If the three numbers of a square in the complex plane are [tex]-19+32i,-5+12i and -22+15i[/tex] , then the fourth complex number [tex]-2+19i[/tex].
Given [tex]-19+32i,-5+12i and -22+15i[/tex] are three numbers.
Complex numbers are those numbers which extends the real numbers with an imaginary i. In this [tex]i^{2}=-1[/tex]. Major complex numbers are in the form a+ bi where a and b are real numbers.
let the fourth complex numbers be [tex]x+yi[/tex]. Then according to question;
=[tex](-22+15i)-(-5+12i)[/tex]
=(cos π/2+i sin π/2) [tex](x+yi)-(-5+12i)[/tex]
[tex]-17+3i=-y+12[/tex][tex]+(x+5)i[/tex]
Now solving for x and y by equating both sides.
x=-2 and y=29
Put the value of x and y in [tex]x+yi[/tex]
Z=-2+29i
Hence if the three numbers which forms vertices of a square are [tex]-19+32i,-5+12i,-22+25i[/tex] then the fourth complex numbers be [tex]-2+29i[/tex].
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Identify two angles that are marked
congruent to each other on the diagram
below. (Diagram is not to scale.)
Answer:
Angles G and H are congruent.
Step-by-step explanation:
table shows the travelling time to work of 50 people.
Travelling time (t) in minutes
Frequency
0 < t < 10
5
10 < t < 20
15
20 < t < 30
13
30 < t < 40
10
40 < t < 50
Calculate an estimate of the mean travelling time.
An estimate of the mean travelling time will be 24.8 mins.
What are mean?The mean is the average value which can be calculated by dividing the sum of observations by the number of observations
Mean = Sum of observations/the number of observations
Given;
Time > timemark > frequency
0 – 10 > 10/2 = 5 > 5
10 – 20 > (10+20)/2 = 15 > 15
20 – 30 > (20+30)/2 = 25 > 13
30 – 40 > (30+40)/2 = 35 > 10
40 – 50 > (40+50)/2 = 45 > 7
The mean time for the 50 people can be calculated as;
Mean = Summation of (mid-time x frequency) / total frequency
Mean = [5x5 + 15x15 + 25x13 + 35x10 + 45x7] / 50
Mean = [25 + 225 + 325 + 350 + 315] / 50
Mean = 1240 / 50
Mean = 24.8 mins
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simplify 26a7 + (-25a7)
Answer:
1a7
Step-by-step explanation:
26+-25=1
Round 38.856 to the nearest tenth
Answer:38.9
Step-by-step explanation:
The figure shows the letter M and four of its transformed images—A, B, C, and D:
A coordinate grid is shown from positive 8 to negative 8 on the x-axis and from positive 8 to negative 8 on the y-axis. An image of the letter M is shown on ordered pair 1, 2 and 1, 4 and 2, 3 and 3, 12, and 3, 4. Another image of letter M is shown on ordered pair 4, negative 4 and 4, negative 2 and 5, negative 3 and 6, negative 2 and 6, negative 4. This M is labeled as B. Another image of letter M labeled C is shown on negative 4, negative 4 and negative 4, negative 2 and negative 3, negative 3 and negative 2, negative 2 and negative 2, negative 4. An image of the letter W labeled A is shown on 1, negative 2 and 1, negative 4 and 2, negative 3 and 3, negative 2 and 3, negative 4. Another image of the letter W labeled D is shown on negative 2, 4 and negative 2, 2 and negative 3, 3 and negative 4, 2 and negative 4, 4. The letters A, B, C, D are written towards the bottom left of the respective W and M.
Which of the four images was formed by a reflection of the letter M?
A
B
C
D
The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.
Explanation of how reflection across axis works?When a graph is reflected along an axis, say x axis, then that leads the graph to go just in the opposite side of the axis as if we're seeing it in a mirror.
If you study it more, you will find that it's symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.
Thus, if you're reflecting a point (x,y) along the x-axis, then its x abscissa will stay the same but y coordinates will negate.
Thus (x,y) turns to (x, -y)
Similarly, if you're reflecting a point (x,y) along the y -axis, the resultant image of the point will be (-x,y).
The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.
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The reflection of letter M is (A)
What is reflection?A figure is said to be a reflection of the other figure, then every point in a figure is at equidistant from each corresponding point in another figure.
According to the graph the reflection of Of letter M is with same coordinates but with x as positive and y as negative.
Hence the reflection is (A).
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BD is the bisector of angle ABC Determine the measure of angle ABD
Answer:
45 degrees
Step-by-step explanation:
A bisector divides an angle into two equal parts. Since we are dividing a 90 degree angle by 2, we get a resulting value of 45 degrees.
please help, performance task: trigonometric identities
The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)
How to solve the trigonometric equations?Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)
The equation can be split as follows:
y = 1 - cos(x)
y = 2 - 2sin²(x)
Next, we plot the graph of the above equations (see graph 1)
Under the domain interval (-π, π), the curves of the equations intersect at:
(-π/3, 0.5) and (π/3, 0.5)
Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)
Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)
The equation can be split as follows:
y = 4cos⁴(x) - 5cos²(x) + 1
y = o
Next, we plot the graph of the above equations (see graph 2)
Under the domain interval [0, 2π), the curves of the equations intersect at:
(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)
Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)
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Horizontal lines n and m are intersected by lines q and p. At the intersection of lines q and n, the uppercase right angle is angle 4. At the intersection of lines q and m, the uppercase left angle is angle 1. At the intersection of lines p and n, the bottom left angle is angle 3. At the intersection of lines p and m, the uppercase left angle is angle 2.
If angle 1 is 110°, what would the other angle measures have to be in order for m || n and
q || p?
Angle 2 = °
Angle 3 = °
Angle 4 =
The values of the angles based on the information will be:
Angle 2 = 110°
Angle 3 = 70°
Angle 4 = 70°
How to calculate the angles?From the information given, angle 1 is 110° and the horizontal lines n and m are intersected by lines q and p.
In this case, it should be noted that vertcally opposite angles are equal. Hence, angle 2 is also 110°.
Angle 3 will be:
= 180° - 110° = 70° (angle on a straight line).
Angle 4 will also be 70° as a vertically opposite angle to angle 3.
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Answer:
The values of the angles based on the information will be:
Angle 2 = 110°
Angle 3 = 70°
Angle 4 = 70°
Step-by-step explanation:
is this correct ?-?
I need to get this done lol
Answer:
6
Explanation:
[tex]\textsf {The range of a data representation refers to difference of the smallest and }\\\textsf {greatest possible values. }[/tex]
[tex]\textsf {Here :}[/tex]
[tex]\textsf {smallest value = 5}\\\textsf {greatest value = 11}[/tex]
[tex]\textsf {Then the range will be :}\\\implies \textsf {greatest value - smallest value}\\\implies \mathsf {11 - 5}\\\implies \mathsf {6}[/tex]
Can I have the solution with steps
Answer:
1/6
Step-by-step explanation:
As usual in trigonometry, there are so many relationships between the trigonometric functions, there is bound to be more than one method to arrive at the answer.
Knowing values for the sine and cosine function for certain angles on the unit circle proves to be quite helpful. In general, I recommend 0°, 30°, 45°, 60°, and 90° at a minimum.
Recall the following 6 things:
[tex]\cos(30^o)=\frac{\sqrt{3}}{2}[/tex][tex]\cos(60^o)=\frac{1}{2}[/tex][tex]\sin(30^o)=\frac{1}{2}[/tex][tex]\sin(60^o)=\frac{\sqrt{3}}{2}[/tex][tex]\tan(\theta)=\dfrac{\sin(\theta)}{\cos(\theta)}[/tex][tex]\tan^2(\theta)=\tan(\theta)\tan(\theta)[/tex]Knowing these 6 things (4 things from the unit circle, a way to write the tangent function in terms of sine and cosine, and the definition of a squared trig function), we can simplify the given expression down to a single number:
The definition of the tangent squared function is that the output of the tangent function is squared...
[tex]\dfrac{1-\tan^2(30^o)}{1+\tan^2(60^o)}=\dfrac{1-(\tan(30^o))^2}{1+(\tan(60^o))^2}[/tex]
Using fact 5, and turning the tangent function into sines and cosines...
[tex]=\dfrac{1-\left(\frac{\sin(30^o)}{\cos(30^o)}\right)^2}{1+\left(\frac{\sin(60^o)}{\cos(60^o)}\right)^2}[/tex]
Using facts 1-4, and substituting known values for sines and cosines...
[tex]=\dfrac{1-\left(\frac{(\frac{1}{2})}{(\frac{\sqrt{3}}{2})}\right)^2}{1+\left(\frac{(\frac{\sqrt{3}}{2})}{(\frac{1}{2})}\right)^2}[/tex]
Division is multiplication by the reciprocal...
[tex]=\dfrac{1-\left(\frac{1}{2}*\frac{2}{\sqrt{3}}\right)^2}{1+\left(\frac{\sqrt{3}}{2}*\frac{2}{1}\right)^2}[/tex]
Reducing/simplifying common factors of 2...
[tex]=\dfrac{1-\left(\frac{1}{\sqrt{3}}\right)^2}{1+(\sqrt{3})^2}[/tex]
Squaring a square root...
[tex]=\dfrac{1-\left(\frac{1}{3}\right)}{1+(3)}[/tex]
Finding a common denominator...
[tex]=\dfrac{\frac{3}{3}-\frac{1}{3}}{4}[/tex]
Definition of subtracting fractions...
[tex]=\dfrac{\frac{3-1}{3}}{4}[/tex]
Arithmetic...
[tex]=\dfrac{\frac{2}{3}}{4}[/tex]
Division is multiplication by a reciprocal...
[tex]=\dfrac{2}{3}*\dfrac{1}{4}[/tex]
Simplification and reducing the fraction...
[tex]=\dfrac{1}{6}[/tex]
So, [tex]\dfrac{1-\tan^2(30^o)}{1+\tan^2(60^o)}=\dfrac{1}{6}[/tex]
Please please help what is equivalent to this??
The correct option is Option A: [tex]16^{3x/4}[/tex] is equivalent to the expression [tex](\sqrt[4]{16})^{3x[/tex].
The rules of the exponent are
(a) [tex]a^m*a^n=a^{m+n[/tex]
(b)[tex]a^m/a^n=a^{m-n[/tex]
(c)[tex](a^b)^c=a^{bc}[/tex]
(d) [tex]\sqrt[n]{a}=a^{1/n[/tex]
here the given expression is [tex]16^{3x/4}[/tex]
we can rewrite the expression as
[tex]16^{3x/4}[/tex]
as we know by the rule of the exponent that [tex](a^b)^c=a^{bc}[/tex]
=[tex](16^{1/4})^{3x[/tex]
as we know by the rule of the exponent [tex]\sqrt[n]{a}=a^{1/n[/tex]
=[tex](\sqrt[4]{16})^{3x[/tex]
Therefore the correct option is Option A: [tex](\sqrt[4]{16})^{3x[/tex]
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Work out the sum of the interior angles of any quadrilateral
Answer:
The sum of the interior angles of any quadrilateral is 360°.
Answer:
360°Step-by-step explanation:
A quadrilateral is a polygon which has 4 vertices and 4 sides enclosing 4 angles and the sum of all the angles is 360°.
I'll give you an example with the square, it has 4 right angles, so the sum is 360 ° as in all quadrilaterals.
please help .. . . .
Answer:
Step-by-step explanation:
For each expression below, select the letter that corresponds to the equivalent expression from the given list.
is equivalent to expression
is equivalent to expression
is equivalent to expression
Option 1 corresponds to Part B , Option 2 corresponds to Part D , Option 3 corresponds to Part A , Option 4 corresponds to Part C
The complete question is attached in the image
What is an Expression ?An expression corresponds to the mathematical statement that consists of variables , Constants and mathematical operators simultaneously.
Solving the given option will give us the answer.
(x²+15x+65)+(2x-5)*(3x+8)
(x²+15x+65)+(6x²+16x-15x-40)
(7x²+16x+25)
Option 1 corresponds to Part B
(4x+1)*(3x-4)-(5x²-10x-12)
(4x+1)*(3x-4)-(5x²-10x-12)
(12x²-16x+3x-4)-(5x²-10x-12)
(7x²-3x+8)
Option 2 corresponds to Part D
(8x²+19x+4)+(3x+2)*(x-5)
(8x²+19x+4)+(3x²-15x+2x-10)
(11x²+6x-6)
Option 3 corresponds to Part A
(6x+1)*(3x-7)-(7x²-34x-20)
(18x²-42x+3x-7)-(7x²-34x-20)
(11x²-5x+13)
Option 4 corresponds to Part C
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Josie needs to rent a car from SureRide Car Rentals. The cost of renting a car iS a
one-time fee of $80 plus $0.75 per mile. Write and graph an equation to represent
pay tO rent a car a from SureRide.
the cost which Josie must
Answer: y = 0.75x + 80
Step-by-step explanation:
let x = 1 mile
y = 0.75x + 80
A glass cylinder with a radius of 7cm has water up to a height of 9cm. A metal cube of 5.5cm edge is immersed in it completely. calculate the height by which the water rises in the cylinder.
i love robloox
n n n nn
A certain species of virulent bacteria is being grown in a culture. It is observed that the rate of growth of the bacterial population is proportional to the number present. If there were 1000 bacteria in the initial polulation and the number doubled after the first 30 minutes, how many bacteria will be present after 4 hours
Answer:
256,000
Step-by-step explanation:
If the culture doubles in size every 30 minutes, it doubles 2 times per hour. In 4 hours it will have doubled 2×4 = 8 times. Each doubling multiplies the number by 2, so 8 doublings will multiply the number by 2^8.
The population will be ...
1000×2^8 = 256,000 . . . bacteria present after 4 hours
lcm of 15,18,21
lcm of 56 84 140
lcm
Step-by-step explanation:
The lcm of first question is 630 and second is 840
Answer:
LCM of 15,18,21: 630
LCM of 56,84,140: 840
Step-by-step explanation:
The right method is to list all the multiples of the number and circle the least common ones. In this way you will get your answer for any LCM question!
2. The wind blows the pinwheel below clockwise 180 degrees. What positions would the ribbon labeled A end up in after the wind blows it?
Answer: In between the red and yellow ribbons
Step-by-step explanation:
When something is rotated 180 degrees, you basically just mirror it. Since this pinwheel has an uneven amount of ribbons, there isn't a ribbon opposite of it, so it would be between red and yellow.
One way to prove this quadrilateral is a square is by calculating the slopes of its sides and the slopes of its diagonals.
If we can prove that it has 2 pairs of parallel sides, one pair of consecutive sides perpendicular and perpendicular diagonals, then the quadrilateral shown ab
By examining it we found that:
If your answer is a fraction enter is as a fraction. Example: To enter negative one fifth type: -1/5
a. Slope of CB is
b. Slope of DA is
so DA is parallel to CB
c. Slope of CD is
so CD is perpendicular to CB
d. Slope of BD is
e. Slope of CA is
so CA is perpendicular to BD
A slope is also known as the gradient of a line. Slope of a line or straight object is the ratio of how much amount of rise occurs in correspondence to the increment in the run.
What is Slope?A slope is also known as the gradient of a line is a number that helps to know both the direction and the steepness of the line.
How to find the slope?Slope of a line or straight object is the ratio of how much amount of rise occurs in correspondence to the increment in the run.
Thus, we get:
Slope = rise/ run
The slope of any line can found by finding the ratio of the vertical distance to horizontal distance between two ends. Therefore, the blanks can be filled as shown below.
The Slope of CB is 4/3,The Slope of DA is 4/3, so DA is parallel to CBThe Slope of CD is (-3/4), so CD is perpendicular to CBThe Slope of BD is -7The Slope of CA is 1/7, so CA is perpendicular to BD.Learn more about Slope of Line:
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The slope of the line containing the points (-5, 3) and (-2, 1) is
O-2/3
02/3
0-3/2
Answer:
Step-by-step explanation:
slope=(1-3)/(-2-(-5))
=-2/(-2+5)
=-2/3
If f(x) = −3x 4 and g(x) = 2, solve for the value of x for which f(x) = g(x) is true. x =
The value of x for the equation to the true is 2/3
Solution to equationGiven the following functions
f f(x) = −3x + 4 and;
g(x) = 2
If the functions are equal, then;
-3x + 4 = 2
Subtract 4 from both sides
-3x = 2 - 4
-3x = -2
x = 2/3
Hence the value of x for the equation to the true is 2/3
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1
2
4
10
01:28:2
solve x2 + 12x = -11 by completing the square. which is the solution set of the equation?
be
o {-11, -1}
o {-11, 1}
{11, -1}
o {11, 1}
Answer:
11
Step-by-step explanation:
Find the common difference and the SIMPLIFIED general term formula.
3) a 14=1322 and a 38 = 3722
I reallyyyy need help!!! ASAP PLEASE!!!!!
Answer:
[tex]a_{n}[/tex] = 100n - 78
Step-by-step explanation:
the nth term of an arithmetic sequence is
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
given a₁₄ = 1322 and a₃₈ = 3722 , then
a₁ + 13d = 1322 → (1)
a₁ + 37d = 3722 → (2)
subtract (1) from (2) term by term to eliminate a₁
24d = 2400 ( divide both sides by 24 )
d = 100
substitute d = 100 into either of the 2 equations and solve for a₁
substituting into (1)
a₁ + 13(100) = 1322
a₁ + 1300 = 1322 ( subtract 1300 from both sides )
a₁ = 22
then nth term formula is
[tex]a_{n}[/tex] = 22 + 100(n - 1) = 22 + 100n - 100 = 100n - 78
PLEASE HELP. DON’T NEED DEEP EXPLANATION JUST ANSWERS.
Which of the following are solutions to the equations below?
x^2 + 6x + 9= 20
Check all that apply.
Answer:
[tex]\large {\textsf{B and E}}\ \implies x_1=-2\sqrt{5}-3,\ x_2=+2\sqrt{5}-3[/tex]
Step-by-step explanation:
Quadratic Formula: [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Quadratic Equation: ax² + bx + x = 0, where a ≠ 0
Given equation: x² + 6x + 9 = 20
Step 1: Subtract 20 from both sides.
x² + 6x + 9 - 20 = 20 - 20
⇒ x² + 6x - 11 = 0
Step 2: Identify the values of a, b, and c and substitute them in the formula.
⇒ a = 1, b = 6, c = -11
[tex]x=\dfrac{-6\pm\sqrt{\bold{6^2}-4(1)(-11)}}{\bold{2(1)}}\\\\x=\dfrac{-6\pm\sqrt{36\bold{\ - \ 4(-11)}}}{2}\\\\x=\dfrac{-6\pm\sqrt{\bold{36+44}}}{2}\\\\x=\dfrac{-6\pm\sqrt{80}}{2}\\\\x=\dfrac{-6\pm\sqrt{16\times5}}{2}\implies \dfrac{-6\pm\sqrt{\bold{16}}\times\sqrt{5}}{2} \\\\x=\dfrac{-6\pm4\sqrt{5}}{2}[/tex]
Step 3: Separate into possible cases.
[tex]x_1=\dfrac{-6-4\sqrt{5}}{2}\implies \dfrac{-6}{2}+\dfrac{-4\sqrt{5}}{2}\implies \boxed{-3-2\sqrt{5}\ \ \textsf{or}\ -2\sqrt{5}-3}\\\\x_2=\dfrac{-6+4\sqrt{5}}{2}\implies \dfrac{-6}{2}+\dfrac{4\sqrt{5}}{2}\implies \boxed{-3+2\sqrt{5}\ \ \textsf{or}\ \ 2\sqrt{5}-3}[/tex]
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4(p+q) /p-q x q+p/8(p+q)
Answer:
[tex]\frac{q+p}{2(p-q)}[/tex]
Step-by-step explanation:
[tex]\frac{4(p+q)}{p-q} *\frac{q+p}{8(p+q)}[/tex]
We will cancel out like terms.
[tex]\frac{4}{p-q} *\frac{q+p}{8}\\=\frac{4(q+p)}{8(p-q)} \\=\frac{q+p}{2(p-q)}[/tex]
work out the length x in the triangle
Answer:
The length x is 16 m==============
Imagine the height of the triangle is h, which is perpendicular to 15 m side.
The area is:
A = bh/2Use this formula and given values and find the value of h:
60 = 15h/2h = 60*2/15h = 8 mSince h is opposite to 30° angle and x is the hypotenuse of the formed right triangle, we'll use the property of 30°x60°x90° triangle.
Hypotenuse is twice the length of the side opposite to 30° angle.In our case h is opposite to 30° angle, therefore we have:
x = 2h = 2*8 = 16 mAnswer:
x = 16
Step-by-step explanation:
the area (A) of the triangle is calculated as
A = [tex]\frac{1}{2}[/tex] absinC
where a, b are 2 sides of the triangle and C the angle between them
here a = 15, b = x, C = 30° and A = 60 , then
[tex]\frac{1}{2}[/tex] × 15 × x × sin30° = 60
7.5x × [tex]\frac{1}{2}[/tex] = 60 ( multiply both sides by 2 to clear the fraction )
7.5x = 120 ( divide both sides by 7.5 )
x = 16
Which of the following is the solution to 3I x-1 I≥ 12?
A. x≤ -3 or x≥ 5
B. x≤ -3 and x≥ 5
C. x≥ 5
D. x≥ -3 or x≥ 5
The solution for the given inequality will be x≤ -3 or x≥ 5. Thus, the correct option is B.
What are inequalities?Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.
For the given inequality the solution can be found as,
When the value of x is negative,3|x-1| ≥ 12
x-1 ≥ 4
x ≥ 5
When the value of x is positive,3|x-1| ≥ 12
- x + 1 ≥ 4
-x ≥ 3
x ≤ -3
Hence, the solution for the given inequality will be x≤ -3 or x≥ 5. Thus, the correct option is B.
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At an amusement park, 40 percent of the tickets were sold in the first hour. If 800 tickets were sold in the first hour, which equation can be used to find the total number of tickets sold for the entire day?
StartFraction 800 divided by 40 Over 40 divided by 40 EndFraction = StartFraction 20 Over 1 EndFraction
StartFraction 100 divided by 4 Over 800 divided by 4 EndFraction = StartFraction 25 Over 200 EndFraction
StartFraction 40 times 20 Over 800 times 20 EndFraction = StartFraction 800 divided by 16,000 EndFraction
Answer:
2000 tickets were sold
Step-by-step explanation:
40% can also be written as 0.40
800/ 0.40 = 2000 total tickets
PLEASE HELP 20 POINTS
Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about point P.
A -105
B -75
C 75
D 105
Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about point P at; D: 105°
How to Interpret Rotation of objects?From the given image, If we connect points C of the blue quadrilateral to point C' of the rotated quadrilateral using the center of rotation P, then we will notice that ∠CPC' will be greater than 90°.
Now, the rotation is counterclockwise and it therefore means that the angle of rotation is will be positive and since ∠CPC' is greater than 90°, then we can say that the only correct option is Option D which is 105°
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