(h+k)(1) is
(k-h)(4) is
(k/h)(3) is
(h•k)(0) is
(k •h)(0) is
(h•k)(3) is
h(k(-2))

The average rate of change (slope) is 579.875 if, in 2009, there were 12,078 Burger King restaurants; in 2017, there were 16,717 Burger King restaurants.

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have:

In 2009, there were 12,078 Burger King restaurants; in 2017, there were 16,717 Burger King restaurants.

The slope:

[tex]\rm m =\dfrac{16717-12078}{2017-2009}[/tex]

m = 4639/8

m = 579.875

Thus, the average rate of change (slope) is 579.875 if, in 2009, there were 12,078 Burger King restaurants; in 2017, there were 16,717 Burger King restaurants.

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Answer:

Step-by-step explanation:

Comment

I find the wording a bit confusing. Does the question mean that the laws of algebra determine what single vale of x will make the right side = the left side in both equations?

I think that's the way I will interpret it.

The easiest way to solve both of them is to divide by 4 on both sides of the top equation and divide by 2 on the bottom equation.

Solution

Top equation

4(x - 2) = 1000                                 Divide by 4

4(x-2 )/ 4 = 1000/4          

(x - 2)  = 250                                    Remove the brackets

x - 2 = 250                                       Add 2 to both sides

x - 2 + 2 = 250 + 2                           Combine

x = 252

Bottom equation

2(x - 2) = 50                                      Divide by 2

2(x - 2)/2 = 50/2

(x - 2) = 25                                        Remove the brackets

x - 2 = 25                                          Add 2 to both sides

x - 2 + 2 = 25 + 2                              Combine

x = 27

Conclusion

If the equations are structured the same way but have different numbers then the answers will be unique.

Answer:

[tex]P = A - I[/tex]

Step-by-step explanation:

Answer:

hjjj gogo fgjvsgjgccvvggggggffffffddsddddfffgv

Answer:

b) angles 1 and 4 are congruent.

Hope it helps!

Answer:

[tex] \frac{289}{111} [/tex]

Step-by-step explanation:

[tex]2 + \frac{603}{1000 - 1} = 2 \frac{603}{999} = 2 \frac{67}{111} = \frac{289}{111} [/tex]

Answer:

First Graph:  -2x - 1 = 3(^-x)

Last Graph: 2^(-x) + 2 = 5^-x + 3

Step-by-step explanation:

For a system of equations to have a solution set, the graphs that depict them must intersect at one point.

Both graphs #1 and #5 do not intersect, hence graphs #1 and #5 are the only graphs that do not have solutions while the other graphs do.

The cash flow in year 1 is $15.

A growing perpetuity increases continuously and indefinitely.

Cash flow = present value x (rate of return - growth rate)

214 x (10% - 3%)

214 x 0.07 = $15

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Answer:

3x²

Step-by-step explanation:

0.482 to 1sf is 0.5

61.2x² to one sf is 60x²

√98.01 to 1sf is √100

√100 = 10

0.5 x 60x² = 30x²

30x² / 10 = 3x²

D.

[tex]m(x) = 0 \\ - 3x = 0 \\ x = 0[/tex]

E.

[tex]m(x) = \frac{ - 3}{25} [/tex]

[tex] \frac{ - 3x}{x {}^{2} + 2x - 24} = \frac{ - 3}{25} [/tex]

[tex] - 3(x {}^{2} + 2x - 24) = - 3(x)(25) \\ divide \: both \: sides \: by - 3[/tex]

[tex]x {}^{2} + 2x - 24 = 25x[/tex]

[tex]x {}^{2} - 23x - 24 = 0[/tex]

[tex](x - 24)(x + 1) = 0 [/tex]

[tex]x = 24 \\ x = - 1[/tex]

Answer:

D

x=0

Step-by-step explanation:

E)

[tex]\frac{-3x}{x^2+2x-24} =\frac{-3}{25} \\x^2+2x-24=25x\\x^2+2x-25x-24=0\\x^2-23 x-24=0\\x^2-24x+x-24=0\\x(x-24)+1(x-24)=0\\(x-24)(x+1)=0\\x=24,-1[/tex]

The correct answer is option B which is 3

Mean is defined as the ratio of the sum of the number of the data sets to the total number of the data.

Given data:-

4,3,2

The mean will be calculated as:-

Mean = (4 + 3 + 2) / 3

Mean =  9 / 3

Mean = 3

Therefore the correct answer is option B which is 3

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Answer:

Let us assume that √2 is a rational number.

So it can be expressed in the form p/q where p, q are co-prime integers and q≠0

√2 = p/q

Here p and q are coprime numbers and q ≠ 0

Step-by-step explanation:

√2 = p/q

On squaring both the sides we get,

=>2 = (p/q)2

=> 2q2 = p2……………………………..(1)

p2/2 = q2

So 2 divides p and p is a multiple of 2.

⇒ p = 2m

⇒ p² = 4m² ………………………………..(2)

From equations (1) and (2), we get,

2q² = 4m²

⇒ q² = 2m²

⇒ q² is a multiple of 2

⇒ q is a multiple of 2

Hence, p, q have a common factor 2. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number

√2 is an irrational number.

Answer:

-4.5

Step-by-step explanation:

You arrange the numbers from lowest to highest value:

-17, -12, -11, -10, -7, -2, 7, 10, 16, 20

Then you find the one in the middle:

-7, -2

Because there are two in the middle, you add them and divide them by two:

(-7 + -2)/2 = -4.5

Your answer is -4.5.

Step-by-step explanation:

firstly arrange it increasingly

-2,-7,-10,-11,-17, 7,10,16,20

n=9 it is odd so we use (n+1/2 )th formula

9+1/2

10/2=5th

os it is -17

Answer:

Step-by-step explanation:

The answer would be "me" as the indirect object

David will be 10 and John will be 9

Answer:

Step-by-step explanation:

4c + 11 = -25

4c = -25 - 11

4c = -36

c = -36 : 4

c = -9

or

4c + 11 + 25 = 0

4c + 36 = 0

c = (-36)/4

c = -9

-------------------

check

4 *(-9) + 11 = -25

-36 + 11 = -25

-25 = -25

the answer is good

Answer:

c= -9

Step-by-step explanation:

1. 4c + 11 = -25

2. Put all like terms together and change the sign. In this case, the +11 will go to the right with the -25 and it will become -11.

Therefore:

4c= -25 -11

4c= -36

3. Make c the subject. Since 4 is being multiplied by c, when it goes to the right, it will divide.

Therefore:

c= -36/4

c= -9

Answer: neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1

Step-by-step explanation:

Areas under the graphs:

Graph A

[tex](1)(0.5)+(7-2)(0.2)=1.5\\\\[/tex]

Graph B

[tex]\frac{\pi}{2}(1^{2})=\frac{\pi}{2}[/tex]

As neither of these graphs have an area of 1, neither of them are density curves.

The statement - "neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1" is true.

A few fundamental principles apply to density curves:

Neither curve of Graph A nor of Graph B has the area under the curve summed up as 1, though the curve is above the horizontal axis.

Hence, because neither graph has an area of 1, even if both curves are above the horizontal axis, the statement "neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1" is true.

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Therefore, we can write it as f(x) ≥ 0 over the interval [-1,1].

The given coordinates of the given table are (-3,15), (-2,-5), (-1,0), (0,5), and (1,0).

We need to write a valid prediction about the continuous function f(x).

In mathematics, a continuous function is a function such that a continuous variation of the argument induces a continuous variation of the value of the function.

Now, it is clear from the values of f(x) with respect to x, that the function reaches zero at x = -1, then goes up to 5 at x = 0 and then again reaches zero at x = 1.

So, the value of f(x) remains positive within the interval of [-1,1].

Therefore, we can write it as f(x) ≥ 0 over the interval [-1,1].

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Answer:

3

Step-by-step explanation:

Cardinalities are the number of elements in a set.

(A∩B∩C) is the very middle part of the circle, and there are 3 elements there.

Answer:

Step-by-step explanation:

Solution by substitution method

3x+5y=7

and 4x-y=5

Suppose,

3x+5y=7→(1)

and 4x-y=5→(2)

Taking equation (2), we have

4x-y=5

⇒y=4x-5→(3)

Putting y=4x-5 in equation (1), we get

3x+5y=7

⇒3x+5(4x-5)=7

⇒3x+20x-25=7

⇒23x-25=7

⇒23x=7+25

⇒23x=32

⇒x=32/23

→(4)

Now, Putting x=32/23

in equation (3), we get

y=4x-5

⇒y=4(32/23)-5

⇒y=(128-115)/23

⇒y=13/23

∴y=13/23   and x=32/23

The short leg of a 90-45-45 triangle is 3 and the long leg is 7. The hypotenuse would be [tex]c = \sqrt{58}[/tex].

The Pythagoras theorem states that the square of the longest side must be equal to the sum of the square of the other two sides in a right-angle triangle.

The short leg of a 90-45-45 triangle is 3 and the long leg is 7.

Since this is a right triangle, we can use the Pythagoras theorem

a^2+b^2 = c^2  

where a and b are the legs and c is the hypotenuse

[tex]3^2 + 7^2 = c^2\\\\9 + 49 = c^2\\\\58 = c^2\\\\c = \sqrt{58}[/tex]

Hence, The hypotenuse would be [tex]c = \sqrt{58}[/tex].

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The speed of the rabbit in miles per hour is 50.33 mi/h.

We know that the speed of the jackrabbit is:

1.35 km/min.

Now we need to use the relations:

1 hour = 60 minutes.

So, in one hour, the rabit runs 60 times the distance that it runs in one minute, then:

1.35 km/min = 60*(1.35 km/h) = 81km/h

Now we need to change kilometers for miles.

1km = 0.6214 mi

Then we can rewrite:

81km/h = 81*0.6214mi/h = 50.33 mi/h

The speed of the rabbit in miles per hour is 50.33 mi/h.

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Answer:

1/90

Step-by-step explanation:

Comment

To begin with, there are 10 tiles.. You draw one and don't replace it. Then you draw another tile from the 9 that remain.  The job is to figure out the probability of that happening.

You have a 1/10 chance of drawing the M.

But now there are only 9 tiles left and you have a 1 in 9 chance of drawing a T

Solution

P(M,T) = 1/10 * 1/9 = 1 / 90

You have a 1 in 90 chance of getting the two tiles in the order you have specified.

The slope for both the line is m= 1/3 and  they are parallel lines , Option B and C are correct two options

The first equation is

 y = (1/3)x-4 and not y = -x-4

(if the equation is not corrected then it will not have two true statements)

A system of equation is a set of equation which have a common solution

The given system of equation is

y = (1/3)x-4

3y -x = -7

3y = x-7

As it can seen from the standard equation of a line that

y =mx+c

so slope for both the line is m= 1/3

Therefore they are parallel lines

Thus , Option B and C are correct two options

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Answer:

This is my answer↓:

Step-by-step explanation:

He school play sold $550 in tickets one night.

The number of $8 adult tickets was 10 less than twice the number of

$5 child tickets.

How many of each ticket were sold

Let say child ticket sold = x

Adult tickets was 10 less than twice the number of    child tickets.

=> Adult ticket sold = 2x - 10

Child ticket sold = x

$5 child tickets price

=> Revenue = 5x  $

Adult ticket sold = 2x - 10

$8 Adult tickets price

=> Revenue = 8(2x - 10) =16x - 80 $

5x + 16x - 80 = 550

=> 21x = 630

=> x = 30

Child ticket sold = 30

Adult ticket sold = 50

Total ticket sold = 80

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[tex]\dfrac{x!-(x-3)!}{23}=1\\x!-(x-3)!=23\\(x-3)!((x-2)(x-1)x-1)=23\\(x-3)!((x^3-x^2-2x^2+2x)-1)=23\\(x-3)!((x^3-3x^2+2x)-1)=23[/tex]

23 is a prime number, therefore there are two possibilities:

[tex]\text{I.}\, (x-3)!=1 \wedge x^3-3x^2+2x-1=23[/tex]

or

[tex]\text{II.}\, (x-3)!=23 \wedge x^3-3x^2+2x-1=1[/tex]

[tex]\text{I.}\\(x-3)!=1\\x-3=0 \vee x-3=1\\x=3 \vee x=4[/tex]

Now, we check if any of these solutions is also a solution to the second equation:

[tex]3^3-3\cdot3^2+2\cdot3-1=23\\27-27+6-1-23=0\\ -18=0[/tex]

Therefore, 3 is not a solution.

[tex]4^3-3\cdot4^2+2\cdot4-1=23\\64-48+8-1-23=0\\0=0[/tex]

Therefore, 4 is a solution.

[tex]\text{II.}[/tex]

[tex](x-3)!=23[/tex]

We know that [tex]3!=6[/tex] and [tex]4!=24[/tex], therefore there isn't any [tex]n\in\mathbb{N}[/tex], for which [tex]n!=23[/tex], so there's no solution.

So, the only solution is [tex]x=4[/tex].