_____ electrons are the most important electrons to an atom .

Answer:

The magnitude of the velocity is approximately 11.45 units

Explanation:

Since they give us the x and y components of the vector velocity, we can find its magnitude via the Pythagorean theorem:

[tex]|v|=\sqrt{9.5^2+(-6.4)^2} \approx 11.45[/tex]

Answer:

I think its n u c l e a r e n e r g y.

Answer:

It's not -7.6

Explanation:

All I can tell you

Answer:

Protons

Explanation:

The Proton is one of the subatomic particles that are found in the nucleus of an atom. The protons are positively charged. They have an electric charge of 1.6 * 10^-19 C. Protons have an approximately 1 atomic mass unit, or otherwise called, 1 amu.

One or more protons, at least, are found in every nucleus if an atom, as they are an essential and very necessary part of the nucleus. Ernest Rutherford, in 1920, named protons, proton

Answer: Regardless of their weight, before opening their parachutes, the guys fell at the same velocity.

According to the data, the acceleration due to gravity is 9.8 m/s/s

Opening the parachutes provided air resistance and changed their velocity.

Explanation:

When in free fall, mass does not affect the speed of moving objects (only gravitational force is acting upon it).

If you take a look at the data, you can see that the velocity is increasing at a constant rate in intervals of 9.8. This is the acceleration which makes sense because acceleration is the change of velocity divided by time.

Think about it: parachutes slow down the object that is falling because it creates a barrier between the object falling and the gravitational force it encounters. The change in the effects of the gravitational force will alter the velocity.

I hope this was helpful. Have a nice day!

Answer: C. 7,350 J

Explanation:

Just did it in Apex

The crate's potential energy at this point will be 7,350 J.Option C is correct.

The potential energy is the energy by the virtue of the position in the system. It varies with the height of the system. The potential energy unit is the joule (j).

The given data in the problem is;

m is the mass of the crate= 75 kg

h is the height = 10 m.

a is the acceleration due to gravity = 9.8 m/s²

P is the potential energy of the crate to be found as;

[tex]\rm PE = mgh \\\\ \rm PE =75 \times 9.81 \times 10 \\\\ PE=7350 \ J[/tex]

The potential energy at this point will be 7,350 J.

Hence option C is correct.

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Answer: D (2000 J)

Explanation: p= 200 W

t= 10 s

E=pt

E=200 W * 10s

E= 2000 J

Answer:

it is D.

Explanation:

Answer:

* I will look at the range of both, such as 100-5 = 95 and 94+4=98. Since the ranges overlap, I can conclude that they are the same within uncertainty.

* I willl draw a dot-and-whisker plot for both. Since they overlap, I can conclude that they are equal within the uncertainty

Explanation:

The value of all physical measurement has an uncertainty, so it is within a range of values, in this case we must compare the range of values ​​of the resistors

The nominal value is 100 ± 5 Ω

therefore its range of possible values ​​is between

             95 <= R <= 105

For the experimentally measured value

          88 <= R <= 96

as the values ​​overlap we must conclude that they are the same.

When reviewing the different options we have two statements that are correct

* I will look at the range of both, such as 100-5 = 95 and 94+4=98. Since the ranges overlap, I can conclude that they are the same within uncertainty.

* I willl draw a dot-and-whisker plot for both. Since they overlap, I can conclude that they are equal within the uncertainty

Answer:

The equation is missing in the question. The equation is [tex]$10 m + 5(m/s^2)t^2+3(m/s^3)t^3$[/tex]

a). [tex]$v=10 t +9t^2$[/tex] , the horse will not turn.

b). a(t) = 10 + 18t

Explanation:

Given :

[tex]$x(t)=10 m + 5(m/s^2)t^2+3(m/s^3)t^3$[/tex]

∴ At t =0, x = 10 m

a). Velocity as a function of time

[tex]$v = \frac{dx}{dt} $[/tex]

  = [tex]$10 t +9t^2$[/tex]

Turning velocity must be zero.

v(t) = 0

[tex]$10 t +9t^2=0$[/tex]

[tex]$\therefore t = 0 \text{ or}\ t =-\frac{10}{9}$[/tex]

Taking the positive value of time.

The horse will not turn.

b). Acceleration as a function of time.

[tex]$a(t)=\frac{dv}{dt}$[/tex]

     = 10 + 18t

∴ a(t) = 10 + 18t

Answer:

7.05479

Explanation:

Answer:

200 grams:     ounces:7.05479239 that's the answer

Explanation:

Answer:

a) 5000 g

b) 5250 g

c) 5150 g

Explanation:

For easier calculations, the formulas will be converted from g/cm³ to kg/m³, and then back when we're done.

Density of pure water is 1 g/cm³

1 g/cm³ = 1 * 0.001/0.000001

1 g/cm³ = 1000 kg/m³, and thus,

Density of pure blood

1.05 g/cm³ = 1050 kg/m³

Density of seawater

1.03 g/cm³ = 1030 kg/m³

Recall that, Density = mass / volume, and as such, mass = density * volume.

Converting our volume from L to m³

1 m³ = 1000 L, and as such

1 L = 0.001 m³

5 L = 0.005 m³

Mass of pure water = 1000 * 0.005

Mass of pure water = 5 kg

Mass of pure blood = 1050 * 0.005

Mass of pure blood = 5.25 kg

Mass of seawater = 1030 * 0.005

Mass of seawater = 5.15 kg

Converting these masses back to g, we have

Mass of pure water = 5 kg * 1000 g

Mass of pure water = 5000 g

Mass of pure blood = 5.25 kg * 1000 g

Mass of pure blood = 5250 g

Mass of seawater = 5.15 kg * 1000 g

Mass of seawater = 5150 g

Answer:

When moisture is removed from air, its density increases. The speed of sound in a humid air is inversely proportional to the square root of its density. Therefore, the speed of sound in moist air is humidity increases, the velocity of sound increase and vice-versa.

Hope it helps :)

Answer:

Explanation:

Using the equation of motion expressed as v = u+gt where;

v is the  final velocity of the ball

u is the initial velocity

g is the acceleration due to gravity

t is the time taken

Given

u = 9m/s

v = 0m/s

t = 6.4s

Required

acceleration due to gravity g

Since the rock is thrown up, g will be a negative value.

v = u+(-g)t

0 = 9-6.4g

-9 = -6.4g

6.4g = 9

divide both sides by 6.4

6.4g/6.4 = 9/6.4

g = 1.40625m/s²

Hence the acceleration due to gravity on the planet is  1.40625m/s²

Answer:

i try B

Explanation:

Answer:

9.1m/s  

Explanation:

Nate throws a straight ball to Kayla who is standing at a balcony 3.8m above Nate

When she catches the ball, it is still moving upward with a speed of 2.8m/s

v = 2.8m/s

u = ?

s = 3.8m

a= -9.8(The acceleration has a negative sign because the speed of the ball is declining)    

Therefore the initial speed at which Nate threw the ball can be calculated as follows

v^2= u^2 + 2as

2.8^2= u^2 + 2(-9.8)(3.8)

7.84= u^2 + (-74.48)

7.84= u^2 - 74.48

u^2= 7.84 + 74.48

u^2= 82.32

u= √82.32

u = 9.1m/s    

Hence the initial speed at which Nate threw the ball is 9.1m/s

Answer: Always accelerates in a downward direction

Explanation: Gravity is pulling the ball downward

Answer:

[tex]H_1 =39.05 \ m[/tex] OR [tex]H_2 =14.5 \ m)[/tex]

Explanation:

From the question we are told that

The constant speed of the balloon is [tex]v = 6.60 \ m/s[/tex]

The height of the balloon is [tex]h = 11.0 \ m[/tex]

The initial speed of the pellet is [tex]u = 30 \ m/s[/tex]

Generally the height of the balloon at the point it is the same altitude with the pellet is mathematically represented as

[tex]H = h + v * (t)[/tex]

Note: vt is the distance covered by the balloon before the pellet got to it

Generally the height of the pellet when it is the same height with the balloon is mathematically represented using kinematics equation

[tex]s = ut + \frac{1}{2} gt^2[/tex]

So

H = s

=> [tex] ut + \frac{1}{2} gt^2 = h + v * (t)[/tex]

=> [tex] 30t + \frac{1}{2} *( -9.8)t^2 = 11 + 6.60t[/tex]

=> [tex] 4.9t^2 -23.4t + 11= 0[/tex]

using the quadratic formula to solve the above equation

From the quadratic formula calculation

[tex]t_1 = 4.25 \ s[/tex]

   OR

     [tex]t_1 =  0.529  \  s[/tex]

So the height of this two place above the ground is mathematically evaluated as

[tex]H_1 = h + v * (4.25)[/tex]

[tex]H_1 = 11 + 6.60 * (4.25)[/tex]

[tex]H_1 =39.05 \ m[/tex]

OR

[tex]H_2 = h + v * ( 0.529)[/tex]

[tex]H_2 = 11 + 6.60 * (0.529)[/tex]

       [tex]H_2  =14.5 \  m)[/tex]

Explain how they interact with each other. I'm not a chem genius but taht would make the most sense.

Hope it helps! Comment if you have any questions and have an amazing day!

Answer:

60 km/hr

Explanation:

220 km is covered at 92km/hr in the round trip

There is 1 hour lunch break

During the return of the round trip 220 km is covered at 55km/hr

The first step is to calculate the total distance

= 220km + 220km

= 440km

The time spent during the entire round trip can be calculated as follows

= (220/92) + 1 + (220/55)

= 2.3913 + 1 + 4

= 7.3913

Therefore the average speed can be calculated as follows

= distance/ time

= 440/7.3913

= 59.52

= 60km/hr (approximated to 2 significant figures)

Hence the average speed is 60 km/hr

Answer:

a) The acceleration of the sprinter is 6.521 meters per square second, b) The acceleration of 84512.16 kilometers per square hour.

Explanation:

Note: Statement is incomplete, complete description of the problem is: A sprinter accelerates from rest to [tex]9.00\,\frac{m}{s}[/tex] in 1.38 seconds. What is his acceleration in a. [tex]\frac{m}{s^{2}}[/tex] and b. [tex]\frac{km}{h^{2}}[/tex]?

a) We assume that sprinter accelerates uniformly, so that acceleration ([tex]a[/tex]), measured in meters per square second, can be obtained from this kinematic expression as function of initial and final velocities ([tex]v_{o}[/tex], [tex]v[/tex]), measured in meters per second, and time ([tex]t[/tex]), measured in seconds, as well.

[tex]v = v_{o} + a\cdot t[/tex]

[tex]a = \frac{v-v_{o}}{t}[/tex]

If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v = 9\,\frac{m}{s}[/tex] and [tex]t = 1.38\,s[/tex], the acceleration experimented by the sprinter is:

[tex]a = \frac{9\,\frac{m}{s}-0\,\frac{m}{s} }{1.38\,s}[/tex]

[tex]a = 6.521\,\frac{m}{s^{2}}[/tex]

The acceleration of the sprinter is 6.521 meters per square second.

b) If we know that a hour is equivalent to 3600 seconds and a kilometer is equivalent to 1000 meters, the result of the previous item is converted by using two consecutive unit conversions:

[tex]a = \left(6.521\,\frac{m}{s^{2}} \right)\cdot \left(\frac{1}{1000}\,\frac{km}{m} \right)\cdot \left(3600^{2}\,\frac{s^{2}}{h^{2}} \right)[/tex]

[tex]a = 84512.16\,\frac{km}{h^{2}}[/tex]

The acceleration of 84512.16 kilometers per square hour.

Answer:

The voltage drop across the wire is 2 V

Explanation:

Given;

length of wire, L = 10 m

current density, I/A, μ = 4 x 10⁶ (A/m²)

wire conductivity, σ = 2 x 10⁷ (S/m)

The resistivity of wire is given by;

[tex]\rho = \frac{RA}{L} \\\\But \ R = V/I\\\\\rho = \frac{VA}{IL}[/tex]

Conductivity, σ = ¹/ρ

[tex]\sigma = \frac{IL}{VA}\\ \\V = \frac{IL}{ A \sigma}\\\\V = (\frac{I}{A})\frac{L}{\sigma}\\ \\V = (\mu)\frac{L}{\sigma}\\\\V = (4*10^{6} )*\frac{10}{2*10^{7} } \\\\V = 2 \ V[/tex]

Therefore, the voltage drop across the wire is 2 V

Answer:

in pretty sure the last one

The qualities of objects do gravity depend on Each object's mass and the distance between them. Hence the correct option is (4).

Gravity is the force of attraction between two objects with mass. The strength of the gravitational force depends on the mass of each object and the distance between them.

The mass of an object refers to the amount of matter it contains. The greater the mass of an object, the stronger its gravitational pull.

The distance between two objects is also a crucial factor. The gravitational force weakens as the distance between the objects increases. In other words, the force of gravity decreases with increasing distance.

So, the two qualities that gravity depends on are each object's mass and the distance between them.

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Answer:

A. The potential difference is given as

V =q/C=0.146uC/240pF

608.33 V

B) The area of each plate is

A =Cd/eo =9.9525*10^-3m ²

C) the electric field magnitude between the plates=V/d

608.33/0.367mm

=1.657x 10^6 N/C

D) The surface-charge density on each plate=q/A

0.146uC/9.9525 x 10^-3m ²

=1.466 x 10^-5 C/m²

Answer:

The equation which describes conservation of charge is [tex]Q_{initial} - Q_{final } = 0[/tex]

Explanation:

The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.

let the sum of initial charges = [tex]Q_{initial}[/tex]

let the sum of the final charges = [tex]Q_{final}[/tex]

[tex]Q_{initial } = Q_{final}\\\\Q_{initial } - Q_{final} = 0[/tex]

Therefore, the equation which describes conservation of charge is [tex]Q_{initial} - Q_{final } = 0[/tex]

Answer:

[tex]Q_{initial}-Q_{final}=0[/tex]

Explanation:

According to the conservation of charge "Charge can neither be created nor destoryed". This line means the net amount of charges remain conserved, no matter what happens.

Equation will be of the form:

Initial Charge =Final Charge

It can also be written as:

Initial Charge- Final Charge=0

Let Q be the charge:

[tex]Q_{initial}-Q_{final}=0[/tex]

The above equation describes conservation of charge.

Answer:

100 mph.

Explanation:

Given that,

Distance covered by an object is 500 miles in 5 hours.

We need to find the average velocity of the object. It can be given by :

[tex]v=\dfrac{d}{t}\\\\v=\dfrac{500\ \text{miles}}{5\ \text{hour}}\\\\v=100\ \text{mph}[/tex]

Hence, the average velocity of the object is 100 mph.

Answer:

246ft/min

Explanation:

In this problem we are faced with unit conversion.

We are expected to convert from km/h to ft/min

Given that

1.00 m = 3.28 ft

1km(1000m)= 3280 ft

But we need to convert 4.5km to ft

Hence in ft 4.5km= 3280*4.5

= 14760ft

We now convert hour to minutes

60min make 1 hour

Therefore the convert form km/h to ft/min is

= 14760/60= 246ft/min

The answer is 246ft/min

Answer:

B

Explanation:

I think this is right.

If it is Good luck!

The controlled experiment includes a control group and an experiment group, this statement describes a controlled experiment, therefore the correct answer is option B.

Scientific discovery is the method of finding solutions through in-depth analysis and discovering them through the outcomes of experiments.

True experimental outcomes that can be backed up by data are incredibly important to scientific inquiry.

A regulated investigation where all sensors to measure have been held constant and the scientific element is utilized as a factor associated.

Since the statement depicts a controlled experiment with a control group and an experiment group, option B is the appropriate response.

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Answer:

a) 28877 AU

b) 1.795 sec

Explanation:

Time it took the radio signal to reach earth = 4 hours = 4 x 3600 = 14400 s

speed of radio signal = speed of vacuum speed of light  = 3 x 10^8 m/s

Distance traveled by this signal = speed x time

distance = 3 x 10^8 x 14400 = 4.32 x 10^12 m

One Astronomic unit AU is the distance between the Earth and the sun and it is approximately equal to 1.496 x 10^8 m

The distance traveled by the signal in AU = (4.32 x 10^12)/(1.496 x 10^8) = 28877 AU

b) The minimum separation between Earth and Mars = 0.36 AU

This distance = 0.36 x 1.496 x 10^8 = 538560000 m

Time that will be taken for a radio signal to travel this distance = distance/speed

==> 538560000/(3 x 10^8) = 1.795 sec