Find x. Round your answer to the nearest tenth of a degree.

Answer:

The probability is: 0.8889.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Approved

Event B: Qualified

Probability of a person being approved:

80% of 75%(qualified)

30% of 25%(not qualified). So

[tex]P(A) = 0.8*0.75 + 0.3*0.25 = 0.675[/tex]

Probability of a person being approved and being qualified:

80% of 75%, so:

[tex]P(A \cap B) = 0.8*0.75[/tex]

Find the probability that a person is qualified if he or she was approved by the manager.

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.8*0.75}{0.675} = 0.8889[/tex]

The probability is: 0.8889.

Answer:

The number is 5

Step-by-step explanation:

Let the number be x,

Four times the number= 4x

two times the same number= 2x

So we have ,

4x – 2x = 10

2x = 10

x = 5

Therefore the number is 5

Answer:

f(x) = 16*0.75^x

Step-by-step explanation:

first off let's use this coordinate (the one given) :

(0,16)

let's substitute this into the equation with x being 0 and f(x) being 16

16 = a*b^0

*anything to the power of 0 is 1*

so:

a = 16

now use the second coordinate :

(1,12)

and do the same by substituting 1 for x and 12 for f(x), we also know what 'a' is:

12 = 16*b^1

12 = 16 * b

b = 3/4

so :

f(x) = 16*0.75^x

Answer:

f(x) = 16(.75)^x

Step-by-step explanation:

hi  

x/6 = 10

In a equation , you can use every math operation you know as long as you do the same thing on both sides.  

Here we have   x/6 = 10  

But what I want is  x .  

Here X is split in 6.  So  I 'm going to multiplicate all by 6 to find the original amount of X  

In bold operation that are often not written but that you must understand to do that kind of exercices.

So  :  x/6 = 10

      (x/6) *6  = 10 *6

        6x/6 =  60

             x = 60

Answer:

610.48

Step-by-step explanation:

The formula for compound interest is

A = P(1+r/n) ^nt  where

A is the amount in the account

P is the principle

r is the interest rate

n is the number of times the interest is compounded per year

t is the time in years

A = 500(1+.05/12) ^12*4

A = 500(1+.0041666666) ^48

A = 500(1.0041666666) ^48

A = 500*1.220895355

A =610.4476775

Rounding to the nearest cent

A = 610.48

Answer:

The answer is "Option a, Option b, and Option d".

Step-by-step explanation:

In the given question it is used to stratifying the sampling if the population of this scenario it flights takes off when it is divided via some strata.

Answer:

For each day of the week, randomly select 5% of all flights that depart on that day of the week.

Divide all flights into the following 4 groups on the basis of scheduled departure time: before 9:00 am, 9:00 am to 1:00 pm, 1:00 pm to 5:00 pm, and after 5:00 pm. Randomly select 5% of the flights in each group.

Divide the airports from which the airline's flights depart into 4 regions: Northeast, Northwest, Southwest, and Southeast. Randomly select 5% of all flights departing from airports in each region.

Step-by-step explanation:

ll sampling methods that divide the flights into a small number of mutually exclusive categories are appropriate. These methods include all flights on the basis of a characteristic that might be associated with the variable being investigated and randomly selects a proportionate number of flights from each group.

Answer:

[tex]\frac{121}{14} = 8\frac{9}{14}[/tex]

Step-by-step explanation:

1 & 2:The null and alternate hypotheses are

H0 : u = 16 vs Ha: u < 16

The null hypothesis is that the mean is 16 ounces against the claim that it is less than 16 ounces.

3:The significance level is 0.05

4. Critical Value:

The critical region for significance level = 0.05  for one tailed test is z< ± 1.645

5.The test statistic

The test statistic to be used is

z= x- μ/σ/√n

z= 15.8-16/0.32/√20

z= -0.2/ 0.071556

z= -2.7950

6. The p-value ≈ 0.00259 for one tailed test.

7. Reject H0

Since the calculated value of z= -2.7950 is less than z∝= -1.645  we reject the null hypothesis.

8. Conclusion:

There is enough evidence to  support the inspector's claim that the mean number of ounces of coffee in the jars.

https://brainly.com/question/15980493

Graph

Answer:

Hill doctoral tricot trivial paint Tahiti he who Olney of Accokeek if Dogtown k park pectin rabbit tabernacle numbed.

Answer:

1 balloon is 4/ 1 cake is 7

Step-by-step explanation:

2 balloons is 8/ 3 cakes are 21 add together you get 29.

Answer:

36 miles

Step-by-step explanation:

We want to find 40% of 90 miles

40% * 90

.40 * 90

36 miles

We have to find travelled distance inorder to find this we have to find 40℅ of 90miles

[tex]\\ \Large\sf\longmapsto 90\times 40\℅[/tex]

[tex]\\ \Large\sf\longmapsto 90\times \dfrac{40}{100}[/tex]

[tex]\\ \Large\sf\longmapsto 9\times 4[/tex]

[tex]\\ \Large\sf\longmapsto 36miles [/tex]

Answer:

za/2: Divide the confidence level by two, and look that area up in the z-table: .95 / 2 = 0.475. ...

E (margin of error): Divide the given width by 2. 6% / 2. ...

: use the given percentage. 41% = 0.41. ...

: subtract. from 1.

NA = A + W

By adding one unit to length, we increase the overall area by the width of the rectangle. This is because the formula for the area of a rectangle is A = l x w. So, NA = (l + 1) x w = (l x w) + w = A + w.

Answer:

V = 64.6

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos V = adj side/ hypotenuse

cos V = 3/7

Taking the inverse cos of each side

cos ^-1 ( cos V) = cos ^-1 (3/7)

V=64.62306

Rounding to the nearest tenth

V = 64.6

Answer:

V=64.6

Step-by-step explanation:

the same thing as other guy, lol

Answer:

A

Step-by-step explanation:

Its not a linear function; there is no consistent rate of change between each of the points.

Answer:

3rd option

Step-by-step explanation:

(1/2)^-2t

= (2^-1)^-2t

= 2^2t

= (2^2)^t

Answered by GAUTHMATH

9514 1404 393

Answer:

  (f·g)(x) = 2x^3 +6x^2 -4x -12

Step-by-step explanation:

The distributive property is used to find the expanded form of the product.

  (f·g)(x) = f(x)·g(x) = (x +3)(2x^2 -4) = x(2x^2 -4) +3(2x^2 -4)

  = 2x^3 -4x +6x^2 -12

  (f·g)(x) = 2x^3 +6x^2 -4x -12

Answer:

6

Step-by-step explanation:

2+4 = 6

..............

Answer:

Here is your answer omisha

2+4=6

Answer:

22

Step-by-step explanation:

(5x2) + (3x2) + (3x2)

22 square units

Answer from Gauthmath

Answer:

option A 5

I hope it's correct

.....

Answer:

6

Step-by-step explanation:

Remember: Each layer has 6 cubes. Step 3 Count the cubes. cubes Multiply the base and the height to check your answer. So, the volume of Jorge's rectangular prism is cubic centimeters. if wrong very sorry

Answer:

9

Step-by-step explanation:

took the test

Answer:

[tex]\displaystyle\frac{19,683}{200,000}\text{ or }\approx 9.84\%[/tex]

Step-by-step explanation:

For each planted seed, there is a 90% chance that it grows into a healthy plant, which means that there is a [tex]100\%-90\%=10\%[/tex] chance it does not grow into a healthy plant.

Since we are planting 6 seeds, we want to choose 2 that do not grow and 4 that do grow:

[tex]\displaystyle \frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}[/tex]

However, this is only one case that meets the conditions. We can choose any 2 out of the 6 seeds to be the ones that don't grow into a healthy plant, not just the first and second ones. Therefore, we need to multiply this by number of ways we can choose 2 things from 6 (6 choose 2):

[tex]\displaystyle \binom{6}{2}=\frac{6\cdot 5}{2!}=\frac{30}{2}=15[/tex]

Therefore, we have:

[tex]\displaystyle\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \binom{6}{2},\\\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot 15,\\\\P(\text{exactly 2 don't grow})=\boxed{\frac{19,683}{200,000}}\approx 9.84\%[/tex]

Answer:

[tex] {?}^{?} However, this is only one case that meets the conditions. We can choose any 2 out of the 6 seeds to be the ones that don't grow into a healthy plant, not just the first and second ones. Therefore, we need to multiply this by number of ways we can choose 2 things from 6 (6 choose 2):

\displaystyle \binom{6}{2}=\frac{6\cdot 5}{2!}=\frac{30}{2}=15(26)=2!6⋅5=230=15

Therefore, we have:

\begin{gathered}\displaystyle\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \binom{6}{2},\\\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot 15,\\\\P(\text{exactly 2 don't grow})=\boxed{\frac{19,683}{200,000}}\approx 9.84\%\end{gathered}P(exactly 2 don’t grow)=101⋅101⋅109⋅109⋅109⋅109⋅(26),P(exactly 2 don’t grow)=101⋅101⋅109⋅109⋅109⋅109⋅15,P(exactly 2 don’t grow)=200,00019,683≈9.84%

[/tex]

Answer:

6 percent increase

Step-by-step explanation:

2650 divided by 2500 gives you 1.06 which means if 2500 is 100 percent 2650 would be 106 percent so the answer is a 6 percent increase

Answer:

6%

Step-by-step explanation:

another way of doing this type of calculation is...

NEW-OLD  =  2650-2500  = 150     = .06 = 6%

   OLD                2500            2500

Answer:

True, I believe

Step-by-step explanation:

Answer:

The answer is yes because its horizontal

Answer:

The mean is of -0.4 hours.

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Mean of the sample of 64 Duracell:

By the Central Limit Theorem, 4.1 hours.

Mean of the sample of 64 Eveready:

By the Central Limit Theorem, 4.5 hours.

Mean of the difference?

Subtraction of normal variables, so we subtract the means.

4.1 - 4.5 = -0.4

The mean is of -0.4 hours.

Answer:

12x - 28° = 116°

7x + 32° = 116°

Step-by-step explanation:

12x - 28° and 7x + 32° are vertical angles. Vertical angles are congruent.

Therefore, to find the measure of each angle, we have to set each equation equal to each other as follows:

12x - 28° = 7x + 32°

Collect like terms

12x - 7x = 28 + 32

5x = 60

Divide both sides by 5

5x/5 = 60/5

x = 12

✔️12x - 28°

Plug in the value of x

12(12) - 28

= 144 - 28

= 116°

✔️7x + 32°

7(12) + 32

= 84 + 32

= 116°

Recall that

[tex]\sin(x)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n+1}}{(2n+1)!}[/tex]

Differentiating the power series series for y(x) gives the series for y'(x) :

[tex]y(x)=\displaystyle\sum_{n=0}^\infty a_nx^n \implies y'(x)=\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty (n+1)a_{n+1}x^n[/tex]

Now, replace everything in the DE with the corresponding power series:

[tex]y'-2xy = 6\sin(3x) \implies[/tex]

[tex]\displaystyle\sum_{n=0}^\infty (n+1)a_{n+1}x^n - 2\sum_{n=0}^\infty a_nx^{n+1} = 6\sum_{n=0}^\infty(-1)^n\frac{(3x)^{2n+1}}{(2n+1)!}[/tex]

The series on the right side has no even-degree terms, so if we split up the even- and odd-indexed terms on the left side, the even-indexed [tex](n=2k)[/tex] series should vanish and only the odd-indexed [tex](n=2k+1)[/tex] terms would remain.

Split up both series on the left into even- and odd-indexed series:

[tex]y'(x) = \displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} + \sum_{k=0}^\infty (2k+2)a_{2k+2}x^{2k+1}[/tex]

[tex]-2xy(x) = \displaystyle -2\left(\sum_{k=0}^\infty a_{2k}x^{2k+1} + \sum_{k=0}^\infty a_{2k+1}x^{2k+2}\right)[/tex]

Next, we want to condense the even and odd series:

• Even:

[tex]\displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2k+2}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2(k+1)}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2(k+1)}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=1}^\infty a_{2(k-1)+1}x^{2k}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=1}^\infty a_{2k-1}x^{2k}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty \bigg((2k+1)a_{2k+1} - 2a_{2k-1}\bigg)x^{2k}[/tex]

• Odd:

[tex]\displaystyle \sum_{k=0}^\infty 2(k+1)a_{2(k+1)}x^{2k+1} - 2\sum_{k=0}^\infty a_{2k}x^{2k+1}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2(k+1)}-2a_{2k}\bigg)x^{2k+1}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2k+2}-2a_{2k}\bigg)x^{2k+1}[/tex]

Notice that the right side of the DE is odd, so there is no 0-degree term, i.e. no constant term, so it follows that [tex]a_1=0[/tex].

The even series vanishes, so that

[tex](2k+1)a_{2k+1} - 2a_{2k-1} = 0[/tex]

for all integers k ≥ 1. But since [tex]a_1=0[/tex], we find

[tex]k=1 \implies 3a_3 - 2a_1 = 0 \implies a_3 = 0[/tex]

[tex]k=2 \implies 5a_5 - 2a_3 = 0 \implies a_5 = 0[/tex]

and so on, which means the odd-indexed coefficients all vanish, [tex]a_{2k+1}=0[/tex].

This leaves us with the odd series,

[tex]\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2k+2}-2a_{2k}\bigg)x^{2k+1} = 6\sum_{k=0}^\infty (-1)^k \frac{x^{2k+1}}{(2k+1)!}[/tex]

[tex]\implies 2(k+1)a_{2k+2} - 2a_{2k} = \dfrac{6(-1)^k}{(2k+1)!}[/tex]

We have

[tex]k=0 \implies 2a_2 - 2a_0 = 6[/tex]

[tex]k=1 \implies 4a_4-2a_2 = -1[/tex]

[tex]k=2 \implies 6a_6-2a_4 = \dfrac1{20}[/tex]

[tex]k=3 \implies 8a_8-2a_6 = -\dfrac1{840}[/tex]

So long as you're given an initial condition [tex]y(0)\neq0[/tex] (which corresponds to [tex]a_0[/tex]), you will have a non-zero series solution. Let [tex]a=a_0[/tex] with [tex]a_0\neq0[/tex]. Then

[tex]2a_2-2a_0=6 \implies a_2 = a+3[/tex]

[tex]4a_4-2a_2=-1 \implies a_4 = \dfrac{2a+5}4[/tex]

[tex]6a_6-2a_4=\dfrac1{20} \implies a_6 = \dfrac{20a+51}{120}[/tex]

and so the first four terms of series solution to the DE would be

[tex]\boxed{a + (a+3)x^2 + \dfrac{2a+5}4x^4 + \dfrac{20a+51}{120}x^6}[/tex]

Answer:

Translation 2 units to the right

Vertical stretch by a factor of 3

Translation 1 unit up

Step-by-step explanation:

Correct on plato :}

Answer:

8.6

Step-by-step explanation:

VW = WX / cos (36°)

= 7 / 0.81

= 8.6

Answer:

8.65

Step-by-step explanation:

cos 36° = 7 / VW

VW = 7 /  cos 36°

VW = 8.65