Answer:
The answer is "[tex]\bold{e^{-t} \sin t}[/tex]"
Explanation:
Given equation:
[tex]\to x+2x+2x=0.............(a)[/tex]
Let x= e^{mt} be a solution of the equation will be:
[tex]\to m^2+2m+2=0[/tex]
compare the value with the [tex]am^2+bm+c=0[/tex]
[tex]\to a= 1\\\to b= -2\\\to c= 2\\[/tex]
Formula:
[tex]\bold{=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\\\\=\frac{-2 \pm \sqrt{(-2)^2-4\times 1 \times 2}}{2 \times 1}\\\\=\frac{-2 \pm \sqrt{4-8}}{2}\\\\=\frac{-2 \pm \sqrt{-4}}{2}\\\\=\frac{-2 \pm 2i}{2}\\\\[/tex]
Calculate the g.s at equation (a):
[tex]\to x = e^{-t} (c_1 \cos t+ c_2 \sin t)............(b)\\\\\to x = e^{-t} (c_2 \cos t -c_1 \sin t) - e^{-t} (c_1 \cos t + c_2\sin t) ...............(c)\\\\[/tex]
[tex]_{when} \\\\\to t= 0\\\\\to x=x_0\\\\\to x= v_0 =1 \\\\ \ then \ form \ equation \ (b) \ and \ equation \ (c)[/tex]
[tex]\to a= 0 \\ \to c_2 -c_1 =1 \\ \to c_2=1[/tex]
The value of [tex]x = e^{-t} ( 0 \times \cos t + 1 \times \sin t)[/tex]
[tex]\boxed{\bold{x = e^{-t} (\sin t)}}[/tex]
Determine the voltage across a 2-μF capacitor if the current through it is i(t) = 3e−6000t mA. Assume that the initial capacitor voltage is zero g
Answer:
[tex]v = 250[1 - {e^{-6000t}}][/tex] mV
Explanation:
The voltage across a capacitor at a time t, is given by:
[tex]v(t) = \frac{1}{C} \int\limits^{t}_{t_0} {i(t)} \, dt + v(t_0)[/tex] ----------------(i)
Where;
v(t) = voltage at time t
[tex]t_{0}[/tex] = initial time
C = capacitance of the capacitor
i(t) = current through the capacitor at time t
v(t₀) = voltage at initial time.
From the question:
C = 2μF = 2 x 10⁻⁶F
i(t) = 3[tex]e^{-6000t}[/tex] mA
t₀ = 0
v(t₀ = 0) = 0
Substitute these values into equation (i) as follows;
[tex]v = \frac{1}{2*10^{-6}} \int\limits^{t}_{0} {3e^{-6000t}} \, dt + v(0)[/tex]
[tex]v = \frac{1}{2*10^{-6}} \int\limits^{t}_{0} {3e^{-6000t}} \, dt + 0[/tex]
[tex]v = \frac{1}{2*10^{-6}} \int\limits^{t}_{0} {3e^{-6000t}} \, dt[/tex]
[tex]v = \frac{3}{2*10^{-6}} \int\limits^{t}_{0} {e^{-6000t}} \, dt[/tex] [Solve the integral]
[tex]v = \frac{3}{2*10^{-6}*(-6000)} {e^{-6000t}}|_0^t[/tex]
[tex]v = \frac{-3000}{12} {e^{-6000t}}|_0^t[/tex]
[tex]v = -250 {e^{-6000t}}|_0^t[/tex]
[tex]v = -250 {e^{-6000t}} - [-250 {e^{-6000(0)}][/tex]
[tex]v = -250 {e^{-6000t}} - [-250][/tex]
[tex]v = -250 {e^{-6000t}} + 250[/tex]
[tex]v = 250 -250 {e^{-6000t}}[/tex]
[tex]v = 250[1 - {e^{-6000t}}][/tex]
Therefore, the voltage across the capacitor is [tex]v = 250[1 - {e^{-6000t}}][/tex] mV
In python code write a program that prompts the user to input two POSITIVE numbers — a dividend (numerator) and a divisor (denominator). Your program should then divide the numerator by the denominator, and display the quotient followed by the remainder.
Answer:
The python code for the given problem is written in explanation section.
Explanation:
The code for the given situation, in Python, can be written as follows:
x = int(input("Enter a positive number for dividend: "))
y = int(input("Enter a positive number for divisor: "))
quotient = x//y
remainder = x%y
print("The Quotient of the given calculation is:",quotient)
print("The Remainder of the given calculation is:",remainder)
Mild neurotoxins can cause which of these physical effects?
Which unit is used, when specifying a vehicle's height, length and width?
Meters
Millimeters
Kilometres
Centimeters
Answer:
Centimeters
Explanation:
While supporting load P, the maximum contraction permitted in a 4.75-m long pipe column is 7 mm. Given that E =180 GPa for the column, determine the stress in the pipe at the maximum allowable contraction.
Answer:
[tex]\mathbf{stress \ \sigma = 264.6 \ Mpa}[/tex]
Explanation:
From the concept of Hooke's Law,
[tex]E =\dfrac{ stress \ \sigma}{ strain \ \varepsilon}[/tex]
where;
[tex]strain \ \varepsilon = \dfrac{change \ in \ dimension }{original \ dimension}[/tex]
[tex]strain \ \varepsilon = \dfrac{7 \ mm }{4.75 \times 10^{3} \ mm}[/tex]
[tex]strain \ \varepsilon =0.00147368[/tex]
Recall:
[tex]E =\dfrac{ stress \ \sigma}{ strain \ \varepsilon}[/tex]
[tex]stress \ \sigma = E \times { strain \ \varepsilon}[/tex]
[tex]stress \ \sigma = 180 \times 10^{3} \ Mpa \times 0.00147[/tex]
[tex]\mathbf{stress \ \sigma = 264.6 \ Mpa}[/tex]
Thus, the stress in the pipe at the maximum allowable contraction = 264.6 Mpa
You are a designer of a new processor. You have to choose between two possible implementations (called M1 and M2) of the same architecture. a. Machine M1 has a clock rate of 2.8 GHz and the following characteristics:Instruction classes CPI (Clocks per instruction) for each Instruction classes Frequency A 1 40% B 3 25%C 3 25%D 5 10%Instruction classes CPI (Clocks per instruction) Frequency A 2 40%B 2 20% C 3 15%D 4 25%Required:a. What is the CPI for each machine? b. What are the native MIPS ratings for M1 and M2? c. Which machine has a better by the MIPS performance (by comparing their MIPS values) and by how much?
Answer:
A ) CPI : M1 = 2.4 , M2 = 2.65
B ) MIPS : M1 = 1083, M2 = 1056
C ) The machine that has a better performance based on MIPS is M1 and this is by 27 million number of instructions per sec
Explanation:
A) The CPI for each machine
CPI = ( Total number of execution cycles ) / ( instruction counter executed )
For Machine 1 ( M1 )
we have to make some assumptions : number of instructions = 10
number of times A was executed = 4 , Number of times B was executed = 2.5 , number of times C was executed = 2.5, Number of times D was executed = 1. and this was based on the frequency given above
hence CPI for M1 =[ ( 1 * 4 ) + ( 3 * 2.5 ) + ( 3 * 2.5 ) + ( 5 * 1 ) ] / 10
CPI for M1 = 2.4
For Machine 2 ( M2 )
we have to make some assumptions : number of instructions = 10
number of times A was executed = 4 , Number of times B was executed = 2. number of times C was executed = 1.5, Number of times D was executed = 2.5 times. and this was based on the frequency given above
Hence CPI for M1 = [ ( 2 * 4 ) + ( 2 * 2 ) + ( 3 * 1.5 ) + ( 4 * 2.5 ) ] / 10
CPI for M2 = 2.65
B ) Calculate the native MIPS ratings for M1 and M2
MIPS = ( instruction counts ) / ( Execution time * 10^6 )
For M1
Assumptions : number of instructions executed = 10
each clock cycle = 0.3846 * 10^-9. frequency = 2.6 Ghz
first we calculate the total execution time which is equal to :
= [ ( 1 * 4 ) + ( 3 * 2.5 ) + ( 3 * 2.5 ) + ( 5 * 1 ) ] * 0.3846 * 10 ^-9
= 9.2304 * 10 ^-9 secs
therefore the MIPS for M1
= 10 / ( 9.2304 * 10^-9 ) * 10^6 = 1083
For M2
Assumptions : number of instructions executed = 10
each clock cycle = 0.3846 * 10^-9. frequency = 2.8 Ghz
first we calculate the total execution time which is equal to :
= [ (2*4) + (2*2) + (3 * 1.5 ) + ( 4 * 2.5 ) ] * 0.3846 * 10^-9 = 9.4631 * 10^-9 secs
therefor the MIPS for M2
= 10 / ( 9.4631*10^-9) * 10^6 = 1056
C ) The machine that has a better performance based on MIPS is M1 and this is by 27 million number of instructions per sec
A wastewater is to be disinfected using ultraviolet (UV) light. Batch experiments find that the bacterial concentration decays under UV light with first-order kinetics, with a half of the initial bacteria killed after 6.2 minutes of illumination. You need to design a reactor than can kill 99% of bacteria in a stream having a flow rate of 140, 000 gal/d. Assume that regardless of the reactor type it will be possible to have UV illumination conditions identical to those of the batch experiment. a. Based on the batch experiments, what is the first-order rate constant k for bacterial inactivation
Answer:
k = 0.1118 per min
Explanation:
Assume;
Initial number of bacteria = N0
Number of bacteria IN 'T' time = Nt
So,
[tex]Nt=N0e^{-kt}\\\\in\ 6.2 min\\\\\\frac{N0}{2}= N0e^{-k(6.2)}\\\\ln\frac{1}{2} = -k[6.2][/tex]
k = 0.1118 per min
Please help I need by today !!
What is the purpose of an engineering notebook ?
What is the purpose of a portfolio?
Find the Rectangular form of the following phasors?
1. P =10
2. P = 5
3. P = 25
4. P = 54
5. P = 65
6. P = 95
7. P = 250
8. P = 8
9. P = 35
10. P = 150
Answer:
The angles are missing in the question.
The angles are :
45, 30, 60, 90, -34, -56, 20, -42, -65, -15
P=10, P=5, P=25, P=54, P=65, P=95, P=250, P=8, P=35, P=150
Explanation:
1. P = 10, θ = 45° rectangular coordinates
x = r cosθ , y = r sinθ
So, rectangular form is x + iy
x = P cosθ = 10 cos 45°
= 7.07
y =P sinθ = 10 sin 45°
= 7.07
Therefore, rectangular form
x + iy = 7.07 + i (7.07)
2. P = 5 , θ = 30°
x = 5 cos 30° = 4.33
y = 5 sin 30° = 2.5
So, (x+iy) = 4.33 + i (2.5)
3. P = 25 , θ = 60°
x = 25 cos 60° = 12.5
y = 25 sin 60° = 21.65
So, (x+iy) = 12.5 + i (21.65)
4. P = 54 , θ = 90°
x = 54 cos 90° = 0
y = 54 sin 90° = 54
So, (x+iy) = 0+ i (54)
5. P = 65 , θ = -34°
x = 65 cos (-34°) = 53.88
y = 65 sin (-34°) = -36.34
So, (x+iy) = 53.88 - i (36.34)
6. P = 95 , θ = -56°
x = 95 cos (-56)° = 53.12
y = 95 sin (-56)° = -78.75
So, (x+iy) = 53.12 - i (78.75)
7. P = 250 , θ = 20°
x = 250 cos 20° = 234.92
y = 250 sin 20° = 85.5
So, (x+iy) = 234.92 + i (85.5)
8. P = 8 , θ = (-42)°
x = 8 cos (-42)° = 5.94
y = 8 sin (-42)° = -5.353
So, (x+iy) = 5.94 - i (5.353)
9. P = 35 , θ = (-65)°
x = 35 cos (-65)° = 14.79
y = 35 sin (-65)° = -31.72
So, (x+iy) = 14.79 - i (31.72)
10. P = 150 , θ = (-15)°
x = 150 cos (-15)° = 144.88
y = 150 sin (-15)° = -38.82
So, (x+iy) = 144.88 - i (38.82)
The interactive activities in this course
A. will be tested in lesson quizzes but not the final exam
B. will be tested in the final exam but not the lesson quizzes
C. will be scored by your instructor
D. will not be score
The interactive activities for the course will be scored by the instructor.
Interactive activities
Interactive classroom activities are defined as the activities or interactive sessions which is a two way communications or discussions where the students involved also participate in discussions and interacts with the teacher or the instructor.
In some school curriculars, the interactive activities are scored and in some it is not scored.For the particular course, the interactive sessions will be scored by the instructor.
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Which of the following was the most important group of engineers on the project described in the following scenario? The "Big Dig" in Boston, Massachusetts, redesigned the entire highway system in the city, moving roads underground in many areas. The "Big Dig* required the services of different types of engineers. computer engineers civil engineers manufacturing engineers electrical engineers
Answer:
the answer is A
Explanation:
Answer:
A
Explanation:
which option identifies the AFNR pathway in the following scenarios? Jalal works for a prestigious golf course that hosts an annual PGA Tour event. His employers depend on him to use cutting-edge science and technology to prepare the course and maintain it with the utmost care.
A. Agricultural System
B. Plant System
C. Biotechnology System
D. Natural Resource System
Answer: C. Biotechnology system
Explanation:
If the driver gear has 10 teeth and is moving at 10 RPMs (revolutions per minute), at what speed would the driven gear move if it has 20 teeth?
Answer:
5 rpm
Explanation:
Each turn of the driver gear moves 10 teeth past the point of engagement with the driven gear. That is half of the 20 teeth on the driven gear, so it makes 1/2 turn for each turn of the driver.
In 1 minute, the driver makes 10 turns, so the driven gear makes 5 turns. Its speed is 5 rpm.
Buying shop supplies from the shop owner to work on your own car at home is an ethical practice
Answer:
yes yes it is why wouldn't it be
It is true that buying shop supplies from the shop owner to work on your own car at home is an ethical practice.
What is ethical practice?The term "ethical practises" refers to deeds and conduct that uphold established moral and social norms as well as shared values.
Honesty, fairness, transparency, accountability, respect, and responsibility are the traits that define these procedures.
The precise circumstances and the relationship between the shop owner and the individual will determine if purchasing shop materials from a shop owner to work on your own car at home is an ethical practise.
The exact situation and the relationship between the shop owner and the individual will determine whether or not purchasing shop materials from a shop owner to work on your own car at home is ethical.
Before implementing such a method, it is crucial to think about the possible outcomes and any ethical issues.
Thus, the given statement can be considered as true.
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Three single-phase loads in parallel are supplied from a 1400V (RMS), 60 Hz supply. The loads are as follows: Load 1: Inductive load: 125 kVA, 0.28 power factor Load 2: Capacitive load: 10 kW, 40 kVAR Load 3: Resistive load: 15 kW Find the total kW, kVAR, kVA, and supply power factor. (5 points) Find the capacitive correction (in kVARs) required to improve the power factor to 0.8 and calculate the supply current with this correction in place. (10 points) What is the least current that can service these three loads and how much compensation would it require
Answer:
The answer is below
Explanation:
[tex]\theta_1=cos^{-1}0.28=73.74^o\ lagging\\\\S_1=125\angle 73.74^o=35\ kW+j120\ kVAR\\\\S_2=10\ kW-j40\ kVAR\\\\S_3=15\ kW[/tex]
Total power = P = 35 kW + 10 kW + 15 kW = 60 kW
Total kVAR = 120 kVAR - 40 kVAR = 80 kVAR
[tex]Total\ apparent \ power =S= S_1+S_2+S_3=(35+j120)+(10-j40)+(15)\\\\S=60\ kW+j80\ kVAR=100\angle 53.13^o\\\\Current(I)=\frac{S^*}{V^*} \frac{100000\angle -53.13^o}{1400\angle0}=71.43\angle-53.13^o\\ \\Power\ factor (PF)=cos(53.13)=0.6\ lagging\\\\The \ new\ power\ factor\ is\ to \ be\ 0.8[cos^{-1}0.8=36.87^o], hence\ since\ the\ total\ \\real\ power(P)= 60\ kW, the\ capacitor\ kVAR(Q_c)\ is:\\\\Q_c=60tan(53.13)-60tan(36.87)=80-45=35\ kVAR\\\\[/tex]
[tex]C=\frac{Q_c}{wV^2} =\frac{35000\ VAR}{2\pi*60\ Hz*1400\ V}=47.38\ \mu f[/tex]
New current (I') = [tex]\frac{S'^*}{V^*}=\frac{60000-j45000}{1400}=53.57\angle-36.87^o[/tex]
Current reduce from 71.43 A to 53.57 A
The minimum fresh air requirement of a residential building is specified to be 0.35 air changes per hour (ASHRAE, Standard 62, 1989). That is, 35 percent of the entire air contained in a residence should be replaced by fresh outdoor air every hour. If the ventilation requirement of a 2.7-m-high, 200-m2 residence is to be met entirely by a fan, determine the flow capacity in L/min of the fan
Answer:
3150 L/min
Explanation:
The volume of the room is the product of the height of the room and its area. It is given as:
Volume (V) = height (h) × Area (A)
V = h × A
Height = 2.7 m, Area = 200 m². Hence:
V = h × A = 2.7 × 200 = 540 m³
The flow capacity ([tex]\dot {V}[/tex]) is given by
[tex]\dot {V}=ACH*Volume\ of\ room[/tex]
ACH = air changes per hour = 0.35
[tex]\dot {V}=ACH*Volume\ of\ room\\\\\dot {V}=0.35*540\\\\\dot {V}=189\ m^3/h[/tex]
But 1 m³ = 1000 L, 1 hr = 60 min
[tex]\dot{V}=189\ m^3/h=\frac{189\ m^3*\frac{1000\ L}{1\ m^3} }{1\ h*\frac{60\ min}{1\ h} } =3150\ L/min\\\\\dot{V}=3150 \ L/min[/tex]
What are the four categories of engineering materials used in manufacturing?
Answer:
metals, composite, ceramics and polymers.
Explanation:
The four categories of engineering materials used in manufacturing are metals, composite, ceramics and polymers.
i) Metals: Metals are solids made up of atoms held by matrix of electrons. They are good conductors of heat and electricity, ductile and strong.
ii) Composite: This is a combination of two or more materials. They have high strength to weight ratio, stiff, low conductivity. E.g are wood, concrete.
iii) Ceramics: They are inorganic, non-metallic crystalline compounds with high hardness and strength as well as poor conductors of electricity and heat.
iv) Polymers: They have low weight and are poor conductors of electricity and heat
why did my dad leave me yesterday like whatd i do?
Answer:
hmm i would try calling him. ask your mom or other adults where he is!
Explanation:
hope you get help soon!
Answer:
if he actually said that about the money, then do it. If its dirty money then get away. drug cartels or corrupt people will torture you just to get back at him, regardless if he even knows or if you did anything to them. If you are female, then yeah you really should run. its like the tv shows, but except, they dont have to keep it within movie standards.
Explanation:
he following is true for a Function Generator (select all that apply): Select one or more: a. It produces a variety of patterns of voltage in adjustable range of frequencies and amplitudes. b. Its main use is to provide input signals to circuits to test the response to known signals. c. It can deliver the set voltage level of the signal waveform to any load connected to its outputs without any attenuation. d. It can measure peak to peak voltage of sine waves. e. Some of common useful signal it can generate include sine, square, pulse, triangular, sawtooth waveforms.
Answer:
A,C and E
Explanation:
It should be understood that a function generator can be explained as a piece of electronic test equipment or software which is used in generating different types of electrical waveforms over a wide range of frequencies. It should be noted that some of the examples of waveforms produced by the function generator are the sine wave, square wave, triangular wave and sawtooth shapes.
Therefore, the reason why of picking the options as highlighted above.
The best way to check the efficiency of individual cylinders is:________.
Answer:
To run. The machine one at a time
Explanation:
factors of production examples for a home?
Answer:
The four factors of production are land, labor, capital, and entrepreneurship. They are the inputs needed for supply. They produce all the goods and services in an economy. That's measured by gross domestic product.
please give brainlist
hope this helped........
Drivers must slow down from 60 mi/hr to 40 mi/hr to negotiate a severe curve on a rural highway. A warning sign for the curve is clearly visible for a distance of 120 ft. How far in advance of the curve must the sign be located to ensure that vehicles have sufficient distance to decelerate safely. Use the standard reaction time and deceleration rate recommended by AASHTO for basic braking maneuvers.
Answer: the distance in advance of the curve the sign must be located to ensure that vehicles have sufficient distance to decelerate safely is 292.07 ft
Explanation:
first we calculate the distance to place sign board in advance to curve for decelerating the speed
d = 1.47Si t + [ (Si² - Sf²) / 30(0.348 ± 0.01G)
where d is the safe stopping distance, initial speed is Si (60 mi/hr ), time reaction is t (2.5s), Sf is the final speed (40 mi/hr), G is the grade (0).
so we substitute
d = (1.47 × 60 × 2.5) + [ (60² - 40²) / 30(0.348 ± 0)
= 220.5 + ( 2000/10.44)
= 220.5 + 191.57
= 412.07 ft
Now giving that a warning sign is clearly visible at a distance of 120 ft
optimum safe distance will be
d = minimum distance - sign visible distance
d = 412.07 - 120
d = 292.07 ft
therefore the distance in advance of the curve the sign must be located to ensure that vehicles have sufficient distance to decelerate safely is 292.07 ft
What are the benefits of using the engineering design process
Answer:
Some of the benefits are tangible for they are visible in the design and production process, while the other benefits are intangible which may not be visible directly but result in improvement in the quality of product, better control over designing and production process, reduction of stress on the designers etc.
6. You are evaluating flow through an airway. The current flow rate is 10 liters per minute with a fixed driving pressure (P1) of 20 cm H2O and a fixed downstream pressure (P2) of 5 cm H2O. Identify whether each statement is correct or incorrect if we pinch the lumen in the middle of the tube. a. The flow would decrease b. P1 would increase to maintain the flow rate c. The resistance would increase
Answer:
B) P1 would increase to maintain the flow rate ( correct )
C) The resistance would increase (correct )
Explanation:
flow rate = 10 liters per minute
Driving pressure (p1) = 20 cm H20
Fixed downstream pressure (p2) = 5 cm H20
The correct statements when we pinch the Lumen in the middle of the tube would be : P1 would increase to maintain the flow rate and The resistance would increase.this is because when we pinch the Lumen we reduce its diameter and the reduction of its Diameter will result to increased resistance against the flow and resistance of flow is directly proportional to pressure hence P1 would increase as well
The wrong statement would be : The flow would decrease
Which sentence best compares LCDs with CRTs
Answer:
LCDs consume less power than CRTs
Explanation:
The sentence that best compares LCDs with CRTs is that "LCDs consume less power than CRTs".
Recently, in many homes and offices, cathode ray tube (CRT) monitors are being replaced by liquid crystal display (LCD) monitors. There are some benefits that LCD panels offer over CRT monitors. Some of them are:
LCD monitors don't usually take up much space. They take less space than CRT monitors. Also, LCDs consume less power than CRT monitors. Which means that CRTs consume more power than LCDs. LCD monitors gives a much brighter image than CRT monitors .
A condenser accepts steam from the turbine in problem 2 at a pressure of 2.34 kPa. Saturated water at the same pressure leaves the condenser. (Note: 20 C is the saturation Temperature for 2.34 kPa)) a. Give P, v, u, h and s for the saturated liquid water leaving the condenser. b. How much heat leaves the condenser per kg of steam? c. What is the heat transfer rater from the condenser, assuming a water flow of 1 kg/s,
Answer:
The answer is "83.98, 1889.195, and 1889.195"
Explanation:
Given value:
[tex]\bold{P_{4}=2.34 \ kPa}[/tex]
In point a:
The value of [tex]h_{f4}=83.915 \ \ \frac{Kj}{kg}\\[/tex]
[tex]V_4=0.001002 \ \ \frac{Kj}{kg}\\\\U_4= 83.98 \ \ \frac{Kj}{kg}\\\\[/tex]
In point b:
calculating heat leaves formula= [tex]h_3-h_{f4}[/tex]
[tex]= 1973.11-83.915\\\\= 1889.195 \ \ \frac{KJ}{kg}[/tex]
In point c:
calculating Heat transfer rate formula[tex]=m(h_3-h_4)[/tex]
[tex]= 1(1889.195)\\\\ = 1889.19 \ \ kw.[/tex]
What are sketches or technical drawings called
Answer:
Technical drawing, also known as drafting or draughting, is the act and discipline of making detailed drawings. These drawings visually communicate how something works or how it is to be made.
When an object is made of the plastic polyester (PET), it uses antimony as a catalyst. After production, antimony can leach into food and drink stored in PET containers. Usually, if stored correctly for a short amount of time, the amount of antimony found in liquids is well below the safety limits. However, there have been reports of as much as 44.7 micrograms per liter [µg/L] of antimony found in fruit juice concentrates. How much antimony, in units of moles [mol], could be found in one gallon [gal] of fruit juice concentrate at this level of contamination? The molecular mass of antimony is 121.76 grams per mole [g/mol].
Answer:
1.39 µmol
Explanation:
(1 gal) × (44.7 µg/L)/(121.76 g/mol)(3.785411784 L/gal) = 1.39 µmol
Identify the characteristics of parallel flow heat exchangers.
a. The hot and cold fluids enter the heat exchanger at opposite ends.
b. The hot and cold fluids move in the opposite direction.
c. The hot and cold fluids move in the same direction.
d. The hot and cold fluids enter the heat exchanger at the same end.
Answer:
A.
Explanation:
Eleanore Rigby picks up the rice in the church after the wedding. Why she might she do this?
Explanation:
It gives her a sense of purpose.
