Derive that efficiency is the ratio of output and input work.​

Answer:

15.29 kg

Explanation:

F = k * d                  5cm = .05 m

 = 3 x 10^3  n/m     *   .05 m  = 150 N

                                                =  150 kg -m / s^2

150 kg- m / s^2   / 9.81 m/s^2 =15.29kg

Answer

100% - double

200% - triple

300% - 4X

For a 300% increase the KE must be 4 time as large

KE2 / KE1 = M V2^2 / M V1^2 = (V1 / V2)^2 = 4

So V2 = 2 V1 for the requested increase

M V2 / M V1 = V2 / V1 = 2

So the momentum would double for a 100% increase

Answer:

The change in time for the first quarter is  seconds.  = 2.07

The change in time for the second quarter is  seconds.

=1.09

The change in time for the third quarter is  seconds.

=0.95

The change in time for the fourth quarter is  seconds.=0.81

Explanation:

Hope this helped.

Answer:

D

Explanation:

PCN was discovered in mold

Answer:

a single closed path of electrical components including a voltage source

Taking into account the definition of pH and pOH, the concentration of H⁺ ions at pH=8 is 1×10⁻⁸ M and the concentration of OH⁻ ions at pH=8 is 1×10⁻⁶ M.

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The following relationship can be established between pH and pOH:

pOH + pH= 14

In this case, pH=8. Replacing in the definition of pH:

8= - log [H⁺]

Solving:

[H⁺]= 10⁻⁸= 1×10⁻⁸ M

Finally, the concentration of H⁺ ions at pH=8 is 1×10⁻⁸ M.

Being pH= 8, pOH is calculated as:

pOH + 8= 14

pOH= 14 - 8

pOH= 6

Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:

- log [OH⁻]= 6

Solving

[OH⁻]= 10⁻⁶= 1×10⁻⁶ M

Finally, the concentration of OH⁻ ions at pH=8 is 1×10⁻⁶ M.

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Answer:2140 watts x 6 hours =12.84 kWh. Are you looking for specific type units such as Jules?

The total length of the wire required is 63 m.

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

Given is a solenoid is configured to produce a magnetic field of 0.027T at its center. it has radius 1.4 cm and length 40cm and the wire can carry a maximum current of 12.0 A.

Radius, r = 1.4cm = 0.014 m

Length l = 40 cm = 0.4 m

If the current is I, then the magnetic field in solenoid is given by

B =  μ₀ n I

By substituting the values, we get

0.027 = 4π x 10⁻⁷ x n x 0.4

n = 1792 turns/unit length

Total length of wire = circumference x Turns

L = 2πr x N

where N = nl

Plug the values, we get

L = 2π x 0.014 x1792 x 0.4

L = 63 m

Thus, the total length of the wire is 63 m.

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A. The final temperature of the system is 0°C.

B. The amount of ice (if any) remaining is  0.0331 g

C. The initial temperature of the water that would be enough to just barely melt all of the ice is 20.57 °C.

The specific heat is the amount of heat required to change the temperature by 1°C. It is denoted by C.

Heat lost or gained is represented as

Q = m C ΔT

Given, Mass of ice, mice = 9x10⁻² kg, Mass of water, mw =0.35 kg, T = 13 °C

A. If ice is in excess, final water temperature will be 0°C.

B. Specific heat of water Cp = 1000 cal/kg°C

Latent heat of ice L = 80 kcal/kg

In that case, heat lost by water =Heat gain by ice

Q = mCp x dT = mL

0.35 x 1000 x 13 = m x 80 x 1000

m = 0.0569 kg of ice.

The gram of ice remaining = 0.09 - 0.0569

                                             = 0.0331 gram of ice.

Thus,  the amount of ice remaining is 0.0331 g

C. Heat required to melt 90 gram of ice,  Q  mL

Q = 90 x 80 = 7200 cal.

If the initial temperature of water needed = T,

mCp x dT = mL

350 x T = 7200

T = 20.57 °C

Thus,  the initial temperature of the water that would be enough to just barely melt all of the ice is  20.57 °C.

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The velocity is 6.75

The velocity in the equation stated above can be calculated as follows

m= 2,000
p= 2.25

y= 6000

velocity= 2.25 × 6000/ 2000
= 13500/2000
= 6.75

Hence the velocity is 6.75

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Answer:

This process is CONDENSATION

Explanation:

Condensation occurs when water vapour loses some of its kinetic energy to a colder body and changes into liquid state.

Answer:

What is freezing point?

A liquid's freezing point is determined at which it turns into a solid. Corresponding to the melting point, the freezing point often rises with increasing pressure. In the case of combinations and for some organic substances, such as lipids, the freezing point is lower than the melting point. The first solid which develops when a combination freezes often differs in composition from the liquid, and the development of the solid alters the composition of the remaining liquid, typically lowering the freezing point gradually. Utilizing successive melting and freezing to gradually separate the components, this approach is used to purify mixtures.

What is melting point?

The temperature at which a purified substance's solid and liquid phases may coexist in equilibrium is referred to as the melting point. A solid's temperature goes up when heat is added to it until the melting point is achieved. The solid will then turn into a liquid with further heating without changing temperature. Additional heat will raise the temperature of the liquid once all of the solid has melted. It is possible to recognize pure compounds and elements by their distinctive melting temperature, which is a characteristic number.

The difference between freezing point and melting point:

Reference: Berry, R. Stephen. "When the melting and freezing points are not the same." Scientific American 263.2 (1990): 68-75.

Given that a ball is thrown into the air and its height in feet after t seconds is given by y = 45t - 15t²,  the instantaneous velocity when t=4 is -75ft/s.

Given that;

First, we determine the derivative of y = 45t - 15t²

y' = (1)45 - (2)15t

y' = 45 - 30t

We substitute in t = 4

y' = 45 - 30t

y' = 45 - 30(4)

y' = 45 - 120

y' = -75ft/s

Given that a ball is thrown into the air and its height in feet after t seconds is given by y = 45t - 15t²,  the instantaneous velocity when t=4 is -75ft/s.

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Velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common

This is a which have both magnitude and direction. Example include:

This is a quantity which has magnitude but no direction. Example include:

From the above, we can see that velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common

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Answer:

Actually, the correct answer is D. The system releases 75 J of heat, and its volume doubles.

Explanation:

I took this computer-scored test, and while I was stuck on this answer for a while, I was able to get 100%. This was my thought process:

We know that molecular motion increases with an increase in temperature, because collisions increase. For that reason, for molecular motion to decrease in a system, as the question states, the system must RELEASE heat and decrease in temperature.  Additionally, when a system's volume is smaller, its molecular motion increases. This is because the molecules hit the container more easily and more often. If the volume is halved then, the molecules would have MORE motion, which we aren't looking for in this question! Therefore, the volume must DOUBLE so that less molecular motion takes place. The answer is D! :)

The formula that can be used to obtain a convergent series is given by;

a/1 – r.

In mathematics, we define a series as sum of numbers which could be convergent or divergent. In a convergent series, the summation of the numbers approaches a given value.

The formula that can be used to obtain a convergent series is given by;

a/1 – r.

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Answer:

[tex]\fbox {3.6kW}[/tex]

Explanation:

Formula used :

[tex]\boxed {P = F \times v} \leftarrow \rightarrow \boxed {P = \frac{F \times S}{t}}[/tex]

Given :

⇒ F = 6 × 10³ N

⇒ S = 18 m

⇒ t = 30 s

Solving :

⇒ P = 6 × 10³ × 18 / 30

⇒ P = 2 × 100 × 18

⇒ P = 3600 W

⇒ P = 3.6kW

Explanation:

The correct is A.

every magnet have two pole

An example of an object moving in projectile motion is; A basketball being thrown into a net.

Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity.

Now, an example of an object moving in a projectile motion is throwing a basketball into a basketball net in a game. This is because the ball is thrown into the air at an angle towards the net and as such is subject to only acceleration of gravity.

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Momentum is the rate of increase in speed or decrease in speed after application of force

The formula is given by

p is momentum

m is mass

v is velocity

A virtual and erect image is formed by concave mirror.

The focal length of the mirror is the distance between the lens and the image sensor.

It is also defined as the distance from a lens or mirror to the focal point.

It is also stated by the formula

[tex]\frac{1}{y} +\frac{1}{u} = \frac{1}{f}[/tex]

u = -50 cm and f = 0.50 m (50cm)

[tex]\frac{1}{v} +\frac{1}{-50} =\frac{1}{50}[/tex]

v= -50 cm

where - sign shows that image is virtual.

Magnification  m= [tex]\frac{v}{u}[/tex]

m = -50/50

m = 0

hence, virtual and erect image will be formed.

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The statement which best describes Deena's error is: B. Include the area of the rectangle under the line to find displacement for constant acceleration.

A velocity vs. time graph can be defined as a type of graph that is used to graphically represent the rate of change of velocity of an object with respect to time.

Based on the information provided in the table shown (see attachment), the statement which best describes Deena's error is her not including of the area of the rectangle under the line, so as to enable her find displacement for constant acceleration.

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Complete Question:

Deena made a chart to summarize features of a velocity vs. time graph for objects with constant acceleration and objects with constant velocity.

Which best describes Deena's error?

A. The line for constant velocity is not horizontal; it is diagonal and slopes downward.

B. Include the area of the rectangle under the line to find displacement for constant acceleration.

C. Find acceleration by finding the area of the rectangle above the line.

D. Find velocity by calculating the slope of the line.

Answer:

convex lense

Explanation:

people with hyperopia or hypermetropia are long sighted or farsighted, so what happens here is that light doesn't focus on the surface of the retina but behind it so the picture is moved forward by positioning a convex lense in front of a hypermetropic eye and is correctly centered in the retina.

Answer:

Explanation:

Comment

The main points are that

Solution

               40 miles west

<==========================   0

=====================================================>

                                                  Displacement (30 km east)

Answer

30 km east                

The degree measure of angle ∠ bac will be 70°. Option C is correct.

The angle is the distance between the intersecting lines or surfaces. In addition, the angle is expressed in degrees. The angle is 360 degrees for a full revolution.

Given expression;

[tex]\rm cos^{-1}(\frac{3.4}{10})=x \\\\ x = cos^{-1}(0.34) \\\\ x = 70.12^0[/tex]

The degree measure of angle ∠bac will be 70°.

Hence option C is correct.

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Answer:

70 Degrees

Explanation:

Geometry B E2020!! :3

Answer:

h = 4.25 m

Explanation:

[tex]gravitational \space\ potential \space\ energy \space\ (gpe)= m g h\\[/tex] ,

where m is the mass, g is acceleration of gravity, and h is height of object.

In our case, m = 1.2 kg, g = 9.8m/s², and gpe = 50 J.

50 = 1.2 x 9.8 x h

h = 50 / (1.2 x 9.8)

h = 4.25 m

Answer:

4.25m

Explanation:

Joules is a "derived unit", meaning it is really composed of other units, and it is just abbreviated as a single letter.

[tex]1[J]=1 [\frac{kg \cdot m^2}{s^2}][/tex]

This comes from the formula for potential energy, often denoted "U"

[tex]U=mgh[/tex], where m is the mass of the object (measured in kilograms,  [tex]kg[/tex]), g is the acceleration due to gravity at that spot (measured in meters per second squared,  [tex]\frac {m}{s^2}[/tex]), and h is the height of the object (measured in meters, [tex]m[/tex]).

Note:  The object itself may or may not have an acceleration of "g" at the given point because it may be supported (like on a bookshelf).  However, the "g" is representative of its gravitational acceleration at that point if gravity could accelerate it unimpeded.

Rearranging the potential energy equation to isolate the unknown "h", dividing both sides by "m" and "g", we get the following:

[tex]\dfrac{U}{mg}=h[/tex]

Substituting known values (and rewriting Joules as its SI units so we can ensure units cancel the way we need them to):

[tex]\dfrac{\left (50 [\frac{kg \cdot m^2}{s^2}] \right)}{(1.2 [kg])(9.8 [\frac{m}{s^2}])}=h\\\dfrac{\left (50 [\frac{kg \!\!\!\!\!\!\!{--} \cdot m^{2 \!\!\!{-}}}{s^2\!\!\!\!\!\!\!{--} }] \right)}{(1.2 [kg \!\!\!\!\!\!\!{--} ])(9.8 [\frac{m\!\!\!\!\!\!\!{--} }{s^2\!\!\!\!\!\!\!{--} }])}=h\\\dfrac{(50)}{(1.2)(9.8)}[m]=h\\\\4.2517[m] \approx h[/tex]

Thus, the height of the book would be approximately 4.25meters high.

[tex]\huge\color{Basic}{\boxed{\tt{answer}}}[/tex]

Answer: yes it cannot be 100% efficient

Explanation:

only an ideal machine with 0 friction can have 100 percent efficiency

The energy input would it take to climb a ladder will be 20000 J.

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of the given mechanical machine.

Mechanical advantage is a measure of how much a machine multiplies the input force.

The complete question is;

"if we assume a typical efficiency of 25% for the human body how much energy input would it take to climb a ladder increasing body potential energy by 5000J"

The formula for the efficiency is;

[tex]\rm E = \frac{P}{\eta} \\\\ E = \frac{5000}{0.25} \\\\ E = 20000 \ J[/tex]

Hence, the energy input would it take to climb a ladder will be 20000 J.

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