Engineering High School

Determine the dimensions for T if T = M V^2 A / L^3 where M is a mass, V is a velocity, A is an area, and L is a length.
A. M
B. L/T
C. ML/T^2
D. M/(L T^2)
E. No dimensions

Answers

Answer 1

Answer:

C

Explanation:

I literally had this question yesterday

Answer 2
Answer: C

Explanation: I had this question a couple minutes ago too

Related Questions

Select the correct answer.
Which of these physical concepts is most important in civil engineering?
A energy transformations
B.motion under gravity
C. heat transfer
D. forces In structures
E. atomic structure

Answers

Answer:

option A energy transformation

Option A energy transformations

Brown bears can weigh half a ton (500 kilograms). The piston on the left has a cross-sectional
area of 1 square meter. The piston on the right has a cross-sectional area of 4 square meters.
How much force has to be exerted on the left piston to lift the bear? Show your work and
specify units.

Answers

In order to lift the Bear, a force of 1226.25 N has to be exerted on the left piston,

What is pressure is on the piston carrying the Bear?

The pressure on the piston carrying the Bear is calculated as follows:

Pressure = force/area

Force of the Bear = 500 kg * 9.81 m/s² = 4905 N

Pressure on the right piston = 4905 N / 4 m² = 1226.25 N/m²

To lift the Bear, the pressure on  both sides must be equal.

Force to be applied on the left piston = pressure * area

Force = 1226.25 N/m² * 1 m² = 1226.25 N

Therefore, a force of 1226.25 N has to be exerted on the left piston to lift the bear.

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11. What are restrictions when building or completing a challenge?

Answers

Explanation:

The minimum exterior open spaces around buildings that are 55 metres or more, should be 16 metres. On sides where no habitable rooms face, a minimum space of 9 metres shall be left for heights above 27 metres.

A bridge a mass of 800 kg and is able to support up to 4 560 kg. What is its structural efficiency?

Answers

Answer:4560÷800=5.4

Explanation:

Est = DL / W

EST=4560/800=5.7

Determine the dimensions for W if W = P L^3 / (M V^2) where P is a pressure, L is a length, M is a mass, and V is a velocity.

a. M
b. L / T
c. M L / T^2
d. M / (L T^2)
e. No dimensions

Answers

Correct answer is option E. No dimensions

As we know formula Pressure (P) is [tex]\frac{F}{A}[/tex]

also,

Dimensional formula of Pressure is [tex]M^{1}L^{-1}T^{-2}[/tex]Dimensional formula of length is L Dimensional formula of mass is MDimensional formula  of velocity is [tex]L^{1} T^{-1}[/tex]

So, as given W=[tex]\frac{P*L^{3} }{M*V^{2} }[/tex]

Dimensional formula of W =[tex]\frac{M^{1}L^{-1}T^{-2} L^{3} }{M^{1} L^{2}T^{-2} }[/tex]

since all terms get cancelled

Work is dimensionless i.e no dimensions

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