Find the value of: (4/5)^1 A. 4/5 B. 1 C. 0 D. 16/25​

Answers

Answer 1

Answer:

A. 4/5

Step-by-step explanation:

Answer 2

Answer:

4/5  (option a)

Step-by-step explanation:

by following the exponent rule of [tex]a^1 = a[/tex], we know that

[tex](\frac{4}{5} )^1[/tex] = [tex]\frac{4}{5}[/tex]

So, the value of

[tex]\frac{4}{5}^{1}[/tex]  is  4/5


Related Questions

How many units were started into production in a period if there were zero units of beginning work in process inventory, 4,714 units in ending work in process inventory, and 20,661 completed and transferred out units?

Answers

The number of the units were started into production in a period will be 25,375.

What is inventory?

A industry's fully prepared kinds of goods, as well as the primary materials needed to make them, are considered to as inventory.

If there were zero units of beginning work in process inventory, 4,714 units of ending work in process inventory, and 20,661 completed and transferred out units.

Completed and transferred out = 20,661

Ending Inventory = 4,714

Units accounted for = 25,375

Beginning Inventory = 0

Units started into production = [Units accounted for – Beginning work in progress Inventory] = 25,375

Units accounted for = 25,375

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The average THC content of marijuana sold on the street is 10.9%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street

Answers

(a) X ≈ N (0.10 , 0.02²)

(b) The probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.

(c) The 60th percentile is 11%.

The complete question is:The average THC content of marijuana sold on the street is 10%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. Round all answers to two decimal places and give THC content in units of percent. For example, for a THC content of 11%, write "11" not 0.11.  

A. X ~ N( , )  

B. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11%.

C. Find the 60th percentile for this distribution.

According to the question,

The random variable X is defined as the THC content for a bag of marijuana that is sold on the street.

(a)The random variable X is Normally distributed with mean, μ = 0.10 and standard deviation, σ = 0.02.

Therefore, X ≈ N (0.10 , 0.02²)

(b) The value of P (X > 0.11) as follows:

P (X > o.11_ = P(X -μ/a > [tex]\frac{0.11-0.10}{0.02} \\[/tex])

= P(Z > 0.50)

= 1 -P (Z <0.50)

= 1- 0.69146

= 0.30854 ≈ 0.31

Hence,

the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.

(c)Let x represent the 60th percentile value.

Then, P (X < x) = 0.60.

⇒ P (Z < z) = 0.60

The value of z is,

z = 0.26.

Now put the value of x as follows:

z = x - μσ

0.26 = x - 0.100.02

x = 0.10+ ( 0.26 x 0.02)

x = 0.1052

x ≈ 0.11

Therefore,

The 60th percentile is 11%

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Choose the single logarithmic expression that is equivalent to the one shown. log6 25 − log6 5

Answers

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(25) - log_{6}(5) [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) {}^{2} - log_{6}(5) [/tex]

[ property : x² = 2 log x ]

[tex]\qquad \tt \rightarrow \: 2 \: log_{6}(5) {}^{} - log_{6}(5) [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Evaluate the piecewise-defined function for the indicated values. I’m just unsure of how to solve when the value isn’t given directly. Namely, how to solve for b through d

Answers

The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for [tex]m^{2} +1[/tex] is 9.

Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and [tex]\sqrt{t-1}[/tex] for 8<t<11.

A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.

B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.

C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.

D) In this we have to find the function at [tex]m^{2} +1[/tex] when m belongs to [tex]\sqrt{7} and \sqrt{10}[/tex] the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.

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If f(x) = 2x+6 and g(x)= x3 what is (g f)(0)?

Answers

Answer:

[tex]27[/tex]

Step-by-step explanation:

[tex]g(f(0))=g(2(0)+3)=g(3)=3^3=27[/tex]

D
4
3
2
1
-5 -4 -3 -2 -1 0
1
2
GO
-4
-5
A
1
2
3 4 5 Match the graph with its equation

Answers

This graph represents the equation y = -3

15 points help! Select the correct answer from the drop-down menu.
Consider the equation (x^m)³ = (113)5 x(x−8)—5
The value of mis
Reset
Next

Answers

Answer:The value of m for the given equation is, 35

Step-by-step explanation:

Given an equation:  https://tex.z-dn.net/?f=x%5E%7B3m%7D%3D(x%5E%7B65%7D)*(x%5E%7B40%7D)

Use the above property on  RHS in equation [1];

Since the base are same i.e, x ; we can add the exponents.

or

Using:  , then a=b.

Therefore, 3m=105.

Divide 3 on both sides of an equation:

Simplify:

m=35

Therefore, the valur of m is, 35.

Quadrilateral WXYZ has vertices W(2, 10), X(10, 10), (10,2), and Z(2, 2). Determine if quadrilateral WXYZ is a rhombus.
A. No, quadrilateral WXYZ is not a rhombus.
B. Yes, quadrilateral WXYZ is rhombus because the sides are perpendicular.
C. Yes, quadrilateral WXYZ is a rhombus because the slopes of the diagonals are perpendicular.
D. There is not enough information to determine.
Please select the best answer from the choices provided

Answers

Answer:

B. Yes, quadrilateral WXYZ is rhombus because the sides are perpendicular.

Step-by-step explanation:

1) according to the given coordinates the equations of the sides are:

YZ: y=2; WZ: x=2; WX: y=10; XY: x=10. It means

2) YZ⊥WZ; YZ⊥XY; WX⊥XY; WX⊥WZ. To the additional, WX=WZ=YZ=XY, then

3) the given quadrilateral is sqare (rhombus with angles m∠=90°).

4) finally, the correct answer is

B. Yes, quadrilateral WXYZ is rhombus because the sides are perpendicular.

Given: A = { -1,5,6} B = {-1,2,3,4,6,8} Find the union of sets A and B.

Answers

Step-by-step explanation:

{-1,2,3,4,5,6,8} is the answer

A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is 65% salt and Solution B is 80% salt. She wants to obtain 120 ounces of a mixture that is 70% salt. How many ounces of each solution should she use?

Answers

We can use these variables:

A = number of ounces for solution A
B = Number of ounces for solution B

A + B = 20

Now, we can use decimal conversions.

0.65A + 0.80B = 0.70(120)

Next step: We substitute A into 120 - B to show their relationship.

0.65(120 - B) + 0.80B = 84

Now onto the next equation:

78 - 0.65B + 0.80B = 84
0.80 - 0.65 = 0.15, so…

0.15B = 84 - 78
0.15B = 6
B = 6 divided by 0.15
B = 40 ounces

To find A, we can simply plug B into the starting equation.

A = 120 - 40
A = 60 ounces

Your final answer: The scientist should use 60 ounces of solution A and she should use 40 ounces of solution B. Yeah

Assume that 900 births are randomly selected and 4 at the births are girls. Use subjective judgment to describe the number of girls as significantly high, significantly low, or neither

Answers

The number of girls are significantly low.

What is Probability ?

Probability is the study of likeliness of an event to happen.

It is given that

900 births are randomly selected

The probability of birth of a boy or a girl is 1/2 = 0.5

Total chances of a girl is 900 * 0.5 = 450

The birth of girl observed is 4

Therefore the number of girls are significantly low.

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Given log base 2 =1/6, what is log base 4

Answers

Answer:

log x to the base 2 +log x to the base 4 =2

or log x/ log 2+ log x /lig 4 =2

or log x /log2 + log x /2.log 2 = 2

or log x/log 2(1+1/2)= 2

or log x/log 2 = 4/3

or 3.log x =4.log2

or logx^3=log 2^4

or x^3= 2^4

or x =(2)^4/3 or 2.(2)^1/3 ,Answer.

hope this helps

Step-by-step explanation:

The Rainbow Motor Motel is a 50-room facility with a restaurant to accommodate its guests. The motel is open 365 days a year, even on leap years; as Lurena Boucha, the proprietor, closes down the facility every February 29, her birthday, for an all day celebration of four years of successful operations. On the average, 98% of the rooms are available for sale. For the year just ended, the actual number of rooms sold totaled 15,000 and the number of guests for the year totaled 20,000. The projected occupancy rate for the next year is 82% of the available rooms based on past experience. The food information is as follows:

Sales $150,000, Beg Inventory 8,000, Purchases $70,000, Ending Inventory, $ 13,000 Consumption by employees (free of charge) $3,000, Number of checks 64,139. Cost of sales ?

Answers

From the information given, the cost of sales is $65,000. See the explanation below.

What is the definition of cost of sales?

Add your initial inventory to the purchases made over the time period, remove that amount from your ending inventory, and that is your cost of sales.

Cost of Sales = (Bi + P) - Ei

Where Bi is Beginning Inventory

P is Purchases; and

Ei is Ending Inventory.

So the derivation of the solution above is?

Beginning Inventory = 8,000

(add)          Purchase = 70,000

Bi + P                          = 78,000

Ending Inventory  = 13,000

Cost of sales = 78,000 - 13,000

= $65,000

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What should you substitute for y in the second equation (bottom equation) in order to solve the system by the substitution method?​

Answers

Answer:

C. 3x - 9

Step-by-step explanation:

3x – y = 9 ___(1)

8x – 4y = 0 ___(2)

From (1) eq.

3x – y = 9

– y = 9 – 3x

y = - (-3x + 9)

y = 3x – 9

Hence, 3x - 9 should be substituted in the second equation to get the required answer.

Answer:

c

Step-by-step explanation:

solve for y in the first equation

y = 3x - 9

when you substitute, you will get a value of 9 for x and 18 for y

cos^2 x = (1 - cos 2x)/2 A. True B. False

Answers

We know that cos2x=cos²x-sin²x

=cos²x-(1-cos²x)         [since, cos²x+sin²x=1]

=cos²x-1+cos²x

=2cos²x-1

So, cos2x=2cos²x-1

Hence, cos²x= (1+cos2x)/2

Trigonometric Identities are useful whenever trigonometric functions are involved in an expression or an equation. Trigonometric Identities are true for every value of variables occurring on both sides of an equation. Geometrically, these identities involve certain trigonometric functions (such as sine, cosine, tangent) of one or more angles.

Most common trigonometric identities are:

- cos²x + sin²x = 1

- sec²x - tan²x = 1

- cosec²x - cot²x = 1

- cos2x = cos²x - sin²x

Therefore we get that the statement cos² x = (1 - cos 2x)/2 is false.

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Triangle X Y Z is shown. The length of X Z is 12, the length of Y Z is 11, and the length of Y X is 6.
A scalene triangle has the lengths 6, 11, and 12. Keyla uses the law of cosines to find the measure of the largest angle. Complete her work and find the measure of angle Y to the nearest degree.

1. 122 = 112 + 62 − 2(11)(6)cos(Y)

2. 144 = 121 + 36 − (132)cos(Y)

3. 144 = 157 − (132)cos(Y)

4. −13 = −(132)cos(Y)

Answers

According to law of cosines if the lengths of triangle are 12,11,6 then the angle will be 114=157-132cos(Y)

Given the length of XZ is 12, length of YZ is 11 and the length of YX=6.

According to law of cosines the angle of a triangle when the length of sides are given can be written as:

[tex]c^{2} =a^{2} +b^{2} -2abcosd[/tex]

where c is the side opposite to the angle which we have to find and a and b are the rest sides.

We have to put the values of sides in the above law:

[tex]12^{2} =6^{2} +11^{2} -2*6*11cosY[/tex]

144=36+121-132 cos Y.

Hence the angle can be written as 144=36+121-132 cos Y.

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Find the value of x.

2x
70
120

Answers

The value of X is 10

can someone help me ​

Answers

Answer:

See Pictures

Step-by-step explanation:

Which ordered pair is a solution of the equation?
y=4x−7

Answers

Answer:

Unknown

Step-by-step explanation:

Hi! so you didn't add the ordered pair options but I will do my best :) so if you see the ordered pair (0.7) that could definitely be a solution because using the slope intercept form equation you gave I know that's our y Intercept. the slope is 4/1 so moving up 4 and to the right 1 or down 4 and to the left 1 on a graph could show you more points! If you don't want to draw it you could use Desmos and just put this equation in or give me the ordered pairs and I will give you your answer!

hope this helps :)

any solutions will each system of linear equations have? Match the systems with the correct number of
Solutions

Answers

Based on the information given, the correct options will be

y = x + 6 and 3x - 3y = -18 .... Infinitely many solutions.

y = -2x + 5 and 2x + y = -7 .... No solution.

y = -4x + 11 and -6x + y = 11 ... One solution.

Solving equations

y = -4x + 11 ....... equation i

-6x + y = 11 ...... equation ii

Put equation i into ii.

-6x + y = 11

-6x + (-4x + 11) = 11

-6x - 4x + 11 = 11

-6x - 4x = 11 - 11

-10x = 0

x = 0

Therefore, x = 0 and y = 11. This gives a solution for each variable.

y = -2x + 5 ..... i

2x + y = -7 ..... ii

Put equation I into ii

2x + y = -7

2x + (-2x + 5) = -7

2x - 2x = -7 - 5

0 = -12

This indicates no solution.

y = x + 6 ..... i

3x - 3y = -18 ..... ii

Put equation I into ii

3x - 3y = -18

3x - 3(x + 6) = -18

3x - 3x - 18 = -18

3x - 3x = - 18 + 18

0 = 0

This implies that there are infinitely many solutions.

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If REX ~ ROB, find the value of a.​

Answers

Answer: 8

Step-by-step explanation:

As corresponding sides of similar triangles are proportional,

[tex]\frac{RX}{RB}=\frac{XE}{BO}\\\\\frac{6}{15}=\frac{a}{20}\\\\a=20\left(\frac{6}{15} \right)=\boxed{8}[/tex]

How do I get this answer?

Answers

Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

cos(2x) = cos²(x) -sin²(x)cos²(x) +sin²(x) = 1cos(x) = 1/sec(x)

Proof

Starting with the left side, we can transform it into the right side.

  [tex]2\cos(2x)=2(\cos^2(x)-\sin^2(x)) = 2(\cos^2(x)-(1-\cos^2(x)))\\\\=2(2\cos^2(x)-1)=2\left(\dfrac{2}{\sec^2(x)}-\dfrac{\sec^2(x)}{\sec^2(x)}\right)\\\\=\boxed{\dfrac{4-2\sec^2(x)}{\sec^2(x)}}[/tex]

What is the result of M x H?????

I have asked 4 tutors and none of them know how to answer this.

Answers

Answer: m x H = [ -9  36  - 9/2 ]

Step-by-step explanation:

Write the number five and a quarter million in figures.

Answers

Answer:

5 and a 250,000

Step-by-step explanation:

A quarter million = 1,000,000 · [tex]\frac{1}{4}[/tex] = 250,000

Answer:

It is: 5,250,000

A company makes Citi bikes. 95% (i.e., 0.95) pass final inspection. Suppose that 5 bikes are randomly selected. ( use binomial distribution formula ) do I need to use a factorial symbol V! When showing steps by step

a) What is the probability that exactly 4 of these 5 sports bikes pass final inspection?
b) What is the probability that less than 3 of these 5 sports bikes pass final inspection?
I got disconnected with my tutor

Answers

Using the binomial distribution, it is found that the probabilities are given as follows:

a) 0.2036 = 20.36%.

b) 0.0011 = 0.11%.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.

The values of the parameters are given as follows:

p = 0.95, n = 5.

Item a:

The probability is P(X = 4), hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 4) = C_{5,4}.(0.95)^{4}.(0.05)^{1} = 0.2036[/tex]

Item b:

The probability is P(X < 3), hence:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2).

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{5,0}.(0.95)^{0}.(0.05)^{5} \approx 0[/tex]

[tex]P(X = 1) = C_{5,1}.(0.95)^{1}.(0.05)^{4} \approx 0[/tex]

[tex]P(X = 2) = C_{5,2}.(0.95)^{2}.(0.05)^{3} = 0.0011[/tex]

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0 + 0.0011 = 0.0011.

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Ms. Jerome wants to buy identical boxes of art supplies for her 25
students. If she can spend no more than $375 on art supplies,
what inequality describes the price can she afford for each
individual box of supplies, b?

Answers

The inequality describes the price $375  she can afford for 25

individual box of supplies will be $375 ≥ 25x.

What is inequality?

An inequality is comparison of  two values, showing if one is less than, greater than, or simply not equal to another value.

Let the price of each box is $x.

The inequality describes the price can she afford for each

individual box of supplies will be $375 ≥ 25x.

Therefore inequality is $375 ≥ 25x.

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Algebra 2 help needed image below

Answers

Answer:

8x + 100

Step-by-step explanation:

Your answer is correct! But because the equation is already set to "y =", you do not need the "f(x)" in your equation.

A group fitness gym classifies its fitness class attendees by class type and member status. The marketing team has gathered data from a random month, in which there
were 2039 class attendees. The data is summarized in the table below.
Class Type and Member Status of Class
Attendees
Class Type
Barre
Boot Camp
Boxing
Spinning
Yoga
Member
.240
204
288
191
177
Non-Member
185
155
234
271
94
What is the probability that a class attendee is a non-member of the gym and is attending a barre class or is a member of the gym and is attending a boot camp class?
Enter a fraction or round your answer to 4 decimal places, if necessary.

Answers

The probability that a class attendee is a non-member of the gym and is attending a barre class or is a member of the gym and is attending a boot camp class is 0.009.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The marketing team has gathered data from a random month, in which there were 2039 class attendees.

The probability that a class attendee is a non-member of the gym and is attending a barre class

= 185/2039

= 0.09

The probability that a class attendee is a member of the gym and is attending a boot camp class

= 204/2039

= 0.10004

The probability for both the event would be

= 0.09 x 0.10004

= 0.009

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What is the solution of the following system?

Use the substitution method.

{3x+2y=11x−2=−4y

A.) The only solution is (12, - 5/2)
B.) The only solution is (4, - 1/2)
C.) There is no solution
D.) There are an infinite number of solutions

Answers

Answer:

  B.) The only solution is (4, - 1/2)

Step-by-step explanation:

To solve this system of equations using the substitution method, we need to use one equation to find an expression for one of the terms or variables that can be substituted for that term or variable in the other equation.

__

expression for x

Here, it is convenient to use the second equation to write an expression for x:

  x -2 = -4y

  x = 2 -4y . . . . add 2 to both sides

substitute

Using this expression for x, we can write the second equation as ...

  3x +2y = 11

  3(2 -4y) +2y = 11 . . . . . substitute for x

  6 -10y = 11 . . . . . . . . eliminate parenthses

solve

This 2-step equation can be solved in the usual way:

  -10y = 5 . . . . . . . subtract the constant to isolate the variable term

  y = -5/10 = -1/2 . . . . . divide by the coefficient of the variable

  x = 2 -4(-1/2) = 2 +2 = 4 . . . . . find the corresponding x-value

The only solution is (x, y) = (4, -1/2).

The only solution is (x, y) = (4, -1/2). so, the correct option is B.

What is a system of equations?

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

we have the system of equations;

3x+2y=11

x−2=−4y

By the substitution method;

use the second equation to write an expression for x:

 x -2 = -4y

 x = 2 -4y

substitute

 3x +2y = 11

 3(2 -4y) +2y = 11

 6 -10y = 11

solve

 -10y = 5

 y = -5/10 = -1/2

 x = 2 -4(-1/2)

x = 2 +2 = 4

Thus, The only solution is (x, y) = (4, -1/2). so, the correct option is B.

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In the figure shown below, AC is parallel to DE with transversal BF

Determine the values of x and y

PLEASE SHOW WORK FOR THIS!


x=_______
y=_______

Answers

Answer:

X = 142°Y = 38°

Given - AC is parallel to DE

angle 3y + 28 = angle X ( Vertically opposite angles are equal).

3y + 28 = X

X + Y = 180° ( supplementary angles).

3y - X = (-28)

Solving both the equation we get

multiply eq 1 with 3

3x + 3y = 540

-X + 3y = (-28)

subtracting

4x = 568

x = 142°

3y + 28 = 142

3y = 142 - 28

3y = 114

y = 38°

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