Using a system of equations, the total number of marbles that they have is given by:
A. 27.
What is a system of equations?A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
The variables are given as follows:
Variable x: Eve's marbles.Variable y: Solene's marbles.Variable z: Steve's marbles.Eve has two more marbles than Solene, hence:
x = y + 2.
Solene has twice as many marbles as Steve, hence:
y = 2z -> z = y/2.x = 2z + 2.Steve has 7 less marbles than eve, hence:
z = x - 7.
Hence:
[tex]\frac{y}{2} = x - 7[/tex]
y = 2(x - 7)
y = 2(y + 2 - 7)
y = 2y - 10
y = 10.
Then:
x = y + 2 = 10 + 2 = 12.z = x - 7 = 12 - 7 = 5.Hence the total is given by:
T = 12 + 10 + 5 = 27.
Which means that option A is correct.
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Find all real zeros of the function.
Answer:
Zeros: 0, 1, and 7
Step-by-step explanation:
Given function: f(x) = 3x(x - 1)²(x - 7)²
To find the zeros (also known as the x-intercepts) of the function, first substitute f(x) = 0 into the equation and simplify.
1. Substitute f(x) = 0:
[tex]\sf f(x) = 3x(x - 1)^2(x - 7)^2\\\\\Rightarrow 0 = 3x(x - 1)^2(x - 7)^2[/tex]
2. Divide both sides by 3:
[tex]\sf \dfrac{0}{3} = \dfrac{3x(x - 1)^2(x - 7)^2}{3}\\\\\Rightarrow 0=x(x-1)^2(x-7)^2[/tex]
3. Separate into possible cases:
[tex]\sf a)\ x = 0\\b)\ (x - 1)^2 = 0\\c)\ (x - 7)^2 = 0[/tex]
4. Simplify:
[tex]\sf a)\ x = 0\ \textsf{[ already simplified ]}[/tex]
[tex]\sf b)\ (x - 1)^2=0\ \textsf{[ take the square root of both sides ]}\\\\\sqrt{(x - 1)^2}=\sqrt{0}\\\\\Rightarrow x-1=0\ \textsf{[ add 1 to both sides ]}\\\\x-1+1=0+1\\\\\Rightarrow x=1[/tex]
[tex]\sf c)\ (x - 7)^2=0\ \textsf{[ take the square root of both sides ]}\\\\\sqrt{(x - 7)^2}=\sqrt{0}\\\\\Rightarrow x-7=0\ \textsf{[ add 7 to both sides ]}\\\\x-7+7=0+7\\\\\Rightarrow x=7[/tex]
Therefore, the zeros of this function are: 0, 1, and 7.
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2
What is the equation of the line that is perpendicular to y=x+4 and that passes through (5,-4)?
--5v-20
K
Perpendicular lines have slopes that are negative reciprocals of each other, so since the slope of the given line is 1, the slope of the line we want to find is -1.
Substituting into point-slope form,
[tex]y+4=-1(x-5)\\\\y+4=-x+5\\\\\boxed{y=-x+1}[/tex]
Statement: "Three less than four times a number is greater
than or equal to 41."
Answer:
x≥11
Step-by-step explanation:
4x-3≥41
4x≥41+3 -44
x≥44/4 = 11
Given: a || b, transversal k
Prove <3 = <6
By the property of corresponding angles ∠3 ≅ ∠5.
What is transversal line?In geometry, a transversal is any line that intersects two straight lines at distinct points.
If two parallel lines are cut by a transversal, then each pair of corresponding angles are equals.
That is, ∠3 = ∠5 and ∠4 = ∠6.
Therefore the given angles ∠3 and ∠5 are equal.
Hence ∠3 ≅ ∠5 .
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Plot the complex number and find its absolute value 2−i
The absolute value of the complex number is √2. The graph is plotted and attached.
What is the complex number?A complex number is one that has both a real and an imaginary component, both of which are preceded by the letter I which stands for the square root of -1.
The given complex number as;
2−i
The absolute value is found as;
[tex]\rm R = \sqrt{1^2 +(-1)^2 } \\\\ R = \sqrt 2[/tex]
The graph for the complex number is attached.
Hence the absolute value of the complex number is √2.
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226,710 - 724,435 =
How to work this out without calculator
What is one possible value of 2x
Answer:
really good
Step-by-step explanation:
thanks for your help you with that do not have a copy of the receipt for your time to help you with theWhich sequences are arithmetic sequences? Select all that apply.
a) 100, 95, 90, 85, ...
b) 10, 20, 40, 80, ...
c) 5, 17, 29, 41, 53, ...
d) -1, 1, -1, 1, -1, 1, ...
e) 42, 52, 62, 72, 82, ...
Answer:
state Avogadro's hypothesis and prove that molecular weight
solve for x -
[tex]\bold{x {}^{2} - 4 = 0}[/tex]
ty! ~
Answer:
x² - 4 = 0
x² = 4
x =± √4
x = +2 or x = -2.
Answer:
2 and -2 (±2)
Step-by-step explanation:
Step 1: Move -4 to the other side of the equal sign; we get x² = 4.
Step 2: A lot of people miss the negative answer! The square root of 4 is equal to both positive 2 and negative 2.
Hope this helped! Please mark me as Brainliest b/c I really need it!!!Find how many numbers between 23^2 and 25^2.
Answer:
Step-by-step explanation:
We know that, 252 = 625
And, 262 = 676
Now, 676 - 625 = 51
So, there are 51 - 1 = 50 numbers lying between 252 and 262
If the odds against an event are 3:5, then the probability that the event will fail to occur is
Answer:
3/8
Step-by-step explanation:
probability = wanted outcomes / total outcomes
odds = wanted outcomes / unwanted outcomes
Odds of 3:5 losing means 3 losing outcomes and 5 winning outcomes.
The total outcomes is 8
The probability of losing which is the probability that the event will fail to occur is 3/8.
Simplify the following expression to its simplest form
Step-by-step explanation:
[tex] \sin(\pi - x) + \tan(x) \cos(x) (x - \frac{\pi}{2} [/tex]
[tex] \sin( - x + \pi ) + \tan(x) ( \cos(x - \frac{\pi}{2} ) )[/tex]
Sin is odd function, so if you add pi to it, it would become switch it sign.
[tex] - \sin( - x) + \tan(x) \cos(x - \frac{\pi}{2} ) [/tex]
Also since sin is again, a odd function, we can just multiply the inside and outside by -1, and it would stay the same.
[tex] \sin(x) + \tan(x) \cos(x - \frac{\pi}{2} ) [/tex]
Cosine is basically a sine function translated pi/2 units to the right or left so
[tex] \sin(x) + \tan(x) \sin(x) [/tex]
[tex] \sin(x) ( 1 + \tan(x) )[/tex]
Assume that BK Call Center receives 2 phone calls in one hour on average. If the department works 10 hours a day receiving the class, find the probability,
A. Exactly 20 calls will be received at a particular day
B. No call is received in a particular hour
C. At least 1 call will be received in a particular hour
Using the Poisson distribution, the probabilities are given as follows:
A. 0.0888 = 8.88%.
B. 0.1354 = 13.54%.
C. 0.8646 = 86.46%.
What is the Poisson distribution?In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
The parameters are:
x is the number of successese = 2.71828 is the Euler number[tex]\mu[/tex] is the mean in the given interval.Item a:
10 hours, 2 calls per hour, hence the mean is given by:
[tex]\mu = 2 \times 10 = 20[/tex].
The probability is P(X = 20), hence:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
[tex]P(X = 20) = \frac{e^{-20}20^{20}}{(20)!} = 0.0888[/tex]
Item b:
1 hour, hence the mean is given by:
[tex]\mu = 2[/tex]
The probability is P(X = 0), hence:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-2}2^{0}}{(0)!} = 0.1354[/tex]
Item c:
The probability is:
[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1354 = 0.8646[/tex]
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6(2x² - 5) = [?]
x = -3
x = -3
[tex]6( {2x}^{2} - 5) \\ \\ 6(2 \times { (- 3)}^{2} - 5) \\ \\ 6(2 \times ( 9) - 5) \\ \\ 6( 18 - 5) \\ \\ 6 \times ( 13) \\ \\ 78.[/tex]
Which expression is equivalent to this quotient?
Answer: C
Step-by-step explanation:
[tex]\frac{3x^{2}-3}{x^{2}+3x}=\frac{3(x^{2}-1)}{x(x+3)}=\frac{3(x-1)(x+1)}{x(x+3)}[/tex]
So, the original fraction is equal to
[tex]\frac{\frac{3(x-1)(x+1)}{x(x+3)}}{\frac{x+1}{x(x+3)}}=\boxed{3(x-1)}[/tex]
whats the answer? :(
Answer:
D) 8[tex]\frac{1}{2}[/tex]
Step-by-step explanation:
5[tex]\frac{2}{3}[/tex] ÷ [tex]\frac{2}{3}[/tex] = 8[tex]\frac{1}{2}[/tex]
FAST!
A right rectangular prism has a square base and a height of 2.5 meters. If the length of a side of the square base is 4 meters, what is the volume of the prism?
Answer:
69 there hope it helps ;)
Step-by-step explanation:
420
Please help me answer this question
Step-by-step explanation:
look at the attachment above
Answer:
[tex]\textsf{1)} \quad -\dfrac{1}{16}e^{-4x}\left(4x+1\right)+\text{C}[/tex]
[tex]\textsf{2)} \quad - \cos x+\dfrac{2}{3} \cos^3 x - \dfrac{1}{5} \cos^5 x +\text{C}[/tex]
Step-by-step explanation:
Question 1
[tex]\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}[/tex]
[tex]\boxed{\begin{minipage}{5 cm}\underline{Integration of $e^{ax}$} \\\\$\displaystyle \int e^{ax}\:\text{d}x=\dfrac{1}{a}e^{ax}+\text{C}$\\\\for $a\neq 0$\\\end{minipage}}[/tex]
Given integral:
[tex]\displaystyle \int xe^{-4x}\:\text{d}x[/tex]
Using Integration by parts:
[tex]\textsf{Let }\:u=x \implies \dfrac{\text{d}u}{\text{d}x}=1[/tex]
[tex]\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=e^{-4x} \implies v=-\dfrac{1}{4}e^{-4x}[/tex]
Therefore:
[tex]\begin{aligned}\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x & =uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x\\\\\implies \displaystyle \int xe^{-4x}\:\text{d}x & =-\dfrac{1}{4}xe^{-4x}-\int -\dfrac{1}{4}e^{-4x}\: \text{d}x\\\\& =-\dfrac{1}{4}xe^{-4x}+\int \dfrac{1}{4}e^{-4x}\: \text{d}x\\\\& =-\dfrac{1}{4}xe^{-4x}-\dfrac{1}{16}e^{-4x}+\text{C}\\\\& =-\dfrac{1}{16}e^{-4x}\left(4x+1\right)+\text{C}\end{aligned}[/tex]
Question 2
[tex]\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\\ \end{minipage}}[/tex]
[tex]\boxed{\begin{minipage}{5 cm}\underline{Integrating a constant}\\\\$\displaystyle \int n\:\text{d}x=nx+\text{C}$\\(where $n$ is any constant value)\end{minipage}}[/tex]
Rewrite the given integral:
[tex]\begin{aligned}\displaystyle \int \sin^5 x \: \text{d}x & =\int (\sin x)^4 \cdot \sin x \: \text{d}x\\& =\int (\sin^2 x)^2 \cdot \sin x \: \text{d}x\end{aligned}[/tex]
Use the trig identity [tex]\sin^2x+\cos^2x \equiv 1[/tex] to rewrite [tex]\sin^2x[/tex] :
[tex]\implies \displaystyle \int \sin^5 x \: \text{d}x = \int (1-\cos^2 x)^2 \cdot \sin x \: \text{d}x[/tex]
Integration by substitution
[tex]\textsf{Let }\:u=\cos x \implies \dfrac{\text{d}u}{\text{d}x}=-\sin x \implies \text{d}x=-\dfrac{1}{\sin x}\: \text{d}u[/tex]
Therefore:
[tex]\begin{aligned}\implies \displaystyle \int \sin^5 x \: \text{d}x & = \int (1-u^2)^2 \cdot \sin x \cdot -\dfrac{1}{\sin x}\: \text{d}u\\& = \int -(1-u^2)^2 \: \text{d}u\\ & =\int -1+2u^2-u^4 \: \text{d}u\\& =-u+\dfrac{2}{3}u^3-\dfrac{1}{5}u^5+\text{C}\end{aligned}[/tex]
Finally, substitute [tex]u = \cos x[/tex] back in:
[tex]\implies \displaystyle \int \sin^5 x \: \text{d}x=- \cos x+\dfrac{2}{3} \cos^3 x - \dfrac{1}{5} \cos^5 x +\text{C}[/tex]
6z + 10= -2 solve this problem
Answer:
z = -2
Step-by-step explanation:
Answer:
[tex]\boxed{\bf z = - 2}[/tex]
Step-by-step explanation:
[tex]\bf 6z + 10 = - 2[/tex]
Subtract 10 from both sides.
[tex]\bf 6z + 10 - 10= - 2 - 10[/tex]Simplify.
[tex]\bf 6z = - 12[/tex]Divide both sides by 6.
[tex]\bf \cfrac{6z}{6} = \cfrac{ - 12}{6} [/tex]Simplify.
[tex]\bf z = - 2[/tex]_________________________
Find the midpoint of the line segment whose endpoints are given. (9,3), (10,- 10)
Answer:
Step-by-step explanation:
(xm , ym ) = x1 + x2 / 2 and y1 + y2 / 2
= 9 +3 / 2 = 10 -10 / 2
= 12/2 = 0/2
= 6 = 0
So midpoints are (6 , 0)
Answer:
midpoint = [tex](9\frac{1}{2} , -3\frac{1}{2} )[/tex]
Step-by-step explanation:
To find the midpoint of a line segment, you have to find the average of the x and y-values of the end-points, i.e., add the x-coordinate values and divide the answer by 2, and do the same for the y-coordinate values.
• midpoint = [tex](\frac{x_{2} + x_1}{2}, \frac{y_2 + y_1}{2} )[/tex]
= [tex](\frac{9 + 10}{2}, \frac{3 + (-10)}{2} )[/tex]
= [tex](\frac{19}{2}, \frac{-7}{2} )[/tex]
= [tex](9\frac{1}{2} , -3\frac{1}{2} )[/tex]
Given market demand Qd=50-p, and market supply p=Qs+5.what would be the state of the market if market price was fixed at Birr 25 per unit?
The state of the market if market price was fixed at Birr 25 per unit is excess demand
Quantity demandedQd = 50 - p
p = Qs + 5
p - 5 = Qs
if market price was fixed at Birr 25 per unit?
Qd = 50 - p
= 50 - 25
Qd = 25
Qs = p - 5
= 25 - 5
Qs = 20
The state of the market if market price was fixed at Birr 25 per unit is excess demand (demand greater than supply) leading to an increase in price.
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Solve the linear programming problem.
Minimize and maximize
P = 10x + 5y
Subject to
2x+3y 230
2x+y ≤ 26
-2x+3y ≤ 30
x, y 20
The minimized value is 50 and the maximized value is 130
How to minimize and maximize the function?The objective function is:
P = 10x + 5y
Subject to
2x+3y ≤30
2x+y ≤ 26
-2x+3y ≤ 30
x, y >0
Next, we plot the graph of the constraints (see attachment)
From the graph, the vertices of the feasible regions are:
(0, 10),(12, 2) and (6,14)
Substitute these values in P = 10x + 5y
P = 10(0) + 5(10) = 50
P = 10(12) + 5(2) = 130
P = 10(6) + 5(14) = 130
Hence, the minimized value is 50 and the maximized value is 130
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Math: One to One function...help!
A one-to-one function has an inverse. The inverse is another function that undoes the action of the first one, so if we evaluate a function [tex]f[/tex] at some point [tex]x[/tex] to get the number [tex]f(x)[/tex], evaluating the inverse at [tex]f(x)[/tex] will recover the original input [tex]x[/tex]. In other words,
[tex]f^{-1}(f(x)) = x[/tex]
The process works in the opposite direction, too:
[tex]f\left(f^{-1}(x)\right) = x[/tex]
From the given definition of [tex]g[/tex], we have [tex]g(-4) = 3[/tex], so taking inverses on both sides, we find
[tex]g(-4) = 3 \implies g^{-1}(g(-4)) = g^{-1}(3) \implies \boxed{g^{-1}(3) = -4}[/tex]
Given [tex]h(x)=2x-13[/tex], evaluating [tex]h[/tex] at its inverse will recover [tex]x[/tex], so that
[tex]h\left(h^{-1}(x)\right) = x \implies 2h^{-1}(x) - 13 = x \implies \boxed{h^{-1}(x) = \dfrac{x+13}2}[/tex]
[tex](h\circ h^{-1})(x)[/tex] is another way of writing the compound function [tex]h\left(h^{-1}(x)\right)[/tex]. As already discussed, this reduces to [tex]x[/tex], so
[tex]\boxed{\left(h\circ h^{-1}\right)(-9) = -9}[/tex]
What is the value for y?
What is the value of x?
Enter your answer in the box.
x =
Equiangular triangle A B C. Angles A, B, and C are marked congruent. The length of side A C is labeled as 5 x minus 22. The length of side A B is labeled as 4 x minus 10. The length of side B C is labeled as 3 x plus 2.
Enter your answer in the box.
y =
An isosceles triangle A B C with horizontal base B C and vertex A is above the base. Side A C and C B are labeled with single tick mark. All the three angles are labeled. Base angles C A B is labeled as 50 degrees and angle C B A is labeled as 2x degrees. The angle A C B is labeled left parenthesis 5 y plus 10 right parenthesis degrees.
1. The value of x in the equilateral triangle is: 12
2. x = 25; y = 14
What is an Equilateral Triangle?If a triangle has three sides that are marked congruent, then the triangle is an equilateral triangle.
1. Since triangle ABC is an equilateral triangle and its sides are equal, therefore:
5x - 22 = 3x + 2 [congruent sides]
Solve for x
5x - 3x = 22 + 2
2x = 24
2x/2 = 24/2
x = 12
The value of x is: 12.
2. Base angles of an isosceles triangle are congruent, therefore:
2x = 50
x = 50/2
x = 25
Thus, using the triangle sum theorem, we have:
2x + 50 + 5y + 10 = 180
Plug in the value of x and find y
2(25) + 50 + 5y + 10 = 180
50 + 50 + 5y + 10 = 180
110 + 5y = 180
5y = 180 - 110
5y = 70
y = 70/5
y = 14
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What number comes next in the sequence?
1, 1, 2, 3, 5, 8, 13, 21, 34, ?
Answer:
55
Step-by-step explanation:
1+1 = 2
1+2 = 3
2+3 = 5
3+5 = 8
5+8 = 13
8+13 = 21
13+21 = 34
21 +34 = 55
PLEASE GIVE BRAINLIEST
I need help with number 10 please
Answer:
Liz
Step-by-step explanation:
if the chart is correct only 3 people spent more than 2 1/2 hours on homework when 9 people spent less than 2 1/2 hours on homework
A kitchen measures 20 feet long and 10 feet wide. A scale drawing is made using a scale factor of 124.
What is the length of the kitchen in the scale drawing?
5/12
5/6
5/4
Drag and drop a number to correctly complete the statement.
The length of the kitchen in the scale drawing is Response area ft.
The length of the kitchen in the drawing using the scale factor is: B. 5/6.
How to Find Length Using Scale Factor?We are given a scale factor of 1:24.
Let the length of the kitchen in the drawing = x
Actual length of kitchen = 20 ft.
Using the scale factor, we have:
1/24(20) = 20/24
= 5/6
The length of the kitchen in the drawing is: B. 5/6.
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Question
Find the distance between the points (-5, 8) and (-3,0).
To calculate the distance between two points we use this formula:
[tex] \boxed{ \boxed{{d \: = \: \sqrt{(x_2 \: - \: x_1)^{2} \: + \: (y_2 \: - \: y_1)^{2} } }}}[/tex]
______________________We organize the values:x₁ = -5 x₂ = -3 y₁ = 8 y₂ = 0______________________
We apply the values already obtained to the formula to get the distance:
[tex]d \: = \: \sqrt{( - 3 \: - \:( - 5))^{2} \: + \: (0 \: - \: 8)^{2} }[/tex]
[tex]d \: = \: \sqrt{( - 3 \: - \: ( - 5))^{2} \: + \: ( - 8)^{2} }[/tex]
[tex]d \: = \: \sqrt{( - 3 \: + \: 5) ^{2} \: + \: 64 } [/tex]
[tex]d \: = \: \sqrt{ {2}^{2} \: + \: 64 } [/tex]
[tex]d \: = \: \sqrt{4 \: + \: 64} [/tex]
[tex]d \: = \: \sqrt{68} [/tex]
[tex]d \: = \boxed{ \bold{ \: 2 \sqrt{17} \: units}}[/tex]
Answer:[tex] \huge{\boxed{ \bold{2 \sqrt{17} \: units }}}[/tex]
MissSpanishJack has a rectangular piece of land, the area of which is represented by a₁ = 9.5%. His brother has a different rectangular piece of land, the area of which is represented by a2 = 14-). Let a represent the area in square meters and /represent the length in meters of the pieces of land. The two equations plotted on a graph meet at a point as shown in the image.
Answer:
yea that’s right
Step-by-step explanation:
Which of the following linear equations represents the data chart?
X Y
1 6
2 5
3 4
4 3
y=x+5
y=x+3
y = -x + 7
None of these choices are correct.
Answer: y = -x + 7
Step-by-step explanation:
The slope is [tex]\frac{5-6}{2-1}=-1[/tex], so we know the equation is of the form [tex]y=-x+b[/tex].
Substituting in the coordinates (1,6) to find b,
[tex]6=-1+b\\\\b=7[/tex]
Thus, the equation is y = -x + 7