial velocity in m/s:
[tex]\begin{aligned}s & = ut+\dfrac{1}{2}at^2\\\implies s &=\dfrac{22.1}{3.6}(4.4)+\dfrac{1}{2}(0.84)(4.4)^2\\s &=27.0111...+8.1312\\s &=35.1423111...\sf m\end{aligned}[/tex]
Convert meters into kilometers by dividing by 1000:
[tex]\implies \dfrac{35.1423111...}{1000}=0.0351423111...=0.04 \sf \; km\;(2\:d.p.)[/tex]
Therefore, the displacement of the car after 4.4 s was 0.04 km (2 d.p.).
.A 2.0-L balloon at room temperature (20.0°C) is placed in a freezer at -18°C. What is the volume of the balloon after it cools in the freezer?
Answer step by.
if a 2.0-L balloon at room temperature (20.0°C) is placed in a freezer at -18°C, then the volume of the balloon would be 1.74 liters.
What is an ideal gas?It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one.
PV = nRT
By assuming the pressure constant the volume would be directly proportional to the temperature changes from 293 kelvin to 255 kelvin,
V₁ /V₂ = T₁/ T₂
1000 litre = 1 m³
1 litre = 1/1000 m³
2 litre = 2/1000 m³
=0.002 m³
0.002 / V₂ = 293 / 255
V₂ = 0.001740 m³
The final volume of the balloon =1.74 liters.
Thus, the volume of the balloon would be 1.74 liters.
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A 50N force is applied to the free end of a spiral spring of force constant 100N/m. Calculate the work done by the force to stretch the spiral spring.
Explanation:
I solved it in the picture but I'm not a hundred percent sure
In 1954 the English runner Roger Bannister broke the four-minute barrier for the mile with a time of 3:59.4 s (3 min and 59.4 s). In 1999 the Moroccan runner Hicham el-Guerrouj set a record of 3:43.13 s for the mile. If these two runners had run in the same race, each running the entire race at the average speed that earned him a place in the record books, el-Guerrouj would have won. By how many meters?
Answer:
Bannister = 3:59.4 sec = 239.4 sec
Guerruoj = 3:43.13 = 223.13 sec
1 mi = 5280 ft
G = 5280 / 223.13 = 23.66 ft/sec
B = 5280 / 239.4 = 22.06 ft/sec
In 223.13 sec B runs 223.13 * 22.06 = 4922 ft
G Wins by 358 ft = 119.3 yds = 109.1 meters
An Alaskan rescue plane traveling 45 m/s
drops a package of emergency rations from
a height of 110 m to a stranded party of
explorers.
margolalaraq
The acceleration of gravity is 9.8 m/s².
Where does the package strike the ground
relative to the point directly below where it
was released?
Answer in units of m.
The package strike the ground relative to the point directly below it was released at 213.3m.
Equation:Given values,
Velocity of plane 45 m/s
Acceleration due to gravity 9.8 m/s²
horizontal component of plane velocity is
ux = 45 m/s
Vertical component is zero
In the same way
ay = - 9.8 m/s²
ax = .0 m/s^2
Motion in y direction = -110 m
From equation of motion time of flight is
d = u x t + 1/2 at²
where,
d is distance
u is velocity initial
a is acceleration
t is time
So, putting values
-110 = 0 + 1/2 (-9.8)t²
-110 = -4.9t²
t² = 110 / -4.9
t² = 22.45
t = √22.45
t = 4.74
Motion in x direction,
d = u x t + 1/2 at²
d = ( 45 x 4.74) + 1/2 (0) 4.74²
d = 213.3 + 0
d = 213.3m
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Which type of circuit has
more than one path for
electrons to flow?
A. Parallel
B. Series
C. Neither
Answer:
A. Parallel connection
Answer:
Parallel circuit to be exact
given that vector c=a+b, indicate the conditions that A and B have to meet in order for c to have the largest and smallest possible magnitudes
A Vector is a quantity which has both magnitude as well as direction.
vectors follow parallelogram law of addition and uses cosine of the angle between the vectors.
The addition of two vectors, i.e. c, is given by the formula
c=[tex]\sqrt{a^2+b^2+2abcos\alpha }[/tex]
where [tex]\alpha[/tex] is the angle between the vectors
now we know that maximum value of cos[tex]\alpha[/tex] can be is 1
and minimum value of cos [tex]\alpha[/tex] can be-1
now the maximum value cos[tex]\alpha[/tex] is 1 at the angle of π/2
and the minimum value of cosα is -1 is at the angle of -π
Therefore, A and B should have 0 degree between them and in the same direction to have the maximum value
there fore they should be in same direction and 0 degree meaning they should be on same line
A and B will have minimum value when the angle is 180 degree which means they should be on same line and be inn opposite direction to each other.
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What is the kinetic energy of a 29 kg dog that is running at a speed of 8.5 m/s (about 17 mi/h)?
The kinetic energy of of given data is K.E. = 1,047.62 J
Equation:To calculate kinetic energy using the formula,
K.E. = 1/2 m v²
where,
K.E is kinetic energy
m is mass
v is velocity
So, Putting values,
K.E. = 1/2 x 29 x (8.5m/s)²
K.E. = 1,047.62 J
What is kinetic energy in simple words?The energy an object has as a consequence of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the object, which then moves at a new, constant speed.
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A person is dragging a crate over a shag carpet with a push force of 10N. The shag rug creates a friction force of 5N. The mass of the crate is 5 k
g. Calculate the acceleration of the crate?
(Just enter the numbers, no
The acceleration of the crate after the frictional force is overcame is determined as 1 m/s².
What is acceleration?Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity with time.
The acceleration of the crate is calculated from the net force acting on the crate as shown below;
F(net) = applied force - frictional force
F(net) = 10 N - 5N
F(net) = 5 N
Apply Newton's second law of motion to calculate the acceleration of the crate.
F(net) = ma
where;
m is mass of the cratea is acceleration of the cratea = F(net) / m
a = 5/5
a = 1 m/s²
Thus, the acceleration of the crate after the frictional force is overcame is determined as 1 m/s².
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A boy leaves his home at 5:00 pm, drives around the city a distance of 24 miles, and returns home at 5:30 pm. His average velocity is???
We can see that the speed of the car is obtained as 12 miles per hour.
What is speed?The term speed is the ratio of the distance covered to the time taken. We can see that the distance that have been covered by the boy is 24 miles. The total time that have been taken to cover this distance is 30 mins or 0.5 hours.
We now come up with the following;
Distance = 24 miles
time = 0.5 hours
We now want to compute the speed of the boy in miles per hours so we have;
Speed = 24 miles / 0.5 hours = 12 miles per hour
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What is the magnitude of the resultant of a 61m north and 21m south vector?
Answer:
1281
Explanation:
what is the magnitude of the resultant of a 61m north and 21m south vector
Choose the correct statement about precession of the Earth's axis.
A. Precession of the Earth's axis of rotation is caused by changes in the shape of the Earth's orbit due only to the gravitational pull of the Sun.
B. One complete cycle of the Earth's pole star is not affected by precession.
C. One cycle of the precessional motion of the North Celestial Pole takes about 26,000 years.
D. Precession is the motion of Earth along its orbital path.
The precession is the motion of Earth along its orbital path.
What is earth's axis of rotation?
Earth's rotation or Earth's spin is the rotation of planet Earth around its own axis.
What is precession of the Earth's axis?Precession of the Earth's axis consists of a cyclic wobbling in the orientation of Earth's axis of rotation with a period of 25,772 years.
The precession of the Earth's axis wobble is due to tidal forces caused by the gravitational influences of the Sun and Moon.
Thus, precession is the motion of Earth along its orbital path.
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The "Screaming Swing" is a carnival ride that is - not surprisingly - a giant swing. It's actually two swings moving in opposite directions. At the bottom of its arc, a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. The rider in the other swing is moving in a similar circle at the same speed, but in the exact opposite direction. What is the acceleration, in m/s2 , that riders experience?
The acceleration, in m/s² , that riders experience is 50.3 m/s²
What is the acceleration, in m/s² , that riders experience?Since the riders move in a circle, they undergo circular motion and will have a centripetal acceleration.
So, the centripetal acceleration, is given by a = v²/r where
v = speed of rider andr = radius of circleGiven that a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. We have that
v = speed of rider = 34 m/s and r = radius of circle = 46/2 = 23 mSo, substituting the values of the variables into the equation for the acceleration, we have
a = v²/r
a = (34 m/s)²/23 m
a = 1156 m²/s²/23 m
a = 50.26 m/s²
a ≅ 50.3 m/s²
So, the acceleration, in m/s² , that riders experience is 50.3 m/s²
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1. Do stars going supernova have any impact on
allowing life to exist? Why?
Yes, the stars going supernova will have impact on allowing life to exist in nearby planets.
When a star goes supernova, a large amount of radiation is emitted. So, if a nearby planet inhabiting life has a ozone layer, it will be depleted. This results in increased harmful radiation levels on the ground. There will be mutations in organisms that can survive the radiations. Those that are not strong will die.
A supernova is the explosion of a star. This phenomenon happens when a star's nuclear fuel in its core runs out. As a result the pressure created by the burning in its core becomes completely null. Thus the gravity is only force acting, so the star collapses on itself emitting huge quantities of light and harmful radiation.
Therefore, the stars going supernova will have impact on allowing life to exist in nearby planets.
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You pull a rope to the left with 300 N and a friend pulls the rope to the right with 425 N. Draw a vector for the two forces acting on the rope
The total forces acting on the rope is 125 N towards the right side.
125 N of total forces are being applied to the rope's right side.
How are two forces operating on the rope represented by a vector?300 N of force as well as additional forces are applied in the proper direction.These forces are 425 N and are bigger than the starting force. The necessary vector diagram is shown here.The two forces' large, calm vector diagram is seen here. We must now determine the product of these two forces for part B.These two forces combine to produce a vector that is equal to the bigger force in the right direction less the smaller force in the left.Due to the smaller forces moving left. Therefore, since positive (425 -300) N is equivalent to 125 N, we have determined that the direction is correct.These two forces add up to 125 newtons moving in the proper direction.We must determine the size of the resultant, which is the magnitude of 125 newtons, for part C.The rightward movement of the outcome entities. The response to part C is this.To construct the resultant vector for party in this manner, we must widen it. The rope is this.Small and pointing in the right direction by 125 N, the outcome vector is small.To know more about vector visit:
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A driver travels +2170 m in 35.0
S. If the driver's initial velocity is +62.0 m/s, what is her acceleration?
HELP PLEASE
The acceleration of driver with given values is - 1.771 m/s².
Equation :To know acceleration used formula is the rate of change of the velocity of an object with respect to time that is,
a = dv / dt
Where,
dv is the small change in velocity
dt is change in time of an object
Given,
The distance traveled by the driver is +2170 m
The time taken by the driver is 35. 0 s
The initial velocity of driver is + 62.0 m/s
Therefore , to get the acceleration of the driver with the equation of motion
v = u + at
Here v is the final velocity which is taken zero
Then by putting the values in the above equation,
0 = (+62. o m/s) + (a) 35.0s
a = - (+62. o m/s) / ( 35.0s)
a = - 1.771 m/s²
The negative sign of acceleration shows that, the driver is slowing then acceleration is in the opposite as the velocity.
So, the acceleration
a = -1.771 m/s².
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Consider the case of an object moving with
constant acceleration a along a straight line.
If we plot v(t) versus t, we find that v(t) plots
as a straight line with some slope.
What is the physical meaning of that slope?
The straight line in the velocity versus time graph has a physical significance as it depicts constant acceleration of the motion.
What is acceleration?Acceleration is a physical quantity which is defined as the change of velocity per unit time it is a vector quantity and therefore can be both positive and negative.
What is velocity versus time graph?Velocity versus time graph is the depiction of emotion in which the y-axis represents the velocity of the motion and the x-axis represents the time the graph can either be a positive state line or a curve depending on the acceleration of the motion.
According to the question the velocity versus time graph in our case is a straight line.
A straight line in a velocity versus time graph means that motion has a constant acceleration.
The following conclusion can also be reached from the use of differential calculus as we differentiate velocity with respect to time we get a new physical quantity that is known as acceleration.
On differentiating velocity with respect to time we will get a new value that will represent the change in velocity per unit time and since from the definition of acceleration we know that acceleration is change in velocity per unit time therefore we can conclude that the straight line in the velocity time graph depicts constant acceleration.
Therefore, The straight line in the velocity versus time graph has a physical significance as it depicts constant acceleration of the motion.
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Suppose an electron in some atom absorbs energy and transitions from level 1 up to level 4. Which of the following is a true statement regarding the electron transitions back down to level 1?
a. It must transition from 4 to 3, then 3 to 2, then 2 to 1. All downward transitions are one step at a time.
b. 4 to 2, followed by 2 to 1, is possible. Downward transitions can be any number of levels.
c. It can go from 4 to 1 only. The downward transition must match the upward one.
Marking brainliest for the right awnser
Answer:
It's the last one- Finley > Xander > Max
Explanation:
You just divided the velocity by the time
A flowerpot falls from a window sill 36.5 m
above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? Choose upwards to be
the positive y direction. The acceleration of
gravity is 9.81 m/s
2
Answer in units of m/s.
When a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
From Newton's third equation of motion,
v^2 = u^2 + 2gh
where,
h is the height of the object or body from ground
u is the initial velocity of the body or object
v is the final velocity of the body or object
g is the acceleration due to gravity
Now, as we know that
Flowerpot is at rest. So, u = 0
g = 9.81m/s^2
h = 36.5m
By substituting all the values, we get
v^2 = 2 × 9.81 × 36.5
= 716.13
v = 26.7m/s
Thus, we concluded that when a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
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The thermal energy that causes the ice to melt is transferred from the lemonade as it cools. The loss of this thermal energy causes the temperature of the 300 g of the lemonade to fall by 19 °C. Calculate the specific heat capacity of the lemonade.
According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.
The formula for the specific heat capacity (C) = Q/ m × ΔT
Q is energy added and the value, which is 334J
m is the mass of the lemonade, which is 300g = 0.3 kg
Δ T is the change in temperature, which is 19°C =(273+19)= 292 K
So, C = 334/ 0.3 × 292
= 3.81 J/kg/k
So the specific heat capacity of the lemonade is 3.81 J/kg/k.
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Suppose you landed on an unknown planet whose mass is 10x that of the Earth and whose radius is 3x that of the Earth. How much would you weigh on this new planet?
Give your answer in what fraction or multiple of your earthly weight.
Mass on the planet would be 10/3 times the mass on Earth weigh on this new planet.
How do you define mass?A quantitative measure of the fundamental characteristic of all matter, inertia. In essence, it's the resistance of a mass of matter to changing its direction or speed in reaction to the force applied to it. The much more weight a body has, the less change an applied force produces.
Briefing:Let the mass of Earth = Me
Let the radius of Earth = Re
Mass of the planet, Mp = 10Me
Radius of the planet, Rp = 3Re
Weight on other planet, W = ?
Weight on planets is determined by the gravitational force
Gravitational force, F = GMm/r²
where, G = gravitational constant
M = Mass of the planet
m = our mass
r = radius of the planet
Gravitational force on Earth:
F = G X Me X ma/ Re².....eq (1) (ma = mass on earth)
Gravitational force on planet :
F = G X 10Me X mₓ/ (3Re)²....eq (2) (mx = mass on other planet)
Dividing both the equations, we get
mx = 10/3ma
Therefore, mass on the planet would be 10/3 times the mass on Earth.
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A satellite orbiting Earth at an orbital radius [tex]r[/tex] has a velocity [tex]v[/tex]. Which represents the velocity if the satellite is moved to an orbital radius of [tex]4r[/tex]?
A. [tex]4v[/tex]
B. [tex]\frac{1}{2}v[/tex]
C. [tex]\frac{1}{4}v[/tex]
D. [tex]2v[/tex]
Answer: C
Explanation:
The bigger the satellite, the longer it will take to get around the satellite. Hence, the velocity would get smaller.
r*v=4r*?
r*v/4r=?
r/4r * v=?
1/4 * v=?
?=v/4 ==> C
launched at ground level with an initial speed of 41 m/s, at an angle of 29° above the horizontal. It strikes a target above the ground 2.3 seconds
What is the vertical distance, in meters, from where the projectile was launched to where it hits the target?
The horizontal distance is 82.455m and vertical distance is 19.734m
Let us first find the x and y components of velocity
The velocity is given to be 41m/s
the angle of projectile is given to be 29 degree
The x component of velocity = Vx =v cosα =41 x 0.8746 =35.85 m/s
The y component of velocity= Vy= v sinα=41 x 0.484 =19.85 m/s
The horizontal displacement x= Vxt = 35.85 x 2.3 =82.455 m
To solve for vertical distance y = Vyt+1.2at^2
y = 19.85 x 2.3 + 1/2 x -9.8 m/s^2 x 2.3
= 19.734m
Hence, the horizontal distance is 82.455m and vertical distance is 19.734m
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