Choose the correct graph of the following condition. {(x, y) : x - y6}
The correct graph of the following condition. {(x, y) : x - y6} is depicted in the graph attached.
What is a graph?
A graph is a diagram showing the relation between variable quantities each measured along one of a pair of axes at right angles.
In this case, the correct graph of the following condition. {(x, y) : x - y6} is depicted in the graph attached.
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This is the full question
Answer:
< $0 --------------$35------ $50>
Step-by-step explanation:
I see it's still the same, the maximum discount can be put off is still $50
and you can find that out by discount 30% off 50 to get $35 :)
< $0 --------------$35------ $50>
Help me with this piecewise function!
Answer:
According to the given function, the value of h(-1) is -1, h(-0.5) is 0 and h(1) is 1.
Step-by-step explanation:
The given function says that:
If the range of the values of x is x∈(-2,-1], then the value of the function is -1.
If the range of the values of x is x∈(-1,0], then the value of the function is 0.
If the range of the values of x is x∈(0,1], then the value of the function is 1.
If the range of the values of x is x∈(1,2], then the value of the function is 2.
In the first case, we have x = -1. This satisfies the first condition. So accordingly, the value that the function will give is -1.
In the second case, we have x = -0.5. This satisfies the second condition. So accordingly, the value that the function will give is 0.
In the third case, we have x = 1. This satisfies the third condition. So accordingly, the value that the function will give is 1.
So, h(-1) = -1, h(-0.5) = 0 and h(1) = 1.
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A person buys a used car with a down payment of $1,200 and makes monthly payments of $275 for 3 years.What is the total amount of the person pays for the car?PLEASE EXPLAIN
A.$2,025
B.$9,900
C.11,100
D.13,500
Answer:
2025 $
Step-by-step explanation:
275 multiply 3 +1200
Answer:
A.$2,025
Step-by-step explanation:
$275 x 3 years + $1,200
= $2,025
An equivalent ratio to the tape diagram shown is
to pls i need a answer
An equivalent ratio to the tape diagram shown is 1 to 2
How to determine the equivalent ratio?From the tape diagram, we have:
Red = 2
Blue = 4
Express as a ratio
Red : Blue = 2 : 4
Divide by 2
Red : Blue = 1 : 2
Hence, an equivalent ratio to the tape diagram shown is 1 to 2
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Guys i just cant do this my brain doesnt work right now
Answer:
[tex] \frac{1}{4} [/tex]
Step-by-step explanation:
To find the gradient of the graph, we use the formula,
[tex]gradient \: (m) = \frac{(y2 - y1)}{(x2 - x1)} [/tex]
From the graph, we obtain values for x and y
x1 = 4, x2 = 8
y1 = 2, y2 = 3
Substitute the values into our formula.
[tex]m \: = \frac{(3 - 2)}{(8 - 4)} \\ = \frac{1}{4} [/tex]
Therefore, the gradient, m, =
[tex] \frac{1}{4} [/tex]
Note:-
Use the above formula when determining the gradient of the graph.Obtain the values of x and y then subtract [∆y] and [∆x].Divide the twoWrite an equation in point-slope form of the line that passes through the given point and with the given slope m
(-9,2); m=6
The equation is [tex]\boxed{y-2=6(x+9)}[/tex].
which expression is equivalent to...
Answer:
[tex]\frac{y^{12} }{5}[/tex]Step-by-step explanation:
1) Cancel [tex]x^5[/tex].
[tex]\frac{9y^{16} }{45y^4}[/tex]
2) Take out the constants.
[tex]\frac{9}{45} \times\frac{y^{16} }{y^4}[/tex]
3) Simplify [tex]\frac{9}{45}[/tex] to [tex]\frac{1}{5}[/tex].
[tex]\frac{1}{5} \times\frac{y^{16} }{y^4}[/tex]
4) Simplify.
[tex]\frac{y^{16} }{5y^4}[/tex]
5) Use Quotient Rule: Use Quotient Rule: [tex]\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}[/tex].
[tex]\frac{{y}^{16-4}}{5}[/tex]
6) Simplify [tex]16-4[/tex] to [tex]12[/tex].
[tex]\frac{y^{12} }{5}[/tex]
Algebra 2 help please
Blank 1: 3
Blank 2: 27
Blank 3: 21
you have to distribute the three to everything inside the parenthesis, and because it's directly in front of the parenthesis it's being multiplied.
3(x - 9) = 3x - 27
Now you need to isolate the y, in this e ample you need to add 6 to both sides
the final equation should be:
y = 3x - 21
An elephant went 119 km moving 42 km/h how many hours did the journey take?
2 1/6
2 1/2
2 5/6
Answer:
1 HR ---> 42 km
? .----> 119 km
119 * 1/42
2.833
Answer:
[tex]\boxed {2 \frac{5}{6}}[/tex]
Step-by-step explanation:
Formula used :
[tex]\boxed {Time = \frac{Distance}{Speed}}[/tex]
Solving :
Time = 119/42
Time = 17/6
Time = 2 5/6 hours
help please
what is
Option A. is correct for the given condition.
Lets solve it through steps of range and functions,
First of all, Solve the equation:
[tex]f(x) = |x|+5[/tex]
[tex]= > x = -5[/tex] (1)
[tex]= > x = 5[/tex] (2)
So these would be the ranges of X in between 5 and -5.
Hence option A. [tex]R{f(x)eR [f(x) < 5}[/tex] is correct.
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Using the diagram, if angle 3 + angle 4 is a straight line then what is the total
measure?
Answer: 180 degrees
Step-by-step explanation:
Angles on a line add to 180 degrees since they form a straight angle.
What is the solution to 3(–3x + 9) = −18?
O x = -5
O x = 5 or x=1
O x = -5 or x = 1
no solution
Answer:
x = 5 (If solved algebraically)
No Solution (If the parentheses are absolute value lines)
Step-by-step explanation:
Result when solving this way: 3|-3x + 9| = -18
1) Divide both sides by 3
|-3x + 9| = -18/3
2) Simplify 18/3 to 6
|-3x + 9| = -6
3) Break down the problem into these 2 equations.
-3x + 9 = -6
- (-3x + 9) = -6
4) Solve the 1st equation: -3x + 9 = -6
- Subtract 1 from both sides.
-3x = -6 - 9
-Simplify -6 - 9 to -15.
-3x = -15
-Divide both sides by -3.
x = -15/-3
- Two negatives make a positive.
x = 15/3
- Simplify 15/3 to 5.
x = 5
6) Solve the 2nd equation: - (-3x+ 9) = -6
1 - Remove parentheses
3x - 9 = -6
2 - Add 9 to both sides
3x = -6 + 9
3 - Simplify -6 + 9 to 3.
3x = 3
- Divide both sides by 3.
x = 1
6) Collect all solutions.
x = 1,5
7) Check solution.
When x = 1, the original equation 3|-3x + 9| = -18 does not hold true.
We will drop x = 1 from the solution set.
8) Check solution.
When x = 5, the original equation 3|-3x + 9| = -18 does not hold true.
We will drop x = 5 from the solution set.
9) Therefore,
No solution exists.
Result when solving algebraically:
Simplifying
3(-3x + 9) = -18
Reorder the terms:
3(9 + -3x) = -18
(9 * 3 + -3x * 3) = -18
(27 + -9x) = -18
Solving
27 + -9x = -18
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-27' to each side of the equation.
27 + -27 + -9x = -18 + -27
Combine like terms: 27 + -27 = 0
0 + -9x = -18 + -27
-9x = -18 + -27
Combine like terms: -18 + -27 = -45
-9x = -45
Divide each side by '-9'.
x = 5
Simplifying
x = 5
A
Find the value of x.
6
X
B
D
x = [?]
8
4
C
Answer:
x = 3
Step-by-step explanation:
8/2 = 4
6/2 = 3
x = 3
An entertainment company is opening a theme park in a nearby city. They are in the process of designing the theatre where a water show will take place. The following design is already under construction and will house the dolphins that perform in the show:
Main Show Tank Calculation:
The main show tank has a radius of 70 feet and forms a quarter sphere where the bottom of the pool is spherical and the top of the pool is flat. (Imagine cutting a sphere in half vertically and then cutting it in half horizontally.) What is the volume of the quarter-sphere shaped tank? Round your answer to the nearest whole number. You must explain your answer using words, and you must show all work and calculations to receive credit.
Holding Tank Calculations:
The holding tanks are congruent. Each is in the shape of a cylinder that has been cut in half vertically. The bottom of each tank is a curved surface and the top of the pool is a flat surface. What is the volume of both tanks if the radius of tank #1 is 35 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations to receive credit.
You must show all steps and provide any evidence needed in your solution to receive full credit.
The company is building a scale model of the theater’s main show tank for an investor's presentation. Each dimension will be made one sixth of the original dimension to accommodate the mock-up in the presentation room. What is the volume of the smaller mock-up tank?
Using the information from above answer the following question by filling in the blank: The volume of the original main show tank is ____% of the mock-up of the tank.
1) The volume of the quarter sphere shaped tank is; V = 20510 ft³
2) The volume of the smaller mock-up tank is; 230790 ft³
How to find the area and volume of a composite shape?1) The volume of the quarter sphere shaped tank is;
V = ⁴/₃πr²
V = ⁴/₃π * 70 * 70
V = 20510 ft³
2) We multiply dimensions by 2 not radius to make 1 whole cylinder. Thus
r = 35 feet remains the same as radius can only be half of a joined circle,
Since vertically cut, we have;
h = 125 * 2 = 250ft
Let's find the Area;
A = πr²
A = π * 35 * 35
A = Surface Area = 3846.5 ft²
Volume = Surface area * h
V = 3846.5 * 120 = 461580 combined.
For each; V = 461580/2 = 230790 ft³
3) Volume of smaller mock-up tank is;
V = (1/6) * 20510
V = 3418.33 ft³
4) 5/6 * 20510 = 17091.66 ft³
For the larger tank the increase is 17092 ft rounded up (0.165 value) of that of the smaller mock up tank. Therefore percentage is 1/6 = 16.67% and 5/6 = 83.33%
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This is a lengthy math problem. Help please! Thank you
Step-by-step explanation:
look at the attached and just plot the data. S on the x-axis and s(x) on the y-axis.
Please answer the question down below!
Answer:
144°Step-by-step explanation:
regular decagon = all side equal and all angles congruent, so your answer is 144°
Given: m∠ELG = 124°
Prove: x = 28
3 lines are shown. A line with points D, L, G intersects a line with points E, L, H at point L. Another line extends from point L to point F between angle E L G. Angle D L E is (2 x) degrees.
Answer:
By using opposite angles of two intersecting straight lines are congruent we proved that x = 28°
Step-by-step explanation:
Opposite angles of two intersecting straight lines are congruent
Therefore ∠DLE = ∠GLH
Here ∠DLE = 2x = ∠GLH
Sum of all angles on a straight line is 180°
Therefore ∠ELG + ∠GLH = 180°
Given that ∠ELG = 124°
124° + ∠GLH = 180°
124° + 2x = 180°
2x = 180° - 124°
2x = 56°
x = 28°
hence proved that x = 28°
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Help please I need it now!
Answer: [tex]\sum^{7}_{n=1} (-2+9n)[/tex]
Step-by-step explanation:
This is an arithmetic series with first term 7 and common difference 9, so the general formula for the nth term of the sequence is [tex]7+9(n-1)=7+9n-9=-2+9n[/tex].
The sequence has 7 terms, so the sigma notation is:
[tex]\sum^{7}_{n=1} (-2+9n)[/tex]
The table shows the probabilities of certain prizes in a restaurant’s contest where the first 100 customers are winners.
A 2-column table with 6 rows. The first column is labeled prize with entries 1 dollar drink, 5 dollar meal, 5 dollar gift card, 10 dollar gift card, 20 dollar gift card, 100 dollar gift card. The second column is labeled number of prizes with entries 44, 25, 16, 10, 5, 1.
How does the $100 gift card affect the measure of center of the data?
It increases the mean value of the prizes.
It decreases the mean value of the prizes.
It increases the median value of the prizes.
It decreases the median value of the prizes.
A mean is an arithmetic average of a set of observations. The correct option is A.
What is Mean?A mean is an arithmetic average of a set of observations. it is given by the formula,
Mean = (Sum of observations)/Number of observations
Since the median is the middle value of the given data set, therefore, the median will not be changed for the given data set. But since the mean is the arithmetic average, therefore, the $100 gift will increase the mean value of the prizes.
Hence, the correct option is A.
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Answer:
this is the anwser
this
A vehicle purchased for $20,700 depreciates at a constant rate of 4%. Determine the approximate value of the vehicle 15 years after purchase.
The approximate value of the vehicle 15 years after purchase is $11,221.19.
What is the approximate value of the vehicle 15 years after purchase?Depreciation is when the value of an asset declines with the passage of time as a result of wear and tear.
Value of the car = purchase price x (1 - rate of decline)^number of years
20,700 x (1 - 0.04)^15 = $11,221.19
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The graphs below have the same shape. What is the equation of the red graph? g(x) = A. g(x)=2^x+3-2 B. 2^x-3-2 C. 2^x-2-3 D. g(x)=^x+2-3
The equation of the red graph is g(x)=^x+2-3.
Since the upscaling in the y-axis is not the main focus of this equation (being g(x) and not g(y)), the change is not applied to the x-axis.
What is the equation of the graph?
The y-intercept and the slope in order to write the equation in y-intercept (y=mx+b) form. The slope is the change in y over the change in x.
Hence, we can rule out (-3)^2 and (x+3)^2 since they apply changes to the x-axis.
Finally, since this is an upscaling of the y-value on the y-axis, the answer is x^2 + 3 and not x^2 - 3.
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-750 DEGREE TO RADIAN
Question 18 25
f(x) = 2x
g(x) = 4x + 1
Find
() (2). Include any restrictions on the domain.
A.
(4) (x) = 477³¹, x ≥ 0
○ B. ( 4 ) (x) = ¹⁄⁄², ¤ / 0
4c-1
x
O c. (1) (₂) -
O D. (5)(x) =
✓/2T
55-1
2,² / 1
2 / -4
Answer: D
Step-by-step explanation:
[tex]\left(\frac{f(x)}{g(x)} \right)=\frac{f(x)}{g(x)}=\frac{\sqrt[3]{2x}}{4x+1}[/tex].
This eliminates A and B.
Also, the domain excludes when the denominator equals 0, which in this case, makes the answer D
Put the equation y+x^2-10+16 in the form y=(x-h)^2+k
Answer:
Step-by-step explanation:
hello :
y=x²-10x+16 in the form y=(x-h)²+k
y= x²-2(5)(x)+16
y = x²-2(5)(x)+5²-9
y= (x-5)²-9 when h=5 and k = -9
Determine the Theorem or Postulate that proves triangle
congruence. If the triangles cannot be proven congruent,
choose "not congruent."
Answer:
SSS theorem
Step-by-step explanation:
It is indicated in the image that 2 sides of the triangles are congruent, and the third side is shared, which makes the third side automatically congruent as well. Therefore, we can use the side-side-side theorem to prove that the triangles are congruent.
what is the average daily balance for the February 1-28 billing period in the table?
A radioactive substance decays from 90 mg to 12.6 mg in 29 years according to the exponential decay model y=ae−bx , where a is the initial amount and y is the amount remaining after x years.
Find the b -value.
Use the EXACT b -value to write the exponential decay model for this substance with initial amount 90 mg, then use that model to find the half-life.
Find the half-life.
The half life of the radioactive substance is 10.22 years.
What is Half Life ?Half Life is the amount of time needed by the radioactive substance to reduce to its half concentration (as compared to the initial concentration).
It is given that
y = ae⁻ᵇˣ
here a is the initial amount , y is the amount remaining after x years
a = 90mg at x =0
Value of y = 12.6 mg at x = 29 years
On substitution of value
12.6 = 90 e⁻²⁹ᵇ
0.14 = e⁻²⁹ᵇ
b = 0.0678
The equation is
[tex]\rm y = 90 e^{-0.0678 * x}\\[/tex]
Half life is when the concentration is reduced to half
On 1st half life , the concentration = 90/2 = 45 mg
[tex]\rm 45 = 90 e^{-0.0678 * x}\\[/tex]
x = 10.22 years
Therefore the half life of the radioactive substance is 10.22 years.
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A number is equal to the sum of half a second number and 3. The first number is also equal to the sum of one- quarter of the second number and 5. The situation can be represented by using the graph below, where x represents the second number. 16 NO 8 K 3₂ 5 2 4 st 6 8 10 12 14 16 Which equations represent the situation? Hurry
Evaluate each expression for r=9 n t=14 enter in your numerical answer
Answer:
1764
Step-by-step explanation:
[tex]from \: the \: question \: rt {}^{2} \\ were \: r =9 \\ and \: t = 14 \\ rt {}^{2} = 9 \times (14) {}^{2} = 9 \times 196 = 1764[/tex]
Hii!
__________________________________________________________
[tex]\rightsquigarrow\circ\boldsymbol{Answer.}\circ \leftharpoonup[/tex]
1764
[tex]\rightsquigarrow\circ\boldsymbol{Explanation.}\circ\leftharpoonup[/tex]
Stick in the values: 9 for r and 14 for t, and simplify.
[tex]\twoheadrightarrow\sf 9\cdot14^2}[/tex]
[tex]\bullet[/tex] Square 14 first
[tex]\twoheadrightarrow\sf 9\cdot196}[/tex]
[tex]\bullet[/tex] Multiply the numbers
[tex]\twoheadrightarrow\sf 1764}[/tex]
[tex]\bullet[/tex] Great job! We found the answer
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Hope that this helped! Best wishes.
[tex]\textsl{Reach far. Aim high. Dream big.}\\\boldsymbol{-Greetings!-}[/tex]
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