cx=dr, for x, i need help

Answer:

743000

1.2×10^9

hope it helps;)

Answer:

Length: 10 cm

Width: 5 cm

Step-by-step explanation:

The required length and width of the scale drawing are given a length will be 10 cm and the width will be 5 cm.

Given that,
A swimming pool of rectangle shape that measures 50 meters in length and 25 meters in width. To make a scale drawing of an Olympic-size swimming pool where 1 centimeter represents 5 meters.

The scale factor is defined as the ratio of the modified change in length to the original length.

Here,
Given scale: 1 cm = 5 m
So, for 1 m = 1/5 cm
Now,
Length = 50 × 1/5  = 10 cm
Width = 25 × 1/5 = 5 cm

Thus, the required length and width of the scale drawing is given a length will be 10 cm and a width will be 5 cm.

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Answer:

171

Step-by-step explanation:

Use PEMDAS (parenthesis, exponent, multiplication/division, addition/subtraction)

Add the two numbers in parenthesis first

175-[100/25]

Divide 100 by 25 in the brackets

175-4

Subtract

171

Answer:

terms: 3x,+90y,-70

coefficient:3,-90,-70

Answer:

[tex]6[/tex]

Step-by-step explanation:

[tex]5+\sqrt{81}\div9[/tex]

[tex]5+\frac{\sqrt{81}}{9}[/tex]

[tex]5+\frac{9}{9}[/tex]

[tex]5+1[/tex]

[tex]6[/tex]

Answer:

[tex]47 \frac{11}{12} [/tex]

Step-by-step explanation:

[tex]10 + (\frac{5}{12} \times 91 )= 10 + (\frac{455}{12} = 37 \frac{11}{12} ) = 47 \frac{11}{12} [/tex]

Answer: each pair of pants costed 15 $

Step-by-step explanation:

35+10 = 45/3 = 15

Answer: $15 each

Step-by-step explanation: add 35 + 10 = 45, then divide 45 ÷ 3 = 15

Answer:

y=12/7x +39/7

Step-by-step explanation:

7y-12x=39

7y=12x+39

y=12/7x+39/7

Answer:

7y -12x = 39

   +12x    +12x

 7y =  39 + 12x

 ----     ----------

  7         7

  y=  12/7x + 39/7

Answer:144

Step-by-step explanation:

36 x 4 = 144

48 × 3 = 144

Answer:

Because they are fractions every fractions is rational .

Step-by-step explanation:

Answer:

The sum is a fraction

Step-by-step explanation:

Answer:

[tex]= \dfrac{1}{75}[/tex]

Step-by-step explanation:

Given that:

[tex]\lim_{x \to -5} \dfrac{(x+5)}{(x^3+125)}[/tex]

[tex](x^3 + 125) = (x+5)(x^2 -5x+25)[/tex]

Thus;

[tex]= \lim_{x \to -5} \dfrac{(x+5)}{(x+5)(x^2 -5x +25)}[/tex]

[tex]= \lim_{x \to -5} \dfrac{1}{(x^2 -5x +25)}[/tex]

[tex]= \dfrac{1}{((-5)^2 -5(-5) +25)}[/tex]

[tex]= \dfrac{1}{(25 +25 +25)}[/tex]

[tex]= \dfrac{1}{75}[/tex]

The wooden board is 24 times the length of Crayon which is represented by Figure C.

We have,

A crayon is 4 inches long.

A wooden board is 8 feet long.

We know that

1 feet = 12 inch

So, 8 feet = 12 x 8 = 96 inches

Now, the factor between Caron and wooden block

= 96 / 4

= 24

Thus, the wooden board is 24 times the length of Crayon which is represented by Figure C.

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Answer:

A

Step-by-step explanation:

I used my brain so hope it helps

Answer:

Stop and Save is a better value

Step-by-step explanation:

[tex]\frac{3}{1.05} = 2.86\\\frac{5}{2.30} = 2.17[/tex]

Answer:

3 apples at quick market.

Step-by-step explanation:

they only cost $0.44 dollars each

Answer:

p = -7

a = 10

Step-by-step explanation:

Question 1:

Step 1: Write out equation

-22 = 12p - 2(5p + 4)

Step 2: Distribute

-22 = 12p - 10p - 8

Step 3: Combine like terms (p)

-22 = 2p - 8

Step 4: Add 8 to both sides

-14 = 2p

Step 5: Divide both sides by 2

-7 = p

Step 6: Rewrite

p = -7

Question 2:

Step 1: Write out equation

11a - (4a - 7) = 77

Step 2: Distribute

11a - 4a + 7 = 77

Step 3: Combine like terms (a)

7a + 7 = 77

Step 4: Subtract 7 on both sides

7a = 70

Step 5: Divide both sides by 7

a = 10

Answer:

follow me and mark me brainliest

Answer:

25. books: 1/7, games: 5/14

26. clothes: 3/14, games: 5/14, toys: 2/7

27. books: 1/7, toys: 2/7

Step-by-step explanation:

1) The bar graph shows 2 for books, and Tony got 14 gifts; therefore, 2/14 were books. However, 2/14 isn't the answer because they are asking for the simplest form which is 1/7. Keep repeating this process for the rest of the gifts and you will get your answer.

Hope this helps!

Answer:

perpendicular bisector of a segment

Step-by-step explanation:

When using compass and drawing two arcs, the point the two arcs intersect at a point above and below the line, when connect the two point it forms a perpendicular bisector of a segment

Answer:

idek

Step-by-step explanation:

Answer:

-7

Step-by-step explanation:

Answer:

-7

Step-by-step explanation:

-15 - 8= -7

Answer:

I believe it would be 14

Step-by-step explanation:

Answer:

assuming that point u is inbetween points T and V then the length of TV would be 13

Step-by-step explanation:

T-----------U--V

Answer:

x > 2

Step-by-step explanation:

Given

5x + [tex]\frac{1}{3}[/tex](3x + 6) > 14 ← distribute and simplify left side

5x + x + 2 > 14

6x + 2 > 14 ( subtract 2 from both sides )

6x > 12 ( divide both sides by 6 )

x > 2

Answer: x > 2  

Step-by-step explanation:

5x + 1/3(3x +6) > 14     Distribute

5x + 1x + 2 > 14     Combine like terms on the left side

  6x + 2 > 14      Subtract 2 from both sides

         -2    -2

   6x > 12      Divde both sides by 6

 x > 2

Answer:

1032

Step-by-step explanation:

(2^5-8^2)^2+2^3 subsitute

(32-64)^2+2^3

(-32)^2+2^3

1024+8

1032

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

[tex] AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] A(-6, 2)) = (x_1, y_1) [/tex]

[tex] B(2, 6) = (x_2, y_2) [/tex]

[tex] AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2} [/tex]

[tex] AB = \sqrt{(8)^2 + (4)^2} [/tex]

[tex] AB = \sqrt{64 + 16} = \sqrt{80} [/tex]

[tex] AB = 8.9 [/tex] (nearest tenth)

Distance between B(2, 6) and C(7, 1):

[tex] BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] B(2, 6) = (x_1, y_1) [/tex]

[tex] C(7, 1) = (x_2, y_2) [/tex]

[tex] BC = \sqrt{(7 - 2)^2 + (1 - 6)^2} [/tex]

[tex] BC = \sqrt{(5)^2 + (-5)^2} [/tex]

[tex] BC = \sqrt{25 + 25} = \sqrt{50} [/tex]

[tex] BC = 7.1 [/tex] (nearest tenth)

Distance between C(7, 1) and D(3, -5):

[tex] CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] C(7, 1) = (x_1, y_1) [/tex]

[tex] D(3, -5) = (x_2, y_2) [/tex]

[tex] CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2} [/tex]

[tex] CD = \sqrt{(-4)^2 + (-6)^2} [/tex]

[tex] CD = \sqrt{16 + 36} = \sqrt{52} [/tex]

[tex] CD = 7.2 [/tex] (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

[tex] DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] D(3, -5) = (x_1, y_1) [/tex]

[tex] A(-6, 2) = (x_2, y_2) [/tex]

[tex] DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2} [/tex]

[tex] DA = \sqrt{(-9)^2 + (7)^2} [/tex]

[tex] DA = \sqrt{81 + 49} = \sqrt{130} [/tex]

[tex] DA = 11.4 [/tex] (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

Answer:

0=0

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4(3y−6)=−3(8−4y)

(4)(3y)+(4)(−6)=(−3)(8)+(−3)(−4y)(Distribute)

12y+−24=−24+12y

12y−24=12y−24

Step 2: Subtract 12y from both sides.

12y−24−12y=12y−24−12y

−24=−24

Step 3: Add 24 to both sides.

−24+24=−24+24

Answer:

All real numbers

Step-by-step explanation:

So we have the equation:

[tex]4(3y-6)=-3(8-4y)[/tex]

First, distribute the left side:

[tex]12y-24=-3(8-4y)[/tex]

Now, distribute the right:

[tex]12y-24=-24+12y[/tex]

Subtract 12y from both sides. Both sides cancel:

[tex]-24=-24[/tex]

This statement is true.

In other words, our solution is all real numbers.

And we're done!