Fez loves team sports and gets abundant exercise through team activities. When Fez engages in team activities such as running or passing the ball, what is happening to Fez’s muscles?

It is discovered that the capacitor’s potential difference increases to 4.0 V in one second.

There is a potential difference (p.d.) between the plates of a capacitor when it is completely charged, and the larger the area of the plates and/or the smaller the distance between them (known as separation), the greater the charge that the capacitor can carry and the greater the capacitance.

Divide the resistance present in the circuit by the current flow rate.

The resulting number, expressed in volts, is the potential difference. Ohm's Law, or V = IR, is the name of this equation.

With several parallel capacitors, the potential difference is the same, but the charge increases. Similar to adding resistance in series, paralleling capacitors increases effective capacitance.

Effective capacitance is calculated as effective capacitance = capacitance 1 + capacitance 2.

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Conduction is the process by which ice packs transfer heat when put on an injury.

Both gel packs and ice packs mostly absorb heat by conduction, or by coming into close touch with the treatment region.

By producing vasoconstriction, which lowers blood flow to the damaged spot, ice minimizes edema, bleeding, and inflammation. By inhibiting pain receptors and nerve transmission, ice immediately reduces pain and muscular spasm.

Direct contact between the items is how heat is transferred during conduction. Convection is the process through which heat is moved within the fluid. Heat transmission in radiation happens by electromagnetic waves without the need of particles. The temperature differential causes the heat transfer to occur.

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Acceleration of the car is 6 m / s ².

a =  ( v - u ) / t

a stands for acceleration

u stands for initial velocity

v stands for final velocity

Given ,

u = 5 m / s

v = 20 m / s

t = 2.5 s

a =  ( v - u ) / t

a = ( 20 - 5 ) / 2.5

  =  15 / 2.5

 a  = 6 m / s ²

Hence , Acceleration of car is 6 m / s ² .

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The given question is incomplete kindly refer below for complete question :

A car accelerates from 5m/s to 20m/s in 2.5 seconds . Find the acceleration of the car .

The average speed in m/s, given the data is 820.80 m/s

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

This is the total distance travelled divided by the total time taken to cover the distance.

Average speed = total distance / total time

Speed = distance / time

684 = 446000 / time

Cross multiply

684 × time = 446000

Divide both side by 684

Time = 446000 / 684

Time to fly away = 652.05 s

Speed = distance / time

1026 = 446000 / time

Cross multiply

1026 × time = 446000

Divide both side by 1026

Time = 446000 / 1026

Time to return = 434.70 s

The average speed can be obtained as follow:

Average speed = total distance / total time

Average speed = 892000 / 1086.75

Average speed = 820.80 m/s

Thus, the average speed is 820.80 m/s

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Angular momentum is the rotational analog of linear momentum, found by taking the product of moment of inertia and The reciprocal of linear acceleration is angular velocity.

The right-hand rule, which uses the thumb to indicate the direction of angular velocity momentum and four fingers to represent the direction of motion, can be used to determine the direction of angular momentum.

Angular momentum is a characteristic that describes an object's rotatory inertia while it is moving about an axis that may or may not pass through it.

Torque is needed in rotational motion to cause an item to accelerate angularly. The distribution of the object's mass affects how much torque is needed to produce an angular acceleration. The value that describes the distribution is called the moment of inertia.

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The inductive reactance is 1578.34 Ω.

We need to know about inductive reactance to solve this problem. The inductive reactance is the internal resistance in the inductor caused by changing current. It can be described as

XL = ω . L

where XL is inductive reactance, ω is angular speed and L is inductance.

The angular speed can be determined by

ω = 2π . f

where f is frequency.

From the question above, we know that

f = 81 Hz

L = 3.1

By substituting the given parameters, we get

XL = ω . L

XL = 2π . f . L

XL = 2π . 81 . 3.1

XL = 1578.34 Ω

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In ernest rutherford's gold foil experiment, why did alpha particles sometimes (1 in 8,000) fly violently in the positive alpha particle were perfectly aligned to strike a nucleus.

In Rutherfords' experiment, the positively charged alpha particles were perfectly aligned to strike the nucleus. Thus they got deflected in a random direction due to repulsions between the positively charged nucleus and positively charged alpha particles.

Ernest Rutherford conducted this experiment in response to J.J. Thomson's plum-pudding model experiment.

A thin piece of gold foil, an alpha particle-emitting radioactive source, and a fluorescent screen that encircles the gold sheet were used in this experiment. He set the radioactive source in front of the gold sheet, which had a fluorescent screen surrounding it. Now, the alpha particle from that radioactive source bombarded this gold foil sheet.

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Conservation of energy describes law of thermodynamics.

Energy can be converted from one form to another, but it cannot be created or destroyed. According to the rule of conservation of energy, the total energy of any isolated system (for which energy and matter transfer over the system boundary is not feasible) is constant.

deltaU=Q-W

where Delta U}\Delta U denotes the change in the internal energy of a closed system (for which heat or work through the system boundary are possible, but matter transfer is not possible), Q denotes the quantity of energy supplied to the system as heat, and W denotes the amount of thermodynamic work done by the system on its surroundings

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The ball that is thrown directly downward with an initial speed of 7.05 m/s, from a height of 29.9 m. takes 3.29 s to strike the ground

The formula for the downward vertical launch and the procedure we will use is:

t = {V₀ + [tex]\sqrt{}[/tex][(V₀)² + 2*g*y]}/ g

Where:

Information about the problem:

With the information gave, we can calculate the time from the ball is thrown, using the formula of downward vertical launch:

t = {V₀ + [tex]\sqrt{}[/tex][(V₀)² + 2*g*y]}/ g

t = {7.05 m/s + [tex]\sqrt{}[/tex][(7.05 m/s)² + 2*9.8 m/s²*29.9 m]}/ 9.8 m/s²

t = {7.05 m/s + [tex]\sqrt{}[/tex][49.70 m²/s² + 586.04m²/s² ]}/ 9.8 m/s²

t = {7.05 m/s + [tex]\sqrt{}[/tex][635.74 m²/s² ]}/ 9.8 m/s²

t = {7.05 m/s + 25.214 m/s}/ 9.8 m/s²

t = 32.26 m/s/ 9.8 m/s²

t = 3.29 s

In physics vertical launch is the motion described by an object that has been launched vertically in which the acceleration is the earth's gravitational force.

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By Avogadro's number, the mass of Neon atom is 20 grams.

We need to know about Avogadro's number to solve this problem. Avogadro's number is the number that explains how many carbon atoms are in one mol. The Avogadro's number is

Na =  6,02 × 10²³ atoms / mol

From the question above, we know that

Mr = 20

N = 6,02 × 10²³ atoms

By using Avogadro's number, we can calculate how much Neon atoms

N = n . Na

6,02 × 10²³ = gr / Mr . 6,02 × 10²³

gr / 20 = 1

gr = 20 grams

Hence, the mass of Neon atom is 20 grams.

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The combination of low oxygen levels in the ocean and low carbon dioxide in the atmosphere led to cooling temperatures and the Late Devonian extinction, 380 million years ago. Many ocean dwellers went extinct, including trilobites. In contrast, tetrapods fared best since they were transitioning from sea to land and could survive in both regions.

The tetrapods are characteristized by the possession of muscles and skeleton which aids support and movement respectively.

The tetrapods are referred to as vertebrates ( those animals with backbones) which have two pairs of limbs. That is, they have four different limbs

So therefore, The combination of low oxygen levels in the ocean and low carbon dioxide in the atmosphere led to cooling temperatures and the Late Devonian extinction, 380 million years ago. Many ocean dwellers went extinct, including trilobites. In contrast, tetrapods fared best since they were transitioning from sea to land and could survive in both regions.

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The gravitational force applied on the object or weight of the object is equal to 1920 N.

What is weight?

The force exerted on an object by gravity is known as the weight of the object in science and engineering. The gravitational force acting on the any object is referred to as weight in several common textbooks. Some people refer to weight as a scalar quantity that measures the gravitational force's strength. Others define it as the strength of the force that mechanisms that counteract the effects of gravity impose on a body.

In order to calculate the object's weight we just needed to multiply its mass with the given gravitational acceleration. Then after inserting the values for m and g we can obtain the solution.

So, we get equation

[tex]F = m \times g[/tex]

Putting values in the equation,

[tex]F = 200 \times 9.6[/tex]

We get the force,

[tex]F = 1920 N[/tex]

Therefore, the weight of the object is 1920 N.

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The emergence of millions of cicadas  benefits.

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The path of motion observed during the javelin throw is an example of curvilinear motion.

When an object is thrown at a particular angle, the motion of an object is curved i.e, called curvilinear motion.

Example: A stone thrown into the air at a particular angle.

The javelin throw is a sport with a track and field event where a spear of 2.5m in length is thrown into the air at a particular angle. Thus considered an example of curvilinear motion

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The length by which the guy wire stretches is; δ = 0.091 in

We are given;

Length of guy wire AB = 6ft = 72 in

Diameter of wire = 0.2 in

UDL = 200 lb/ft

From the free body diagram of the rigid beam system and the guy wire attached, we can say that;

Taking moments about point C gives;

∑Mc = 0; -(2000 * 5) + (F_BA * cos 30 * 10) = 0

-10000 + 8.66F_BA = 0

8.66F_BA = 10000

F_BA = 10000/8.66

F_BA = 1154.73 lb

Now, the length which it stretches is gotten from the formula;

δ = PL/AE

Where;

δ is change in length

P is Force

L is length of wire

A is area

E is modulus of elasticity of wire(steel) = 29000 ksi = 29000000 psi

A = πd²/4

A = π * 0.2²/4

A = 0.0314 in²

Thus;

δ = (1154.73 * 72)/(0.0314 * 29000000)

δ = 0.091 in

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The most immediate, but necessarily limited, source of energy for reformation of ATP in muscle cells is creatine phosphate. When ATP is used for energy by the cells, it is broken down into ADP and inorganic phosphate. This process is reversible, but it requires energy to reform ATP from ADP and inorganic phosphate. The primary source of this energy is creatine phosphate, which donates a phosphate group to ADP to form ATP.

This process is called phosphocreatine resynthesis and it occurs in the mitochondria of muscle cells. Phosphocreatine is synthesized from creatine and ATP in a reaction that requires the enzyme creatine kinase. This reaction is irreversible, meaning that the synthesis of phosphocreatine from creatine and ATP cannot be used to generate ATP.

The amount of ATP that can be generated from phosphocreatine resynthesis is limited by the amount of creatine phosphate available in the muscle cells. Creatine phosphate is synthesized in the liver from creatine and ATP. It is then transported to the muscle cells where it is used for phosphocreatine resynthesis. The synthesis of creatine phosphate in the liver is a slow process and the amount of creatine phosphate in the muscle cells is limited.

The most immediate source of energy for reformation of ATP in muscle cells is therefore creatine phosphate. This source of energy is limited, however, and other sources of energy must be used to maintain ATP levels in the cells.

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Answer:

(2,-9)

Explanation:

Reflection over the y-axis:

As a general rule any point (x, y) reflected over the y-axis becomes ( -x, y)

The y-axis acts like a mirror.

Reflect (-2, 9) over the y-axis:

The point (-2,-9) reflected over the y-axis becomes point ( 2,-9)

The speed of the car at the first point is 18 m/s.

How do we calculate the initial speed?

The equation we can be used for finding the speed of the first point is:

         ⇒ Δx = ½ (v + v₀)t

From this we can easily calculate v₀ i.e,

        ⇒ v₀ = 2Δx/t - v

According to the question it is given that,

Distance between two points is , Δx =120 m,

Time t = 8.0 s,

Speed at second point is, v = 12 m/s,

Speed at first point is, v₀ = ?

From above formula,

 ⇒  v₀ = 2Δx/t - v

           = 2×120/8 - 12

           = 240-96/8

           = 144/8

           = 18 m/s

Therefore the speed at first point is 18 m/s.

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Here in this question neither of them are correct. As the friction bearings are not made of balls and rollers. Also, non friction bearings are not in a sliding contact between moving surfaces.

In order to provide a low-friction support surface for rotating or sliding surfaces, friction bearings are composed of a stationary, non-moving bearing surface, such as machined metal or a pressed-in bushing.

Lubricating oil is frequently used in friction bearings to isolate the moving part from the mated non-moving bearing surface. An antifriction bearing uses rolling parts connected by inner and outer rings to absorb the radial forces acting on the rotor.

It is typically mounted to the shaft with an interference fit. Pumps and aero-derived gas turbines frequently use antifriction-type bearings.

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Answer:

That would be:

(2) younger

No there is nothing that shows third type of charge existence.

A few straightforward experiments can demonstrate the existence of two different types of charges. As it loses electrons to the silk cloth when the glass rod is rubbed against it, the glass rod becomes positively charged. The silk material acquires a negative charge.

The physical characteristic of matter is its electric charge. It comes in both positive and negative forms. While opposite charges repel one another, like charges attract.

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Answer:

Explanation:

No, If An object is moving in a uniform velocity that means there is no change in velocity(speed) ,The object keeps on moving with the same speed  .No change in speed means that thee is no acceleration encountered by the object. Even the Equations of motions support the statement.

The downward acceleration after release is 9.8 m/s^2.

What is the universal law of gravitation, or NLG?

Every particle of matter in the universe is drawn to every other particle by a force that varies directly with their combined masses and inversely with their distance from one another.

Whether an object is moving or at rest, gravity still exerts its force on it.

In the given case, the general equation is as follows:

s = s₀+v₀t+1/2g[tex]t^{2}[/tex]

where

s is referred to as position at time t,

s₀ is referred to as the initial position,

v₀ is referred to as the initial velocity,

g is referred to as the acceleration of gravity and

t is referred to as the elapsed time.

When the object leaves your hand, we would typically say that time is (t)=0.

An object initial velocity is increased when it is thrown, whereas it would be zero if it were simply dropped.

However, once it is out of your hand, gravity accelerates at the same rate in both directions. As a result, the downward acceleration is 9.8 meters per second squared.

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3 times that of the celsius  = 80°F

1/ 3 times that of the celsius = -160°F/29 F

Fahrenheit scale = 9/5 (°Celcius) +32

a) 3 times that of the celsius

F = 3C

C= F/3

Fahrenheit scale = 9/5 (°Celcius) +32

= 3F/5 + 32

F - 3F/ 5 = 32

2F/5 = 32

2F = 160

F = 80° F

b) 1/ 3 times that of the celsius

F = 1/3 C

3F = C

F = 9/5( 3F) + 32

F = 27F/5 +32

5F-27F = 160

-22F = 160

F = -160°F/ 29

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The change in the enthalpy of argon Almost doubles

Argon

Cp = Specific heat at constant volume = 0.520 kJ/kgK

T₁ = Initial temperature = 75°C

T₂ = Final temperature = 35°C

Enthalpy,

Δh = CpΔT

⇒Δh = Cp(T₂-T₁)

⇒Δh = 0.520×(35-75)

⇒Δh = -20.8 kJ/kg

Neon

Cp = Specific heat at constant volume = 1.03 kJ/kgK

T₁ = Initial temperature = 75°C

T₂ = Final temperature = 35°C

Δh = Cp(T₂-T₁)

⇒Δh = 1.03×(35-75)

⇒Δh = -41.2 kJ/kg

Enthalpy will change because the Cp value is different.

Enthalpy almost doubles.

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Two forces 3N and 4N act on a body in a direction due north From East, the equilibrant's angle is given by [tex]\theta=\tan ^{-1} \frac{3}{4}=36.8^{\circ}[/tex].

The equilibrium force is the balanced force when the net force acting is zero and is the exact opposite of the consequent force. The resultant force is one single force replaced by numerous forces.

3N and 4N are the two forces pulling on a body.

The forces work along the North and the East, which are perpendicular to one another.

The resultant of the forces, which is provided by the equilibrant force,

R  = √(3)²+(4)²

R = 5N

From East, the equilibrant's angle is given by

[tex]\theta=\tan ^{-1} \frac{3}{4}=36.8^{\circ}[/tex]

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For enrolling authentication servers with server certificates for use with 802.1X authentication, you have two options: construct your own public key infrastructure using Active Directory Certificate Services (AD CS) or utilize server certificates enrolled by a public certification authority (CA).

The Active Directory Certificate Services (AD CS) server is a Windows server that is used to issue digital certificates. Certificates have been shown to be more secure and user-friendly than passwords. Microsoft recognized this and deployed AD CS to assist Microsoft environments in reaping the benefits of certificates. A client computer, on the other hand, trusts a CA when the CA certificate is loaded in the Trusted Root Certification Authorities certificate store. Multiple public CA certificates are installed by default in the Trusted Root Certification Authorities certificate store on Windows systems.

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In order to calculate the mass of the solution, we use the formula

V = πr2h

After heating, the test tube and anhydrous hydrate weigh 17.05 g. The test tube weighs 15.81 g when it is empty. 1.24 g is the mass of anhydrous hydrate. 0.48 g of water is lost.

Don’t factor in the glass’s thickness when reading. Using the following formula, determine the capacity of each test tube: V = r2h, where r (the radius) = ½ the diameter and = 3.14.

Your final computation should be rounded to the correct number of significant figures.

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