y=5+3x for x
Show work

Answer: 8788

Step-by-step explanation:

Use the formula and use 3 for pi

13cm is the radius

[tex]13^{3\\[/tex] = 2197

2197 x 3 = 6591

6591 x 4/3 = 8788

Therefore the solution to this equation is imaginary given by x = [tex]\rm \dfrac { 3 \pm \sqrt{-3}}{2}[/tex]

A Quadratic equation is an equation that can be written in the form of

ax² +bx+c = 0

The solution of the given quadratic equation

x² -3x +3 = 0

the roots of the equation is given by

[tex]\dfrac { -b \pm \sqrt{b^2 -4ac}}{2a}[/tex]

here a = 1 , b = -3 , c = 3

Substituting the values

The solution is

[tex]\rm \dfrac { 3 \pm \sqrt{(-3)^2 -4*1 *3}}{2}[/tex]

Therefore the solution to this equation is imaginary

given by

x = [tex]\rm \dfrac { 3 \pm \sqrt{-3}}{2}[/tex]

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The angle BAC will be 29 and the angle BOC will be 58.

The angle in a circle's centre is twice that at its perimeter when two angles are subtended by the same arc. So, angle AOB = 2 angle ACB. Angles that the same arc subtends at its circumference are equal. As a result, angles inside a section are equal.

Here the given angle is ∠BDC = 29 so from the given theorem the angle BEC will be equal to the angle BDC.

∠BDC = 29

The centre angle BOC will be twice the angle at the circumference so the angle will be twice.

∠BOC = 59

Therefore the angle BAC will be 29 and the angle BOC will be 58.

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#1

As d is days

So days can't be negative

hence domain is W or Whole numbers set.

But according to the equation

Round to next whole as it's no of days

d=2

Domain=[2,oo)

#b

Put d=0

f(0)

It passes through (0,7)

But 0 is not in domain ,hence no y intercept in real

#C

f(11)

f(4)

Rate of change

It represents change in radius

The points D(-7, 5), E(-8, -3), and H(10, -5) will not be visible the answers are D, E, and H.

A graphing calculator is a portable computer that can plot graphs, solve multiple equations at once, and carry out other variable-related activities.

We have points shown in the coordinate plane.

As the window of a graphing utility is set at:

X(min) : -6

X(max): 6

Y(min) : -6

Y(max) : 6

The points out of 6 will not be visible.

We can draw a square as shown in the attached picture.

The points D(-7, 5), E(-8, -3), and H(10, -5) will not be visible.

Thus, the points D(-7, 5), E(-8, -3), and H(10, -5) will not be visible the answers are D, E, and H.

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Answer:

[tex]6y^1^6[/tex]

Step-by-step explanation:

I hope this has Helped :)

x=  10, NL= 8 , NP = 12

A secant is a line that intersects a curve at a minimum of two distinct points.

Using secant theorem,

NL* NM = NP* NO

(3+5)*3 = (2+x)*2

24=  (2+x)*2

12= 2+x

x= 12-2

x= 10

So, NP= 2+x

     NP = 12

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Answer:

the answer is 0

Step-by-step explanation:

because anything multiply by 0 is 0.

Can make me the brainliests answerer?Please

The value of x from the given diagram is -6

Line is defined as the distance between two points. Given the line RP with the following measures

RP = 17

RQ = x + 14

QP = x + 15

Using the expression

RP = RQ + QP

Substitute

17 = x + 14 + x + 15

17 = 2x + 29

Determine the value of x

2x = 17 - 29
2x= -12

x = -6

Hence the value of x from the given diagram is -6

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Answer:

1/3×22/7×r^2h

Step-by-step explanation:

the volume =1/3 ×22/7×r^2×13.5

A ratio shows how many times one number contains another.

Hence, the sand is in the ratio [tex]\frac{1}{6}[/tex] of the mixture is

[tex]\frac{1}{6}[/tex]×[tex]1800=300kg[/tex]

The Gravel is in the ratio [tex]\frac{2}{6}[/tex]×[tex]1800=600kg[/tex]

And the cement is in ratio [tex]\frac{3}{6}[/tex]×[tex]1800=900kg[/tex]

What is the ratio ?

A ratio is an ordered pair of numbers [tex]a[/tex] and [tex]b[/tex], written [tex]\frac{a}{b}[/tex] where [tex]b[/tex] does not equal [tex]0[/tex]. A proportion is an equation in which two ratios are set equal to each other.

Here the given ratio is [tex]1:2:3[/tex].

Here given that,

The dry concrete is   [tex]1800kg[/tex].

And the multiplication of the ratio is [tex]1[/tex]×[tex]2[/tex]×[tex]3=6[/tex]

Hence, the sand is in the ratio [tex]\frac{1}{6}[/tex] of the mixture is

[tex]\frac{1}{6}[/tex]×[tex]1800=300kg[/tex]

The Gravel is in the ratio [tex]\frac{2}{6}[/tex]×[tex]1800=600kg[/tex]

And the cement is in ratio [tex]\frac{3}{6}[/tex]×[tex]1800=900kg[/tex]

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The domain of the linear function is a real number, and the range of the linear function is also a real number.

The domain means all the possible values of x and the range means all the possible values of y.

The table is given below.

  x               y

 -4              5

 -2              3

  0              1

  2             -1

  4             -3

Then the linear function will be

y – 1 = [(5 – 1) / (- 4 – 0)] (x – 0)

y – 1 = -x

x + y = 1

Then the domain of the linear function is a real number and the range of the linear function is also a real number.

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The probability that favourite basketball player make all 12 is 0.

Give 90% free- throw percentage of favourite basketball player and he has taken 12 shots in the game.

Probability is the chance of happening an event among all the events possible. It lies between 0 and 1.

This is a binomial probability question "makes" is what some writer call a "success". In the binomial probability distribution, the probability of r successes in trials is :

=[tex]nC^{r}[/tex][tex]p_{r}p^{r}(1-p)^{n-r}[/tex]

p is the probability of "success" n p r=n!/((n-r)!

n [tex]p_{n}[/tex]=0

In this problem , n=12, r=12,p=0.9. the probability of exactly 12 made shots out of 12 attempted is 12[tex]C_{12} (0.90)^{12} (1-0.90)^{0}[/tex].

=12!/12!(12-12)!*[tex](0.90)^{12}(0.10)^{0}[/tex]

=0

Hence the probability that they make all 12 is 0.

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The range of the function lies between (0,8) to (1.5,1.25).

Range and Domain. The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

The given function is:-

f(x) = 3x² -9x + 8

The value of the range will be from (0,8) to ( 1.5,1.25). When we plot the graph of the function the value of the range lies between the points (0,8) to ( 1.5,1.25). The graph is attached with the answer.

The domain of the function will be all the values of the real numbers for the function ranges from ( 0, ∞ ).

Therefore the range of the function lies between (0,8) to (1.5,1.25).

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The correct option is Option D: the approximate loudness of a dinner conversation will be 50Db with a sound intensity 10⁻⁷.

The loudness L, ( which is measured in decibels (Db)), of the sound of the intensity I, can be calculated in watts per square meter,

L = 10 log(I/I₀)  

where I₀ = 10⁻¹²  which is the least intensity that a human can hear.

The sound intensity of a dinner conversation= I= 10⁻⁷

Loudness L of that conversation = 10 log (10⁻⁷/10⁻¹²)

= 10 log(10⁻⁷⁻⁽⁻¹²⁾)

= 10 log(10⁻⁷⁺¹²)

= 10 log(10⁵)

= 10*5

= 50 Db

Therefore the correct option is Option D: the approximate loudness of a dinner conversation will be 50Db with a sound intensity 10⁻⁷.

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Answer:

Step-by-step explanation:

Answer:

f(1) = 2

f(n) = 2 × f(n - 1) , n ≥ 2

Step-by-step explanation:

the point of coordinates (1 , 2) is on the graph

Then

f(1) = 2

…………………………

We notice that :

f(2) = 4

f(3) = 8

f(4) = 16

16/8 = 8/4 = 4/2 = 2/1 = 2

________________________

This means the common ratio

of the geo sequence = 2

Hence ,

f(n) = 2 × f(n - 1)

Answer: f(n) = 2 × f(n - 1) , n ≥ 2

Step-by-step explanation:

The cross-section parallel to the base of a cone is a circle

The cross-section parallel to the base of a cylinder is a circle

The cross-section perpendicular to the base of a cone is a triangle

The cross-section perpendicular to the base of a cylinder is a rectangle

Answer:

Group A, because seven children have a forearm length longer than 10 inches

Step-by-step explanation:

Create the dot plots based on the given information (please see attached images).

Group A = blue dots

Group B = red dots

From inspection of the attached dot plots, we can see that Group A appears to have the longer average forearm length.  This is because 7 children have a forearm length of longer than 10 inches.

To calculate the average forearm length, sum all data values and divide by the total number of data values.

[tex]\textsf{Average of Group A}=\dfrac{ 3 \times 10 + 4 \times 11 + 3 \times 12}{10}=11[/tex]

[tex]\textsf{Average of Group B}=\dfrac{ 3 \times 9 + 5\times 10+ 2\times 11}{10}=9.9[/tex]

Thus proving that Group A has the longer average former length.

According to given text data

Average of both groups

A:-

B:-

Group A has bigger average

Answer: The two imaginary solutions with rational coefficients are +/- 4i and the two imaginary solutions with irrational coefficients are +/- 1.414213562i.

Step-by-step explanation:

I would recommend using pascal's triangle to solve this problem.

*Note: This is more of a quick answer, I can show a detailed step-by-step procedure if you need, just comment.

Answer:

AAA

Step-by-step explanation:

yesss

The only option that cannot be used to prove that the diagonals of parallelogram abcd intersect at point e is; Option C

A) The sum of the interior angles of any quadrilateral is 360° and so this is true about the parallelogram.

B) AB = CD and BC = DA from opposite sides of a parallelogram are equal. Also AC = CA because of reflexive property of congruence. Thus, ∠ABC ≅ ∠CDA

C) This is not true because ∠ABC ≅ ∠CDA instead of ∠ABC ≅ ∠CDE.

D) This is true because of the definition of a transversal.

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Explanation:

r = distance from the origin (0,0) to a point on the polar curve

To find the length of the flower petal, we need to max out r (i.e. get it as large as possible).

Recall that sin(x) maxes out at 1, so that also applies to sin(2θ) as well.

Therefore, r = 7*sin(2θ) maxes out at r = 7*1 = 7 and this is the length of each petal. Basically it's the number out front of the sine term.

The graph is shown below. To type the symbol θ into desmos, you need to type "theta" without quotes.

Answer:

4:5

girls:boys

16:20

divide both by 4

4:5