When the experimental measurements diverge at very low values of the voltages. When the ratio of current to saturated current is very small. That is, i/I less than or equal to 1/100. When there is a finite current at Voltage
V = 0
Diffusion will have influence on current - voltage curve in the working electrode which is ionization detector.
The estimation under set of conditions that is possible, despite the spherical shape of the working electrode, to use linear diffusion equations to theoretically predict the current vs voltage curve expected in this experiment will be:
When the experimental measurements diverge at very low values of the voltageswhen the ratio of current to saturated current is very small. That is, i/I less than or equal to 1/100When there is a finite current at Voltage V = 0Where
i = electric current
I = saturated current
V = voltage supplied
The curve expected will therefore give exponential curve from positive to negative domain because of the diffusion of ions from different directions
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Two 4 kg blocks hang from a rope that passes over two frictionless pulleys . What is the tension in the horizontal portion of the rope if the blocks are not moving and the rope and the two pulleys have negligible mass?
The tension in the horizontal portion of the rope provided the blocks are not moving and the rope has negligible mass is 40 N
The tension in the rope is a pulling force that acts on the rope when the mass of 4kg is placed on each side of the two frictionless pulley.
According to Newton's second Law;
Force = (Tension) = mass × acceleration due to gravity
∴
We can say:
Tension = 4kg × 9.81 m/s²
Tension = 39.24 N
Tension = 40 N (to the nearest whole number)
Therefore, we can conclude that the tension in the horizontal portion of the rope is 40 N
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What types of energy do you acquire when you eat a bowl of hot vegetable soup?
Answer:
you need kinetic energy because it is the energy that is used when In motion
The type of energy that one acquire when you eat a bowl of hot vegetable soup is chemical energy.
What is chemical energy?Chemical power the bonds of chemical molecules contain energy. Exothermic reactions are those in which chemical energy is released during the reaction, frequently in the form of heat.
Some of the heat energy needed for a reaction to continue can be stored as chemical energy in newly created bonds.
Food particles go through a chemical reaction that releases chemical energy when we eat it. The body then uses this energy to carry out its regular tasks.
As a result, when you eat a cup of vegetable soup, you also consume the chemical energy it contains.
Thus, the answer is chemical energy.
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1. Explain why the energy of photoelectrons in XPS depends on energy of x-ray source, while energy of Auger electrons does not.
Answer:
Only part of the incident energy from an X-ray source may be used by the ejected electron (some of the energy can be used by the exiting photo electron and some of the energy by the exiting photon).
Auger electrons depend on the energy difference between energy levels of an atom and are fixed - so the ejected electron will have a fixed energy depending on the difference of energy levels of the atom. The Auger effect is called a "radiationless" transition because no radiation is detected outside of the atom.
What is the number of the of significant figures in 2.50400-.pliz, help me l will mark you the brainest.(⊙_◎)
Answer:
Number of Significant Figures: 6
The Significant Figures are 2 5 0 4 0 0
Explanation:
Non-zero digits are always significant which are in this case 2,5,4, and Any zeros between two significant digits are significant and final zero or trailing zeros are significant therefore making the entire digit significant.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The number of significant figures in 2.50400 is ~
[tex] \boxed{6}[/tex]What kind of force could cause this ball to not be at rest anymore, or cause it to move?
Answer:
friction
Explanation
Answer:
Friction
Explanation:
What force prevents an object at rest?
Sliding Friction While static friction keeps an object at rest, sliding friction slows down an object that slides. If you push an object across a room, you notice the sliding friction between the bottom of the object and the floor. You have to keep pushing to overcome the force of sliding friction.
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Zhiyu wants to start an exercise program. He knows that he should talk to his doctor, but he cannot get an appointment for several weeks. He does not have any health conditions. What is the BEST advice for Zhiyu?
A.
All exercise needs to be medically supervised, so he must wait.
B.
There is always a risk of injury, so he needs professional advice before he starts.
C.
He can start slowly with low impact activity like walking or light weightlifting.
D.
He should do whatever he feels like; his body will let him know if he overdoes it.
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
c
Explanation:
Prove that the two equations shown below are equivalent.
F = ma and F = p/t
Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
[tex]\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma[/tex]
F = ma is the formula of Newton’s Second Law of Motion.
To prove Newton's second law of motion,
Given Force F = Δp/Δt
What is relation between F = ma and F = Δp/Δt?Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. The second law of Newton can be described as the acceleration of an object which produces a net force is directly proportional to the magnitude of the net force, in the same path i.e., direction as the net force, and inversely proportional to the mass of the object.As the acceleration has its magnitude and direction it is a vector quantity.Proof for F=ma
Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,
For initial velocity u, p1 = m × u
The final velocity v, p2 = m × v
The change in momentum can be expressed as
p2 – p1 = (m × v) – (m × u)
p2 – p1 = m (v – u)
Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.
The applied force F,
F ∝ [m (v – u)]/t
F ∝ m × a
As acceleration (a) is the rate of change of velocity with respect to time.
F = k × m × a
F = ma
where k can be the constant.
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If an object is rolling without slipping, how is the speed of its center related to its angular velocity
Speed of its center will be directly proportional to its angular velocity in the case of rolling without slipping
What is rolling without slipping ?
Rolling without slipping is a combination of translation and rotation where the point contact is instantaneously at rest.
When an object rolls without slipping on an inclined plane , then the velocity of the center of mass will be equal to angular velocity times radius that object.
Vo = angular velocity * radius
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How far from the center of the earth is the center of mass of the earth moon system?.
Answer:
With a typical distance of 384,400 kilometers separating Earth and the moon's centers, that works out to a center of mass that is roughly 379,700 kilometers from the moon's center and about 4,700 kilometers from Earth's. Explanation:
Please help! Question is attached!
Answer:
1. -6m/s
2. 0m/s
3. 3m/s
4.14.38N
5. 25.9 J
Explanation:
1. point A and C same height means velocity will be the same just in opposite direction, = -6m/s
2. at max height vertical velocity is 0
3. same as point A
4. Weight is mg = 1.438*10 = 14.38N
5. total energy is KE+PE, which never changes
so TE = 32.4 and KE =6.5J then PE = 32.4-6.5 = 25.9 J
A falling object with a weight of 15N is moving downwards towards earth at a steady speed. What is the size of the drag force on this object?
Answer:
15 N :D
Explanation:
The size of the drag force on this object falling at a constant speed is determined as 15 N.
Drag force on the objectThe drag force on the object is determined by calculating the net force on the object;
F(net) = W - D
where;
W is weight of the objectD is the drag force of airma = W - D
at constant speed, acceleration, a = 0
0 = W - D
W = D
15 N = D
Thus, the size of the drag force on this object falling at a constant speed is determined as 15 N.
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What is occurring in the umbra?
A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse
Answer:
A. a total solar eclipse
Explanation:
During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth
The wheel of bicycle has a radius of 25cm.what will be the magnitude of the angular displacemant in radian and revolution respectively,when the wheel has rolled a distance of 350cm on straight level road?
I need help quickly pls
Answer:
Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:
Explanation:
Which of the following is NOT a part of Earth’s atmosphere?
1. mesosphere
2. troposphere
3. asthenosphere
4. stratosphere
Answer:
3
Explanation:
It is part of the Earth's mantle
Answer:
it is the astenospere number 3
What happens if you drop a chicken wing from the top of the Eiffel Tower
Answer:
I think it will brake or squashed
How many sulfur atoms are there in 25 molecules c4h4s2?.
how do i do this question in science?
simple subtract and ummmmmm.....
2Cu + 02 —> 2Cuo
In the equation above, what is the
coefficient of the oxygen molecule?
A) O
B) 1
C) 2.
D) 4
Answer:
C
Explanation:
Hi all, can u please help me in this. I would very appreciate it :)
Write four questions and below the answers about water and air resistance.
Questions And Answers About Air Resistance.
Question 1: What is Air resistance?
Answer: Air resistance is a force that is caused by air. The force acts in the opposite direction to an object moving through the air. A lorry with a flat front will experience high air resistance while a sports car with a streamlined shape will experience lower air resistance, allowing the car to go faster.
Question 2: What causes air resistance?
Answer: Air resistance, also known as drag, is a force that is caused by air, the force acts in the opposite direction to an object moving through the air. It is where air particles hit the front of the object slowing it down. The more surface area, the more air particles hit it and the greater the resistance.
Question 3: How can air resistance be overcome?
Answer: Two ways to reduce air resistance are stated: reducing the area in contact with air (by the cyclist ducking down or cycling behind someone else) and by being more streamlined (wearing smoother surfaces or a more streamlined helmet).
Question 4: What happens when air resistance increases?
Answer: As it gains speed, the object's weight stays the same but the air resistance on it increases. There is a resultant force acting downwards. Eventually, the object's weight is balanced by the air resistance. There is no resultant force and the object reaches a steady speed – this is known as the terminal velocity.
Questions And Answers About Water Resistance.
Question 1: What is Water resistance?
Answer: Water resistance is a type of force that uses friction to slow things down that are moving through water. ... Water resistance occurs because of the particles in the liquid. As an object moves through a liquid, it collides with the particles which cause it to slow down.
Question 2: What causes water resistance?
Answer: Water resistance doesn't have to be just water, however, it can happen to objects moving through any type of fluid. Water-resistance happens because of the particles in water or the fluid. As the object moved through it collides with the particles which try to slow it down.
Question 3: How is water resistance useful?
Answer: Like friction and air resistance, it SLOWS THINGS DOWN, trying to stop them from moving. Water resistance can also be useful at times. When you are swimming and you push against the water with your hands, the water-resistance pushes back and helps you to move forward. This also happens when you use oars to row a boat.
Question 4: Does water-resistant mean waterproof?
Answer: The technical definition of water-resistant is that it's able to resist the penetration of water to a certain degree, but not entirely. Waterproof technically means that it's impermeable to water, no matter how much time it spends in the water.
Hope This Helps...:)
NO LINKS! What are the definitions of initial horizontal velocity and initial vertical velocity? Please help! This like is my 10th time asking this question because many people have been scamming me...
Answer:
Additionally, the initial horizontal velocity may be calculated by measuring the diameter d of the ball and dividing the result by the amount of time t required for the ball to pass across the photogate. Vo = d/t is the formula.
Initial vertical velocity is the vertical component of the initial velocity: v 0 y = sin 0 sin 0 = (30.0 m/s) sin 45° = 21.2 m/s
Explanation:
Hope it helps:)
28
If it takes 1,697 m to stop a car initially moving at 46 m/s, what distance is required to stop a car moving at a quarter
of the initial speed under the same conditions?
Answer:
Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.
Explanation:
Let [tex]v[/tex] and [tex]u[/tex] denote the final and initial velocity of the vehicle ([tex]v = 0\; \rm m \cdot s^{-1}[/tex] since this vehicle has come to a stop.)Let [tex]a[/tex] denote the acceleration of the vehicle (a constant under the assumption.) Let [tex]x[/tex] denote the displacement of the vehicle.If the acceleration on this vehicle is constant, the SUVAT equations would apply:
[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].
Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:
[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].
Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.
If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:
[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].
Two forces are applied to a 50-kg box. One is 60.0
N to the south and the other is 80.0 N to the east.
These are the only forces acting on the box. The
magnitude of the acceleration of the box is:
1. 20m/s^2
2. 1.5 m/s^2
3. 5.2 m/s^2
4. 0.50m/s^2
5. 10m/s^2
The magnitude of the acceleration of the box is 2 m/s².
The given parameters;
mass of the box, m = 50 kgfirst force, F₁ = 60 N southsecond force, F₂ = 80 eastThe resultant of the two given forces is calculated as follows;
[tex]F= \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{60^2 + 80^2} \\\\F = 100 \ N[/tex]
The magnitude of the acceleration of the box is calculated as follows;
[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{100}{50} \\\\a = 2 \ m/s^2[/tex]
Thus, the magnitude of the acceleration of the box is 2 m/s².
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Bijan wanted to find the density of a piece of metal. He weighed it. Them he measured its volume by placing it in measuring cylinder which was half-full of water. Here are his measurements: Mass of metal - 196.0 g, reading on measuring cylinder (water only) = 45 cm3 and reading on measuring cylinder (water + metal) = 68 cm3. What is the density of the piece of metal?
This should be pretty easy i think.
Describe the components within the system involved in the collision between pilot and landing zone.
Answer:
its a sure for not but i think its a 192583
How to find density of a gas.
Answer:
Subtract the mass of the cylinder from the mass of the cylinder when it contains gasoline. This is the mass of the gasoline. Divide this figure by the volume, 100 ml, to get the density.
jxjxjfjfjfknfnfnnfmfgmmmmmmmm(xmpqitexsy.)
Answer:
Hi! can you give me BRAINLIEST ANSWER please.
I would appreciate it
A state government wants to increase the taxes on cigarettes to increase tax revenue. Because cigarettes are addictive, we would expect its demand to be: ______________
a. Elastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
b. Elastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
c. Inelastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
d. Inelastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
The demand of cigarette is elastic so the government's cigarette-tax revenues would rise with a tax increase.
The demand of cigarette is elastic because of the addiction the people can buy the cigarette even at high prices and the government's cigarette-tax revenues would rise.
The demand for cigarettes is unitary elastic (−1.06) means that a 1% increase in the price of cigarette would reduce its consumption by 1.06% so we can conclude that the demand of the cigarette is elastic and the government revenues increases.
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A block with a mass of 6.0 kg is
held in equilibrium on an incline
of angle θ = 30.0° by a horizontal
force, F, as shown in the figure.
Find the magnitudes of the
normal force on the block and of F. (Ignore friction.)
(a) The normal force on the block is 50.92 N.
(b) The horizontal force on block keeping it in equilibrium is 29.4 N.
The given parameters;
mass of the block, m = 6 kgangle of inclination, θ = 30.0°The normal force on the block is calculated as follows;
[tex]F_n = W \times cos(\theta)[/tex]
where;
W is the weight of the block[tex]F_n = mg \times cos(\theta)\\\\F_n = 6 \times 9.8 \times cos(30)\\\\F_n = 50 .92 \ N[/tex]
The horizontal force on block keeping it in equilibrium is calculated as follows;
[tex]F- F_x = 0\\\\F-mgsin\theta= 0\\\\F = mgsin\theta\\\\F = 6 \times 9.8 \times sin(30)\\\\F = 29.4 \ N[/tex]
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how is pure salt obtained from the sea water ?describe in brief
Answer:
Evaporation
Explanation:
Evaporation
Answer:
Salt from sea water is obtained by the process of evaporation. ... The sea water evaporates due to the sun's heat and solid salt is left behind. The left salt is collected and refined to get purified salt. Hence, salt is obtained from sea water by evaporation.
