The materials that would float in a molten vat of lead are glass and charcoal.
Which material floats on the solution?Glass and charcoal are the materials that would float in a molten vat of lead because they are less denser than the lead solution while on the other hand, platinum and gold get drowned into the solution because of its high density as compared to lead.
So we can conclude that the materials that would float in a molten vat of lead are glass and charcoal.
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Need answer asap!! Molecules in the solid state
A) transfer heat to neighboring molecules by convection
B) have no motion
C) have no internal energy
D) vibrate in fixed positions
Answer:
c, have no internal energy
Which of the following is the electron configuration of an atom in the ground state?
(a) 1s2 2s1
(b) 1s2 2s2 2p5 3s2
(c) 1s2 2s1 2p6
(d) 1s1 2s2
Answer:
(a) 1s2 2s1
Explanation:
Electron configurations of atoms are in their ground state when the electrons completely fill each orbital before starting to fill the next orbital.
Understanding the notationIt's important to know how to read and interpret the notation.
For example, the first part of option (a) says "1s2"
The "1" means the first level or shellThe "s" means in an s-orbitalThe "2" means there are 2 electrons in that orbitalOther things to know about electron orbitalsIt important to know which orbitals are in each shell:
In level 1, there is only an s-orbitalIn level 2, there is an s-orbital and a p-orbitalin level 3, there is an s-orbital, a p-orbital, and a d-orbital (things get a little tricky when the d-orbitals get involved, but this problem is checking on the basic concept -- not the higher level trickery)So, it's also important to know how many electrons can be in each orbital in order to know if they are full or not. The electrons should fill up these orbitals for each level, in this order:
s-orbitals can hold 2p-orbitals can hold 6d-orbitals can hold 10 (but again, that's beyond the scope of this problem)Examining how the electrons are filling the orbitalsFor option (a):
the 1s orbital is filled with 2, andthe 2s orbital has a single electron in it with no other orbitals involved.This is in it's ground state.
For option (b):
the 1s orbital is filled with 2, the 2s orbital is filled with 2,the 2p orbital has 5 (short of a full 6), andthe 3s orbital has a single electron in it.Because the 3s orbital has an electron, but the lower 2p before it isn't full. This is NOT in it's ground state.
For option (c):
the 1s orbital is filled with 2, the 2s orbital has 1 (short of a full 2), andthe 2p orbital is filled with 6Although the 2p orbital is full, since the 2s orbital before it was not yet full, this is NOT in it's ground state.
For option (d):
the 1s orbital has 1 (short of a full 2), andthe 2s orbital is filled with 2Again, despite that the final orbital (in this case, the 2s orbital), is full, since the 1s orbital before it was not yet full, this is NOT in it's ground state.
Which of the following is a covalent compound?
NF3
KBr
CuO
FeCI3
1. A balloon contains 100g of oxygen gas (O₂) when the volume is 110 dm³. Find the volume of the balloon when the mass of oxygen gas is decreased to 50g. [take O=16] 1. A balloon contains 100g of oxygen gas ( O₂ ) when the volume is 110 dm³ . Find the volume of the balloon when the mass of oxygen gas is decreased to 50g . [ take O = 16 ]
The volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.
We will use the ideal gas equation-
PV=nRT
P=Pressure
V=volume
n=no. of moles
T=temperature
In this question temperature and pressure will remains constant then the above equation can be rewritten as-
[tex]V_{1} /n_{1} =V_{2} /n2[/tex]
where V1= initial volume of the balloon
V2= volume of the balloon when the mass of oxygen gas is decreased to 50g
now, substitute the values in the above equation-
V1=100dm3=100Ln1=100/32=3.12n2=50/32=1.56100/3.12=V2/1.56
V2=50 Lhence, the volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.
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Al + 0₂ → Al₂O3 help
Answer:
4Al +3O₂ → 2Al₂O₃
Explanation:
To balance the chemical equation, start by identifying the number of atoms of each element on both sides of the equation.
Al +O₂ → Al₂O₃
Reactants (right-hand side of the arrow)
Al➭ 1
O➭ 2
Products (left-hand side of the arrow)
Al➭ 2
O➭ 3
Balancing the equation means that we need to ensure the number of atoms of each element is the same on both sides of the equation.
Let's balance the number of O atoms.
Al +3O₂ → 2Al₂O₃
Reactants
Al➭ 1
O➭ 3(2)= 6
Products
Al➭ 2(2)= 4
O➭ 2(3)= 6
Balancing the number of Al atoms:
4Al +3O₂ → 2Al₂O₃
Reactants
Al➭ 4
O➭ 6
Products
Al➭ 4
O➭ 6
The equation is now balanced.
Additional:
For a similar question on balancing equations, do check out the following!
https://brainly.com/question/140725520.160g of Mg is equal to how many moles Mg
The 0.160 grams of Mg is equal to 0.00658 moles of Magnesium (Mg).
Given,
Mass of Mg, m=0.160g
The atomic mass of Mg is 24.31 g.
The number of moles can be represented as the ratio of the given mass of the atom/molecule to the Atomic/Molar mass of the atom/molecule.
Atomic mass can be defined as the mass of the one mole of an atom and Similarily, molecular mass can be defined as the mass of one mole of a molecule.
Number of moles, n=Given mass/Molar mass
n=0.160g/(24.31g/mol)=0.00658 moles
Hence, the 0.160 grams of Magnesium (Mg) is equal to 0.00658 moles of Magnesium (Mg).
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37) Which chemical equation is correctly balanced?
a) Al(OH)3(s) → Al₂O3(s) + 2 H₂O(g)
b) KI(aq) + Pb(NO3)2(aq) → KNO3(aq) + 4 Pbl₂(aq)
c) 2 Na3PO4(aq) + 3 CaCl₂(aq) →6 NaCl(aq) + Ca3(PO4)2(aq) to S
d) CsH12) +6 O₂(g)→ 5 CO₂(g) + 6 H₂O(g)
0 (0
Answer: c) [tex]2\text{Na}_{3}\text{PO}_{4}+3\text{CaCl}_{2} \longrightarrow 6\text{NaCl}+\text{Ca}_{3}\text{(PO}_{4})_{2}[/tex]
what is the relationship of work with distance and the force?
The good answer will be marked as brainlist.....
Answer:
Work is the use of force to move an object. It is directly related to both the force applied to the object and the distance the object moves. Work can be calculated with this equation: Work = Force x Distance.
:)
6. Give the balanced full reaction and calculate the E° for galvanic cells based on the
following reactions. Draw diagrams indicating; the anode, cathode, flow of electrons,
salt bridge
(a) Zn^2 (aq) + 2e- = Zn(s)
Pb²(aq) + 2e- → Pb(s)
(b) Cr2O7 + 14H + 6e- 2Cr³+ 7H₂O
H₂O2 + 2H+ + 2e- →2H₂O
Electrochemical cell is one in which energy is released by a chemical action.
What is an electrochemical cell?An electrochemical cell is one in which energy is released by a chemical action.
Now we have the reaction;
Zn^2 (aq) + 2e- = Zn(s)
Pb²(aq) + 2e- → Pb(s)
and
Cr2O7 + 14H + 6e- 2Cr³+ 7H₂O
H₂O2 + 2H+ + 2e- →2H₂O
In the first case, the Ecell is obtained from;
(-0.13 V) - (-0.76 V)
= 0.63 V
In the second case;
1.78 V - 1.33 V
= 0.45 V
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Polyester and Nylon are examples of synthetic materials called polymers.
A. True
B. False
Answer:
true is correct
Polyester and Nylon are examples of synthetic materials called polymers. This statement is True.
Polymers are large molecules composed of repeating subunits called monomers, which are chemically bonded together. In the case of polyester, it is made from a polymer called polyethylene terephthalate (PET), while Nylon is made from polyamide monomers. These polymers are created through polymerization processes that combine smaller molecules to form long chains.
Synthetic polymers like polyester and nylon are widely used in various applications due to their desirable properties, such as strength, durability, and resistance to chemicals and moisture.
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Calculate the theoretical yield in , grams AlI₃, aluminum iodide, from the complete reaction of 113 grams I₂ according to the following balanced chemical equation: 2Al(s) + 3I₂(s) → 2AlI₃(s)
121 g [tex]AlI_{3}[/tex] aluminum iodide, from the complete reaction of 113 grams I₂ according to the following balanced chemical equation:
2Al(s) + 3I₂(s) → 2[tex]AlI_{3}[/tex]
As per the given balanced equation,
3 moles of [tex]I_{2}[/tex] are used to give 2 moles of [tex]AlI_{3}[/tex].
Atomic weight of iodine is 127 gm/ mole
So, molecular weight of iodine molecule = 254 gm/ mole
There for , we can say that 1 mole o iodine molecule contain 254 g
So ,Given 113 gm iodine contains how many moles?
Moles of iodine = 113/254 = 0.44 moles
from the equation we can say that 3 moles of iodine used to give 2 moles of aluminum iodide.
So, 0.44 moles of iodine gives how many moles of aluminum iodide ?
Moles of aluminum iodide = 0.44 × 2 ÷ 3
= 0.2965 moles
Molecular weight of one mole of aluminum iodide = atomic weight of Al + 3( atomic weight of iodine )
= 408 gm
∴ 1 mole of aluminum iodide = 408 gm
so, 0.2965 moles of aluminum iodide = ?
= 0.2964 × 408
= 121 gm Aluminum iodide formed.
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How many moles of HCl are needed to react with 0.87 moles of Na?
A:0.87 mol HCl
B:0.82 mol HCl
C:1.0 mol HCl
D:0.96 mol Na
The moles of HCl are needed to react with 0.87 moles of Na are the A:0.87 mol HCl.
How do you calculate moles of HCl?M = mol / L Calculate the molarity of an HCl answer which includes 18.23 g of HCl in 355. zero mL of answer. Calculate the wide variety of moles of HCl. Divide the wide variety of moles of HCl with the aid of using the overall quantity in liters.
We'll start with the aid of using writing the balanced equation for the reaction. This is illustrated below:Na+HCl->NaCl +H From the balanced equation above, 1 mole of Na reacted with 1 mole of HCI.Finally, we will decide the wide variety of moles of HCI required to react with 0.87 moles of Na. This may be acquired as illustrated below:From the balanced equation above,1 mole of Na reacted with 1 mole of HCI.Read more about the moles ;
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How many orbitals are contained in the third principal level (n = 3) of a given atom?
The third principal level(n=3) of a given atom has 9 orbitals.
what are orbitals?
orbitals are different energy sub-levels.orbitals are of 4 types.each orbital has a unique and different shape.four types of orbital are-s, p, d, fThe 3rd electron shell has 3 subshells - 3s, 3p, 3d
s subshell only has one orbital.p subshell has three orbitals.d subshell has five orbitals.therefore, the total number of orbitals in the third electron shell is:
1+3+5=9 orbitals
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How many grams S03
are needed to make 400g
H₂So4 in 49%
160 g of SO3 are needed to make 400 g of 49% H2SO4.
How many grams of SO3 are required to prepare 400 g of 49% H2SO4?The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:
[tex]SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]
1 mole of SO3 produces 1 mole of H2SO4
Molar mass of SO3 = 80 g/mol
Molar mass of H2SO4 = 98 g/mol
80 g of SO3 are required to produce 98 og 100%H2SO4
mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3
Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g
Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.
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Perform the following
mathematical operation, and
report the answer to the
appropriate number of
significant figures.
15.225 - 3.88 =
You are given the following information: mass = 48 g; volume=24 cm. What is the density of this substance?
Answer:
Density = 0.0035 g/cm³
Explanation:
The density equation looks like this:
Density (g/cm³) = mass (g) / volume (cm³)
You have been given both the mass and volume. However, the given volume is not in the correct units. To convert cm to cm³, you should simply raise the given volume to the power of 3.
24 cm = (24 cm)³ = 24³cm³ = 13,834 cm³
Now, you can plug you mass and volume into the equation and solve for density. The final answer should have 2 sig figs to reflect the given values.
Density = mass / volume
Density = 48 g / 13,824 cm³
Density = 0.00347 g/cm³
Density = 0.0035 g/cm³
If 13.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
6.349 g mass of anhydrous magnesium sulfate will remain.
What are moles?A mole is defined as 6.02214076 × 1023 of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Molar mass MgSO₄.7 H₂O = 246.52 g/mol
[tex]Moles =\frac{mass}{molar \;mass}[/tex]
[tex]Moles =\frac{13.0 g}{246.52}[/tex]
0.0527 moles
Molar mass MgSO₄ = 120.4 g/mol
Mass of anhydrous magnesium sulfate :
( 0.0527 x 120.4 ) => 6.349 g
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QUESTION TO
What would I have to change to have a lunar eclipse happen every month?
You would have to fix the tilt of the Moon's orbit and make the Moon orbit planet Earth within the same plane that the Earth orbits the Sun.
What is a lunar eclipse?A lunar eclipse can be defined as a phenomenon which occurs when the planet Earth comes in between the Moon and the Sun, thereby causing the Earth to cover the Moon with its shadow.
In order to have a lunar eclipse occur every month, you would have to fix the tilt of the Moon's orbit and make the Moon orbit planet Earth within the same plane that the Earth orbits the Sun, so as to block any ray of sunlight from reaching the Moon.
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Look at the question marks between zinc (Zn) and arsenic (As) . At the time no elements were known with atomic weights between 65.2 and 75
Mendeleev positioned elements in the periodic table in increasing order of their atomic numbers, such that elements having identical chemical properties and characteristics plunge into the same group.
What is Mendeleev's periodic table?Mendeleev's periodic table may be defined as a collection of elements in an increasing atomic mass hierarchy in a table arrangement, such that it reminisces resemblances and manias according to their chemical properties and characteristics.
Mendeleev found that two elements existed between atomic weights 65.2 and 75 because he comprehended especially pleasingly that the possessions of the elements were more comparable and closer to this degree.
He also anticipated having other elements that would have their possessions comparable to these other elements.
Therefore, he departed a void for these two elements in the periodic table until they were ultimately found in their real existence.
The complete question is as follows:
Look at the two question marks between zinc (Zn) and arsenic (As). At the time, no elements were known with atomic weights between 65.2 and 75. But Mendeleev predicted that two elements must exist with atomic weights in this range. What led Mendeleev to predict that two undiscovered elements existed in that range?
Therefore, it is well described above.
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Select the correct answer from each drop-down menu. At chemical equilibrium, the amount of because .
A chemical equilibrium when the amounts of reactants or products no longer change.
Explanation:
Chemical equilibrium is a dynamic process, meaning the rate of formation of products by the forward reaction is equal to the rate at which the products re-form reactants by the reverse reaction.
? If a weaker solution of sodium bicarbonate was used in beaker b, would that solution require more or less hydrochloric to neutralize it and why?
Answer:
less HCL acid is required to neutralize a weaker solution of base (sodium bicarbonate).
Explanation:
b. Describe hydrogen bonding. (1 point)
Of protons, neutrons, and electrons, the least massive particle is the electron.is it True or False
The least massive particle is the electron. Hence, the option true is correct.
What are subatomic particles?Sub-atomic particles are tiny particles of matter that together constitute an atom. There are three subatomic particles, which are namely electrons, protons and neutrons.
Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron).
Hence, the option true is correct.
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Calculate the pH of a solution that is 0.113 M HCI.
Simplified concentration
[tex]\\ \rm\Rrightarrow 1.13\times 10^{-2}M[/tex]
Now
[tex]\\ \rm\Rrightarrow pH=-log[H^+][/tex]
[tex]\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})[/tex]
[tex]\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}[/tex]
[tex]\\ \rm\Rrightarrow pH=-0.05+2[/tex]
[tex]\\ \rm\Rrightarrow pH=1.95[/tex]
Highly acidic
Which of the following stage is also known as the unstable stage?
a.Transient creep stage
b.Constant creep stage
c.Fracture stage
d.Steady stage creep stage
Transient stage is also called the unstable stage and in this stage, there is a gradual decrease in deformation rate to a definite constant value.
What is Transient stage ?A transient state is when a process variable or variables changes, but before the system reaches a steady state.
Transient time is the time it takes for a circuit to change from one steady state to the next.
Therefore, Transient stage is also called the unstable stage and in this stage, there is a gradual decrease in deformation rate to a definite constant value.
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What is the pH of a 8.4x10⁻6 M H+solution?
What is pH?
pH=[?]
The pH can be obtained directly from the concentration using the formula below pH = - log [H⁺] Hence, pH of a 8.4x10⁻⁶ M H⁺ solution is 5.08.
What is pH ?
A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.
Taking the negative logarithm of the concentration of hydronium ions that are in the solution:
pH = - log [H⁺]
= - log [8.4x10⁻⁶ ]
= 5.08
Hence, pH of a 8.4x10⁻⁶ M H⁺ solution is 5.08.
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Which of the following is non polar covalent bond?
electronegativities:
C = 2.5, H = 2.1, P = 2.1, Cl = 3.0, N = 3.0, O = 3.5
N -O
N-Cl
P-O
H-Cl
Answer:
N-Cl
Explanation:
Look at the chart below. Since N-Cl bond has a electronegativity difference of (3.0-3.0) zero, they are non-polar.
What is the freezing point of an aqueous suger (C12H22O11) solution that boils at 110C°?
Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.
What is the freezing point?The temperature at which a liquid solidifies.
Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.
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How many valence electrons will a Cl- ion have?
Answer:
8
Explanation:
im pretty sure it'll be 8 electrons
Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.
Answer:
= 64584.7176 g
or
= 64.5847 kg
Explanation:
From our question, we have been asked to find the mass of SO₂ containing 6.075 × 10^26 S atoms.
We know that from Avogadro's constant,
1 mole of a substance contains 6.02 x 10²³ ions/atoms/units
Thus,
1 mole => 6.02 x 10²³ atoms
x moles=> 6.075 × 10²⁶ atoms
We cross multiply;
x moles = (6.075 × 10²⁶ x 1)/(6.02 x 10²³)
= 1009.1362 moles
1 mole of SO2 = 64 g
1009.1362 moles = ?
=>
[tex] \frac{1009.1362 \times 64}{1} [/tex]
= 64584.7176 g
= 64.5847 kg
