According to the question, 50 kN reactions at the supports A and B for equilibrium of the beama.
What is a physical example of equilibrium?When we move a body a tiny distance, the state creates forces that usually oppose the movement and bring the body back to its equilibrium, we say that the body is in stable equilibrium. Think of a stone at the base of a bowl as an illustration.
Since the laden beam is stationary, we should equalize each other out by moving upward and downward.
Thus,
= R+R
=40+60=100 kN - (1)
Now that the beam's force has been evenly distributed across the two supports, the reaction force exerted by the two supports will also be equally, or R=R.
2R=100 kN
R=50 kN
As a result, the reaction at supports A and B will each be 50 kN.
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lava hot springs resort in idaho has a 11.5 meter tall diving platform. if you step off the platform, how fast will you be traveling in meters per second when you hit the surface of the water? neglect air drag.
The fast with which lava hot springs travelling in 15.01 m/s when it hit the surface of water.
What do you mean by motion in a gravitational field?When an object moves, it is said to be in motion under gravity since gravity has an impact on the object's vertical motion. Gravity is the force that pulls objects down. Known as acceleration owing to gravity, the earth's gravity pulls the object toward itself with an acceleration.
Height of platform =11.5 m = h
V^2 = U^2 -2gh
initial vlocity U = 0
V^2= - 2 x-9.8m/s x 11.5
= > V= 15.01m/s
What is free fall in motion under gravity?A body is said to be in freefall when it is only being moved by the gravity of the earth. The ball is encountering external push, thereby the motion will intensify. The term "gravitational acceleration" is also used to describe this rate of free fall.
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A microwave oven operates at 2.4 GHz with an intensity inside the oven of 2800 W/m2 .
a) What is the amplitude of the oscillating electric field?
b) What is the amplitude of the oscillating magnetic field?
a) The amplitude of the oscillating electric field is 2.34453×10⁻⁶T.
b) The amplitude of the oscillating magnetic field is 703.359V/m.
Describe a magnetic field.The area in which magnetism acts, called the magnetic field, is where a magnetic substance or a moving electric charge is located. An illustration of the magnetic field that shows how a magnetic force is distributed both inside and outside of a magnetic material
µ₀ = Vacuum permeability = 4π×10⁻⁷H/m
I = Flux = 2800 W/m²
c = Speed of light is 3×10⁸m/s
The magnetic field's oscillation's amplitude
B₀ = √2µ₀I/c
B₀ = √2× 4π×10⁻⁷×2800/ 3×10⁸
B₀ = 2.34453×10⁻⁶T
The oscillating magnetic field's amplitude is 2.34453×10⁻⁶T
The electric field's oscillation's amplitude
E₀ = c ×B₀
E₀ = 3×10⁸× 2.34453×10⁻⁶
E₀ = 703.359V/m.
The oscillating electric field's amplitude is 703.359V/m.
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The length of a diagonal of a square is given by the function d(s) = 2s2 , where s is the length of a side of the square. Find the distance from home plate to second base on a softball diamond and on a baseball diamond. The illustration gives the dimensions of each type of infield. (Round your answers to one decimal place.)
The distance from home plate to second base on a softball diamond is 84.85 m and on a baseball diamond is 127.28 m.
What is the illustration?The illustration is a stylized drawing of a group of people gathered together in a circle, their arms linked together in a gesture of solidarity. The figures are all various shades of blue, and their faces are uplifted and smiling. The image conveys the idea of collective strength and unity. It is a powerful visual representation of coming together to support each other, and of the strength that can be found in community.
Using the Pythagorean Theorem
c = [tex]\sqrt{a^2 + b^2}[/tex]
Diagonal = c = d(s) = √2s2
d(s) = [tex]\sqrt{2s^2}[/tex]
d(s) = [tex]\sqrt{s^2 + s^2}[/tex]
The function represents Pythagorean theorem
Given s is 90m
d(90) = [tex]\sqrt{90^2 + 90^2}[/tex]
d(90) = 127.28 m
In the same way
d(60) = [tex]\sqrt{60^2 + 60^2}[/tex]
d(60) = 84.85 m
Thus, The distance from home plate to second base on a softball diamond is 84.85 m and on a baseball diamond is 127.28 m.
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What causes friction between two surfaces? How can friction be reduced?
Answer:
Explanation:
Friction between two surfaces is caused by the contact between them. When two surfaces interact, the roughness of the surfaces combine with the contact force to create a force that resists the motion of the surfaces. When two surfaces are moving relative to each other, the contact force must overcome the friction force in order for the surfaces to move.
Friction can be reduced by either reducing the contact force, or by making the surfaces smoother. One way to reduce the contact force is by using a lubricant, such as oil or grease, to reduce the amount of contact between the surfaces. This reduces the force of friction and allows the surfaces to move more easily. Another way is to make the surfaces smoother, which reduces the amount of roughness and therefore reduces the friction. This can be done with sandpaper or other abrasive materials.
a force acts on a particle that undergoes a displacement. find the work done by the force on the particle. what is the angle between f and r
To determine the work done by a force on a particle, we need to consider the displacement of the particle and the angle between the force and the displacement vector.
When the force acts on a particle, it causes the particle to undergo a displacement. The work done by the force is equal to the magnitude of the force multiplied by the magnitude of the displacement vector, and then multiplied by the cosine of the angle between the force and displacement vector.
To find the work done by the force, you must first calculate the magnitude of the force, the magnitude of the displacement vector, and the angle between the force and displacement vector.
Once these three components have been calculated, the work done by the force can be calculated using the equation W = F * r * cos(θ).
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the type of system in which mass and energy are constantly transferred in form, quantity, and location is a(n) blank system
The type of system in which mass and energy are constantly transferred in form, quantity, and location is a(n) open system.
An open system is a system that allows the exchange of energy and matter with its surroundings. The energy and matter can flow in and out of the system, and can change its form, quantity, and location. An open system is also known as a non-isolated system.
if you walked at an average speed of 1.2 m/s, how long would it take to cross a road that is 16-m wide?
If you walked at an average speed of 1.2 m/s, 13.3 s long would it take to cross a road that is 16-m wide.
What is speed ?
The rate of a directionally changing object's location. The distance travelled divided by the time required to travel that distance is the definition of speed. Speed is a scalar quantity because it only has an angular component and no magnitude.
What is velocity ?
An object's velocity is a key factor in determining its position and rate of motion. It is comprehensible as the distance an object moves in a single interval of time. The term "velocity" describes how far an object travels in a predetermined length of time.
T = D/S = 16m/1.2m/s = 13.3 s
Therefore, If you walked at an average speed of 1.2 m/s, 13.3 s long would it take to cross a road that is 16-m wide.
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the earth travels around the sun once a year in approximately circular orbit with a radius of 1.50*10^11m Using the orbital speed of the earth, calculate the mass of the sun
The sun has a mass of 1.9891 x 10^30 kg. The planet's orbital speed causes the earth to orbit the sun in an approximately circular orbit with a radius of 1.50*10^11m once every year.
A essential quality of a body is its mass. It was widely believed to be connected to the volume of matter in a physical body before to the atom's discovery and the development of particle physics. Theoretically, the same chemical might be included in different atoms and elementary particles. In celestial physics, an orbit is a curved path. Orbital velocity equals (9.424 x 1011 m)/31536000 s orbital velocity is 29883.307 m/s.
The Earth's orbital speed is therefore 29883.307 m/s.
There are 1.9891 x 10^30 kilogrammes in the sun.
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An 65 kg Olympic runner leaps over a hurdle. The acceleration of gravity is 9.81 m/s 2 . If the runner’s initial vertical speed is 2.9 m/s, how much will the runner’s center of mass be raised during the jump? Answer in units of m.
The vertical height in which the runner’s center of mass is raised during the jump is 0.43 m.
What is the vertical height reached by the runner?
The vertical height reached by the runner is calculated by applying the third kinematic equation as shown below.
Mathematically, the formula is given as;
v² = u² - 2gh
where;
v is the final velocity of the runner at the maximum heightu is the initial velocity of the runnerg is acceleration due to gravityh is the height reached by the runnerat maximum height, the final velocity, v = 0
The vertical height reached by the runner is calculated as;
0 = u² - 2gh
2gh = u²
h = u² / 2g
h = ( 2.9² ) / ( 2 x 9.8 )
h = 0.43 m
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a 30kg child sits 2.0 m from the fulccrum of a seasaw how far form the fulccrum must an 18 kg child sit
The 18 kg child must sit 3.3 meters from the fulcrum to balance the system.
To determine the distance from the fulcrum at which an 18 kg child must sit on a seesaw to balance a 30 kg child sitting 2.0 m away from the fulcrum, you can use the principle of moments.
The principle of moments states that for a system to be in equilibrium (i.e., balanced), the clockwise moments (force x distance) must be equal to the counterclockwise moments.
We know the weight of the 30 kg child is 30 x 9.8 = 294 N (Newtons), and it is 2.0 m away from the fulcrum. Therefore, the clockwise moment is 294 x 2 = 588 Nm.
The weight of the 18 kg child is 18 x 9.8 = 176.4 N.
To balance the system, the counterclockwise moment must also be 588 Nm. Therefore, the distance from the fulcrum at which the 18 kg child must sit is:
588 Nm = 176.4 N x d
d = 588/176.4 = 3.3 meters
So, the 18 kg child must sit 3.3 meters from the fulcrum to balance the system.
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When a golf club hits a 0.0459 kg ball (initially at rest), it exerts a 2380 N force for 0.00100 s. What is the momentum of the ball afterwards?
PLEASE I NEED HELP!
The momentum of the ball after being hit by the club can be calculated using the formula p = mv, where p is momentum, m is mass, and v is velocity. Since the force exerted on the ball is known (2380 N) and the time over which the force is exerted is also known (0.00100 s), we can use the formula F = ma to find the acceleration of the ball, where F is force, m is mass, and a is acceleration.
F = m*a
a = F/m
a = 2380 N / 0.0459 kg
The acceleration of the ball is 51760 m/s^2
Next, we can use the kinematic equation v = u + at to find the velocity of the ball, where v is final velocity, u is initial velocity and t is time.
v = u + at
u = 0 m/s (initial velocity)
t = 0.00100 s (time)
v = 0 + (51760 m/s^2)*(0.00100 s)
v = 5.176 m/s
Finally, we can use the momentum formula
p = m*v
p = (0.0459 kg)*(5.176 m/s)
p = 238.64 Ns (Newton second)
Therefore, the momentum of the ball after being hit is 238.64 Ns.
object a has a charge 1.8 x 10-6 c. object b has a charge -1.0 x 10- 6 c. they are 0.014 m apart. what is the force on a? on b?
The charge of object A is 1.8 x 10-6C. The charge on object B is 1.0 x 10- 6C. Their distance is 0.014 meters. The force is 83N on both A and B.
Given the charge on object A is (Q1) = 1.8 x 10^-6C
The charge on object B is (Q2) = -1.0 x 10^-6C
They are separated at a distance of (r) = 0.014m = 1.4 x 10^-2m
The force of attraction between them is calculated as (F) = kQ1Q2/r^2
where k = 9 x 10^9
Since they are unlike charges they will be attracted to each other.
F = 9 x 10^9 x 1.8 x 10^-6 x 1 x 10^-6 / (1.4 x 10^-2)^2 = 82.6 = 83N
Hence the force on object A and object B is 83N.
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50 W of power are used lifting a crate of fruit and 75 seconds. What was the work done lifting?
Answer:
0.667 joules
Explanation:
work = power/Time
50/75
=0.667joules
In the circuit shown in the figure (Figure 1) find.
A) the current in resistor R
B) the resistance R
C) the unknown emf E
C)If the circuit is broken at point x, what is the current in resistor R?
From the given circuit the current in resistor R is 2A, the resistance R is 5ohm, the unknown emf E is 42V and if the circuit is broken at point x, the current in resistor R is zero.
Given the diagram, the voltage passing through resistor R (V) = 28V
The current passing through resistor R is = I1
The resistance of second resistor (R2) =6 ohm.
The current passing through R2 = 4A
The resistance of third resistor (R3) = 3 ohm
The current passing through R3 = 6A
The emf at resistor R2 = e
Here we can see that current passing through R3 is split into I1 and I2 such that I1 + I2 = I3. Then, I1 + 4 = 6A
I1 = 2A
(a) The current in resistor R = 2A
(b) From ohms law we know that V = IR. Then V1 - I3R3 -I1R1 = 0
28 - (3 x 6) - (2 x R) = 0. then R = 5ohm.
The resistance R = 5 ohm
(c) Similarly, e - (3 x 6) - ( 6 x 4) = 0
Then e = 42V
The unknown emf = 42V
(d) When the circuit is broken at x, that branch is eliminated from the circuit. It will stop carrying current. The distribution of currents and voltages in the other portions of the circuit will vary as a result.
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A spring-loaded toy is released, and the force from the spring accelerates a 1 kg ball from rest to a velocity of 200 m/s.
What was the impulse experienced by the ball?
The impulse experienced by an object is the force applied to it multiplied by the time during which the force is applied. In this case, the impulse experienced by the ball is equal to the force exerted by the spring on the ball multiplied by the time over which the force is applied. Since the force is equal to the mass of the ball multiplied by the acceleration of the ball, we can use the following equation to calculate the impulse:
Impulse = Force x time = (mass x acceleration) x time
We know that the mass of the ball is 1 kg, and the final velocity of the ball is 200 m/s, but we don't know the time of the acceleration, so we need more information to calculate the impulse.
Another way to calculate the impulse is using the change of momentum principle. The impulse is equal to the change in momentum. The change in momentum = final momentum - initial momentum = m * vf - m * vi = m * (vf - vi)
Since the initial velocity was 0 and the final velocity is 200 m/s, the impulse is equal to m * vf = 1 kg * 200 m/s = 200 Ns
So, the impulse experienced by the ball is 200 Ns
I hope this helps :)
a bicycle completed the first 500.0 m of a ride in 80.9 s. what was the bicycle's average speed in kilometers per hour?
The bicycle's average speed was 54.43 kilometers per hour. the bicycle's average speed in kilometers per hour.
what is speed ?
Speed is a measure of how quickly an object moves or changes its position over time. It is a scalar quantity, which means it is described by a magnitude only and does not have a direction. Speed is measured in units such as meters per second (m/s), kilometers per hour (km/h), and miles per hour (mph). The faster an object moves, the greater its speed.
Speed is often confused with velocity, which is a vector quantity that includes both magnitude and direction. Acceleration is the rate at which an object's speed changes over time. An object with a constant speed will have an acceleration of zero, while an object increasing its speed will have a positive acceleration and an object decreasing its speed will have a negative acceleration.
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can velocity be negative with respect to the direction?
Answer: Yes!
Explanation: Think of a number graph. If we go right it will be positive and if we go left it'll be negative. Like this the velocity can me negative or positive based on the direction.
pollux, one of the brightest stars in the night sky, is 33.7 light-years from earth. if one light-year is 6,000,000,000,000 miles, about how many miles is pollux from earth? write answer in scientific notation, rounding to two decimal places.
According to the question, Pollux is approximately 2 x 1014 kilometers, or 34 light years, away from the Earth.
What is the length of a light-year?
A light-year measures distance rather than time (as the name might imply). A light-year is the distance a light beam travels in one year on Earth, which is around 6 trillion miles (9.7 trillion kilometers).
Do light years have 365 days?
The distance that light travels in a year is called a light year (365 days). Because "year" is right there in the name, it is frequently used incorrectly as a measure of time. Light will always need one year to traverse one light year.
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As you walk away from a vertical plane mirror, your image in the mirror O decreases in height. O is always a real image, no matter how far you are from the mirror. O may or may not decrease in height, depending on where the observer is positioned. o changes from being a virtual image to a real image as you pass the focal point. is always the same height.
The vertical plane mirror is a flat, vertical surface, usually made of glass or metal.
What is virtual image?Virtual image is an optical illusion created by a lens or mirror. It is a two dimensional representation of an object which appears to be the same distance away from the lens as the original object. It is formed by the convergence of light rays that are not actually present, but seem to be originating from the image. Virtual images can be viewed on a screen or projected onto a wall. Virtual images cannot be projected onto a surface for viewing.
When you stand in front of it, the light from the object that you are looking at reflects off the mirror and creates an image of the object in the mirror. This is because light travels in straight lines and when it meets the mirror it bounces off it in the same direction.
When you are standing close to the mirror, the image of the object in the mirror is upright and appears to be the same height as the original object. This is because the light from the object is reflected off the mirror and reaches your eyes in a straight line. As you move away from the mirror, the distance between the object and the mirror increases and the light is no longer traveling in a straight line. The light is now traveling at an angle and this causes the image to appear tilted in the mirror. This tilt causes the image to appear shorter than the original object.
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A 54-g tennis ball is in contact with the racket for a distance of 40 cm as it leaves the racket with a velocity of 48 m/s. What is the average force on the ball?
Need to know ASAP
Answer:
Explanation: First list the parameters
m = 54 g, d = 40 cm, v = 48 m/s, f =?
Then, convert the distance to meters
That is d = 40/ 100
d = 0.4 m
Now, let's find the force
f = ma
From the question, a is not given
Therefore, we find a
a = v/ t
a = 48 / 0.4
a = 120 m/s^2
Now, back to f
f = ma
f = 54 x 120
f = 6480N
Two consecutive harmonics of air column in a pipe closed at one end are frequency 150Hz and 250Hz ccalculat the fundamental frequency
The fundamental frequency of the air column is 150 Hz.
How to calculate the fundamental frequency?The fundamental frequency of an air column in a pipe closed at one end is related to the frequency of the first harmonic (also known as the first overtone or the fundamental mode) by the equation:
f1 = (2Lc)/n
where L is the length of the air column, c is the speed of sound in air, and n is the harmonic number (1 for the fundamental frequency, 2 for the second harmonic, etc.).
If two consecutive harmonics of an air column have frequencies of 150Hz and 250Hz, we can use these frequencies to calculate the fundamental frequency by solving the equation for n=1 and n=2.
For n=1:
150Hz = (2Lc)/1
For n=2:
250Hz = (2Lc)/2
Dividing the two equations:
(250Hz * 2) = (150Hz * 1)
Lc = (150Hz * 1) / 2
And now we can calculate the fundamental frequency
f1 = (2Lc) / 1 = 2 * (150Hz * 1) / 2 = 150Hz
The fundamental frequency of the air column is 150 Hz.
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depending on the wavelength, laser energy is emitted in very specific portions of the electromagnetic spectrum. where in the spectrum do most dental lasers operate?
With emission wavelengths ranging from 500 to 10,600 nm, all dental lasers now on the market can be classified as either visible or invisible (infrared) nonionizing radiation.
Most dental lasers work in the visible and ultraviolet ranges of the electromagnetic spectrum. The sign, with nm units, stands for the laser wavelength. It is dictated by the resonator length of the chip structure and the crystal material's bandgap. The wavelengths of ultraviolet radiation used in lasers range from 180 to 400 nanometers (nm). Radiation with wavelengths between 400 and 700 nm makes up the visible range. A particular kind of laser made for use in oral surgery or dentistry is known as a dental laser.
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Now suppose Bx>0 , and another electron is projected in the same manner. Which of the following is the most accurate qualitative description of the electron's motion once it enters the region of nonzero magnetic field
The right response, based on the provided statement, is that the electron travels in the x direction at a consistent speed along a helical route centred on an axis corresponding to the field lines.
What does an electron mean simply?A opposite charges new particle known as an electron can either be free or attached to an atom (not bound). One of the three main types of molecules within an atom is an ion that is bonded to it; the other other are protons and nuclei.
What does a scientific electron mean?A tiny, negatively charged particle that exists in every atom. Radiation therapy can make use of electron streams produced by specialised equipment.
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The complete question is-
Now suppose Bx>0 , and another electron is projected in the same manner. Which of the following is the most accurate qualitative description of the electron's motion once it enters the region of nonzero magnetic field?
a). The electron decelerates before coming to a halt and turning around while always moving along a straight line.
b). The electron's motion will be unaffected. (It will continue moving in a straight line with the same constant velocity.)
c). The electron moves in a circle in the xy plane.
d). The electron moves along a helical path about an axis parallel to the field lines with constant radius and constant velocity in the x direction.
you watch a giant spider crawling across your bedroom floor at 630 ft/hr. your bedroom is 15 ft wide. how long did it take the spider to travel
The time taken for the giant spider traveling at 630 ft/hr to travel through your bedroom that is 15 ft wide is 42 hours
How do I determine the time taken for the spider to travel?Speed is defined as the distance travel over a given time. Mathematically, it is written as:
Speed = Distance / time
Making time the subject of the formula, we have:
Speed = Distance / time
Cross multiply
Speed × time = Distance
Divide both sides by speed
Time = Distance / speed
Apply the above formula, we can obtain the time taken from the spider to travel through your bedroom. Details below:
Speed of giant spider = 630 ft/hrDistance travel = 15 ftTime taken to travel =?Time = Distance / speed
Time = 630 / 15
Time = 42 hours
Thus, we can conclude that the time taken for the giant spider to travel is 42 hours
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. a scuba diver is diving into lake superior, a deep freshwater lake. at what depth below the surface is the absolute pressure 2 atm? freshwater has a density of 1000 kg/m3 . show your work.
The density of seawater is 1025 kg per meter cube, the G is 9.8 m per second square, and the depth is 40 m, thus we switched to the power three pascal plus.
Why is it important for scuba divers to practice and be well-prepared before venturing into the ocean's depths?
You run the risk of passing out. The bends decompression sickness. If you rise from deep water to the surface too rapidly, this syndrome may develop. Your body emits nitrogen gas, which causes bubbles to form in your blood.
What pressure exists 100 meters under the water's surface?
Water pressure is 10bar at 100 meters below the surface. Although atmospheric pressure is 1 bar, the absolute pressure is 11 bar.
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An unfingered guitar string is 0.73 m long and is tuned to play E above middle C (330 Hz).
(a) How far from the end of this string must the finger be placed to play B above middle C (494 Hz)?
?m
(b) What is the wavelength on the string of this 494 Hz wave?
?m
(c) What are the frequency and wavelength of the sound wave produced in air at 20
a) The distance from the end of the string is calculated to be 0.24 m.
b) The wavelength of the string is 0.98 m.
c) The wavelength of the sound produced is 0.69 m.
Given that,
Length L₁ = 0.73 m
Frequency F₁ = 330 Hz
Frequency F₂ = 494 Hz
Let us find out L₂ using the relation, L₁ F₁ = L₂ F₂
Making L₂ as subject, we have,
L₂ = L₁ F₁/F₂ = (0.73 × 330)/494 = 240.9/494 = 0.49 m
The length from the end is said to be 0.73-0.49 = 0.24 m
Wavelength of the string is given by the formula, Δ = 2 L₂ = 2(0.49) = 0.98 m
Frequency of the wave = 494 Hz
We know the relation, V = Δ × f
where, Δ is wavelength
f is frequency
V is velocity
As we know, V = 343 m/s
Let us make Δ as subject, as place f value.
Δ = V/ f = 343/494 = 0.69 m
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A small polyester ball and a piece of polyvinyl chloride (PVC) pipe are given the same negative charge. The ball is then placed over the PVC pipe, where it is observed to remain at rest 20 cm from the pipe. The mass of the polyester ball is 5.0 grams. Determine the charge on the ball.
The charge is ___uc
Also, solve using significant figures.
The magnitude of the charge on the ball is 0.467 μC.
What is the charge on the ball?
The magnitude of the charge on the ball is calculated by applying Newton's second law of motion Coulomb's law as follows;
Mathematically, the formula for Newton's second law of motion and coulomb's law is given as;
F = mg
F = kq²/r²
where;
m is the mass of the ballq is the charge of the ballg is acceleration due to gravityr is the distance of the ballk is Coulomb's constantkq²/r² = mg
q² = ( mgr² ) / ( k )
q = √ ( mgr² / k )
The magnitude of the charge on the ball is calculated as follows;
q = √ ( 0.005 x 9.8 x 0.2² / 9 x 10⁹ )
q = 4.67 x 10⁻⁷ C
q = 0.467 x 10⁻⁶ C = 0.467 μC
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calculate the height (in m) of a cliff if it takes 2.36 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.05 m/s. (enter a number.) 8.312 correct: your answer is correct. m (b) how long (in s) would it take to reach the ground if it is thrown straight down with the same speed? (enter a number.)
The time would it take to reach the ground if it is thrown straight down with the same speed is found to be 2.36sec
What do the first and second laws of motion mean?The velocity-time relation refers to the first motion equation, v = u + it. On the other hand, the position-time relation is denoted by the second equation of motion, s = ut + 1 / 2at2. The third equation of motion, v2 = u2+ 2as, is also referred to as the position-velocity relation.
S-(ut )-1/2 at2 =0
a=g=> -9.8m/s2
S=> 8.05x2.36 -9.8/2 x (2.36)2
S = -8.32m
S-(ut )-1/2 at2 =0
0 = -9.8 t2/2 +8.05t + 8.32
solve quadratic equation online
t=> 2.36sec
How is acceleration determined?The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t). This enables you to calculate the change in velocity in metres per second squared (m/s2).
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a bullet with mass 60.0 g is fired with an initial velocity of 575 m/s from a gun with mass 4.50 kg. the speed of the recoil of the gun is (2 points)
A bullet with mass is fired with an initial velocity from a gun with a mass of 4.50 kg the speed of the recoil of the gun is -7.67 m/s.
Given information:
Mass, (m) = 60.0 g,
velocity, (v) = 575 m/s,
Mass, (M) = 4.50 kg,
The speed of the recoil of gun V is calculated by the conservation of momentum:
momentum conservation:
0 = mv + MV
Rearrange:
V = (-mv) ÷ M
V = (-60 × 575) ÷ (4500)
V = -7.67 m/s
Here negative means the direction is opposite to v.
Therefore, The speed of the recoil of the gun is -7.67 m/s.
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Pressure in the Ocean The pressure at 10 m below the surface of the ocean is about 2.00x105 Pa Part A Which of the following statements is true? You did not open hints for this part. ANSWER Part B Now consider the pressure 20 m below the surface of the ocean. Which of the following statements i true? You did not open hints for this part. ANSWER The weight of a column of seawater 1 m2 in cross section and 10 m high is about 2.00x105 N The weight of a column of seawater 1 m2 in cross section and 10 m high plus the weight of a column air with the same cross section extending up to the top of the atmosphere is about 2.00x10s N The weight of 1 m3 of seawater at 10 m below the surface of the ocean is about 2.00x 105 N The density of seawater is about 2.00x105 times the density of air at sea level
The weight of a column of seawater 1m² in cross sectional and 10 m high plus the weight of a column so air with the same cross sectional extending up to the top of the atmosphere is about 2.00×10⁵ N .
What is absolute pressure?Absolute pressure is defined as the pressure present in a space that is completely devoid of all substances, or a vacuum. This absolute zero serves as the reference point for calculations of absolute pressure. Barometric pressure measurements are the best illustration of an absolute referenced pressure.
The absolute pressure at 10m depth,
P = F/A
P = 2.00×10⁵ N/(1m²)
P = 2.00×10⁵ Pa.
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