[tex]\textsf {Finding y :}[/tex]
[tex]\implies \mathsf {1^{2} + y^{2} = 3^{2}}[/tex]
[tex]\implies \mathsf {y^{2} = 8}[/tex]
[tex]\implies \mathsf {y = 2\sqrt{2}}[/tex]
[tex]\textsf {Finding z :}[/tex]
[tex]\implies \mathsf {(2\sqrt{2})^{2}+8^{2}=z^{2}}[/tex]
[tex]\implies \mathsf {z^{2} = 72}[/tex]
[tex]\implies \mathsf {z = 6\sqrt{2}}[/tex]
Answer:
z =8.49 or 6[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Do the Pythagorean theorem = [tex]a^{2} +b^{2} =c^{2}[/tex]
Length of hypotenuse = 8+1=9
length of one side = 3
so, a²+3²=9²
a²+3²=9²
a²=81-9
a²=72
a=√72=8.49 or 6[tex]\sqrt{2}[/tex]
Bob sets the price of the plants according to their height in inches. A plant that is 9.5 inches high costs $2.28 in his store. What is the price per inch of a plant? Show your calculation.
Characters used: 21 / 15000
Part E
What is the price of a plant that is 5.5 inches high? Show your calculation.
Answer: $0.24
Step-by-step explanation:
9.5 inches --> $2.28
1 inch--->X
now cross multiply it and get,
9.5X = 2.28*1
X = 2.28/9.5
so its $0.24 per inch
the tabel shows the time merrida spent driving and the number of miles she drove she drove the same number of miles each other
Answer:
35 miles/hour
Step-by-step explanation:
See attached image.
Tawny wrote an expression to represent “the quotient of 82 and a number, decreased by 26.” She then evaluated the expression when n = 2. Which statements are true about the expression and its value? Check all that apply.
The correct expression is 82 minus StartFraction 24 Over n EndFraction.
To evaluate the expression, subtract 26 from the quotient.
To evaluate the expression, subtract the quotient from 82.
The correct expression is StartFraction 82 Over n EndFraction minus 26.
The operations include division and subtraction.
To evaluate, substitute 24 for the variable in the equation.
The value of the expression is 15.
The value of the expression (82/n – 26) at n = 2 will be 15. Then the correct options are B, D, E, and G.
What is division?Division means the separation of something into different parts, sharing of something among different people, places, etc.
Tawny wrote an expression to represent “the quotient of 82 and a number, decreased by 26.”
She then evaluated the expression when n = 2.
Then the expression will be
⇒ 82 / n – 26
If the value of n is 2, then the value of the expression will be
⇒ 82 / 2 – 26
⇒ 41 – 26
⇒ 15
Then the correct options are B, D, E, and G.
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If M is the midpoint in the figure, find MQ and PQ.
Answer:
pm = 4
M is the mid point of PQ which means that pm = mq
so MQ = 4
PQ = PM + MQ
= 4 + 4
= 8
X^2 + y^2 = 81 write down the equations of the two horizontal lines that are tangent to c
Answer:
Step-by-step explanation:
x² + y² = 81
x + y = √81
x + y = 9
x ≥ 9
y ≤ 9
The heights of adult men in the united states are approximately normally distributed with a mean of 70 inches and a standard deviation of 3 inches. use this information together with the 68-95-99.7 rule to make three statements about the height of adult men in the united states.
Answer:
Use the graphing calculator to graph the system of equations and find the solution where x is the total hats sold and y is the total t-shirts sold.
x + y = 152,
8.5x + 12y = 1,656
How many hats were sold?
hats
Step-by-step explanation:
a) 74.857% of adult men are shorter than Michael
b) 84.134% of adult men are taller than Jack
c) 58.991% of adult men are of height between Jack and Michael
What is 68-95-99.7 rule?Within one standard deviation of the mean is 68% of the population. Within two standard deviations of the mean, 95% of the population is located. The median is within 3 standard deviations for 99.7% of the population.
Given:
µ = 70in, σ = 3in.
We know Z = (x-µ)/σ
a) Actor Michael B. Jordan is 6’0” (72”) tall.
Z = (72-70)/3 = 0.67
So, the probability of an adult man having a height of 0-72 inches, and no greater is 74.857%
b. Comedian Jack Black is 5’7’ (67”) tall.
Z = (67-70)/3 = -1
The corresponding value is .15866 which can be the probability of an adult man having a height of 0-67 inches, and no greater.
But the percentage of those taller than jack is = 1 – .15866 = 0.84134
c) P(X < 72) – P(x < 67)
= 0.74857 – 0.15866
= 0.58991
= 58.991%
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The Question attached here is incomplete, the complete question is
a. Actor Michael B. Jordan is 6’0” (72”) tall. What percentage of adult men are shorter than Michael?
b. Comedian Jack Black is 5’7’ (67”) tall. What percentage of adult men are taller than Jack?
c. What percentage of adult men are of height between Jack and Michael?
Pool A starts with 300 gallons of water. It has a leak and is losing water at a rate of 6 gallons of water per minute. At the same time, Pool B starts with 400 gallons of water and also has a leak. It is losing water at a rate of 10 gallons per minute. The variable t represents the time in minutes. After how many minutes will the two pools have the same amount of water? How much water will be in the pools at that time?
Answer:
25 minutes
150 gallons
Step-by-step explanation:
Definition of variables
Let t = time in minutes
Let V = volume in gallons
Create two equations with the given information:
Pool A
Starting volume = 330 gallonsLeak rate = 6 gallons/min⇒ V = 300 - 6t
Pool B
Starting volume = 400 gallonsLeak rate = 10 gallons/min⇒ V = 400 - 10t
To find after how many minutes the two pools will have the same amount of water, substitute the equation for pool A into the equation for pool B and solve for t:
⇒ 300 - 6t = 400 - 10t
⇒ 300 - 6t + 10t = 400 - 10t + 10t
⇒ 300 + 4t = 400
⇒ 300 + 4t - 300 = 400 - 300
⇒ 4t = 100
⇒ 4t ÷ 4 = 100 ÷ 4
⇒ t = 25
Therefore, the two pools will have the same amount of water after 25 minutes.
To find how much water will be in the pools at that time, substitute the found value of t into one of the equations and solve for V:
⇒ V = 400 - 10t
⇒ V = 400 - 10(25)
⇒ V = 400 - 250
⇒ V = 150
Therefore, the amount of water in the pools at the time when they have the same amount of water is 150 gallons.
If time be x and volume be y
The equations are
y=300-6ty=400-10tEquate and solve
300-6t=400-10t4t=100t=25minNow
y=400-10(25)y=400-250y=150gallonsy>-3x +3
y≥ 2x-2
O (1,0)
O (-1,1)
O(2,2)
(0,3)
Answer:
(1,0)
Step-by-step explanation:
y>-3x +3
y≥ 2x-2
If we plot these two inequalities, we can see where the lines intersect, See attached graph.
They intersect at (1,0)
We can also do this mathematically:
y>-3x +3
- (y≥ 2x-2)
0 [tex]\geq[/tex] -5x + 5
5x [tex]\geq[/tex] 5
x [tex]\geq[/tex] 1
If x = 1:
y≥ 2x-2
y≥ 2(1)-2
y≥ 0
(x,y) = (1,0)
Solve x+ 2y = -2 I’m really confused
Answer:
y=−1/2x−1
Step-by-step explanation:
I put it in slope intercept form as I assume that is what the question is asking.
If triangles ABC and DEF are congruent, then find the measure of DE.
Answer:
DE = 3 UnitsReason -
In the question it is given that triangle ABC is congruent to triangle DEF
if a triangle is congruent to other triangle than the corresponding parts of it (.ie sides and angles) are equal to that of other
A fair die is rolled 4 times in succession. What is the probability that the number on each roll is strictly less than the number on the previous roll
The probability that the number on each roll is strictly less than the number on the previous roll is 7/72
The number of such results in which each number is not less than the previous number will be equal to the number of ways of choosing 4 numbers out of 6 with replacement; regardless of order!
Let us choose any such set of size 4, say {2, 1, 1, 3}. we can sort it to get the sequence {1,1,2,3}, which is one of our desired results. Thus, each sequence ordered in this way corresponds to one selection of size 4, with replacement and regardless of order.
The number of such selections will be equal to the number of solutions to the following equation:
x1 + x2 + x3 + x4 + x5 + x6 = 4
where:
x1: number 1 in selections
x2: number of 2s in selection
.
.
x6: number of 6s in selection
The number of unique solutions of such an equation = 9, choose 5 = 126
Number of possible outcomes = 6^4 = 1296
Probability of favorable results = 126/1296=7/72
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A four line classified ad costs 25 for a week. Each additional line costs 2. What is the weekly cost for a 12 line ad
Answer: 41
Step-by-step explanation:
If each line costs 2, then for the four-line ad, the cost is the initial price plus 4(2), meaning the initial cost is 25-8=17.
Thus, the cost of a 12-line ad is 17+2(12)=41
Mei Mei left her house at time zero and drove for 4 minutes to the store, at a speed of 2 blocks per minute. Then she stopped and went into the store for 5 minutes. From there, she drove in the same direction at a speed of 5 blocks per minute until she got to the bank, which is 10 blocks away from the store. She stopped at the bank for 2 minutes. Then she drove home at a speed of 3 blocks every minute. Make a graph of showing the number of blocks away from home that Mei Mei is xx minutes after she leaves her house, until she gets back home.
The graph for Mei Mei' trip is attached accordingly. Also attached are the values derived from the question.
What is the explanation for the graph?The secret to comprehending the graph is to understand that every time Mei Mei spent while she was on the way to bank and back were are all computed cumulatively.
This means that when she stops at the store which is 8 blocks away from home (that is 2 blocks per min x 4 mins = 8blocks) the time spent is recorded as 4 + 5 at location 8 blocks, which is equals 9 minutes.
Also take note of the fact that the time spent is plotted on the x-axis and the blocks away from home on the y-axis.
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A sequence of numbers begins with 12 and progresses
geometrically. Each number is the previous number
divided by 2.
Which value can be used as the common ratio in an
explicit formula that represents the sequence?
N/H
02
06
O 12
Answer:
1/2
Step-by-step explanation:
since every time you divide by 2, the common ratio is 1/2
Helppp!!!
[tex] \dfrac{2}{15} \div \dfrac{20}{3} [/tex]
.........
[tex]{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}[/tex]
[tex] \sf \dfrac{2}{15} \div \dfrac{3}{20} = \dfrac{2 \times 20}{15 \times 3} = \dfrac{40}{45} = \dfrac{8}{9} [/tex]
Answer :-
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \Rrightarrow \dfrac{8}{9} [/tex]
I hope I've helped : )
[tex]\dfrac{1}{50}[/tex]
Step-by-step explanation:1. We multiply.[tex] \cfrac{2}{15} \times \cfrac{3}{20} [/tex]
2. We join the fractions and put it only in 1.[tex] \cfrac{2 \times 3}{15 \times 20} [/tex]
3. We multiply the one above which is 2 × 3.[tex] \cfrac{6}{15 \times 20} [/tex]
4. Now we will multiply the below.[tex] \cfrac{6}{300} [/tex]
5. Now we simplify.[tex] \cfrac{1}{50} [/tex]
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If two angles are supplementary, and the angle measurements are in the ratio 3:1, what is the measure of the smaller angle?
Answer:
The measure of smaller angle = 45°
Step-by-step explanation:
Finding the unknown angle
Ratio of the supplementary angles = 3 :1
The angles are 3x , x
Supplementary angles add up to 180°
3x + x = 180
4x = 180
x = 180 ÷ 4
x = 45°
3x = 3*45 = 135°
the answer to this is 40=
Step-by-step explanation:
I did this
Find the nth term of the sequence 3, -1, -5, -9.
Answer:
-4n+7
Step-by-step explanation:
because you take away 4 each time and the nber that would come before 3 is 7.
Express ratio 3.5:14 as 1:n
Answer:
1 : 4
Step-by-step explanation:
3.5 : 14 ( divide both parts by 3.5 )
= 1 : 4
Solve the following please:
Answer:
most likely b
Step-by-step explanation:
the more than symbol tells me that it is going to move past 10.
Find the perimeter of the triangle.
23.
7 in.
(x + 4) in.
(4x + 1) in.
Answer:
17 in.
Step-by-step explanation:
There are two same angles shown, so two sides are equal. We can form an equation x+4=4x+1. Solution is x=1, then both unknown sides are 5 in. long. Given all side lengths we add them 7+5+5+15 getting the perimeter.
which two values of x are roots of the polynomial below?
x^2 + 5x + 9
Answer:
The answer:
A. [tex]x= \frac{-5+ \sqrt{-11} }{2}[/tex]
F.[tex]x= \frac{-5- \sqrt{-11} }{2}[/tex]
Step-by-step explanation:
Step 1: Solve with quadratic formula
[tex]x_{1},2 = \frac{-b+- \sqrt{b^2}- 4ac }{2a}[/tex]For [tex]a=1, b=5, c=9\\x_{1},2 = \frac{-5 + \sqrt{5^2 -4 *1 *9} }{2*1}[/tex]Step 2: Simplify
[tex]\sqrt{5^2 - 4 *1 *9} : \sqrt{11} i[/tex]Multiply the numbers: [tex]4*1*9 = 36[/tex][tex]i\sqrt{ 36 -5^2}[/tex] = [tex]\sqrt{-5^2 + 36} = i\sqrt{11}[/tex][tex]5^2 = 25 = \sqrt{-25 + 36}[/tex]Add/subtract the numbers [tex]-25 +36 = 11 = \sqrt{11} = \sqrt{11}i[/tex]Step 3: Separate the solution
[tex]x_{1} = \frac{-5 + \sqrt{-11}i}{2} , x_{2} = \frac{-5 - \sqrt{-11}i}{2}[/tex]Answer:
[tex]\large {\textsf{A and F}}\ \implies \bold{x_1}=\dfrac{-5-\sqrt{-11}}{2},\ \bold{x_2}=\dfrac{-5+\sqrt{-11}}{2}[/tex]
Step-by-step explanation:
Quadratic Formula: [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Standard Form of a Quadratic Equation: ax² + bx + c = 0, where a ≠ 0.
Given polynomial: x² + 5x + 9
⇒ a = 1, b = 5, c = 9
Step 1: Rewrite to Standard Form.
⇒ x² + 5x + 9 = 0
Step 2: Substitute the values of a, b, and c into the formula.
⇒ a = 1, b = 5, c = 9
[tex]x=\dfrac{-5\pm\sqrt{\bold{5^2}-4\bold{(1)(9)}}}{\bold{2(1)}}\\\\x=\dfrac{-5\pm\sqrt{25\bold{\ - \ 4(9)}}}{2}\\\\x=\dfrac{-5\pm\sqrt{\bold{25-36}}}{2}\\\\x=\dfrac{-5\pm\sqrt{-11}}{2}[/tex]
Step 3: Separate into two possible cases.
[tex]x_1=\dfrac{-5-\sqrt{-11}}{2}\\\\x_2=\dfrac{-5+\sqrt{-11}}{2}[/tex]
Other examples:
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Identify the Property of Equality that is used in each statement.
If x=2, then 2x = 4.
5= 3a; therefore, 3a = 5.
If T=4, then 5T + 7 equals 27.
If 9 = 4x and 4x = m, then 9 = m.
Step-by-step explanation:
x = 2. 2(x) = 2(2). 2x= 4. Multiplication Property of Equality (if you have two equals sides and then multiply them by the same quantity both sides will remain equal)
5=3a therefore 3a = 5. Symmetric Property if a=b then b=a
T = 4 => 5T = 20 (Multiplication Property of Equality) => 5T + 7 = 27 (Addition Property of Equality. basically if two sides are equal and you add the same quantity they will remain equal)
Last one is transitive property which states. if a=b and b=c then a=c so in this case a would be 9, b would be 4x and c would be m
Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| + 1 > 7/2
The graph is shown below:
What is inequality?A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.
Rearrange unknown terms to the left side of the equation:
|x| > 7/2-1
Now,
|x| > (7-2)/ 2
Calculate the sum or difference:
|x| > 5/ 2
Convert the absolute inequality to standard inequality:
x> 5/2 or x< -5/2
Solve the inequality:
x> 5/2
Solve the inequality:
x< -5/2
Graph on number line is attached
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The two conditional relative frequency tables below show the results of a survey asking students whether they are taking a foreign language or not.
A 4-column table with 3 rows. The first column has no label with entries middle school, high school, total. The second column is labeled taking a foreign language with entries 0.34, 0.66, 1.0. The third column is labeled not taking a foreign language with entries 0.64, 0.36, 1.0. The fourth column is labeled total with entries 0.4, 0.6, 1.0.
Table B: Frequency of Foreign-Language Studies by Row
A 4-column table with 3 rows. The first column has no label with entries middle school, high school, total. The second column is labeled taking a foreign language with entries 0.68, 0.88, 0.8. The third column is labeled not taking a foreign language with entries 0.32, 0.12, 0.2. The fourth column is labeled total with entries 1.0, 1.0, 1.0.
Which table could be used to answer the question "Assuming a student is taking a foreign language, what is the probability the student is also in high school?”
Table A, because the given condition is that the student is in high school.
Table A, because the given condition is that the student is taking a foreign language.
Table B, because the given condition is that the student is in high school.
Table B, because the given condition is that the student is taking a foreign language.
Option fourth ''Table B, because the given condition is that the student is taking a foreign language" is correct.
What is a conditional relative frequency?It is defined as the frequency that can be evaluated by the two-way frequency table. Usually, we can obtain this frequency by dividing the frequency that is not in the total frequency cell by the total frequency.
We have two tables given in the question.
The conditional relative frequency tables show the results of a survey asking students whether they are taking a foreign language or not.
The condition is: "Assuming a student is taking a foreign language"
Table B can be used to answer the above statement.
Thus, option fourth ''Table B, because the given condition is that the student is taking a foreign language" is correct.
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Answer:
Option b: Table A, because the given condition is that the student is taking a foreign language.
Step-by-step explanation:
on ed
Camille bought 120 doughnuts for $60. Her profit was $48 once she sold 80 doughnuts. Write an
equation that represents Camille's profit P, as a function of the number of doughnuts sold, n.
PLEASE HELP WITH SHOWED WORK!!!
The equation that represents Camille's profit p as a function of the number of doughnuts sold, n is P = 1.35n - 60
How to represent an equation ?She bought 120 doughnuts for $60.
Therefore,
cost = $60
Her profit was $48 once she sold 80 doughnuts.
p = profit
n = number of doughnuts sold.
Therefore,
let
x = amount she is selling each doughnuts
p = nx - 60
Using the information given we have:
48 = (80x) - 60
Therefore,
x = $1.35
Hence, for any number of doughnuts then, we have the profit equation as follows:
P = 1.35n - 60
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Solve the inequality. –6 < 2 x – 4 < 4
Step-by-step explanation:
-6<2x-4<4
-2<2x<8
-1<x<4
x = (-1,4)
HELP !
Which of the following best describes the slope of the line below?
• A. Negative
O B. Zero
• C. Positive
D. Undefined
4. Fill in the blanks for the following proof:
Answer:
Step-by-step explanation:
Fraction
Puja Limbu did 8 out of 10 math problems and Raju lama did 11 out of 15 similar maths problems.Express the number of problems solved by each of them in fractions and identify who did better performance.
Using percentages, we have that Puja Limbu did 80% of the problems and Raju Lama did 73.3%, hence Puja Limbu had the better performance.
What is a percentage?The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:
[tex]P = \frac{a}{b} \times 100\%[/tex]
The percentage for Puja Limbu is:
[tex]P = \frac{8}{10} \times 100\% = 80\%[/tex]
The percentage for Raju Lama is:
[tex]P = \frac{11}{15} \times 100\% = 73.3\%[/tex]
80% > 73.3%, hence Puja Limbu had the better performance.
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If a varies directly as the square of b, and a = 4 when b = 3, find a when b = 2
Answer:
a = 46. Look down to find out more↓:
Step-by-step explanation:
a = kb²
4 = k(3)²
4 = k9
k = 4/9
a = 4/9(9²)
a = 4/9 (81)
a = 324/9
a = 36