David throws a ball up in the air. The graph below shows the height of the ball hh in feet after tt seconds. What is the ball’s greatest height?

HELP ASAP!

Answer:

(x-5)²+(y+2)²=200.

Step-by-step explanation:

1) using the given coordinates it is possible to calculate

- the centre of the given circle:

[tex]x_0=\frac{10+0}{2}=5; \ y_0=\frac{2-8}{2}=-2;[/tex]

- the radius of the given circle:

[tex]r=\sqrt{(10-0)^2+(2+8)^2} =\sqrt{200} ;[/tex]

2) finally, the required equation (common form is (x-x₀)²+(y-y₀)²=r²):

(x-5)²+(y+2)²=200.

Answer:

1/90

Step-by-step explanation:

Comment

To begin with, there are 10 tiles.. You draw one and don't replace it. Then you draw another tile from the 9 that remain.  The job is to figure out the probability of that happening.

You have a 1/10 chance of drawing the M.

But now there are only 9 tiles left and you have a 1 in 9 chance of drawing a T

Solution

P(M,T) = 1/10 * 1/9 = 1 / 90

You have a 1 in 90 chance of getting the two tiles in the order you have specified.

Answer:

Step-by-step explanation:

The answer would be "me" as the indirect object

The total number of tea received in three years is 192.

The total number of coffee received in three years is 128.

The total number of biscuits received in three years is 64.

The total quantity of tea, coffee and biscuits received in the first year = (6 x 2) , (4 x 2) ,  (2 x 2) = 12, 8, 4 respectively

The total quantity of tea, coffee and biscuits distributed in the second year = (6 x 12) , (4 x 12) ,  (2 x 12) = 72, 48, 24 respectively

The total quantity of tea, coffee and biscuits distributed in the third year = (6 x 18) , (4 x 18) ,  (2 x 18) = 108, 72, 36 respectively

Total number of tea received in three years = 108 + 72 + 12 = 192

Total number of coffee received in three years = 8 + 48 + 72 = 128

Total number of biscuits received in three years = 4 + 24 + 36 = 64

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Answer:

Yellow: 4

blue: 2

red: 12

green: 2

Answer: 8

Step-by-step explanation:

We are going from a smaller triangle to a larger triangle, so the scale factor is greater than 1.

We know scale factor = (image)/(preimage), so the scale factor is 32/4 = 8

The scale factor of dilation of the triangle is k = 8

Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent

The result of dilation is that the shapes and boundaries of objects in the input image are expanded or thickened. It is often used in conjunction with other morphological operations such as erosion, opening, and closing to manipulate and enhance images.

Given data ,

Let the first triangle be represented as ΔABC

Let the second triangle be represented as ΔDEF

where the measures of sides of ΔABC are

AB = 6 , BC = 6 and AC = 4

The measure of sides of triangle ΔDEF are

DE = 48 , EF = 48 and DF = 32

The scale factor of dilation k = measure of side DE / measure of side AB

k = 48 / 6

k = 8

Hence , the dilation factor is k =8

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Answer:

A. 0.78

Step-by-step explanation:

A rational number is a number that you can express as [tex]\frac{x}{y}[/tex] where [tex]y\neq 0[/tex].

Answer:

This is my answer↓:

Step-by-step explanation:

He school play sold $550 in tickets one night.

The number of $8 adult tickets was 10 less than twice the number of

$5 child tickets.

How many of each ticket were sold

Let say child ticket sold = x

Adult tickets was 10 less than twice the number of    child tickets.

=> Adult ticket sold = 2x - 10

Child ticket sold = x

$5 child tickets price

=> Revenue = 5x  $

Adult ticket sold = 2x - 10

$8 Adult tickets price

=> Revenue = 8(2x - 10) =16x - 80 $

5x + 16x - 80 = 550

=> 21x = 630

=> x = 30

Child ticket sold = 30

Adult ticket sold = 50

Total ticket sold = 80

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Answer: neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1

Step-by-step explanation:

Areas under the graphs:

Graph A

[tex](1)(0.5)+(7-2)(0.2)=1.5\\\\[/tex]

Graph B

[tex]\frac{\pi}{2}(1^{2})=\frac{\pi}{2}[/tex]

As neither of these graphs have an area of 1, neither of them are density curves.

The statement - "neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1" is true.

A few fundamental principles apply to density curves:

Neither curve of Graph A nor of Graph B has the area under the curve summed up as 1, though the curve is above the horizontal axis.

Hence, because neither graph has an area of 1, even if both curves are above the horizontal axis, the statement "neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1" is true.

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These [tex]N[/tex] outcomes make up the entire sample space, so

[tex]\displaystyle \sum_{k=1}^N P(e_k) = P(e_1) + P(e_2) + P(e_3) + \cdots + P(e_N) = 1[/tex]

We're given that [tex]P(e_{j+1}) = 2 P(e_j)[/tex] for all [tex]j\in\{1,2,\ldots,N-1\}[/tex], so

[tex]P(e_1) + 2 P(e_1) + 2^2 P(e_1) + \cdots + 2^{N-1} P(e_1) = 1 \\\\ \implies P(e_1) = \dfrac1{1 + 2 + 2^2 + \cdots + 2^{N-1}} = \dfrac1{2^N - 1}[/tex]

Then we can solve the recurrence relation to get the probability of the [tex]j[/tex]-th outcome,

[tex]P(e_{j+1}) = 2 P(e_j) = 2^2 P(e_{j-1}) = 2^3 P(e_{j-2}) = \cdots \\\\ \implies P(e_{j+1}) = 2^j P(e_1) \\\\ \implies P(e_j) = 2^{j-1} P(e_1) = \dfrac{2^{j-1}}{2^N - 1}[/tex]

The probability of getting this sequence of [tex]k[/tex] outcomes is then

[tex]\displaystyle P(E_k) = P(e_1) + P(e_2) + \cdots + P(e_k) = \sum_{j=1}^k \frac{2^{j-1}}{2^N-1} = \frac{2^k-1}{2^N-1}[/tex]

as required.

Some preliminary results: If [tex]S[/tex] is the sum of the first [tex]n[/tex] terms of a geometric series with first term [tex]a[/tex] and common ratio [tex]r[/tex], then

[tex]S = a + ar + ar^2 + \cdots + ar^{n-1}[/tex]

[tex]\implies rS = ar + ar^2 + ar^3 + \cdots + ar^n[/tex]

[tex]\implies S - rS = a(1 - r^n)[/tex]

[tex]\implies S = \dfrac{a(1 - r^n)}{1 - r}[/tex]

which gives us, for instance,

[tex]1 + 2 + 2^2 + \cdots + 2^{N-1} = \dfrac{1 - 2^N}{1 - 2} = 2^N-1[/tex]

The correct answer is option C which is the angle LMO is 50°

The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle termed trigonometry.

Given that:-

∠O = 70°

∠L = 60°

∠LMO =?

As we know that the sum of the three angles are 180 degree applying this relation:-

∠LOM + ∠OLM  + ∠LMO = 180

70 + 60 +  ∠LMO = 180

∠LMO = 180 - 70 - 60 = 50

Therefore the correct answer is option C which is the angle LMO is 50°

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The correct answer is option B which is 3

Mean is defined as the ratio of the sum of the number of the data sets to the total number of the data.

Given data:-

4,3,2

The mean will be calculated as:-

Mean = (4 + 3 + 2) / 3

Mean =  9 / 3

Mean = 3

Therefore the correct answer is option B which is 3

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Answer:

[tex] - \frac{1}{6} [/tex]

Step-by-step explanation:

Using the slope formula:

[tex] \frac{ - 1 - 0}{0 - ( - 6)} = - \frac{1}{6} [/tex]

[tex]\dfrac{x!-(x-3)!}{23}=1\\x!-(x-3)!=23\\(x-3)!((x-2)(x-1)x-1)=23\\(x-3)!((x^3-x^2-2x^2+2x)-1)=23\\(x-3)!((x^3-3x^2+2x)-1)=23[/tex]

23 is a prime number, therefore there are two possibilities:

[tex]\text{I.}\, (x-3)!=1 \wedge x^3-3x^2+2x-1=23[/tex]

or

[tex]\text{II.}\, (x-3)!=23 \wedge x^3-3x^2+2x-1=1[/tex]

[tex]\text{I.}\\(x-3)!=1\\x-3=0 \vee x-3=1\\x=3 \vee x=4[/tex]

Now, we check if any of these solutions is also a solution to the second equation:

[tex]3^3-3\cdot3^2+2\cdot3-1=23\\27-27+6-1-23=0\\ -18=0[/tex]

Therefore, 3 is not a solution.

[tex]4^3-3\cdot4^2+2\cdot4-1=23\\64-48+8-1-23=0\\0=0[/tex]

Therefore, 4 is a solution.

[tex]\text{II.}[/tex]

[tex](x-3)!=23[/tex]

We know that [tex]3!=6[/tex] and [tex]4!=24[/tex], therefore there isn't any [tex]n\in\mathbb{N}[/tex], for which [tex]n!=23[/tex], so there's no solution.

So, the only solution is [tex]x=4[/tex].

The complete question is

"What is the value of this expression when c= -4 and d= 10?

1/4 (c^3+d²)

A.2

B.9

C.21

D.41"

The value of this expression when c = -4 and d = 10 will be option B 9.

Usually, simplification involves proceeding with the pending operations in the expression.

Simplification usually involves making the expression simple and easy to use later.

The given expression is

[tex]1/4 (c^3+d^2)\\\\1/4 ((-4)^3+(10)^2)\\\\1/4 ( -64 + 100)\\\\1/4 (36)\\\\9[/tex]

Hence, the value of this expression when c = -4 and d = 10 will be option B 9.

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The converse of the statement will be : if x^2 = 100 then x = -10, which is not true.

In order to write a converse of a conditional statement "p then q",  will be "q then p" the hypothesis and conclusion interchanges.

Then the converse of the statement will be :

if x^2 = 100 then x = -10,

which is not true.

Since , x = +10, then x^2 = 100

Therefore, if x^2 = 100 then x = -10, which is not true.

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Answer:

3

Step-by-step explanation:

Cardinalities are the number of elements in a set.

(A∩B∩C) is the very middle part of the circle, and there are 3 elements there.

Answer:

51° and 39°

Step-by-step explanation:

x + 4x - 165 = 90

5x = 90 + 165

5x = 255

x = 255 / 5

x = 51

4 x 51 = 204

204 - 165 = 39

2 angles are 51 and 39

David will be 10 and John will be 9

Answer:

0.5km or 500m

Step-by-step explanation:

Given Distance = Speed x Time

In this case, we should use the difference in speed and time of the 2 scenarios.

Difference in Time = 20 mins(late) + 10 mins(early)

= 30 mins or 0.5 hour

Difference in Speed = 4km/h - 3km/h = 1km/h

Distance = 1km/h x 0.5 hr = 0.5km or 500m.

The degree of the provided polynomial is 18, and the leading term is √7.

It is defined as the combination of constants and variables with mathematical operators.

We have given an expression:

[tex]= \rm \sqrt{7}x ^{18} + 12.1x^{ 15} + \pi 4 x^ 6 + 1 9[/tex]

As we can see in the expression the greatest degree is 18.

So the degree of the polynomial is 18

And the coefficient of the variable which has a height degree is the leading term.

The leading term = √7

Thus, the degree of the provided polynomial is 18, and the leading term is √7.

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Answer:

Step-by-step explanation:

Solution by substitution method

3x+5y=7

and 4x-y=5

Suppose,

3x+5y=7→(1)

and 4x-y=5→(2)

Taking equation (2), we have

4x-y=5

⇒y=4x-5→(3)

Putting y=4x-5 in equation (1), we get

3x+5y=7

⇒3x+5(4x-5)=7

⇒3x+20x-25=7

⇒23x-25=7

⇒23x=7+25

⇒23x=32

⇒x=32/23

→(4)

Now, Putting x=32/23

in equation (3), we get

y=4x-5

⇒y=4(32/23)-5

⇒y=(128-115)/23

⇒y=13/23

∴y=13/23   and x=32/23

The solution to the system of equation is (-4 , 2) , Option A is the right answer.

A set of equation whose factors are common are called system of equations.

It is given in the question

3x +5y = -2

3x +7y = 2

On solving this we get

-2y = -4

y = 2

On substitution in any equation

x = -4

Therefore solution to the system of equation is (-4 , 2) , Option A is the right answer.

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Answer:

A.

Step-by-step explanation:

took tha quiz

The factor of the function will be x and (x³ – 6). Then the zeroes of the function will be 0 and √6.

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

The polynomial function is given below.

f(x) = x⁴ − 6x

Then the factor of the function will be

f(x) = x(x³ – 6)

Then the zeroes of the function will be

x = 0, √6

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Answer:

b) angles 1 and 4 are congruent.

Hope it helps!

[tex]\huge\text{Hey there!}[/tex]

[tex]\text{4x = 19}\\\\\large\textbf{DIVIDE 4 to BOTH SIDES}\\\\\rm{\dfrac{4x}{4} = \dfrac{19}{4}}\\\\\large\textbf{SIMPLIFY IT!}\\\\\rm{x = \dfrac{19}{4}}\\\\\rm{x = 19 \div 4}\\\\\text{x = 4.75}\\\\\rm{x \approx 4.7500}\\\\\\\huge\text{Therefore, the answer should be: \boxed{\mathsf{4.7500}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Solving a quadratic equation, the age of the man with a blood pressure of 125 mmHg is of 27 years old.

A quadratic function is given according to the following rule:

[tex]y = ax^2 + bx + c[/tex]

The solutions are:

In which:

[tex]\Delta = b^2 - 4ac[/tex]

The pressure is given by:

P = 0.006A² - 0.02A + 120.

When the pressure is of 125 mmHg, we have that:

0.006A² - 0.02A + 120 = 125.

0.006A² - 0.02A - 5 = 0.

Hence the coefficients are a = 0.006, b = -0.02, c = -5, and the solutions, applying the formula are:

A = -30 and A = 27.

Age has to be positive, hence the man is 27 years old.

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