Find the zeroes of the function and write in a+bi form. -(x+1)^2-4=0

Answer:

x = 2  +  √-16 [ (-2)⁻¹]

See steps below.

Step-by-step explanation:

Finding the zeroes of a function simply means solving for the unknown variable (in this case "x") when the function is equated to zero.

The function here is   [tex]f(x) = -(x + 1)^{2} - 4 = 0[/tex]

Start by opening the bracket. Ignore the minus sign. It will be reintroduced at the end of this step.

(x + 1)(x + 1)   = x² + x + x + 1    = x² + 2x + 1

Reintroduce the minus sign. Don't forget to put the result above back in a bracket.

- (x² + 2x + 1)  = -x² -2x -1

Place the expression back in the equation and solve. Make sure to put it back in the position where it was.

-x² - 2x - 1 - 4 = 0

Simplify the non-algebraic terms.

-x² - 2x - 5 = 0

Use Quadratic Formula to solve for x.

Quadratic formula: x =  -b ± √(b² - 4ac)

                                              2a

a = the coefficient of x² = -1

b = the coefficient of x  = -2

c = the unit term            = -5

So   x = -(-2)  ± √ [(-2)² - 4(-1 x -5)]

                       2(-1)

x = 2 + √-16                    or x = 2 - √-16

         -2                                          -2

This is where the evaluation ends, since the square root of minus sixteen cannot be evaluated. x hence is equal to a complex number. The above are the two values for x.

Next step is to put it in "a + bi" form.

x = 2  +  √-16  ÷  -2     =  2  +  √-16  x (-2)⁻¹

So   x = 2  +  √-16 [ (-2)⁻¹]

where

a is 2;

b is √-16

i is [(-2)⁻¹]

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