dk how to do this :)

Answer:

Lim reag = NO        .07 mole of O2 left over

Explanation:

From the equation, you need twice as many moles of NO as O2

  2 x moles O2 =     2 * .503 moles = 1.06 moles of NO needed....you do not have enough so this is the limiting reagent    O2 will be left over

    1/2 * .866 = .433  moles of O2 used    .503 - .433 = .07  mole O2 leftover

Answer:

molecular mass of each substance

molecular mass of each substance

Explanation:

Answer:

Socratic app

Explanation:

it will help you

Answer:

Niche.

A niche is a place where an organism lives at a given time or how the organism lives there.

negative ion or anion

hope it helps...!!!

Answer:

C. None of these

Explanation:

Take a example of water

Attached structure

Based on the milligram per Kg of soil sample of each analyte, calcium ion, Ca2+ and magnesium ion, Mg2+ are both classified as macronutrients.

Soil nutrients are minerals which are found present in the soil and which are required by plants for their growth and development.

Soil nutrients can be classified based on amount needed by plants as well as the amount present in the soil into:

The mg/Kg of each analyte in the soil sample is as follows:

mass of soil sample = 2.65 g = 0.00265 kg

Calcium ion:

amount per mg/Kg of soil sample = 0.625mg/0.00265 kg

amount per mg/Kg of soil sample = 236 mg/kg

Magnesium ion:

0.00245 g = 2.45 g

amount per mg/Kg of soil sample = 2.45 mg/0.00265

amount per mg/Kg of soil sample = 924 mg/Kg

Therefore, calcium ion, Ca2+ and magnesium ion, Mg2+ are both classified as macronutrients.

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Answer:

D

Explanation:

the correct answer is D

Answer: Red supergiant.

Explanation:

The stars in group C are even more luminous than the giants. These are super giants, the largest of stars with extremely high luminosisties. A red supergiant such as Betelguese would extend beyond the orbit.

If 4.0 L of a 4.6M SrCl2 solution is diluted to 45L, the molarity of the diluted solution is 0.41M.

The molarity of a diluted solution can be calculated using the following formula:

M1V1 = M2V2

Where;

According to this question, 4.0 L of a 4.6M SrCl2 solution is diluted to 45L, the molarity of the diluted solution is calculated as follows:

4.6 × 4 = 45 × M2

18.4 = 45M2

M2 = 18.4/45

M2 = 0.41M

Therefore, if 4.0 L of a 4.6M SrCl2 solution is diluted to 45L, the molarity of the diluted solution is 0.41M.

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Answer:

b) potential energy is stored in an object, and kinetic energy is released mechanical energy that causes motion.

Explanation:

potential energy is stored because it is the possible energy of an object if a force is acted upon it. on the other hand, kinetic energy is essentially when potential energy is being acted upon or changed.

Answer: The second option

Explanation: For example, if a ball is sitting at the top of a hill, it has a lot of potential energy. If it then falls off, potential energy will turn into kinetic energy and the ball will roll down the hill.

Answer:

∆H or Enthalpy of the reaction

Explanation:

If ∆H is +ve

If ∆H is -ve

Answer:

nose

Explanation:

xde

Answer:

Ok giv me a min

Explanation:

For the excited state of Ca at the absorption of 422.7 nm light,the energy difference  is mathematically given as

E= 4.70x10-22 kJ/mol

Generally, the equation for the Energy  is mathematically given as

E = nhc / λ

Where

h= plank's constant

h= 6.625x 10-34 Js

c = speed of light

c= 3x 108 m/s

Therefore

E = 1*(6.625x 10-34 Js)( 3x 10^8 m/s) / ( 422.7x10^-9)

E= 4.70x10-22 kJ/mol

In conclusion, Energy  

E= 4.70x10-22 kJ/mol

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Answer:

True

Explanation:

Answer:

true

Explanation:

The ratio of moles of AI(NO3)3 to moles Na2CO3 in the reaction is 2:3

In the reaction 2 moles of AI(NO3)3 reacted with 3 moles Na2CO3 so the ratio of the moles is 2 is to 3 represented as 2:3

hope it helps

The calculated percentage purity of the original sample of calcium carbonate is 44%.

In the back titration of the excess acid, we neutralize the excess titrand left in a system.

We have the reaction equation;

CaCO3 + 2HCl ----> CaCl2 + H2O + CO2

To get the moles of HCl = 0.2254 M * 20/1000 L = 0.0045 moles

The reaction involving the excess acid occurs thus;

HCl + NaOH ----> NaCl + H2O

Number of moles of NaOH = 0.1041 M * 20/1000 = 0.0021 moles

We have a  1:1 hence 0.0021 moles of HCl reacted also

Number of moles of HCl that reacted with CaCO3 initially = 0.0045 moles - 0.0021 moles = 0.0024 moles

Given the stoichiometry of the reaction,  0.0012 moles of CaCO3 reacted.

Hence;

Mass of pure CaCO3 in the sample= 0.0012 moles * 100 g/mol = 0.12g

Percent purity of the sample = 0.12g/0.2719 g * 100/1

= 44%

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[tex]\large\red{\underline{\textbf{Given:-}}}[/tex]

Answer:

WHR Boilers

Explanation:

I hope this helps.

The reaction mechanims shows the sequence of steps through which a reaction occurs. The reaction mechanism for this reaction is;

step 1: NO2 + NO2 → NO + NO3 (slow)

step 2: NO3 + CO → NO2 + CO2 (fast)

We have to note that not all reactions occur in a single reactive encounter. If a reaction occurs in a single reactive encounter then it is called an elementary reaction.

The reaction mechanim shows the reaction sequence of a non elementary reaction. The correct mechanims of this reaction is shown as;

step 1: NO2 + NO2 → NO + NO3 (slow)

step 2: NO3 + CO → NO2 + CO2 (fast)

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Answer:

If temperature stays the same, the amount of carbon dioxide dissolved in the ocean would increase.

Explanation:

The carbon dioxide in the air ([tex]{\rm CO_{2}}\, (g)[/tex]) and the carbon dioxide dissolved in the ocean ([tex]{\rm CO_{2}}\, (aq)[/tex]) are in a solution equilibrium:

[tex]{\rm CO_{2}}\, (g) \rightleftharpoons {\rm CO_{2}}\, (aq)[/tex].

Assume that the concentration of carbon dioxide in the air ([tex]{\rm CO_{2}}\, (g)[/tex]) increased while temperature stayed the same.

By Le Ch[tex]^{}[/tex]atelier's Principle, the solution equilibrium [tex]{\rm CO_{2}}\, (g) \rightleftharpoons {\rm CO_{2}}\, (aq)[/tex] would shift to offset this increase in [tex]{\rm CO_{2}}\, (g)[/tex] concentration. Specifically, this equilibrium would reduce the amont of [tex]{\rm CO_{2}}\, (g)\![/tex] in the system by converting more atmospheric [tex]{\rm CO_{2}}\, (g)\!\![/tex] to [tex]{\rm CO_{2}}\, (aq)\![/tex] dissolved in the ocean. Therefore, the concentration of [tex]{\rm CO_{2}}\, (aq)\!\![/tex] dissolved in the ocean would increase.

Answer:

B . chemical. reaction

Explanation:

B chemical reaction

Answer:

The given reaction is a combustion reaction of benzene,

C

6

H

6

. From its balanced chemical equation,

2

C

6

H

6

+

15

O

2

→

12

C

O

2

+

6

H

2

O

,

the mass of carbon dioxide

(

C

O

2

)

produced from 20 grams (g) of

C

6

H

6

is determined through the molar mass of the two compounds, given by,

M

M

C

O

2

=

44.01

g

/

m

o

l

M

M

C

6

H

6

=

78.11

g

/

m

o

l

and their mole ratio:

12

m

o

l

C

O

2

2

m

o

l

C

6

H

6

→

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

With this,

m

a

s

s

o

f

C

O

2

=

(

20

g

C

6

H

6

)

(

1

m

o

l

C

6

H

6

78.11

g

C

6

H

6

)

(

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

)

(

44.01

g

C

O

2

1

m

o

l

C

O

2

)

=

(

20

)

(

6

)

(

44.01

)

g

C

O

2

78.11

=

5281.2

g

C

O

2

78.11

m

a

s

s

o

f

C

O

2

=

67.6

g

C

O

2

Therefore, the mass in grams of

C

O

2

formed from 20 grams of

C

6

H

6

is

67.6

g

C

O

2

.

it is a problem of app

The grams of C₆H₆ needed to produce 25 g of CO₂ are 7.38g.

Avogadro's number is the number of units in one mole of any substance and equals to 6.02214076 × 10²³. The units can be electrons, atoms, ions, or molecules.

No. of moles is defined as a particular no. of particles that we can calculate with the help of Avogadro’s number.

Mass of a particular product is also find out by stoichiometry of a reaction as per the no. of mole given in the reaction.

Given,

Mass of CO₂ = 25g

2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O

As per reaction, 156g of C₆H₆ gives - 528g of CO₂

0.295g of C₆H₆ gives - 1g of CO₂

0.295 × 25 g of C₆H₆ gives - 25g of CO₂ = 7.38g C₆H₆

Therefore, The grams of C₆H₆ needed to produce 25 g of CO₂ are 7.38g.

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Answer:

B

Explanation:

I think that the anserw is B.

Answer:

a. Lead (Pb)

Am 100% sure

Hope it helps

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The freezing points of each of the solutions are as follows;

0.100 m K2S -   - 0.558oC

21.5 g of CuCl2 in 4.50 * 102 g water -   -2oC

5.5% NaNO3 by mass (in water)​ -     - 2.6oC

The freezing point is the point at which liquid changes to solid. Let us now look at the freezing point of each solution.

a)

Since;

ΔT = K m i

K = 1.86 oC m-1

m = 0.100 m

i = 3

ΔT =   1.86 oC m-1 * 0.100 m * 3 = 0.558oC

Freezing point = 0oC - 0.558oC =  - 0.558oC

b) Number of moles of CuCl2 = 21.5 g/134.45 g/mol = 0.16 moles

molality = 0.16 moles/0.45 Kg = 0.36 m

ΔT = K m i

ΔT =  1.86 oC m-1 * 0.36 m * 3 = 2oC

Freezing point = 0oC - 2 = -2oC

c) Number of moles of NaNO3 = 5.5g/85 g/mol = 0.065 moles

molality of the solution =  0.065 moles/0.0945 Kg = 0.69 m

ΔT =  1.86 oC m-1 * 0.69 m * 2 = 2.6oC

Freezing point = 0oC - 2.6oC = - 2.6oC

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Answer:

D

Explanation:

weathering is the breaking down of physical components through unfavorable weather conditions which can likely cause a change in physical properties