Answer:
The answer is C 3- sqrt 11
Step-by-step explanation:
. Alexandro, o professor de Física, avisou aos alunos que a média bimestral seria calculada conforme o seguinte critério: Adicionam-se as notas obtidas no projeto, na prova e no trabalho em grupo e divide-se o resultado obtido por três. Laura é uma das alunas do professor Alexandre. As notas de Laura: Projeto: 5,0 Prova: 6,5 trabalho em grupo: 9,5. A) Por que o resultado deve ser dividido por 3?
Answer:
É necessário dividir por 3 para calcular a média simples das 3 notas.
Média = 7.
Step-by-step explanation:
O resultado deve ser dividido por três porque três notas com pesos iguais (projeto, prova e trabalho em grupo) foram somadas, portanto para calcular a média bimestral de Laura, a soma das três notas deve ser dividida por 3. A média de Laura é:
[tex]M=\frac{5,0+6,5+9,5}{3}\\ M=7[/tex]
Can anyone help me ?????
Answer:
Step-by-step explanation:
The graph of a function and its inverse will always reflect through the line
y = x.
This is because a function has a specific set of coordiates, (x, y). That function's inverse has a set of coordinates that flips the x and y coordinates. For example, if a function has a set of coordinates (0, 1), (2, 3), (4, 5) then its inverse will have the coordinates (1, 0), (3, 2), (5, 4). If you plot the function's points and then the inverse's points in the same plane (meaning on the same graph) and connect the dots, you will see that the function and its inverse are reflections of each other through y = x. Below is an example of this. The dotted purplish line is the line y = x.
I will mark you brainliest!!!! What is the first step in adding these equations to eliminate y?
Answer:
I believe D
Step-by-step explanation:
If you multiplied -3 times 3 that would make -9
you can then add 9 + -9 and cross y off
If f(x) = 3x-2 and g(x) = 2x + 1 find (f-g)(x)
Answer:
x-3
Step-by-step explanation:
f(x) = 3x-2
g(x) = 2x + 1
(f-g)(x) = 3x-2 - (2x+1)
Distribute the minus sign
=3x-2-2x-1
Combine like terms
= 3x-2x-2-1
=x-3
Which set of ordered pairs does not represent a function?
Answer:
it is the last one
Step-by-step explanation:
Since a function is based on a set of ordered pairs, where the first element in each pair is from the domain and the second is from the codomain. Also A function is a mapping from a set of inputs (the domain) to a set of possible outputs (the codomain).
The last one doesn't show the correct inputs and outputs
How do I post a picture
Answer:
Go to me. Click on your profile picture then click on your profile picture again to change it
3a+2b=9 and 8x+6y=60
what is the value of 9a+6b
what is the value of 4x+3y
Answer:
The Value of 9a+6b is 27. and the value of 4x+3y is 30.
Explanation
1)
3a+2b=9
multiplying both by side by 3
or, 3×( 3a+2b)=3×9
Hence, 9a+6b=27
2)
8x+6y=60
Dividing both by side by 2
or, (8x+6y)/2 = 60/2
Hence, 4x+3y=30
Which of the following is an angle shown in the drawing?
Answer:
ABE
DBC
CBE
Step-by-step explanation:
They all have B as the middle one, and B is the vertex
I think
Please answer correctly!!!!!! Will mark brainliest !!!!!!!!!!!
Answer:
see below
Step-by-step explanation:
g(x) = sqrt(x+3)
g(-6) = sqrt(-6+3) = sqrt(-3) not a real number not in domain
g(-3) = sqrt(-3+3) = sqrt(0) 0 in domain
g(3) = sqrt(3+3) = sqrt(6) in domain
part 1. Find the value of the trig function indicated, use the Pythagorean Theorem to find the 3rd side if you need it
Answer: [tex]\bold {1)\ \cos\ \theta}=\dfrac{\sqrt2}{2}\qquad 2)\ \tan \theta =\dfrac{1}{3}\qquad 3)\ \cos\ \theta=\dfrac{3\sqrt{13}}{13}\qquad 4)\ \cos\ \theta = \dfrac{2\sqrt5}{5}}[/tex]
Step-by-step explanation:
Pythagorean Theorem is: a² + b² = c², where "c" is the hypotenuse
[tex]1)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt2}\quad =\large\boxed{\dfrac{\sqrt2}{2}}[/tex]
Note: 2² + 2² = hypotenuse² → hypotenuse = 2√2
[tex]2)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{2}{2\sqrt2}\quad =\dfrac{5}{15}\quad \rightarrow \large\boxed{\dfrac{1}{3}}[/tex]
Note: hypotenuse not needed for tan θ
[tex]3)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3}{\sqrt{13}}\quad =\large\boxed{\dfrac{3\sqrt{13}}{13}}[/tex]
Note: 2² + 3² = hypotenuse² → hypotenuse = √13
[tex]4)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{2\sqrt5}\quad =\large\boxed{\dfrac{2\sqrt5}{5}}[/tex]
Note: hypotenuse given in problem
in a wood there are 420 silver birch trees, 160 oak tees and 300 wild cherry trees. what is the percentage of the oak trees give your answer to 1 decimal place
Answer:
18.2%
Step-by-step explanation:
The total number of trees in the wood = 420 + 160 + 300
= 880 trees
∴ The percentage of the oak trees = [tex]\frac{160}{880} * \frac{100}{1}[/tex]
= [tex]\frac{2 * 100}{11}[/tex]%
= [tex]\frac{200}{11}[/tex]%
= 18.181818...%
In 1 decimal place = 18.2%
Hope this helps!!
At the corner store near Billy’s
house, loose mixed nuts cost
$1.75 per 100 g. Write an
equation to represent the amount
of mixed nuts, n, he can buy if he
has d dollars. Then, use your
equation to determine how many
grams of mixed nuts Billy can buy
if he has $5.
Answer:
d = 0.0175n ---> required equation
Billy can buy 285.714 gram nut with $5
Step-by-step explanation:
cost of 100g loose nut = $1.75
dividing LHS and RHS by 100
cost of 100/100g loose nut = $1.75
Thus, cost of 1 gm loose nut = $0.0175
let the weight of loose nut be n gm
Multiplying LHS and RHS by n
cost of x g loose nut = $0.0175*n = $0.0175n
It is given that Billy spent d dollars to buy n gm nuts
thus,
d = 0.0175n ---> required equation
________________________________________________
He spent $5 to buy nuts
substituting value of d as 5 we have
0.0175n = 5
=>n = 5/0.0175 = 285.714
Thus, Billy can buy 285.714 gram nut with $5.
∠A and ∠B are complementary. If m∠B = 64° , what is the measure of ∠A?
26°
36°
11°
64°
Answer: 26
Step-by-step explanation:
Two Angles are Complementary when they add up to 90 degrees (a Right Angle). Then
∠A + ∠B = 90
∠A =90- ∠B
∠A = 26
Answer:
The measure of [tex]\angle A[/tex]:
[tex]\angle A = 26\textdegree[/tex]
Step-by-step explanation:
Since both [tex]\angle A[/tex] and [tex]\angle B[/tex] are complementary (Which they both add up to 90°), and you want to find the measure of
Measure of [tex]\angle A[/tex]: unknown
Measure of [tex]\angle B[/tex]: 64°
Finding the measure of [tex]\angle A[/tex]:
[tex]90 - 64 = 26[/tex]
[tex]\angle A = 26\textdegree[/tex]
So, the measure for [tex]\angle A[/tex] is [tex]26\textdegree[/tex].
What is the value of x?
Answer:
x = 20
Step-by-step explanation:
The angles are vertical angles and we know that vertical angles are equal
x+40 = 3x
Subtract x from each side
x+40-x = 3x-x
40 = 2x
Divide each side by 2
40/2 = 2x/2
20 =x
Answer:
The value of [tex]x[/tex]:
[tex]x = 20[/tex]
Step-by-step explanation:
-Since, one angle with the measure [tex]x + 40[/tex] and another angle with measure [tex]3x[/tex] are vertical angles, they equal each other. So, it will be written as:
[tex]x + 40 = 3x[/tex]
-After you have formed an equation, you switch the equation and you solve for the value of [tex]x[/tex]:
[tex]x + 40 = 3x[/tex]
[tex]x - x + 40 = 3x -x[/tex]
[tex]40 = 2x[/tex]
[tex]\frac{40}{2} = \frac{2x}{2}[/tex]
[tex]20 = x[/tex]
So, the final answer is [tex]20 = x[/tex] or [tex]x = 20[/tex] (They are both the same, you just switch them).
I need help people please help me
Answer:
Each Cup has 3/8
Step-by-step explanation:
Divide
Last year, there were “x” students in the Math Club, but this year, there was a 40% increase in membership. Represent this year’s membership in terms of “x”.
Answer:
(x)1.4=Y
Step-by-step explanation:
40% increase of memeber so ita 140% of X
pleaseeeeee right answer struggling
The right answer is of:
option C
please see the attached picture....
Hope it helps.....
Good luck on your assignment.....
PLS HELP will give brainliest
If a graph is symmetric with respect to the x-axis, then it cannot be symmetric with respect to the y-axis.
A. FALSE
B. TRUE
Answer:
False, it could be.
express 0.3°8° in form a/b where by b#0
Answer:
0.3° = 0.3π/180
8° = 2π/45
Multiplying both
0.3π/180×2π/45
3/10π/180 × 2π/45
You will get
π/300 × π/45
= π²/13500 where a = π² b= 13500
Hope this helps.
the distance between (3,k) and ( 5,6) is 2root2 units then k
Answer:
Step-by-step explanation:
[tex]\sqrt{x} Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\\sqrt{(5-3)^{2}+(6-k)^{2}}=2\sqrt{2}\\\\\sqrt{(2)^{2}+[(6)^{2}-(2*6*k)+(k)^{2}]}=2\sqrt{2}\\\\\sqrt{4+[36-12k+k^{2}]}=2\sqrt{2}\\\\\sqrt{40-12k+k^{2}}=2\sqrt{2}\\[/tex]
Take square both side
[tex]40-12k+k^{2}=(2\sqrt{2})^{2}\\\\40-12k+k^{2}=4*2\\\\40-12k+k^{2}=8\\\\k^{2}-12k+40-8=0\\\\k^{2}-12k+32=0\\[/tex]
Factorize,
Sum = -12
Product = 32
Factors = -8 , -4
k² - 8k - 4k + (-8)*(-4) = 0
k(k - 8) - 4(k - 8) = 0
(k - 8)(k - 4) = 0
k = 8 or 4
The points are (3,k) and (5,6).
Given, distance = 2√2 units
Applying distance formula,
Distance = √(x2-x1)^2 + (y2-y1)^2
2√2 = √(x2-x1)^2 + (y2-y1)^2
Squaring both sides,
(2√2)^2 = [√(x2-x1)^2 + (y2-y1)^2]^2
8 = (x2-x1)^2 + (y2-y1)^2
8 = (5-3)^2 + (6-k)^2
8 = 2^2 + (6^2 - 2x6xk + k^2)
8 = 4 + 36 - 12k + k^2
8 = 40 - 12k + k^2
= k^2 - 12k + 32 = 0
On factorising,
=> k^2 - 4k - 8k + 32 = 0
=> k(k-4) -8(k-4) = 0
=> (k-4)(k-8) = 0
=> k-4 = 0 , k-8 = 0
=> k = 4 , k = 8
Joey and Nolan are each solving the equation 13x - 42 = 18 - 7x.
Joey's first step was to rewrite the equation as 20x - 42 = 18 while Nolan's first step was to rewrite the
equation as 13x = 60 - 7x.
Who is correctly applying the addition property of equality in the first step of his work?
A. Only Joey
B. Only Nolan
C. Both Joey and Nolan
D. Neither Joey nor Nolan
Answer:
First step=13x+7x=18+42
Step-by-step explanation:
13x-42=18-7x
First step
It is to collect like terms of the equation
13x+7x=18+42
20x=60
x=60/20
x=3
Simultaneous equation
Answer:
x = 5, y = 9.
Step-by-step explanation:
8^x / 2^y = 64
3^4x * (1/9)^(y -1) = 81
From the first equation
2^3x / 2^y = 2^6
2^(3x-y) = 2^6
So 3x - y = 6 ..........(1)
From the second equation:
3^4x * 9^(-(y-1)) = 3^4
3^4x * 3^2(-(y-1)) = 3^4
3^(4x+ 2(1 - y)) = 3^4
So 4x + 2(1 - y) = 4
4x - 2y = 2
2x - y = 1 .............(2)
Subtract: (1) - (2):
x = 5.
and 2(5) - y = 1
so y = 9.
Solving the simultaneous equations we get x is 5 and y is 9 .
Simultaneous equations in algebra are those that concurrently involve two or more variables, such as x and y. Even though they are solved simultaneously, the equations are known as simultaneous equations. Just these equations alone have innumerable answers.
A system of equations, often known as an equation system, is a collection of finite equations for which common solutions are sought.
The two given equations can be simplified as:
[tex]8^x \div 2^y = 64\\\\or,\frac{2^{3x}}{2^y} =2^6\\\\or, 2^{3x-y}=2^6\\\\or, 3x-y = 6[/tex]
And :
[tex]3^{4x} \times (\frac{1}{9})^{y-1}=81\\\\or, 3^{4x} \times 3^{-2(y-1)}=3^4\\\\or, 3^{4x+2-2y}=3^4\\\\or, 4x-2y = 2\\\\or,2x-y=1[/tex]
Now we can solve the two simultaneous equations :
3x - y = 6 and 2x - y = 1
Subtracting the equations we get:
x = 5
and
y = 9
Solving the simultaneous equations we get the value of x as 5 and the value of y as 9 .
To learn more about simultaneous equations visit:
brainly.com/question/16763389
#SPJ1
Find t12 term in an arithmetic progression having t3 = 10 and t10 = −4 .
Answer:
t12= -8
Step-by-step explanation:
t3
a+2d=10 (1)
t10
a+9d=-4. (2)
From (1)
a=10-2d. (3)
Sub into (3) into equ (2)
a+9d=-4
10-2d+9d=-4
10+7d=-4
7d=-4-10
7d=-14
Divide both sides by 7
d=-14/7
d= -2
10=a+2d
10=a+2(-2)
10=a-4
10+4=a
14=a
a=14
t12=a+11d
= 14+11(-2)
=14-22
= -8
t12= -8
Solve the simultaneous equation.
7a+3b=46
4a+5b=69
Answer:
a=1 and b=13
do you need the working out?
Ron had some pens. 3 8 of them were black coloured, 1 4 of them were red coloured and the rest of them were blue coloured. There were 15 blue pens. How many pens did Ron have?
Answer:
40 pens
Step-by-step explanation:
Let the total number of pens Ron had be x.
We need to find the fraction of the pen that were blue.
3/8 of them were black and 1/4 of them were red. This means that the fraction of the pens that were blue is:
1 - (3/8 + 1/4) = 1 - 5/8 = 3/8
There were 15 blue pens. This means that 3/8 of x is 15:
3/8 * x = 15
x = 15 * 8/3 = 40 pens
Ron had 40 pens.
Which one of the following is discrete data?
Answer:
Number of people in a room
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Point D is located on the segment CE. IF CD = 24 and DE = x and CE - 5x, what is the measure of segment CE?
Answer:
30Step-by-step explanation:
If point D is located on the segment CE, then point C, D and E lies on the same line i.e they are collinear. Mathematically, CD+DE = CE
Given CD = 24 and DE = x and CE = 5x, on substituting this values in the equation we have;
[tex]24+x = 5x\\5x-x = 24\\4x = 24\\x = 24/4\\x = 6[/tex]
Since CE = 5x, CE = 5(6) = 30
The measure of segment CE is 30
Find the slope of the line that passes through (10, 3) and (1, 10).
Simplify your answer and write it as a proper fraction, improper fraction, or integer.
Answer: -7/9
Step-by-step explanation:
10-3
1-10
The slope of the line is - 7/9
please see the attached picture for full solution
Hope it helps
Good luck on your assignment
Airborne Airlines Inc. has a $1,000 par value bond outstanding with 20 years to maturity. The bond carries an annual interest payment of $102 and is currently selling for $880. Airborne is in a 30 percent tax bracket. The firm wishes to know what the aftertax cost of a new bond issue is likely to be. The yield to maturity on the new issue will be the same as the yield to maturity on the old issue because the risk and maturity date will be similar.
a. Compute the yield to maturity on the old issue and use this as the yield for the new issue. (Do not round intermediate calculations. Input your answer as a percent rounded to 2 decimal places.)
b. Make the appropriate tax adjustment to determine the aftertax cost of debt. (Do not round intermediate calculations. Input your answer as a percent rounded to 2 decimal places.)
Answer:
(a) 11.64%
(b) 8.15%
Step-by-step explanation:
Airborne airlines has an annual interest of payment= $102
Principal payment= $1,000
Time to maturity= 20 years
Current price of the bond= $880
The formular for calculating the yield on maturity is
[ Annual interest payment+Principal payment-(price of the bond/number of years to maturity)] / 0.6(price of the bond) + 0.4(principal payment)
(a) [102+(1000-880)/20)]/ [0.6(880) + 0.4(1000)]
= [102+ (120/20)]/ [528+400]
= [102+6]/ 928
= 108/928
= 11.637%
= 11.64% ( to 2 decimal places)
(b) Kd= Yield(1-T)
Kd= 11.64(1-0.30)
Kd= 11.64×0.7
Kd= 8.145%
Kd= 8.15%( to 2 decimal places)
Hence the yield to maturity on the new issue is 11.64% and the aftertax cost of debt is 8.15%
Which is equivalent to v10 3/4?
Answer:
d) [tex](\sqrt[8]{(10} )^{3 x}[/tex]
Step-by-step explanation:
Step(i):-
Given [tex](\sqrt{10} )^{\frac{3 x}{4} }[/tex]
we will use formula
[tex](a)^{m n} = (a^{m} )^{n}[/tex]
[tex](\sqrt{10} )^{\frac{3 x}{4} } =( (10)^{\frac{1}{2} } )^{\frac{3 x}{4} }[/tex]
= [tex]( (10)^{\frac{1}{2} X\frac{3 x}{4} } )[/tex]
= [tex]( (10)^{\frac{3 x}{8} } )[/tex]
= [tex]((10)^{\frac{1}{8} } )^{3x}[/tex]
Step(ii):-
we will apply [tex](a)^{\frac{1}{n} } = \sqrt[n]{a}[/tex]
= [tex](\sqrt[8]{(10} )^{3 x}[/tex]
