Graph the equation 2x - y = -3

PLEASE HELP, I HAVE NO IDEA HOW.

Answer:

A

Step-by-step explanation:

Its not a linear function; there is no consistent rate of change between each of the points.

Answer:

22

Step-by-step explanation:

(5x2) + (3x2) + (3x2)

22 square units

Answer from Gauthmath

NA = A + W

By adding one unit to length, we increase the overall area by the width of the rectangle. This is because the formula for the area of a rectangle is A = l x w. So, NA = (l + 1) x w = (l x w) + w = A + w.

9514 1404 393

Answer:

  (f·g)(x) = 2x^3 +6x^2 -4x -12

Step-by-step explanation:

The distributive property is used to find the expanded form of the product.

  (f·g)(x) = f(x)·g(x) = (x +3)(2x^2 -4) = x(2x^2 -4) +3(2x^2 -4)

  = 2x^3 -4x +6x^2 -12

  (f·g)(x) = 2x^3 +6x^2 -4x -12

Answer:

(4x² -6x+1.5²) +9-1.5²= (2x-1.5)²+9-2.25= (2x-1.5)²+6.75

(2x-1.5)² is greater or equal to 0 , 6.75>0 so expression is positive for all real numbers x

Step-by-step explanation:

a) Use the formula a²-2ab+b²= (a-b)² (You need to make squared expression because it is always positive)

Consider 4x² as a² and -6x=-2ab

4x²=a² a=2x  ab=3x 2x*b=3x

b=1.5

Express 4x² -6x+9= (4x² -6x+1.5²) +9-1.5²= (2x-1.5)²+9-2.25= (2x-1.5)²+6.75

(2x-1.5)² is greater or equal to 0 , 6.75>0 so expression is positive for all real numbers x

QUESTION:- An artist uses 200 tiles to create a tessellation design that covers a rectangle with dimensions 2 ft by 3 ft. He will cover a wall with dimensions 10 ft by 15 ft using the same design and tiles of the same size. How many tiles will he need to cover the entire wall?

ANSWER:-

CASE 2:-

IT IS GIVEN THAT DESIGN AND SIZE OF TILES R SAME SO WE CAN CONSIDER THAT SAME NUMBER OF TILES WILL COVER SAME AREA IN BOTH CASE.

WE CAN USE UNITARY METHOD FOR SOLVING THIS:-

[tex]6ft² \: is \: covered \: using \: 200 \: tiles \\ 1ft² \: is \: covered \: using \: \frac{200}{6} \: tiles \\ 150ft² \: is \: covered \: using \: \frac{200 \times 150}{6} \: tiles \\ 150ft² \: is \: covered \: using \: \frac{200 \times \cancel{150}^{ \: \: 25} }{ \cancel6 {}^{ \: 1} } \: tiles \\ 150ft² \: is \: covered \: using \: 200 \times 25 \: tiles \\ 150ft² \: is \: covered \: using \: 5000 \: tiles[/tex]

Answer:

The answer is "Option a, Option b, and Option d".

Step-by-step explanation:

In the given question it is used to stratifying the sampling if the population of this scenario it flights takes off when it is divided via some strata.

Answer:

For each day of the week, randomly select 5% of all flights that depart on that day of the week.

Divide all flights into the following 4 groups on the basis of scheduled departure time: before 9:00 am, 9:00 am to 1:00 pm, 1:00 pm to 5:00 pm, and after 5:00 pm. Randomly select 5% of the flights in each group.

Divide the airports from which the airline's flights depart into 4 regions: Northeast, Northwest, Southwest, and Southeast. Randomly select 5% of all flights departing from airports in each region.

Step-by-step explanation:

ll sampling methods that divide the flights into a small number of mutually exclusive categories are appropriate. These methods include all flights on the basis of a characteristic that might be associated with the variable being investigated and randomly selects a proportionate number of flights from each group.

first invert fraction of the slope from 4/1 to 1/4 and switch sign. then figure out the y-intercept

the algebraic approach would work like this:

-4x + 10 = 1/4x + b

plug in what you got, here: the intersection information

-4*(4) + 10 = 1/4*(4) + b

-16 + 10 = 1 + b

-6 = 1 + b

-7 = b

hi  

x/6 = 10

In a equation , you can use every math operation you know as long as you do the same thing on both sides.  

Here we have   x/6 = 10  

But what I want is  x .  

Here X is split in 6.  So  I 'm going to multiplicate all by 6 to find the original amount of X  

In bold operation that are often not written but that you must understand to do that kind of exercices.

So  :  x/6 = 10

      (x/6) *6  = 10 *6

        6x/6 =  60

             x = 60

Answer:

3rd option

Step-by-step explanation:

(1/2)^-2t

= (2^-1)^-2t

= 2^2t

= (2^2)^t

Answered by GAUTHMATH

Answer:

6 percent increase

Step-by-step explanation:

2650 divided by 2500 gives you 1.06 which means if 2500 is 100 percent 2650 would be 106 percent so the answer is a 6 percent increase

Answer:

6%

Step-by-step explanation:

another way of doing this type of calculation is...

NEW-OLD  =  2650-2500  = 150     = .06 = 6%

   OLD                2500            2500

Answer:

V = 64.6

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos V = adj side/ hypotenuse

cos V = 3/7

Taking the inverse cos of each side

cos ^-1 ( cos V) = cos ^-1 (3/7)

V=64.62306

Rounding to the nearest tenth

V = 64.6

Answer:

V=64.6

Step-by-step explanation:

the same thing as other guy, lol

Answer:

za/2: Divide the confidence level by two, and look that area up in the z-table: .95 / 2 = 0.475. ...

E (margin of error): Divide the given width by 2. 6% / 2. ...

: use the given percentage. 41% = 0.41. ...

: subtract. from 1.

Answer:

Translation 2 units to the right

Vertical stretch by a factor of 3

Translation 1 unit up

Step-by-step explanation:

Correct on plato :}

Answer:

12x - 28° = 116°

7x + 32° = 116°

Step-by-step explanation:

12x - 28° and 7x + 32° are vertical angles. Vertical angles are congruent.

Therefore, to find the measure of each angle, we have to set each equation equal to each other as follows:

12x - 28° = 7x + 32°

Collect like terms

12x - 7x = 28 + 32

5x = 60

Divide both sides by 5

5x/5 = 60/5

x = 12

✔️12x - 28°

Plug in the value of x

12(12) - 28

= 144 - 28

= 116°

✔️7x + 32°

7(12) + 32

= 84 + 32

= 116°

Answer:

28  and 38

Step-by-step explanation:

a+b = 66

a + 10 = b

using substitution, a + (a+10) = 66

2a = 56

a = 28

28 + 10 = 38

b = 38

Answer:

1 balloon is 4/ 1 cake is 7

Step-by-step explanation:

2 balloons is 8/ 3 cakes are 21 add together you get 29.

9514 1404 393

Answer:

  {-5.2555, 1.1278 ± 1.2579i}

Step-by-step explanation:

Descarte's rule of signs tells you there are 0 or 2 positive real roots and 1 negative real root. A graph shows you the negative roots is irrational, and the positive roots are complex.

There are formulas for solving equations of this sort. The method you use will depend on whether you need an exact result or just a numerical approximation. Exact results can be obtained in terms of radicals or in terms of trig functions.

The first attachment is from a freely available solver. It gives 4 decimal places, which is sufficient for many purposes.

The second attachment is the graph, along with the quadratic that results from dividing f(x) by the factor that gives the real root. While the values shown on the graph are to 3 decimal places, the calculator can be used to find them to greater precision. (We have used Newton's Method iteration to find the real root to 12 significant figures.)

Answer:

12 miles

Step-by-step explanation:

Let the amount of hours it takes Leroy to catch up to Kevin equal x. Since speed multiplied by time is distance, Leroy would have run a total of 6x miles(6*x). Kevin already had a head start of 24 minutes, which is the same as 2/5 of an hour. In 2/5 an hour, Kevin ran 2 miles as 2 is 2/5 *5. For the next x hours his distance would be a total of 5x(5*x). This means, after x hours, Kevins distance is 5x + 2. In this case, catching up to someone is the same as having the same distance value. This means we can set the two expressions equal to each other, and solve:

6x = 5x + 2

x = 2

The time it took Leroy to catch up is 2 hours, but we are looking for the distance, which is represented by 6x. We substitute in 2 to get:

6(2) = 12

This means Leroy had to run 12 miles.

Answer:

The number is 5

Step-by-step explanation:

Let the number be x,

Four times the number= 4x

two times the same number= 2x

So we have ,

4x – 2x = 10

2x = 10

x = 5

Therefore the number is 5

Answer:

The mean is of -0.4 hours.

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Mean of the sample of 64 Duracell:

By the Central Limit Theorem, 4.1 hours.

Mean of the sample of 64 Eveready:

By the Central Limit Theorem, 4.5 hours.

Mean of the difference?

Subtraction of normal variables, so we subtract the means.

4.1 - 4.5 = -0.4

The mean is of -0.4 hours.

Answer:

[tex]\frac{121}{14} = 8\frac{9}{14}[/tex]

Step-by-step explanation:

Answer:

option A 5

I hope it's correct

.....

Answer:

610.48

Step-by-step explanation:

The formula for compound interest is

A = P(1+r/n) ^nt  where

A is the amount in the account

P is the principle

r is the interest rate

n is the number of times the interest is compounded per year

t is the time in years

A = 500(1+.05/12) ^12*4

A = 500(1+.0041666666) ^48

A = 500(1.0041666666) ^48

A = 500*1.220895355

A =610.4476775

Rounding to the nearest cent

A = 610.48

Answer:

36 miles

Step-by-step explanation:

We want to find 40% of 90 miles

40% * 90

.40 * 90

36 miles

We have to find travelled distance inorder to find this we have to find 40℅ of 90miles

[tex]\\ \Large\sf\longmapsto 90\times 40\℅[/tex]

[tex]\\ \Large\sf\longmapsto 90\times \dfrac{40}{100}[/tex]

[tex]\\ \Large\sf\longmapsto 9\times 4[/tex]

[tex]\\ \Large\sf\longmapsto 36miles [/tex]

Answer:

6

Step-by-step explanation:

2+4 = 6

..............

Answer:

Here is your answer omisha

2+4=6

The operation manager is responsible to identify whether there are errors in quality of the tires manufactured.

There are three different shifts and each shift has different team of workers who manufacture tires. For this we test hypothesis as;

H0 ; Quality of tire manufactured is independent on shifts

Ha ; Quality of tires manufactured is dependent on shifts.

The p value of chi squared test is greater than the significance level therefore we reject the null hypothesis.

This hypothesis reach to conclusion that quality of tires is dependent on shifts, which means there are differences in quality among the three shifts.

Learn more at https://brainly.com/question/24365931

Recall that

[tex]\sin(x)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n+1}}{(2n+1)!}[/tex]

Differentiating the power series series for y(x) gives the series for y'(x) :

[tex]y(x)=\displaystyle\sum_{n=0}^\infty a_nx^n \implies y'(x)=\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty (n+1)a_{n+1}x^n[/tex]

Now, replace everything in the DE with the corresponding power series:

[tex]y'-2xy = 6\sin(3x) \implies[/tex]

[tex]\displaystyle\sum_{n=0}^\infty (n+1)a_{n+1}x^n - 2\sum_{n=0}^\infty a_nx^{n+1} = 6\sum_{n=0}^\infty(-1)^n\frac{(3x)^{2n+1}}{(2n+1)!}[/tex]

The series on the right side has no even-degree terms, so if we split up the even- and odd-indexed terms on the left side, the even-indexed [tex](n=2k)[/tex] series should vanish and only the odd-indexed [tex](n=2k+1)[/tex] terms would remain.

Split up both series on the left into even- and odd-indexed series:

[tex]y'(x) = \displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} + \sum_{k=0}^\infty (2k+2)a_{2k+2}x^{2k+1}[/tex]

[tex]-2xy(x) = \displaystyle -2\left(\sum_{k=0}^\infty a_{2k}x^{2k+1} + \sum_{k=0}^\infty a_{2k+1}x^{2k+2}\right)[/tex]

Next, we want to condense the even and odd series:

• Even:

[tex]\displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2k+2}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2(k+1)}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2(k+1)}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=1}^\infty a_{2(k-1)+1}x^{2k}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=1}^\infty a_{2k-1}x^{2k}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty \bigg((2k+1)a_{2k+1} - 2a_{2k-1}\bigg)x^{2k}[/tex]

• Odd:

[tex]\displaystyle \sum_{k=0}^\infty 2(k+1)a_{2(k+1)}x^{2k+1} - 2\sum_{k=0}^\infty a_{2k}x^{2k+1}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2(k+1)}-2a_{2k}\bigg)x^{2k+1}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2k+2}-2a_{2k}\bigg)x^{2k+1}[/tex]

Notice that the right side of the DE is odd, so there is no 0-degree term, i.e. no constant term, so it follows that [tex]a_1=0[/tex].

The even series vanishes, so that

[tex](2k+1)a_{2k+1} - 2a_{2k-1} = 0[/tex]

for all integers k ≥ 1. But since [tex]a_1=0[/tex], we find

[tex]k=1 \implies 3a_3 - 2a_1 = 0 \implies a_3 = 0[/tex]

[tex]k=2 \implies 5a_5 - 2a_3 = 0 \implies a_5 = 0[/tex]

and so on, which means the odd-indexed coefficients all vanish, [tex]a_{2k+1}=0[/tex].

This leaves us with the odd series,

[tex]\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2k+2}-2a_{2k}\bigg)x^{2k+1} = 6\sum_{k=0}^\infty (-1)^k \frac{x^{2k+1}}{(2k+1)!}[/tex]

[tex]\implies 2(k+1)a_{2k+2} - 2a_{2k} = \dfrac{6(-1)^k}{(2k+1)!}[/tex]

We have

[tex]k=0 \implies 2a_2 - 2a_0 = 6[/tex]

[tex]k=1 \implies 4a_4-2a_2 = -1[/tex]

[tex]k=2 \implies 6a_6-2a_4 = \dfrac1{20}[/tex]

[tex]k=3 \implies 8a_8-2a_6 = -\dfrac1{840}[/tex]

So long as you're given an initial condition [tex]y(0)\neq0[/tex] (which corresponds to [tex]a_0[/tex]), you will have a non-zero series solution. Let [tex]a=a_0[/tex] with [tex]a_0\neq0[/tex]. Then

[tex]2a_2-2a_0=6 \implies a_2 = a+3[/tex]

[tex]4a_4-2a_2=-1 \implies a_4 = \dfrac{2a+5}4[/tex]

[tex]6a_6-2a_4=\dfrac1{20} \implies a_6 = \dfrac{20a+51}{120}[/tex]

and so the first four terms of series solution to the DE would be

[tex]\boxed{a + (a+3)x^2 + \dfrac{2a+5}4x^4 + \dfrac{20a+51}{120}x^6}[/tex]