Construct a confidence interval of the population proportion at the given level of confidence.

x=120 n =1200 95% confidence

The upper bound of the confidence interval is ____ (round to the nearest thousandth as needed)

The lower bound of the confidence intervals is ____ (round to the nearest thousandth as needed)

The probability of getting exactly 8 girls out of 11 births is 21.9%.

The binomial probability formula is used to calculate the probability of getting a certain number of successes (in this case, girls) out of a fixed number of trials (in this case, 11 births).

The first part of the formula (11 choose 8) is the number of ways to choose 8 girls out of 11 births, which is 330.

i.e;    (11 choose 8) * (0.5)^8 * (0.5)^3 = 330

The second part of the formula (0.5)^8 represents the probability of getting 8 girls out of 11 births assuming each birth has a probability of 0.5 of being a girl.

The third part of the formula (0.5)^3 represents the probability of getting 3 boys out of 11 births assuming each birth has a probability of 0.5 of being a boy.

i.e; (11 choose 8) * (0.5)^8 * (0.5)^3 = 330 * 0.00390625 * 0.125 = 0.21875

When we multiply all of these values together we get the final probability of getting exactly 8 girls out of 11 births, which is approximately 0.21875 or about 21.9%.

Therefore, the probability of getting exactly 8 girls out of 11 births is given by the binomial probability formula: (11 choose 8) * (0.5)^8 * (0.5)^3 = 330 * 0.00390625 * 0.125 = 0.21875 or about 21.9%.

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x/12 > 10 is the inequality that describes the problem. This inequality represents the fact that Turner made more than 10 fluid ounces of apple cider, and that he divided that amount evenly among 12 mugs.

Algebra is a discipline of mathematics where abstract symbols rather than concrete numbers are subjected to arithmetic operations and formal transformations. The idea that there is such a separate branch of mathematics, as well as the term algebra to identify it, came about gradually through time. This article traces the development of the equation notion, number systems, symbols for representing and modifying mathematical claims, and the contemporary abstract structural perspective of algebra.

The order in which you perform operations in arithmetic and algebra is governed by a number of laws. The Commutative, Associative, and Distributive Laws are the three that receive the most attention.

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The number of points in a large outer ring and a smaller bull's-eye are 18 points and 84 points respectively.

In order to write a system of equations that model this situation, we would assign variables to the large outer ring and the smaller bull's-eye respectively, and then translate the word problem into algebraic equation as follows:

Next, we would translate the word problem into algebraic equation as follows for both Megan and Paula:

3x + 4y = 390

4x + 5y = 492

In this scenario, we would use an online graphing calculator to plot and solve the above system of equations graphically, with a point of intersection at (18, 84) as shown in the image attached below.

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Answer:

P is equal to or greater than 27  

(c)

Step-by-step explanation:

The exact measurements for the largest side is 12√10 inches. Hence option a is the correct option.

What is the right triangle?

A right triangle or right-angled triangle, or more formally an orthogonal triangle, formerly known as a rectangle triangle, is a triangle with one right angle, i.e. two perpendicular sides. Trigonometry is founded on the relationship between the sides and other angles of a right triangle.

Given that the angles of a triangle are 30-60-90.

The smallest angle is always opposite the shortest side, and vice versa. The longest side is also opposite the largest angle, and vice versa.

The opposite side of angle 30 is the shortest side of the triangle.

The opposite side of angle 90 is the longest side of the triangle.

Sine law:

a/sin A = b/ sin B =c/sin C

a is the opposite side of angle A, b is the opposite side of angle B, c is the opposite side of angle C.

Assume that the length of the longest side is a.

Applying sine law in the given triangle:

6√10/sin 30 = a/sin 90

6√10/(1/2)= a/1

a = 12√10

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Answer:

Eight workers can pave a 1-mile stretch of road in 6 hours.

Step-by-step explanation:

The median and the quartiles of the data-set are given as follows:

The median of a data-set is the middle value of the data-set, that is, the value of which 50% of the data-set is less than and 50% of the data-set is greater than.

The data-set is composed by 16 elements, which is an even cardinality, hence the median is the mean of the 8th and of the 9th elements, as follows:

Median = (20 + 24)/2

Median = 22.

Then the first quartile is the median of the first seven elements of the data-set, which is the fourth element, hence it is of 13.

The third quartile is the median of the last seven elements of the data-set, hence it assumes a value of 29.

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Answer: first quartile is 14 , the median is 22 , and the third quartile is 28

Step-by-step explanation:because I answered that on my homework and it worked.Take words from people who have tried it before!!!

Question 5

The remaining interior angle is [tex]135^{\circ}[/tex].

[tex]\frac{x}{\sin 19^{\circ}}=\frac{32}{\sin 135^{\circ}}\\ \\ x=\frac{32 \sin 19^{\circ}}{\sin 135^{\circ}} \\ \\ x \approx 14.7[/tex]

Question 6

The remaining interior angle is [tex]27^{\circ}[/tex].

[tex]\frac{x}{\sin 27^{\circ}}=\frac{28}{\sin 75^{\circ}}\\\\x=\frac{28\sin 27^{\circ}}{\sin 75^{\circ}}\\\\x \approx 13.2[/tex]

Question 7

The remaining interior angle is [tex]59^{\circ}[/tex].

[tex]\frac{x}{\sin 59^{\circ}}=\frac{9}{\sin 70^{\circ}}\\\\x=\frac{9\sin 59^{\circ}}{\sin 70^{\circ}}\\\\x \approx 8.2[/tex]

Question 8

The remaining interior angle is [tex]95^{\circ}[/tex].

[tex]\frac{x}{\sin 33^{\circ}}=\frac{16}{\sin 95^{\circ}}\\\\x=\frac{16 \sin 33^{\circ}}{\sin 95^{\circ}}\\\\x \approx 8.7[/tex]

Step-by-step explanation:

first

for washing 10 houses we get (14*10) dollars which is 140

now for washing cars ur frirnd gets (28*5) which is also 140

so u both earn the same amount

hence the answer is neither.

Compared to a 95% confidence interval, a 99% confidence interval will be wider.

A confidence interval is a range of values that is likely to contain the true population mean, with a certain level of confidence.

The level of confidence is usually represented as a percentage, such as 95% or 99%. The higher the level of confidence, the wider the confidence interval will be. This is because a higher level of confidence means that the researcher wants to be more certain that the true population mean falls within the interval, so they will make the interval wider to increase the chances of this happening.

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Answer: The function that models the relationship between the number of games played (n) and the number of credits remaining on the card (C(n)) is C(n) = 5n.

Step-by-step explanation: This function can be derived by realizing that each game costs 5 credits to play, so as the number of games played (n) increases, the number of credits remaining on the card (C(n)) decreases by 5 for each game played.

For example, if Shivani played 16 games before her card ran out of credits, we can substitute n = 16 into the function to find that C(16) = 5(16) = 80 credits. This means that her card had 80 credits on it before she started playing games.

To plot points on the graph, we can select a few different values of n and substitute them into the function to find the corresponding values of C(n). Here are a few examples:

When n = 0, C(n) = 5(0) = 0. This represents the case when Shivani has not played any games yet and has no remaining credits on her card.

When n = 8, C(n) = 5(8) = 40. This represents the case when Shivani has played 8 games and has 40 credits remaining on her card.

When n = 16, C(n) = 5(16) = 80. This represents the case when Shivani has played 16 games and her card has no remaining credits.

We can plot these points on the graph and label them (0,0), (8,40), (16,0) respectively.

Note that the y-intercept is (0,0) and the x-intercept is (16,0)

Graph:

n C(n)

0 0

8 40

16 0

The graph is a straight line starting from (0,0) and going down till (16,0) with a slope of -5.

Answer:

The solution of the mathematical expressions will be 0.175.

Step-by-step explanation:

Given that;

The mathematical expressions are,

⇒ [ 2 - | - 1/4 - 2 (-3/5) | ] ÷ -6

Now,

Solve the mathematical expression as;

⇒  [ 2 - | - 1/4 - 2 (-3/5) | ] ÷ -6

Using the BODMAS rule to solve the expressions as;

⇒ [ 2 - | - 1/4 - 2 (-3/5) | ] ÷ -6

⇒ [ 2 - | - 1/4 + 6/5 | ÷ -6

⇒ [ 2 - 19/20 ] ÷ -6

⇒  [ 21/20] ÷ -6

⇒ 21/20 x 1/-6

⇒ - 7 / 40

Therefore,

The solution of the mathematical expressions will be 0.175.

But you didn't have to cut me off

Make out like it never happened and that we were nothing (aah-ooh)

And I don't even need your love (ooh)

But you treat me like a stranger, and that feels so rough (aah)

No, you didn't have to stoop so low (ooh)

Have your friends collect your records and then change your number (aah)

I guess that I don't need that, though

Now you're just somebody that I used to know

Answer:

[tex]-\dfrac{7}{40}[/tex]

Step-by-step explanation:

Given expression:

[tex]\left[2-\left|-\dfrac{1}{4}-2\left(-\dfrac{3}{5}\right)\right|\right] \div (-6)[/tex]

Carry out the operations inside the absolute value bars (following the order of operations):

[tex]\implies \left[2-\left|-\dfrac{1}{4}+\dfrac{6}{5}\right|\right] \div (-6)[/tex]

[tex]\implies \left[2-\left|\dfrac{19}{20}\right|\right] \div (-6)[/tex]

As the fraction inside the absolute value bars is already positive, we can simply remove the bars:

[tex]\implies \left[2-\dfrac{19}{20}\right] \div (-6)[/tex]

Rewrite 2 as 40/20 and carry out the subtraction inside the square brackets:

[tex]\implies \left[\dfrac{40}{20}-\dfrac{19}{20}\right] \div (-6)[/tex]

[tex]\implies \left[\dfrac{40-19}{20}\right] \div (-6)[/tex]

[tex]\implies \left[\dfrac{21}{20}\right] \div (-6)[/tex]

Rewrite -6 as a fraction:

[tex]\implies \dfrac{21}{20} \div -\dfrac{6}{1}[/tex]

When dividing fractions, multiply the first fraction by the reciprocal of the  second fraction:

[tex]\implies \dfrac{21}{20} \times-\dfrac{1}{6}[/tex]

[tex]\implies \dfrac{21 \times (-1)}{20 \times 6}[/tex]

[tex]\implies -\dfrac{21}{120}[/tex]

Reduce the fraction to its simplest form by dividing the numerator and denominator by the highest common factor, 3:

[tex]\implies -\dfrac{21 \div 3}{120 \div 3}[/tex]

[tex]\implies -\dfrac{7}{40}[/tex]

The number of distinct prime factors are 17

The term prime factors in math is defined as a method to find the prime factors of a given number and it can be said a composite number.

As per the definition of prime factor here we have know that a and b have 7 prime factors in common.

Then it can be written as a*b has 28 prime factors

And here we also know that the number of prime factors of a or b that are not common to both is 21

Here we have also know that a has less prime factors than b so at most 10 of these 21 extra prime factors belong to a

Then the  the most prime factors that  a  can have is calculated as

=> 7 + 10 = 17

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Answer:

a.x²+4x+4

=x²+2x+2x+4

=X(X+2)+2(X+2)

=(X+2)(X+2)

=(X+2)²

b.x²-12x+27

=x²-9x-3x+27

=X(x-9)-3(x-9)

=(x-9)(x-3)

c.x²-x-42

=x²-7x+6x-42

=X(x-7)+6(x-7)

=(X+6)(x-7)

d.x²+8x-9

=x²+9x-x-9

=X(X+9)-1(X+9)

=(x-1)(X+9)

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Answer:

Step-by-step explanation:

Let, f(x) = y

y = 5 + √(5x - 3)

((y - 5)² = 5x + 3

y² - 10y + 25 - 3 = 5x

x = (y² - 10y +22)/5

so, [tex]f^{-1} (y)[/tex] = (y² - 10y +22)/5

[tex]f^{-1} x[/tex] = (x² - 10x + 22)/5

Answer:

yes to all 3

Step-by-step explanation:

A

3z = 21 ( isolate z by dividing both sides by 3 )

z = 7

B

n + 14 = 36 ( subtract 14 from both sides )

n = 22

C

[tex]\frac{3}{4}[/tex] v = 12 ( multiply both sides by 4 to clear the fraction )

3v = 48 ( divide both sides by 3 )

v = 16

The missing lengths of the sides  a = 3 inches  , b =  3√3 inches  .

90 -60 -30 triangle .

We have given 90 -60 -30 triangle with hypotenuses = 6 in.

By the 90 -60 -30 triangle rule  :  The hypotenuse is equal to twice the length of the shorter leg, which is the side across from the 30 degree angle and the length of the longer leg is 3√ times the length of the shorter leg.

Then Shorter leg = a longer leg = b.

Hypotenuse = 2 * Shorter leg .

Plug the values.

6 =  2 *  Shorter leg .

On dividing both sides by 2

Shorter leg (a)  = 3 inches .

Then by the rule :  longer leg is 3√ times the length of the shorter leg.

Longer leg =  3√Shorter .

Longer leg (b)  =  3√3 inches  .

Therefore, a = 3 inches  , b =  3√3 inches  .

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The given surface is [tex]\cos(xy) = e^z-2[/tex]. The unit vector normal to this surface at the point (1, π, 0) is[tex]\vec{n}=\langle 0, 0, 1\rangle[/tex].

A vector with a magnitude of one is termed a unit vector. To determine a unit normal vector for the given surface, start by describing the surface as a function of form F(x, y, z). Next, calculate this function's gradient and then normalize the outcomes.

Consider the normal vector [tex]\vec{n}=\langle a, b, c\rangle[/tex]  to the plane ax + by + cz = d. Given [tex]\cos(xy) = e^z-2[/tex] then, z = ln(2+cos(xy)).

At point (x₀,y₀,z₀), the equation for the tangent plane to z = f(x,y) is written as, [tex]z-z_0 = f_x(x_0,y_0)(x-x_0) + f_y(x_0,y_0)(y-y_0)[/tex]. The value of [tex]f_x[/tex] and [tex]f_y[/tex] are

[tex]f_x = \frac{-y \sin(xy)}{(2+\cos(xy))}[/tex] and [tex]f_y =\frac{ -x \sin(xy) }{ (2+\cos(xy))}[/tex].

At *x, y) = (1, π), the value of [tex]f_x[/tex] and [tex]f_y[/tex] is zero. Then, the equation of the tangent plane is given as z-0=0+0 ⇒ z=0.

Then, the resulting unit normal vector is [tex]\vec{n}=\langle 0, 0, 1\rangle[/tex].

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In this case, the proportion (79%) only applies to the sample of 481 consumers and thus it is a statistic because it represents the sample.

The distinction between a parameter and a statistic is that a parameter refers to a sample property, but a statistic is referred to as a population distribution characteristic.

For instance, a population mean is a parameter, but a sample mean is a statistic.

Although we can use it to draw conclusions about the population, in this case, the proportion (79%) only applies to the sample of 481 consumers and is thus only a statistic.

Therefore, This percentage is a statistic because it represents the sample.

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you can use math away app

The absolute value graph shifted to the right 5 units is

Transformation is a term used in mathematics to refer to the movements made by objects.

Translation refers to a type of transformation that involve a linear movement.

Translation has to do with the following movements

The up and down movements are on the vertical direction controlled by the y coordinate.

While the left and right movements are on the horizontal direction controlled by the x coordinate.

The movement represented by the absolute value equation  |x - 5| is is translation 5 units right

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|

The area of the rectangle ABEF = 2sa = 2ss/(2*tan(180/8)) = s^2/(tan(180/8)).

What is an octagon?

An octagon is a polygon with eight straight sides and eight angles. It is a closed two-dimensional shape with eight sides of equal length. A regular octagon is an octagon in which all sides and angles are equal.

When it comes to the area of a regular octagon, the area of a regular polygon can be calculated using the formula

A = (ns^2)/(4tan(180/n)) where A is the area, n is the number of sides and s is the length of each side.

In case of a regular octagon, the area of an octagon is (8s^2)/(4tan(180/8))

A rectangle ABEF is made up of two congruent sides with the length of the side of the octagon, and two congruent sides with the length of the apothem of the octagon.

An apothem of a regular polygon is the distance from the center of the polygon to the midpoint of any side. The apothem of a regular octagon can be calculated by using the formula

a = s/(2*tan(180/8)) where a is the apothem and s is the side of the octagon.

Hence, the area of the rectangle ABEF = 2sa = 2ss/(2*tan(180/8)) = s^2/(tan(180/8)).

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Answer:

-.56296296296...

Step-by-step explanation:

[tex]\frac{(2)(-35)-13}{(-6.75)(15)}[/tex]

[tex]\frac{70-13}{-101.25}[/tex]

[tex]\frac{57}{-101.25}[/tex]

-.56296296296...  The 296 is repeating

Answer:go to teacher 56

Step-by-step explanation:

pop op

Answer: Vera's starting salary at the company was $53600.

Step-by-step explanation:

We can start by using the following proportion:

(Current salary) / (Starting salary) = (Percent increase) / 100

So we can write:

67,000 / Starting salary = 125 / 100

To find the starting salary we can cross-multiply and divide:

67,000 = (125 * Starting salary) / 100

67,000 * 100 = 125 * Starting salary

67,000 * 100 = 125 * Starting salary

67,000,000 = 125 * Starting salary

Starting salary = 67,000,000 / 125

- C

Answer:

Step-by-step explanation:

(a) 10p = 3p - 5

7p = - 5

p = -5/7

(b) a^0 = 1 no matter what a is.

(c) 0.5 y²/x

(d) 5cd²(2c² + 3d²)

solving for a variable:

a)

[tex]10p=3p-5[/tex]

[tex]7p=-5[/tex]

[tex]p=\frac{-5}{7}[/tex]

b) A simple rule to follow is that any number raised to the exponent of 0 is equal to 1

[tex]a^0=1[/tex]

c)

[tex]\frac{xy^3}{2x^2y}[/tex]  cancelled out the common factor of 3

[tex]\frac{y^2}{2x}[/tex]             note that [tex]a^-^y=\frac{1}{a^y}[/tex]

d)

[tex]5cd^2(2c^2+3d^2)[/tex]

On Earth, the golf ball would travel much farther and higher than on the moon due to the difference in gravity. On the moon, the gravity is only 1/6th the strength of Earth's, making it much easier for the golf ball to travel farther and higher. On Earth, the golf ball would travel farther and higher due to the stronger gravitational pull.

The orthocenter for an obtuse triangle is always outside the circumcircle in which the obtuse triangle is drawn.

In geometry, each triangle has a few highly significant points that go along with it. One such point is the triangle's orthocenter, which is identified as the location where the triangle's altitudes cross.

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The orthocenter for an obtuse triangle is always outside the circumcircle in which the obtuse triangle is drawn.

In geometry, each triangle has a few highly significant points that go along with it. One such point is the triangle's orthocenter, which is identified as the location where the triangle's altitudes cross.

An altitude of a triangle is a line segment that extends perpendicularly from one of its vertices to the side opposite that vertex. A triangle with an angle larger than 90° is said to have an obtuse angle. The heights of the vertices of the acute angles of an obtuse triangle reside outside of the triangle due to the way the triangle is constructed.

The orthocenter, or the location where the three elevations intersect, must therefore be outside of the circumcircle in which the triangle is inscribed.

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The complete question is as follows:

Is the orthocenter for an obtuse triangle always outside the circumcircle which the obtuse triangle is drawn in?

Answer:

Step-by-step explanation: