Devon keeps his commitments, submits work when it's due, and shows up when scheduled. What personal skill does Devon
demonstrate?
Attire
Collaboration
Dependability
Verbal


It’s D

Answer:

There's nothing wrong with the question you posted except that it's not well presented or arranged.

When properly formatted, the program will be error free and it'll run properly.

The programming language used in the question is Java programming lamguage.

in java, the sign ";" signifies the end of each line and lines that begins with // represent comments. Using this understanding of end of lines and comments, the formatted code goes thus

import java.util.Scanner;  

public class Arraysum {  

public static void main(String[] args) {  

Scanner scnr = new Scanner(System.in);  

final int NUM_ELEMENTS = 8;

// Number of elements  

int[] userVals = new int[NUM_ELEMENTS];  

// User numbers  

int i = 0;  

// Loop index  

int sumVal = 0;  

// For computing sum  

// Prompt user to populate array  

System.out.println("Enter " + NUM_ELEMENTS + " integer values...");  

for (i = 0; i < NUM_ELEMENTS; ++i) {  

System.out.print("Value: ");  

userVals[i] = scnr.nextInt();  

}  

// Determine sum  

sumVal = 0;

for (i = 0; i < NUM_ELEMENTS; ++i)

{

sumVal = sumVal + userVals[i];

}

System.out.println("Sum: " + sumVal); return;

}

}

Also, see attachment for source file

Answer:

a. to provide a graphical user interface (GUI) and several capture filters

Explanation:

TcPDump is a command line tool used to capture packets. TcPDump is used to filter packets after a capture has been done. To control network interfaces, TcPDump need to be assigned root privileges. Data is represented in form of text

Wireshark provide a graphical user interface (GUI) and several capture filters. It is a graphical tool used in packet capture analysis. Data is represented in wireshark as text in boxes.

Answer: Provided in the explanation section

Explanation:

import java.util.Scanner;

public class commission

{

   public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

        int totals[]={0,0,0,0,0,0,0,0,0};          

      int n,sales,i,index;

       double salary;

        System.out.print("how many salesmen do you have? ");                          

      n=input.nextInt();

        for(i=1;i<=n;i++)

           {System.out.print("Salesman "+i+" enter sales: ");

            sales=input.nextInt();

            salary=200+(int)(.09*sales);

               System.out.printf("Salary=$%.2f\n",salary);

            index=(int)salary/100-2;

            if(index>8)

                index=8;

            totals[index]++;

            }

        System.out.println("SUMMARY\nSALES\t\tCOUNT");

        for(i=0;i<8;i++)

           System.out.println("$"+(i*100+200)+"-"+(i*100+299)+"\t"+totals[i]);

        System.out.println("$1000 and over\t"+totals[i]);

       }                                

   }

cheers i  hope this helped !!      

Answer:

Brute force is  technique that is used for cracking password

In this case the system uses only three characters(0-9). By applying Brute force attack in "hit and try" manner we easily crack the password.

Explanation:

Solution

There are a wide variety of password cracking mechanisms.Brute force is one of the popular password cracking technique.Brute force attack is generally used to crack small passwords.

In the given example the system uses only three characters(0-9).By using Brute force attack in "hit and try" manner we easily crack the password.There are only 10 possible passwords for this type of system.Because we can arrange 0-9 only in 10 ways.But for Systems with long passwords it is difficult to find it in hit and try manner.But instead of having plain password each password have a random salt value.

In a system of 32 bit salt value there are 2^32 different key values.

By increasing the salt value from 32 bits to 64 bits there are 2^64 different key values.It increases the time taken to crack a password for an attacker.so by changing salt value from 32 to 64 bits will make it more harder for the adversary's attack to be successful.

Answer:

weight1 = float(input("Enter the weight of first package: "))

price1 = float(input("Enter the price of first package: "))

weight2 = float(input("Enter the weight of second package: "))

price2 = float(input("Enter the price of second package: "))

if weight1 > 0 and price1 > 0 and weight2 > 0 and price2 > 0:

   unit_cost1 = price1 / weight1

   unit_cost2 = price2 / weight2

   if unit_cost1 < unit_cost2:

       print("Package 1 has a better price.")

   else:

       print("Package 2 has a better price.")

else:

   print("All the entered values must be positive!")

Explanation:

*The code is in Python.

Ask the user to enter the weight and the price of the packages

Check if the all the values are greater than 0. If they are, calculate the unit price of the packages, divide the prices by weights. Then, compare the unit prices. The package with a smaller unit price has a better price.

If all the entered values are not greater than 0, print a warning message

xekksksksksgBcjqixjdaj

Answer:

Explanation:

Create two arrays to hold the list of popcorn name and their sales (Line 5-8). Next prompt user to input the sales for each popcorn (Line 10-14). Get the maximum sales of the popcorn (Line 17-24) and minimum sales (Line 27-34). Print the popcorn name and sales (Line 37-40) and the popcorn name with highest and lowest selling (Line 43-44).

Answer: Provided in the explanation section

Explanation:

C++ Code

#include<iostream>

#include<fstream>

#include<string>

using namespace std;

// read plain text from file

void readPlaneText(char *file,char *txt,int &size){

  ifstream inp;

  inp.open(file);

  // index initialize to 0 for first character

  int index=0;

  char ch;

  if(!inp.fail()){

      // read each character from file  

      while(!inp.eof()){

          inp.get(ch);

          txt[index++]=ch;

      }

  }

  // size of message

  size=index-1;

}

// read key

int **readKey(char *file,int **key,int &size){

  ifstream ink;

  //

  ink.open(file);

      if(!ink.fail()){

          // read first line as size

      ink>>size;

      // create 2 d arry

      key=new int*[size];

      for(int i=0;i<size;i++){

          key[i]=new int[size];

      }

      // read data in 2d matrix

      for(int i=0;i<size;i++){

          for(int j=0;j<size;j++){

              ink>>key[i][j];

          }  

      }

  }

  return key;

}

// print message

void printText(string txt,char *msg,int size){

  cout<<txt<<":\n\n";

  for(int i=0;i<size;i++){

      cout<<msg[i];

  }

}

// print key

void printKey(int **key,int size){

  cout<<"\n\nKey matrix:\n\n";

  for(int i=0;i<size;i++){

      for(int j=0;j<size;j++){

          cout<<key[i][j]<<" ";

      }  

      cout<<endl;

  }

}

void encrypt(char *txt,int size,int **key,int kSize,char *ctxt){

  int *data=new int[kSize];

  for(int i=0;i<size;i=i+kSize){  

  // read key size concecutive data

      for(int a=0;a<kSize;a++){

          data[a]=txt[i+a]-'a';

      }

      // cipher operation

      for(int a=0;a<kSize;a++){

          int total=0;

          for(int b=0;b<kSize;b++){

              total+=key[a][b]*data[b];

          }  

          total=total%26;

          ctxt[i+a]=(char)('a'+total);

      }      

  }

}

int main(int argc,char **argv){

  char text[10000];

  char ctext[10000];

  int **key;

  int keySize;

  int size;

  // input

  key=readKey(argv[1],key,keySize);

  readPlaneText(argv[2],text,size);

  encrypt(text,size,key,keySize,ctext);

  // output

  printKey(key,keySize);

  cout<<endl<<endl;

  printText("Plaintext",text,size);

  cout<<endl<<endl;

  printText("Ciphertext",ctext,size);

  return 0;

}

cheers i hope this helped !!!

Answer:

1. The solution to question 1 is as follows;

srand(seedVal);

cout<<rand()%10<<endl;

cout<<rand()%10<<endl;

2. The solution to question 2 is as follows

cout<<100+rand()%50 <<endl;

cout<<100+rand()%50 <<endl;

Explanation:

The general syntax to generate random number between interval is

Random Number = Lower Limit + rand() % (Upper Limit - Lower Limit + 1)

In 1;

The solution starts by calling srand(seedVal);

The next two statements is explained as follows

To print two random integers between intervals of 0 and 9 using rand()"

Here, the lower limit = 0

the upper limit =  9

By substituting these values in the formula above; the random number will be generated as thus;

Random Number = 0 + rand() % (9 - 0 + 1)

Random Number = 0 + rand() % (10)

Random Number = rand() % (10)

So, the instruction to generate the two random variables is rand() % (10)

2.

Similar to 1 above

To print two random integers between intervals of 100 and 149 using rand()"

Here, the lower limit = 100

upper limit = 149

By substituting these values in the formula above; the random number will be generated as thus;

Random Number = 100 + rand() % (149 - 100 + 1)

Random Number = 100 + rand() % (50)

So, the instruction to generate the two random variables is 100 + rand() % (50)

Answer:

This program is written using python

It uses less comments (See explanation section for more explanation)

Also, see attachments for proper view of the source code

Program starts here

#Prompt user for price of package 1

price1 = int(input("Enter Price 1: "))

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

#Prompt user for weight of package 1

weight1 = int(input("Enter Weight 1: "))

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

#Calculate Unit of Package 1

unit1 = float(price1/weight1)

print("Unit cost of Package 1: "+str(unit1))

#Prompt user for price of package 2

price2 = int(input("Enter Price 2: "))

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

#Prompt user for weight of package 2

weight2 = int(input("Enter Weight 2: "))

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

#Calculate Unit of Package 2

unit2 = float(price2/weight2)

print("Unit cost of Package 2: "+str(unit2))

#Compare units

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Explanation:

price1 = int(input("Enter Price 1: ")) -> This line prompts the user for price of package 1

The following while statement is executed until user inputs a value greater than 1 for price

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

weight1 = int(input("Enter Weight 1: ")) -> This line prompts the user for weight of package 1

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

unit1 = float(price1/weight1) -> This line calculates the unit cost (per weight) of package 1

print("Unit cost of Package 1: "+str(unit1)) -> The unit cost of package 1 is printed using this print statement

price2 = int(input("Enter Price 2: ")) -> This line prompts the user for price of package 2

The following while statement is executed until user inputs a value greater than 1 for price

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

weight2 = int(input("Enter Weight 2: ")) -> This line prompts the user for weight of package 2

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

unit2 = float(price2/weight) -> This line calculates the unit cost (per weight) of package 2

print("Unit cost of Package 2: "+str(unit2)) -> The unit cost of package 2 is printed using this print statement

The following if statements compares and prints which package has a better unit cost

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Answer:

Many-to-one (multiple inputs, single output)

Explanation:

Solution

In the case of a recurrent neural network that listens to a audio speech sample, and classifies it according to whose voice it is, the RNN will listen to the audio and will give result by doing classification.

There will be a single output, for the classified or say identified person.

The RNN will take a stream of input as the input is a audio speech sample.

Therefore, there will be multiple inputs to the RNN and a single output, making the best fit Architecture to be of type Many-to-one(multiple inputs, single output).

Answer:

A method  used to improve the performance of structure when running queries is known as Partitioning indexes.

The advantages of partitioning indexes are, It enables data management operations for example,  index creation and rebuilding, It increases query performance.

The disadvantages are, one cannot define the primary index of partitioned table to be unique unless the whole partitioning column set is part of the primary index definition.

Explanation:

Solution

Partitioning indexes are known as b -tress indexes that shows hon how to break up the index into separate or different partitions.

Partitioning is usually done to enhance the performance and increased availability. when data are spread over  multiple partitions, one can be able to operate on one partition  without affecting others. i.e to run utilities, or to take data offline.

Almost all DBMS products support partitioning, but in various ways. we must be sure to know the nuances of an individual a particular DBMS execution before partitioning.

The advantages of Partitioned indexes are as follows:

It enables data management operations for example,  index creation and rebuilding

It increases  performance of query

It can significantly the impact of schedule downtime for maintenance operations

Disadvantages:

The primary index of partitioned table cannot be described to be unique except if  the whole partitioning column set is part of the primary index definition.

Answer:

C. Resource Pool share value.

Explanation:

The vSphere is a term used to describe the VMware’s virtualization cloud platform. The vSphere comprises of the following, vCenter Server, ESXi, Virtual Machine File System (VMFS) and vCenter Client.

If a vSphere Administrator receive complaints that a database Virtual Machine (VM) is experiencing performance issues and the Virtual Machine (VM) is a member of the high priority resource pool and the cluster has not experienced contention.

In order to address immediate performance concerns, the vSphere Administrator should check the Resource Pool share value.

VMware resource pool refers to the aggregated central processing unit and memory allocated to a Virtual Machine (VM) for flexible management of the resources.

Also, the vSphere Administrator should install VMware tools to check which processes are having high CPU usage by using vimtop, as well as checking if vCenter Server is swapping.

Answer:

CASE tools reduce the need for end user participation in systems development.

Explanation:

CASE is an acronym for Computer-aided Software Engineering and it comprises of software application tools that provide users with automated assistance for Software Development Life Cycle (planning, analysing, designing, testing, implementation and maintenance). The CASE tools helps software developers in reducing or cutting down of the cost and time of software development, as well as the enhancement of the software quality.

Some other benefits of using the CASE tools are;

- CASE tools provide automated graphics facilities for producing charts.

- CASE tools have capabilities for validating design diagrams and specifications.

- CASE tools support collaboration among team members.

- CASE tools facilitate the creation of clear documentation.

- CASE tools checks for consistency, syntax errors and completeness.

The CASE tools can be grouped as, requirement and structure analysis, software design, test-case and code generation, reverse engineering, and document production tools.

Examples of CASE tools are flowchart maker, visible analyst (VA), dreamweaver, net-beans, microsoft visio, adobe illustrator and photoshop etc.

Answer:

The correct syntax to overload is bool operator (float amt): so, the third statement is right.

Explanation:

Solution

From the given question we have to find which statements is correct for the following function prototype.

Now,

Since the price of a Car object is above  $5000, the car here is considered a struct and myCar is an object of Car

Both Car object consists of  two variables which are  id (int) and price (float)

Thus, from the given example the corresponding code says that the ID of myCar is represented as follows:

myCar - [12345, 6000);

The float price = 5000

Then,

cout << "My car price is more than $5,000/n"

Therefore the following statement bool operator (float amt): is the right syntax to overload.

Answer:

I think that they should ban ads for all four products.  These products, e-cigarettes, abortion clinics, ice cream, and sugared soft drinks, are all discreet adult products that should not be advertised because of their health hazards.  Since the "large online company provides a widely used search engine, social network, and/or news service, which are mainly patronized by younger people, such ads that promote products injurious to individual health should be banned.  Those who really need or want these products know where they could get them.  Therefore, the products should not be made easily accessible to all people.  Nor, should ads promote their patronage among the general population.

Explanation:

Advertisements create lasting and powerful images which glamourize some products, thereby causing the general population, especially children, to want to consume them without any discrimination of their health implications.  If online banning is then contemplated, there should not be any distinguishing among the four products: e-cigarettes, abortion clinics, ice cream, and sugared soft drinks.

Answer:

The programming language is not stater; However, I'll answer this question using C++.

This program does not use comments (See explanation)

See Attachment for program file

Program starts here

#include <iostream>

using namespace std;

int main()

{

string response;

cout<<"What kind of swallow?\n";

cin>>response;

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

else

{

 cout<<"You really are not fit to be a king.";

}

   return 0;

}

Explanation:

string response; -> A string variable to hold user input is declared

cout<<"What kind of swallow?\n"; -> prompts user for input

cin>>response; -> user input is stored here

The following iteration converts user input to uppercase; so that the program will work for inputs like African, AFRICAN, AFriCAN, etc.

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

The following if statement prints "Yes, it could grip it by the husk." if user input is AFRICAN

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

Otherwise, if user input is EUROPEAN, it prints; "A five-ounce bird could not carry a one-pound coconut."

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

Lastly; for every inputs different from AFRICAN and EUROPEAN, the program displays "You really are not fit to be a king."

else

{

 cout<<"You really are not fit to be a king.";

}

Answer:

Web pages with personal or biographic information are called. a. Social Networking sites. c.

Explanation:

Answer:

Full back up

It creates complete copy of the source of data. This feature made it to the best  back  up with good speed of recovery of the data and  simplicity.However, because it  is needed for backing up  of  a lot of data, it is time consuming process,Besides it also  disturbs the routine application of  the technologist infrastructure. In addition large capacity storage is needed  for the  storage of  the large volume of back up with each new creation.

Incremental back up: back up work at high speed thus saves time, Little storage capacity is needed. This type of back up can be run as  many time as wished.

However, the restoration of data takes time, due to the time spent for restoration of initial back up and the incremental.

Differential Back up has very fast back up operation, because it only requires two pieces of back up.This is however slower compare to the Incremental.

The selective back up enable selection of certain type of file or folders for back up.

it can only be used to back up folders only when important data  are needed only.Thus the  storage capacity is low.

CPD eliminates back up window and reduces the recovery point objective.However, it has issue of compatibility with the resources to back up.,it is also expensive because its solutions are disk based.

Cloud based is affordable and save cost,It is easier to access. it is efficient,it can be access remotely for convenience.

However, Internet sources and some bandwidth must be available for access., always depends on third party providers,There is also problems encountered when switching providers.

Explanation:

Answer:

B - The user is no longer able to log on to the network

Explanation:

Answer:

google kis kam ka hai us se puch lo

Answer:

b. Try to convince the owner of the computer to give you to decryption key/password.

Explanation:

Encrypted hard drives have maximum security and high data protection. to access them you need to enter a password to unlock them.

The image filtering technique is a method that serves to selectively highlight information contained in an image, for which it does not work.

The encryption algorithm is a component used for the security of electronic data transport, not to access data on an encrypted hard drive.

The encryption key is used in encryption algorithms to transform a message and cannot be exposed by disconnecting the hard drive from its power source.

Answer:

import java.util.*;

public class Grade {

   public static void main(String[] args) {

       Scanner input = new Scanner(System.in);

       double[] grades =  new double[4];

       for (int i=0; i<4; i++){

           System.out.print("Enter a grade: ");

           grades[i] = input.nextDouble();

       }

       double lowest = grades[0];

       double highest = grades[0];

       double total = 0;

       for (int i=0; i<4; i++){

           System.out.println("Grade " + (i+1) + " is: "  + grades[i]);

           if(grades[i] >= highest)

               highest = grades[i];

           if(grades[i] <= lowest)

               lowest = grades[i];

           total += grades[i];

       }

       double average = total/4;

       System.out.println("The highest grade is: " + highest);

       System.out.println("The lowest grade is: " + lowest);

       System.out.println("The average is: " + average);

  }

}

Explanation:

Ask the user for the grades and put them in the grades array using a for loop

Create another for loop. Inside the loop, print the grades. Find highest and lowest grades in the grades array using if-structure. Also, add each grade to the total.

When the loop is done, calculate the average, divide the total by 4.

Print the highest grade, lowest grade and average.

Answer:

The csharp program is given below.

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Windows.Forms;

namespace WindowsFormsApplication1

{

   public partial class Form1 : Form

   {

       public Form1()

       {

           InitializeComponent();

      }

       private void button6_Click(object sender, EventArgs e)

       {

           int total = (Convert.ToInt32(textBox1.Text) +  Convert.ToInt32(textBox2.Text) + Convert.ToInt32(textBox3.Text) + Convert.ToInt32(textBox4.Text) + Convert.ToInt32(textBox5.Text));

           int dozen = total / 12;

           int eggs = total % 12;

           textBox6.Text = dozen.ToString();

           textBox7.Text = eggs.ToString();

       }

       private void button7_Click(object sender, EventArgs e)

       {

           textBox1.Text = "";

           textBox2.Text = "";

           textBox3.Text = "";

           textBox4.Text = "";

           textBox5.Text = "";

           textBox6.Text = "";

           textBox7.Text = "";

       }

        private void button8_Click(object sender, EventArgs e)

       {

           Close();

       }

    }

}

Explanation:

1. The integer variables are declared for total eggs, number of dozens and number of eggs.

2. The input of each text box is converted into integer by using the Convert.ToInt32() method on the value of that particular text box.

3. All the inputs are added and the sum is assigned to variable, total.

4. The number of dozens are obtained by dividing total by 12 and assigning the value to the variable, dozen.

5. The number of extra eggs are obtained by taking the modulus of total and 12 and the value is assigned to the variable, eggs.

6. The integer values in the variables, dozen and eggs, are converted into string using the ToString() function with that particular value.

dozen.ToString();

eggs.ToString();

7. The text boxes are assigned the respective values of dozens and number of eggs.

textBox6.Text = dozen.ToString();

textBox7.Text = eggs.ToString();

8. Two additional buttons, clear and exit, are also added.

9. The clear button erases the contents of all the text boxes. The Text property of each textbox is set to “” thereby clearing all the text fields.

10. The exit button closes the application using Close() function.

11. The program is made in visual studio and the output is attached.

Answer:

Here is the function unzip:

def unzip(lst):

   result= zip(*lst)

   return list(result)

The complete program in Python is given below:

def unzip(lst):

   result= zip(*lst)

   return list(result)

lst =[(1, "one"), (2, "two"), (3, "three")]

tup= unzip(lst)

print(tup)

Explanation:

Here zip() function is used in the unzip function. The return type of zip() function is a zip object. This means the function returns the iterator of tuples. This function can be used as its own inverse by using the * operator.

If you do not want to use zip() function then the above program can also be implemented as following which uses a for loop for elements in the given list (lst). This can make a pair of lists (2 tuple) instead of list of tuples:

def unzip(lst):

   output = ([ a for a,b in lst ], [ b for a,b in lst ])

   return output

lst =[(1, "one"), (2, "two"), (3, "three")]  

tup= unzip(lst)  

print(tup)

The programs along with their output are attached.

Answer:

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

Explanation:

This program that we are told to write will be done by using python programming language/ High-level programming language.

The question wants us to write a program in which the output will be as below;

hey 1

hi 2

Mark 1

hi 2

mark 1

Just by imputing hey hi mark hi mark.

Just copy and run the code below.

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is

input_list = input()

list = input_list.split()

for word in list:

frequency=list.count(word)

print(word,frequency)

See more about python at brainly.com/question/18502436

Answer:

one-sided looking

Explanation:

Larry purposely looks away

Answer:

1  

def dict_intersect(d1,d2): #create dictionary

  d3={} #dictionaries

  for key1,value1 in d1.items():       #iterate through the loop  

      if key1 in d2:   #checking condition

          d3[key1]=(d1[key1],d2[key1])   #add the items into the dictionary  

  return d 3

print(dict_intersect({'a': 'apple', 'b': 'banana'}, {'b': 'bee', 'c': 'cat'})) #display

2

def consolidate(*l1):  #create consolidate

  d3={} # create dictionary

  for k in l1:       #iterate through the loop

      for number in k:   #iterate through  the loop                               d3[number]=d3.get(number,0)+1   #increment the value

             return d 3 #return

print(consolidate([1,2,3], [1,1,1], [2,4], [1])) #display

Explanation:

1

Following are  the description of program

2

Following are  the description of program